SOMEONE PLSSSS HELPPPP. When under equal tension, the frequency of a vibrating string in a piano varies inversely with the string length. If a string that is 410 millimeters in length vibrates at a frequency of 515 cycles a second, at about what frequency will a 705-millimeter string vibrate?

Answer:

There are 200 girls in that school

Step-by-step explanation:

The correct and complete question is as folly;

In a school 3/5 pupils are boys. One day 1/6 of the boys were absent when 250 boys were present. How many girls are in the school?

SOLUTION

Let the total number of students in the school be x students

Since 3/5 are boys , then the number of girls in the school would be 1-3/5 = 2/5

The number of boys are 3/5 * x = 3x/5

The number of girls are 2/5 * x = 2x/5

Now on a particular day, 1/6 of the boys were absent and 250 boys were present.

What this means is that the fraction of boys present is 1-1/6 = 5/6

Now, 5/6 of the total boys population were present.

Mathematically;

5/6 * 3x/5 = 250

3x/6 = 250

x/2 = 250

x = 2 * 250 = 500

So there are 590 students in the school.

The number of girls in the school is ;

2x/5 = 2/5 * 500 = 200 girls

The residual value is the distance between where the line is and the dot is.

At x = 2, the line crosses at y = 2, and the dot is at y = 1

The difference is: 2-1 = 1

BeUse the dot is below the line it becomes a negative value.

The answer would be -1

Answer: The probability that she will visit them in the exact order ABCD or DCBA =  [tex]\dfrac{1}{12}[/tex]

Step-by-step explanation:

Given: Jennifer wants to visit 4 different cities A,B,C and D on her vacation.

If she visits in an order , total such orders will be [tex]4![/tex] = 4 x 2 x 3 x 1 =24.

Since probability = [tex]\dfrac{\text{Favourable outcomes}}{\text{total outcomes}}[/tex]

In this case favorable outcomes ( ABCD ,  DCBA)=  2

Total outcomes = 24

Required probability = [tex]\dfrac{2}{24}=\dfrac{1}{12}[/tex]

Hence, the probability that she will visit them in the exact order ABCD or DCBA =  [tex]\dfrac{1}{12}[/tex]

Answer:

4107 cells

Step-by-step explanation:

From the question, we have the following values:

Day 1 : 113 cells

Number of cells increases by day by 82%

Hence,

Day 2

113 × 82% = 92.66cells

Hence, Total number of bacteria cells for Day 2 = 113 + 92.66 = 205.66cells

Day 3

205.66 × 82% = 168.6412 cells

Hence, Total number of bacteria cells for Day 3 = 168.6412 + 205.66 = 374.3012 cells

Day 4

374.3012 × 82% = 306.926984 cells

Hence, Total number of bacteria cells for Day 4 = 306.926984 + 374.3012 = 681.228184 cells

Day 5

681.228184 × 82% = 558.60711088 cells

Hence, Total number of bacteria cells for Day 5 = 558.60711088 + 681.228184 = 1239.8352949 cells

Day 6

1239.8352949 × 82% = 1016.6649418 cells

Hence, Total number of bacteria cells for Day 5 = 1016.6649418 + 1239.8352949 = 2256.5002367 cells

Day 7

2256.5002367 × 82% = 1850.3301941 cells

Hence, Total number of bacteria cells for Day 7 = 1850.3301941 + 2256.5002367 = 4106.8304308 cells

Approximately to nearest whole number, the total number of bacteria cells that would be present after 7 days = 4107 cells

Answer:

I think it doesnt have solution.

Hey there! I'm happy to help!

To find the volume of a cone, we multiply the base by the height and then divide by three.

First, we find the area of the base, which is a circle. To find a circle, you square the radius and then multiply by pi (or 3.14 in our case).

Radius is half of the diameter.

3/2=1.5

We square this.

1.5²=2.25

We multiply by 3.14

2.25×3.14=7.065

Now, we multiply this base area by the height.

7.065×7=49.455

We divide by 3.

49.455/3=16.485

Therefore, if we round this, our answer is 16.49 in³.

Now you can find the volume of a cone! Have a wonderful day! :D

Answer:

16.49

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

When you plug it in, another form could be y=-3x+2

Answer:

y=-3x+2

Step-by-step explanation:

y=-3x+7

parallel lines have the same slope but different y intercept which is b in the equation y=mx+b

since it passes through (2,-4) then x=2 and y=-4, m(slope)=-3

y=mx+b

-4=-3(2)+b

b=-4+6

b=2

y=-3x+2

Answer:

[tex] area = 10x^2 - 4x + 6 [/tex]

Step-by-step explanation:

Given that the rectangle has a height = 2, and width of [tex] 5x^2 - 2x + 3 [/tex]

Area of the whole rectangle can be calculated as:

[tex] area = 2(5x^2 - 2x + 3) [/tex]

Use the distributive property of multiplication by using 2 to multiply each term in the expression, [tex] (5x^2 - 2x + 3) [/tex]

[tex]area =2(5x^2) +2 (-2x) + 2(3)[/tex]

[tex] area = 10x^2 - 4x + 6 [/tex]

Answer:

138.37 gram

Step-by-step explanation:

Formula of density

density = mass/ volume

given

volume = 202 mL

density = 0.685g/mL

using these values in Formula of density

0.685g/mL = mass/ 202 mL

mass = 0.685g/mL * 202 mL = 138.37 gram

Thus, weight of liquid is  138.37 gram to the nearest hundredth.

Answer:

138.37 grams

Step-by-step explanation:

I'm taking the exam. Good luck on yours!

Answer:

The expression is equal to 3,120 when x = -5 and y = 25.

Step-by-step explanation:

In order to obtain the output of the expression when x = -5 and y = 25, we need to apply these numbers in its correct places as shown below. We need to pay close attention to [tex]|x|[/tex] which is the absolute value of "x", this means that if x is positive, then [tex]|x|[/tex] will also be positive, but if x is negative then the result will still be positive.

[tex]\frac{5|x| - y^3}{x}[/tex]

[tex]\frac{5*|-5| - (25)^3}{-5}\\\frac{5*5 - 15625}{-5}\\\frac{25 - 15625}{-5}\\\frac{-15600}{-5} = 3,120[/tex]

The expression is equal to 3,120 when x = -5 and y = 25.

Answer:

Bearing of R from S = S 45° E or 135°

The bearing of R from Q

= S 66.42° w or 246.42°

Step-by-step explanation:

Distance between R and S

RS²= RP²+PS²

RS²= 15²+15²

RS²=225+225

RS= √450

RS= 21.21

Angle at S

21.21= 15/sins

Sin s= 15/21.21

S= sin^-1 15/21.21.

S= 45°

90+45= 135°

Bearing of R from S = S 45° E or 135°

Distance between R and Q

RQ²= PQ²+PR²

RQ²= 35²+15²

RQ²=1225+225

RQ= √1450

RQ= 38.08

RQ= 15/sinQ

SinQ= 15/38.08

SinQ= 0.40

Q=23.58°

90-23.58 = 66.42°

66.42+180= 246.42°

The bearing of R from Q

= S 66.42° w or 246.42°

Answer:

[tex]4 \frac{1}{4} [/tex] hours

Step-by-step explanation:

Given,

Time spent in studies : [tex]1 \frac{3}{4} [/tex] hours

Time spent in playing cricket : [tex]2 \frac{1}{2} [/tex] hours

Now, let's find the time that he spent in all:

[tex]1 \frac{3}{4} + 2 \frac{1}{2} [/tex]

Add the whole number and fractional parts of the mixed numbers separately

[tex](1 + 2)( \frac{3}{4} + \frac{1}{2} )[/tex]

Add the numbers

[tex]3 +( \frac{3}{4} + \frac{1}{2} )[/tex]

Add the fractions

[tex]3 + ( \frac{3 + 1 \times 2}{4} )[/tex]

[tex]3 + ( \frac{3 + 2}{4} )[/tex]

[tex]3 + \frac{5}{4} [/tex]

Convert the improper fraction into mixed number

[tex] 3 + 1\frac{1}{4} [/tex]

Write the mixed number as a sum of the whole number and the fractional part

[tex]3 + 1 + \frac{1}{4} [/tex]

Add the numbers

[tex]4 + \frac{1}{4} [/tex]

Write the sum of whole number and the fraction as a mixed number

[tex]4 \frac{1}{4} [/tex] hours

Hope this helps..

Best regards!!

Answer:

4 1/4 hours.

Step-by-step explanation:

1 3/4 + 2 1/2

= 1 + 2 + 3/4 + 1/2

= 3 + 3/4 + 1/2   The LCM of 2 and 4 is 4 so 1/2 = 2/4. and so we have:

3 + 3/4 + 2/4

= 3 + 5/4

= 3 + 1 1/4

= 4 1/4 hours.

Answer:

3²

Step-by-step explanation:

We have to use BPEMDAS Order of Operations:

B - Brackets

P - Parenthesis

E - Exponents

M - Multiply

D - Divide

A - Addition

S - Subtraction

We use this order left to right. Since we have parenthesis, we look at that first. Inside, we have division and exponents. Since exponents come first, we have to evaluate 3² first.

Answer:

square the 3

Step-by-step explanation:

In the order of operations, you must do the exponent inside the parentheses first, so the first step is:

4(27 ÷ 3²) =

= 4(27 ÷ 9)

Answer: square the 3

Answer:

Perimeter = 20cm ; area = 59.5cm

Step-by-step explanation:

Given the following :

Perimeter of entire figure = 42cm

Diameter of circle (d) = 7cm

Find the perimeter of the circle :

The perimeter (p) of a circle equals :

2πr

Where r = radius of circle

r = diameter /2 = 7/2 = 3.5cm

Therefore,

P = 2 * (22/7) * 3.5

P = 22 cm

Looking at the figure, we only take the semicircle :

Therefore perimeter of each semicircle =

22cm / 2 = 11cm

Therefore, perimeter of the red shaded region =

(42 - 22)cm = 20cm

Area of Circle = πr^2

(22/7) * 3.5^2 = 38.5 cm

Area of each semicircle = 38.5/2 = 19.25cm

Total area of semicircle = (19.25 +19.25) = 38.50cm

To find sides of rectangle :

Perimeter of the rectangle :

width = diameter of circle = 7cm

2(l + w) = 42

2(l + 7) = 42

2l + 14 = 42

2l = 42 - 14

2l = 28

l = 28/2

length (l) = 14cm

Therefore, area of rectangle :

Length * width

14 * 7 = 98cm

Area of red portion:

Area of rectangle - (area of the 2 semicircles)

98cm - 38.50cm

= 59.50cm

Answer:

[tex]\dfrac{74}{20}=3.7 meters[/tex]

Step-by-step explanation:

Hello!

1) Since no other data has been given. Suppose Natasha is in the center and the beagle is to the right.

[tex]\dfrac{25}{4} \:meters[/tex]  

2) The labrador is [tex]\dfrac{51}{20}\: to\: the\: left.[/tex]

[tex]\dfrac{25}{4} -\dfrac{51}{20} =\dfrac{(5*25)-51}{20} \\\dfrac{(125-51}{20} =\dfrac{74}{20}[/tex]

Answer:

The answer is B :D hope this helps

Step-by-step explanation:

Answer:

T = - 3.2e + 80

Step-by-step explanation:

Given the following :

e = elevation in thousands of feets

T = temperature (°F)

e1 = 5 ; e2 = 10 (in thousands of feet)

T1 = 64° ; T2 = 48°

y = mx + c ; T = me + c

y = ; m = slope, c = intercept

64 = m5 + c - - - - (1)

48 = m10 + c - - - - (2)

From (1)

c = 64 - m5

Substitute c = 64 - m5 into (2)

48 = m10 + c - - - - (2)

48 = m10 + 64 - m5

48 - 64 = 10m - 5m

-16 = 5m

m = - 16 / 5

m = - 3.2

Substitute the value of m into c = 64 - m5

c = 64 - 5(-3.2)

c = 64 - (-16)

c = 64 + 16

c = 80

Inserting our c and m values into T = me + c

T = - 3.2e + 80

Where e is in thousands of feet

T is in °F

Answer:

y = 2x + 4

Step-by-step explanation:

y = mx + b

b = y-intercept = 4

m = slope = rise/run = 4/2 = 2

y = 2x + 4

Answer:

108

Step-by-step explanation:

To find x, you need the geometric mean. First, find the second part of 225 by doing 225 - 144 = 81. Now, to find geometric mean, do 81 x 144 = 11,664; [tex]\sqrt{11,664} = 108[/tex].

The missing length in the right triangle as given in the task content is; 108.

It follows from the complete question that the triangle given is a right triangle and the missing length can be calculated as;

First, find the second part of 225 by

225 - 144 = 81.

Now, to find geometric mean,

81 × 144 = x²

11,664 = x²

x = 108

Thus, The missing length in the right triangle as given in the task content is; 108.

Read more on missing length;

https://brainly.com/question/28040679

#SPJ2

Answer:

y = 110°

Step-by-step explanation:

The inscribed angle CHF is half the measure of its intercepted arc CDF

The 3 arcs in the circle = 360°, thus

arc CDF = 360° - 160° - 60° = 140°, so

∠ CHF = 0.5 × 140° = 70°

∠ CHF and ∠ y are adjacent angles and supplementary, thus

y = 180° - 70° = 110°

Answer:

2x² + [tex]\frac{3}{2}[/tex] x - 5

Step-by-step explanation:

(f + g)(x) = f(x) + g(x), thus

f(x) + g(x)

= [tex]\frac{x}{2}[/tex] - 2 + 2x² + x - 3 ← collect like terms

= 2x² + [tex]\frac{3}{2}[/tex] x - 5

Answer:

log Subscript 2 Baseline 9 + 3 log Subscript 2 Baseline x.

Log₂ 9 + 3Log₂ x

Step-by-step explanation:

Log subscript 2 baseline 9 x cubed can be written as:

Log₂ 9x³

Now, let us simply Log₂ 9x³.

This is illustrated below:

Log₂ 9x³

Recall: LogMN = Log M + Log N

Log₂ 9x³ = Log₂ 9 + Log₂ x³

Recall: Log Mⁿ = nLog M

Log₂ 9x³ = Log₂ 9 + 3Log₂ x

Therefore, the answer is log Subscript 2 Baseline 9 + 3 log Subscript 2 Baseline x.

The equivalent expression of [tex]\log_2(9x^3)[/tex] is [tex]\log_2(9) + 3\log_2(x)[/tex]

The logarithmic expression is given as:

[tex]\log_2(9x^3)[/tex]

Apply the quotient law of logarithm

[tex]\log_2(9x^3) = \log_2(9) + \log_2(x^3)[/tex]

Apply the power rule of logarithm

[tex]\log_2(9x^3) = \log_2(9) + 3\log_2(x)[/tex]

Hence, the equivalent expression of [tex]\log_2(9x^3)[/tex] is [tex]\log_2(9) + 3\log_2(x)[/tex]

Read more about equivalent expressions at:

https://brainly.com/question/2972832

Answer:

A).300763=+ 67

b) 704969= +87

c)( - 226981)= -61

Step-by-step explanation:

The values of the cube root iyf the given numbers above will be looked up in a calculator and the estimated value will be returned back.

Going through the numbers

A).for 300763

The value of the cube root = +67

B). For 704969

The value of the cube root = +89

C). For ( - 226981)

The value of the cube root= -61

Answer:

The probability that a defective ball bearing was manufactured on a Friday is 0.375.

Step-by-step explanation:

The conditional probability of an events X given that another event A has already occurred is:

[tex]P(X|A)=\frac{P(A|X)P(X)}{P(A)}[/tex]

The information provided is as follows:

P (D|M) = 0.08

P (D|Tu) = 0.04

P (D|W) = 0.04

P (D|Th) = 0.04

P (D|F) = 0.12

It is provided that the Company manufactures an equal amount of ball bearings, 20% on each weekday, i.e.

P (M) = P (Tu) = P (W) = P (Th) = P (F) = 0.20

Compute the probability of manufacturing a defective ball bearing on any given day as follows:

[tex]P(D)=P(D|M)P(M)+P(D|Tu)P(Tu)+P(D|W)P(W)\\+P(D|Th)P(Th)+P(D|F)P(F)[/tex]

      [tex]=(0.08\times 0.20)+(0.04\times 0.20)+(0.04\times 0.20)+(0.04\times 0.20)+(0.12\times 0.20)\\\\=0.064[/tex]

Compute the probability that a defective ball bearing was manufactured on a Friday as follows:

[tex]P(F|D)=\frac{(D|F)P(F)}{P(D)}[/tex]

             [tex]=\frac{0.12\times 0.20}{0.064}\\\\=0.375[/tex]

Thus, the probability that a defective ball bearing was manufactured on a Friday is 0.375.

Answer:

Step-by-step explanation:

In this problem we are going find the natural logarithmic of the numbers involved and solve for x

[tex]ln65-Ln x= 39\\[/tex]

from tables

[tex]4.17-ln x= 39\4.17-39= lnx\\-34.83=lnx\\[/tex]

taking the exponents of both sides we have

[tex]e^-^3^4^.^8^3= x\\x= 7.47[/tex]

Answer:

You get 12$ per B and 15$ per A.  Thus, the answer is A) $282

Step-by-step explanation:

4A+4B=108

Divide by 4

A+B=27

Subtract B

A = 27 - B

3A+5B=105

Substitution

3(27-B)+5B = 105

Distribute

81-3B+5B=105

Combine like terms

81+2B=105

Subtract 81

2B=24

Divide by 2

B = 12

A = 15

14(15)+6(12)=x

210+72=x

282=x

Hope it helps <3

[tex](2+3)^{-1}\equiv5^{-1}\pmod7[/tex] is the number L such that

[tex]5L\equiv1\pmod7[/tex]

Consider the first 7 multiples of 5:

5, 10, 15, 20, 25, 30, 35

Taken mod 7, these are equivalent to

5, 3, 1, 6, 4, 2, 0

This tells us that 3 is the inverse of 5 mod 7, so L = 3.

Similarly, compute the inverses modulo 7 of 2 and 3:

[tex]2a\equiv1\pmod7\implies a\equiv4\pmod7[/tex]

since 2*4 = 8, whose residue is 1 mod 7;

[tex]3b\equiv1\pmod7\implies b\equiv5\pmod7[/tex]

which we got for free by finding the inverse of 5 earlier. So

[tex]2^{-1}+3^{-1}\equiv4+5\equiv9\equiv2\pmod7[/tex]

and so R = 2.

Then L - R = 1.

Answer:

Slope = 3

Step-by-step explanation:

Slope is rise (vertical distance) over run (horizontal distance).

Our rise is equal to 3

Our run is equal to 1

So, slope = 3/1 = 3

Answer:

Answer c): write the function in standard form

Step-by-step explanation:

To start with, it is important to write the polynomial in standard form, so as to have the two terms with the dependence in x together:

[tex]6x^2-42\,x+5[/tex]

then you extract 6 as a common factor of just the terms with the variable x:

[tex]6(x^2-7x)+5[/tex]

Then proceed to complete the square in the expression inside the parenthesis:

[tex]6(x^2-7x+\frac{49}{4} -\frac{49}{4})+5[/tex]

[tex]6\,((x-\frac{7}{2} )^2-\frac{49}{4} )+5\\6\,(x-\frac{7}{2} )^2-\frac{147}{2}+5\\6\,(x-\frac{7}{2} )^2-\frac{137}{2}[/tex]

Then, the function can be finally be written as:

[tex]f(x)=6\,(x-\frac{7}{2} )^2-\frac{137}{2}[/tex]

in vertex form

Answer:

C.) Write the function in standard form

Step-by-step explanation:

[tex](3-9i)(6-i)=18-3i-54i+9i^2=18-57i-9=\boxed{9-57i}[/tex].

Hope this helps.