Suppose you deposit $1100 in an account with an annual interest rate of 8 % compounded quarterly: Use the formula 4 = P(1+#)" and round each answer to 2 decimal places, if necessary: Find an equation that gives the amount of money in the account after t years: A(t) Preview Find the amount of money in the account after 8 years After 8 years_ there will be $ in the account: c How many years will it take for the account to contain $2200? It will take years for there to be S2200 in the account: d. If the same account and interest were compounded continuously, how much money would the account contain after 8 years? With continuous compounding interest; there would be in the account after 8 years

The system of inequalities is correctly graphed on Shannon's graph.

Here we have the following system of inequalities:

y ≥ (1/2)*x - 1

x - y > 1

We can rewrite the second inequality as:

y < x - 1

Then the system becoimes:

y ≥ (1/2)*x - 1

y < x - 1

The first line will be one with positive slope, it is solid (due to the symbol ≥) and the shaded area is above the line.

For the second we will have a dashed line, and now the shaded area is below the dashed line.

From that, we caonclude that Shannon's graph is the correct one.

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If z varies jointly as x and y, then the value of z when x = 20 and y = 8 is 24.

When a variable varies jointly as two other variables, it means that the variable is directly proportional to the product of the two other variables.

In this case, we can use the formula:

z = kxy

where k is a constant of proportionality.

We can find the value of k by using the given values of z, x, and y:

6 = k(4)(10)

6 = 40k

k = 6/40

k = 3/20

Now that we know the value of k, we can use the formula to find z when x = 20 and y = 8:

z = (3/20)xy

z = (3/20)(20)(8)

z = (3)(8)

z = 24

Therefore, the value of z when x = 20 and y = 8 is 24.

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The Null Hypothesis (H0: μ ≤ 90) and Alternative Hypothesis (Ha). of the wait time for a new roller coaster is at least 90 minutes.

The null hypothesis states that a population parameter is equal to a value. The null hypothesis is often an initial claim that researchers specify using previous research or knowledge.

Null Hypothesis (H0): The wait time for a new roller coaster is equal to or less than 90 minutes (H0: μ ≤ 90).

Alternative Hypothesis (Ha): The wait time for a new roller coaster is greater than 90 minutes (Ha: μ > 90).

In words, the null hypothesis states that the average wait time for the new roller coaster is equal to or less than 90 minutes.

The alternative hypothesis states that the average wait time is greater than 90 minutes.

We use the symbol μ to represent the population means of wait times for the new roller coaster.

Therefore, the Null Hypothesis (H0: μ ≤ 90) and Alternative Hypothesis (Ha). of the wait time for a new roller coaster is at least 90 minutes.

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Answer:

B. 6

Step-by-step explanation:

3/4 can be added to itsef to be 6/8

6/8

----      6/1   = 6

1/8

Answer:

Step-by-step explanation:

tbh i don't know how to explain it but i feel like its D i multiply and add

The quadratic function written in vertex form is:

y = -1*(x - 1)^2

We know that the vertex of the parabola is (1, 0), so if the leading coefficient is a, we can write the vertex form:

y = a*(x - 1)^2 + 0

y = a*(x - 1)^2

In this case we know two points on the parabola, the vertex which is at(1, 0) and the y-intercept which is (0, -1).

Using the vertex (1, 0) we can write the parabola as:

y = a*(x - 1)^2 + 0

y = a*(x - 1)^2

Now we can use the values of the other point and replace this in the formula above so we get:

-1 = a*(0 - 1)^2

-1 = a

Then the quadratic function is:

y = -1*(x - 1)^2

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The result of the (3-3x^(3)-7x^(2))-(-2x^(2)-3x+7)  polynomial  is -3x^(3) - 5x^(2) + 3x - 4.

A polynomial is a mathematical expression consisting of variables and coefficients, that involves only the operations of addition, subtraction, multiplication, and non-negative integer exponents of variables.

To find the result of the given polynomials, we need to combine like terms. Like terms are terms that have the same variable and the same exponent.

Step 1: Distribute the negative sign to the second polynomial:
(3 - 3x^(3) - 7x^(2)) - (-2x^(2) - 3x + 7) = (3 - 3x^(3) - 7x^(2)) + (2x^(2) + 3x - 7)

Step 2: Combine like terms:
3 - 3x^(3) - 7x^(2) + 2x^(2) + 3x - 7 = -3x^(3) - 5x^(2) + 3x - 4

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Answer:

55/100 and 48/100, in decimal form it will be 0.55 and 0.48

Step-by-step explanation:

11/20 and 12/25

The common denominator in this question will be 100

55/100 and 48/100

Fοr the inequality 12 + 11/6x ≤ 5 + 3x, the cοrrect οptiοns are -

E. 6 ≤ x

F. The sοlutiοn set is (x l x∈R, x ≥ 6].

In Algebra, an inequality is a mathematical statement that uses the inequality symbοl tο illustrate the relatiοnship between twο expressiοns. An inequality symbοl has nοn-equal expressiοns οn bοth sides. It indicates that the phrase οn the left shοuld be bigger οr smaller than the expressiοn οn the right, οr vice versa.

Tο sοlve the inequality 12 + 11/6x ≤ 5 + 3x, we can fοllοw these steps -

Mοve all the terms cοntaining x tο οne side -

12 + 11/6x - 3x ≤ 5

Simplify the left-hand side -

72/6 + 11/6x - 18/6x ≤ 5

(72 + 11x - 18x)/6 ≤ 5

(72 - 7x)/6 ≤ 5

Multiply bοth sides by 6 tο eliminate the fractiοn -

72 - 7x ≤ 30

Mοve all the terms cοntaining x tο οne side -

72 - 30 ≤ 7x

42 ≤ 7x

Divide bοth sides by 7 (since 7 is pοsitive, we dοn't need tο flip the inequality) -

6 ≤ x

Therefοre, the cοrrect statement(s) and number line(s) that can represent the inequality are -

E. 6 ≤ x

F. The sοlutiοn set is (x ∈ R, x ≥ 6].

This means that the sοlutiοn set includes all real numbers greater than οr equal tο 6.

The interval nοtatiοn (6, ∞) cοuld alsο be used tο represent this sοlutiοn set.

Optiοn A is incοrrect because it οnly includes natural numbers (pοsitive integers), but the sοlutiοn set includes all real numbers greater than οr equal tο 6.

Optiοn B is incοrrect because it shοws a number line frοm -7 tο 7, which is nοt relevant tο the sοlutiοn set.

Optiοn C is incοrrect because it shοws an arrοw with a filled circle mοving tοwards pοsitive infinity, which implies that the sοlutiοn set is all pοsitive numbers, but the inequality οnly requires x tο be greater than οr equal tο 6.

Optiοn D is incοrrect because it is tοο limited in scοpe - it οnly tells us that the number substituted fοr x is greater than 6, but dοesn't give us the full sοlutiοn set.

Therefοre, οptiοn E and F are cοrrect.

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About 22,500 people at the Super Bowl game will not be wearing team jerseys.

Here the entire population is proportional to the number of people who entered the main gate without wearing team jerseys.

Find the proportion of people not wearing team jerseys by dividing 150 by 500. Now multiply the resultant proportion by the actual population.

Here we have

150 out of the first 500 people who entered the main gate were not wearing team jerseys,

The proportion of people not wearing team jerseys  

=> p = 150/500 = 0.3

Given that the sample is representative of the entire population of 75,000 people attending the game,

The population that will not be wearing team jerseys can be calculated as follows

75,000 x 0.3 = 22,500

Therefore,

About 22,500 people at the Super Bowl game will not be wearing team jerseys.

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Margin of error = 1.4

Sample mean = 13.4

=============================================================

Explanation:

To find the margin of error, we subtract the endpoints and divide by 2.

(b-a)/2 = (14.8-12.0)/2 = 1.4 is the margin of error

The b-a portion calculates the width of the confidence interval. It's the distance from one endpoint to the other. Splitting that in half gives the "radius" so to speak of this interval.

----------

The sample mean is at the midpoint of those given confidence interval endpoints.

The midpoint formula will have us add up the values and divide by 2

(a+b)/2 = (12.0+14.8)/2 = 13.4 is the sample mean

The a+b portion is the same as b+a, meaning we could have written that formula as (b+a)/2 as indicated in the next section.

-----------

Take note how similar each formula is:

The only difference is one has a minus sign and the other has a plus sign.

The answer is (C) No, the estimate should be less than $77.92.

Estimation cost refers to the process of approximating or calculating the cost of a project or service before it is actually carried out or completed. This is an important step in budgeting and financial planning, as it helps individuals and organizations to anticipate and prepare for the financial impact of a particular activity or initiative.

To determine if the estimate of $77.92 is reasonable, we can calculate the actual cost of printing 13 posters using the given information:

Setup fee: $14.21

Cost per poster: $3.90

Number of posters: 13

Total cost = setup fee + (cost per poster x number of posters)

Total cost = $14.21 + ($3.90 x 13)

Total cost = $14.21 + $50.70

Total cost = $64.91

We can see that the actual cost of printing 13 posters is $64.91, which is less than the estimated cost of $77.92. Therefore, the estimate of $77.92 is not reasonable and the answer is (C) No, the estimate should be less than $77.92.

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Answer:

Step-by-step explanation:

ISSA PARADE INSIDE MY CITY YEAHHHHH

solve for t to get t = 4

1. To find the derivative of f(x) = (3 – 2x^3)^3 we can apply the power rule, the chain rule, and the product rule. The power rule states that the derivative of f(x) = x^n is f'(x) = nx^n-1. The chain rule states that the derivative of f(x) = g(h(x)) is f'(x) = g'(h(x))*h'(x). The product rule states that the derivative of f(x) = uv is f'(x) = u'v + uv'. In this case, we can rewrite f(x) as f(x) = (h(x))^3 where h(x) = 3 - 2x^3. We then apply the chain rule to get f'(x) = 3(3 - 2x^3)^2(-6x^2). Similarly, we can find the derivative of f(t) = 100(6-t)/t+3. We can rewrite f(t) as f(t) = u(t)v(t) where u(t) = 100 and v(t) = (6-t)/t+3. Applying the product rule, we get f'(t) = 100(-1/(t+3)^2) + (6-t)(-1/(t+3)^2).

2. To find other information about a function, we can use the derivative we just found. For example, if we want to find the maximum or minimum values of a function, we can set the derivative equal to 0 and solve for the x or t values. In the case of f(x), we can set 3(3 - 2x^3)^2(-6x^2) = 0 and solve for x to get x = (sqrt(3/2))^(1/3). Similarly, for f(t) we can set 100(-1/(t+3)^2) + (6-t)(-1/(t+3)^2) = 0 and solve for t to get t = 4. We can also use derivatives to find the equation of a tangent line to a function at any given point. In this case, we would use the derivative we found in order to calculate the slope of the tangent line at any given point and then use point-slope form to find the equation of the line.

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The values of x if the distance between the points (x, 4) & (3, x) be 131/2 are approximately 9.39 and -4.39.

To find the values of x if the distance between the points (x, 4) & (3, x) be 131/2, we can use the distance formula:

D = √((x2 - x1)² + (y2 - y1)²)

Where D is the distance, (x1, y1) and (x2, y2) are the coordinates of the two points.

Plugging in the given values, we get:

131/2 = √((3 - x)² + (x - 4)²)

Squaring both sides and simplifying, we get:

169 = (3 - x)² + (x - 4)²

Expanding and rearranging, we get:

2x² - 14x - 110 = 0

Using the quadratic formula, we can find the values of x:

x = (-(-14) ± √((-14)² - 4(2)(-110))) / (2(2))

x = (14 ± √(196 + 880)) / 4

x = (14 ± √1076) / 4

x ≈ 9.39 or x ≈ -4.39

So the values of x are approximately 9.39 and -4.39.

Therefore, the values of x if the distance between the points (x, 4) & (3, x) be 131/2 are approximately 9.39 and -4.39.

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The result of the formula "20 - 4.65" is 15.35, which corresponds to the amount of change the customer gets.

Expressions are separated by mathematical sign i.e positive or negative.

The expression "20 - 4.65" represents the amount of change a customer would receive after ordering from the menu board.

The first part of the expression, "20", represents the amount of money the customer paid for their order. This is the total cost of the items they purchased from the menu board.

The second part of the expression, "4.65", represents the amount of money that the customer spent on their order. This is the subtotal of the items they purchased before tax and any other fees that may be added to the bill.

To calculate the change the customer receives, you subtract the amount the customer spent from the amount they paid. So in this case, the expression "20 - 4.65" gives us the answer of 15.35, which represents the amount of change the customer receives.

As for what the customer ordered, we cannot know for sure based on this expression alone. It's possible that the customer ordered a single item that cost exactly $4.65, or they may have ordered multiple items that added up to that subtotal. Without more information about the menu board and the prices of the items, it's impossible to determine exactly what the customer ordered.

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To divide two polynomials, P(x) and D(x), we can use either synthetic or long division. In this example, we'll use long division to divide P(x) by D(x) and express P in the form P(x)=D(x)⋅Q(x)+R(x).

First, we must make sure the degree of P(x) is greater than or equal to the degree of D(x). In this case, P(x)=-x^3-2x+6 and D(x)=x+1, so P(x) has a greater degree than D(x).

Next, we must write down P(x) and D(x) with the same degree. In this example, we can multiply D(x) by -x^2 to get -x^3+1. Then, P(x)=-x^3-2x+6 and D(x)=-x^3+1.

We can now start the long division process. First, we divide the leading coefficients, -1 and -1, so our quotient is 1. We then multiply the quotient by D(x), which gives us -x^3+1. We subtract this result from P(x), and the result is -2x+6.

Next, we divide the leading coefficients, -2 and -1, so our quotient is 2. We then multiply the quotient by D(x), which gives us -2x^2+2. We subtract this result from our previous result, -2x+6, and the result is 6.

Finally, we have reached the end of the long division process. Our quotient is Q(x)=2x+1 and our remainder is R(x)=6. Therefore, P(x)=D(x)⋅Q(x)+R(x), or -x^3-2x+6=(-x^3+1)⋅(2x+1)+6.

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The correct answer is option b. both the statement are false.


Given that A is a 3×3 matrix such that A^2 −5A+7I=O

Statement I: A^−1 = 1/2 (5I−A)

To find the inverse of a matrix, we need to multiply both sides of the equation by A^−1

A^−1(A^2 −5A+7I)=A^−1(O)

A−5I+7A^−1=O

A^−1=1/7(5I-A)

This statement is false because the inverse of matrix A is not equal to 1/2 (5I−A).

Statement II: The polynomial A^3−2A^2−3A+I can be reduced to 5(A−4I)

To reduce the polynomial, we need to factor it.

A^3−2A^2−3A+I=(A−1)(A^2−A−I)

This statement is also false because the polynomial A^3−2A^2−3A+I cannot be reduced to 5(A−4I).

Therefore, both statements are false and the correct answer is option b. both the statement are false.

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Answer:

10.39; 6

Step-by-step explanation:

Horizontal component= |v| Cos theta = 12 Cos 60° = 6

Vertical component= |v| Sin theta = 12 Sin 60° = 10.39

The continuous growth rate of a function is given by its derivative.

So, taking the derivative of f(x) with respect to x, we get:

f'(x) = 0.07e^(0.07x)

Therefore, the continuous growth rate of the function is 1.07.

Answer:

20

Step-by-step explanation:

The following unit multipliers are used:

1 loaf of bread = 400g of flour = 0.4kg of flour: [tex]\frac{0.4kg Of Flour}{1 loaf}[/tex]

1 day = 64 loaves of bread: [tex]\frac{64 loaves}{1 day}[/tex]

∴Mass of flour needed to last for 20 days:

[tex](20 days)[/tex]× [tex]\frac{64loaves}{1day}[/tex] ×[tex]\frac{0.4 kg}{1 loaf}[/tex]

  = 512 kg of flour

                  1 sack = 25 kg of flour

∴ x sacks of flour = 512 kg of flour

Cross-multiplication is applied:

(x sacks of flour)(25 kg of flour) = (1 sack)(512 kg of flour)

∴ x sacks of flour = [tex]\frac{(1 sack)(512kg Of Flour)}{25 kg Of Flour}[/tex]

                             = 20.48 sacks of flours

∴The minimum number of sacks = 20

The ratio of similarity  DEFG to TSRQ is '3: 1'.

Two quadrilaterals are considered similar if they have the same shape but may have different sizes. Similar quadrilaterals have corresponding angles that are congruent, and their corresponding sides are in proportion to each other.

The ratio of similarity is a measure of how much two geometric figures are enlarged or reduced to become similar.

Here we have

Quadrilateral DEFG and Quadrilateral TSRQ.

Where DEFG similar to TSRQ

Hence, the ratio of corresponding sides will be equal

=> DE/TS  = EF/SR  = FG/RQ = DG/TQ

=> 24/8  = 24/8  = 24/8 = 24/8 = 3/1

Therefore,

The ratio of similarity  DEFG to TSRQ is '3: 1'.

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a) To find the linear velocity of a point on the tip of one of the blades, we need to use the formula: V = 2πr/T where V is the linear velocity, r is the radius of the circle, and T is the period of rotation. In this case, the radius of the circle is the length of the propeller blades, which is 3 meters, and the period of rotation is the inverse of the frequency of rotation, which is 1/6 minutes. Plugging in the values, we get: V = 2π(3)/(1/6) = 36π meters per minute. To the nearest meter per minute, the linear velocity is approximately 113 meters per minute.

b) To find the arc length and the area of the circular sector, we need to use the formulas: Arc length = θr and Area = (θr^2)/2 where θ is the central angle in radians, and r is the radius of the circle. In this case, the central angle is 25 degrees, which is equivalent to (25π)/180 radians, and the radius of the circle is 12 cm. Plugging in the values, we get: Arc length = ((25π)/180)(12) = (5π)/3 cm and Area = (((25π)/180)(12^2))/2 = (25π)/3 cm^2. Therefore, the arc length is approximately 5.24 cm and the area is approximately 26.18 cm^2.

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Answer:

Step-by-step explana2 4

457

6.46

The LCD in this case is 2x^(2). So the solutions to the equation are x = 0 and x = 5.

To solve the equation, we first need to find the least common denominator (LCD) of all the fractions.

Next, we multiply each side of the equation by the LCD to eliminate the fractions:

2x^(2)*(x^(2)-x-6)/(x^(2)) = 2x^(2)*(x-6)/(2x) + 2x^(2)*(2x+12)/(x)

Simplifying the equation gives us:

2x^(2)-2x-12 = x^(2)-3x-12

Next, we move all the terms to one side of the equation:

x^(2)-5x = 0

Finally, we can factor the equation and set each factor equal to zero:

x(x-5) = 0

x = 0 or x = 5

So the solutions to the equation are x = 0 and x = 5.

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For the given cuboid, it's volume value is deduced as 30 cm³.

What is volume?

Each thing in three dimensions takes up some space. The volume of this area is what is being measured. The space occupied within an object's borders in three dimensions is referred to as its volume. It is sometimes referred to as the object's capacity.

The figure is given as a cuboid.

The length of the cuboid is 5 cm.

The breadth of the cuboid is 6 cm.

The height of the cuboid is 1 cm.

The formula for volume of cuboid is given as -

Volume = length × breadth × height

Substitute the values into the equation -

Volume = 5 × 6 × 1

Volume = 30 cm³

Therefore, the volume value is obtained as 30 cm³.

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The paper is 147/8 square inches in size. If preferred, this can be condensed to a mixed number or decimal.

A three-dimensional object's surface area is the sum of its sides. It is a measurement of the object's visible surface area. Depending on the shape of the item, different surface area formulas apply. For instance, adding the surface areas of all six sides of a rectangular prism will yield its surface area. The calculation for a rectangular prism's surface area is: Flat area equals 2lw + 2lh + 2wh where the rectangular prism's dimensions are l for length, w for breadth, and h for height.

given

The length and breadth of the postcard must be multiplied to determine its area.

The mixed integers must first be transformed into improper fractions:

5 1/4 = 21/4

3 1/2 = 7/2

We can now multiply:

Area is equal to length times breadth.

Area = (21/4) × (7/2)

Area = (21 × 7) / (4 x 2)

Area = 147/8

The paper is 147/8 square inches in size. If preferred, this can be condensed to a mixed number or decimal.

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The smallest positive integer value of m is 676.

To find the smallest positive integer value of m, we need to factor 52m into its prime factors and find the smallest value of m that makes 52m a perfect cube.

First, let's factor 52m into its prime factors:

52m = 2 * 2 * 13 * m

A perfect cube has all of its prime factors raised to the power of 3. So, in order for 52m to be a perfect cube, we need to have two more 2's, two more 13's, and two more m's.

This means that m must be equal to 2 * 2 * 13 * 13 = 676.

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Answer:

To find the derivative of the function y = x^2 - x + 3 using the first principle, we start by applying the definition of the derivative:

f'(x) = lim (h -> 0) [f(x+h) - f(x)] / h

where f(x) = x^2 - x + 3.

Now we substitute the function into the equation and simplify:

f'(x) = lim (h -> 0) [(x+h)^2 - (x+h) + 3 - (x^2 - x + 3)] / h

f'(x) = lim (h -> 0) [(x^2 + 2xh + h^2 - x - h + 3) - (x^2 - x + 3)] / h

f'(x) = lim (h -> 0) [2xh + h^2 - h] / h

Now we can cancel out the h in the numerator and denominator, leaving:

f'(x) = lim (h -> 0) [2x + h - 1]

Finally, we take the limit as h approaches 0:

f'(x) = 2x - 1

Therefore, the derivative of y = x^2 - x + 3 with respect to x is f'(x) = 2x - 1.

Step-by-step explanation:

Answer:

[tex]\dfrac{\text{d}y}{\text{d}x}=2x-1[/tex]

Step-by-step explanation:

Differentiating from First Principles is a technique to find an algebraic expression for the gradient at a particular point on the curve.

[tex]\boxed{\begin{minipage}{5.6 cm}\underline{Differentiating from First Principles}\\\\\\$\text{f}\:'(x)=\displaystyle \lim_{h \to 0} \left[\dfrac{\text{f}(x+h)-\text{f}(x)}{(x+h)-x}\right]$\\\\\end{minipage}}[/tex]

The point (x + h, f(x + h)) is a small distance along the curve from (x, f(x)). As h gets smaller, the distance between the two points gets smaller. The closer the points, the closer the line joining them will be to the tangent line.

To differentiate y = x² - x + 3 using first principles, substitute f(x + h) and f(x) into the formula:

[tex]\implies \displaystyle \dfrac{\text{d}y}{\text{d}x}=\lim_{h \to 0} \left[\dfrac{(x+h)^2-(x+h)+3-(x^2-x+3)}{(x+h)-x}\right][/tex]

Simplify the numerator:

[tex]\implies \displaystyle \dfrac{\text{d}y}{\text{d}x}=\lim_{h \to 0} \left[\dfrac{x^2+2hx+h^2-x-h+3-x^2+x-3)}{x+h-x}\right][/tex]

[tex]\implies \displaystyle \dfrac{\text{d}y}{\text{d}x}=\lim_{h \to 0} \left[\dfrac{2hx+h^2-h}{h}\right][/tex]

Separate into three fractions:

[tex]\implies \displaystyle \dfrac{\text{d}y}{\text{d}x}=\lim_{h \to 0} \left[\dfrac{2hx}{h}+\dfrac{h^2}{h}-\dfrac{h}{h}\right][/tex]

Cancel the common factor, h:

[tex]\implies \displaystyle \dfrac{\text{d}y}{\text{d}x}=\lim_{h \to 0} \left[\:2x+h-1\:\right][/tex]

As h → 0, the second term → 0:

[tex]\implies \dfrac{\text{d}y}{\text{d}x}=2x-1[/tex]

Answer: y = -5/3x + 4

Step-by-step explanation:

The slope intercept form is y = mx + b

The slope (m) is rise over run, so slope = -5/3

The y-intercept (b) is 4 because that is where the line intersects the y-axis at.

Hope this helps!