Claim 1: Yes, there probably will be a lunar eclipse of the moon of Kepler-47c during a year.
Claim 2: No, there probably won't be a lunar eclipse of the moon of Kepler-47c during a year.
What are the evidence to support this claim?Kepler-47c is a moon orbiting Kepler-47 AB, a binary star system. This implies that the moon's light varies on a regular basis as it circles the two stars. These changes in light might result in a lunar eclipse.
Lunar eclipses occur when the moon passes through the Earth's shadow. While Kepler-47c circles two stars, it is still subject to Earth's gravitational pull and may pass into its shadow.
Lunar eclipses occur on a regular basis, with two to four eclipses occurring on average per year. Given the frequency of lunar eclipses, Kepler-47c is likely to see at least one lunar eclipse every year.
Evidence to support this claim 2:
Lunar eclipses occur when the moon passes through the Earth's shadow. While Kepler-47c is in the Earth's gravitational field, it is not on the same orbital plane as the Earth.
While Kepler-47c circles two stars, its orbit is not known to be stable. Variations in Kepler-47c's orbit may reduce the likelihood of a lunar eclipse.
While lunar eclipses are common, they are not uniformly distributed throughout the year. The locations and motions of the Earth, moon, and sun govern the timing and frequency of lunar eclipses.
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How many grams of KBr are dissolved in 72.7 mL of a 0.998 M solution?
You dissolve 123g KBr into 689g of water. Calculate the mass percent.
You dissolve 3 moles KBr into 46 moles of water. Calculate the mass percent
8.63 grams of KBr are dissolved in 72.7 mL of a 0.998 M solution.
To answer first we need to calculate the molar mass of this molecule (KBr):
For this we go to the periodic table and check the molar weight of potassium and bromine:
K: 39.098 g/mol
Br: 79.904 g/mol
So the molar mass of KBr is
= 39.098 g/mol + 79.904 g/mol
=119 g/mol
Now, we know that the solution is 0.998 M, this means that in 1000 ml there are 0.998 moles of KBr. So we calculate the number of moles in 72.7ml:
number of moles of KBr
= 72.7 ml × 0.998 molL⁻¹/ 1000 mlL⁻¹
=0.0725 moles
Now we use the molar mass to calculate the mass in grams in the sample:
mass of KBr
= 0.0725 moles ₓ 119 g/mol
=8.6275 g
≈8.63 g
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A teacher has given a lab student a white chemical sample and asks her to confirm that it contains 33.4 g sodium hydroxide (NaOH). If the teacher provides the amount in formula unitswhich value is correct?
A. 40.0 g
B. 46.78
C. 5.03 x 10^23
D. 7.03 x 10^24
The amount in, formula unit. of 33.4 g sodium hydroxide is 5.03 x [tex]10^{23[/tex] . Option C.
Formula unitsIn order to calculate the mass of NaOH from formula units, first, we need to know the molar mass of NaOH, which is 40 g/mol1.
The formula units are related to moles by Avogadro’s number which is 6.022 x 10^23 formula units per mole.
Therefore, we can calculate the mass of NaOH as follows:
33.4 g NaOH = (33.4 g NaOH / 40) x (6.022 x 10^23) = 5.03 x [tex]10^{23[/tex] formula units.
In other words, there are 5.03 x [tex]10^{23[/tex] formula units in 33.4 g sodium hydroxide.
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HELP
Write the products formed in the following acid-base reaction.
NaOH + HCl →
Then, describe the reaction using the terms strong acid, strong base, weak acid, weak base, salt, conjugate acid, conjugate base, and neutralization, as appropriate.
Answer in complete sentences.
The products formed in the acid-base reaction between NaOH and HCl are NaCl (sodium chloride) and H₂O (water).
NaOH + HCl → NaCl + H₂O
In this reaction, NaOH is a strong base, and HCl is a strong acid. A strong base is one that completely dissociates in water to form hydroxide ions (OH⁻) while a strong acid is one that completely dissociates in water to form hydrogen ions (H⁺).
NaOH + H₂O → Na⁺ + OH⁻
HCl + H₂O → H⁺ + Cl⁻
When NaOH is added to HCl, the hydroxide ions (OH⁻) from the NaOH react with the hydrogen ions (H⁺) from the HCl to form water (H2O). The remaining ions, Na⁺ and Cl⁻, combine to form sodium chloride (NaCl), which is a salt.
Na⁺ + Cl⁻ → NaCl
The reactants in this reaction are a strong base (NaOH) and a strong acid (HCl), and the products are a salt (NaCl) and water (H₂O). This reaction is an example of neutralization, which is a reaction between an acid and a base that produces a salt and water. The Na⁺ ion is the conjugate acid of the strong base NaOH, while the Cl⁻ ion is the conjugate base of the strong acid HCl
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How many mL of 3.00 M HCI are needed to completely react with 4.85 g CaCO3? The
reaction is: 2HCl(aq) + CaCO3(s)-> CaCl2(aq) + CO2(g) + H20(1)
The amount of volume that is needed to completely react with 4.85 grams of calcium carbonate is 32 mL.
How to calculate volume?The amount of volume needed to complete a chemical reaction can be calculated using the following formula;
molarity = no of moles ÷ volume
According to this question, hydrochloric acid reacts with calcium carbonate to produce calcium chloride, water and carbondioxide.
2 moles of HCl reacts with 1 mole of calcium carbonate. 4.85g of calcium carbonate is equivalent to 0.0485 moles.
0.0485 moles of calcium carbonate will react with 0.097 moles of HCl.
volume = 0.097 mol ÷ 3M = 32 mL
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How many moles of KBr are dissolved in 60.2 mL of a 3.50 M solution?
There are 0.2107 moles of KBr are dissolved in 60.2 mL of a 3.50 M solution.
The molarity of a substance is defined as the number of moles of solute present in 1 litre of a solution.
According to the given data, the molarity of the solution tells us that there are 3.50 moles of KBr in 1000mL of solution. But we only have 60.2mL of solution, so with a mathematical rule of three we can calculate the amount of moles in 60.2mL:
1000 ml - 3.50 moles
60.2 ml -x = 60.2 ml× 3.50 moles/1000 ml
x= 60.2 ml -0.2107 moles
So, there are 0.2107 moles of KBr.
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What is the vapor pressure of SiCl4
in mmHg
at 33.0 ∘C
? The vapor pressure of SiCl4
is 100 mmHg
at 5.4 ∘C
, and ΔHvap
= 30.2 kJ/mol
.
The vapor pressure of the SiCl₄ in the mmHg at the 33.0 °C is the 312 mmHg.
The Clausius - Clapeyron equation is as :
ln ( P₂ / P₁ ) = ΔHvap / R ( 1 / T₁ - 1 / T₂ )
P₂ = P₁eˣ
Where,
The temperature, T₁ = 5.4 °C = 278.55 K
The temperature, T₂ = 33.0 °C= 306 K
The pressure, P₁ = 100 mmHg
ΔHvap is the heat of the vaporization = 30.2 kJ /mol = 30200 J/mol
The gas constant, R = 8.314 J / mol K
x = ΔHvap / R ( 1 / T₁ - 1 / T₂ )
x = 30200 / 8.314 ( 1/ 278.55 - 1/ 306 )
x = 1.05
P₂ = 100 [tex]e^{1.05}[/tex]
P₂ = 312 mmHg
The vapor pressure of the SiCl₄ is 312 mmHg.
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During the titration, a student pulls out the pH electrode from the titration beaker several times (with about 0.25 mL of solution on it each time) and rinses it off with DI water into a waste container. Will this affect the measured equivalent mass? If so, will the equivalent mass come out higher or lower?
The student pulling out the pH electrode from the titration beaker and rinsing it off with DI water into a waste container several times during the titration will not significantly affect the measured equivalent mass.
This is because the equivalent mass of a substance is determined by the stoichiometry of the reaction, which is not influenced by the pH electrode or the rinsing process. However, it is important to note that if the student is rinsing the electrode with a significant amount of water, it could dilute the solution and affect the accuracy of the titration. Therefore, it is recommended to use a minimal amount of water during the rinsing process to minimize any potential dilution effect.
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A population of comb jellies has members that show two distinct traits. One part of the population has male comb jellies that use a complex bioluminescence pattern to attract females. Another part of the population has male and female comb jellies that produce light in quick flashes. A new animal that preys on comb jellies enters the area.
Using Table 1, which statement describes the most probable change in the comb jelly population over time due to the introduction of the new predator?
Only comb jellies whose genes mutate to no longer glow will survive and pass on this trait. This describes the most probable change in the comb jelly population over time. Therefore, the correct option is option A.
The term "population" is frequently used to describe the total number of people living in a particular location. To estimate the number of the resident population inside a certain territory, governments conduct censuses. The phrase has particular use in the domains of ecology and genetics and is also used to refer to plants, animals, and microbes.
A population is frequently referred to as a group of organisms in genetics where any two individuals can breed with each other. A breeding group known as a gamodeme is one that may routinely exchange gametes to create children who are normally viable. Only comb jellies whose genes mutate to no longer glow will survive and pass on this trait. This describes the most probable change in the comb jelly population over time.
Therefore, the correct option is option A.
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Need help with this please it’s due today
Write agree or disagree next to each statement. Explain why you agree or why you disagree
1. Metal atoms don’t have full vallance electron shells, so they try to gain electrons to fill their outer shell.
2. When atoms join together,the bond is either covalent or ionic
3. Oxygen atoms bond together,but this is not because of an atomic force.
4. Covalent bonds happen when an electron moves back and forth between two atoms
5. Ionic bonds occur when an electron is transferred from one atom to another
6. When hydrogen joins with oxygen,a hydrogen bond has been formed.
Answer:
The statements 1, 2, 5 are correct, while the statements 3, 4, 6 are incorrect. It's important to have a clear understanding of the different types of chemical bonds and how they are formed in order to understand the properties and behavior of molecules and compounds.
Explanation:
1. Agree: Metal atoms have partially filled valence shells, which makes them more likely to lose electrons than to gain them. This loss of electrons creates a positive ion with a full valence shell, which is more stable than the original atom.
2. Agree: Chemical bonds are either covalent or ionic. Covalent bonds involve the sharing of electrons between atoms, while ionic bonds involve the transfer of electrons from one atom to another.
3. Disagree: Oxygen atoms bond together due to a strong atomic force called a covalent bond. This occurs when the two oxygen atoms share electrons to form a stable molecule of O2.
4. Disagree: Covalent bonds occur when electrons are shared between atoms, but they do not "move back and forth" between the atoms. Rather, the electrons are shared between the atoms to create a stable molecule.
5. Agree: Ionic bonds occur when one atom transfers an electron to another atom. The transfer of the electron creates two ions with opposite charges, which are then attracted to each other.
6. Disagree: A hydrogen bond is a weak electrostatic attraction between a hydrogen atom and an electronegative atom such as oxygen or nitrogen. When hydrogen joins with oxygen, a covalent bond is formed, not a hydrogen bond.
Metal atoms try to gain electrons; Covalent or ionic bonds form when atoms join; Oxygen atoms bond via atomic force.
Explanation:1. Agree - Metal atoms do not have full valence electron shells, so they tend to gain electrons to achieve stability. This process is known as electron transfer or ionic bonding.
2. Agree - when atoms join together, the resulting bond is either covalent or ionic. Covalent bonds involve the sharing of electrons, while ionic bonds involve the transfer of electrons from one atom to another.
3. Disagree - Oxygen atoms bond together through a force known as the atomic force. This force arises due to the different electronegativities of the oxygen atoms, leading to the formation of a covalent bond.
4. Disagree - Covalent bonds occur when electrons are shared between atoms, rather than moving back and forth between them.
5. Agree - Ionic bonds occur when one atom transfers an electron to another atom.
6. Disagree - When hydrogen joins with oxygen, a covalent bond is formed, not a hydrogen bond. Hydrogen bonds occur when a hydrogen atom is attracted to an electronegative atom, such as oxygen, in a different molecule.
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If 5 moles of Na2SO4 react, how many moles of NaNO3 can be produced
The concept stoichiometry is used here to determine the moles of NaNO₃ produced. Chemical stoichiometry refers to the quantitative study of the reactants and products involved in a chemical reaction. Here the moles of NaNO₃ is
Stoichiometry is an important concept in chemistry which helps us to use the balanced chemical equation to find out the amounts of reactants and products. Here we make use of ratios in the balanced equation.
The balanced equation is:
Co(NO₃)₂ + Na₂SO₄ → 2 NaNO₃ + CoSO₄
1 mole of Na₂SO₄ gives 2 moles of NaNO₃.
So 5 moles of Na₂SO₄ gives: 2 NaNO₃ × 5 mole Na₂SO₄ / 1 mole Na₂SO₄ = 10 mole NaNO₃
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If you have an 8.53 mg sample of phosphorus oxychloride and it contains 1.72 mg of phosphorus, what is the percent composition of the phosphorus in the compound?
If you have an 8.53 mg sample of phosphorus oxychloride and it contains 1.72 mg of phosphorus, 20.6% is the percent composition of the phosphorus in the compound.
The ratio of each element's amount to the sum of all the individual components present in the compound, multiplied by 100, is what determines any compound's percentage composition. Here, we quantify the amount of the constituents in the solution in terms of grammes.
Any compound's percent composition expresses its makeup in terms of all the components that are present. The chemical analysis reveals the relevance of this composition calculation.
percent composition = (1.72/8.53 )× 100
= 20.6%
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Neutralization is a type of chemical reaction in which an acid and a base react with each other to form water and a salt.
Calculate the % yield of a reaction that combined 28.0 grams of sodium hydroxide with 125.0 mL of 3.10 M solution of sulfuric acid hat produced 24.5 g of Na2SO4 in the laboratory.
Balanced equation:
2 NaOH + H₂SO4 → Na₂SO4 + 2 H₂O
The percent yield of the reaction is 45.44%
Percentage yield is basically,
[tex]\rm Percent\ yield\ = \frac{actual\ yield}{theoretical\ yield} \times 100[/tex]
2 NaOH + H₂SO₄ → Na₂SO₄ + 2 H₂O
To calculate the theoretical yield, consider the stoichiometry of the reaction.
2 moles of NaOH reacts with 1 mole of H₂SO₄ to give 1 mole of Na₂SO₄ and 2 moles of H₂O. The mole ratio of H₂SO₄ and Na₂SO₄ is 1:1
For this mole ratio to be useful, convert the given concentration of H₂SO₄ into moles.
[tex]\rm Molarity\ =\ \frac{No.\ of\ moles}{Volume\ of\ solution (L)}[/tex]
[tex]\rm 3.10\ =\ \frac{No.\ of\ moles}{0.125}[/tex]
[tex]\rm No.\ of\ moles\ =\ 3.10 \times 0.125\[/tex]
[tex]=\ 0.38[/tex]
Since, mole ratio of H₂SO₄ and Na₂SO₄ is 1:1
Amount of Na₂SO₄ formed would be also 0.38 mol
Convert this amount in moles to amount in grams
[tex]\rm No.\ of\ moles\ =\ \frac{Mass\ formed\ }{Molecular\ mass}[/tex]
[tex]\rm Mass\ formed\ =\ No.\ of\ moles\times molecular\ mass[/tex]
[tex]\rm =\ 0.38\times 142.04[/tex]
[tex]\rm =\ 53.97\ grams[/tex]
Theorical yield of Na₂SO₄ is 53.97 grams
Therefore, [tex]\rm Percent\ yield\ = \frac{actual\ yield}{theoretical\ yield} \times 100[/tex]
[tex]\rm =\ \frac{24.5}{53.97}\times 100[/tex]
= 45.44%
The percent yield of the reaction is 45.44%
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3 Ca + 2 P→ Ca3P₂
Identify the limiting reactant (LR), excess reactant (ER), and theoretical yield (TY), in moles, of Ca³P₂
when 17.0 grams Ca reacts with 18.0 grams P.
To identify the limiting reactant, excess reactant, and theoretical yield, we first need to determine the amount of each reactant in moles.
Using the molar masses of Ca and P:
Number of moles of Ca = 17.0 g / 40.08 g/mol = 0.424 mol
Number of moles of P = 18.0 g / 30.97 g/mol = 0.581 mol
Next, we need to determine the stoichiometric ratio of the reactants. From the balanced chemical equation, we see that the ratio of Ca to P is 3:2.
3 Ca + 2 P → Ca3P2
To use the stoichiometric ratio to determine the limiting reactant, we need to compare the actual ratio of the reactants to the stoichiometric ratio.
Actual ratio of Ca to P = (0.424 mol Ca) / (0.581 mol P) ≈ 0.73
Stoichiometric ratio of Ca to P = 3/2 = 1.5
Since the actual ratio is greater than the stoichiometric ratio, Ca is the excess reactant and P is the limiting reactant.
To find the theoretical yield of Ca3P2, we need to use the stoichiometric ratio to determine how many moles of Ca3P2 can be produced from the limiting reactant (P).
From the balanced chemical equation, we see that 2 moles of P react with 3 moles of Ca to produce 1 mole of Ca3P2.
So, the number of moles of Ca3P2 that can be produced from 0.581 mol of P is:
(0.581 mol P) × (1 mol Ca3P2 / 2 mol P) = 0.2905 mol Ca3P2
Therefore, the theoretical yield of Ca3P2 is 0.2905 mol.
Find the ions in the periodic table that have an electron configuration of nd8 (n = 3, 4, 5...). Check all that apply. Find the ions in the periodic table that have an electron configuration of (n = 3, 4, 5...).Check all that apply. Ag3+ Gd3+ Cr6+ Ni2+ P3+ Pt2+
The correct ions that have the quoted electron configuration would be [tex]Ag^{3+[/tex], [tex]Gd^{3+[/tex], [tex]Cr^{6+[/tex], [tex]Ni^{2+[/tex], and [tex]Pt^{2+[/tex].
Ions and electronic configurationsThe electron configuration (n = 3, 4, 5, ...) corresponds to the elements in the d-block and f-block of the periodic table. Therefore, the ions with this electron configuration are:
Ag3+ (silver ion): [Kr] 4d^9Gd3+ (gadolinium ion): [Xe] 4f^7Cr6+ (chromium VI ion): [Ar] 3d^0Ni2+ (nickel ion): [Ar] 3d^8Pt2+ (platinum ion): [Xe] 4f^14 5d^8P3+ (phosphorus ion) does not have an electron configuration of (n = 3, 4, 5, ...) as it is a p-block element with the electron configuration [Ne] 3s^2 3p^3.
Therefore, the correct ions that have this electron configuration are [tex]Ag^{3+[/tex], [tex]Gd^{3+[/tex], [tex]Cr^{6+[/tex], [tex]Ni^{2+[/tex], and [tex]Pt^{2+[/tex].
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What is the best conclusion that Tara should make about the commercial?
The best inference Tara can draw about the commercial is the fact that it is making pseudoscientific claims based on opinions rather than scientific evidence, according to the message at the bottom of the screen.
The claims claimed in the commercial are not supported by scientific data and may be exaggerated or inaccurate because the pill has not been examined by physicians and has not been put through rigorous testing. Therefore, before making any judgements regarding the use of the product, it is crucial to exercise caution and skepticism towards the assertions made in such advertising and to look for trustworthy sources of information.
Therefore, the correct option is D.
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Your question is incomplete, most probably the complete question is:
Tara sees a commercial for a brand of pills that promise to boost energy and help people perform better in work and school. As people in the commercial talk about how much better they feel when taking the pill, Tara notices a message on the bottom of the screen that reads, "This pill is not approved by doctors and has not been tested in controlled experiments." What is the best conclusion that Tara should make about the commercial?
It is making scientific claims based on subjective observations. It is making scientific claims based on opinions instead of pseudoscientific facts. It is making pseudoscientific claims based on objective observations. It is making pseudoscientific claims based on opinions instead of scientific facts.Rank the following elements by increasing Ionization energy: Cs, Sn, W, Xe
(1 being small, 4 being large)
pls help me with homework!!!
The ranking of the elements by increasing ionization energy is; Cs < Sn < W < Xe.
Xenon (Xe) has the highest ionization energy among the given elements. It is a noble gas in Group 18 of the periodic table and has a full complement of valence electrons, making it very stable and difficult to remove an electron.
Tungsten (W) has higher ionization energy compared to tin. It is a transition metal in Group 6 of the periodic table and has even more valence electrons, which are held more tightly by the increased effective nuclear charge, resulting in higher ionization energy.
Tin (Sn) has higher ionization energy compared to cesium. It is a metal in Group 14 of the periodic table and has more valence electrons, which are closer to the nucleus, requiring more energy to remove.
Cesium (Cs) has the lowest ionization energy among the given elements. It is in the alkali metal group (Group 1) of the periodic table and has only one valence electron, which is relatively far from the nucleus, making it easier to remove.
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Suppose the galvanic cell sketched below is powered by the following reaction: Pb(s)+Pd(NO3) (aq) - Pb(NO3) (aq)+Pd(s) E1 E2 S1 S2 Write a balanced equation for the half-reaction that happens at the cathode of this cell. 0-0 0 09 Write a balanced equation for the half-reaction 0 that happens at the anode of this cell. 0,0,... e Of what substance is E1 made? X ? Of what substance is E2 made? What are the chemical species in solution S1? 0 What are the chemical species in solution $2?
The substance E₁ is made of lead (Pb), and electrode E₂ is made of palladium (Pd) and the species in solution S₁ is Pb(NO₃)₂(aq), while the species in solution S₂ is Pd(NO₃)₂(aq).
The galvanic cell given in the question can be represented as;
Pb(s) | Pb(NO₃)₂(aq) || Pd(NO₃)₂(aq) | Pd(s)
where '|' represents a phase boundary, and '||' represents a salt bridge or porous disk separating the two half-cells.
The anode is the electrode where oxidation occurs, while the cathode is the electrode where reduction occurs.
To write the balanced equation for the half-reaction that occurs at the cathode, we need to identify the reduction half-reaction. Looking at the cell notation, we can see that Pd(NO₃)₂(aq) is being reduced to Pd(s), so the reduction half-reaction can be written as;
Pd²⁺(aq) + 2 e⁻ → Pd(s)
To write the balanced equation for the half-reaction that occurs at the anode, we need to identify the oxidation half-reaction. The anode is where the Pb(s) is oxidized to Pb²⁺(aq). The balanced oxidation half-reaction is;
Pb(s) → Pb²⁺(aq) + 2 e⁻
The species E₁ and E₂ refer to the electrodes at the anode and cathode, respectively. The electrode E₁ is made of lead (Pb), and electrode E₂ is made of palladium (Pd).
Therefore, the species in solution S₁ is Pb(NO₃)₂(aq), while the species in solution S₂ is Pd(NO₃)₂(aq).
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Part E Why does the car stop? Where did the energy go?
When the moving car brakes to the stop the kinetic energy of car will be converted to the heat energy.
The mechanical brake will be applies to the friction force and it convert the kinetic energy of the car into the thermal energy that which then dissipates on atmosphere. The process of the braking will follow the principle of the conservation of the energy.
The conservation of the energy is the principle, that is expressed in its the most general form, and it is the first law of the thermodynamics. The first law of thermodynamics explains that "the energy of the universe remains the same."
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This question is incomplete, the complete question is :
A car in motion has kinetic energy. A moving car is suddenly stopped. Why does the car stop? Where did the energy go?
you made 95.41 gram of carbon monoxide, how many moles of carbon did you start with?
Answer:
The balanced equation for the formation of carbon monoxide from carbon is:
C(s) + CO2(g) -> 2CO(g)
The molar mass of CO is 28 g/mol.
First, we need to calculate the number of moles of CO produced:
moles CO = mass of CO / molar mass of CO
moles CO = 95.41 g / 28 g/mol
moles CO = 3.412 mol
According to the balanced equation, 1 mole of carbon creates 2 moles of CO. As a result, the amount of carbon moles is:
moles C = moles CO / 2
moles C = 3.412 mol / 2
moles C = 1.706 mol
So, the initial amount of carbon was 1.706 moles.
please provide explanation!! thank you in advance!!
The correct rate law of the reaction from the experimental data is k[NO]^2 [O2]. Option D
What is the rate of reaction?The rate of reaction is usually expressed in terms of the amount of reactant consumed or product formed per unit time, and is typically measured in units of moles per liter per second (mol/L/s) or similar units.
We have that;
For NO;
3.4 * 10^-5/8.4 * 10^-6 = 2 * 10^-4/ 2 * 10^-4
4 = 2^n
n = 2
For O2;
8.4 * 10^-6/2.8 * 10^-6 = 3 * 10^-4/ 1 * 10^-4
3 = 3^n
n = 1
Thus the rate law of the reaction is;
Rate = k[NO]^2 [O2]
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Drag each phrase to show weather it causes water pollution or is an effect of water pollution. (2 points)
Choices:
Algal blooms
Overgrazing
Use of chemical fertilizers to enhance production
High concentration of nitrogen in water
Algal blooms and high concentrations of nitrogen in water are effects of water pollution. Overgrazing and the use of chemical fertilizers cause water pollution.
Water pollutionAlgal blooms are an effect of water pollution. They occur when there is an excessive amount of nutrients, particularly nitrogen and phosphorus, in the water due to pollution. The overgrowth of algae depletes the oxygen levels in the water, which can harm fish and other aquatic animals.
Overgrazing can cause water pollution by increasing the sedimentation rate of waterways. This sedimentation can carry nutrients, bacteria, and other pollutants into the water, which can degrade water quality and cause harm to aquatic life.
The use of chemical fertilizers to enhance production is a cause of water pollution. When fertilizer is overused, it can leach into waterways and cause nutrient pollution, which can lead to algal blooms and other forms of water pollution.
High concentrations of nitrogen in water are often an effect of water pollution. This can be caused by the overuse of fertilizers or the discharge of untreated sewage into waterways. High nitrogen levels can cause algal blooms, which can lead to oxygen depletion and harm aquatic life.
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Answer:
Cause:
: : use of chemical fertilizers to enhance production
: : overgrazing
Effect:
: : high concentration of nitrogen in water
: : algal blooms
Hope this helps ;)
A solution containing 0.026 moles of H2O2 at 25.0 °C is placed in a coffee cup calorimeter and
allowed to decompose completely according to the thermochemical equation shown below. The final temperature of the solution is 44.9 °C. Calculate the enthalpy of the reaction shown, in kJ/mol. The mass of the solution is 30.0 g and the specific heat capacity of the solution
is 4.18 J/g°C.
CHEMICAL Formula is in the photo
The enthalpy (in kJ/mol) of the reaction, given that 0.026 moles of H₂O₂ at 25.0 °C is placed in a coffee cup calorimeter is 95.98 KJ/mol
How do i determine the enthalpy of the reaction?First, we shall determine the heat energy of the reaction. Details below:
Mass of solution = 30 gInitial temperature of statue (T₁) = 25 °CFinal temperature of statue(T₂) = 44.9 °CChange in temperature (ΔT) = 44.9 - 25 = 19.9 °C Specific heat capacity of solution (C) = 4.18 J/gºC Heat energy (Q) =?Q = MCΔT
Q = 30 × 4.18 × 19.9
Q = 2495.46 J
Finally, we shall determine the enthalpy of the reaction. Details below:
Heat absorbed (Q) = 2495.46 J = 2495.46 / 1000 = 2.49546 KJMole of H₂O₂ (n) = 0.026 moleEnthalpy of reaction (ΔH) =?Q = n × ΔH
2.49546 = 0.026 × ΔH
Divide both sides by 0.026
ΔH = 2.49546 / 0.026
ΔH = 95.98 KJ/mol
Thus, the enthalpy of reaction is 95.98 KJ/mol
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13. Which of the following chemical reactions is an oxidation-reduction reaction?
A. C02 + H20 - H2C03
B. Pb(N03)2 + 2HC1- PbCh + 2HN03
C. H2S04 + Ba(OH)2 - BaS04 + 2H20
D. NH3 + HCl - NH4CI
E. Mg + CO2 - MgO + CO
Mg + CO[tex]_2[/tex]→ MgO + CO is an oxidation-reduction reaction. Therefore, the correct option is option E among all the given options.
Redox reactions involve oxidation-reduction chemical processes in which the oxidation states of the reactants change. Redox is a shortened version of reduction-oxidation. Two distinct processes—a reduction process or an oxidation process—can be used to describe all redox reactions.
In redox and oxidation-reduction processes, the oxidation or reduction reactions usually take place concurrently. In a chemical reaction, the material that is being reduced is referred to as the reducing agent, and the substance that is being oxidised is the oxidising agent. Mg + CO[tex]_2[/tex]→ MgO + CO is an oxidation-reduction reaction.
Therefore, the correct option is option E.
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If 6.00 6.00 L of water vapor at 50.2 °C 50.2 ° C and 0.121 0.121 atm reacts with excess iron, how many grams of iron(III) oxide will be produced? 2Fe(s)+3H2O(g)⟶Fe2O3(s)+3H2(g) 2 Fe ( s ) + 3 H 2 O ( g ) ⟶ Fe 2 O 3 ( s ) + 3 H 2 ( g )
The mass of iron(III) oxide produced is 115.29 grams.
To determine the mass of iron(III) oxide produced, we can use the stoichiometry of the balanced chemical equation provided.
The balanced equation shows that 2 moles of iron (Fe) react with 3 moles of water vapor (H₂O) to produce 1 mole of iron(III) oxide ( Fe₂O₃).
Given that we have 6.00 L of water vapor at 50.2 °C and 0.121 atm, we can use the ideal gas law to calculate the moles of water vapor;
PV = nRT, where P is pressure, V is volume, n is moles, R is the ideal gas constant, and T is temperature in Kelvin.
First, let's convert the temperature from Celsius to Kelvin;
T = 50.2 + 273.15 = 323.35 K
Now, we can plug in the values and solve for n;
0.121 atm × 6.00 L = n × 0.0821 atm L/mol K × 323.35 K
n = (0.121 atm × 6.00 L) / (0.0821 atm L/mol K × 323.35 K)
n = 0.361 mol
According to the stoichiometry of the balanced equation, the mole ratio between Fe and Fe₂O₃ is 2:1. Therefore, 0.361 mol of water vapor will react with 2 × 0.361 mol = 0.722 mol of Fe.
Now, we can calculate the molar mass of Fe₂O₃;
Fe₂O₃ = 2 × atomic mass of Fe + 3 × atomic mass of O
Fe₂O₃ = 2 × 55.85 g/mol + 3 × 16.00 g/mol
Fe₂O₃ = 159.70 g/mol
Finally, we can calculate the mass of Fe₂O₃ produced;
Mass of Fe₂O₃ = moles of Fe₂O₃ × molar mass of Fe₂O₃
Mass of Fe₂O₃ = 0.722 mol × 159.70 g/mol
Mass of Fe₂O₃ = 115.29 g
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Calculate the acid ionization constant for propanoic acid if a 0.200 M solution is 0.815% ionized. The abbreviated structural formula for butanoic acid is CH3CH2COOH.
The ionization constant of propanoic acid is 0.7181
The ionization constant (Ka) of the monoprotic acid can be calculated using the equation:
Ka = ([H⁺][A⁻])/[HA]
where [H⁺] is the concentration of hydrogen ions, [A⁻] is the concentration of the conjugate base, and [HA] is the initial concentration of the acid.
We know that the acid is 0.815 percent ionized, which means that only 0.815 percent of the initial concentration of the acid has ionized into hydrogen ions and the conjugate base.
Therefore, the concentration of hydrogen ions and the conjugate base can be calculated using the following equations:
[H⁺] = 0.815 x 0.200 M = 0.163 M
[A⁻] = 0.815 x 0.200 M = 0.163 M
The initial concentration of the acid ([HA]) can be calculated by subtracting the concentration of hydrogen ions and the conjugate base from the initial concentration of the solution:
[HA] = 0.200 M - 0.163M= 0.037 M
Substituting these values into the equation for Ka, we get:
Ka = (0.163 M)² / 0.037M = 0.7181
Therefore, the ionization constant (Ka) of propanoic acid is 0.7181
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The concentration of iodide ions in a saturated solution of lead (II) iodide is ________ M. The solubility product constant of PbI2 is 1.4 x 10-8.
The concentration of iodide ions in a saturated solution of lead (II) iodide is 3.03 x 10⁻³ M. The solubility product constant of PbI₂ is 1.4 x 10-8.
The solubility product constant, which is denoted by Ksp is defined as the equilibrium constant for a solid substance which dissolves in an aqueous solution.
when PbI₂ dissolves, it dissociates as follows
PbI₂ --> Pb²⁺ + 2I⁻
Molar solubility is the number of moles of salt that can be dissolved in 1 L of solution
If molar solubility of PbI₂ is x , then molar solubility of Pb²⁺ is x and I⁻ is 2x
ksp is solubility product constant.
ksp = [Pb²⁺][I⁻]²
ksp = [x][2x]²
ksp = 4x³
4x³ = 1.4 x 10⁻⁸
x³ = 0.35 x 10⁻⁸
x = 1.51 x 10⁻³ M
since molar solubility of I⁻ is 2x ,
then molar solubility of I⁻ or concentration of iodide ions is 3.03 x 10⁻³ M
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A 3-column table with 5 rows. Column 1 is unlabeled with entries A, B, C, D, E. Column 2 is labeled Temperature in degrees Celsius with entries 2.4, 21.5, 39.6, 55.6, 71.2. Column 3 is labeled Volume in cubic centimeters with entries 5.8, 5.8, 6.7, 6.9, 7.4. A student collected the data shown above. Row may represent an error.
Since it reflects no change in volume – it is most likely that the data recorded in row B is erroneous.
How to solveIn order to pinpoint the row with a probable error, we will scrutinize the correlation between temperature and volume.
Typically, whenever there is an increase in temperature, there would be an accompanying escalation in the volume of a given substance.
Let's take a closer look at the values reflected in the table:
From A to B: Temperature rises but the volume remains stagnant.
From B to C: Both temperature and volume show an increment.
Similarly, from C to D, as well as from D to E, we see that for every rise in temperature, there is subsequently more volume illustrated.
Given the dissimilarity between rows A and B – where the former shows a temperature increase while the latter reflects no change in volume – it is most likely that the data recorded in row B is erroneous.
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Which row in the table below is likely to represent an error in the student's data collection?
Temperature (°C) Volume (cm³)
A 2.4 5.8
B 21.5 5.8
C 39.6 6.7
D 55.6 6.9
E 71.2 7.4
Answer:
A student collected the data shown above. Row
✔ B
may represent an error.
Explanation:
edge 2023
5. If a beaker contains 15.6 moles of water, H2 O, how many molecules does this represent?
6. How many formula units of PbO are contained in 0.317 moles of lead (II) oxide?
7. 6.01 x 10 25 atoms of cesium, Cs, are equivalent to how many moles of cesium?
8. Determine the number of moles that are represented by 3.54 x 10 21 molecules of sulfur dioxide, SO2 .
If a beaker contains 15.6 moles of water, H[tex]_2[/tex] O, 9.3×10²⁴ are the number of molecules this represent.
The smallest recognisable unit into that a pure substance may be divided while retaining its composition & chemical properties is a molecule, which is a collection of more than one atom.
Until parts made up of individual molecules are reached, splitting of a sample of an item smaller progressively smaller parts does not result in a change regarding its composition as well as its chemical properties.
5.number of molecules= 15.6 × 6.022×10²³
=9.3×10²⁴
6. .number of molecules=0.317 × 6.022×10²³
=1.89×10²³
7. number of moles =6.01 x 10 25/ 6.022×10²³
= 100 moles
8. number of moles =3.54 x 10²¹/ 6.022×10²³
= 0.005moles
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Equation: 2H2 + O2 —> 2H2O
How many moles of hydrogen will be required to react with 2.1g of oxygen gas
(0₂)?
If you have 10,000 grams of a substance that decays with a half-life of 14 days, then how much will you have after 70 days?
Answer:
If the substance has a half-life of 14 days, then we know that after every 14 days, the amount of the substance remaining will be divided by two.
Since 70 days is five half-lives (70 ÷ 14 = 5), we can find the amount of substance remaining after 70 days by dividing the initial amount by 2 five times.
Amount remaining = 10,000 grams / (2^5) = 10,000 grams / 32
Amount remaining = 312.5 grams
Therefore, after 70 days, you will have 312.5 grams of the substance remaining.