Squids propel themselves by expelling water. They do this by keeping water in a cavity and then suddenly contracting the cavity to force out the water through an opening. A 9 kg squid (including the water in the cavity) at rest suddenly sees a dangerous predator. If the squid expels 2 kg of water out of its body with a speed of 8 m/s, what would be its own escape speed

Answer:

Multiply the x values with -1.

Explanation:

By multiplying the numbers by one, you are changing them to be the opposite of their original state.

You multiply the numbers that are in the x-value column because you are reflecting the image over the y-axis.

Hope this helped and good luck!

Answer:

Multiply each x-value in the table by -1

Explanation:

Answer:

Explanation:

In physics, there are two types of physical quantities namely the fundamental and the derived quantities. Fundamental quantities are independent quantities on which derived quantities depends on. Length, mass and time are examples of fundamental quantities.

The SI unit of length is meters. A meter is a multiple unit. Its submultiple units are centimetres (10⁻²metres), kilometres (10³metres), decimetres (10⁻¹metres) etc

The SI unit of mass is kilogram (kg). The only sub multiple unit used in real-life situation is grams.

1 kg = 100 grams

The SI unit of time is seconds. The multiple units are the minutes, hours, weeks, days and years.

1 minute = 60 seconds

1 hour = 3600 seconds

1 day = 24 * 3600 = 86,400 secs

Answer with explanation:

Complete question is provided in the attachment below.

There are 3 undefined term in geometry :1) A Point  2)  A line 3) A Plane.

When two lines are parallel they never meet , so the requirement to define them is lines and a plane on which they lie.

While when two lines are perpendicular , they intersect each other at a point by making a right angle between them.

So it required lines and a point to define it.

Answer:

72.16 N

Explanation:

Given:

q₁ = -53.0 μC

q₂ = 105 μC

q₃ = -88.0 μC

q₁ to q₂ = 0.50 m

q₂ to q₃ = 0.95 m

To find:

Net force on q₃

Solution:

First compute net electric field on q₃

E = F/q = k.Q/d²

The formula of electric field at q₃:

E = k.Q / r²

Where    

r is distance

Q is magnitude of charge

k is a constant with a value of 8.99 x 10⁹ N m²/C²

When

q₂ to q₃ = 0.95m and

q₂ = 105 μC then

Find electric field due to charge q₂

E = ( (8.99 x 10⁹)x( 105 x 10⁻⁶) ) / 0.95²

  =  (8990000000  x 0.000105) / 0.9025

  = 943950  / 0.9025

  = 1045927.977839

  = 1.046 x 10⁶ N/C

This interprets that it will act or point away from q₂

q₁ to q₂= 0.50m

q₂ to q₃ = 0.95m and

q₁ = -53 μC then

Find electric field due to charge q₁

E = (8.99 x 10⁹) x (53 x 10⁻⁶) / (0 .50 + 0.95)²

  =  (8990000000  x  0.000053) / (1.45)²

  = 476470 /2.1025

  = 226620.689655

  = 0.227  x 10⁶ N/C

This interprets that it will act or point towards q₁

Since these fields are opposite in direction.

Compute Net Field

Net Field = 1.046 x 10⁶ - 0.227  x 10⁶ N/C

               =  1046000 - 227000

               = 819000

               = 0.819 x 10⁶

               ≈ 0.82 x 10⁶

This interprets that it will act or point away from q₂

Compute force on q3

q₃ E  = 88 x 10⁻⁶ x 0.82 x 10⁶

       = 88000000  x 820000

       = 72160000000000

       = 72.16 N

Force on -ive charge in a field is always in a direction opposite to direction of field

So this interprets that direction of this field will be towards q₂.

[tex]\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}[/tex]

Actually Welcome to the Concept of the Electrostatics.

Basically here we can see that, the Negative test charge usually a Electron is facing a force from the right side, this we can say that a Electric field as like charge is creating a repulsive force from the right to left side.

thus,

1) The electric field points to the left because the force on a negative charge is opposite to the direction of the field.

Answer:

c. Intensity

Explanation:

Wavelength is a distance (meters).

Speed is distance per time (meters / second).

Intensity is power per area (Watts / square meter).

Pitch is frequency (cycles / second).

Explanation:

let us use the explanation below to get the intuition so desired;

According to Faraday's law of electro magnetic induction, when ever a coil/conductor is made to rotate in a magnetic field, voltage or emf is created and current is produced, in the long run energy has be produced or converted.

The conversion of this energy is made possible by the motion of the coil/conductor is the magnetic field, just by the  motion of the conductor cutting through the magnetic field, thus creating electro motive force(E.M.F) hence producing current, and ultimately energy is created

Answer:

5.5 m/s^2

Explanation:

I believe this is the answer > using the formula a= v-v0/t

Hope this helps!

Answer:

-1 m/s²

Explanation:

Given:

Δx = 32 m

v₀ = 10 m/s

t = 4 s

Find: a

Δx = v₀ t + ½ at²

32 m = (10 m/s) (4 s) + ½ a (4 s)²

a = -1 m/s²

Answer:

(a) By small angle approximation, we have;

F = -2×T×Δy/l

(b) [tex]The \ frequency \ of \ oscillation, \ f = \dfrac{1}{2\cdot \pi }\cdot\sqrt{\dfrac{2 \cdot T}{l \cdot M} }[/tex]

Explanation:

(a) The diagram shows the mass, M, being restored by two equal tension, T acting on the elastic strings l, such the restoring force, F acts along the path of motion of the mass, with distance Δy

Therefore, the component of the tension T that form part of the restoring force is given as follows;

Let the angle between the line representing the extension of the elastic strings T and the initial position of the string = ∅

Then we have;

String force, [tex]F_{string}[/tex] = T×sin∅ + T×cos∅ + T×sin∅ - T×cos∅  = 2×T×sin∅

Whereby the angle is small, we have;

sin∅ ≈ tan∅ = Δy/l

Which gives;

[tex]F_{string}[/tex] = 2×T×sin∅ = 2×T×Δy/l (for small angles)

Restoring force F = [tex]-F_{string}[/tex] = -2×T×Δy/l

F = -2×T×Δy/l

(b) Given that the the tensions do not change appreciably as the mass, M, oscillates from Δy we have;

By Hooke's law, F = -k×x

Whereby Δy corresponds to the maximum displacement of the mass, M from the rest position, which gives;

Which gives;

F = M×a = -k×Δy

a =  -k×Δy/M

d²(Δy)/dt² =  -k×Δy/M

When we put angular frequency as follows;

ω² = k/M

We get;

d²(Δy)/dt² =  -ω²×Δy

Which gives;

Δy(t) = A×cos(ωt + Ф)

The angular frequency is thus, ω = √(k/M)

Period of oscillation = 2·π/ω = 2·π/√(k/M)

The frequency of oscillation, f = 1/T = √(k/M)/(2·π)

Where:

k = 2·T/l, we have;

f = √(k/M)/(2·π) = √(2·T/l)/m)/(2·π)

The frequency of oscillation is given as follows;

[tex]f = \dfrac{1}{2\cdot \pi }\cdot\sqrt{\dfrac{2 \cdot T}{l \cdot M} }[/tex]

Answer:

BETTER EXPLANATION

Explanation:

When you drink from a straw, you create a little space of low pressure inside your mouth and in the top of the straw. Then the air outside the straw pushes down on the surface of the drink and forces the liquid up through the straw and into your mouth.

Answer:

-4m/s

Explanation:

use the formula

[tex]f = ma[/tex]

where f-force

m-mass

a-accleration

so

1kN=1000N

so apply

4000=1000×a

a=4m/s

(the negative is because the car was braking)

Answer:

Your answer is -4 m/s^2

Explanation:

Set Up: Let +x be the direction the car is traveling.  

List the known & unknown quantities:  

   m = mass of the car = 1000 kg

  υ = 30 m/s

  Fx = –4 kN = –4000 N (negative since it is a braking force)

  ax = acceleration =?  

Solve: Use Newton’s second law of motion.  

Fx=max    

ax=Fx/m = −4000 N /1000 kg = −4000 kg·m/s^2 / 1000 kg =−4m/s^2

Answer:

S1 = 1/2 g t^2     distance stone falls in time t

S2 = Vy t - 1/2 g t^2   distance thrown stone rises in time t

H = 49 = S1 + S2 = Vy t

t = 49 / 40 sec   time when stones meet

Check:

Stone 1 falls:      1/2 g t^2 = 1/2 * 9.8 * (49 / 40)^2 = 7.35 m

Stone 2 rises :  40 * (49 / 40) - 1/2 * 9.8 (49 / 40)^2 = 41.65 m

Answer:

a = 30 km / h²

Explanation:

Dado que

Velocidad inicial, u = 70 km / h

Velocidad final, v = 95 km / h

Tiempo, t = 30 s = 0.1 h

Lo sabemos

v = u + a t

a = aceleración

Ahora poniendo los valores en la ecuación anterior

[tex]95 = 70 + a \ times 0.1 [/tex]

[tex]a = \ dfrac {95-70} {0.1} = 30 \ km / h ^ 2 [/tex]

Por lo tanto, la aceleración será

a = 30 km / h²

Answer:

Q1 acceleration = 16m/s²

Q2 Net force = 9N North

Explanation:

Q1 Using the formula F=ma

Q2 R = F1 + F2

Answer:

 K = 9.53 MeV

Explanation:

The kinetic energy that the alpha particle has emitted, is the energy in excess after removing the resting energy of the atoms and the helium nucleus that forms the alpha particle

Since energy and masses are related and cannot be

          m₀ c² = [tex]m_{f}[/tex] c² + m_He c²+ K

          K = c² (m₀ - m_{f} - m_He)

the mass of the Helium atom is 4 u

           K = (3 10⁸)² (211,988868 -207.976652 - 4,002) 1,661 10⁻²⁷

           K = 14,949 10⁻¹¹ (0.0102)

          K = 1,527 10⁻¹² J

let's reduce 1 J = 6,242 10¹² MeV

           K = 9.53 MeV

Answer:

[defined as]

Explanation:

it is the missing word

a).  frequency = (speed) / (wavelength)

The speed of light is around 3 x 10⁸ m/s.

For 380 nm (violet light), frequency = (3 x 10⁸ m/s) / (380 x 10⁻⁹ m)

Frequency = 7.89 x 10¹⁴ Hz

For 760 nm (red light), frequency = (3 x 10⁸ m/s) / (760 x 10⁻⁹/s)

Frequency = 3.94 x 10¹⁴ Hz

The ratio is 2 .

That's 1 octave, or 0.3 of a decade.

b).  The ratio of highest/lowest sounds is (20,000 Hz/20 Hz) = 1,000

That's 3 decades, or about 10 octaves.

===> Speaking logarithmically ( ! ), ears are sensitive to a range of sound frequencies that's 10 times as wide as the range of light frequencies that eyes can detect.

Answer:

W =1562.53 N

Explanation:

It is given that,

Radius of the aluminium ball, r = 24 cm = 0.24 m

The density of Aluminium, [tex]d=2698.4\ kg/m^3[/tex]

We need to find the thrust and the force. The mass of the liquid displaced is given by :

[tex]m=dV[/tex]

V is volume

Weight of the displaced liquid

W = mg

[tex]W=dVg[/tex]

So,

[tex]W=dg\times \dfrac{4}{3}\pi r^3\\\\W=2698.4\times 10\times \dfrac{4}{3}\times \pi \times (0.24)^3\\\\W=1562.53\ N[/tex]

So, the thrust and the force is 1562.53 N.

Answer:

D. AC+BD -> AD +BC

Explanation:

I got it right

A double displacement reaction is also called the double replacement reaction or double decomposition reaction. Here AC + BD → AD + BC is a double displacement reaction. The correct option is D.

A double displacement reaction is defined as a chemical reaction in which the positive and negative ions of two ionic compounds exchange their places to form two new compounds. The general form of a double displacement reaction is given as:

AC + BD → AD + BC

Here 'A' and 'B' are positively charged cations, whereas 'C' and 'D' are negatively charged anions. The double displacement reactions generally occur between the substances in an aqueous solution. In order for a reaction to occur, one of the products is usually a solid precipitate, a gas or a molecular compound like water.

Thus the correct option is D.

To know more about double replacement reaction, visit;

https://brainly.com/question/13870042

#SPJ3

Answer:

λ = 1.8 x 10⁻⁷ m = 180 nm

Explanation:

First we find the work function of tungsten by using the following formula:

∅ = hc/λmax

where,

∅ = work function = ?

h = Plank's Constant = 6.626 x 10⁻³⁴ J.s

c = speed of light = 3 x 10⁸ m/s

λmax = maximum wavelength for photoelectric emission = 230 nm

λmax = 2.3 x 10⁻⁷ m

Therefore,

∅ = (6.626 x 10⁻³⁴ J.s)(3 x 10⁸ m/s)/(2.3 x 10⁻⁷ m)

∅ = 8.64 x 10⁻¹⁹ J

Now we convert Kinetic Energy of electron into Joules:

K.E = (1.5 eV)(1.6 x 10⁻¹⁹ J/1 eV)

K.E = 2.4 x 10⁻¹⁹ J

Now, we use Einstein's Photoelectric Equation:

Energy of Photon = ∅ + K.E

Therefore,

Energy of Photon = 8.64 x 10⁻¹⁹ J + 2.4 x 10⁻¹⁹ J

Energy of Photon = 11.04 x 10⁻¹⁹ J

but,

Energy of Photon = hc/λ

where,

λ = wavelength of light = ?

Therefore,

11.04 x 10⁻¹⁹ J = (6.626 x 10⁻³⁴ J.s)(3 x 10⁸ m/s)/λ

λ = (6.626 x 10⁻³⁴ J.s)(3 x 10⁸ m/s)/(11.04 x 10⁻¹⁹ J)

λ = 1.8 x 10⁻⁷ m = 180 nm

Explanation:

Ohm's law gives the relationship between current, voltage, and resistance. Its mathematical form is given by :

V = IR

I is current and R is resistance

Resistance resists the flow of electric current in a circuit. When the amount of applied voltage is increased, it will not change the resistance. It increases the current. Hence, the correct option is (C).

Answer:

Explanation:

Given,

Mass ( m ) = 70 kg

Distance ( d ) = 4.5 m

Time taken ( t ) = 4 seconds

Power = ?

Now, applying the formula to find power:

[tex]power = \frac{work \: done}{time \: taken} [/tex]

[tex] = \: \frac{f \: \times \: d}{t} [/tex]

[tex] = \frac{m \: \times \: g \: \times \: d}{t} [/tex]

Plugging the values:

[tex] = \frac{70 \times 9.8 \times 4.5}{4} [/tex]

Calculate the products

[tex] = \frac{3087}{4} [/tex]

Divide:

[tex] = 771.75 \: watt[/tex]

Hope this helps...

Best regards!!

Answer:

A primary source is an original document such as diaries, speeches, manuscripts, letters, interviews, records, eyewitness accounts, autobiographies. Empirical scholarly works such as research articles, clinical reports, case studies, dissertation

Explanation:

Answer:

Scientific paper

Explanation:

A p e x

Explanation:

momentum = mass x velocity

momentum = 40 x 20 = 800kgm/s

Answer:

800kgm/s

Explanation:

momentum= mass×velocity

= 40×20

= 800kgm/s

Answer:

Ok, sabemos que la velocidad inicial de la pelota es 15m/s.

Desconocemos la posición inicial a la que es lanzada la pelota, pero vamos a suponer que es a una altura igual a cero, es decir, la pelota es lanzada al ras del suelo.

Una vez lanzada, la única fuerza actuando en la pelota es la gravitatoria, entonces la aceleración de la pelota es:

a = -g = -9.8m/s^2

El signo negativo es por que esta aceleración apunta hacia abajo.

Ahora, para la velocidad, necesitamos integrar sobre el tiempo.

v(t) = (-9.8m/s^2)*t + v0

donde v0 = 15m/s

v(t) = (-9.8m/s^2)*t + 15m/s.

De aca podemos obtener el tiempo en el que la pelota llega a la altura máxima, que es el punto donde la velocidad es igual a cero.

0 = (-9.8m/s^2)*t + 15m/s.

t = (15/9.8)s = 1.53 s

Ahora, para la ecuación de la posición integramos la ecuación de la velocidad sobre el tiempo:

p(t) = (1/2)(-9.8m/s^2)*t^2 + 15m/s*t + p0

donde p0 es la pocision inicial, pero arriba dijimos que era igual a cero, entonces la ecuación queda:

p(t) = (-4.5m/s^2)*t^2 + 15m/s*t

ahora reemplazamos t por el tiempo que encontramos antes, y descubrimos que:

p(1.53s) =  (-4.5m/s^2)*(1.53s)^2 + 15m/s*1.53s = 12.41m

La máxima altura que alcanza la pelota es 12.41 metros arriba del punto desde el que se la lanzo.

Ahora, el tiempo total que esta en el aire puede ser calculado de tal forma que la posición vuelva a ser cero, es decir, la pelota llega a la misma altura desde la que fue lanzada inicialmente (y es agarrada por la persona, podemos suponer)

Entonces:

p(t) = 0 =  (-4.5m/s^2)*t^2 + 15m/s*t

Ahora resolvemos la eq cuadrática, usando la eq. de Bhaskara:

[tex]t = \frac{-15 +- \sqrt{15^2 - 4*(-4.5)*0} }{-2*4.5} = \frac{-15 +-15}{-9.8}[/tex]

Entonces las soluciones son:

t = (-15 + 15)/-9.8 = 0s

t = (-15 - 15)/-9.8 = 3.06s

Tomamos la segunda solución, ya que la primera corresponde al tiempo inicial.

Entonces concluimos con que la pelota estuvo 3.06 segundos en el aire.

Answer:

[tex]\boxed{ V_{2}= 0.03189 m^3}[/tex]

Explanation:

According to Charles Law

=> [tex]\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}[/tex]

Where [tex]V_{1}[/tex] = 0.0279 m³, [tex]T_{1}[/tex] = 280 K and [tex]T_{2}[/tex] = 320 K

=> [tex]\frac{0.0279}{280} = \frac{V_{2}}{320}[/tex]

=> [tex]V_{2}[/tex] = 0.03189 m³

Answer:

The potential difference at the customer's house is 117.1 V.

Explanation:

a) The potential difference at the customer's house can be calculated as follows:

[tex] \Delta V_{h} = \Delta V_{p} - \Delta V_{l} [/tex]

Where:

[tex]V_{h}[/tex]: is the potential difference at the customer's house

[tex]V_{p}[/tex]: is the potential difference from the main power lines = 120 V

[tex]V_{l}[/tex]: is the potential difference from the lines

[tex] \Delta V_{h} = \Delta V_{p} - IR [/tex]

The resistance, R, is:

[tex]\frac{0.109 \Omega}{300 m}*2*34.0 m = 0.025 \Omega[/tex]

Now, the potential difference at the customer's house is:

[tex]\Delta V_{h} = 120 V - 116A*0.025 \Omega = 117.1 V[/tex]

Therefore, the potential difference at the customer's house is 117.1 V.

I hope it helps you!

Answer:

λ₀ = 2 d n

Explanation:

A soap film is a layer where the lus is reflected on the surface and on the inside of the film, these two reflected rays can interfere with each other either constructively or destructively.

Let's analyze the general conditions of this interference,

* When the ray of light reaches the surface of the film it is reflected, as the index of refraction of the air is less than the index of the film, the reflected ray has a phase change of 180º

* When the ray penetrates the film, its wavelength changes due to the refractive index of the film.

          λ = λ₀ / n

where lick is the wavelength in the vacuum or air and n index of refraction of the film, in general this interference is observed perpendicular to the film, so the sine veils 1. the expression for constructive interference taking in what previous remains

         2d = (m + ½) λ

the expression for destructive interference remains

         2d = m λ

          2d = m λ₀ / n

When the film is placed on a glass plate whose index of refraction is greater than the index of refraction of the film, in the reflection in the lower part of the film another phase difference of 180º is created, for which we have a difference of total phase of 180 +180 = 360º, which is equivalent to no phase difference, therefore the two previous equations are interchanged.

Therefore where we had destructive interference now a cosntructive interference happens we can see the reflected light.

Find us the wavelength that this constructive interference creates

           2d n = m λ₀

           λ₀ = 2 d n / m

To find the minimum wavelength, suppose we observe the first interference pattern m = 1

         λ₀ = 2 d n

where d is the thickness of the film and n the index of refraction of the same

Answer:

Explanation:

the resistance of a electrical device

R = V² / P where V is volt and P is power .

The devices are in parallel so same volt will apply on them

So R₁ = 12² / 32.5 = 4.431 ohm

R₂ = 12² / 2 x 10³ = .072 ohm

when they are in series

Common Current in them = 12 / 4.431 + .072

= 2.6649 A

power consumed by first device when they are in series

= current² x resistance

= 2.6649² x 4.431 = 31.46 W

power consumed by other

= 2.6649² x .072  = .511 W

Answer:

The safe distance is 199 cm approximately 200 cm

Explanation:

Safe intensity = 1.00 W/m^2

wattage of radar leaked radar = 50.0 W

safe distance from the microwave will be = ?

We know that the intensity of a wave radiated uniformly in all direction is given as

[tex]I[/tex] = [tex]\frac{W}{A}[/tex]

where

W is the wattage of the leaked radar

A is the radial area, which is the area of a sphere that encapsulates the region through which this wave spreads uniformly.

From the equation above,

[tex]A[/tex] = [tex]\frac{W}{I}[/tex] = 50/1 = 50 m^2

But the area of this sphere [tex]A[/tex] = [tex]4\pi r^{2}[/tex]

where

r is the safe distance from the radar source

substituting for the area, we have

50 = 4 x 3.142 x [tex]r^{2}[/tex]

50 = 12.568 [tex]r^{2}[/tex]

[tex]r^{2}[/tex] = 50/12.568 = 3.978

r = [tex]\sqrt{3.978}[/tex] = 1.99 m = 199 cm ≅ 200 cm