Explanation:
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Find the (a) mean, (b) median, (c) mode, and (d) midrange for the data and then (e) answer the given question.
Listed below are the jersey numbers of 11 players randomly selected from the roster of a championship sports team. What do the results tell us?
24 26 89 16 38 69 93 3 1 80 49
The statistical values such as mean, Median and mode gives measure of centre of a data, while the midrange gives information about the spread. Hence, the statistical measures are :
Mean = 44.36Median = 38Mode = 1, 3, 16, 24, 26, 38, 49, 69, 80, 89, 93Midrange = 46Given the data :
1, 3, 16, 24, 26, 38, 49, 69, 80, 89, 93Mean = [Σx ÷ n]
Mean = (24+26+89+16+38+69+93+3+1+80+49) / 11
Mean = (488 ÷ 11) = 44.36
The median :
0.5(n + 1)th termMedian = 0.5(11 + 1) = 6th term
Median = 38
The Mode :
The most frequently occurring value in a distribution ; since each the value occur just one, then there is no single mode value.
The midrange :
(maximum - minimum) / 2Midrange = (93 - 1) / 2
Midrange = 92/2 = 46
Therefore, the midrange is the value of the range divided by 2.
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