Si se impulsa un bloque con una velocidad de 15m/s sobre el piso sin rozamiento mostrado. Determinar la altura “h” que alcanzará, no existe rozamiento.
PORFAAA AYUDA URGENTE
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La altura máxima alcanzada por el bloque es de 14.471 metros.
En esta pregunta asumimos que la altura inicial del bloque es igual a tres metros por encima del la altura de referencia y la altura final puede ser determinada mediante el principio de conservación de la energía, en cuyo caso, la suma de la energía cinética traslacional inicial ([tex]K[/tex]) y la energía potencial gravitacional inicial ([tex]U_{o}[/tex]), ambos en joules, es igual a la energía potencial gravitacional final ([tex]U_{f}[/tex]), en joules. Matemáticamente hablando, tenemos la siguiente expresión:
[tex]U_{o}+K = U_{f}[/tex]
[tex]m\cdot g\cdot z_{o} + \frac{1}{2}\cdot m\cdot v^{2} = m\cdot g \cdot z_{f}[/tex] (1)
Donde:
[tex]m[/tex] - Masa del bloque, en kilogramos.[tex]g[/tex] - Aceleración gravitacional, en metros por segundo al cuadrado.[tex]z_{o}[/tex], [tex]z_{f}[/tex] - Alturas inicial y final, en metros.[tex]v[/tex] - Rapidez inicial del bloque, en metros por segundo.A continuación, despejamos la altura final del bloque:
[tex]z_{f} = z_{o}+\frac{1}{2}\cdot \frac{v^{2}}{g}[/tex] (2)
Si sabemos que [tex]z_{o} = 3\,m[/tex], [tex]v = 15\,\frac{m}{s}[/tex] y [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], entonces la altura máxima alcanzada por el bloque es:
[tex]z_{f} = 3\,m + \frac{1}{2}\cdot \left[\frac{\left(15\,\frac{m}{s} \right)^{2}}{9.807\,\frac{m}{s^{2}} } \right][/tex]
[tex]z_{f} = 14.471\,m[/tex]
La altura máxima alcanzada por el bloque es de 14.471 metros.
Invitamos cordialmente a ver esta pregunta sobre el principio de conservación de la energía: https://brainly.com/question/19561287
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