Solve the following....
[tex]5x+3y=7\\3x-5y=-23[/tex]

Answer: is 832cm

Step-by-step explanation:

Answer:

d.  5490

Step-by-step explanation:

[tex]\begin{aligned}\displaystyle \sf \sum_{n=1}^{60} 3n & =3(1)+3(2)+3(3)+...+3(49)+3(50)\\ & = 3+6+9+...+147+150\end{aligned}[/tex]

Therefore, this is an arithmetic series with:

Sum of the first n terms of an arithmetic series:

[tex]S_n=\dfrac12n[2a+(n-1)d][/tex]

Therefore, the sum of the first 60 terms:

[tex]\begin{aligned}S_{60} &=\dfrac12(60)[2(3)+(60-1)3]\\ & =30[6+(59)3]\\ & = 30[6+177]\\ & = 30[183]\\ & = 5490 \end{aligned}[/tex]

Answer:

The answer is D) 5,490.

Step-by-step explanation:

The interval of times which represents the middle 68% of Ryan's finishing times in the 400 meter race, using the empirical rule, is 74.5 seconds to 75.5 seconds.

According to the empirical rule, also known as 68-95-99.7 rule, the percentage of values that lie within an interval with 68%, 95% and 99.7% of the values lies within one, two or three standard deviations of the mean of the distribution.

[tex]P(\mu - \sigma < X < \mu + \sigma) = 68\%\\P(\mu - 2\sigma < X < \mu + 2\sigma) = 95\%\\P(\mu - 3\sigma < X < \mu + 3\sigma) = 99.7\%[/tex]

Here we had  where mean of distribution of X is [tex]\mu[/tex]  and standard deviation from mean of distribution of X is [tex]\sigma[/tex].

When Ryan runs the 400 meter dash, his finishing times are normally distributed with a mean of 75 seconds and a standard deviation of 0.5 seconds.

The interval of times that represents the middle 68% of his finishing times in the 400 meter race is,

[tex]P(75 - 0.5 < X < 75 + 0.5) = 68\%\\P(74.5 < X < 75.5) = 68\%[/tex]

Thus. the interval of times which represents the middle 68% of Ryan's finishing times in the 400 meter race, using the empirical rule, is 74.5 seconds to 75.5 seconds.

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The unique triangles that can be formed with side lengths of 6.5 centimeters, 6 centimeters, and 2.5 centimeters is[tex]9.[/tex]

A triangle  can be referred to as a polygon with three edges and three vertices.

we can arrange length of one side of a unique triangle in 3 different ways.

Let x,y,z be the length of the three sides.

For triangles to be unique, length of one side can be arranged in 3 different ways.

Then, length of 6.5 cm can be at maximum three positions which is x,y,z.

The 2.5 cm lenght can appear to be at maximum three positions which is  x,y,z.This can as well be done for 6cm.

Therefore, total ways of making unique triangles[tex]= (3 + 3+ 3)= 9[/tex]

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Answer:

1

Step-by-step explanation:

Given:

What is the total number of unique triangles that can be formed with side lengths of 6.5 centimeters, 6 centimeters, and 2.5 centimeters?

​Solve:

Define:

What is a unique triangle?

Only one way to create triangle.

Are congruent which means same.

As you may know the word "Unique"

which means : original and unique designs

So without even solving we can see that there is only "One" way .

Kavinsky

Answer:

5

Step-by-step explanation:

ty

]

Answer:

1.2 m

Step-by-step explanation:

1 meter = 100 cm

120-100(1m)=20

.2 meters would be 20 cm if we're going by 1 m = 100cm.

We already have 1 meter from 100 cm and then we add the .2 meters to the 1 meter. 1+.2= 1.2 m

Answer:

1.2

Hope this helped!

Answer:

A

Step-by-step explanation:

Every 360 degrees (full circle) that you add or subtract from 140 is coterminal

140 + 360 = 500

please view the calculations section of this ans

The easiest way to determine the sine, cosine, and tangent of a number is to utilize the calculator, which we are asked to do.

cos (89) = 0.017

sin (17) = 0.29

tan (35) = 0.700

hope helpful ~

[tex]5 \frac{1}{4} + 1 \frac{3}{8} [/tex]

Lets solve it

[tex]5 \frac{1}{4} + 1 \frac{3}{8} [/tex]

[tex] \frac{21}{4} + \frac{11}{8} [/tex]

Taking the LCM of both denominator which is 8

[tex] \frac{42 + 11}{8} [/tex]

[tex] \frac{53}{8} [/tex]

Hey ! there

Answer:

Step-by-step explanation:

In this question we are given with two whole fraction . And we are asked to simplify them by adding .

Solution : -

Step 1 : Converting the fractions into improper fraction :

[tex]\dashrightarrow \: \qquad \: \dfrac{21}{4} + \dfrac{11}{8} [/tex]

Step 2 : We know that L.C.M of 4 and 8 is 8. So,

[tex]\dashrightarrow \: \qquad \: \dfrac{42 + 11}{8} [/tex]

Step 3 : Adding 42and 11 :

[tex]\dashrightarrow \: \qquad \: \dfrac{53}{8} [/tex]

Step 4 : Converting it in form of whole fraction :

[tex]\dashrightarrow \: \qquad \blue{\underline{\boxed{\frak{ \:6 \dfrac{5}{8} }}}} \quad\bigstar[/tex]

Answer: 64%

Step-by-step explanation:

The score you have entered means that the individual who took the test is at the sixty-fourth percentile – their percentile rank is 64%. This means that the student had a test score greater than or equal to 64% of the reference population. Conversely, 36% of students scored equal to or higher than the individual tested.

========================================================

Explanation:

The order matters because the jobs are different. This means we'll use a permutation.

We have n = 9 workers to pick from and r = 6 jobs to fill.

Plug those values into the nPr permutation formula.

[tex]n P r = \frac{n!}{ (n-r)! }\\\\9 P 6 = \frac{9!}{ (9-6)! }\\\\9 P 6 = \frac{9!}{ 3! }\\\\9 P 6 = \frac{9*8*7*6*5*4*3*2*1}{ 3*2*1 }\\\\9 P 6 = 9*8*7*6*5*4 \ \ \text{.... Note: The 3*2*1 cancels}\\\\9 P 6 = 60480\\\\[/tex]

There are 60480 ways to assign the 9 workers to the 6 different jobs where order matters.

----------------------

Another approach:

Label the 6 jobs as A,B,C,D,E,F

For job A, we have 9 workers to pick from.

For job B, we have 8 workers to pick from. This is because it states that there is "no more than one job to a worker".

For job C, we have 7 workers to pick from. And so on. We have this countdown going on. We stop once we reach job F.

We end up with 9*8*7*6*5*4 = 60480 different permutations

The string "9*8*7*6*5*4" is found in the second to last step of the section above.

Answer:

8000 pounds are in 4 tons

Step-by-step explanation:

hope it helps loves x :))

Answer:

8000 Pounds

Step-by-step explanation:

There are 8,000 pounds in 4 tons.

1 ton = 2,000 pounds.

Therefore, you multiply 4 x 2,000. Your answer is 8,000 pounds.

Answer:

32 yards and 64 feet

Step-by-step explanation:

just multiply them by 32

Answer:

y = negative 5 x + 4

Step-by-step explanation:

Hope it helps you in your learning process

Answer:

Assuming that the circle bissects the triangles equal sides at their midpoints, the ratio of the larger to smaller triangle should be close to 1/3

System of equations are equations that is more than one and have two or more unknowns. The solution to the given system of equation is expressed as (0, 2)

System of equations are equations that is more than one and have two or more unknowns.

Given the simultaneous equation

m + 4n = 8

m = n - 2

Substitute equation 2 into 1 to have:

n - 2 + 4n = 8

5n - 2  = 8

5n = 10

n = 2

Recall that m = n - 2

m = 2 - 2

m = 0

Hence the solution to the given system of equation is expressed as (0, 2)

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Answer:

B

Step-by-step explanation:

The number is x and you want 6 of that, so that makes 6x

You want 8 less of this, so subtract 8

Therefore you get 6x - 8

Answer:

B

Step-by-step explanation:

8 less than the product of 6 and x gives the expression 6x-8.

Answer:

1/6

Step-by-step explanation:

To simplify the expression:

      1. Change the divisor into it's reciprocal

     2. Change the sign into a multiplication sign.

     3. Evaluate the product of those fractions.

     4. Simplify the fraction. (If possible)

Given expression:

[tex]\dfrac{1}{6^3 } \div \dfrac{1}{36}[/tex]

According to step 1, we need to convert the divisor of the expression into it's reciprocal.

[tex]\dfrac{1}{6^3 } \div \dfrac{36}{1}[/tex]

According to step 2, we need to change the division sign (÷) into a multiplication sign (×).

[tex]\implies \dfrac{1}{6^3 } \times \dfrac{36}{1}[/tex]

According to step 3, we need to determine the product of these fractions. This can be done by evaluating the exponent.

[tex]\implies \dfrac{1}{(6)(6)(6) } \times \dfrac{36}{1}[/tex]

[tex]\implies \dfrac{1}{216 } \times \dfrac{36}{1}[/tex]

Multiply the fractions as needed. [a/b × c/d = (a × c)/(b × d) = (ac)/(bd):

[tex]\implies \dfrac{36}{216 }[/tex]

According to step 4, (If possible), Simplify the product of 1/216 and 36. In this case, the product of 1/216 and 36 is 36/216. Since both are divisible by 6, we can divide the numerator and the denominator by 6 to simplify the fraction.

[tex]\implies \dfrac{36 \div 6}{216 \div 6 }[/tex]

[tex]\implies \dfrac{1}{6 }[/tex]

Therefore, the quotient of 1/6^3 and 1/36 is 1/6.

Learn more about this topic: https://brainly.com/question/22322495

Answer:

[tex]\large\textsf{$\dfrac{1}{6}$}[/tex]

Step-by-step explanation:

[tex]\large\textsf{$\dfrac{1}{6^3} \div \dfrac{1}{36}$} \implies \normalsize \textsf{Convert 36 into a base with an exponent}[/tex]

[tex]\large\textsf{$\dfrac{1}{6^3} \div \dfrac{1}{6^2}$} \implies \normalsize \textsf{Cross multiply}[/tex]

[tex]\large\textsf{$\dfrac{1 \cdot 6^2}{1 \cdot 6^3}$} \implies \normalsize \textsf{Multiply}[/tex]

[tex]\large\textsf{$\dfrac{6^2}{6^3}$}\implies \normalsize \textsf{Simplify using the Quotient of Powers Property: \normalsize\textsf{$\dfrac{x^m}{x^n} = x^{m-n}$}}[/tex]

[tex]\large\textsf6^{2-3}[/tex]

[tex]\large\textsf6^{-1} \implies \normalsize \textsf{Simplify using the Negative Exponent Property: \normalsize\textsf {${x^{-m}} = \dfrac{1}{x^m}$}}[/tex]

[tex]\large\textsf{$\dfrac{1}{6^1}$} \implies \normalsize \textsf{Simplify}[/tex]

[tex]\large\textsf{$\dfrac{1}{6}$} \implies \normalsize \textsf{Final answer}[/tex]

Hope this helps!

Answer:

14 times.

Step-by-step explanation:

It is how many times 1/4 go in 3 1/2.

3 1/2 as an improper fraction is 7/2.

To make them have the same denominator, we have to change 7/2.

7 x 2 = 14

2 x 2 = 4

So, how many times does 1/4 go in 14/4?

14 times.

Answer:

935 yards

Step-by-step explanation:

If she runs 85 yards at each practice you would multiply it by the amount of practices. So 85x11

Answer:

The graph is decreasing in a non linear form, this is shown because from the 0 value to the 12 value on the x axis the y value decreases from 4000 to less than 400( graph going downwards) and its non linear because the graph does not form a straight line

Answer:

y=40/183x

Step-by-step explanation:

y = Rise/Run multiplied plus y intercept by x or Y= mx + b

There is no b

m = 40/183

Y = 40/183x

Answer:

266

Step-by-step explanation:

Let the attendence of 5days be a,b,c,d,e

given,

(a+b+c+d+e)/5=264

a+b+c+d+256=264*5 [since 5th day=256]

(a+b+c+d+)/4=1(320-256)/4 [dividing both side by 4]

average attendence of 4 days =266

Answer:

25.796... km

Step-by-step explanation:

We are given that:

Formula of circumference:

Thus, we can rewrite the circumference as:

Since we are asked to determine the diameter, it is recommended to use the formula (πd). Therefore,

Divide π both sides to isolate the diameter:

Substitute π as 3.14 and simplify:

Therefore, the diameter of the circle is 25.796... km.

Based on the calculations, the chemical element (X) in this nuclear equation is equal to ²³⁵U₉₂.

An alpha decay refers to a type of nuclear reaction in which the atomic nucleus of a radioactive element emits an alpha particle (atom of helium), thereby, producing chemical elements with a different atomic nucleus.

In this exercise, we are given the following nuclear equation with an alpha decay:

²³⁹Pu₉₄  -----> X + ⁴He₂

For the superscript, we have:

239 - 4 = 235.

For the subscript, we have:

94 - 2 = 92.

Therefore, the chemical element (X) is equal to ²³⁵U₉₂.

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Answer:

its c

Step-by-step explanation:

trust

#1

Slope:-

Equation in point slope form

Shading done to right means towards origin

So

shading is towards origin

The inequality is

Dashed line given so we remain it <

#2

Slope:-

Equation in point slope form

Put (0,0)

The inequality is(solid line given)

Graph attached

Answer:

c and b was right for me

Step-by-step explanation:

Answer:

4 ^3√7m^2

Step-by-step explanation:

^3√64×7m^2

^3√4^3×7m^3

^3√4^3 3^√7m^2

= 4^3√7m^2

Answer:

[tex] \boxed{ \tt = 4 \sqrt[3]{7m {}^{2} } }[/tex]

Step-by-step explanation:

Given,

[tex] \sqrt[3]{448m {}^{2} } [/tex]

Solution:

[tex] = \sqrt{4 {}^{3 } \times 7 \: m {}^{2} } [/tex]

[tex] \tt = 4 \sqrt[3]{7m {}^{2} } [/tex]

[tex] \rule{225pt}{2pt}[/tex]

Answer:

He was 11

Step-by-step explanation:

if Camila was 4 years younger than her brother and she was seven. That means he is 4 years older than her. so 7+4=11