Solve For X. Assume that lines which appear are tangent.

The length of PQ in triangle PQR is 110.

What are similar triangles ?

Similar triangles are two triangles that have the same shape but may differ in size. In other words, their corresponding angles are equal, and their corresponding sides are in proportion. This means that if you were to resize one triangle by a constant factor, the resulting triangle would still be similar to the original triangle.

For example, if you take a triangle and multiply all its side lengths by a factor of 2, you will end up with a triangle that is twice as large but still similar to the original triangle.

According to the question:
Since the triangles XYZ and PQR are similar, their corresponding sides are in proportion. That is:

XY/PQ = XZ/PR = YZ/QR

We can use this property to find the length of the missing side QP.

First, let's find the ratio of corresponding sides:

XY/PQ = XZ/PR

48/PQ = 55/110

Simplifying this equation, we get:

PQ = 48*110/55 = 96

So, PQ is 96.

Alternatively, we could use the other pair of corresponding sides:

XZ/PR = YZ/QR

55/110 = 73/146

Simplifying this equation, we get:

QP = 55*146/73 = 110

So, QP is also 110.

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Answer:

a. 4

b. -2

c. 0,5

it js wants u to say what the number line represents

Step-by-step explanation:

the probability that 50 or more requests are made for pop songs is  0.0967, or about 9.67%.

The binomial distribution is a probability distribution that describes the number of successes in a fixed number of independent trials, where each trial has the same probability of success.

We can use the binomial distribution to model this situation, where the number of trials is 120 (the number of people at the party), and the probability of success (making a request for a pop song) is 0.37. Let X be the number of requests for pop songs. Then:

The mean of X is μ = np = 120 x 0.37 = 44.4

The standard deviation of X is σ = sqrt(np(1-p)) = sqrt(120 x 0.37 x 0.63) = 4.32

To find the probability that 50 or more requests are made for pop songs, we can use the normal approximation to the binomial distribution, which applies when np >= 10 and n(1-p) >= 10.

Let Z be a standard normal random variable, then:

P(X >= 50) = P((X - μ)/σ >= (50 - μ)/σ)

= P(Z >= (50 - 44.4)/4.32)

= P(Z >= 1.2963)

= 1 - P(Z < 1.2963)

= 1 - 0.9033

= 0.0967

Therefore, the probability that 50 or more requests are made for pop songs is approximately 0.0967, or about 9.67%.

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Answer: ∠1 and ∠2 are supplementary angles.

Step-by-step explanation:

Complementary angles are two angles that add up to 90 degrees.

Supplementary angles are angles that add up to 180 degrees.

∠1 + ∠2 = 180 degrees, so it is a supplementary angle.

Answer:

To subtract two-digit numbers, use column form. Subtract one column at a time, starting with the Ones column. We regroup, or borrow. To regroup, take 1 from the Tens column and add 10 to the Ones column.

Step-by-step explanation:

The probability that the newspapers sample will lead it to predict defeat is 92.36%.

To solve this problem, we need to use the binomial distribution formula.

Let's define the following:

X: number of voters in the sample who do not support the budget (i.e., the sample leads to a prediction of defeat).

n: sample size, which is 377.

p: proportion of voters who support the budget, which is 0.54 (since 54% support it, 46% do not support it).

The probability of the sample leading to a prediction of defeat is:

P(X = k) = (n choose a) * pᵃ * (1-p)ⁿ⁻ᵃ

where (n choose a) = n! / (a! * (n-a)!) is the binomial coefficient.

We want to find P(X >= 189), which means that at least 189 voters in the sample do not support the budget.

P(X >= 189) = 1 - P(X < 189)

To calculate P(X < 189), we can use a normal approximation to the binomial distribution, since n is large and p is not too close to 0 or 1.

The mean of the binomial distribution is mu = n * p = 377 * 0.54 = 203.58

The standard deviation is sigma = √(n * p * (1-p)) = √(377 * 0.54 * 0.46) = 10.20

We can standardize X using the z-score formula:

z = (X - mu) / sigma

P(X < 189) = P(z < (189 - 203.58) / 10.20) = P(z < -1.43)

Using a standard normal table or calculator, we can find that P(z < -1.43) = 0.0764.

Therefore, P(X >= 189) = 1 - P(X < 189) = 1 - 0.0764 = 0.9236.

So the probability that the newspaper's sample will lead it to predict defeat is approximately 0.9236, or 92.36%.

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Answer:

(a) Using the given mean and standard deviation, we can standardize the random variable X representing the lifespan of a light bulb as:

Z = (X - μ) / σ = (10,500 - 9,000) / 1,000 = 1.5

Then, we can use a standard normal distribution table or calculator to find the probability that a randomly chosen light bulb lasts more than 10,500 hours:

P(X > 10,500) = P(Z > 1.5) ≈ 0.0668

So the probability is approximately 0.0668, rounded to four decimal places.

(b) The distribution of the mean lifespan of 15 light bulbs can be described as approximately normal with a mean of 9,000 hours, and a standard deviation of 1,000 hours divided by the square root of 15 (since the sample size is 15).

This is because, according to the Central Limit Theorem, the distribution of sample means tends to be approximately normal regardless of the underlying distribution of the population, as long as the sample size is large enough. In this case, a sample size of 15 is large enough to assume a normal distribution.

Answer:

[tex]\frac{4}{3}[/tex]

Step-by-step explanation:

The probability that between 6 and 9 (both inclusive) bulbs from the sample are defective is 0.5362

This is a binomial distribution problem, where the probability of success (defective bulb) is 0.2 and the probability of failure (non-defective bulb) is 0.8. We need to find the probability that between 6 and 9 (both inclusive) bulbs out of 16 bulbs in the sample are defective.

We can use the binomial probability formula to solve this problem

P(6 ≤ X ≤ 9) = P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9)

where X is the number of defective bulbs in the sample.

P(X = k) = (n choose k) × p^k × (1-p)^(n-k)

where n is the sample size, k is the number of defective bulbs, p is the probability of a defective bulb, and (n choose k) is the binomial coefficient.

Using this formula, we can calculate the probability for each value of X and sum them up to get the probability for the range 6 to 9.

P(X = 6) = (16 choose 6) × 0.2^6 × 0.8^10 = 0.0881

P(X = 7) = (16 choose 7) × 0.2^7 × 0.8^9 = 0.1409

P(X = 8) = (16 choose 8) × 0.2^8 × 0.8^8 = 0.1606

P(X = 9) = (16 choose 9) × 0.2^9 × 0.8^7 = 0.1462

Therefore, the probability that between 6 and 9 (both inclusive) bulbs from the sample are defective is

P(6 ≤ X ≤ 9) = 0.0881 + 0.1409 + 0.1606 + 0.1462 = 0.5362

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Answer: -1  1/3 (this is one and a third) or -4/3 (improper fraction)

Step-by-step explanation:

Solve for y by simplifying both sides of the equation then isolate the variable (y).

Answer: q = -3, p = 6

Step-by-step explanation:

Multiply second equation by 3. 6q + 9q = 9. Equation one minus equation two which gives you p = 6. Then plug it in the second equation. 12 + 3q = 3. 3q = -9. q = -3.

Answer:

x = y = 20

Step-by-step explanation:

The two triangles shown are similar because one is simply an extension of othe other.

From this, we can use a similar side lengths formula specifically for triangles.

[tex]\frac{y + 5}{y} = \frac{15}{12}\\[/tex]

Notice that this represents the ratio of the whole side to the smaller side and says that this proportion is equal to the proportion for its adjacent side lengths. Cross mutiply the above equation to solve for y.

12(y+5) = 15y

12y + 60 = 15y

y = 20

Now we need to find the value of x. We have a side and hypotenuse's length of this large triangle, so we can use the pythagorean theorem to calculate the unknown side length.

(12 + 3)² + x² = (20 + 5)²

15² + x² = 25²

225 + x² = 625

x² = 400

x = ±20

The negative 20 doesn't make sense for this application so use the positive 20.

Therefore x = 20, y = 20.

The value of x that makes the expression 3√(53x) equivalent to 21√53 is 49.

In mathematics, an expression is a combination of numbers, variables, and operations, typically written using mathematical symbols and/or mathematical notation. An expression can be a single number, variable, or combination of the two, or it can be a more complex combination of numbers, variables, and operators such as addition, subtraction, multiplication, division, exponentiation, or root extraction. Expressions can be used to represent a wide variety of mathematical concepts and relationships, such as equations, inequalities, functions, and geometric figures. They are an important part of mathematical language and are used to communicate mathematical ideas and concepts.

In mathematics, an equation is a statement that shows the equality of two expressions. It typically involves one or more variables and mathematical operations such as addition, subtraction, multiplication, division, exponentiation, or root extraction. The expressions on both sides of the equation are separated by an equal sign (=), indicating that they have the same value. The purpose of an equation is to find the value of the variable(s) that makes the equation true. Solving an equation involves manipulating the expressions on both sides of the equation to isolate the variable and determine its value. Equations are used in a wide variety of mathematical applications, such as solving problems in algebra, geometry, calculus, and physics.

We can start by equating the expression 3√(53x) to 21√53 and then solving for x.

3√(53x) = 21√53

Dividing both sides by 3√53, we get:

√x = 7

Squaring both sides of the equation, we get:

x = 49

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The set notation that represents the shaded portion in the given Venn-diagram​ is: A ∪ B − (A ∩ B).

The union of the sets A and B simply denotes everything which is in either A or B, as represented by the shaded region in the given venn diagram. The intersection of two sets is that which is in both sets, as represented by the unshaded region in the following Venn diagram

The union of A and B is the entirety of all that is in either A or B, as represented by the shaded area inside the given venn diagram.

The intersection of  sets is  in each sets, as represented via way of means of the magenta shaded area withinside the following Venn diagram.

Thus, it is A ∪ B − (A ∩ B).

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Answer:

The equation for the width is:

1056 = (2w+4) * w

And the solution is:

Width: 22 inches

Length: 48 inches

Step-by-step explanation:

Area of a rectangle = length * width

1056 = h * w   Eq. 1

h = 2w + 4         Eq. 2

h = length

w = width

Replacing Eq. 2 in Eq. 1:

1056 = (2w+4) * w

1056 = 2w*w + 4*w

1056 = 2w² + 4w

2w² + 4w - 1056 = 0

w = {-4±√((4²)-(4*2*-1056))} / (2*2)

w = {-4±√(16 + 8448)} / 4

w = {-4±√8464} / 4

w = {-4±92} / 4

Is a geometric figure, therefore, only the positive value will be obtained

w = {-4+92}/4

w = {88} / 4

w = 22

From Eq. 2:

h = 2w+4

h = 2*22+4

h = 44+4

h = 48

Check:

From Eq. 2

1056 = h * w

1056 = 48 * 22

The probability that at least 50 respondents of a random sample of 100 Mississippi residents do not identify themselves as conservative is approximately 0.158

To solve this problem, we need to use the binomial distribution. Let's define the following

n = 100 (sample size)

p = 1 - 0.534 = 0.466 (probability of not identifying as conservative)

x = number of respondents who do not identify as conservative (we want at least 50)

We want to find P(X >= 50), which represents the probability of getting at least 50 respondents who do not identify as conservative in a random sample of 100 Mississippi residents.

We can use the cumulative distribution function (CDF) of the binomial distribution to calculate this probability. The CDF gives us the probability of getting up to a certain number of successes (in this case, respondents who do not identify as conservative).

Using a calculator or statistical software, we find

P(X >= 50) = 1 - P(X < 50) = 1 - binomcdf(100, 0.466, 49) = 0.158

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The given question is incomplete, the complete question is:

Mississippi is the most conservative U.S. state, with 53.4 percent of its residents identifying themselves as conservative. What is the probability that at least 50 respondents of a random sample of 100 Mississippi residents do not identify themselves as conservative?

The sequence converges to ln 2 / ln 6 as n approaches infinity.

How to find limit?

To determine whether the sequence converges or diverges, we need to take the limit of the sequence as n approaches infinity.

a_n = (ln 2n) / (ln 6n)

We can simplify this expression by applying logarithm rules:

a_n = (ln 2n) / (ln 6n) = (ln 2 + ln n) / (ln 6 + ln n)

Now we can use the fact that for any constant a>1, ln n is dominated by ln a as n approaches infinity, i.e., ln n / ln a approaches infinity as n approaches infinity.

Thus, as n approaches infinity, we have:

a_n = (ln 2 + ln n) / (ln 6 + ln n) ≈ ln 2 / ln 6

Therefore, the sequence converges to ln 2 / ln 6 as n approaches infinity.

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Answer:

x = 6.464 and x = -0.464

Step-by-step explanation:

3/x + 6 = x

3 + 6x/x = x

3 + 6x = x²

x² - 6x - 3 = 0

x = 6 ± √36 - 4x - 3/2 = 6 ± √36 + 12/2

x = 6 ± √48/2 = 6 ± 4√3/2 = 3 ± 2√3

So x = 3 + 2√3 and 3 - 2√3

x = 6.464 and x = -0.464

The object distance is 0, which implies that the object is at the focus of the concave mirror.

For a concave mirror, the magnification is given by the formula:

m = -di/do

where m is the magnification, di is the image distance, and do is the object distance. Since we are given that the magnification is -2.0, we can write:

-2.0 = -di/do

Simplifying this expression, we get:

di = 2do

We can also use the mirror formula for a concave mirror:

1/f = 1/do + 1/di

where f is the focal length of the mirror. Substituting di = 2do and f = -16 cm (since the mirror is concave), we get:

1/-16 = 1/do + 1/(2do)

Multiplying both sides by -16do, we get:

do - 2f = -32

Substituting f = -16 cm, we get:

do - (-32) = -32 + 32

do = 0

This means that the object distance is 0, which implies that the object is at the focus of the concave mirror. This is a valid result, since a concave mirror can form a real, inverted image for an object placed at a distance equal to its focal length. In this case, the magnification would be -1, not -2. So, it is not possible to have a magnification of -2 for an object distance in front of a concave mirror with a focal length of 16 cm.

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We would see a logarithmic sequence of values if we plotted the amount of time Edna spends watching TV weekly on a logarithmic scale.

If we plot the amount of time Edna spends watching TV on a logarithmic scale, we would see a continuous sequence of values that increase as her viewing time increases. Specifically, the sequence would be a logarithmic scale of the number of hours she watches TV per week.

On a logarithmic scale, each increment corresponds to a multiplication by a constant value. For example, if we use a logarithmic scale base 10, then each increment of 1 corresponds to a multiplication by 10. So, if we plot Edna's TV watching time on a logarithmic scale, we would see a sequence of values that increase by a factor of 10 as her TV watching time increases by an order of magnitude.

For example, if Edna watches 2 hours of TV per week, the logarithmic value would be log(2) = 0.3. If she watches 7 hours per week, the logarithmic value would be log(7) = 0.85. If she watches 20 hours per week, the logarithmic value would be log(20) = 1.3. As her viewing time increases, the logarithmic values would continue to increase in a continuous sequence.

Therefore, if we plotted the amount of time Edna watches TV each week on a logarithmic scale, we would see a logarithmic sequence of numbers.

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Mira can afford to pay at most $1,094.03 per month in rent if she wants to limit her rent to 28% of her annual salary of $46,830.

To calculate the monthly maximum rent Mira can afford to pay, we need to follow these steps:

Step 1: Find 28% of Mira's annual salary:

28% of $46,830 = 0.28 x $46,830 = $13,128.40

Step 2: Divide the result from Step 1 by 12 to get the maximum monthly rent:

$13,128.40 ÷ 12 = $1,094.03 (rounded to the nearest cent)

Therefore, Mira can afford to pay at most $1,094.03 per month in rent if she wants to limit her rent to 28% of her annual salary.

Step 1 involves finding 28% of Mira's annual salary, which is done by multiplying her annual salary by 0.28 (which is equivalent to 28/100 or 0.28). This gives us the maximum amount of money Mira can spend on rent in a year while still staying within her 28% limit.

In Step 2, we divide the result from Step 1 by 12 to get the monthly maximum rent Mira can afford to pay. This is because there are 12 months in a year, so we need to divide the yearly rent limit by 12 to get the monthly limit.

In this case, the maximum amount of money Mira can spend on rent in a year is $13,128.40. Dividing this by 12 gives us a monthly maximum rent of $1,094.03 (rounded to the nearest cent). This means that if Mira wants to keep her rent payments at or below 28% of her annual salary of $46,830, she should look for a rental property that costs no more than $1,094.03 per month.

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You consumed approximately 69 calories from the 9 cashews you ate.

What is statistics?

Statistics is a branch of mathematics that deals with the collection, analysis, interpretation, presentation, and organization of numerical data.

A nutrition label typically provides information about the nutrient content of a food item per serving size. In this case, the label states that 28 grams of dry roasted cashews contain 161 calories.

To determine the number of calories in a smaller portion of cashews, we need to use a proportion or ratio.

We start by calculating the number of calories per gram of cashews by dividing the total number of calories by the total weight of cashews:

161 calories / 28 grams = 5.75 calories per gram of cashews

This means that each gram of cashews contains about 5.75 calories.

Next, we need to figure out how many grams of cashews you ate. The question states that you ate 9 cashews, which weighed a total of 12 grams.

To find out the number of calories you consumed, we simply need to multiply the weight of the cashews (12 grams) by the number of calories per gram (5.75):

5.75 calories per gram x 12 grams = 69 calories

Therefore, you consumed approximately 69 calories from the 9 cashews you ate.

Complete question is:

A nutrition label shows that there are 161 calories in 28 grams of dry roasted cashews. You eat 9 cashews totaling 12 grams. How many calories did you consume?

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Answer:

Step-by-step explanation:

y = –5x + 10

y = –3x + 2

–5x + 10= –3x + 2

2x= 8

x=4

y= -5(4)+10

y= -20+10

y=(-10)

Answer:

Step-by-step explanation:

[tex]-5x + 10= -3x + 2[/tex]        (since both equal y)

            [tex]10=2x+2[/tex]          ([tex]+5x[/tex] both sides)

             [tex]8=2x[/tex]                 (-2 both sides)

             [tex]x=4[/tex]                   (÷2 both sides)

Sub [tex]x=4[/tex] to find y:

      [tex]y=-5(4)+10=-10[/tex]

Solution: x=4, y= -10

Geometric growth is a type of exponential growth where a quantity or value increases at a fixed percentage rate over a certain period of time.

Geometric growth is a type of exponential growth where a quantity or value increases at a fixed percentage rate over a certain period of time. This means that the growth rate is proportional to the current size or value of the quantity, resulting in a continuously increasing growth rate.

Geometric growth is commonly observed in natural and social systems, such as population growth, compound interest, and the spread of infectious diseases. It is represented mathematically by an exponential function, where the base of the exponent is greater than one, indicating an increasing rate of growth over time.

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I have solved the question in general, as the given question is incomplete.

The complete question is:

What is geometric growth ?

The scale drawing of the mural would be 594.36 cm wide and 1097.28 cm tall.

A scale drawing is a drawing that shows an object or area at a scale that differs from the real size of the object or area. A scale, which is a ratio comparing the size of the drawing to the size of the actual item or location, is used to make scale drawings. A scale of 1:50, for instance, indicates that one unit on the design corresponds to fifty in real life.

In several disciplines, including architecture, engineering, and design, scale drawings are employed in real-world situations. Scale drawings are used by architects to construct building floor plans, elevations, and sections. Scale drawings are used by engineers to develop mechanical systems and machinery.

Given that the dimensions of the mural is 13 feet by 24 feet.

Converting into cm we have:

width = 13 feet * 30.48 cm/foot = 396.24 cm

height = 24 feet * 30.48 cm/foot = 731.52 cm

Now using the scale we have:

3cm : 2ft = x cm : 396.24 cm

Using cross multiplication we have:

2ft * x cm = 3cm * 396.24 cm

x = (3cm * 396.24 cm) / 2ft = 594.36 cm

For the height, we have:

3cm : 2ft = y cm : 731.52 cm

2ft * y cm = 3cm * 731.52 cm

y = (3cm * 731.52 cm) / 2ft = 1097.28 cm

Hence, the scale drawing of the mural would be 594.36 cm wide and 1097.28 cm tall.

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=================================================

Explanation:

2 freshmen + 3 sophomores + 2 juniors + 2 seniors = 9 students total.

Let's consider the cases where we have the same number of juniors and seniors. We'll then take the complement of this to get the final answer.

-----------

Case A: There is 1 junior and 1 senior

There are 2 ways to pick a junior and 2 ways to pick a senior. That's 2*2 = 4 ways so far.

Then we have 9-4 = 5 students left to pick from (i.e. 2 freshmen+3 sophomores = 5 students left) and we have 5-2 = 3 seats to fill. Order doesn't matter on the committee since each person has equal rank.

We use the nCr combination formula.

n = 5 students

r = 3 seats to fill

n C r = (n!)/(r!(n-r)!)

5 C 3 = (5!)/(3!*(5-3)!)

5 C 3 = (5!)/(3!*2!)

5 C 3 = (5*4*3!)/(3!*2!)

5 C 3 = (5*4)/(2!)

5 C 3 = (5*4)/(2*1)

5 C 3 = (20)/(2)

5 C 3 = 10

There are 10 ways to fill the remaining 3 seats when we pick from the freshmen and sophomores only.

To recap everything so far:

Therefore, we have 4*10 = 40 different combinations possible for case A. We'll refer to this value later.

-----------

Case B: We pick 2 juniors and 2 seniors

Since there 2 juniors to pick from, and 2 junior seats to fill, there's only 1 way to do this. Likewise, there's only 1 way to pick the 2 seniors to fill the 2 seats.

In total so far there is 1*1 = 1 way to pick the 2 juniors and 2 seniors in any order you like.

Then we have 9-4 = 5 students left that are freshmen or sophomores. This is the number of choices we have for the final 5th seat.

We have 1*5 = 5 ways to have case B happen.

----------

Summary so far:

There are 45 ways to have the same number of juniors as seniors (either 1 of each or 2 of each).

Now we must calculate the number of total combinations possible on this committee. We'll turn to the nCr formula again.

n = 9 students

r = 5 seats

n C r = (n!)/(r!(n-r)!)

9 C 5 = (9!)/(5!*(9-5)!)

9 C 5 = (9!)/(5!*4!)

9 C 5 = (9*8*7*6*5!)/(5!*4!)

9 C 5 = (9*8*7*6)/(4!)

9 C 5 = (9*8*7*6)/(4*3*2*1)

9 C 5 = (3024)/(24)

9 C 5 = 126

There are 126 different five-person committees possible.

Of those 126 committees, 45 of them consist of cases where we have the same number of juniors and seniors.

That must mean there are 126-45 = 81 combinations where we do not have the same number of juniors and seniors. This is where the concept of "complement" comes in.

Equation one can be solved by additive property two by subtractive property.

A mathematical statement known as an equation consists of two algebraic expressions separated by equal signs (=) on either side.

It demonstrates the equality of the relationship between the printed statements on the left and right.

Left side equals right side in all formulas.

To find the values of unknowable variables, which stand in for unknowable quantities, you can solve equations.

A statement is not an equation if it lacks the equals sign.

When two expressions have the same value, a mathematical statement known as an equation will include the symbol "equal to" between them.

7=m+1.2

m=7-1.2

6.8

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Based on the information provided, it is most likely that the variable Amari used to construct the bar graph is the "Type of orange". This is because a bar graph is a visual representation of categorical data and is used to show the frequency or proportion of each category in a dataset. The other variables mentioned - diameter of the oranges, number of navel oranges, and price per pound of oranges - are all quantitative variables and are better represented using other types of graphs such as histograms, scatterplots, or line graphs.