Suppose, that you are measuring the length of a wood block and the edge of your block appears to be lined up exactly with a millimeter mark. How would you express the estimate part of a millimeter when you record the block’s length?

Answer:

When speed reduces, acceleration decreases

Explanation:

From first equation of motion;

[tex]{ \tt{v = u + at}}[/tex]

When time is constant:

[tex]{ \tt{v = 0 + kt}} \\ { \tt{v = kt}} \\{ \tt{v \: \alpha \: \: a}}[/tex]

When speed is decreasing, velocity and acceleration are in opposite directions.

Answer:

All the cells in an organism have exactly the same function

Answer:

letter B..

Explanation:

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The ball encounters resistance as it travels through the air. Drag is the term for the air's resistance to the ball. Drag slows down the baseball because it is applied against the direction of the ball's flight. Thus, option B is correct.

When two objects rub against one another, a force known as friction is applied. Friction force often works to prevent an object from moving. For instance, friction between a ball and carpet when rolling a ball across it causes the ball to move more slowly.

A baseball in flight is impacted by three forces. The three forces are lift, drag, and weight. Actually, the aerodynamic force exerted on the ball is made up of two parts: lift and drag. Lift acts perpendicular to the motion, and drag acts in the direction opposite to the motion.

Therefore,  the direction of the force the least effect on the motion of a ball.

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Answer:

Counter clockwise

Explanation:

The average acceleration of the car over 3 seconds is -7 m/s².

Acceleration is defined as the rate of change of velocity with respect to time. Mathematically -

a = Δv/Δt

Given is a car that car slows from 36 m/s to 15 m/s over 3 seconds.

We can calculate acceleration as follows -

a = Δv/Δt

a = (15 - 36)/(3)

a = -21/3

a = - 7m/s²

Therefore, the average acceleration of the car over 3 seconds is -7 m/s².

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Answer:

3.69 rad/s

Explanation:

From the question given above, the following data were obtained:

Period (T) = 1.7 s

Angular frequency (ω) =?

Thus, we can obtain the angular frequency (ω) by applying the following formula:

ω = 2π/T

Period (T) = 1.7 s

Pi (π) = 3.14

Angular frequency (ω) =?

ω = 2π/T

ω = 2 × 3.14 / 1.7

ω = 6.28 / 1.7

ω = 3.69 rad/s

Thus, the angular frequency of the motion is 3.69 rad/s

Answer:

Cost = $ 7.72

Explanation:

Considering the trip of 100 km, the cost spent on the fuel during the trip can be calculated by the following formula:

[tex]Cost = Average Fuel Consumption\ x\ Unit Fuel Cost\ x\ Distance[/tex]

where,

Average Fuel Consumption = 6 liter/100 km

Unit Fuel Cost = (1.063 euros/liter)($ 1.21/1 euro) = $ 1.29/liter

Distance = 100 km

Therefore,

[tex]Cost = (6\ liter/100\ km)(\$\ 1.29/liter)(100\ km)\\[/tex]

Cost = $ 7.72

Answer:

-79

Explanation:

because I know because that's what the answer is because it is -79 when it hits the ground

A bowling ball results in kinetic friction compared to a sliding bowling ball.

According to Conservation of momentum, if a bowling ball hits some pins, the momentum that lost by the bowling ball is known to be equal to the momentum obtained by the pins.

The friction that is used in bowling is kinetic friction because the more oil that is placed down, the lower the friction that is found between the ball and that of the lane surface. The  little friction, the stronger it is for the bowler to be able to send the ball in a curved path and thus the formula to find the kinetic friction is know to be : µk=F k/mg.

Therefore, A bowling ball results in kinetic friction compared to a sliding bowling ball.

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Answer:

The horse moves due to kinetic energy and is walking balanced because of the gravitational energy

Explanation:

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Answer:

3.08m/s²

Explanation:

Given parameters:

Radius = 20m

Tangential velocity  = 7.85m/s

Unknown:

Centripetal acceleration  = ?

Solution:

Centripetal acceleration is the acceleration of a body along a circular path.

 it is mathematically given as;

       a  = [tex]\frac{v^{2} }{r}[/tex]  

v is the tangential velocity

r is the radius

      a  = [tex]\frac{7.85^{2} }{20}[/tex]   = 3.08m/s²

Complete Question

Argon gas (a monatomic gas) is sometimes used to insulate a double-pane window for purposes of insulation. In a particular window, the space in between two glass sheets has a volume of [tex]0.025 \ m^3[/tex]. If the temperature of the gas is 290 K. what is the rms speed of the gas atoms? The atomic mass of Argon is 39.9 u.(l u= 1.66x10-27 kg) Enter your answer in m/s

Answer:

The value is [tex]V_{rms} = 425.75 \ m/s[/tex]

Explanation:

From the question we are told that

     The volume of the space in between the two glass sheet is  [tex]a = 0.025 \ m^3[/tex]

     The temperature of the gas is [tex]T = 290 \ K[/tex]

       The atomic mass of Argon is  [tex]m = 39.9 \ u = 39.9 * 1.66 *10^{-27} = 6.623 *10^{-26} \ kg[/tex]

Generally the root mean square velocity is mathematically represented as

      [tex]V_{rms} = \sqrt{\frac{3 K T}{ m } }[/tex]

Here K is the Boltzmann constant  with value [tex]k = 1.38 *10^{-23} \ m^3 \cdot kg \cdot s^{-2} \cdot K^{-1}[/tex]

So

     [tex]V_{rms} = \sqrt{\frac{3 * 1.38 *10^{-23} * 290 }{ 6.6234*10^{-26} } }[/tex]

=>   [tex]V_{rms} = 425.75 \ m/s[/tex]

Answer:

τ = 0.009 Nm

Explanation:

The torque applied on the tooth can be given by the following formula:

[tex]\tau = Fd[/tex]

where,

τ = Torque on the tooth= ?

F = Force acting on tooth = 9 N

d = distance between force and tooth axis = 1 mm = 0.001 m

Therefore, using these values in the equation, we get:

[tex]\tau = (9\ N)(0.001\ m)[/tex]

τ = 0.009 Nm

Given that,

The rate of change of current = 3.2 A/s

Emf induced in the coil = 5.7 V

To find,

The magnitude of the mutual inductance of the two coils.

Solution,

The mutual inductance between the coils is given by the formula as follows :

[tex]\epsilon=M\dfrac{dI}{dt}\\\\M=\dfrac{\epsilon}{\dfrac{dI}{dt}}\\\\M=\dfrac{5.7}{3.2}\\\\=1.78\ H[/tex]

So, the mutual inductance of the two coils is 1.78 H.

The statements that describe the processes involved in the accretion of planetesimals and protoplanets are :

II. Both processes involve nebular materials becoming solid particles.

IV. In both cases, masses of stuff are clumped together and gases are trapped.

Accretion basically involves the accumulation of particles into a massive object by gravitationally attracting more matter, mainly the gaseous matter, in an accretion disk.

A protoplanet is basically a large planetary embryo that has originated within a protoplanetary disc and which also has undergone internal melting to produce a differentiated interior.

Planetesimals are known to be small rock-type objects which are

formed by collisions with other objects present in the solar system.

Hence, the statements that describe the processes involved in the accretion of planetesimals and protoplanets are :

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The complete question is mentioned below:

Which statements describe processes involved in the accretion of planetesimals and protoplanets?

( I ) Both involve the melting of solid materials in the nebula.

( II ) Both involve the formation of solid particles from nebular materials.

( III ) Both involve the work of the gravitational push on nebular materials.

( IV ) Both involve the trapping of gases and the clumping of masses of matter.

( V ) Both involve the growing of gas grains with the addition of atoms and molecules.

The acceleration of the electrical current is -2.4 m/s².

Acceleration can be defined as the rate of change of velocity.

To calculate the acceleration of the electric current, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the acceleration of the electrical current is -2.4 m/s².

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Answer:

The tension in the string is 52.89 N.

Explanation:

Given;

mass of the string, m = 19.1 g = 0.0191 kg

length of the string, L = 1.95 m

⇒mass per unit length, μ = 0.0191 / 1.95 = 0.009795 kg/m

Also Given;

frequency of the string, F = 440 Hz

wavelength of the sound wave, λ = 16.7 cm = 0.167 m

⇒the speed of the wave, v = Fλ = 440 x 0.167 = 73.48 m/s

The tension T in the string is calculated as;

[tex]v = \sqrt{\frac{T}{\mu} } \\\\v^2 = \frac{T}{\mu}\\\\T = v^2 \mu\\\\T = (73.48)^2 (0.009795)\\\\T = 52.89 \ N[/tex]

Therefore, the tension in the string is 52.89 N.

Given that,

At 3.00 m from a source that is emitting sound uniformly in all directions, the sound level is 60.0 dB.

To find,

The distance from the source would the sound level be one-fourth the sound level at 3.00 m.

Solution,

The intensity from a source is inversely proportional to the distance.

Let I₁ = 60 dB, r₁ = 3 m, I₂ = 60/4 = 15 dB, r₂ =?

Using relation :

[tex]\dfrac{I_1}{I_2}=\dfrac{r_2^2}{r_1^2}\\\\r_2^2=\dfrac{I_1r_1^2}{I_2}\\\\r_2^2=\dfrac{60\times (3)^2}{15}\\\\r_2=6\ m[/tex]

So, at a distance of 6 m the sound level will be one fourth of the sound level at 3 m.

Answer:

16m/s

Explanation:

Given the following data;

Force, F = 16N

Mass, m = 5kg

Time, t = 5 seconds.

First of all, we would find the acceleration of the object.

Force is given by the multiplication of mass and acceleration.

Mathematically, Force is given by the formula;

[tex] F = ma[/tex]

Where;

Making acceleration (a) the subject, we have;

[tex]Acceleration, a = \frac{F}{m}[/tex]

Substituting into the equation;

[tex]Acceleration, a = \frac{16}{5}[/tex]

Acceleration, a = 3.2 m/s²

Now, to find velocity;

We would use the first equation of motion given by the formula;

[tex] V = U + at[/tex]

Where;

We know that acceleration due to gravity is 9.8m/s² and initial velocity (U) is 0 since the object is at rest.

Substituting into the equation, we have;

[tex] V = 0 + 3.2*5[/tex]

[tex] V = 0 + 16[/tex]

Velocity, V = 16m/s.

Answer: A

Explanation:

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The atoms come from the parents of the puppies and were formed by biosynthesis in the bodies of the parent dogs.

The term biological molecules are those molecules that are important for life. These are the molecules that are involved in the processes of life that take place in an organism.

Now, from the time of conceptions, the biomolecules in the new organism begins to form. Recall that the DNA is the molecule that is used to store the genetic information of an organism. Now et us recall that the DNA is passed on from the parents to the offspring.

Now, we know that the atoms that compose these puppies come from the parent organisms. The molecules in which the atoms are formed are formed during the natural processes that were taking place in the bodies of the parents of puppies. This occurs by the process of reproduction.

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"Distance" here is the total distance traveled along the red path (see attached) from point A to point B. Just count how many how sides of each square in the grid are touched by the path. Then distance = 24 units.

"Displacement" is the net distance covered by moving from point A to point B, or the length of the green path. So displacement = 2 units to the right. Of course, your question seems to ask for the displacement in terms of units to the left, in which you could say -2 units to the left.

Answer:

An induction is the process a new recruit goes through to be introduced to the company and their new role. ... Beyond the initial days, the induction programme continues for many months, so that the new employee can fully integrate into life in the company and settle into their role to become a valuable member of staff.

Explanation:

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Answer:b) 4.5×10^9km

Explanation:use s= vt/1000 here, v= speed of light which is 3×10^8m/s

t= time in second

This question is incomplete, the complete question is on the image uploaded along this answer.

Answer:

the potential at point B is 5 V, Option d) is the correct answer

Explanation:

Given that;

from the image;

R = 3 + 4 + 5 = 12 Ω

so I = 12/12 = 1 A

Q = 0 + 12 = 12 V

now

VA - VQ = - I × 3 = -3 V

VA = VQ - 3 =  12 - 3 = 9 V

VB - VA = - I × 4Ω = - 4 V

⇒VB = VA - 4 = 9 V - 4 V = 5 V

Therefore the potential at point B is 5 V

Option d) is the correct answer

Answer:

v = 0.6c = 1.8 x 10⁸ m/s

Explanation:

From Einstein's theory of relativity, we know that the length of an object contracts while traveling at a speed relative to speed of light. The contraction is according to following equation:

[tex]L = L_{0}\sqrt{1 - \frac{v^2}{c^2}}[/tex]

where,

L = Relative Length

L₀ = Rest Length

According to given:

L = 0.8 L₀

c = speed of light = 3 x 10⁸ m/s

v = relative speed of train = ?

Therefore,

[tex]0.8L_{0} = L_{0}\sqrt{1 - \frac{v^2}{c^2} } \\\\0.8 = \sqrt{1 - \frac{v^2}{c^2} }[/tex]

squaring on both sides:

[tex]0.64 = 1-\frac{v^2}{c^2}\\\\\frac{v^2}{c^2} = 1-0.64 \\v^2= 0.36c^2\\[/tex]

taking square root on both sides:

v = 0.6c = 1.8 x 10⁸ m/s

Answer:

6

Explanation:

The magnetic field inside a solenoid is given by the following formula:

[tex]B = \mu_{0}nI[/tex]

where,

B = Magnetic Field Inside Solenoid

μ₀ = permittivity of free space

n = No. of turns per unit length

I = Current Passing through Solenoid

For Solenoid 1:

[tex]B_{1} = \mu_{0}n_{1}I ------------------- equation 1[/tex]

For Solenoid 2:

n₂ = 6n₁

Therefore,

[tex]B_{1} = \mu_{0}n_{2}I\\B_{1} = 6\mu_{0}n_{1}I ----------------- equation 2[/tex]

Diving equation 1 and equation 2:

[tex]\frac{B_{2}}{B_{1}} = \frac{6\mu_{0}nI}{\mu_{0}nI}\\\\\frac{B_{2}}{B_{1}} = 6[/tex]

Hence, the correct option is:

6

The ratio of the magnetic fields in interior 2 to interior 1 will be

[tex]\dfrac{B_2}{B_1} =\dfrac{6}{1}[/tex]

The formula for the magnetic fields inside the solenoid will be given:

[tex]B=\mu_onI[/tex]

here,

B = Magnetic Field Inside Solenoid

μ₀ = permittivity of free space

n = No. of turns per unit length

I = Current Passing through Solenoid

For the first Solenoid

[tex]B_1=\mu_on_1I[/tex]..................(1)

For the second solenoid

[tex]n_2=6n_1[/tex]

Now

[tex]B_2=\mu_on_2I[/tex]

[tex]B_2=\mu_o(6n_1)I[/tex]..................(2)

Diving equation 1 and equation 2:

[tex]\dfrac{B_2}{B_1} =\dfrac{\mu_o(6n_1)I}{\mu_on_2I}[/tex]

[tex]\dfrac{B_2}{B_1} =6[/tex]

Thus the ratio of the magnetic fields in interior 2 to interior 1 will be

[tex]\dfrac{B_2}{B_1} =\dfrac{6}{1}[/tex]

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