Small roads with lower speed limits are known as:
O A. interstate highways.
O B. secondary roads.
C. streets
O D. county roads.​

Answer:

3√6

Step-by-step explanation:

tan60=opp/adj

opp(d)=tan60*3√2=√3*3√2=3√6

Answer:

32.8 cm

Step-by-step explanation:

decagons have 10 sides, so 328/10=32.8

Answer:

32.8 cm

Step-by-step explanation:

A regular decagon has 10 equal sides.

The perimeter of the decagon is 328 centimeters. The perimeter is the measure of all 10 sides added together. Since this is a regular decagon, all 10 sides are equal. Therefore, we can divide 328 by 10.

328 / 10

32.8

Add units, in this case, centimeters or cm.

32.8 cm

Each side of the decagon is 32.8 centimeters.

Answer:

1024

Step-by-step explanation:

so first you would do 2^10 and 2^20

2^10 = 1024

2^20 = 1048576

then you would just divide 1048576 by 1024

1048576 / 1024 = 1024

Answer:

Y= 2/3x +(5/3)

Step-by-step explanation:

First, have to get Y alone on one side 3y=2x+5

Second, have to get read of the 3 with the Y so divide each side by three.

Answer:

1

Step-by-step explanation:

If y=x, than the only way

y=rx can be possible is if r=1

Hope this helps!

Have a good day! :)

Answer:

1

Step-by-step explanation:

y = rx

Use any set of x and y-coordinates in the equation and solve for r.

For example, use (5.8, 5.8).

5.8 = r(5.8)

Divide both sides by 5.8:

r = 1

Answer: r = 1

Answer:

C - LA = 2πrh

Step-by-step explanation:

Lateral surface area of right cylinder = 2 * π * radius * height

Answer:

Hey there!

Marked down by 20 percent is equal to 80 percent of the original value.

4.5(0.8)=3.6

9 percent sales tax

3.6(1.09)=3.92

Hope this helps :)

Answer:

$3.92

Step-by-step explanation:

I took the test

Answer:

AC = EF

Step-by-step explanation:

ABC = DEF

You would need to know that AC = EF

In the first place, using deduction we know that we dont need another angle. We also know that BC does not equal DF by looking at the angles on the triangles.

The solution is : ∠C ≅ ∠F is congruent to show that ΔABC ≅ ΔDEF, else would need to be congruent to show that AABC= ADEF by the AAS theorem.

The angle-angle-side theorem, or AAS, tells us that if two angles and a non-included side of one triangle are congruent to two angles and a non-included side of another triangle, then the triangles are congruent.

here, we have,

to find congruency in a triangle:

ΔABC ≅ ΔDEF

Therefore,

AAS congruence rule or theorem states that if two angles of a triangle with a non-included side are equal to the corresponding angles and non-included side of the other triangle, they are considered to be congruent.

Therefore,

∠C ≅ ∠F

Hence, The solution is : ∠C ≅ ∠F is congruent to show that ΔABC ≅ ΔDEF, else would need to be congruent to show that AABC= ADEF by the AAS theorem.

learn more on AAS here:

brainly.com/question/2699309

#SPJ7

Answer:

x = -3 , x = 1

Step-by-step explanation:

Hello,

you need to draw the graph of the two functions and then find the intersection points.

please see below

So the solution is the two points A and B

(-3,9) and (1,1)

Hope this helps

Answer:

A. 3

Step-by-step explanation:

ΔDEC is bigger than ΔABC by 5. For the hypotenuse, 25 is 5 times bigger than 5.

So, side DE on ΔDEC has to be 5 times bigger than side AB on ΔABC.

If side AB equals 3, side DE equals 18 - 3, which is 15.

15 is five times bigger than 3, so the answer is A. 3.

Hope that helps.

Answer:

1/3

Step-by-step explanation:

There are three elements that are intersecting: 5, 14, 22

Probability of choosing an item is 1/3

Answer:

Option B is the correct option.

Step-by-step explanation:

[tex] {(4 - 2)}^{3} - 3 \times 4[/tex]

Subtract the numbers

[tex] = {(2)}^{3 } - 3 \times 4[/tex]

Multiply the numbers

[tex] = {(2)}^{3} - 12[/tex]

Evaluate the power

[tex] = 8 - 12[/tex]

Calculate the difference

[tex] = - 4[/tex]

Hope this helps..

Best regards!!

Answer:

[tex]\boxed{-4}[/tex]

Step-by-step explanation:

[tex](4-2)^3-3 \times 4[/tex]

Brackets or parenthesis are to be evaluated first. Subtract the numbers in the brackets.

[tex](2)^3-3 \times 4[/tex]

Evaluate the power or exponent.

[tex]8-3 \times 4[/tex]

Multiply the numbers.

[tex]8-12[/tex]

Finally, subtract the numbers.

[tex]=-4[/tex]

Answer:

6 is the best estimate.

Step-by-step explanation:

(90/7) / (1 & 3/4) == (90/7) / (7/4) == (90/7) * (4/7) == 360/49 > 7.

Choose 6 as your best approximation.

Answer:

D

Step-by-step explanation:

What we need to do here is to calculate the required probability and convert to percentage

Firstly, we start by calculating the z-scores of the two boundary limits

Mathematically;

z-score = (x-mean)/SD

Form the question, we can see that the mean is 103 and the standard deviation is 11

so for 115, z-score would be

z-score = (115-103)/11 = 1.1

For 145, z-score would be

(145-103)/11 = 3.8

So the probability we want to calculate would be;

P(1.1<z<3.8)

We use the standard normal table for this

Mathematically;

P(1.1<z<3.8) = P(z<3.8) - P(z<1.1) = 0.13559

which to percentage is 13.559 %

The closest answer here is D

Answer:  3.2 yd

Step-by-step explanation:

Notice that TWV is a right triangle.  

Segment TU is not needed to answer this question.

∠V = 32°, opposite side (TW) is unknown, hypotenuse (TV) = 6

[tex]\sin \theta=\dfrac{opposite}{hypotenuse}\\\\\\\sin 32=\dfrac{\overline{TW}}{6}\\\\\\6\sin 32=\overline{TW}\\\\\\\large\boxed{3.2=\overline{TW}}[/tex]

Answer:

x = 6 and x = 11.

Step-by-step explanation:

sqrt(x - 2) + 8 = x

sqrt(x - 2) = x - 8

(sqrt(x - 2))^2 = (x - 8)^2

x - 2 = x^2 - 16x + 64

x^2 - 16x + 64 = x - 2

x^2 - 17x + 66 = 0

We can use the discriminant to find whether there are solutions to the equation.

b^2 - 4ac; where a = 1, b = -17, and c = 66.

(-17)^2 - 4 * 1 * 66

= 289 - 264

= 25

Since the discriminant is positive, we know there are two valid solutions to the equation.

x^2 - 17x + 66 = 0

(x - 6)(x - 11) = 0

The solutions are when x - 6 = 0 and x - 11 = 0.

x - 6 = 0

x = 6

x - 11 = 0

x = 11

Hope this helps!

Answer:

x=11 solution

x=6 extraneous

Step-by-step explanation:

sqrt( x-2) + 8 = x

Subtract x from each side

sqrt(x-2) = x-8

Square each side

(sqrt(x-2))^2 = (x-8) ^2

x-2 = x^2 -8x-8x+64

x-2  = x^2 -16x+64

Subtract ( x-2) from each side

0 = x^2 -17x +66

Factor

0 = (x-6) ( x-11)

Using the zero product property

x=6  x=11

Checking the solutions

x=6

sqrt( 6-2) + 8 = 6

sqrt(4) +8 = 6

2 +8 = 6

False  not a solution

x=11

sqrt( 11-2) + 8 = 11

sqrt(9) +8 =11

3 +8 = 11

solution

Answer:

Step-by-step explanation:

Given the expression 1/6.43 +2/3.56 +1/8.51, If 'a' is a number, the reciprocal of such number is 1/a. According to the question, the reciprocal of 6.43, 3.56 and 8.51 are  1/6.43 and 1/3.56 and 1/8.51 respectively.

1/6.43 = 0.1555

2/3.56 = 2 * 1/3.56

= 2 * 0.2809

= 0.5618

1/8.51 = 0.1175

Taking the sum of the reciprocals;

1/6.43 +2/3.56 +1/8.51 = 0.1555 + 0.5618 + 0.1175

1/6.43 +2/3.56 +1/8.51 = 0.8348

Hence, the sum of 1/6.43, 2/3.56 and 1/8.51 is 0.8348

Answer: x = -12

Step-by-step explanation:

-1/2x=6

Divide by -1/2

x = -12

Hope it helps <3

Answer:

a) -900 L/min

b) 63000 L

c)  -900t +63000

 d) 7200 L

Step-by-step explanation:

a) You are given two points on the curve of volume vs. time:

(t, V) = (20, 45000) and (70, 0)

The rate of change of volume

= ΔV/Δt = (0 -45000)/(70 -20) = -45000/50 = -900 liters per minute

b) In the first 20 minutes, the change in volume was

(20 min)(-900 L/min) = -18000 L

So, the initial volume was

initial volume - 18000 = 45000

initial volume = 63,000 liters

c) Since we have the slope and the intercept, we can write the equation in slope-intercept form as

 V= -900t +63000.

d) now putting the number in the equation and do the arithmetic.

When t=62, the amount remaining is

= -900(62) +63000 = -55800 +63000 = 7200

Thus, 7200 L remain after 62 minutes.

Answer:

[tex]V = \frac{1}{3} (\pi \cdot 10^2 \cdot 16) \\\\V = \frac{1}{3} (1600 \pi ) \\\\V = 1675.52 \: m^3[/tex]

The maximum amount of sand that can be stored in this structure is 1675.52 m³.

Step-by-step explanation:

The volume of a conical-shaped structure is given by

[tex]V = \frac{1}{3} (\pi \cdot r^2 \cdot h)[/tex]

Where r is the radius and h is the height of the structure.

We are given that

radius = 10m

height = 16m

Substituting the above values into the formula, we get

[tex]V = \frac{1}{3} (\pi \cdot 10^2 \cdot 16) \\\\V = \frac{1}{3} (1600 \pi ) \\\\V = 1675.52 \: m^3[/tex]

Therefore, the maximum amount of sand th can be stored in this structure is 1675.52 m³.

Answer:

-2

Step-by-step explanation:

The slope formula is

m = ( y-2-y1)/(x2-x1)

Using two points on the line  (0,4) and  (2,0)

m = ( 0-4)/(2-0)

   = -4/2

  =-2

Answer:

-2

Step-by-step explanation:

Slope is change in y over change in x

the change in y is -2 and the change in x is 1 so you do -2/1 and that as a whole number is -2.

Answer:

11 /13 = t

Step-by-step explanation:

5/13  = t -6/13

Add 6/13 to each side

5/13 + 6/13  = t -6/13+ 6/13

11 /13 = t

Answer:

[tex]t=\frac{11}{13}[/tex]

Step-by-step explanation:

[tex]\frac{5}{13} = t -\frac{6}{13}[/tex]

Add [tex]\frac{6}{13}[/tex] to both sides.

[tex]\frac{5}{13} + \frac{6}{13} = t -\frac{6}{13} + \frac{6}{13}[/tex]

[tex]\frac{11}{13} =t[/tex]

x^2+y^2-12x+6y+36=0

Top Point: (6,0)

Left Point: (3,-3)

Right Point: (9,-3)

Bottom Point: (6,-6)

Answer:

[tex] x^2 +y^2 -12x +6y +36 =0[/tex]

And we can complete the squares like this:

[tex] (x^2 -12x +6^2) + (y^2 +6y +3^2) = -36 +6^2 +3^2[/tex]

And we got:

[tex] (x-6)^2 + (y+3)^2 = 9[/tex]

And we have a circle with radius r =3 and the vertex would be;

[tex] V= (6,-3) [/tex]

The graph is on the figure attached.

Step-by-step explanation:

For this case we have the following expression:

[tex] x^2 +y^2 -12x +6y +36 =0[/tex]

And we can complete the squares like this:

[tex] (x^2 -12x +6^2) + (y^2 +6y +3^2) = -36 +6^2 +3^2[/tex]

And we got:

[tex] (x-6)^2 + (y+3)^2 = 9[/tex]

And we have a circle with radius r =3 and the vertex would be;

[tex] V= (6,-3) [/tex]

The graph is on the figure attached.

Answer:

1. [tex]27^{\frac{2}{3} } =9[/tex]

2. [tex]\sqrt{36^{3} } =216[/tex]

3. [tex](-243)^{\frac{3}{5} } =-27[/tex]

4. [tex]40^{\frac{2}{3}}=4\sqrt[3]{25} =4325[/tex]

5. Step 4: [tex](\frac{343}{27}) ^{-1} =\frac{27}{343}[/tex]

6. [tex]D. -72cd^{7}[/tex]

Step-by-step explanation:

Use the following properties:

[tex]a^{\frac{x}{y} } =\sqrt[x]{a^{y} }[/tex]

[tex]\sqrt[n]{ab} =\sqrt[n]{a} \sqrt[n]{b}[/tex]

[tex]a^{-n} =\frac{1}{a^{n} }[/tex]

[tex](xy)^{z} =x^{z} y^{z} \\\\[/tex]

[tex](x^{y}) ^{z} =x^{yz}[/tex]

[tex]x^{y} x^{z} =x^{y+z}[/tex]

So:

1. [tex]27^{\frac{2}{3} } =\sqrt[3]{27^{2}} =\sqrt[3]{729} }=9[/tex]

2. [tex]\sqrt{36^{3} } =\sqrt{36*36*36} =\sqrt{36} \sqrt{36} \sqrt{36} =6*6*6=216[/tex]

3. [tex](-243)^{\frac{3}{5} } =\sqrt[5]{-243^{3} } =\sqrt[5]{-14348907} =-27[/tex]

4. [tex]40^{\frac{2}{3}}=\sqrt[3]{40^{2} } =\sqrt[3]{2^{6} 5^{2} } =\sqrt[3]{2^{6} } \sqrt[3]{5^{2} } =2^{\frac{6}{3} } 5^{\frac{2}{3} } =4 *5^{\frac{2}{3} } =4\sqrt[3]{5^{2} } =4\sqrt[3]{25}=4325[/tex]

5. [tex](\frac{343}{27}) ^{-1} =\frac{1}{\frac{343}{27} } =\frac{27}{343}[/tex]

6.

[tex](-8c^{9} d^{-3} )^{\frac{1}{3} } *(6c^{-1}d^{4})^{2} =\sqrt[3]{-8} c^{3} d^{-1} 36c^{-2} d^{8} \\\\-2c^{3} d^{-1} 36c^{-2} d^{8}=-72cd^{7}[/tex]

Answer:

37.8 m

Step-by-step explanation:

The computation of the distance is shown below:

In triangle ADE

[tex]AD^2 = AE^2 + DE^2 \\\\ AD^2 = 5^2 + 3^2 \\\\ AD^2 = 34[/tex]

AD = 5.8

Now the distance walked after completing his edging is

Distance = AD + AB + BC + CD

= 5.8 + 12 + 5 + 15

= 37.8 m

We simply added these four sides so that the correct distance could arrive

Hence, the distance walked after completing his edging is 37.7

so first day and so on

7, 10, 13,....

as you can see it's an arithmetic progression

so sum for nth term= n/2 { 2a + (n-1) d}

it's the sum of the 7th term

so

7/2 { 7 ×2 + ( 7-1) 3}

7/2 × 32

7× 16

112 fishes

Answer:

I think the answer is 25

Step-by-step explanation:

Answer:

3x^2 + 3/2 x -9

Step-by-step explanation:

f(x) = x/2 -3

g(x) =3x^2 +x -6

(f+g) (x) =  x/2 -3 + 3x^2 +x -6

   Combine like terms

            = 3x^2 + x/2 +x -3-6

              = 3x^2 + 3/2 x -9

Answer: Zak - Resp after 24 months = $4,344.00

              Zak - Technology Fund after 24 months = $1,102.98

              Zak's Technology Fund has enough money to buy a laptop.

              Zak's Savings (Resp) will last less than 6 months

Step-by-step explanation for Zak:

January - June 2019

$15/hr x 20 hr x 4 wks x 6 months = $7200 Gross Income

Taxable Income is $7200 - $1080 = $6120    (Annual Income $12,240)

→ $7,200 - ($1080 + $360 + $144 + $0 + $129.60) = $5,486.40 Net Income

Tech Fund (5%): $5486.40(0.05) = $274.32

Food Expense (30%): $5486.40(0.3) = $1,645.92

Clothing Expense (30%): $5486.40(0.3) = $1,645.92

Entertainment Expense (25%): $5486.40(0.25) = $1,371.60

Miscellaneous Expense (10%): $5486.40(0.1) = $548.64      

                                               Other Expenses: $5,212.08

July - December 2019 (excluding August)

$16/hr x 20 hr x 4 wks x 5 months = $6400 Gross Income

Taxable Income is $6400 - $960 = $5440    (Annual Income $11,560)

→ $6,400 - ($960 + $320 + $128 + $0 + $75.20) = $4,916.80 Net Income

Tech Fund (5%): $4916.80(0.05) = $245.84

Food Expense (30%): $4916.80(0.3) = $1,475.04

Clothing Expense (30%): $4916.80(0.3) = $1,475.04

Entertainment Expense (25%): $4916.80(0.25) = $1,229.20

Miscellaneous Expense (10%): $4916.80(0.1) = $491.68      

                                              Other Expenses: $4,670.96

January - June 2020

$17/hr x 20 hr x 4 wks x 6 months = $8160 Gross Income

Taxable Income is $8160 - $1224 = $6936    (Annual Income $13,872)

→ $8,160 - ($1224 + $408 + $163.20 + $0 + $194.88) = $6,169.92 Net Income

Tech Fund (5%): $6169.92(0.05) = $308.50

Food Expense (30%): $6169.92(0.3) = $1,850.98

Clothing Expense (30%): $6169.92(0.3) = $1,850.98

Entertainment Expense (25%): $6169.92(0.25) = $1,542.48

Miscellaneous Expense (10%): $6169.92(0.1) = $616.98      

                                               Other Expenses: $5,861.42

July - December 2020 (excluding August)

$18/hr x 20 hr x 4 wks x 5 months = $7200 Gross Income

Taxable Income is $7200 - $1080 = $6120    (Annual Income $13,056)

→ $7,200 - ($1080 + $360 + $144 + $0 + $129.60) = $5,486.40 Net Income

Tech Fund (5%): $4916.80(0.05) = $274.32

Food Expense (30%): $5486.40(0.3) = $1,645.92

Clothing Expense (30%): $5486.40(0.3) = $1,645.92

Entertainment Expense (25%): $5486.40(0.25) = $1,371.60

Miscellaneous Expense (10%): $5486.40(0.1) = $548.64      

                                              Other Expenses: $5,212.08

[tex]\boxed{\begin{array}{l|r|r|r|r||r}\underline{ZAK}&\underline{Jan-Jun'19}&\underline{Jul-Dec'19}&\underline{Jan-Jun'20}&\underline{Jul-Dec'20}&\underline{Totals\quad }\\Gross&\$7200.00&\$6400.00&\$8160.00&\$7200.00&\$28960.00\\Resp&\$1080.00&\$960.00&\$1224.00&\$1080.00&\$4344.00\\Net&\$5486.40&\$4916.80&\$6169.92&\$5486.40&\$22059.52\\Other&\$5212.08&\$4670.96&\$5861.42&\$5212.08&\$20956.54\\Tech&\$274.32&\$245.84&\$308.50&\$274.32&\$1102.98\end{array}}[/tex]

Answer:

The unit price at the village market is 2.80 / 5 = 0.56 and the unit price at Sam's Club is 4.90 / 10 = 0.49. Since 0.49 < 0.56, the answer is Sam's Club.

Answer: Sam's club

Step-by-step explanation:

Because 10/2 = 5, at Sam's club you get twice the beans.  Thus, simply multiply 2.8*2 = 5.60.  Because $5.60>$4.90, the village market is the worse place to buy.

Answer:

Examine the system of equations.

–2x + 3y = 6

–4x + 6y = 12

Answer the questions to determine the number of solutions to the system of equations.

What is the slope of the first line?  

✔ 2/3

What is the slope of the second line?  

✔ 2/3

What is the y-intercept of the first line?  

✔ 2

What is the y-intercept of the second line?  

✔ 2

How many solutions does the system have?  

✔ infinitely many

The equations are a multiple of the other, therefore, by the multiplicative

property of equality, the equations are equivalent.

Response:

The given system of equations are;

-2·x + 3·y = 6

-4·x + 6·y = 12

Required:

The slope of the first line.

Solution:

The slope of the first line is given by the coefficient of x when the equation is expressed in the form; y = m·x + c.

Therefore, from -2·x + 3·y = 6, we have;

3·y = 2·x + 6

[tex]y = \dfrac{2}{3} \cdot x + \dfrac{6}{3} = \dfrac{2}{3} \cdot x + 2[/tex]

[tex]y =\dfrac{2}{3} \cdot x + 2[/tex]

[tex]\underline{The \ slope \ of \ the \ first \ equation \ is \ \dfrac{2}{3}}[/tex]

Required:

The slope of the second line;

Solution:

The equation of the second line, -4·x + 6·y = 12, can be expressed in the form;

[tex]y =\dfrac{4}{6} \cdot x + \dfrac{12}{6} = \dfrac{2}{3} \cdot x + 2[/tex]

[tex]y = \mathbf{\dfrac{2}{3} \cdot x + 2}[/tex]

[tex]\underline{The \ slope \ of \ the \ second \ equation \ is \ therefore \ \dfrac{2}{3}}[/tex]

Given that the equation have the same slope and the same y-intercept, the equations are equations of the same line, therefore;

Learn more about the solutions of a system of equations here:

https://brainly.com/question/15356519