Answer:
the answer is 2.6409.
Explanation:
i asked my teacher
A mass on a
string is swung in a circle of radius 1.0m
at a speed of 5.0mls. What is the period of
revolution?
Answer:
S = 2 * pi * 1 m = 6.28 m = distance traveled
V = S / T or T = S / V = 6.28 m / 5 m/s = 1.26 sec
This will be the time for 1 revolution or the period of the motion.
If 12 coulombs of electric charge pass a point in 4.0
seconds, the current is
A) 8.0 amperes
B) 16 amperes
C) 3.0 amperes
D) 48 amperes
Answer:
AS
Explanation:
URGENT HELP!
How is it that two moving objects can have a net momentum of zero?
Answer:
because they may not actually be moving be just percieved as so
Explanation:
Answer:
i think that maybe there arent moving but there on something thats moving
Explanation:
The quasar that appears the brightest in our sky, 3C 273, is located at a distance of 2.4 billion lightyears. The Sun would have to be viewed from a distance of 1300 light-years to have the same apparent magnitude as 3C 273. Using the inverse square law for light, estimate the luminosity of 3C 273 in solar units.
Answer:
Explanation:
Let the luminosity of the star be I and luminosity of the sun be Isun.
2.4 billion light years = 2.4 x 10⁹ light years .
brightness = luminosity / (distance)²
Given Sun would have to be viewed from a distance of 1300 light-years to have the same apparent magnitude as 3C 273 so
For the sun
brightness = Isun / (1300 light years )²
For star
brightness = I / (2.4 x 10⁹ light years )²
Both these brightness are same
Isun / (1300 light years )² = I / (2.4 x 10⁹ light years )²
I = Isun x (2.4 x 10⁹ light years )² / (1300 light years )²
= Isun x 3.4 x 10¹² .
Someone is trying to balance a (110cm) plank with certain forces.
a) Calculate the moment of the 60N force (about O), then name its type.
b) Calculate the moment of the 30N force (about O), then name its type
c) Will the plank balance? If not, which way will it tip?
d) What extra force would be needed at (B) to balance the plank?
Answer:
a. i. 30 Nm ii. This moment is a clockwise positive moment.
b. i. 15 Nm ii, This moment is a counter-clockwise negative moment.
c. i. The plank will not balance. ii. The plank would tip up.
d. 150 N
Explanation:
a) Calculate the moment of the 60N force (about O), then name its type.
i. Calculate the moment of the 60N force (about O)
Since moment = Force × perpendicular distance from point of moment ,
M = Fd
Since F = 60 N and d = 50 cm = 0.5 m
M = 60 N × 0.5 m = 30 Nm
ii. Then name its type.
This moment is a clockwise positive moment.
b) Calculate the moment of the 30N force (about O), then name its type.
i. Calculate the moment of the 30N force (about O),
Since moment = Force × perpendicular distance from point of moment ,
M' = F'd'
Since F' = 30 N and d' = 50 cm = 0.5 m
M' = 30 N × 0.5 m = 15 Nm
ii. Then name its type.
This moment is a counter-clockwise negative moment.
c) Will the plank balance? If not, which way will it tip?
i. Will the plank balance?
The plank will balance if the net moment on it is zero
So net moment, M' = positive moment - negative moment = M - M' = 30 Nm - 15 Nm = 15 Nm
Since the net moment on the plank is M" = 15 Nm ≠ 0,the plank will not balance.
ii Which way will it tip?
The plank would tip in the direction of the greater moment since the net moment is positive. This moment tilts the plank in a clockwise direction, so the plank would tip up.
d) What extra force would be needed at (B) to balance the plank?
The extra force must balance the net moment,
So M" = F"d" where F" = force and d" = distance of force from O = 10 cm = 0.10 m
F" = M"/d"
= 15 Nm/0.10 m
= 150 N
Please help help help !!!!! ( science) is
Answer:
I believe it's applied force (push)
What two pigments would be subtracted to reflect a red object?
a. yellow and magenta
b. magenta and cyan
c. green and blue
d. cyan and red
If a ball is travelling in a circle of diameter 10m with velocity 20m/s, find the angular velocity of the ball.
Answer:
4 rad/s
Explanation:
The angular velocity is velocity over time:
[tex]\displaystyle{\omega = \dfrac{v}{r}}[/tex]
We know that the velocity is 20 m/s and the radius is half of diameter which is 10m/2 = 5 m. Hence, substitute in the formula:
[tex]\displaystyle{\omega = \dfrac{20 \: \text{m/s}}{5 \: \text{m}}}\\\\\displaystyle{\omega = 4 \: \text{rad/s}}[/tex]
Therefore, the angular velocity is 4 rad/s
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Which has more momentum, a 0.5kg toy car moving a 5 m/s or a 1000kg real car that is
parked?
Answer:
The toy car. An object that isn't moving has no momentum
Explanation:
n experimental vehicle starts from rest (0 = 0) at = 0 and accelerates at a rate given by
= (7m/s
3
). What is (a) its velocity and (2) its displacement 2 later?
The velocity of the experimental vehicle after 2 seconds is 14 m/s.
The displacement of the experimental vehicle after 2 seconds is 14 m.
What is the velocity and displacement of the experimental vehicle?The velocity of the experimental vehicle is the speed of the in a given direction starting from rest.
The velocity, v, of the experimental vehicle after 2 seconds is calculated using the formula below:
v = u + at
where;
u is the initial velocity = 0 m/s
a is the acceleration = 7 m/s²
t is time = 2 seconds
v = 0 + 7 * 2
v = 14 m/s
The displacement, s, of the vehicle is calculated below as follows:
v² = u² + 2as
14² = 0² + 2 * 7 * s
s = 196 / 14
s = 14 m
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Yellow light (600 nm) passes through a
diffraction grating with d = 2.35 x 10-6 m.
What is the angular separation between
the second (m = 2) and third (m = 3)
maximum?
Answer:
19.284
Explanation:
The answer is right on Accellus.
1- A ball, M = 4 kg is released from rest (vi =0) at a height, h = 2 m above the ground. (a)
What is the kinetic energy of the ball just before it hits the ground? What is the change in the
potential energy, ΔU during this motion? (b) Find the kinetic energy of the ball at a height, y
= 1.2 m above the ground. (Take g = 10 m/s2
).
(a) The kinetic energy of the ball just before it hits the ground is 78.4 J.
(b) The kinetic energy of the ball at a height of 1.2 m is 31.36 J.
What is the kinetic energy of the ball?The kinetic energy of the ball just before it hits the ground is calculated as follows;
K.E ( bottom) = P.E (top)
P.E (top) = mgh
where;
m is the mass of the objecth is the height of the objectg is acceleration due to gravityP.E (top) = 4 x 9.8 x 2
P.E (top) = 78.4 J
The change in the potential energy of the ball during its motion is calculated as follows;
ΔU = P.Ef - P.E i
where;
P.Ef is the final potential energy at ground levelP.Ei is the initial potential energy at maximum heightΔU = 0 J - 78.4 J
ΔU = -78.4 J
The kinetic energy of the ball at a height of 1.2 m is the change in the potential energy of the ball and it is calculated as follows;
K.E = -ΔU
K.E = -mg (hf - hi)
K.E = (4 x 9.8)(2m - 1.2 m)
K.E = 31.36 J
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While skiing in Jackson, Wyoming, your friend Ben (of mass 63.2 kg) started his de- scent down the bunny run. 11.5 m above the bottom of the run. If he started at rest and converted all of his gravitational potential energy into kinetic energy, what is Ben's kinetic energy at the bottom of the bunny run? Use g = 9.8 m/s Answer in units of J.
Answer:
Approximately [tex]7.1 \times 10^{3}\; {\rm J}[/tex] (given: [tex]g = 9.8\; {\rm m\cdot s^{-2}}[/tex].)
Explanation:
To find the change in the gravitational potential energy ([tex]\text{GPE}[/tex]), use the formula:
[tex]\begin{aligned}& (\text{change in GPE}) \\ &= (\text{mass})\, (g)\, (\text{change in height})\end{aligned}[/tex].
Assume that gravitational field strength [tex]g[/tex] is constant (e.g., [tex]g = 9.8\; {\rm m\cdot s^{-2}}[/tex].) For an object of mass [tex]m[/tex], if the altitude of the object changes by [tex]\Delta h[/tex], the [tex]\text{GPE}[/tex] of that object would change by [tex]m\, g\, \Delta h[/tex].
In this question, the mass of Ben is [tex]m = 63.2\; {\rm kg}[/tex]. It is given that [tex]g = 9.8\; {\rm m\cdot s^{-2}} = 9.8\; {\rm N\cdot kg^{-1}}[/tex] and is constant. Since change in the altitude of Ben is [tex]\Delta h = 11.5\; {\rm m}[/tex], the change in the ([tex]\text{GPE}[/tex]) of Ben would be:
[tex]\begin{aligned} m\, g\, \Delta h &= (63.2\; {\rm kg}) \, (9.8\; {\rm N\cdot kg^{-1}})\, (11.5\; {\rm m}) \\ &\approx 7.1\times 10^{3}\; {\rm N\cdot m} = 7.1\times 10^{3}\; {\rm J} \end{aligned}[/tex].
Which are dangerous places to put a flammable substance? Check all that apply.
near a flame
on a scale
near a ruler
in a sink
near a hot plate
Answer:
near a flame and a hot plate
Explanation:
Which statement can be made about the amplitude of any transverse wave?
It is the length from the midpoint to the crest.
It is half the length from the midpoint to the trough.
It is the length of the wavelength.
It is half the length of the wavelength.
Answer:
A) It is the length from the midpoint to the crest.
Explanation:
The correct statement about the amplitude of any transverse wave is: It is the length from the midpoint to the crest. The correct option is A.
What is a transverse wave?A transverse wave is a type of wave in which the displacement of the medium is perpendicular to the direction of wave propagation.
Examples of transverse waves include light waves and water waves in which the surface of the water oscillates up and down while the wave moves horizontally.
The properties of a transverse wave include:
Amplitude: The maximum displacement of the medium from its rest position. This represents the intensity or strength of the wave.
Wavelength: The distance between two adjacent points in the wave that are in phase with each other, for example, between two consecutive crests or troughs. It is typically represented by the symbol λ.
Frequency: The number of complete wave cycles that pass a point in a given amount of time, usually measured in hertz (Hz). The frequency is inversely proportional to the wavelength and is represented by the symbol f.
Period: The time taken for one complete wave cycle to pass a given point, usually represented by the symbol T. The period is directly proportional to the wavelength and inversely proportional to the frequency.
Speed: The speed at which the wave propagates through the medium, usually represented by the symbol v. The speed is directly proportional to the frequency and wavelength.
These properties are related to each other by the wave equation:
v = fλ,
Where v = the speed of the wave,
f = the frequency,
and λ = the wavelength.
Therefore, The correct statement about the amplitude of any transverse wave is A. It is the length from the midpoint to the crest.
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Ruby was training for a race at the high school track. She took her dog walked 2250 meters in 15 minutes. Calculate the average speed
Answer:
Average speed [tex]= 2.5[/tex] meter per second
Explanation:
Given
The total distance walked [tex]= 2250[/tex] meters
The total time taken to walk [tex]2250[/tex] meters is [tex]15[/tex] minutes
In one minute there are [tex]60[/tex] seconds
As we know Average speed is equal to total distance travelled divided by total time taken
Hence,
Average speed
[tex]\frac{2250}{15*60} \\2.5[/tex]meter per second
Hi, can anyone help me with this question I have?
Assume a tornado is in the vicinity of your neighborhood. Which would
be the most useful information to determine your safety - speed or
velocity? Explain your answer.
Answer:
speed
Explanation:
you need to move fast so the tornado can't reach you
Please help with this
A unit vector must have length equal to 1. By calculating the length of (1, 1), we discover that (12 + 12) = 2 = 1.414, which is not the same as 1, is the length.
How do you write unit vector notation?I,J notation is a way to describe a vector. In Cartesian coordinates, a unit vector is a vector with length 1. The unit vectors along the axis are denoted by the letters I and j, respectively. The form ai+bj an I + b j can be used to represent any two-dimensional vector.Numerous operations, including addition, subtraction, and vector multiplication, can be carried out with the aid of the vector form of representation. A=xi+yj+zk is the vector form of the cartesian representation of the three points (x, y, and z). A is equal to x I y j, and z k.Vy = Vyj, Vz = Vz k, and Vx = Vxî. V = Vx + Vy + Vz = Vxî+ Vyj+ Vz k is the result of applying the triangle rule to vector addition twice. The unit vector notation is used in this situation.To learn more about vector refer to:
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Q12. How big is a Moon? How big is a Mars? What is therefore the weight of the person from Q11 on the Moon? What is the person's weight on Mars?
Answer:
The moon is 1,079.4 mi.
Mars is 2,106.1 mi
Multiply your weight by the moon's gravity relative to earth's, which is 0.165. Solve the equation. In the example, you would obtain the product 22.28 lbs. So a person weighing 135 pounds on Earth would weigh just over 22 pounds on the moon
Being that Mars has a gravitational force of 3.711m/s2, we multiply the object's mass by this quanitity to calculate an object's weight on mars. So an object or person on Mars would weigh 37.83% its weight on earth.
Explanation:
~Hope this helps
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Which has more momentum, a 0.5kg toy car moving a 5 m/s or a 1000kg real car that is
parked?
Answer:
The toy car
Explanation:
the real car is parked so yeah but maybe in some way technically the real car has more "momentum"
Explained Kepler's laws, satellites motion and weightlessness
Why is Dimension important in Physics?
Explanation:
Dimensions help understand how physical amounts are related to their dependence on basic or fundamental volumes, i.e. how the body's dimensions rely on mass, time, length and temperature.
Understanding dimensions is of utmost importance as it helps us in studying the nature of physical quantities mathematically. The basic concept of dimensions is that we can add or subtract only those quantities which have same dimensions. Also, two physical quantities are equal if they have same dimensions.
Which kind of kinetic energy is a rolling ball?
Tritium, the 3H atom, consists of a nucleus of one proton and two neutrons with a single electron. It is unstable and decays via beta emission to singly ionized helium, 3 He , consisting of a nucleus of two protons and one neutron with a single electron. This decay takes place instantaneously and thus there occurs a sudden doubling of the Coulomb interaction between the atomic electron and the nucleus. If the tritium atom is in its ground state when it decays, determine the probability that the 3He atom is in its ground state immediately after the decay.
Required:
Determine the probability that the 3H^+ atom is in its ground state immediately after decay.
Answer: hello your question is poorly written attached below is the complete question
P( ³₂He₊ ) at ground state = 1
Explanation:
Determine the probability that the 3He atom is in its ground state after decay
From the attached solution the coulomb interaction of ( ³₂He) is double that of H³ . given that coulomb interaction is attractive ( -ve ) this will make the product to become more stable hence the product ( ³₂He₊ ) will be gotten at the ground state
i.e. P( ³₂He₊ ) at ground state = 1
attached below is a detailed solution
An electron accelerates through a 12.5 V potential difference, starting from rest, and then collides with a hydrogen atom, exciting the atom to the highest energy level allowed. List all the possible quantum-jump transitions by which the excited atom could emit a photon and the wavelength (in nm) of each.
Answer:
Explanation:
An electron accelerates through a 12.5 V potential difference, starting from rest, so it will acquire kinetic energy of 12.5 eV .
In hydrogen atom energy of n th orbit in terms of eV is given as follows
En = -13.6 / n² eV
Total energy of 1 st orbit E₁ = - 13.6 eV
Total energy of 2 st orbit E₂ = - 13.6 eV / 2² = - 3.4 eV
Total energy of 3 st orbit E₃ = - 13.6 eV / 3² = - 1.5 eV
Total energy of 4 st orbit E₄ = - 13.6 eV / 4² = - 0.85 eV
E₄ - E₁ = 13.6 - 0.85 = 12.75 eV
E₃ - E₁ = 13.6 - 1.5 = 12.10 eV
E₂ - E₁ = 13.6 - 3.4 = 10.2 eV .
The electron has energy of 12,5 eV so it can excite electron from E₁ to E₃ . .
Jump possible = E₃ to E₂ , E₂ to E₁ and E₃ to E₁
Energy of E₃ to E₂ = 3.4 - 1.5 eV = 1.9 eV
wavelength = 1237 / 1.9 nm = 651 nm
E₃ - E₁ = 13.6 - 1.5 = 12.10 eV
wavelength = 1237 / 12.10 nm = 102.23 nm
E₂ - E₁ = 13.6 - 3.4 = 10.2 eV
wavelength = 1237 / 10.2 nm = 121.27 nm
wavelength of photon possible are 651 nm , 121.27 nm , 102.23 nm .
the work a force does is measured in?
Answer:
newtons
Explanation:
In the metric system of units, where force is measured in newtons (abbreviated N), work is measured in newton-meters (N-m). For reference, a newton is roughly equal to the force exerted on your hand by a baseball.
Answer:
newtons
In the metric system of units, where force is measured in newtons (abbreviated N), work is measured in newton-meters (N-m). For reference, a newton is roughly equal to the force exerted on your hand by a baseball.
A lawnmower is pushed with a force of 72 Newtons at an angle of 40 degrees from the horizontal. How much work is done to the mower if it moves 740 meters?
The work done to the mower is the product of force and the distance covered by the object which is equal to 40,811 Joules.
What is Work done?Work done can be defined as the product of external force and the distance over which the force is being applied. Work is done on an object when a force is applied to an object and the object is moved through a particular distance.
From this we can see that:
X-Component:
cos(θ) = x/F
Then,
X= F cos(θ).…..(1)
Now putting the values of F and θ in equation (1) we get,
X = 72 N × cos(40)
X = 72 N × 0.766
X= 55.15 N this is the x-component force
The work done to the mower is:
W = F × d
W = 55.15 × 740
W = 40,811 Joules
The work done to the mower is 40811 Joules.
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A ray of light has a wavelength of
284 nm in glass (n = 1.51). What
is its wavelength in a vacuum?
Answer:
The wavelength in vacuum is equal to 428.8 nm.
Explanation:
Given that,
The wavelength of light, [tex]\lambda=284\ nm[/tex]
The refractive index of glass, n = 1.51
We need to find the wavelength in vacuum. The relation between wavelength and refractive index is given by :
[tex]n=\dfrac{\lambda_v}{\lambda}\\\\\lambda_v=n\times \lambda\\\\\lambda_v=1.51\times 284\\\\\lambda_v=428.8\ nm[/tex]
So, the wavelength in vacuum is equal to 428.8 nm.
The bellows of an adjustable camera can be extended so that the largest distance from the lens to the film is 1.45 times the focal length. If the focal length of the lens is 6.14 cm, what is the distance from the closest object that can be sharply focused on the film
Answer: 19.80 cm
Explanation:
Given
focal length [tex]f=6.14\ cm[/tex] (as focal length is positive, it is converging lens)
Image distance [tex]v=1.5f[/tex]
[tex]v=1.5\times 6.14\\v=9.21\ cm[/tex]
using lens formula
[tex]\dfrac{1}{v}+\dfrac{1}{u}=\dfrac{1}{f}[/tex]
insert values
[tex]\dfrac{1}{u}=\dfrac{1}{6.14}-\dfrac{1}{8.9}\\\\\dfrac{1}{u}=0.1628-0.1123\\\\\dfrac{1}{u}=0.0505\\\\u=19.80\ cm[/tex]
Thus, the distance of the object is 19.80 cm
Given:
Focal length, f = 6.14 cmNow,
The image distance will be:
→ [tex]v = 1.5 f[/tex]
[tex]= 1.5\times 6.14[/tex]
[tex]= 9.21 \ cm[/tex]
By using the lens formula, we get
→ [tex]\frac{1}{v} + \frac{1}{u} = \frac{1}{f}[/tex]
By putting the values, we get
→ [tex]\frac{1}{u} = \frac{1}{6.14} - \frac{1}{8.9}[/tex]
[tex]\frac{1}{u} = 0.1628-0.1123[/tex]
[tex]\frac{1}{u} = 0.0505[/tex]
[tex]u = 19.80 \ cm[/tex]
Thus the answer above is correct.
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The reliability or reproducibility of a measurement is its _____
The degree of data stability when the measurement is replicated under identical circumstances is known as reproducibility or reliability.
What exactly are repeatability and reproducibility?Reproducibility determines how an entire study an experiment can be replicated, whereas repeatability assesses the variation in data made by a single equipment or human under similar circumstances.
What makes repeatability crucial?Science needs reproducibility because it enables more in-depth investigation, and replication validates our findings. There are several investigations and experiments, which result in a wide range of variables, unforeseen, and things that are either outside your influence or you cannot guarantee.
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