a)H0:p=0.4
H1:p>0.4
b)right-tailed test
c)0.075
d)0.0074
e)reject the null hypothesis
In this problem, we are testing the claim that the proportion of people who own cats is larger than 40% at the 0.025 significance level. The null and alternative hypothesis can be written as:
H0:p=0.4
H1:p>0.4
This is a right-tailed test. Using the sample data, the test statistic is 0.075 and the p-value is 0.0074. Therefore, we reject the null hypothesis and conclude that the proportion of people who own cats is greater than 40% at the 0.025 significance level.
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Wok out the probability of rolling one 6 from 2 throws on a biased dice rolling 6 1/5 of the time
Wok out the probability of rolling one 6 from 2 throws on a biased dice rolling 6 1/5 of the time is 8/25
The given data is as follows:
Number of throws = 2
probability of rolling number = 6
The probability of getting dice one 6 from 2 throws can happen in two different ways.
1. Rolling a number 6 on the first throw and not getting a number 6 on the second throw.
2. Not rolling a number 6 on the first throw and getting a number 6 on the second throw.
Here, the multiplication rule of probability is used to find the probability of the above two different events.
1.
The probability of getting a 6 on the first throw = is 1/5
The Probability of not getting a 6 on the second throw = (4/5)
The Probability of both happening: (1/5) x (4/5) = 4/25
2.
The Probability of not getting a 6 on the first throw = (4/5)
The Probability of getting a 6 on the second throw = (1/5)
The Probability of both happening: (4/5) x (1/5) = 4/25
The probability of both events is = 4/25 + 4/25 = 8/25
Therefore we can conclude that the probability of getting one 6 from 2 throws on a dice rolling 6 1/5 of the time is 8/25.
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Fill in each blank so that the resulting statement is true. The domain of \( f(x)=\sin ^{-1} x \) is and the range is The domain of \( f(x)=\sin ^{-1} x \) is and the range is
Fill in each blank so t
The domain of \(f(x)=\sin^{-1}x\) is \([-1, 1]\) and the range is \([-π/2, π/2]\).
This is because the inverse sine function, \(sin^{-1}x\), is defined only for values of x between -1 and 1, resulting in a domain of \([-1, 1]\). The range of \(sin^{-1}x\) is the set of all possible output values, which are angles between \(-π/2\) and \(π/2\).
Therefore, the domain of \(f(x)=\sin^{-1}x\) is \(\boxed{[-1, 1]}\) and the range is \(\boxed{[-π/2, π/2]}\).
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lowing linear equation. -3x+6y=-5 aph. Any lines or curves will be drawn once all required points are plotted. Enable
The graph of this equation will be a straight line with a slope of 1/2 and a y-intercept of -5/6.
To solve the given linear equation, we can use the method of isolating the variable on one side of the equation. Here are the steps to solve the equation:
Step 1: Start with the given equation: -3x + 6y = -5
Step 2: Isolate the variable on one side of the equation. We can do this by adding 3x to both sides of the equation:
-3x + 6y + 3x = -5 + 3x
Simplifying the equation gives us:
6y = 3x - 5
Step 3: Now, we can isolate the y variable by dividing both sides of the equation by 6:
(6y)/6 = (3x - 5)/6
Simplifying the equation gives us:
y = (3/6)x - (5/6)
Step 4: Simplify the fractions by reducing them:
y = (1/2)x - (5/6)
This is the final solution of the given linear equation. The graph of this equation will be a straight line with a slope of 1/2 and a y-intercept of -5/6.
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The water level of a lake was 20 feet and increases 10% each week during winter rainstorms
The water level after 4 weeks will be 29.2 feet.
The water level of the lake will increase by 10% each week during the winter rainstorms. This means that each week, the water level will increase by 0.10 × 20 = <<0.10*20=2>>2 feet.
After the first week, the water level will be 20 + 2 = <<20+2=22>>22 feet.
After the second week, the water level will be 22 + 2 = <<22+2=24>>24 feet.
After the third week, the water level will be 24 + 2 = <<24+2=26>>26 feet.
And so on.
We can use the formula A = P(1 + r)^n to find the water level after n weeks, where A is the final amount, P is the initial amount, r is the rate of increase, and n is the number of weeks.
In this case, P = 20, r = 0.10, and n is the number of weeks.
So, the water level after n weeks will be:
A = 20(1 + 0.10)^n
We can plug in different values of n to find the water level after a certain number of weeks.
For example, to find the water level after 4 weeks, we can plug in n = 4:
A = 20(1 + 0.10)^4 = 29.2 feet
So, the water level after 4 weeks will be 29.2 feet.
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What is a possible measure of an angle that has a terminal side in Quadrant III and makes a 60º angle with the x-axis?
A. 120°
B. 210°
C. 150°
D. 240°
Answer: option D is correct
Step-by-step explanation
Angle makes Quadrant III is 60°
To find : terminal side angle .
solution : we know that sum of total angle
is 360° and half of it in 180°
here the possible angle of an
that has terminal side in quadrant III
and makes a 60 degree with the x axis,
=) 120° + 60° =240°
Hence the correct option is in D) 240°
2) Consider the model m Ji = Σβ,tij + u; j=1 where there is no constant in the equation. Derive the properties of R2 for this model.
To derive the properties of R2 for the model m Ji = Σβ,tij + u; j=1, we need to first understand what R2 represents. R2, also known as the coefficient of determination, is a statistical measure that represents the proportion of the variance in the dependent variable that is explained by the independent variable(s) in a regression model.
In the given model, the dependent variable is m Ji and the independent variable is tij. The coefficient β represents the slope of the regression line and u represents the error term.
To derive the properties of R2, we can use the formula:
R2 = 1 - (SSres/SStot)
Where SSres is the sum of squared residuals and SStot is the total sum of squares.
SSres = Σ(m Ji - ŷi)2
SStot = Σ(m Ji - ȳ)2
Where ŷi is the predicted value of m Ji and ȳ is the mean of m Ji.
By substituting the values of SSres and SStot into the formula for R2, we can derive the properties of R2 for the given model.
R2 = 1 - (Σ(m Ji - ŷi)2/Σ(m Ji - ȳ)2)
The properties of R2 for the given model are:
1) R2 is always between 0 and 1. A value of 0 indicates that the independent variable(s) do not explain any of the variance in the dependent variable, while a value of 1 indicates that the independent variable(s) explain all of the variance in the dependent variable.
2) R2 is a measure of the strength of the relationship between the independent variable(s) and the dependent variable. The closer R2 is to 1, the stronger the relationship.
3) R2 is affected by the number of independent variables in the model. The more independent variables there are, the higher the R2 value will be.
4) R2 does not indicate causation. It only measures the strength of the relationship between the independent variable(s) and the dependent variable.
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E. 4(x - 1)^2 + 25(y - 3)^2 = 100 Center: ____ Vertices: ____ Co-Vertices: ____
Foci: ____
For the given equation of an ellipse, Center: (1,3), Vertices: (6,3) and (-4,3), Co-Vertices: (1,5) and (1,1), and Foci: (5.58,3) and (-3.58,3).
The given equation is in the standard form of an ellipse with center at (h,k) with a horizontal major axis.
To find the center, we can simply look at the values of h and k in the equation. In this case, h = 1 and k = 3, so the center is (1,3).
To find the vertices, we need to find the values of a and b, which are the semi-major and semi-minor axes, respectively. In this case, a^2 = 25 and b^2 = 4, so a = 5 and b = 2.
The vertices are located at a distance of a units from the center along the major axis. Since the major axis is horizontal, the vertices are (1 + 5, 3) and (1 - 5, 3), or (6,3) and (-4,3).
The co-vertices are located at a distance of b units from the center along the minor axis. Since the minor axis is vertical, the co-vertices are (1, 3 + 2) and (1, 3 - 2), or (1,5) and (1,1).
To find the foci, we need to find the value of c, which is related to a and b by the equation c^2 = a^2 - b^2. In this case, c^2 = 25 - 4 = 21, so c ≈ 4.58.
The foci are located at a distance of c units from the center along the major axis. Since the major axis is horizontal, the foci are (1 + 4.58, 3) and (1 - 4.58, 3), or (5.58,3) and (-3.58,3).
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What is the hcf of 124
Answer:
2
Step-by-step explanation:
sin
^-1 (sin A) ≠ A
A. implies that A is not in the domain
b. requires that A = 0
c. is not possible because arcsin reverses sin
d. happens when A is not in [-pi/2, pi/2]
The correct answer is d. happens when A is not in [-pi/2, pi/2]. The inverse sine function, sin^-1, or arcsin, is the function that reverses the sine function.
It is defined for values in the range [-1, 1] and has a range of [-pi/2, pi/2]. This means that if A is not in the range [-pi/2, pi/2], then sin^-1 (sin A) will not equal A.
For example, if A = pi, then sin A = 0, but sin^-1 (0) = 0, not pi. This is because pi is not in the range [-pi/2, pi/2], so the inverse sine function cannot return it as an answer.
Therefore, The correct answer is d. happens when A is not in [-pi/2, pi/2].
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People use water to cook, clean, and drink every day. An estimate of 22. 9% of the water used each day is for cleaning. If a family uses 68. 7 gallons of water a day
for cleaning, how many gallons do they use every day?
gallons
(Type a whole number)
The family uses 68.7 gallons of water every day for all purposes
If 22.9% of the water is used for cleaning, then the remaining 100% - 22.9% = 77.1% of the water is used for other purposes such as drinking and cooking.
To find out how much water the family uses every day, we need to add the amount of water used for cleaning to the amount of water used for other purposes.
Quantity of water used for cleaning = 22.9 percentage of the total amount of water used every day = 0.229 x 68.7 gallons = 15.71 gallons
Quantity of water used for other purposes = 77.1% of the total amount of water used every day = 0.771 x 68.7 gallons = 52.99 gallons
Total quantity of water used every day = amount of water used for cleaning + amount of water used for other purposes = 15.71 gallons + 52.99 gallons = 68.7 gallons
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The scale factor of two similar cylinders is 5:2. The volume of the smaller cylinder is 28 m3. What is the volume of the larger cylinder?
70 m3
175 m3
350 m3
700 m3
437.5 m3
Using the scale factor, we found the volume of the larger cylinder as 70 m³.
What is a cylinder?One of the most fundamental curvilinear geometric shapes, a cylinder has historically been a three-dimensional solid. It is regarded as a prism with a circle as its base in basic geometry. One of the fundamental three-dimensional shapes in geometry is the cylinder, which has two distant, parallel circular bases. At a predetermined distance from the centre, a curved surface connects the two circular bases. The axis of the cylinder is the line segment connecting the centres of two circular bases. The height of the cylinder is defined as the distance between the two circular bases.
Given,
The scale factor of the cylinders = 5:2
The scaling factor indicates how much a figure has increased or decreased from its initial value.
The volume of the smaller cylinder = 28 m³
We are asked to find the volume of the larger cylinder.
let the volume of the larger cylinder be x.
x / 28 = 5/2
x =(5/2) × 28 = 70
Therefore using the scale factor, we found the volume of the larger cylinder as 70 m³.
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QUESTION 1 \[ \left(x^{2} y+x y-y\right) d x+\left(x^{2} y-2 x^{2}\right) d y=0 \] QUESTION 2 \[ x \frac{d y}{d x} \sin \left(\frac{y}{x}\right)=y \sin \left(\frac{y}{x}\right)-x \text { using the sub
$$x \frac{dy}{dx}\sin \left(\frac{y}{x}\right)=y \sin \left(\frac{y}{x}\right)-x$$
QUESTION 1:
Using the substitution $u = xy$, we have the following equation:
$$(x^2u+xu-u)dx + (x^2u-2x^2)dy = 0$$
Multiplying both sides by $\frac{dy}{dx}$, we get:
$$(x^2u+xu-u)\frac{dy}{dx}dx + (x^2u-2x^2)\frac{dy}{dx}dy = 0$$
Simplifying, we have:
$$(x^2u+xu-u)\frac{dy}{dx} + (x^2u-2x^2)dy = 0$$
Rearranging, we get:
$$x\frac{dy}{dx}(u \sin \left(\frac{y}{x}\right)) + y\sin \left(\frac{y}{x}\right) - x = 0$$
Which simplifies to:
$$x \frac{dy}{dx}\sin \left(\frac{y}{x}\right)=y \sin \left(\frac{y}{x}\right)-x$$
QUESTION 2:
The solution to the given differential equation is:
$$x \frac{dy}{dx}\sin \left(\frac{y}{x}\right)=y \sin \left(\frac{y}{x}\right)-x$$
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I need help as soon as possible!
Answer:
The answer is 2/15
Step-by-step explanation:
2/5 × 1/3
\[ \frac{1+\frac{4}{a}+\frac{4}{a^{2}}}{1-\frac{8}{a}-\frac{20}{a^{2}}} \] a. \( \frac{a+2}{a-10} \) b. \( \frac{a+2}{a^{2}} \) c. \( -\frac{a-10}{a+2} \) d. \( \frac{4}{a-10} \)
The equation (1 + 4/a+4/a²)/ (1- 8/a - 20/a² simplifies to -(a-10)/(a+2) . (C)
The given expression can be simplified by using the distributive law of multiplication over addition and the inverse law of multiplication to simplify the denominator.
By applying these laws, the given expression becomes: (1 + 4/a+4/a²)/ (1- 8/a - 20/a² = (1 + 4/a+4/a²)/ (a² - 8a - 20) = (a+2)/(a² - 8a - 20). By further simplifying it, we get (a+2)/(a-10). Hence, the answer is C. -(a-10)/(a+2).
In order to simplify the given expression, the distributive law of multiplication over addition is used by multiplying the numerator and denominator separately with the denominator's terms.
The inverse law of multiplication is then used to simplify the denominator. This gives us the simplified expression of (a+2)/(a-10).
By substituting the values of a in the expression, we can verify the answer. If a = 5, then the expression simplifies to
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Complete question:
[tex]\[ \frac{1+\frac{4}{a}+\frac{4}{a^{2}}}{1-\frac{8}{a}-\frac{20}{a^{2}}} \] a. \( \frac{a+2}{a-10} \) b. \( \frac{a+2}{a^{2}} \) c. \( -\frac{a-10}{a+2} \) d. \( \frac{4}{a-10} \)[/tex]
(1 + 4/a+4/a²)/ (1- 8/a - 20/a²) = ?
A. (a+2)/(a-10) b. (a+2)/a² C. -(a-10)/(a+2) D. 4/(a-10)
Let B1 be the basis {(1,2,3),(2,−1,2)}={u1,u2} and B2 be the basis {(0,5,4),(1,−8,−5)}={v1,v2}. Show that these two bases span the same subspace of R3
The two bases B1 and B2 span the same subspace of R3.
Let B1 be the basis {(1,2,3),(2,−1,2)}={u1,u2} and B2 be the basis {(0,5,4),(1,−8,−5)}={v1,v2}. We want to show that these two bases span the same subspace of R3.
To do this, we need to show that any vector in the subspace spanned by B1 can also be written as a linear combination of vectors in B2, and vice versa.
Let x be a vector in the subspace spanned by B1. Then x = a*u1 + b*u2 for some scalars a and b. Substituting the values of u1 and u2, we get:
x = a*(1,2,3) + b*(2,−1,2)
= (a+2b, 2a-b, 3a+2b)
Now we want to express x as a linear combination of v1 and v2:
x = c*v1 + d*v2
= c*(0,5,4) + d*(1,−8,−5)
= (d, 5c-8d, 4c-5d)
Setting the two expressions for x equal to each other, we get the following system of equations:
a+2b = d
2a-b = 5c-8d
3a+2b = 4c-5d
Solving this system of equations, we can find values of c and d that satisfy the equations. This shows that any vector in the subspace spanned by B1 can also be written as a linear combination of vectors in B2.
Similarly, we can show that any vector in the subspace spanned by B2 can also be written as a linear combination of vectors in B1.
Therefore, the two bases B1 and B2 span the same subspace of R3.
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The school packs one lunch based on each of these choices. If Dr. Higgins wants a "Turkey, Water and Cookie" or a " Turkey, Water and Brownie" (I could eat either lunch) - what is the probability that Dr. Higgins randomly picks up one or the other of his Favorite Lunches?
The probability of selecting either lunch is 50%, as both lunches are equally likely to be chosen. This is because both lunches have the same ingredients, with the only difference being the dessert item.
What is probability?Probability is a measure of the likelihood of a certain event or outcome occurring. It is expressed as a number between 0 and 1, where 0 indicates that the event or outcome is impossible and 1 indicates that the event or outcome is certain to occur. Probability is an important concept in mathematics and statistics, and it is widely used in fields such as finance, science, engineering, and gaming.
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Find all the zeros, real and nonreal, of the polynomial and use tha p(x)=x^(2)+16
The zeros of the polynomial p(x)=x²+16 are x = 4i and x = -4i. The zeros of the polynomial can be found using the Quadratic Formula: x = (-b ± √(b²-4ac))/(2a), where a, b, and c are the coefficients of the polynomial. In this case, a = 1, b = 0, and c = 16.
Plugging in these values into the Quadratic Formula, we get:
x = (-0 ± √(0²-4(1)(16)))/(2(1))
Simplifying the expression, we get:
x = (0 ± √(-64))/(2)
Since the square root of a negative number is a nonreal number, we can write this as:
x = (0 ± 8i)/(2)
Simplifying further, we get:
x = 0 ± 4i
So the zeros of the polynomial are x = 4i and x = -4i, both of which are nonreal numbers.
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A variable needs to be eliminated to solve of equations below
5x + y = 48
3x -y=16
Answer:
To eliminate y, we can add the two equations.
5x + y + 3x - y = 48 + 16
Simplifying the left side, we get:
8x = 64
Dividing both sides by 8, we get:
x = 8
Now we can substitute x = 8 into either of the original equations and solve for y:
5x + y = 48
5(8) + y = 48
40 + y = 48
y = 8
So the solution is (x,y) = (8,8).
Find the missing side links, leave your answers as radicals in simplest form
Applying Trigonometric ratios, the missing sides, expressed as radicals in simplest form are:
26. u = 3√2; v = 3
27. a = 3/2; b = 3/2
28. x = 7√2; y = 7
29. u = 5√2; v = 5√2
What are Radicals?Radicals are mathematical expressions that involve the square root or nth root of a number or a variable.
We can express each of the missing sides in radicals using the appropriate Trigonometry ratio in each case as follows:
26. Use sine ratio to find u:
sin 45 = 3/u
u = 3/sin 45
u = 3 / 1/√2 [sin 45 = 1/√2]
u = 3 * √2/1
u = 3√2
Use tangent ratio to find v:
tan 45 = 3/v
v = 3/tan 45
v = 3/1 [tan 45 = 1]
v = 3
27. Use sine ratio to find a:
sin 45 = a / 3√2
a = 3√2 * sin 45
a = 3√2 * 1/√2 [sin 45 = 1/√2]
a = 3/2
Use cosine ratio to find b:
cos 45 = b / 3√2
b = 3√2 * cos 45
b = 3√2 * 1/√2 [cos 45 = 1/√2]
b = 3/2
28. Use cosine ratio to find x:
cos 45 = 7 / x
x = 7/ cos 45
x = 7 / 1/√2 [cos 45 = 1/√2]
x = 7 * √2/1
x = 7√2
Use tangent ratio to find y:
tan 45 = y/7
y = 7 * tan 45
y = 7 * 1 [tan 45 = 1]
y = 7
29. Use sine ratio to find u:
sin 45 = u/10
u = 10 * sin 45
u = 10 * 1/√2 [sin 45 = 1/√2]
u = 10/√2
Rationalize
u = 5√2
Use cosine ratio to find v:
cos 45 = v/10
v = 10 * cos 45
v = 10 * 1/√2 [sin 45 = 1/√2]
v = 10/√2
Rationalize
v = 5√2
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Emily can read 75 words in 15 minutes how many words can she read per minute?
Emily can read 5 words per minute.
Minutes are often used to measure the duration of activities such as meetings, phone calls, or workouts. They are also used to express the duration of processes or events that occur over a short period of time.
To find out how many words Emily can read per minute, we need to divide the total number of words she can read by the amount of time it takes her to read them.
75 words in 15 minutes can be written as a ratio:
75 words / 15 minutes
To simplify this ratio, we can divide both the numerator and the denominator by 15:
(75 words / 15 minutes) ÷ (15 minutes / 15 minutes)
This gives us:
5 words / 1 minute
Therefore, Emily can read 5 words per minute.
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Consider the telephone tariff (charge) schedule by the telephone company: a. First examine the cost of an average phone call with the following charge schedule: each call is charged r for the initial period of length / (or fraction thereof). For call length exceeding !, you are charged incrementally for each subsequent period of length S(or fraction thereof), at a unit cost of p. What is the average cost of a call? (Note that it is a standard practice in the industry to assume that call duration is exponentially distributed.) b. If the cost of a call is $1 per minute, and your call is always pro-rated (as fraction of a minute) and the average call length is one minute, then the average cost of a call is just $1. If your call is rounded up to the next minute (I = S = 1), use the formula derived above to find the average cost. (Are you surprised?) c. If I = S = 0.1 (i.e., rounded up to the next 6 seconds), compute the average cost again.
The average cost of a call depends on the initial period, subsequent period, and unit cost for each subsequent period. By using the formula derived above, we can calculate the average cost of a call for different values of I, S, and p.
The average cost of a call can be calculated using the formula: Average Cost = r + p(S-1)/(S-1+1/e^S), where r is the cost for the initial period, p is the unit cost for each subsequent period, and S is the length of each subsequent period.
If the cost of a call is $1 per minute and the average call length is one minute, then the average cost of a call is just $1. However, if the call is rounded up to the next minute (I = S = 1), then the average cost can be calculated using the formula derived above: Average Cost = r + p(S-1)/(S-1+1/e^S) = $1 + $1(1-1)/(1-1+1/e^1) = $1 + $1(0)/(0+1/e) = $1.
If I = S = 0.1 (i.e., rounded up to the next 6 seconds), then the average cost can be calculated using the formula derived above: Average Cost = r + p(S-1)/(S-1+1/e^S) = $1 + $1(0.1-1)/(0.1-1+1/e^0.1) = $1 + $1(-0.9)/(-0.9+1/e^0.1) = $1.07.
Therefore, the average cost of a call depends on the initial period, subsequent period, and unit cost for each subsequent period. By using the formula derived above, we can calculate the average cost of a call for different values of I, S, and p.
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57. FO correct to two decimal places. (c) (d) Rectangle A X Rectangle B x+3 Two rectangles, A and B, each have an area of 11 cm². The length of rectangle A is x cm. The length of rectangle B is (x+3) cm. (a) Find, in terms of x, an expression for the width of i. Rectangle A Rectangle B (b) Given that the width of rectangle A is 2 cm greater than the width of rectangle B, form an equation in x and show that it simplifies to 2x² +6x-33=0. Solve the equation 2x² +6x-33=0, giving both answers correct to 2 decimal places. Hence find the width of rectangle B. Two docimal places N98/2/2b J99/2/7 N99/2/2c
By assuming and solving with the rectangle measurements, we get the equation, 2x^2 + 6x - 33 = 0.
Follow the steps below to reach the answer:
A region of 11 cm2 divides the two rectangles A and B.
Rectangle A has a length of x cm.
Rectangle B has a length of (x+3) cm.
Form an equation in x and demonstrate that it simplifies when given the fact that rectangle A's width is 2 cm bigger than rectangle B's width:
2x^2 + 6x - 33 = 0
Rectangle A's length and area being x and 11, respectively, results in the following for rectangle A's width: 11 / x
Rectangle B's length is equal to x + 3 and its area is equal to 11, hence its width is as follows: 11 / (x + 3)
Given that width of the rectangle, A is 2 cm Larger than the width of rectangle B, we obtain: 11/x = (11/ ( x + 3 ) ) + 2
In addition, based on the situation, we get
11/x - 11/ (x+3) = 2 cm
Let this be equation (1)
The main challenge at hand is to change this equation into the quadratic equation's standard form.
It is obtained by multiplying both sides of equation (1) by x*(x+3). As a result, you will get,
11*(x+3) - 11x = 2x*(x+3)
11x + 33 - 11x = 2x^2 + 6x
2x^2 + 6x - 33 = 0.
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There are 3 tanks each filled with 200 liters of water. There is a hole at the bottom of each tank through which water can be let out at a constant rate of 0. 2 liters per second. A person wants to empty the tanks one after another which means the hole of the next tank will be opened only after the previous tank is empty. Not including the time taken to open the holes of the tanks, what is the total time, in minutes, required to empty all three tanks?
The time taken to empty one tank is 1000 seconds or 16.67 minutes. Therefore, the total time required to empty all three tanks one after another is 50 minutes (16.67 minutes x 3).
The volume of water that can be emptied through the hole at the bottom of each tank per second is 0.2 liters. Therefore, the time taken to empty 200 liters of water from one tank is:
200 liters ÷ 0.2 liters per second = 1000 seconds
Converting the time to minutes:
1000 seconds ÷ 60 seconds per minute = 16.67 minutes
So, it takes 16.67 minutes to empty one tank. Multiplying this by three gives us the total time required to empty all three tanks:
16.67 minutes x 3 = 50 minutes
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please help urgently !
The required measure of y in the given triangle is 14 cm.
What are Similar triangles?Similar triangles are those triangles that have similar properties,i.e. angles and proportionality of sides.
Here,
Following the property of proportionality of sides in similar triangles,
8 + 3.2 / 8 = y / 10
11.2/8 = y / 10
112 = 8y
y = 14
Thus, the required measure of y in the given triangle is 14 cm.
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Knowledge Check Solve for v. -(4)/(v+5)=5 Simplify your answer as much as possible.
v = -29/5 is the simplest form of the (4)/(v+5)=5.
To solve for v, we need to isolate the variable on one side of the equation. We can do this by following these steps:
Step 1: Multiply both sides of the equation by (v+5) to get rid of the fraction. This gives us:
-(4) = 5(v+5)
Step 2: Distribute the 5 on the right side of the equation:
-(4) = 5v + 25
Step 3: Subtract 25 from both sides of the equation:
-29 = 5v
Step 4: Divide both sides of the equation by 5 to solve for v:
v = -29/5
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16) if a cylinder has a volume of 1884 cubic centimeters and a height of six cm, explain how to find the radius of the base circle. (Hint: work backwards and remember that r-squared means r x r )
Answer:
10 cm
Step-by-step explanation:
The volume of a cylinder is:
V = πr²h
Plug in the known values:
1884 cm³ = 3.14 × r² × 6 cm
Solve for r²:
r² = (1884 cm³)/(3.14 × 6 cm)
r² = 100 cm²
Solve for r:
r = √(100 cm²)
r = 10 cm
The students in Karen's class got to choose between pizza and burgers for the celebration on the last day of school. 15 students picked the pizza. If there are 20 students in all in Karen's class, what percentage of the students picked the pizza?
Write your answer using a percent sign (%).
By answering the supplied question, we may infer that the response is percentage Thus, pizza was chosen as the celebratory food by 75% of the pupils in Karen's class.
What is percentage?A ratio or value stated as a percentage of 100 is referred to as a percentage in mathematics. The abbreviations "pct.," "pct," and "pc" are also sporadically used. Nonetheless, the percentage symbol "%" is frequently used to denote it. The percentage amount is dimensionally empty. When the denominator is 100, percentages are essentially fractions. To show that a number is a percentage, a percent symbol (%) should be used next to it. For instance, you receive a 75% grade if you correctly answer 75 out of 25 questions (75/100) on a test. For percentage calculations, multiply the outcome by 100 after dividing the amount by the total. The percentage is calculated by multiplying (value/total) by 100%.
We must divide the number of students who chose pizza (15) by the total number of students (20) and multiply the result by 100 to determine the percentage of students who chose pizza:
(15/20) x 100 = 75%
Thus, pizza was chosen as the celebratory food by 75% of the pupils in Karen's class.
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Solve for x in the equation x squared minus 12 x + 59 = 0.
Answer:
x ∈ { ( 6 + [tex]\sqrt{23}[/tex] * i) , { ( 6 - [tex]\sqrt{23}[/tex] * i) }
Step-by-step explanation:
Given: [tex]x^2-12x+59=0[/tex]
First, collect like terms. [tex]x^2[/tex] and -12x, 59 and 0:
[tex]x^2-12x=0-59[/tex]
+59 is changed to -59 when transferred. Then subtract:
( x - 12 ) x = -59
Finally divide both sides by -59:
x ∈ { ( 6 + [tex]\sqrt{23}[/tex] * i) , { ( 6 - [tex]\sqrt{23}[/tex] * i) }
Help please
Look at the picture
Answer:
C
Step-by-step explanation:
Answer choice A implies that less than received an 80 or better, while according to the boxplot, at least 18 students did.
Answer choice B suggests that most students scored at least 90%, but that is false.
Answer choice C implies that the same number of students scored in the 70-80% range as in the 80-90% range, which is true according to the box plot.
Answer D says that more people scored 65-70% than 90-100%, but the opposite is true.
Solve for x by converting the logarithmic equation to exponential form. log_(3)(x)=-2 -6 -8 (1)/(9) -(1)/(9)
The solution for x is 1/(3^16).
To solve for x, we need to convert the logarithmic equation to exponential form. The general formula for converting a logarithmic equation to an exponential equation is:
log_b(x) = y => b^y = x
In this case, the base is 3, the exponent is -2 - 6 - 8 + (1/9) - (1/9), and x is the value we are trying to find. So, we can write the exponential equation as:
3^(-2 - 6 - 8 + (1/9) - (1/9)) = x
Simplifying the exponent gives us:
3^(-16) = x
Now, we can solve for x by taking the inverse of both sides:
x = 1/(3^16)
Therefore, the solution for x is 1/(3^16).
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