Suppose the National Transportation Safety Board (NTSB) wants to examine the safety of compact cars, midsize cars, and full-size cars. It collects a sample of three for each of the treatments (cars types). Using the hypothetical data provided below, test whether the mean pressure applied to the driver’s head during a crash test is significantly different for each type of car. Use α = 5% to hand calculate and check your work in SPSS.

Compact Cars Midsize Cars Full-Size Cars

6 4 9

6 4 8

7 5 5

Answers

Answer 1

Answer:

The mean pressure applied to the driver’s head during a crash test is not significantly different for each type of car.

Step-by-step explanation:

A one-way ANOVA is used to test whether there is significant difference between the means for more than two groups.

In this case we need to test whether the mean pressure applied to the driver’s head during a crash test is significantly different for each type of car.

So, a one-way ANOVA would be used.

The hypothesis can be defined as follows:

H₀: There is no difference between the means, i.e. [tex]\mu_{1}=\mu_{2}=\mu_{3}[/tex]

Hₐ: There is a significant difference between the means, i.e. at least one of the mean is different.

Use MS-Excel to perform the ANOVA test.

Go to Data – Data Analysis – Anova: Single Factor

Enter the data and enter Alpha as 0.05.

Press OK.

The output is attached below.

The F-test statistic value is, F = 5.143.

The p-value of the test is, p-value = 0.072.

Decision Rule:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected.

p-value = 0.072 > α = 0.05

The null hypothesis will not be rejected.

Conclusion:

The mean pressure applied to the driver’s head during a crash test is not significantly different for each type of car.

Suppose The National Transportation Safety Board (NTSB) Wants To Examine The Safety Of Compact Cars,

Related Questions

PLEASE ASAP There are 20 players on a soccer team. From them, a captain and an alternate captain have to be chosen. How many possibilities are there?

Answers

Answer: 380

Step-by-step explanation:

Total number of players = 20

To select a captain and a vice captain :

One captain from a total of 20 players :

20 combination 1 = 20C1 = 20 ways

Total number of players left after selecting a captain = 20 - 1 = 19

Number of players left from which to select a vice captain = 19

Therefore, one vice captain from a group of 19 players :

19 combination 1 = 19C1 = 19 ways

Therefore no of different possible ways to select a captain and a vice captain :

20C1 × 19C1 = 20 × 19 = 380 Ways

do these problems and get 100 points 1. Given the lengths of two sides of a triangle, find the range for the length of the third side. (Range means find between which two numbers the length of the third side must fall.) Write an inequality. c 22 and 15 2 Given the lengths of two sides of a triangle, find the range for the length of the third side. (Range means find between which two numbers the length of the third side must fall.) Write an inequality. d 13.2 and 6.7 3 Given the lengths of two sides of a triangle, find the range for the length of the third side. (Range means find between which two numbers the length of the third side must fall.) Write an inequality. e 34 and 12 4 Given the lengths of two sides of a triangle, find the range for the length of the third side. (Range means find between which two numbers the length of the third side must fall.) Write an inequality. f 23 and 44

Answers

Answer:

[tex]7 < x < 37[/tex] -- Triangle 1

[tex]6.5 < x < 19.9[/tex] -- Triangle 2

[tex]22 < x < 46[/tex] -- Triangle 3

[tex]21 < x < 67[/tex] -- Triangle 4

Step-by-Step Explanation:

Given

2 sides of a triangle

1. 22 and 15

2. 13.2 and 6.7

3. 34 and 12

4. 23 and 44

Required

Determine the range of the third side in the above triangles

Triangle 1: 22 and 15

Represent the third side with x

We'll make use of the following conditions to calculate  the range of the third side;

[tex]22 + x > 15[/tex]

[tex]22 + 15 > x[/tex]

[tex]15 + x > 22[/tex]

Solving

[tex]22 + x > 15[/tex]

Make x the subject of formula

[tex]x > 15 - 22[/tex]

[tex]x > -7[/tex]

Solving

[tex]22 + 15 > x[/tex]

[tex]37 > x[/tex]

Solving

[tex]15 + x > 22[/tex]

Make x the subject of formula

[tex]x > 22 - 15[/tex]

[tex]x > 7[/tex]

The next step is to dismiss the inequality with negative digit; So, we're left with

[tex]37 > x[/tex] and [tex]x > 7[/tex]

Rewrite both inequalities

[tex]x < 37[/tex] and [tex]7 < x[/tex]

Combine the two inequalities

[tex]7 < x < 37[/tex]

Triangle 2:  13.2 and 6.7

Represent the third side with x

We'll make use of the following conditions to calculate  the range of the third side;

[tex]13.2 + x > 6.7[/tex]

[tex]13.2 + 6.7 > x[/tex]

[tex]6.7 + x > 13.2[/tex]

Solving

[tex]13.2 + x > 6.7[/tex]

Make x the subject of formula

[tex]x > 6.7 - 13.2[/tex]

[tex]x > -6.5[/tex]

Solving

[tex]13.2 + 6.7 > x[/tex]

[tex]19.9 > x[/tex]

Solving

[tex]6.7 + x > 13.2[/tex]

Make x the subject of formula

[tex]x > 13.2 - 6.7[/tex]

[tex]x > 6.5[/tex]

The next step is to dismiss the inequality with negative digit; So, we're left with

[tex]19.9 > x[/tex] and [tex]x > 6.5[/tex]

Rewrite both inequalities

[tex]x < 19.9[/tex] and [tex]6.5 < x[/tex]

Combine the two inequalities

[tex]6.5 < x < 19.9[/tex]

Triangle 3:  34 and 12

Represent the third side with x

We'll make use of the following conditions to calculate  the range of the third side;

[tex]34 + x > 12[/tex]

[tex]34 + 12 > x[/tex]

[tex]12 + x > 34[/tex]

Solving

[tex]34 + x > 12[/tex]

Make x the subject of formula

[tex]x > 12 - 34[/tex]

[tex]x > -22[/tex]

Solving

[tex]34 + 12 > x[/tex]

[tex]46 > x[/tex]

Solving

[tex]12 + x > 34[/tex]

Make x the subject of formula

[tex]x > 34 - 12[/tex]

[tex]x > 22[/tex]

The next step is to dismiss the inequality with negative digit; So, we're left with

[tex]46 > x[/tex] and [tex]x > 22[/tex]

Rewrite both inequalities

[tex]x < 46[/tex] and [tex]22 < x[/tex]

Combine the two inequalities

[tex]22 < x < 46[/tex]

Triangle 4:  23 and 44

Represent the third side with x

We'll make use of the following conditions to calculate  the range of the third side;

[tex]23 + x > 44[/tex]

[tex]23 + 44 > x[/tex]

[tex]23 + x > 44[/tex]

Solving

[tex]23 + x > 44[/tex]

Make x the subject of formula

[tex]x > 23 - 44[/tex]

[tex]x > -21[/tex]

Solving

[tex]23 + 44 > x[/tex]

[tex]67 > x[/tex]

Solving

[tex]23 + x > 44[/tex]

Make x the subject of formula

[tex]x > 44 - 23[/tex]

[tex]x > 21[/tex]

The next step is to dismiss the inequality with negative digit; So, we're left with

[tex]67 > x[/tex] and [tex]x > 21[/tex]

Rewrite both inequalities

[tex]x < 67[/tex] and [tex]21 < x[/tex]

Combine the two inequalities

[tex]21 < x < 67[/tex]

The baseball team has a double-header on Saturday. The probability that they will win both games is 50%. The probability that they will win just the first game is 65%, What is the probability that the team will win the 2nd game given that they have already won the first game? (PLEASE SHOW YOU'RE WORK)

Answers

Answer:

77%

Step-by-step explanation:

Given the following :

Probability of winning both games = 50%

Probability of winning just the first game = 65%

Let the probability of winning the ;

First game = p(A) = 65%

Second game = p(B)

Both games = p(A and B) = 50%

What is the probability that the team will win the 2nd game given that they have already won the first game

The above question is a conditional probability question :

Probability of winning the second Given that they've already won the first = p(B | A)

p(B | A) = (A and B) / p(A)

p(B | A) = 50% / 65%

p(B | A) = 0.5 / 0.65

p(B | A) = 0.7692307

= 76.9% = 77%

The formula for the volume of a pyramid is =13ℎ
V
=
1
3
B
h
, where B is the area of the base and h is the height. Rearrange the formula to solve for the height (h).
Select one:
a. ℎ=3
h
=
3
V
B

b. ℎ=3
h
=
B
3
V

c. ℎ=3
h
=
V
3
B

d. ℎ=3

Answers

Answer:

h = V3B

Step-by-step explanation:

V = 1/3B · h

Divide volume by 1/3 B to get h by itself

V/1/3B = V3B

A steel wire, when bent in the form of a square, encloses an area of 121 sq cm. The same wire

is bent, in the form of a circle. Find the area of the circle.

Answers

Answer:

A = 49[tex]\pi[/tex]

Step-by-step explanation:

First, we need to find the length of the wire. We can calculate this because we are given the area of the square, so we can work backwards.

Use the area formula and plug in the numbers:

A = s²

121 = s²

11 = s

We can calculate the length of the wire by multiplying 11 by 4, which is 44.

Now, we know the circumference of the circle is 44 units because that is how long the wire is.

We can work backwards again to find the radius, using the circumference formula:

C = 2[tex]\pi[/tex]r

44 = 2[tex]\pi[/tex]r

22 = [tex]\pi[/tex]r

7 = r

Now, we can find the area of the circle:

A = [tex]\pi[/tex]r²

A = [tex]\pi[/tex](7)²

A = 49[tex]\pi[/tex]

Hi May I know how to solve this step by step please

Answers

Answer:

2, 3 , 5, 7

Step-by-step explanation:

2(x - 2)/3 < (x + 1)/2 < 3(5x + 6)/4

Considering:

    2(x - 2)/3 < (x + 1)/2

<=>(2x - 4)/3 < (x + 1)/2

<=> (2x - 4)*2 < (x + 1)*3

<=> 4x - 8 < 3x + 3

<=> 4x - 3x < 8 + 3

<=> x < 11

Considering:

     (x + 1)/2 < 3(5x + 6)/4

<=>(x + 1)/2 < (15x + 18)/4

<=>(x + 1)*4 < (15x + 18)*2

<=> 4x + 4 < 30x + 36

<=> 4x - 30x < 36 - 4

<=> -26x < 32

<=> 26x > -32

<=> x > -32/26

=> -32/26 < x < 11

The prime numbers satisfy the above inequalities: 2, 3 , 5, 7

The graph for the equation y = x minus 4 is shown below. On a coordinate plane, a line goes through (0, negative 4) and (4, 0). Which equation, when graphed with the given equation, will form a system that has an infinite number of solutions? y minus x = negative 4 y minus x = negative 2 y minus 4 = x y + 4 x = 1 Brainliest reward

Answers

Answer:

The correct option is;

y minus x = negative 4

(y - x = -4)

Step-by-step explanation:

Given that the line y  = x - 4 of the graph passes through the points (0, -4) and (4, 0)

Comparing with the general equation of a straight line, y = m·x + c, where m is the slope and c is the y-intercept gives;

The slope of the equation y = x - 4 = 1

The y-intercept of the equation y = x - 4 = -4

Two equations will have an infinite number of solutions when they are on the same line, that is having the same slope and intercept, we check for the slope and the intercept of the given options as follows;

For y - x = -4, we have;

y = x - 4 which is the same as the given equation and both equations will have an infinite number of solutions

For y - x = -2 we have;

y = x - 2

The slope is the same as the given equation but the intercept is different giving no solution

For y - 4 = x, we have;

y = x + 4

The slope is the same as the given equation but the intercept is different giving no solution

For y + 4x = 1, we have;

y = 1 - 4x

The slope and  intercept are different giving one solution.

Answer:

y - x = -4

Step-by-step explanation:

PLEASE ANSWER THIS FAST Will the red square and the orange square always equal the blue square? What colored square is the hypotenuse?

Answers

Step-by-step explanation:

The area of the blue square will always equal the sum of the area of the orange and red rectangles

The pythagorian theorem:

a²+b² = c²

now let a be the side of the red triangle and b the side of the orange one

so a² is the area of the red triangle and b² is the area of the orange one

Let c be the side of the blue rectangle

so c² is the area of it

then what we concluded is right

the hypotenuse is the blue side since it is the larger one

aljebra questions anum counted the money she had in her purse and money box . When she doubbled the amount in her purse and add it to the amount in money box she gets rs 1700 . When she triples the amount in her purse and add in to money box she gets rs 2200. How much money does she have in her purse

Answers

Answer:

Money in her purse is Rs. 500.

Step-by-step explanation:

Let the money in her purse = Rs. [tex]x\\[/tex]

Let the money in her Money box = Rs. [tex]y[/tex]

As per question statement,

Double the money in her purse (i.e. [tex]2 \times x[/tex]) and add it to the amount in money box, she gets Rs. 1700.

[tex]2x+y=1700[/tex]  ........ (1)

Triple the money in her purse (i.e. [tex]3\times x[/tex]) and add it to amount in money box ([tex]y[/tex]), she gets Rs. 2200.

[tex]3x+y=2200[/tex] ....... (2)

To find: Money in her purse = ? i.e. [tex]x=?[/tex]

Let us solve for [tex]x[/tex] using the two linear equations.

We can use substitution method here i.e. find value of one variable from one equation and then substitute that value in other equation.

Using equation (1), we get the value of [tex]y[/tex] as follows:

[tex]y=1700-2x[/tex]

Now, let us put this value of y in equation (2) to find the value of [tex]x[/tex]:

[tex]3x+1700-2x=2200\\\Rightarrow x+1700 = 2200\\\Rightarrow x=2200-1700\\\Rightarrow x = Rs.\ 500[/tex]

Money in her purse is Rs. 500.

Jaden learns to perform 2 vocal pieces during each week of lessons . How many weeks of lessons will Jaden need before he will be able to sing a total of 24 pieces?

Answers

Answer:

12 weeks

Step-by-step explanation:

To solve this, all you need to do is divided 24 pieces by the two he learns per week. You'll then find it will take him 12 weeks

Factor the polynomial expression x2 + 5.

Answers

Answer:

Step-by-step explanation:

Please write this as x^2 + 5.  

Roots are ±i√5.

The corresponding factors of x^2 + 5 are (x + i√5) and (x - i√5)

Ashok and Brian are both walking east along the same path; Ashok walks at a faster constant speed than does Brian. If Brian starts 30 miles east of Ashok and both begin walking at the same time, how many miles will Brian walk before Ashok catches up with him

Answers

Answer:

60 miles

Step-by-step explanation:

Ashok and Brian are both walking east along the same path; Ashok walks at a faster constant speed than does Brian. If Brian starts 30 miles east of Ashok and both begin walking at the same time, how many miles will Brian walk before Ashok catches up with him?

Statement 1. Brian’s walking speed is twice the difference between Ashok’s walking speed and his own

Statement 2. If Ashok’s walking speed were five times as great, it would be three times the sum of his and Brian’s actual walking speeds

Solution

A. Brian’s walking speed is twice the difference between Ashok’s walking speed and his own.

Let Brian speed=b

Ashok speed=a

Brian's walking speed=2(a-b)

b=2(a-b)

Divide both sides by 2

b/2=a-b

Ashok catches up in (time)= distance /( relative rate

=30/(a-b)

=30/(b/2)

=30÷b/2

=30*2/b

=60/b.

By that time Brian will cover a distance of

distance=rate*time

=b*60/b

=2(a-b)*60/2(a-b)

=60 miles

(2) If Ashok’s walking speed were five times as great, it would be three times the sum of his and Brian’s actual walking speeds.

5a=3(a+b)

5a=3a+3b

5a-3a=3b

2a=3b

An integer minus 5 times its reciprocal is
76
9
What is the integer?

Answers


Answer: The only one of these that's an integer is 9.

Explanation: Let X be the integer. Then

X - 3/X = 26/3. Multiplying by 3X on both sides:

3X^2 - 9 = 26X

3X^2 - 26X - 9 = 0

X = (26 +/- SQRT(26^2-(4*(-27))))/6 = (26 +/- 28) / 6,

so the two solutions for X are 1/3 and 54/6 = 9.

What is the slope of the line through the points (2,8) and (5,7)

Answers

Answer:

-1/3

Step-by-step explanation:

The slope of the line can be found by

m = (y2-y1)/(x2-x1)

    = ( 7-8)/(5-2)

    = -1/3

Answer:

-1/3.

Step-by-step explanation:

The slope can be found by doing the rise over the run.

In this case, the rise is 8 - 7 = 1.

The run is 2 - 5 = -3.

So, the slope is 1 / -3 = -1/3.

Hope this helps!

wht is the solution of the system defined be y =-x+5 and 5x+2y=14

Answers

Answer:

1.33,3.667

Step-by-step explanation:

Use y=mx+b for second system

which is y=5/2x+7

Now use substitution,graph, or elimination method.

Instructions: Find the measure of the indicated angle to the
nearest degree

Answers

Answer:

? = 23

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

tan ? = opp/ adj

tan ? = 3/7

take the inverse tan of each side

tan ^-1 tan ? = tan ^-1 ( 3/7)

? = 23.19859051

To the nearest degree

? = 23

What is the maximum value of the function f(x)=-x^2+6x+1 (enter an exact number) rotate image to see the problem

Answers

Answer:

10

Step-by-step explanation:

f(x)=-x^2+6x+1

This is a parabola that opens downward( the - coefficient of x^2)

The maximumx is at the vertex

The x coordinate is at

-b/2a  where ax^2 + bx +c  a =-1  b=6 c=1

-6/(2*-1)

-6/-2 = 3

The x coordinate of the vertex is 3

f(3) = - (3)^2 +6(3)=1

    = -9+18+1

    = 10

The vertex is ( 3,10)

The maximum value is 10

Answer:

[tex]10[/tex]

Step-by-step explanation:

[tex]f(x)=-x^2+6x+1[/tex]

x coordinate:

[tex]\frac{-b}{2a}[/tex]

[tex]a=-1\\b=6[/tex]

[tex]\frac{-6}{2(-1)} \\\frac{-6}{-2}\\ =3[/tex]

y-coordinate:

[tex]f(3)=-(3)^2+6(3)+1\\f(3)=-9+18+1\\f(3)=10[/tex]

griffin ordered a pair of sneakers online. he had 16 credit that he applied toward the purchase, and then he used a credit card to pay for the rest of the cost. if the the shoes cost 80, then how much did griffin charge to his credit card when he bought the sneakers? PLEASE ANSWER I BEG Y'ALL

Answers

Answer: Griffin charge $79.854 to his credit card when he bought the sneakers.

Step-by-step explanation:

Griffin ordered a pair of sneakers online.

Value of each credit point = 1 cent

Then , value of 16 credit points = 16 cents = $0.16 [1$ = 100 cents]

Cost of shoes = Rs $80

Charge to credit card = (Cost of shoes) - (Value of 16 credit points)

= $(80-0.16)

= $79.84

Hence, Griffin charge $79.854 to his credit card when he bought the sneakers.

Question 4. In the graph, lines f and g intersect at P(6,6). What is the area, in square units, of the shaded region? * E. 15 F. 21 G. 27 H. 30

Answers

Answer:

E

Step-by-step explanation:

i guess the dotted lines outline a square

so get the area of the square which is 6×6=36

then don't focus on the shaded part but unshaded you'll see two right angled triangles

[tex]a = 1 \div2b \times h[/tex]

you will get a total for both as 21

then get the area of the square 36-21=15

so the area becomes 15

Which equation represents a line that is perpendicular to line FG? A. y=-1/2x+5 B. y=1/2x+2 C. y=-2x-3 D. y=2x-6

Answers

The equation of line which is perpendicular to the line FG is

y = -2x -3.

What is equation of line?

The equation of line is an algebraic form of representing the set of points, which together form a line in a coordinate system.

Formula for finding the equation of line from two points [tex](x_{1} ,y_{1} ) and (x_{2}, y_{2} )[/tex]

[tex](y -y_{1}) = \frac{y_{2}-y_{1} }{x_{2} -x_{1} } (x-x_{1} )[/tex]

What is the slope of two perpendicular lines?

If [tex]m_{1}[/tex] be the slope of one line, then the slope of the perpendicular line is [tex]\frac{-1}{m_{1} }[/tex].

What is the slope intercept form of a line ?

The slope intercept form of the line is given by  y = mx + b

Where, m is the slope of a line.

According to the given question

We have a line FG and the coordinates of points F and G are (-5,1) and (9,8) respectively.

Therefore, the slope of the line FG = [tex]\frac{8-1}{9+5}=\frac{7}{14} =\frac{1}{2}[/tex]

⇒ The slope of the line which is parallel to line FG is -2

Now, from the given option of the equation of line , y = -2x -3 has a slope of -2 .

Hence, the equation of line which is perpendicular to the line FG is

y = -2x -3.

Learn more about the equation of a perpendicular line here:

https://brainly.com/question/20712656

#SPJ2

Suppose you are interested in testing wheter the mean earning of men in the general social survey is representative of the earning of the entire U.S. Male population. If there are 372 men in the general social survey sample and approximately 128 million men in the population, calculate the degrees of freedom for this single-sample t test.

Answers

Answer:

371

Step-by-step explanation:

According to the given situation the calculation of degrees of freedom for this single-sample t test is shown below:-

Degrees of freedom is N - 1

Where N represents the number of Men

Now we will put the values into the above formula.

= 372 - 1

= 371

Therefore for calculating the degree of freedom we simply applied the above formula.

In order to win a quiz contest, Olga must score more than 400400400 points. She earns 121212 points for each right answer, and loses 444 points for each wrong answer. Write an inequality that represents the number of right answers (R)(R)left parenthesis, R, right parenthesis and wrong answers (W)(W)left parenthesis, W, right parenthesis Olga can give to win the contest.

Answers

Answer: The number of points added for r right answers is 12r. The number of points taken away for w wrong answers is 4w, so Olga's total points will be

... 12r -4w

To win, she needs this number to be more than 400. Your inequality is ...

... 12r -4w > 400

Answer:12r -4w > 400

Step-by-step explanation:

Find the perimeter of a square with a diagonal of 15√2.

Answers

Answer:

15

Step-by-step explanation:

Answer:

21.213

Step-by-step explanation:

did this several times but still didn't get the answer .pls do try this :)​

Answers

Answer:

x=-15/2 and x=1

x=6 and x=3/4

Step-by-step explanation:

You have the following equations:

[tex]\frac{4x-3}{x+2}=\frac{2x}{x+5}[/tex]

[tex]\frac{2}{x-2}+\frac{3}{x}-\frac{9}{x+3}[/tex]

To solve both equations you can first multiply by the m.c.m of the denominators, and then solve for x, just as follow:

first equation:

[tex][\frac{4x-3}{x+2}=\frac{2x}{x+5}](x+2)(x+5)\\\\(4x-3)(x+5)=2x(x+2)\\\\4x(x)+4x(5)-3(x)-3(5)=2x(x)+2x(2)\\\\4x^2+20x-3x-15=2x^2+4x\\\\4x^2-2x^2+20x-3x-4x-15=0\\\\2x^2+13x-15=0[/tex]

In this case you use the quadratic formula:

[tex]x_{1,2}=\frac{-13\pm \sqrt{(13)^2-4(2)(-15)}}{2(2)}\\\\x_{1,2}=\frac{-13 \pm 17}{4}\\\\x_1=-\frac{15}{2}\\\\x_2=1[/tex]

Then, for the first equation the solutions are x=-15/2 and x=1

second equation:

[tex][\frac{2}{x-2}+\frac{3}{x}=\frac{9}{x+3}]x(x-2)(x+3)\\\\2x(x+3)+3(x-2)(x+3)=9x(x-2)\\\\2x^2+6x+3(x^2+3x-2x-6)=9x^2-18x\\\\2x^2+6x+3(x^2+x-6)=9x^2-18x\\\\2x^2+6x+3x^2+3x-18-9x^2+18x=0\\\\-4x^2+27x-18=0[/tex]

Again, you use the quadratic formula:

[tex]x_{1,2}=\frac{-27\pm \sqrt{(27)^2-4(-4)(-18)}}{2(-4)}\\\\x_{1,2}=\frac{-27\pm 21}{-8}\\\\x_1=6\\\\x_2=\frac{3}{4}[/tex]

Then, the solutions for the second equation are x=6 and x=3/4

(05.05)
Based on the graph, what is the initial value of the linear relationship?
-4
-3
5/3
5

Answers

Answer:

5

Step-by-step explanation:

The initial value is when x=0

When x=0, y =5

The initial value is 5

help me solve this Algebra problem please​

Answers

Answer:

39858075

Step-by-step explanation:

Hello,

One basic way to see it is to compute the values.

   75 = 25 * 3

   225 = 75 * 3

   675 = 225 * 3

   etc ...

We can notice that this is multiplied by 3 every 10 years so we can compute as below.

year         population

1970 25

1980 75

1990 225

2000 675

2010 2025

2020 6075

2030 18225

2040 54675

2050 164025

2060 492075

2070 1476225

2080 4428675

2090 13286025

2100 39858075

So the correct answer is 39858075

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

PLEASE HELP!

What is the length of the shortest altitude in a triangle, if the lengths of the sides are 15 cm, 17 cm, 8 cm. NO DECIMALS

Answers

Answer:

The shortest altitude = 8 cm

Step-by-step explanation:

Where we have the sides given by

15 cm, 17 cm, 8 cm

From cosine rule, we have;

a² = b² + c² - 2×b×c×cos(A)

We have

For the side 15 cm,

15² = 17² + 8² - 2×17×8 cos A

-388 = -612×cos×A

A = 61.93°

17² = 15² + 8² - 2×15×8 ×cos B

0 = -240·cos B

B = 90°

Therefore, 17 is the hypotenuse side and 15 and 8 are the legs, either of which can be the height which gives the shortest altitude as 8 cm

Graph [tex]y=\frac{2}{3} x[/tex] Which of the following statements are true?

Answers

Answer:

A,C,D

Step-by-step explanation:

When b=0, there is a proportional relationship.

The slope in y=mx+b is the value next to x.

Using RISE/RUN when there is a change of 3 units in x, there is a change of 2 units in y.

simplify
[tex] {a}^{ - 2} {b}^{3} [/tex]

Answers

Answer:

Below

Step-by-step explanation:

● a^(-2) *b^3

●(1/a^2) *b^3

● b^3 / a^2

Find the sum of all integers between 550 and 850 which are divisible by 11.

Answers

Answer:

19008

Step-by-step explanation:

550 is equal to 11 multiplied by 50.

1. Solve for multiples of 11 between 550 and 850

11 · 51 = 561

11 · 52 = 572

11 · 53 = 583

11 · 54 = 594

11 · 55 = 605

11 · 56 = 616

11 · 57 = 627

11 · 58 = 638

11 · 59 = 649

11 · 60 = 660

11 · 61 = 671

11 · 62 = 682

11 · 63 = 693

11 · 64 = 704

11 · 65 = 715

11 · 66 = 726

11 · 67 = 737

11 · 68 = 748

11 · 69 = 759

11 · 70 = 770

11 · 71 = 781

11 · 72 = 792

11 · 73 = 803

11 · 74 = 814

11 · 75 = 825

11 · 76 = 836

11 · 77 = 847

2. Add the products together

= 19008

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