Simplify: 8√3 + 12√3

Answer:

7/20 participate in art.

Answer:

7/20 hcjauwauhfehhfieafuewaueiwavibiurbviubwibvebaiubj

Answer:

answeris: C.(-6,-9)➡(6-9)

Answer:

20, 4

Step-by-step explanation:

Let's assume total number of students registered is n

Last week n/4 people are absent

so people present are n - n/4 = 3n/4

Today after return of Jen  1/5 n are absent

so people present are n - n/5 = 4n/5

which is also equal to last week present people + 1 (Jen)

= 3n/4 + 1

= (3n + 4) / 4

so (3n + 4) / 4 = 4n/5

=> 3n + 4 = 4n/5 * 4

=> (3n + 4) * 5 = 16n

=> 15n + 20 = 16n

=> 20 = n

=> n = 20

So total students registered for class is 20

today no of people absent = n/5 = 20/5 = 4

Answer:

0.38 < 0.70

Step-by-step explanation:

Answer:

Total percent: 3.7%

Step-by-step explanation:

(2000 x 0.01) + (4240 x 0.05) = $232

X/100 = 232/6240

= 23200/6240 = 3.7%

Answer:

45 degrees

Step-by-step explanation:

Subtract 360° 360 ° from 405° 405 ° . The resulting angle of 45° 45 ° is positive, less than 360° 360 ° , and coterminal with 765° 765 ° .

Answer:

A, -4 is the answer

Step-by-step explanation:

it intersects there

Answer; 0 ,2?

Step-by-step explanation:

im not so sure tbh its a lil confusing dont they tell how many years its been?

Answer:

First drop down: √4 and √9

Second drop down: 2 and 3

Third drop down: 10 and 15

Step-by-step explanation:

the root of four is 2

the root of nine is 3

thus √ 7 is between 2 and 3

5√7 is between 10 and 15 because 2x5 is 10 and 3x5 is 15.

Answer:

120 bananas

Step-by-step explanation:

$20 = 2000 cents

Create a proportion:  

Cross multiply, then divide: 3 × 2000 = 6000, 6000 ÷ 50 = 120

So, you can buy 120 bananas for $20

hope this helps

Answer: A

Step-by-step explanation:

Because 489 + 45

The completed ratio chart is provided below:

Feet of Ribbon    1             5   10    15

Cost                     $0.60   $3  $6   $9

The amount Serena would get if she has $12 is 20 yards.

The amount Serena would pay if she wants 17 feet of the ribbon is $10.20.

The first step is to determine the unit cost of a ribbon.

Unit cost of a ribbon = $3 / 5 = $0.60

The cost of 10 feet of the ribbon = $0.60 x 10 = $6

The cost of 15 feet of the ribbon = $0.60 x 15 = $9

The feet of ribbon Serena can buy if she has $12 = $12 / $0.60 = 20 yards.

The cost of 17 feet of the ribbon = $0.60 x 17 = $10.20

To learn more, please check: https://brainly.com/question/12528427

Answer:

the correct function is x -10 -9 0 5

Answer:

x = 8, x = 2

Step-by-step explanation:

|2(x-5)|+11=17​

|2(x-5)| = 6

|(x-5)| = 3

x = 8 AND x = 2 because of the absolute value.

Brainliest, please :)

The solution of the given equation will be x = 2 and 8.

What is an expression?

Expression in math is defined as the collection of the numbers, variables and functions by using signs like addition, subtraction, multiplication, and division.

Given that;

The expression is;

| 2 (x - 5) | + 11 = 17

Now, Solve the expression is;

| 2 (x - 5) | + 11 = 17

Subtract 11 both side,

| 2 (x - 5) | + 11 - 11 = 17 - 11

| 2 (x - 5) | = 6

Reduce modulus we get;

2 (x - 5) = ±6

Take positive sign,

2 (x - 5) = 6

x - 5 = 6/2

x - 5 = 3

x = 3 + 5

x = 8

And, Take negative sign,

2 (x - 5) = -6

x - 5 = -6/2

x - 5 = -3

x = 5 - 3

x = 2

Thus, The solution of the given equation will be x = 2 and 8.

Learn more about the modulus function visit:

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Answer:

  y = x +1

Step-by-step explanation:

The line meets the y-axis (on the left side of the graph) at y=1. This is the y-intercept (b).

The line goes up 1 grid square for each 1 grid square to the right. Its slope is ...

  m = rise/run = 1/1 = 1

Now, we know m and b so we can write the slope-intercept equation for the line:

  y = mx +b . . . . . . line with slope m and y-intercept b

  y = x +1

[tex]\lim \limits_{n \to \infty} ~\dfrac{8n}{3n^2 +5} \\\\\\=8\lim \limits_{n \to \infty} ~ \dfrac{\tfrac n{n^2}}{\tfrac{3n^2}{n^2} + \tfrac 5{n^2}}\\\\\\=8 \lim \limits_{n \to \infty} ~\dfrac{ \tfrac 1n}{ 3 + \tfrac 5{n^2}}}\\\\\\=8 \cdot \dfrac{ 0}{3 +0} = 8 \cdot 0 = 0[/tex]

We want to evaluate the limit of [tex]\frac{8n}{3n^{2}+5}[/tex] as n tends toward infinity (+∞)

The limit of this expression is the same as the limit of [tex]\frac{8n}{3n^{2}}[/tex]

But this last expression can be simplified, we can remove one n up and down which gives us : [tex]\frac{8}{3n}[/tex]

We know the limit of this one, it is simply Zero 0, by definition of the class lesson.

So to conclude the limit of [tex]\frac{8n}{3n^{2}+5}[/tex] as n tends toward infinity is 0.

Good Luck

Answer:

Enzo must have played 11 games.

Step-by-step explanation:

Since Enzo earns 5 tickets from every game and Beatriz wins 11 tickets from each game, we have to find the LCM (Least Common Multiple) since they earned the same amount of tickets when they stopped.

The LCM of 11 and 5 is 55.

To see how many games they both played we have to divide the amount of tickets they earn each time from the LCM (55).

Since Enzo earns 5 tickets from each game and both Enzo and Beatrice earned 55, Enzo must've played 11 games.

(If that makes sense lol)

Answer:

Step-by-step explanation:

Average = (Ymax + Ymin)/2 = (4 + (- 2))/ 2  = 1

Amplitude =  (Ymax - Ymin)/2 = (4 - (- 2))/ 2  = 3

y is at a maximum when x = 0, so cosine function is easy.

one cycle (2π radians) is completed in 2π/3

therefore

y = 1 + 3cos(2π(x /(2π/3))

y = 1 + 3cos(3x)

Answer(s):

[tex]\displaystyle y = 3sin\:(3x + \frac{\pi}{2}) + 1 \\ y = 3cos\:3x + 1[/tex]

Step-by-step explanation:

[tex]\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 1 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-\frac{\pi}{6}} \hookrightarrow \frac{-\frac{\pi}{2}}{3} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{3}\pi \\ Amplitude \hookrightarrow 3[/tex]

OR

[tex]\displaystyle y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{2}{3}\pi \\ Amplitude \hookrightarrow 3[/tex]

You will need the above information to help you interpret the graph. First off, keep in mind that although this looks EXACTLY like the cosine graph, if you plan on writing your equation as a function of sine, then there WILL be a horisontal shift, meaning that a C-term will be involved. As you can see, the photograph on the right displays the trigonometric graph of [tex]\displaystyle y = 3sin\:3x + 1,[/tex]in which you need to replase "cosine" with "sine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the cosine graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the sine graph [photograph on the right] is shifted [tex]\displaystyle \frac{\pi}{6}\:unit[/tex]to the right, which means that in order to match the cosine graph [photograph on the left], we need to shift the graph BACKWARD [tex]\displaystyle \frac{\pi}{6}\:unit,[/tex]which means the C-term will be negative, and by perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{-\frac{\pi}{6}} = \frac{-\frac{\pi}{2}}{3}.[/tex]So, the sine graph of the cosine graph, accourding to the horisontal shift, is [tex]\displaystyle y = 3sin\:(3x + \frac{\pi}{2}) + 1.[/tex]Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph hits [tex]\displaystyle [-\frac{2}{9}\pi, -\frac{1}{2}],[/tex]from there to [tex]\displaystyle [\frac{4}{9}\pi, -\frac{1}{2}],[/tex]they are obviously [tex]\displaystyle \frac{2}{3}\pi\:units[/tex]apart, telling you that the period of the graph is [tex]\displaystyle \frac{2}{3}\pi.[/tex]Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = 1,[/tex]in which each crest is extended three units beyond the midline, hence, your amplitude. So, no matter how far the graph shifts vertically, the midline will ALWAYS follow.

I am delighted to assist you at any time.

Answer:

All ordered pairs with the same x value

Step-by-step explanation:

A vertical line can be represented by the equation x=k for some value k. So any pair with x value equal to k satisfies the equation and is thus in the set

Answer:

the third answer

Step-by-step explanation:

because If two positive numbers are multiplied together or divided, the answer is positive. If two negative numbers are multiplied together or divided, the answer is positive. If a positive and a negative number are multiplied or divided, the answer is negative.

Answer: answer is C

Step-by-step explanation: