Suppose cell C5 contains the formula =B$6+C1.


Match each formula with its respective cell if you copied it.


=A$6+B4 =B$6+C6 =C$6+D2 =D$6+E1


Thank you, have a great week.

Answers

Answer 1

Answer:

=A$6+B4 will be in B8

=B$6+C6 will be in C10

=C$6+D2 will be in D6

=D$6+E1 will be in E5

Explanation:

$ sign is used to lock a certain column or row value, with the $ sign we can create an absolute reference which will remain unchanged as we copy our formula from one cell to another.

As formulars are copied, the references change respectively.

With =B$6+C1 in C5 ; As we move up or down of cell C5, only the row numbers will change that is formula in C6 becomes =B$6+C2.

As we move left and right, the column alphabet will also experience change like the rows did.

Only the absolute reference won't change no matter the direction.

Hence,

=A$6+B4 ; A and B means one move to the left of C5 and 4 signifies, 3 moves downward of C5 that gives B8

=B$6+C6 ; B and C means no horizontal change, 6 means 5 moves downward of C5 which gives C10

=C$6+D2 ; C and D means 1 move to the right and 2 means one move downward of C5 which gives D6

=D$6+E1 ; D and E means 2 moves to the right and 1 means no vertical change from C5 ; which gives E5


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-scav

z 1
-- = --
7 21
solve​

Answers

Answer:

[tex]z= \frac{1}{3}[/tex]

Explanation:

Given

[tex]\frac{z}{7} = \frac{1}{21}[/tex]

Required

Solve

[tex]\frac{z}{7} = \frac{1}{21}[/tex]

Multiply both sides by 7

[tex]7 * \frac{z}{7} = \frac{1}{21} * 7[/tex]

[tex]z= \frac{1}{21} * 7[/tex]

Rewrite as:

[tex]z= \frac{1 * 7}{21}[/tex]

[tex]z= \frac{7}{21}[/tex]

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Answer:

N = [1,1,1,1,1],

[2,2,2,2,2],

[3,3,3,3,3],

[4,4,4,4,4]

def printIt(ar):

   for row in range(len(ar)):

       for col in range(len(ar[0])):

           print(ar[row][col], end=" ")

       print("")

           

N=[]

for r in range(4):

   N.append([])

   

for r in range(len(N)):

   value=1

   for c in range(5):

       N[r].append(value)

       value=value + 1

           

printIt(N)

print("")

newValue=1

for r in range (len(N)):

   for c in range(len(N[0])):

       N[r][c] = newValue

   newValue = newValue + 1

       

printIt(N)

Explanation:

I got 100%.

In this exercise we have to use the knowledge of computational language in python to write the code.

We have the code in the attached image.

The code in python can be found as:

def printIt(ar):

  for row in range(len(ar)):

      for col in range(len(ar[0])):

          print(ar[row][col], end=" ")

      print("")        

N = [1,1,1,1,1], [2,2,2,2,2], [3,3,3,3,3], [4,4,4,4,4]

for r in range(4):

  N.append([])

for r in range(len(N)):

  value=1

  for c in range(5):

      N[r].append(value)

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  for c in range(len(N[0])):

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printIt(N)

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Answer:

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Answer:

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The question is incomplete. The complete question is :

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Answers

Answer:

The program is as follows:

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11 PRINT DIFF

12 END

Explanation:

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6 PROD = A * B

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7 PRINT PROD

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8 TOTAL = A + B

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9 PRINT TOTAL

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11 PRINT DIFF

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Answer:

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n
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It led to the development of octets.

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Answers

Answer:

Option A, Through the Dark Web where the value of the stolen funds can be stored on hidden servers

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Answers

Answer: Clicking on file tab and selecting options, if she has issues contact Help & Support.

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Answer:

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Answer:

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good luck

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Insert
Review
Animations

Answers

Answer: Insert

Explanation:

The Ribbon was introduced by Microsoft in 2017 and it's simply a user interface element that can be found below Quick Access Toolbar. The Ribbon consist of seven tabs which are:

• Home

• Insert

• Page layout

• References

• Mailing

• Review

• View.

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In the Menu bar, the person should click on the Insert tab that us in the Links section. After that, click on the Hyperlink or the Link option, then in the Insert Hyperlink window, one can then type addr as of the web page that the person wants to connect the text to after which the leoen will then click OK.

What is one difference between low- and high-level programming languages? (5 points)
O a
Ob
Low-level programming languages are challenging for humans to read, while high-level programming languages are easier.
Low-level programming languages are more human-friendly, while high-level programming languages are more challenging for
humans to understand.
Ос
Low-level programming languages require interpreters and compilers, while high-level programming languages do not.
Od
Low-level programming languages use program code to communicate with computers, while high-level programming languages
use machine code.

Answers

Answer: Low-level programming languages are computer code at its most basic. They are difficult or sometimes impossible for humans to read, while high-level languages are designed to be easy for humans to understand. I believe the answer is A.

Answer:

Low-level programming languages require interpreters and compilers, while high-level programming languages do not.

Explanation: I AM SURE IT IS CORRECT 100% CORRECT

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