Answer:
This law states that every particle attract every other particle in the universe with a force that is directly proportional to the product of their mass and inversely proportional to the square of the distance between the center
What will the answers for a ,b and c be
Answer:
A. 1.6 Hz
B. 1000 m/s²
C. 50000 N
Explanation:
A. Determination of the frequency.
Period (T) = 0.625 s
Frequency (f) =?
f = 1/T
f = 1/0.625
f = 1.6 Hz
B. Determination of the acceleration.
Radius (r) = 10 m
Velocity (v) = 100 m/s
Acceleration (a) =?
a = v²/r
a = 100² / 10
a = 10000 / 10
a = 1000 m/s²
C. Determination of the net force.
Mass (m) = 50 Kg
Acceleration (a) = 1000 m/s²
Net force (F) =?
F = ma
F = 50 × 1000
F = 50000 N
Assertion: In electrical circuits the connecting wires are usually made of thick copper wires. Reason: Thicker wires offer higher resistance and the wires are made of copper as the electrical conductivity of copper is low
a)Both A and R are true and R is the correct explanation of A.b)Both A and R are true, and R is not the correct explanation of A.c)A is true, but R is false. d)A is false, but R is true. e)Both A and R are false.
There actually three assertions here: one in A and two more in B.
All three assertions, as well as the reasoning described in this mess, are all False.
The correct choice from the list is e), but that doesn't even describe the complete Falseness of this disaster.
Calculate the magnitude of the electric field at one corner of a square 2.42 m on a side if the other three corners are occupied by 2.75×10−6 C charges.
Answer:
loloeuhsh
Explanation:
shwvwgnwajejjeisus
what is the movement of energy by waves
Answer; thermal energy
Explanation:
'Wave' is a common term for a number of different ways in which energy is transferred: In electromagnetic waves, energy is transferred through vibrations of electric and magnetic fields. In sound waves, energy is transferred through vibration of air particles or particles of a solid through which the sound travels.
Ms. Senko is moving a desk around her classroom, the desk weighs 125N.
The Coefficient of Static Friction between the desk legs and the floor is
0.35. The Coefficient of Kinetic Friction between the desk legs and the
floor is 0.23 WHAT IS THE FORCE OF FRICTION ON THE table as it is moving
Answer:
Static force of friction = 428.75 N
Kinetic Force of Friction = 281.75 N
Explanation:
The static force of friction is equal to Coefficient of static Friction * Mass * g
= 0.35 *125 * 9.8
= 428.75 N
The Kinetic force of friction is equal to Coefficient of kinetic Friction * Mass * g
= 0.23 *125 * 9.8
= 281.75 N
A marble is placed at the bottom of a semi-spherical bowl, as shown in the figure. The marble is then displaced from the bottom of the bowl to a position about halfway from the top of the bowl. The marble is then released from rest such that the marble always remains in contact with the bowl. Students observe that the marble rolls back and forth as it oscillates about the bottom of the bowl. Which of the following statements best explains why the marble undergoes oscillatory motion?
a)The sides of the bowl become steeper at positions farther from the bottom of the bowl.b) The net force exerted on the marble always has a component directed toward the bottom of the bowl. c) The normal force exerted on the marble decreases with increasing distance from the bottom of the bowl. D ) The gravitational force exerted on the marble is constant in magnitude and direction.
Answer:
It is D
Explanation:
The explanation why the marble undergoes oscillatory motion should be option D.
What is oscillatory motion?An object should be classified as the motion oscillates related to an equilibrium position because of the restoring force or torque. This motion should be significant to study various phenomena like electromagnetic waves, molecules. etc. In the case when the gravitational force should be exerted on the marble here the magnitude and the direction should be the same.
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A 67.0 kg person is riding in a car moving at 19.0 m/s when the car runs into a bridge abutment. (Assume the initial velocity is in the positive direction.) (a) Calculate the average force (in N) on the person if he is stopped by a padded dashboard that compresses an average of 1.00 cm. (Indicate the direction with the sign of your answer.) N (b) Calculate the average force (in N) on the person if he is stopped by an air bag that compresses an average of 15.0 cm. (Indicate the direction with the sign of your answer.) N
Answer:
a) F = - 1.21 10⁶ N, b) F = - 8.06 10⁴ N
Explanation:
a) For this part let's use the kinematics relations
v² = v₀² - 2 a x
distance traveled to stop is x = 1.00 cm = 0.0100 cm, final speed is zero
0 = v₀² - 2 ax
a = v₀² / 2x
a = [tex]\frac{19^2 }{2 \ 0.01}[/tex]
a = 1.81 10⁴ m / s²
this acceleration is in the opposite direction to velocity
let's use Newton's second law
F = ma
F = 67.0 (-1.81 10⁴)
F = - 1.21 10⁶ N
the negative sign indicates that it is going in the opposite direction to the speed
b) in this case it is stopped by an airbag x = 15.0 cm = 0.15 m
a = v₀² / 2x
a = [tex]\frac{19^2}{2 \ 0.15}[/tex]
a = 1.203 10³ m / s²
calculate the force
F = m a
F = 67.0 (- 1.203 10³)
F = - 8.06 10⁴ N
Please Help!!!
For A&B
Answer:
A. 40N
B. 5m/s
Explanation:
A.
Impulse is equal to the area under the curve of a force vs. time graph. In this case, the area is in the shape of a triangle with base 8 (12-4=8) and perpendicular height 10:
Area of a triangle = (1/2)bh
A=(1/2)*8*10
=40
ANSWER: 40N
B.
Impulse = mass * velocity
40 = 8v
v = 5
ANSWER: 5m/s
two automobiles a and b are travelling in the same direction in adjacent lanes are stopped at a traffic signal. as the signal turns green, automobile a accelerates at a constant rate of 2 m/s2. two seconds later, automobile b starts and accelerates at a constant rate of 3.6 m/s2. determine (a) when b will overtake a, (b) the speed of each automobile at that time, and c) the location where b overtakes a relative to the traffic signal. -truck
Answer:
a.5.85 s b i. 15.7 m/s ii. 21.1m/s c. 61.62 m
Explanation:
(a) when b will overtake a,
Using s = ut + 1/2at² we express the distance moved by each automobile.
Since both automobiles start at rest, their initial speed, u = 0 m/s, a = acceleration of automobile and t = time of travel or overtaking
So s = 0 × t + 1/2at²
s = 0 + 1/2at²
s = 1/2at²
Let time, t be the time the automobile b start, and its acceleration a = 3.6 m/s²
So, s = 1/2 × 3.6 m/s² × t² = 1.8t²
Since automobile a starts 2 seconds earlier, its time of travel is (t + 2) s. Since its acceleration, a = 2 m/s²,
s = 1/2 × 2 m/s² × (t + 2)²
s = (t + 2)²
Since both distances are equal at overtaking
(t + 2)² = 1.8t²
t² + 4t + 4 = 1.8t²
1.8t²- t² - 4t - 4 = 0
0.8t² - 4t - 4 = 0
dividing through by 0.8, we have
0.8t²/0.8 - 4t/0.8 - 4/0.8 = 0
t² - 5t - 5 = 0
Using the quadratic formula to find t,
[tex]t = \frac{-(-5) +/-\sqrt{(-5)^{2} - 4 X 1 X (-5)} )}{2 X 1} \\t = \frac{5 +/-\sqrt{25 + 20} )}{2} \\t = \frac{5 +/-\sqrt{45} )}{2} \\t = \frac{5 +\sqrt{45} )}{2} or \frac{5 -\sqrt{45} )}{2}\\t = \frac{5 + 6.708 )}{2} or \frac{5 - 6.708)}{2}\\t = \frac{11.708 )}{2} or \frac{-1.708}{2}\\t = 5.854 sor -0.854 s[/tex]
t ≅ 5.85 or -0.85
We take the positive answer since t cannot be negative.
So, t = 5.85 s
So, b will overtake a 5.85 s later.
(b) the speed of each automobile at that time,
Using v = u + at for each automobile, where u =initial speed of automobile = 0 m/s (since they both start from rest), a = acceleration of automobile and t = time of travel of automobile
i. Speed of automobile a
For automobile a, its time of travel is (t + 2) s = 5.85 s + 2 s = 7.85 s and its acceleration is 2 m/s²
So, v = u + at
= 0 m/s + 2 m/s² × 7.85 s
= 0 m/s + 15.7 m/s
= 15.7 m/s
ii. Speed of automobile b
For automobile a, its time of travel is t s = 5.85 s and its acceleration is 3.6 m/s²
So, v = u + at
= 0 m/s + 3.6 m/s² × 5.85 s
= 0 m/s + 15.7 m/s
= 21.06 m/s
≅ 21.1 m/s
c) the location where b overtakes a relative to the traffic signal. -truck
The location where b overtakes a relative to the traffic signal is the distance each automobile moves before overtaking. In section (a), we foundthat distance s = 1/2at² = (t + 2)² = 1.8t²
Using s = (t + 2)²
= (5.85 + 2)²
= 7.85²
= 61.6225 m
≅ 61.62 m
As you know a cube with each side 4 m in length has a volume of 64m3. Each side of the cube is now doubled in length. What is the ration if the new volume to the old volume
Answer:
The ratio of the new volume to the old volume is 8 to 1.
Explanation:
Let's first list what we know:
A cube has sides with lengths of 4 mThe volume of the cube is 64 [tex]m^3[/tex]The new cube has sides double the length of the old cubeSince the new cube has sides double the length of the sides of the old cube, and 4 doubled is 8, the length of the sides of the new cube is 8.
The equation for the volume of a cube is [tex]V = s^3[/tex], where "V" is the volume and "s" is the lengths of the sides.
Now, let's solve for the volume of the new cube:
[tex]V = s^3[/tex]
[tex]V = 8^3[/tex]
[tex]V = 512[/tex]
The volume of the new cube is 512 [tex]m^3[/tex].
The ratio of the new volume to the old volume is 512 : 64.
Let's simplify the ratio:
512 : 64
8 : 1
The ratio of the new volume to the old volume is 8 to 1.
P.S. This question should be in the mathematics subject, not the physics subject. (I pretty much only do math problems, so yes, it does matter. I don't know about the others though.)
An 8.20 kg object is pulled along a horizontal surface by a force of 22.0 N. If its acceleration is 1.1 m/s2, what is the coefficient of friction between the two surfaces?
Answer:
0.5
Explanation:
In this picture,
13
Which of the following properties makes a light wave different from all mechanical waves?
A A light wave slows down in a vacuum.
B A light wave is able to transmit energy.
A light wave exists as a transverse wave.
D A light wave can travel without a medium.
Answer:
D. A light wave can travel without a medium.
Explanation:
Light wave can be defined as an electromagnetic wave that do not require a medium of propagation for it to travel through a vacuum of space where no particles exist.
On the other hand, mechanical waves such as sound are highly dependent on matter for their propagation and transmission.
This ultimately implies that, the properties which makes a light wave different from all mechanical waves is that, a light wave can travel without a medium of propagation.
A hunter on a frozen, essentially frictionless pond uses a rifle that shoots 4.20 gg bullets at 970 m/sm/s. The mass of the hunter (including his gun) is 69.5 kgkg, and the hunter holds tight to the gun after firing it. You may want to review (Page) . For related problemsolving tips and strategies, you may want to view a Video Tutor Solution of Collision along a straight line. Part A Find the recoil speed of the hunter if he fires the rifle horizontally.
Answer:
[tex]0.059\ \text{m/s}[/tex]
Explanation:
[tex]m_1[/tex] = Mass of bullet = 4.2 g
[tex]u_1[/tex] = Initial velocity of bullet = 0
[tex]m_2[/tex] = Mass of hunter with rifle = 69.5 kg
[tex]u_2[/tex] = Initial velocity of hunter with rifle
[tex]v_1[/tex] = Final velocity of the bullet = 970 m/s
[tex]v_2[/tex] = Final velocity of the hunter with the rifle
As the momentum of the system is conserved we have
[tex]m_1u_1+m_2u_2=m_1v_1+m_2v_2\\\Rightarrow v_2=\dfrac{m_1u_1+m_2u_2-m_1v_1}{m_2}\\\Rightarrow v_2=\dfrac{0-0-0.0042\times 970}{69.5}\\\Rightarrow v_2=-0.059\ \text{m/s}[/tex]
The recoil speed of the hunter is [tex]0.059\ \text{m/s}[/tex] in the opposite direction of the bullet.
Calories are a unit of energy that are reserved for heat energy but can be
directly converted to and from mechanical units of energy (Joules). How
many calories of energy are there in 500 Joules of energy?
A magnetic field is passing through a loop of wire whose area is 0.026 m2. The direction of the magnetic field is parallel to the normal to the loop, and the magnitude of the field is increasing at the rate of 0.24 T/s. (a) Determine the magnitude of the emf induced in the loop. (b) Suppose the area of the loop can be enlarged or shrunk. If the magnetic field is increasing as in part
Answer:
a) 6.24 × 10⁻³ V
b) 4.16 × 10⁻³ m²/s
Explanation:
Given that:
(a)
Area A = 0.026 m²
[tex]\dfrac{dB}{dt}=0.24 \ T/s[/tex]
[tex]e=\dfrac{d\phi}{dt} \\ \\ = \dfrac{d}{dt}(BA) \\ \\ =A\dfrac{dB}{dt} \\\\= 0.026 \times 0.24 \\ \\ = 0.00624\ V \\ \\ \mathbf{= 6.24 \times 10^{-3} \ V}[/tex]
(b)
[tex]Here; \\ \\ e =0\\\\ \dfrac{d}{dt}(BA) =0 \\ \\ \implies B\dfrac{dA}{dt}+ A\dfrac{dB}{dt} = 0 \\ \\ B\dfrac{dA}{dt}= -A\dfrac{dB}{dt} \\ \\ \dfrac{dA}{dt}= -\dfrac{A}{B} \dfrac{dB}{dt} \\ \\ = -\dfrac{0.026}{1.5}\times 0.24 \\ \\ \dfrac{dA}{dt}= 4.16 \times 10^{-3}\ m^2/s[/tex]
All objects have an electric charge, what are the options they could have select all that apply.
Positive
Negative
Neutral
Right an essay about 250-200 words about water
Answer:250-200l Water
Explanation:
PLEASE HELP ASAP!
A machine has an efficiency of 70%. What happens to the other 30% of the work?
Answer:
The other 30% is lost from friction.
Explanation:
friction 30% ---> |O| <------ 70% work
A machine has an efficiency of 70%, and the remaining 30% of the input work is lost as waste energy or dissipated in the form of heat, noise, or vibration, which cannot be harnessed to do any useful work.
What is work done by machine?In any machine, the total work input is equal to the total work output plus any work that is lost or dissipated due to various factors such as friction, heat transfer, etc., so, for example, if a machine receives 100 units of energy as input, only 70 units of energy are converted into useful output work, and the remaining 30 units of energy are lost as waste energy.
Hence, the remaining 30% of the input work is lost as waste energy or dissipated in the form of heat, noise, or vibration, which cannot be harnessed to do any useful work.
Learn more about the work by machine here.
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Piano tuners tune pianos by listening to the beats between the harmonics of two different strings. When properly tuned, the note A should have the frequency 440 Hz and the note E should be at 659 Hz. The tuner can determine this by listening to the beats between the third harmonic of the A and the second harmonic of the E. A tuner first tunes the A string very precisely by matching it to a 440 Hz tuning fork. She then strikes the A and E strings simultaneously and listens for beats between the harmonics. What beat frequency indicates that the E string is properly tuned
Answer:
The beat frequency = 2.0 Hz
Explanation:
From the given information
The 3rd harmonic frequency of the note is equivalent to thrice note A fundamental frequency.
i.e.
[tex]f_{3A} = 3f_A[/tex]
where;
[tex]f_A =[/tex] note A fundamental freq.
replacing 440 Hz for [tex]f_A[/tex]
[tex]f_{#a} = 3 (440 \ Hz)[/tex]
[tex]f_{3A} = 1320 Hz[/tex]
However, the 2nd harmonic of the E is equivalent to two times the fundamental frequency of the note E.
i.e.
[tex]f_{2E} = 2f_E[/tex]
[tex]f_E =[/tex] note E fundamental freq.
replacing 659 Hz for [tex]f_E[/tex]
[tex]f_{2E} = 2(659)[/tex]
[tex]f_{2E} = 1318 \ Hz[/tex]
Finally, the beat frequency when the E string is properly tuned is:
[tex]\Delta f = f_{3A}-f_{2E}[/tex]
[tex]\Delta f = 1320 \ Hz - 1318 \ Hz[/tex]
[tex]\Delta f = 2.0 \ Hz[/tex]
Thus, the beat frequency = 2.0 Hz
An 85-year-old woman who was having trouble breathing checked into the hospital. There, her heart stopped beating and doctors determined she suffered heart failure. After being resuscitated, she was in a coma and had no brain function. Her family then made the difficult decision to take her off life support, and the woman passed away.
Which order of events did the woman experience?
brain death Right arrow. clinical death Right arrow. somatic death
somatic death Right arrow. brain death Right arrow. clinical death
clinical death Right arrow. brain death Right arrow. somatic death
clinical death Right arrow. somatic death Right arrow. brain death
Answer:c
Explanation:
clinical death Right arrow. brain death Right arrow. somatic death this order of events did the woman experience. Hence option C is correct.
What is death ?The permanent end of all biological activities that support an organism is defined as death. Death may also be defined as the permanent cessation of functioning of the entire brain, including the brainstem, in creatures with a brain, and brain death is frequently used as a legal definition of death.Normally, the remnants of a previous creature begin to degrade quickly after death. Death is an unavoidable process that happens in all species. Turritopsis dohrnii, for example, is physiologically immortal. They can, however, perish from causes other than ageing.
It has been difficult to determine when someone has died. Initially, death was defined as the cessation of breathing and heartbeat.
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A soft drink (mostly water) flows in a pipe at a beverage plant with a mass flow rate that would fill 220 0.355 - L cans per minute. At point 2 in the pipe, the gauge pressure is 152kPa and the cross-sectional area is 8.00cm2. At point 1, 1.35m above point 2, the cross-sectional area is 2.00cm2. Part A Find the mass flow rate. M
Answer:
[tex]1.302\ \text{kg/s}[/tex]
Explanation:
[tex]\rho[/tex] = Density of water = [tex]1\ \text{kg/L}[/tex]
[tex]dV[/tex] = Change in volume = [tex]220\times 0.355\ \text{L}[/tex]
[tex]dt[/tex] = Time elapsed = 1 minute = 60 seconds
Mass flow rate is given by
[tex]\dot{m}=\rho\dfrac{dV}{dt}\\ =1\times \dfrac{220\times 0.355}{60}\\ =1.302\ \text{kg/s}[/tex]
The mass flow rate is [tex]1.302\ \text{kg/s}[/tex].
In the nitrogen cycle, plants take in nitrates and convert them into
How can we calculate gravitational acceleration?
A 6.25 g quarter sits 25 cm from the axis of rotation on a turntable that has a period of rotation of 1.8 seconds.
What must the coefficient of static friction be in order to keep the quarter from sliding outward when the
turntable is in motion?
The coefficient of static friction be in order to keep the quarter from sliding outward when the turntable is in motion will be 0.31.
What is the friction force?It is a type of opposition force acting on the surface of the body that tries to oppose the motion of the body. its unit is Newton (N).
Mathematically it is defined as the product of the coefficient of friction and normal reaction.
On resolving the given force and acceleration in the different components and balancing the equation gets. The friction force balances centripetal force.
The given data in the problem will be;
m is the mass =6.25 g
r is the radius =25 cm=0.25 m
t is the time = 0.18 sec
μ is the coefficient of static friction =?
[tex]\rm F_c= mw^2r \\\\ f= \mu mg \\\\ F_C=f\\\\ mw^2r= \mu mg \\\\ \rm \mu = \frac{\omega^2r}{g} \\\\ \rm \mu = (\frac{2\pi}{1.8} )^2\frac{0.25}{9.81} \\\\ \rm \mu = 0.31[/tex]
Hence the coefficient of static friction will be 0.31.
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Question 1 of 10 Which characteristic of nuclear fission makes it hazardous?
O A. The process destroys every atomic nucleus that goes through it.
O B. The process changes existing atoms into atoms of different elements
C. The process requires very high pressures.
O D. The radioactive wastes it produces can spread to any part of the environment
Answer:
D.
The radioactive wastes it produces can spread to any part of the environment.
Explanation:
Fission is the name given to the splitting of a heavy nucleus into two medium-mass nuclei. Fission is said to be induced if it results from the absorption of a neutron to form an unstable nucleus that decays by fission. The induced fission usually produces further neutrons accompanying the fission fragments.
Answer: D. The radioactive wastes it produces can spread to any part of the environment
Explanation:
Please PLEASE HELP ASAP
A student placed four objects on a plastic tray: a rock, an eraser, a wood block, and an ice cube. The student slowly lifts the tray and measures the height at which each object begins to slide in order to compare the friction of each object. The table above shows the results. In a separate experiment the student used the same objects and tray, but glued a piece of gritty sandpaper to the tray. What results would be expected? A) The items would slide faster at the same heights. B) The items would start to slide when the tray is not lifted as high. C) The items would not slide at all, no matter how high the tray is raised. D) The tray would need to be raised higher before the items start to slide.
Answer:
D) The tray would need to be raised higher before the items start to slide.
Explanation:
The tray would need to be raised higher due to the gritty sandpaper causing it to have more grip or fraction between the two surfaces. In the first experiment it would have a smooth surface to slide across but in the second experiment it would have a rougher surface to slide across.
Example: It would be like taking two different kinds of shoes like tennis shoes and football cleets. Then seeing which one has more traction when going up a hill.
Hope this helps!!
the melting point and boiling point of Ice are respectively
a. 273k,373k. b. 373k,273k c.0k,100k d.100k,0k
a. 273k,373k
This is the answer.
what is a magnet? types of magnet
Answer:
Magnet withe competitive prices and high quality they offer custom-made magnets in defferent form and made with defferent materials grades
Explanation:
Sana makatolong
h. Briefly describe the process taking place in the image below and comment on the
function of the molecule at stage 1 and 3
(6)
pat
AHEMHFgjrhfrshfghesgrgregr
what foxes need to eat to
stay alive
Answer:
They eat meat and vegetation.Answer:
Meat and vegetation...