square root of 1024 using fractorization method​

Answer:

the awnser is A becuse the hair help.

Answer:

The corridor's distance is "90 m".

Explanation:

Now,

⇒  [tex]2x + 2y = 60[/tex]

⇒  [tex]x + y = 30[/tex]

The total distance of the corridor will be:

=  [tex]x + 2x + 2y + y[/tex]

=  [tex]3\times (x + y)[/tex]

=  [tex]3\times 30[/tex]

=  [tex]90 \ m[/tex]

Answer:

the mantle.

Explanation:

The mantle is the mostly-solid bulk of Earth's interior. The mantle lies between Earth's dense, super-heated core and its thin outer layer, the crust. It's practically hot lava (Magma) Flowing and causing earthquakes and what not.

Hope this helps :)

Answer:

The answer is

Explanation:

The distance covered by an object given it's velocity and time taken can be found by using the formula

From the question

velocity = 1.45 × 10² m/s

time = 1.8 × 10³ s

We have

distance = 1.45 × 10² × 1.8 × 10³

We have the final answer as

[tex]2.61 \times {10}^{5} \: \: m[/tex]

Hope this helps you

Answer:

32m

Explanation:

v=u+at

v=0+2×4

v=8m/s

d=vt

d=8×4

d=32m

Answer:

Net force = 11340 N

Explanation:

Given that,

Mass of an automobile, m = 2100 kg

Acceleration of the automobile, a = 5.4 m/s²

We need to find the net force required for the automobile. The net force is the product of mass and acceleration. It can be given by the formula as follows :

[tex]F=ma\\\\F=2100\ kg\times 5.4\ m/s^2\\\\F=11340\ N[/tex]

So, the net force is 11340 N.

Recall the definition of average velocity:

average v = ∆x / ∆t

The driver moves a distance of ∆x = 4.25 km = 4250 m in 2 min = 120 s, so the average velocity is

average v = (4250 m) / (120 s) ≈ 35.4 m/s

Under constant acceleration, the average velocity can also be computed by taking the average of the initial and final velocities:

average v = (initial v + final v) / 2

Solve for (final v) :

35.4 m/s = (20 m/s + final v)/2

final v ≈ 50.83 m/s

Recall the definition of average acceleration:

average a = ∆v / ∆t

Solve for a :

a = (50.83 m/s - 20 m/s) / (120 s)

a ≈ 0.257 m/s²

Given parameters:

Mass on earth  = 50kg

Unknown:

Mass on planet Xenon = ?

Weight on planet Xenon = ?

Mass is the amount of matter contained in a particular substance.

Weight is the force on a body and it is derived from the product of mass and acceleration due to gravity.

         Weight  = mass x acceleration due to gravity

Planet Xenon has half the gravitational force of Earth.

 This translated gives [tex]\frac{9.8}{2}[/tex]   = 4.9m/s²

Now, mass is always the same every where if the amount of matter in a substance does not change.

In this problem, mass = 50kg on planet xenon.

Weight =  mass x acceleration due to gravity  = 50 x 4.9  = 245N

The weight on Xenon is 245N and the mass is 50kg

Answer:

meter, kilogram, second, ampere, Kelvin, candela, and mole.

Explanation:

these are all SI units.

Answer:

it dies

Explanation:

MWUAHHAHAHHA

Answer:

it is algae- shrimp- artic cod-ringed seals- polar bears

Explanation:

you had it right

Answer:

Energy storage plays an important role in this balancing act and helps to create a more flexible and reliable grid system. For example, when there is more supply than demand, such as during the night when low-cost power plants continue to operate, the excess electricity generation can be used to power storage devices.

Explanation:

I hope this helps you out and if your feeling generous plz mark brainliest it helps me a lot thank you:)

It important for scientists to find better ways to store solar and wind energy because solar and wind energy have variable outputs.

Lately, the world have begun to gradually gravitate away from non renewable energy sources such as fossil fuels and research efforts have been concentrated on renewable energy sources such as solar and wind energy.

However, the energy output from these sources are variable. Therefore, it is necessary to device ways to store energy from these sources in order to improve overall energy supply.

Learn more: https://brainly.com/question/17319210

Answer:

v = 190 m/s

Explanation:

Given that,

Initial velocity of a car, u = 10 m/s

Distance, d = 500 m

Time, t = 5 s

We need to find the final velocity of the car. Firstly we can find the acceleration of the car using second equation of motion as follows :

[tex]d=ut+\dfrac{1}{2}at^2\\\\500=10\times 5+\dfrac{a}{2}\times 5^2\\\\500=50+\dfrac{25a}{2}\\\\450=\dfrac{25a}{2}\\\\a=\dfrac{450\times 2}{25}\\\\a=36\ m/s^2[/tex]

let v is the final velocity. using First equation of motion to find a as follows :

v=u+at

v=10+36(5)

v=190 m/s

So, the final velocity of the car is 190 m/s.

Answer:

Objects float in outer space because there is no gravitational force. The farther you get from earth, the less gravity.

Explanation:

Answer:

they float do to gravity

Explanation:

here if you tossed a ball in the air it would come back down fast in space however it would only float up and stay do to gravity

Answer:

D) 12 sodium, 4 phosphorus. 16 oxygen

Explanation:

there is a four in front of the full formula, so you multiply all of the sub numbers by 4

Answer:

Its convergent

Explanation:

There areas where plates move toward each other and collide Also known as compressional pr destructive boundaries.

Answer:

W_net = mg + 2mgh/r

Explanation:

The forces applied in this motion of the bowling ball are both gravitational and centripetal forces.

Now, gravitational force is; F_g = mg

While centripetal force is; F_c = mv²/r

Since we want to express the net force in terms of the variables in the statement and we are not given "v", let's find an expression of v with the variables given.

Now, from Newton's equation of motion, at initial velocity of 0, v² = 2gh.

Thus;

F_c = 2mgh/r

Where;

m is ball mass

r is tube radius

h is fall height

Thus, the net force will be;

F_net = F_g + F_c

Now, Net force would be equal to the net weight that will be read on the scale.

Thus;

W_net = F_net = F_g + F_c

W_net = mg + 2mgh/r

At its lowest point, the net force of the bowling ball is equal to its net weight and this is given by [tex]F_{net} = mg + \frac{2mgh}{r}[/tex]

Given the following data:

To write an expression for the reading of the scale when the bowling ball is at its lowest point, in terms of the given variables:

In this scenario, there are two (2) forces acting on the bowling ball and these include:

Mathematically, centripetal force is given by this formula:

[tex]F_c = \frac{mv^2}{r}[/tex]     .....equation 1.

Mathematically, gravitational force is given by this formula:

[tex]F_g= mg[/tex]    ....equation 2.

Where:

Next, we would derive an expression for the velocity of the ball by applying the Law of Conservation of energy:

[tex]P.E = K.E\\\\mgh = \frac{1}{2} mv^2\\\\V^2=2gh[/tex] .....equation 3.

Substituting eqn. 3 into eqn. 2, we have:

[tex]F_c = \frac{m(2gh)}{r}\\\\F_c = \frac{2mgh}{r}[/tex]

At its lowest point, the net weight of the bowling ball is equal to its net force and this is given by this mathematical expression:

[tex]W_{net} = F_{net} = F_g + F_c\\\\F_{net} = mg + \frac{2mgh}{r}[/tex]

Read more on net force here: https://brainly.com/question/14361879

Answer: positively charged

Explanation: basically when a neutral atom gets some electrons it becomes negatively charged and when a neutral atom loses elections it's positively charged Ik science is weird lol.

I hope this was the answer you were looking for.

Answer:

I'm pretty sure it's false

Answer: D.  Heat transfer between the two things stops​.

Answer:

A

Explanation:

Refraction

On a drive from your home to town, you wish

to average 33.6 mph. The distance from your

home to town is 90 miles. However, at 45 miles

(half way), you find you have averaged only

25.2 mph.

What average speed must you maintain in

the remaining distance in order to have an

overall average speed of 33.6 mph?

Answer in units of mph

let the speed be x

total average = 33.6

Answer:

It is called the unit function because it is the identity element for Dirichlet convolution. It may be described as the "indicator function of 1" within the set of positive integers. It is also written as u(n) (not to be confused with μ(n), which generally denotes the Möbius function).