Suppose there is a 3Mbps uplink and 10Mbps downlink between a geostationary satellite and the base station on earth. If the propagation speed is the speed of light (3 * 10^8 m/sec), the packet size is 20Mb, and the distance from the satellite to earth is 36,000 km, what is the uplink propagation delay of the link in milliseconds

Answer:

Current through them, voltage across them.

Explanation:

Ohm's law states that at constant temperature, the current flowing in an electrical circuit is directly proportional to the voltage applied across the two points and inversely proportional to the resistance in the electrical circuit.

Mathematically, Ohm's law is given by the formula;

[tex] V = IR[/tex]

Where;

V represents voltage measured in voltage.

I represents current measured in amperes.

R represents resistance measured in ohms.

A resistor can be defined as an electronic component that opposes the free flow of current from one point to another in an electrical circuit.

In a series circuit of two resistors, the resistors have the same current through them; in a parallel circuit of two resistors, the resistors have the same voltage across them.

Answer:

The answer is below

Explanation:

Using Coulomb's law of electric field which is:

[tex]F=k\frac{q_1q_1}{r^2}\\\\ k =constant=9*10^9\ Nm^2/C^2,q_1=q_2=1.6*10^{-19}C,r=5.29*10^{-11}m\\\\Substituting\ gives:\\\\F=9*10^9*\frac{(1.6*10^{-19})*(1.6*10^{-19})}{(5.29*10^{-11})^2} =8.22*10^{-8}N\\\\Both\ centripetal\ force\ is\ given\ by:\\\\F=m\frac{v^2}{r} \\\\m = mass\ of \ electron=9.11*10^{-31}g,v=speed\ of\ electron\\\\F=m\frac{v^2}{r} \\\\v=\sqrt{\frac{F*r}{m} } \\\\subsituting:\\\\v=\sqrt{\frac{8.22*10^{-8}*5.29*10^{-11}}{9.11*10^{-31}} } \\\\v=2.18*10^6\ m/s\\\\[/tex]

[tex]But\ \omega=\frac{v}{r}=\frac{2.18*10^6}{5.29*10^{-11}} =4.13*10^{17}\\\\\omega=2\pi f; f=frequency\\\\f=\frac{\omega}{2\pi} =\frac{4.13*10^{17}}{2\pi} \\\\f=6.57*10^{15}\ Hz[/tex]

Answer:

C. The star is receding from you with the speed of 3000 km/s

Explanation:

To get this answer we use the doppler effect equation . The formula for a receding emissor is given in the attachment.

We solve for V

V = 3x10⁶m/s

V = 3000km/s

We have the wavelength to be shifting towards red. Therefore we conclude that it is receding. We say the star is receding with speed of 3000km/s towards you.

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Answer:

a. Momentum A = 280 Kgm/s.  

b. Momentum B = 595 Kgm/s.

c. Total momentum = 875 Kgm/s.

Explanation:

Let the two people be A and B respectively.

Given the following data;

Mass A = 70kg

Mass B = 85kg

Velocity A = 4m/s

Velocity B = 7m/s

Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.

Mathematically, momentum is given by the formula;

[tex] Momentum = mass * velocity [/tex]

a. To find the momentum of A;

[tex] Momentum \; A = 70 * 4 [/tex]

Momentum A = 280 Kgm/s.

b. To find the momentum of B;

[tex] Momentum \; B = 85 * 7 [/tex]

Momentum B = 595 Kgm/s.

c. To find the total momentum of the two persons;

[tex] Total \; momentum = Momentum \; A + Momentum \; B [/tex]

Substituting into the equation, we have;

[tex] Total momentum = 280 + 595 [/tex]

Total momentum = 875 Kgm/s.

Answer:

in this video waves are coming up for the BOTTOM to the top of the sandbar

Answer:

Answer:

Explanation:

Take base of the ground as origin .

component of initial velocity along i and j direction is 145 con23 and 145 sin23 . Along j , gravity acts but along i , no force acts .  

The path  of ball in vector form

s = (145 cos23- 14 )t  i + ( 2.5 + 145sin23 t - 1/2 g t² ) j

t is time period .

b )

vertical component of initial velocity = 145 sin 23 =

for vertical displacement

v² = u² - 2gH

For maximum height , v = 0

0 = (145 sin 23 )² - 2 g H , H is maximum height attained .

H = 3209.56 / 2 x 9.8

= 163.75 m

Total height attained = 163.75 + 2.5 = 166.25 m

if time be t for reaching maximum height

v = u -gt

0 = 145 sin 23 - gt

t = 145 sin23 / g

= 5.78 s

c )

For time of flight , vertical displacement = 2.5 m

2.5 = - 145 sin 23 t + 1/2 g t²

2.5 = -56.65 t + 4.9 t²

4.9 t² - 56.65 t - 2.5 = 0

t = 11.60s

horizontal displacement during this period = 145 cos23 x 11.60 = 1548.28 m

Range = 1548.28 m.

Answer:

c. A number and a unit

Explanation:

A scalar is a real number. We often use the term scalar in the context of vectors or matrices, to stress that a variable such as a is just a real number and not a vector or matrix.

Answer:

Explanation:

We shall represent each move of coach in vector form , considering unit vector i towards east and unit vector j towards north .

he drove 100 m North

First displacement D₁ = 100 j

200 m East to reach the 133

second displacement D₂ = 200 i

500 m North to reach Papa John's

third displacement

D₃ = 500 j

Total displacement ( resultant displacement )

= D₁ + D₂ + D₃

= 100 j + 200 i + 500 j

= 200 i + 600 j

magnitude of resultant displacement

= √ ( 200² + 600² )

= √ 40000 + 360000

= 632.45  m

Answer:

θ₂ = 40.5º

Explanation:

For this exercise we must use the law of refraction

         n₁ sin θ₁ = n₂ sin θ₂

where index 1 is for the incident ray and index 2 is for the refracted ray

in this case the incident ray has an angle of θ₁ = 60º and the refractive index of the water is

          n₂ = 1,333

        sin θ₂ = [tex]\frac{n_1}{n_2} \ sin \theta_1[/tex]

let's calculate

        sin  θ₂ = 1 / 1.3333 sin 60

        sin θ₂ = 0.64968

        θ₂ = sin⁻¹ (0.64968)

        θ₂ = 40.5º

Answer:

It's not connected to the negative end of the battery

Explanation:

To turn on it would need to connect to the positive (+) and negative (-) ends of the battery

Answer:

748.62 m /s.

Explanation:

mass of bullet m = .0051  kg .

mass of block M = 2.3 kg

block rises to a height of .07 m so velocity of block after collision

V = √ 2 gh

=√ (2 x 9.8 x .07 )

= 1.17 m /s

velocity of bullet after collision v = 221 m /s

Now we shall apply law of conservation of momentum to find out the velocity of bullet before collision .

Let it be Vx . then

5.1 x 10⁻³ x Vx + 0 = 5.1 x 10⁻³ x 221 + 2.3 x 1.17

= 1.127 + 2.691 = 3.818

Vx = 748.62 m /s

Answer:

The objects morion will remain the same

Explanation:

Answer:

The bulk modulus of the liquid is 1.534 x 10¹⁰ N/m²

Explanation:

Given;

density of the liquid, ρ = 1500 kg/m³

frequency of the wave, F = 410 Hz

wavelength of the sound, λ = 7.80 m

The speed of the wave is calculated as;

v = Fλ

v = 410 x 7.8

v = 3,198 m/s

The bulk modulus of the liquid is calculated as;

[tex]V = \sqrt{\frac{B}{\rho} } \\\\V^2 = \frac{B}{\rho}\\\\B = V^2 \rho\\\\B = (3,198 \ m/s)^2 \times 1500 \ kg/m^3\\\\B = 1.534 \ \times 10^{10} \ N/m^2[/tex]

Therefore, the bulk modulus of the liquid is 1.534 x 10¹⁰ N/m²

Answer:

a increases

Explanation:

as distance between two objects increases the gravitational force decreases so when distance decreases the gravitational force increases

Answer:

The heavier the object and the higher it is above the ground, the more gravitational potential energy it holds. Gravitational potential energy increases as weight and height increases. Potential energy is energy that is stored in an object or substance.

Answer:

case A) tau_net = -243.36 N m, case B)    tau_net = 783.36 N / m,      tau_net = -63.36 N m,  case C)  tau _net = - 963.36 N m,

Explanation:

For this exercise we use Newton's relation for rotation

         Σ τ  = I α

In this exercise the mass of the child is m = 28.8, assuming x = 1.5 m, the force applied by the man is F = 180N

we will assume that the counterclockwise turns are positive.

case a

         tau_net = m g x - F x2

          tau_nett = -28.8 9.8 1.5 + 180 1

         tau_net = -243.36 N m

in this case the man's force is downward and the system rotates clockwise

case b

2 force clockwise, the direction of

 the force is up

          tau_nett = -28.8 9.8 1.5 - 180 2

          tau_net = 783.36 N / m

in case the force is applied upwards

3) counterclockwise

        tau_nett = -28.8 9.8 1.5 + 180 2

         tau_net = -63.36 N m

system rotates clockwise

case c

2 schedule

 tau_nett = -28.8 9.8 1.5 - 180 3

 tau _net = - 963.36 N m

3 counterclockwise

       tau_nett = -28.8 9.8 1.5 + 180 3

       tau_net = 116.64 Nm

the sitam rotated counterclockwise

Answer:

a

Explanation:

AAAA

Answer:

Explanation:

Let v be the velocity acquired by electron in electric field

V q = 1/2 m v²

V is potential difference applied on charge q , m is mass of charge , v is velocity acquired

2400 x 1.6 x 10⁻¹⁹ = .5 x 9.1 x 10⁻³¹ x v²

v² = 844 x 10¹²

v = 29.05 x 10⁶ m /s

Maximum force will be exerted on moving electron when it moves perpendicular to magnetic field .

Maximum force = Bqv , where B is magnetic field , q is charge on electron and v is velocity of electron

= 1.7 x 1.6 x 10⁻¹⁹ x 29.05 x 10⁶

= 79.02 x 10⁻¹³ N .

Minimum force will be zero when electron moves along the direction of magnetic field .

(a) The maximum force on the  electron due to the magnetic field will be  F= 79.02 x 10⁻¹³ N .

(b) Minimum force will be zero when electron moves along the direction of magnetic field .

Whenever a current is passes through a wire then the magnetic fields are generated around the wire and if any other charged particle comes under the influence of this magnetic field then the magnetic force is applied in the charge.

Let v be the velocity acquired by an electron in electric field

[tex]Vq=\dfrac{1}{2}mv^2[/tex]

V is potential difference applied on charge q ,

m is mass of charge ,

v is velocity acquired

2400 x 1.6 x 10⁻¹⁹ = .5 x 9.1 x 10⁻³¹ x v²

v² = 844 x 10¹²

v = 29.05 x 10⁶ m /s

Maximum force will be exerted on the moving electron when it moves perpendicular to the magnetic field .

Maximum force = Bqv , where B is magnetic field , q is charge on an electron and v is velocity of electron

F=Bqv

F= 1.7 x 1.6 x 10⁻¹⁹ x 29.05 x 10⁶

F= 79.02 x 10⁻¹³ N .

Minimum force will be zero when electron moves along the direction of magnetic field .

Hence the maximum force on the  electron due to the magnetic field will be  F= 79.02 x 10⁻¹³ N and the Minimum force will be zero when electron moves along the direction of magnetic field .

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Answer:

Explanation:

d = rt only works for calculating average speeds.

100 = r(140)

r = 0.714 m/s

Answer: 0.71m/s

Explanation:

Formula: Speed = Distance/time

Speed = 100m/140s

Speed = 100/140 / 20/20

Speed = 5/7 or 0.71m/s

Answer:

the average drift speed of the mobile electrons in the metal is 1.089 x 10⁻⁴ m/s.

Explanation:

Given;

mobility of the mobile electrons in the metal, μ = 0.0033 (m/s)/(N/C)

the electric field strength inside the cube of the metal, E = 0.033 N/C

The average drift speed of the mobile electrons in the metal is calculated as;

v = μE

v =  0.0033 (m/s)/(N/C) x 0.033 N/C

v = 1.089 x 10⁻⁴ m/s.

Therefore, the average drift speed of the mobile electrons in the metal is 1.089 x 10⁻⁴ m/s.

Answer:

The knights will collide at 43.854 meters relative to Sir George's starting point.

Explanation:

Let suppose that initial positions of Sir George and Sir Alfred are 0 and 84.1 meters, respectively. If both knights accelerate uniformly, then we have the following kinematic formulas:

Sir George

[tex]x_{G} = x_{G,o}+v_{o,G}\cdot t + \frac{1}{2}\cdot a_{G}\cdot t^{2}[/tex] (1)

Sir Alfred

[tex]x_{A} = x_{A,o}+v_{o,A}\cdot t + \frac{1}{2}\cdot a_{A}\cdot t^{2}[/tex] (2)

Where:

[tex]x_{G,o}[/tex], [tex]x_{A,o }[/tex] - Initial position of Sir George and Sir Alfred, measured in meters.

[tex]x_{G}[/tex], [tex]x_{A}[/tex] - Final position of Sir George and Sir Alfred, measured in meters.

[tex]v_{o,G}[/tex], [tex]v_{o,A}[/tex] - Initial velocity of Sir George and Sir Alfred, measured in meters per second.

[tex]t[/tex] - Time, measured in seconds.

[tex]a_{G}[/tex], [tex]a_{A}[/tex] - Acceleration of Sir George and Sir Alfred, measured in meters per square second.

Both knights collide when [tex]x_{G} = x_{A}[/tex], then we simplify this system of equations below:

[tex]x_{G,o} + v_{o,G}\cdot t + \frac{1}{2}\cdot a_{G}\cdot t^{2} = x_{A,o}+v_{o,A}\cdot t + \frac{1}{2}\cdot a_{A}\cdot t^{2}[/tex]

[tex](x_{A,o}-x_{G,o}) +(v_{o,A}-v_{o,G})\cdot t +\frac{1}{2}\cdot (a_{A}-a_{G})\cdot t^{2} = 0[/tex] (3)

If we know that [tex]x_{A,o} = 84.1\,m[/tex], [tex]x_{G,o} = 0\,m[/tex], [tex]v_{o,A} = 0\,\frac{m}{s}[/tex], [tex]v_{o,G} = 0\,\frac{m}{s}[/tex], [tex]a_{A} = -0.289\,\frac{m}{s^{2}}[/tex] and [tex]a_{G} = 0.316\,\frac{m}{s^{2}}[/tex], then we have the following formula:

[tex]84.1 -0.303\cdot t^{2} = 0[/tex] (4)

The time associated with collision is:

[tex]t \approx 16.660\,s[/tex]

And the point of collision is:

[tex]x_{G} = 0\,m + \left(0\,\frac{m}{s} \right)\cdot (16.660\,s)+ \frac{1}{2}\cdot \left(0.316\,\frac{m}{s^{2}} \right) \cdot (16.660\,s)^{2}[/tex]

[tex]x_{G} = 43.854\,m[/tex]

The knights will collide at 43.854 meters relative to Sir George's starting point.

Answer: m/s

Explanation:

The slope is the change in y over the change in x. If the graph is velocity over time, then the units will be meters per second

Answer:

it spins

Explanation:

like a lot, bro i was on one before and it was pretty nice :)

Answer:

5 atoms of Boron

Explanation:

Boron makes up approximately 15.944% of the mass and the rest of the 84.056% is Fluorine. There is 5 Atoms because Boron atomic mass is 10.811 in 1 molecule of BF3 and you wanted 5 Molecules.

To see the number of atoms of an element in a given molecule we need to multiply stoichiometry to the number that is written on the foot of the element that is stoichiometry. Therefore, in 5 molecules of  BF[tex]_3[/tex], the number of boron atoms is 5.

Atom is the smallest particle of any element, molecule or compound. Atom can not be further divided. Atoms contains nucleus in its center and electron that revolve around the atom in fixed orbit.

In the nucleus, proton and neutron are present. Electron has -1 charge while proton has +1 charge. Neutron is neutral that is it has no charge. So overall the charge of nucleus is due to only proton, not by neutron.

In one molecule of  BF[tex]_3[/tex], the number of boron atoms is 1. So, in 5 molecules of   BF[tex]_3[/tex], the number of boron atoms is 5.

Therefore, in 5 molecules of   BF[tex]_3[/tex], the number of boron atoms is 5.

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Answer:

1.13%

explanation:

work output/work input =100%

._.Answer:.

ijji._. ji

Explanation:.

ok so i dont know srry5