solve for x 13 + 7x = 27

Answers

Answer 1

Answer:

x=2

Step-by-step explanation:

1) -13 on each side (7x=14)

2) Divide by 7 on each side (x=2)

3) x=2


Related Questions

Match each statement in the table with one of the diagrams shown.
a o o
A
B
C
D
Statement
Diagram
All the vertices of the square touch the circle
Only one side of the square is a chord of the circle
All four sides of the square are tangents to the circle

Answers

Answer:

A

C

B

Step-by-step explanation:

A) All the corners of the square touch the edge of the circle
B) Only 1 side of the square touches the circle so it forms a chord.

C) The circle is inside the square so the sides of the square form tangents (Perpendicular lines to the radius).

Which equation translates the sentence, "Three times the number m plus ten is equal to n"?
A. 3m + 10 = n
B. 3(10) + m = n
C. 3 + 10m = n
D. 3 x 10(m) = n

Answers

Answer is A 3m+10=n

Hope this helps:):)

Linda bought 2 cans of paint and 1/2 of a pint of special paint additive formulated to reduce mildew. Before painting her house, she divided the additive equally between the 2 cans of paint. How much additive did she put in each can?

Answers

1/4 of a pint of additive per can of paint

Which expressions are equivalent to 42-5? Choose all the correct answers. Show your work in arriving at your answers.

Answers

Answer:

B, C, E

Step-by-step explanation:

Exponent Rules

[tex]a^b \cdot a^c=a^{b+c}[/tex]

[tex]\dfrac{a^b}{a^c}=a^{b-c}[/tex]

[tex]a^n \cdot b^n=(ab)^n[/tex]

[tex]a^0=1[/tex]

[tex]\dfrac{1}{a^b}=a^{-b}[/tex]

[tex](a^b)^c=a^{bc}[/tex]

[tex]\textsf{A}\quad42^{-3} \cdot 42^8=42^{-3+8}=42^5[/tex]

[tex]\textsf{B}\quad \dfrac{42^{-7}}{42^{-2}}=42^{-7-(-2)}=42^{-5}[/tex]

[tex]\textsf{C}\quad \dfrac{6^{-5}}{7^5}=6^{-5} \cdot 7^{-5}=(6 \cdot 7)^{-5}=42^{-5}[/tex]

[tex]\textsf{D}\quad 42^0 \cdot 42^5=1 \cdot 42^5=42^5[/tex]

[tex]\textsf{E}\quad \left(\dfrac{1}{42^{-5}}\right)^{-1}=(42^5)^{-1}=42^{-5}[/tex]

[tex]\textsf{F}\quad \left(\dfrac{6^{-5}}{7^5}\right)^{-1}=\left(6^{-5} \cdot 7^{-5}\right)^{-1}=\left(\left(6 \cdot 7\right)^{-5}\right)^{-1}=42^{-5(-1)}=42^5[/tex]

Check one by one

#A

[tex]\\ \rm\Rrightarrow 42^{-3}42^8=42^{-3+8}=42^5[/tex]

#B

[tex]\\ \rm\Rrightarrow \dfrac{42^{-7}}{42^{-2}}=42^{-7+2}=42^{-5}\checkmark[/tex]

#C

[tex]\\ \rm\Rrightarrow \dfrac{6^{-5}}{7^5}=6^{-5}7^{-5}=42^{-5}\checkmark[/tex]

#d

[tex]\\ \rm\Rrightarrow 42^0.42^5=42^{0+5}=42^5[/tex]

#e

[tex]\\ \rm\Rrightarrow \left(\dfrac{1}{42^{-5}}\right)^{-1}=42^{-5}\checkmark[/tex]

#f

[tex]\\ \rm\Rrightarrow \left(\dfrac{6^{-5}}{7^5}\right)^{-1}[/tex]

[tex]\\ \rm\Rrightarrow (42^{-5})^{-1}[/tex]

[tex]\\ \rm\Rrightarrow 42^5[/tex]

Two teenagers work summer jobs. The first teenager earns $20 an hour plus $55 in tips for each shift worked. The second teenager earns $25 per hour and receives no tips. Each teenager worked an 8 hour shift. Who earned more money: the first teenager or the second teenager?

Answers

Answer:

1 :

20×8=$160

160+55=$215

2:

25×8=$200

the first teenager earns more money after every shift

hope this helps you :D

Bella is building two wigwams for a school project on american indian tribes. she first builds two wooden frames, each in the shape of a cone with a base radius of 2 feet and a slant height of 5 feet. if bella wants to cover the frames in fabric, how many square feet of fabric will she need? (use 3.14 for pi and round to the nearest whole number. recall the formulas l a = pi r l and s a = pi r l pi r squared.) square inches

Answers

The amount of fabric needed = 2(surface area of the cone-shaped wooden frame) = 88 ft².

What is the surface Area of a Cone?

Surface area of a cone = πr² + πrl

Given the following dimensions of the cone-shaped wooden frame:

Slant height (l) = 5 feetRadius (r) = 2 feet

Amount of fabric needed = 2(surface area of the cone-shaped wooden frame) = 2(πr² + πrl)

= 2(3.14 × 2² + 3.14 × 2 × 5)

= 87.92

Amount of fabric needed ≈ 88 ft²

Learn more about surface area of a cone on:

https://brainly.com/question/10506554

Answer:

88

Step-by-step explanation:

Help I need the awnser asap
AABC = ADEF
B
C
E
F
Match BC to the corresponding part.
EF FD
ZE

Answers

Answer:

Is it not just EF?

Step-by-step explanation:

I mean BC is the bottom of the triangle so the corresponding part is just the other triangles bottom which is EF if it was just angle B it'd be just angle E but it's not it's both B and C so it's E and F

Divide. give the quotient and remainder
2746/6

Answers

Answer:

On the image

Step-by-step explanation:

...............

Answer:

457 Remainder 4

Step-by-step explanation:

The graph shows the amount in Harold's savings
account over a certain number of weeks. Find the rate
of change and record it in the grid
HELPS A GIRL OUT

Answers

Rise/Run
Rise=-3
Run=2
-3/2
(You don’t simplify slope)

Calculate the median of the data set below. {0.3, 1.5, 3.8, 2.6, 1.5, 9.1, 4.2, 3.8, 1.5, 2.9} A. 3.8 B. 3.35 C. 2.75 D. 2.5

Answers

Answer:

2.75

Step-by-step explanation:

0.3,1.5,1.5,1.5,2.6,2.9,3.8,3.8,4.2,9.1

(smaller to greater)

middle of this is 2.6 and 2.9

so, 2.6+2.9=5.5

now we divide it by 2

so, 5.5/2=2.75

ASAP can somebody please tell me the steps for both problems, I will also give brainliest (please list all the steps i have to show my work

Answers

The answer to #11 is: x = 15

The answer to #12 is: x = 5

prove that
{(tanθ+sinθ)^2-(tanθ-sinθ)^2}^2 =16(tanθ+sinθ)(tanθ-sinθ)

Answers

First, expand the terms inside the bracket you will get

[tex](( \tan {}^{2} (x) + 2 \tan(x) \sin(x) + \sin {}^{2} (x) - ( \tan {}^{2} (x) - 2 \tan(x) + \sin {}^{2} (x) ) {}^{2} = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )[/tex]

[tex]( 4 \tan(x) \sin(x) ) {}^{2} = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )[/tex]

[tex]16 \tan {}^{2} (x) \sin {}^{2} (x) = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )[/tex]

[tex]16 \tan {}^{2} (x) (1 - \cos {}^{2} (x) ) = 16 (\tan(x) + \sin(x) )( \tan(x) - \sin(x) )[/tex]

[tex]16( \tan {}^{2} (x) - \frac{ \sin {}^{2} (x) \cos {}^{2} ( {x}^{} ) }{ \cos {}^{2} (x) } [/tex]

[tex]16( \tan {}^{2} (x) - \sin {}^{2} (x) ) = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )[/tex]

[tex]16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )[/tex]

The stem-and-leaf plot shows the number of digs for the top 15 players at a volleyball tournament.



Find the mean, median, mode, range, and interquartile range of the data. Round your answers to the nearest tenth, if necessary.


The mean is.


The median is.


The modes from least to greatest are , , and.


The range is.


The interquartile range is.














Answers

The data of players of volleyball tournament, the mean is 56.5, median is 53, range is 56 and interquartile range is 20

What is mean, median and mode of a data set?

The mean of the data is the average value of the given data. The mean of the data is the ratio of the sum of all the values of data to the total number of values of data.

The median of the data is the middle value of the data set when it arrange in ascending or descending order.

Mode of a data set is the value, which occurs most times for that data set. The value which has the highest frequency in the given set of data is known as the mode of that data set.

The stem-and-leaf plot shows the number of digs for the top 15 players at a volleyball tournament. The table is attached below.

The data according to the table is,

41,41,43,43,45,50,52,53,54,62,63,63,67,75,97

The mean is-

[tex]\mu=\dfrac{41+41+43+43+45+50+52+53+54+62+63+63+67+75+97}{15}\\\mu=\dfrac{849}{15}\\\mu=56.5[/tex]

The median is.

The arranged data according to the table is,

41,41,43,43,45,50,52,53,54,62,63,63,67,75,97

Here, the middle value is 53. Thus, the median is 53.

The modes from least to greatest are , , and.

Mode is the data which occur most offen. Here the order of modes from least to greatest is,

41   41   43   43   45   50   52   53   54   62   63   63   67   75   97  

The range is.

Lowest value in data is 41 and highest is 97. Thus, the range is,

[tex]r=97-41\\r=56[/tex]

The interquartile range is.

The third quartile of data is 63 while first quartile is 43. Thus, the interquartile range is.

[tex]IQR=63-23\\IQR=20[/tex]

Thus, the data of players of volleyball tournament, the mean is 56.5, median is 53, range is 56 and interquartile range is 20.

Learn more about the mean, median and mode here;

https://brainly.com/question/14532771

#SPJ1

Please help me! No bots or trolls please!

Answers

Answer:

part: 17 players = 1/4

whole: 68 players in all

percent: 17 players = 25%

Step-by-step explanation:

We'll use p as a variable for the total players, alright?

So, 25% of p usually gets called back.

This season, 17 is 25% of p OR you might say 17 = 1/4 of p

in other words, p/4 = 17

multiply each side by 4 (to get the variable alone)

p = 17 * 4

p = 68

______________

part/whole = percent/100

SUBSTITUTE!

17/68 = 25%

check!

(simplify) 1/4 = 25% true!

please help me out on this question

Answers

Answer:

the train won't always go the same distance each minute and for the second one its 4 minutes

Before he moved, Chet was a student at
this school, If you include Chet's ant farm in
the data, the median is 8. How many ants
does Chet's ant farm have? Explain your
reasoning

Answers

The number of ants that Chet's ant farm have based on the median given is 96 ants.

How to calculate the number ants?

Your information is incomplete. Therefore, the numbers will be assumed. Let's assume that the numbers of ants in each column is 12.

In this case, when Chet's ant farm in the data, the median is 8. Therefore, the number of ants will be:

= 12 × 8

= 96 ants.

Learn more about median on:

https://brainly.com/question/26151333

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When Sarah divided a number by 5, the quotient was 147 with a remainder. What is one possible dividend? With a complete sentence, explain how you found the dividend.

Answers

Answer: possible dividend is 736, 737, 738, 739

Step-by-step explanation: The remainder cannot be divided by 5 so it can be 1, 2, 3 and 4 added to (147 ×5)

At Michael's school, 38% of the students have a pet dog and 24% of the students have a pet cat. Michael found that 11% of the students
had both a pet dog and a pet cat.
What is the probability that a randomly chosen student at Michael's school will have a pet dog or a pet cat?
A. 62%
B. 51%
C. 40%
D. 83%

Answers

I find it easiest to draw a venn-diagram for this kind of question but the answer isn’t too complicated.
11% of the students have a pet dog AND a pet cat. Because of this you want to take away 11% from the percentage of students with a pet dog and also from the percentage with a pet cat. This is because 11% of the students with a pet dog also have a pet cat and vice-versa and you don’t want to count any students twice.
Once you’ve done this it’s very simple, just add up your values, so 11 + (38 - 11) + (24 - 11) which will give you 51.
Hope this helps

Answer: C. 51%

Step-by-step explanation:

2. For a simple interest rate of 10%, p.a calculate the number of year's needed for an interest of $1149.60 to be earned on an investment of $2874​

Answers

Answer:

r=10%

I=1149.60

P=2874

t=(I×100)/(p×r)

(1149.60×100)/(2874×10)

114960÷28740

4 years

given:

[tex]r = 10\%[/tex]

[tex]p = 2874[/tex]

[tex]l = 1149.60[/tex]

to find:

the numbers of year's needed for the investment.

solution:

[tex]t = \frac{l \times 100}{p \times r} [/tex]

[tex]t = \frac{1149.60 \times 100}{2874 \times 10} [/tex]

[tex]t = \frac{114960}{28740} [/tex]

[tex]t = 4[/tex]

therefore, 4 years is needed for the investment.

what is the substance of 0.03 in scientific notation

Answers

Answer:

3x10 to the power of -2

Step-by-step explanation:

0.03=3x0.01

0.01=10 to the power of -2

what is 7.364.51 to 3 decimal places

Answers

Answer:

7.265

Step-by-step explanation:

Answer:

7.364

Step-by-step explanation:

Thats my answer.Brainliest

You roll a die 60 times how many times do you expect to roll a factor of 12

Answers

Answer:

Just for fun, the probability of rolling a die 60 times and getting no ones is

(600)(5/6)60=0.0018% .

Step-by-step explanation:

This 10 ones is the value with the highest probability of occurring. It has a probability of  (6010)(1/6)10∗(5/6)50≈13.7% .

Tyler applied the change of base formula to a logarithmic expression. The resulting expression is shown below.

StartFraction log one-fourth Over log 12 EndFraction

Which expression could be Tyler’s original expression?
Log Subscript one-fourth Baseline 12
Log Subscript 12 Baseline One-fourth
12 Log one-fourth
One-fourth log 12

Answers

Answer:

[tex]log_{12}(\frac{1}{4})[/tex]

Step-by-step explanation:

We start with our equation that the change of base formula was applied to:

[tex]\frac{log\frac{1}{4} }{log12}[/tex]

The change of base formula describes taking the base (b) of the logarithm and setting it as the denominator while taking the remaining number (a) and setting that as the numerator.

If we reverse the formula, we end up with the supplied answer.  

[tex]log_{12}(\frac{1}{4})[/tex]

Answer:

Other guy is correct

Step-by-step explanation:

What set of numbers are shaded on the
hundred chart?
A only the factors of ten
B only the multiples of 10
C only the factors of 20
D only the multiples of 20

Answers

I’m pretty sure it’s D

I need help with 19

Answers

Answer: 5/26

Step-by-step explanation:Hope this is helpful

5/26 is the answer i think

In this problem you will compare the effects of different compounding periods on the interest an investment earns. Complete the table below using the values indicated. Show the formula you used, with the correct values, in the second column. In the third column, give the result, rounded to the nearest cent.

Principal: $1,000
APR: 4.5%
Time: 10 years

Find the equations for annually, quarterly, monthly and daily

Answers

Answer:

  see attached

Step-by-step explanation:

You are asked to use the compound interest formula for different values of n, the number of times per year the interest is compounded.

__

The basic formula is ...

  A = P(1 +r/n)^(nt)

for the amount in an account in which principal P earns interest at annual rate r compounded n times per year for t years.

The problem statement gives values for P, r, t, so we only need to compute the result for different values of n. With the given values filled in, the formula is ...

  A = 1000(1 +0.045/n)^(10n)

Values of n to be used are ...

annually: n = 1quarterly: n = 4monthly: n = 12daily: n = 365

The formula you will evaluate uses these values where 'n' is in the formula. Corresponding account balances are ...

annual compounding: $1552.97quarterly compounding: $1564.38monthly compounding: $1566.99daily compounding: 1568.27

__

For repetitive evaluation of the same formula, we like a calculator or spreadsheet. Many calculators have the "time value of money" formulas pre-programmed. This is shown in the second attachment, where the value that varies is "C/Y", the number of compoundings per year.

What is the coefficient of the term x^2 when the expression below is simplified? (5x^2-x-1)-(-3x^2-2x-5)

Answers

Answer: 8

Step-by-step explanation:

     Given:

(5x^2-x-1)-(-3x^2-2x-5)

     Rewrite:

(5x² -x -1) - (-3x² -2x -5)

     Distribute the negative:

5x² -x -1 + 3x² +2x +5

     Reorder terms:

5x² + 3x² -x +2x -1 +5

     Combine like terms:

8x² + x + 4

   The coefficient of the x² term is 8,

8x² + x + 4

Show your work step by step

Answers

Answer: Given that MP \\NS , RS\\PQ and MR =NQ

MRN is a straight line with sum of angles equal to 180⁰ MQN is also a straight line triangle equal to 180⁰

Angle at R + 3 = Angle at Q +2 = 180⁰

Angle R is alternate to Q and angle 2 is alternate to 3 and both sets are equal

Therefore angle 1 is equal to 4 and this makes their third angles in the triangle equal.

Triangle MQP then becomes a perfect replica of NRS

Step-by-step explanation:

An oil can is shaped like a cylinder. The radius of the oil can is 3.5 inches and its height is 10 inches. Which measurement is closest to the volume of the oil can in cubic inches? 109.9 in³ 219.8 in³ 384.8 in³ 1099 in³

Answers

Answer:

384.8 cubic inches.

Step-by-step explanation:

HELP PLSS
Select all of the expressions that are equivalent to 7c.
A c + 3(c + c)
B 2(c + c) +c
C 3c + 4c + c
D 2c + 4c + c
E c (2c + 2c)

Answers

Answer:

D 2c + 4c + c

Step-by-step explanation:

Collect Coefficients of like terms

[tex](2+4+1)\times c[/tex]

__________________________________________________

Calculate the sum or difference

[tex]7c[/tex]

__________________________________________________

Determine true/false

[tex]Determine\ whether\ 7c\ and\ 2c+4c+c\ are equivalent:[/tex]

[tex]True[/tex]

I hope this helps you

:)

.Answer:
Choices A and D =7c
Explanation:
I’ve attached my work..
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