Answer:
b^8
Step-by-step explanation:
When multiplying exponents with the same base, we can add the exponents
b^2 * b^6
b^ (2+6)
b^8
Answer:b8 x
Step-by-step explanation:
Changes made to your input should not affect the solution:
(1): "b6" was replaced by "b^6". 1 more similar replacement(s).
STEP
1
:
Multiplying exponential expressions
1.1 b2 multiplied by b6 = b(2 + 6) = b8
Final result :
b8x
According to the graph, what is the domain and range of the function?
Answer:
if its according to the graph but not according to the function then
domain = {x:-4<x<8}
range = {y:y<16}
Graph y=0.4x............................
Answer:
Look at the image below
41 points * please help Write a linear equation - wil give brainlyist to first person
Answer:
C = 38n + 1750; 15,050
Step-by-step explanation:
We know that for each person, there's a fee of 38. That signifies that the n will be after 38. 1,750 is a one-time fee, so that's by itself. Plug it into the equation to get your first answer. Now, solve for b) by writing C = 38(350) + 1750; C = 15,050
Answer:
C = 38n + 1750; 15,050
Step-by-step explanation:
brainlist plzzzzzz
A school counselor surveyed 90 randomly selected students about thé langages they speak. Of thé students surveyed 16 speak more than one langage fluently. Bases on thèse résults, How many of thé 1800 students at thé school can be expected to speak more than one langage fluently
Answer: 320 students
Step-by-step explanation:
From the question, we are informed that a school counselor surveyed 90 randomly selected students about thé langages they speak and thé students surveyed 16 speak more than one langage fluently. This means that 16/90 speak more than one language.
When 1800 students are surveyed, the number of students that can be expected to speak more than one langage fluently will be:
= 16/90 × 1800
= 16 × 20
= 320 students
The Venn diagram shows the results of two events resulting from rolling a number cube.
Answer:
Option B.
Step-by-step explanation:
From the given venn diagram it is clear that
[tex]A={1,2}[/tex]
[tex]B={1,2,3,4,5,6}[/tex]
[tex]A\cap B={1,2}[/tex]
Since the intersection of A and B is non-empty, therefore by conditional probability
[tex]P(B|A)=\dfrac{P(A\cap B)}{P(A)}[/tex]
[tex]P(B|A)\cdot P(A)=P(A\cap B)[/tex]
[tex]P(A\cap B)=P(B|A)\cdot P(A)[/tex]
Therefore, the correct option is B.
On a number line, a number, b, is located the same distance from 0 as another number, a, but in the opposite direction. The number b varies directly with the number a. For example b = 2 3/4 when a = -2 3/4 . Which equation represents this direct variation between a and b?
Answer:
b=-a
Step-by-step explanation:
What is the length of the line?
Answer:
[tex]\boxed{\sqrt{37} }[/tex]
Step-by-step explanation:
Use Pythagorean theorem.
Create a right triangle, with legs of length 6 and 1 units. Find the length of hypotenuse.
[tex]6^2+1^2 =c^2 \\36+1=c^2 \\37=c^2 \\c=\sqrt{37}[/tex]
Answer:
When you use Pythagorean theorem, the answer is √37.
Step-by-step explanation:
Answer.. Plz!! 1rst one .BRAINLIEST!
Answer:
a) [tex]\boxed{4m^2+20m+25}[/tex]
b) [tex]\boxed{m^2-m+\frac{1}{4} }[/tex]
Step-by-step explanation:
a) [tex](2m+5)^2[/tex]
Using formula [tex](a+b)^2 = a^2+2ab+b^2[/tex]
=> [tex](2m)^2 + 2(2m)(5)+(5)^2[/tex]
=> [tex]4m^2+20m+25[/tex]
b) [tex](m-\frac{1}{2} )^2[/tex]
Using Formula [tex](a-b)^2 = a^2-2ab+b^2[/tex]
=> [tex](m)^2 - 2(m)(\frac{1}{2} ) + (\frac{1}{2} )^2[/tex]
=> [tex]m^2-m+\frac{1}{4}[/tex]
Answer:
a) [tex]\boxed{4m^2 + 20m + 25}[/tex]
b) [tex]\boxed{m^2 - m + \frac{1}{4} }[/tex]
Step-by-step explanation:
[tex](2m + 5)^2[/tex]
[tex](2m + 5) (2m + 5)[/tex]
Use FOIL method.
[tex]2m(2m + 5)+5(2m + 5)[/tex]
[tex]4m^2 + 10m + 10m + 25[/tex]
[tex]4m^2 + 20m + 25[/tex]
[tex](m - \frac{1}{2} )^2[/tex]
[tex](m- \frac{1}{2})(m- \frac{1}{2})[/tex]
Use FOIL method.
[tex]m(m- \frac{1}{2})- \frac{1}{2}(m- \frac{1}{2})[/tex]
[tex]m^2- \frac{1}{2} m- \frac{1}{2}m+ \frac{1}{4}[/tex]
[tex]m^2-m+ \frac{1}{4}[/tex]
Students were surveyed about their preference between dogs and cats. The following two-way table displays data for the sample of students who responded to the survey. Preference Male Female TOTAL Prefers dogs 36 20 56 Prefers cats 10 26 36 No preference 2 6 8 TOTAL 48 52 100 Of students in the sample, what fraction were male?
Answer:
12/25
Step-by-step explanation:
There were a total of 48 males, so 48/100 = 12/25.
+---------------+------+--------+-------+
| | Male | Female | Total |
+---------------+------+--------+-------+
| Prefers Dogs | 36 | 20 | 56 |
+---------------+------+--------+-------+
| Prefers Cats | 10 | 26 | 36 |
+---------------+------+--------+-------+
| No Preference | 2 | 6 | 8 |
+---------------+------+--------+-------+
| Total | 48 | 52 | 100 |
+---------------+------+--------+-------+
WILL GIVE BRAINLIEST Find the value of x, rounded to the nearest degree. 26° 25° 28° 62°
Answer:
X rounded to the nearest degree can me calculated based on parallel lines or if there is a straight line bisected by a line, 180 degress is a staright line. There is not enough info nor a picture to give a direct answer.
Answer:
its D
Step-by-step explanation:
a blue dice and a green dice are rolled. Find the probability that the blue is either 1 or 2 and the green is 1.
Answer:
2
Step-by-step explanation:
green
Answer: 2
Step-by-step explanation:
Please give me correct answer and fast answer it if know answer only
Answer:
Approximatley 5.8 units.
Step-by-step explanation:
We are given two angles, ∠S and ∠T, and the side opposite to ∠T. We need to find the unknown side opposite to ∠S. Therefore, we can use the Law of Sines. The Law of Sines states that:
[tex]\frac{\sin(A)}{a}=\frac{\sin(B)}{b} =\frac{\sin(C)}{c}[/tex]
Replacing them with the respective variables, we have:
[tex]\frac{\sin(S)}{s} =\frac{\sin(T)}{t} =\frac{\sin(R)}{r}[/tex]
Plug in what we know. 20° for ∠S, 17° for ∠T, and 5 for t. Ignore the third term:
[tex]\frac{\sin(20)}{s}=\frac{\\sin(17)}{5}[/tex]
Solve for s, the unknown side. Cross multiply:
[tex]\frac{\sin(20)}{s}=\frac{\sin(17)}{5}\\5\sin(20)=s\sin(17)\\s=\frac{5\sin(20)}{\sin(17)} \\s\approx5.8491\approx5.8[/tex]
Consider the curve of the form y(t) = ksin(bt2) . (a) Given that the first critical point of y(t) for positive t occurs at t = 1 tells us that y '(0) = 1 y(0) = 1 y '(1) = 0 y(1) = 0 Given that the derivative value of y(t) is 3 when t = 2 tells us that y '(3) = 2 y '(0) = 2 y '(2) = 0 y '(2) = 3 (b) Find dy dt = kcos(bt2)·b2t (c) Find the exact values for k and b that satisfy the conditions in part (a). Note: Choose the smallest positive value of b that works.
Answer:
(a). y'(1)=0 and y'(2) = 3
(b). [tex]$y'(t)=kb2t\cos(bt^2)$[/tex]
(c). [tex]$ b = \frac{\pi}{2} \text{ and}\ k = \frac{3}{2\pi}$[/tex]
Step-by-step explanation:
(a). Let the curve is,
[tex]$y(t)=k \sin (bt^2)$[/tex]
So the stationary point or the critical point of the differential function of a single real variable , f(x) is the value [tex]x_{0}[/tex] which lies in the domain of f where the derivative is 0.
Therefore, y'(1)=0
Also given that the derivative of the function y(t) is 3 at t = 2.
Therefore, y'(2) = 3.
(b).
Given function, [tex]$y(t)=k \sin (bt^2)$[/tex]
Differentiating the above equation with respect to x, we get
[tex]y'(t)=\frac{d}{dt}[k \sin (bt^2)]\\ y'(t)=k\frac{d}{dt}[\sin (bt^2)][/tex]
Applying chain rule,
[tex]y'(t)=k \cos (bt^2)(\frac{d}{dt}[bt^2])\\ y'(t)=k\cos(bt^2)(b2t)\\ y'(t)= kb2t\cos(bt^2)[/tex]
(c).
Finding the exact values of k and b.
As per the above parts in (a) and (b), the initial conditions are
y'(1) = 0 and y'(2) = 3
And the equations were
[tex]$y(t)=k \sin (bt^2)$[/tex]
[tex]$y'(t)=kb2t\cos (bt^2)$[/tex]
Now putting the initial conditions in the equation y'(1)=0
[tex]$kb2(1)\cos(b(1)^2)=0$[/tex]
2kbcos(b) = 0
cos b = 0 (Since, k and b cannot be zero)
[tex]$b=\frac{\pi}{2}$[/tex]
And
y'(2) = 3
[tex]$\therefore kb2(2)\cos [b(2)^2]=3$[/tex]
[tex]$4kb\cos (4b)=3$[/tex]
[tex]$4k(\frac{\pi}{2})\cos(\frac{4 \pi}{2})=3$[/tex]
[tex]$2k\pi\cos 2 \pi=3$[/tex]
[tex]2k\pi(1) = 3$[/tex]
[tex]$k=\frac{3}{2\pi}$[/tex]
[tex]$\therefore b = \frac{\pi}{2} \text{ and}\ k = \frac{3}{2\pi}$[/tex]
The y'(1) =0, y'(2) = 3, and the [tex]\rm y'(t) = kb2t \ cos(bt^2)[/tex] and value of b and k are [tex]\pi/2[/tex] and [tex]3/2\pi[/tex] respectively.
It is given that the curve [tex]\rm y(t) = ksin(bt^2)[/tex]
It is required to find the critical point, first derivative, and smallest value of b.
What is a function?It is defined as a special type of relationship and they have a predefined domain and range according to the function.
We have a curve:
[tex]\rm y(t) = ksin(bt^2)[/tex]
Given that the first critical point of y(t) for positive t occurs at t = 1
First, we have to find the first derivative of the function or curve:
[tex]\rm y'(t) = \frac{d}{dt} (ksin(bt^2))[/tex]
[tex]\rm y'(t) = k\times2bt\times cos(bt^2)[/tex] [ using chain rule]
[tex]\rm y'(t) = kb2t \ cos(bt^2)[/tex]
y(0) = 0
y'(0) = 0
The critical point is the point where the derivative of the function becomes 0 at that point in the domain of a function.
From the critical point y'(1) = 0 ⇒ [tex]\rm kb2 \ cos(b) =0[/tex]
k and b can not be zero
[tex]\rm cos(b) = 0[/tex]
b = [tex]\rm \frac{\pi}{2}[/tex]
and y'(2) =3
[tex]\rm y'(2) = kb2\times 2 \times cos(b\times2^2) =3\\\\\rm 4kb \ cos(4b) =3[/tex](b =[tex]\rm \frac{\pi}{2}[/tex])
[tex]\rm 4k\frac{\pi}{2} \ cos(4\frac{\pi}{2} ) =3\\\\\rm2 \pi kcos(2\pi) = 3[/tex]
[tex]\rm2 \pi k\times1) = 3\\\rm k = \frac{3}{2\pi}[/tex]
Thus, y'(1) =0, y'(2) = 3, and the [tex]\rm y'(t) = kb2t \ cos(bt^2)[/tex] and value of b and k are [tex]\pi/2[/tex] and [tex]3/2\pi[/tex] respectively.
Learn more about the function here:
brainly.com/question/5245372
If a number is added to the numerator of StartFraction 11 Over 36 EndFraction and twice the number is added to the denominator of StartFraction 11 Over 36 EndFraction , the resulting fraction is equivalent to one third . Find the number.
Answer:
The number is 3
Step-by-step explanation:
The fraction is 11/36
let
x = no. added to the numerator
2x = no. added to denominator
We have,
x+11/2x+36=1/3
Cross multiply
3(x+11) = (2x + 36)
3x + 33 = 2x + 36
Collect like terms
3x - 2x = 36 - 33
x=3
The number is 3
Check:
3+11/6+36=1/3
14/42=1/3
Someone pls help me I’m struggling
Answer:
2850
Step-by-step explanation:
We know that only 19% of people prefer the sedans, so we have to find 19% of 15,000. Set up a proportion: [tex]\frac{19}{100}=\frac{x}{15000}[/tex], cross multiply and get 2850.
Answer:
2850 sedans per month
Step-by-step explanation:
19 % want sedans
They expect to sell 15000 cars
Take the number of cars and multiply by the percent sedans
19% * 15000
Change to decimal form
.19*15000
2850
Find the (a) mean, (b) median, (c) mode, and (d) midrange for the data and then (e) answer the given question. Listed below are the weights in pounds of 11 players randomly selected from the roster of a championship sports team. Are the results likely to be representative of all players in that sport's league? 293 255 264 240 190 295 199 184 293 205 199
Answer:
A.) Mean = 237.9
B.) Median = 240
C.) Mode = 199
D.) Midrange = 239.5
Step-by-step explanation:
The given data are :
293 255 264 240 190 295 199 184 293 205 199
The mean = (sum of X) / f
Where frequency f = 11
X = 293 + 255 + 264 + 240 + 190 + 295 + 199 + 184 + 293 + 205 + 199
X = 2617
Substitute X and f into the formula
Mean = 2617/11
Mean = 237.9 approximately
B.) To get the median, you need to first rearrange the data, then pick the middle number.
184 190 199 199 205 240 255 264 293 293 295
The median = 240
C.) The mode is the highest frequency. That is the most occuring number
Mode = the two most occuring numbers are 199 and 293
D.) Range = highest number - lowest number
But midrange = (highest number + lowest number ) ÷ 2
Highest number = 295
Lowest number = 184
Substitute into the formula
Midrange = (295 + 184)/2
Midrange = 479/2
Midrange = 239.5
on a number cube (numbered 1-6) what is the probability of rolling a 3?
Answer:
1
Step-by-step explanation:
There is only one 3 on the cube
(Sorry for the spam, making sure these are right) One zero of the polynomial function f(x)=x^3-9x^2+20x is x=0. What are the polynomial function? Choices:
Replace f(x) with 0 and solve for x. We do this because the x intercepts always occur when y = 0. Keep in mind that y = f(x).
f(x)=x^3-9x^2+20x
0=x^3-9x^2+20x
x^3-9x^2+20x = 0
x(x^2-9x+20) = 0 .... factor out GCF x
x(x-5)(x-4) = 0 ... factor the stuff inside
x = 0 or x-5 = 0 or x-4 = 0 ... zero product property
x = 0 or x = 5 or x = 4
The roots or zeros are 0, 5, 4Answer: Choice DThe shaded rectangle in the diagram consists ofthree squares. (Picture for full question)
Answer: 243 cm²
Step-by-step explanation: If the diameter is 18, the radius is 9. Each square is 9×9, so 81 cm² for each. Multiply: 81×3 = 243
Or take the length times width to get area 27×9= 243
write an equation for the translation of x^2 + y^2 = 49 by 7 units right and 4 units up
Answer:
(x - 7)² + (y - 4)² = 49
Step-by-step explanation:
Given
Equation: x² + y² = 49
Required:
New Equation when translated 7 units right and 4 units up
Taking it one step at a time.
When the equation is translated 7 units right, this implies a negative unit along the x axis.
The equation becomes
(x - 7)² + y² = 49
When the equation is translated 4 units up, this implies a negative unit along the y axis.
(x - 7)² + (y - 4)² = 49
The expression can be further simplified but it's best left in the form of
(x - 7)² + (y - 4)² = 49
Simplifying Rational Expressions: I need answers for both 7 and 8 below. Answers for just one or the other is also fine.
Answer:
1. Option A 2. Option DStep by step explanation
1. [tex] \frac{1}{1 - x} + \frac{x}{ {x}^{2} - 1} [/tex]
Use [tex] \frac{ - a}{b} = \frac{a}{ - b} = - \frac{a}{b} [/tex] to rewrite the fractions
[tex] - \frac{1}{x - 1} + \frac{x}{(x - 1)(x + 1)} [/tex]
Write all numerators above the Least Common Denominator ( X - 1 ) ( X + 1 )
[tex] \frac{ - (x + 1) + x}{(x - 1)(x + 1)} [/tex]
When there is a ( - ) in front of an expression in parentheses , change the sign of each term in the expression
[tex] \frac{ - x - 1 + x}{(x - 1)(x + 1)} [/tex]
Using [tex](a - b)(a + b) = {a}^{2} - {b}^{2} [/tex] , simplify the product
[tex] \frac{ - x - 1 + x}{ {x}^{2} - 1 } [/tex]
Since two opposites add up to zero, remove them from the expression
[tex] \frac{ - 1}{ {x}^{2} - 1} [/tex]
So, Option A is the right option.
___________________________________
2.
[tex] \frac{ {x}^{2} - x - 12}{ {x}^{2} - 16} - \frac{1 - 2x}{x + 4} [/tex]
Write - X as a difference
[tex] \frac{ {x}^{2} + 3x - 4x - 12 }{ {x}^{2} - 16 } - \frac{1 - 2x}{x + 4} [/tex]
Using [tex] {a}^{2} - {b}^{2} = (a - b)(a + b)[/tex] , factor the expression
[tex] \frac{ {x}^{2} + 3x - 4x - 12 }{(x - 4)(x + 4)} - \frac{1 - 2x}{x + 4} [/tex]
Factor the expression
[tex] \frac{x(x + 3) - 4(x + 3)}{(x - 4)(x + 4)} - \frac{1 - 2x}{x + 4} [/tex]
Factor out X+3 from the expression
[tex] \frac{(x + 3)(x - 4)}{(x - 4)(x + 4)} - \frac{1 - 2x}{x + 4} [/tex]
Reduce the fraction with x-4
[tex] \frac{x + 3}{x + 4} - \frac{1 - 2x}{x + 4} [/tex]
Write all the numerators above the common denominator
[tex] \frac{x + 3 - ( 1- 2x)}{x + 4} [/tex]
When there is a (-) in front of an expression in parentheses, change the sign of each term in the expression
[tex] \frac{x + 3 - 1 + 2x}{x + 4} [/tex]
Collect like terms
[tex] \frac{3x + 3 - 1}{x + 4} [/tex]
Subtract the numbers
[tex] \frac{3x + 2}{x + 4} [/tex]
Undefined at,
X + 4 = 0
Move constant to R.H.S and change its sign
[tex]x = 0 - 4[/tex]
Calculate
[tex]x = - 4[/tex]
So, the answer is :
[tex] \frac{3x + 2}{x + 4} [/tex] , undefined at X = -4 and 4
Hope this helps..
Best regards!!
In triangle $ABC$, $AB = BC = 25$ and $AC = 40$. What is $\sin \angle ACB$?
Answer:
Sine angle of <ACB = 38.68°
Step-by-step explanation:
Hello,
To solve this problem, we need a good representation of the sides and the angle.
See attached document for better illustration.
Assuming it's a right angled triangle,
AC = hypothenus
AB = opposite
BC = adjacent
AC = 40
BC = 25
AB = 25
From trigonometric ratios
Sinθ = opposite/ hypothenus
Sinθ = AB / AC
Sinθ = 25 / 40
Sinθ = 0.625
θ = sin⁻¹0.625
θ = 38.68°
Sine angle of <ACB = 38.68°
What is the value of the expression
below?
675 - (15 - 12)³ ÷ 3
A 216
C 666
B 224
D 678
Plz help
Answer:
675 – (15-12) ³+3
675-3³ +3
675-27+3
651
Step-by-step explanation:
The value of the given expression is 666 which is the correct answer that would be an option (C).
What is the PEMDAS rule?PEMDAS rule states that the order of operation starts with the calculation enclosed in brackets or the parentheses first. Exponents (degrees or square roots) are then operated on, followed by multiplication and division operations, and then addition and subtraction.
We have been given the expression below as:
675 – (15-12)³ ÷ 3
Using the PEMDAS rule to determine the evaluation of the given expression
⇒ 675 – (15-12)³ ÷ 3
Apply the subtraction operation,
⇒ 675 - (3)³ ÷ 3
⇒ 675 - 27 ÷ 3
⇒ 675 - 27 / 3
Apply the division operation,
⇒ 675 - 9
Apply the subtraction operation,
⇒ 666
Therefore, the value of the given expression would be 666,
Learn more about the PEMDAS rule here :
https://brainly.com/question/20876480
#SPJ6
can somebody please helpp
Answer:
The Answer is the first option
Step-by-step explanation:
If you take the 3x-4>5
than: 3x>5+4
3x>9
x>9/3
x>3
Pls help I can't understand
Answer:
A
Step-by-step explanation:
This shape is a trapezoid. We can divide into two parts: a triangle and a rectangle.
■■■■■■■■■■■■■■■■■■■■■■■■■■
Let A' be the area of the triangle.
● A'= (b*h)/2
b is the base and h is teh heigth.
b= 26-20 = 6 mm
● A'= (6*14)/2 = 42 mm^2
●●●●●●●●●●●●●●●●●●●●●●●●
Let A" be the area of the rectangle.
A"= L*w
L is the length and w is the width.
A"= 14*20
A"= 280 mm^2
■■■■■■■■■■■■■■■■■■■■■■■■■■
Let A be the area of the trapezoid.
A= A'+A"
A= 42+280
A= 322 mm^2
PLEASE HELP!!
Factor the polynomial [tex]x^2+6x+5[/tex]. Your answer can be written as [tex](x+A)(x+B)[/tex] where A
Step-by-step explanation:
[tex]a + b = 6[/tex]
[tex]ab = 1 \times 5 = 5[/tex]
[tex]a = 1 \: \: \: \: \: \: \: \: b = 5[/tex]
[tex]( {x}^{2} + x) + (5x + 5)[/tex]
[tex]x(x + 1) + 5(x + 1)[/tex]
[tex](x + 1)(x + 5)[/tex]
Hope this is correct and helpful
HAVE A GOOD DAY!
Can somebody please answer as many as possible?
Please and thankyou!
A quadrilateral is 360 degrees
I cant make a shape for any! Please help!
Answer:
Simply subtract the sum of the the three angles given from 360° in order to get the measure of the fourth angle!
Step-by-step explanation:
Please can someone help me ASAP
a) [tex]\frac{8}{2}[/tex]
b) [tex]\frac{9}{4}[/tex]
c) [tex]\frac{3}{-1}[/tex]
WILL GIVE BRANLIEST AND 20 POINTS!!
List the coordinates of FOUR vertices that create the feasible region on the graph. Submit your answer in the form of FOUR ordered Pairs (x, y)
Step-by-step explanation:
The coordinates of the feasible region are:(In clockwise direction)
(200, 200)
(300, 200)
(500, 0)
(300, 0)
WILL MARK BRAINLIEST
PLEASE HELP x
Answer:
3. time = 6.4999 approximately 6.5 years
4. $2235.35
5. $ 3950
Step-by-step explanation:
4. amount of interest = final amount - principle= 7535.35 - 5300 = 2235.35
5. principle = final amount - interest earned = 4435.25 - 485.25 = 3950