Select the correct answer from each drop down menu.
Consider polygon JKLMNO on the coordinate grid.

Answers

Answer 1

The other vertices appears to be located in the second and fourth quadrants.

What is a polygon?

A polygon is a two-dimensional geometric shape that is made up of straight line segments connected end-to-end to form a closed shape.

Based on the image, it appears that we are dealing with a polygon JKLMNO on a coordinate grid.

First, we can see that the polygon is a hexagon (six-sided figure) with vertices at points J, K, L, M, N, and O. We can also see that the polygon is not a regular hexagon, since its sides are of different lengths and its angles are not all equal.

To determine the coordinates of the vertices of the polygon, we would need to know the scale and orientation of the coordinate grid. However, based on the image, we can make some general observations about the location of the vertices. For example, we can see that vertex J appears to be in the third quadrant (negative x and y values), while vertex N appears to be in the first quadrant (positive x and y values).

Therefore,  The other vertices appear to be located in the second and fourth quadrants.

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Related Questions

Orange juice drinks were to be distributed to the schools in the District of Nueva Valencia South. 950 packs were given to La Paz Elementary School, 785 to Igdarapdap Elementary School, 1, 370 to Cabalaynan Elementary School. If there are 5, 000 packs of juice drinks, how many were distributed to different schools? How many packs were not given?
3. First Solution: ______________
4. Second Solution: ______________

Answers

By those 2 ways of solution, a total of 3,105 packs of juice drinks were distributed to different schools.

How to find out the numberFirst Solution:

To find out how many packs of juice drinks were distributed to different schools, we need to add the number of packs given to each school.

950 (La Paz Elementary School) + 785 (Igdarapdap Elementary School) + 1,370 (Cabalaynan Elementary School) = 3,105 packs of juice drinks

So, a total of 3,105 packs of juice drinks were distributed to different schools.

Second Solution:

To find out how many packs of juice drinks were not given, we need to subtract the number of packs distributed to different schools from the total number of packs available.

5,000 (total number of packs) - 3,105 (number of packs distributed to different schools) = 1,895 packs of juice drinks

So, a total of 1,895 packs of juice drinks were not given.

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Is (2,1) a solution to this system of equations?
8x+7y=11
x+y=3

Answers

(2,1) is a solution to the system of equations 8x+7y=11 and x+y=3.

What is Equation?

Two or more expressions with an Equal sign is called as Equation.

To check if (2,1) is a solution to the system of equations:

8x + 7y = 11

x + y = 3

We substitute x = 2 and y = 1 into both equations:

For the first equation: 8(2) + 7(1) = 16 + 7 = 23

For the second equation: 2 + 1 = 3

Hence, we can see that both equations are true when x = 2 and y = 1.

Therefore, (2,1) is a solution to the system of equations.

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A jewlery shop sells 240 neaklesses in a month. 180 of the neaklesses were sold via he shops website, the rest were sold in a high street shop. Work out the ratios of online sales to shop sales, give your answer in its simplest form

Answers

The ratios of online sales to shop sales of A jewelery shop which sold 240 necklaces in a month is equals to the 3:1.

We have a jewelery shop and they sold there necklaces to the different shops.

Total number of sold necklaces in a month = 240

Number of online sold necklaces in a month = 180

Total online sales of jewelery shop = 180

and rest of necklaces were sold in a high street shop. So, the number of sold necklaces in high street shop during a month = total number of sold necklaces - online sold necklaces

= 240 - 180 = 60

Total shop sales jewelery shop = 60 necklaces

Ratio is used to determine the relationship between two or more things ( like size, quantity, etc.). It is represented by a/b or a : b ( read as a ratio b). Here, we have to calculate the ratios of online sales to shop sales. So, the ratio of online sales to shop sales = 180 : 60 or 180/60

Simplify the expression,

=> 180/60 = 3

Hence, required ratio is 3: 1.

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It is known that the sound levels of two consecutive thunderstorms in the storm are 0.1W/m² and 10W/m² respectively, find the difference between their sound levels.​

Answers

The difference between their sound levels is 9.9W/m².

What are consecutive numbers?

The preceding number, which is always put before a number, is referred to as the predecessor. A number's successor is the one that is written just after it. Take the list of natural numbers 1, 2, 3, 4, and 5, for instance. 1 is the precursor of 2, and 2 is the successor of 1. Consecutive numbers are those that come after one another in ascending sequence, from smallest to largest. The typical difference between every two numbers is 1.

Here, we have

Given: It is known that the sound levels of two consecutive thunderstorms in the storm are 0.1W/m² and 10W/m² respectively.

We have to find the difference between their sound levels.​

S₁ = 0.1W/m²

S₂ = 10W/m²

Difference = S₂ - S₁

Difference = 10W/m² - 0.1W/m²

Difference  = 9.9W/m²

Hence, the difference between their sound levels is 9.9W/m².

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Which is the better buy?
Frozen Peas
Cost (dollars)
Weight (ounces)
O Brand A
A B
2
16
3
28
O Brand B
O The unit cost is the same.

Answers

The better buy is given by the following brand:

Brand A.

How to obtain the better buy?

The better buy is obtained applying the proportions in the context of the problem.

A proportion is applied as the cost per ounce is given dividing the total cost by the number of ounces.

Then the better buy is given by the option with the lowest cost per ounce.

The cost per ounce for each brand is given as follows:

Brand A: 16/2 = $8 per ounce.Brand B: 28/3 = $9.3 per ounce.

$8 per ounce is a lesser cost than $9.3 per ounce, hence the better buy is given by Brand A.

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PLEASE HELP! THIS IS MY LAST QUESTION, BUT I DON'T KNOW HOW TO DO IT!

The mass of a substance, which follows a continuous exponential growth model, is being studied in a lab. A sample increases continuously at a relative rate of 7% per day. Find the mass of the sample after six days if there were 552 grams of the substance present at the beginning of the study.
Do not round any intermediate computations, and round your answer to the nearest tenth.

Also, may you please explain how you got the answer, it would be very helpful because I don't understand how to solve this. Thank you!

Answers

Answer:

864.3

Step-by-step explanation:

Since the substance is increasing continuously at a relative rate of 7% per day, we can use the continuous exponential growth formula:

P(t) = P(0) * e^(rt)

where:

P(t) is the mass of the substance after "t" days

P(0) is the initial mass of the substance (552 grams in this case)

e is the mathematical constant e (approximately equal to 2.71828)

r is the relative growth rate (0.07 per day in this case)

Substituting the given values, we get:

P(t) = 552 * e^(0.07t)

To find the mass after 6 days, we can substitute t = 6:

P(6) = 552 * e^(0.07*6)

Using a calculator, we get:

P(6) ≈ 864.3 grams

Therefore, the mass of the substance after 6 days is approximately 864.3 grams rounded to the nearest tenth.

1.State domain and range
2.Is it a function
3.Is it a one to one function

Answers

1. domain: All real numbers. range: [2,4]

2. It is a function.

3. Not one to one function.

What is function?

A function is a relationship or expression involving one or more variables.  It has a set of input and outputs

1. domain of the given function would be, real numbers.

  range of the function is [2,4].

2. Yes. It is a function.

3. No it is not one to one function. It is many to one function?

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Please help
Solve the equation.
3x + 2 = 3x + 2
Select the correct choice below and, if necessary, fill in the answer box to complete your choice
A. X =
B. The solution is all real numbers.
C. There is no solution.

Answers

Move 2 to the right

3x=3x+0

Move 3 to the left


Solve

0=0

Since its true there all real numbers


Solution


Option B

The distribution of SAT scores of all college-bound seniors taking the SAT in 2014 was approximately normal with a mean of
1497
14971497 and standard deviation of
322
322322. Let

XX represent the score of a randomly selected tester from this group.
Find

(
1497
<

<
1819
)
P(1497

Answers

The probability of a randomly selected tester from this group having a score between 1497 and 1819 is approximately 0.68.

What is Probability?

Probability is the measure of how likely a certain event is to occur. It is a mathematical concept that is used to quantify the likelihood of a certain outcome from a given set of circumstances. Probability is expressed as a number between 0 and 1, where 0 indicates that the event is impossible, and 1 indicates that the event is certain. Probability is used in many fields, including mathematics, finance, and decision making.

This is because approximately 68% of the data is within one standard deviation of the mean, and the data is normally distributed. The area between the mean and the upper limit of 1819 is 0.68, which means that the graph probability of a randomly selected tester from this group having a score between 1497 and 1819 is 0.68.

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How do you find the verticle asymtote of y = x-4/x-2

Answers

Answer: VA: x = 2

Step-by-step explanation: In order to find the verticle asymtote you have to substitute values for x in order to get zero. Look in the denominator and see which value minus or plus the value next to it will equal zero. In this case, 2-2 is 0 so your verticle asymtote is 2. Keep in mind you want 0 in the denominator because that would mean the value on a graph is undefined, showing your asymtote.

Answer: 2

Step-by-step explanation:

Crash cost per week for activity two?
Activity Normal Time Crash Time Normal Cost Crash Cost Total Allowable Crash Time Crash cost per week
1 12 6 3,000 4,200
2 18 12 1,000 4,600
A. Activity 2 can not be crashed
B. $600 per week
C. $800 per week
D. $3600 per week

Answers

$600


B. $600 per week

For Activity 2, the Normal Cost is $1,000 and the Crash Cost is $4,600, so the Crash cost per week is $60.

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Practice math quadratic equation
4a^2+6=0

Answers

The given quadratic equation does not have a real solution.

What are Quadratic Equations?

Quadratic equations are polynomial equations of second degree.

The general form of a quadratic equation is ax² + b x + c = 0.

The given quadratic equation is,

4a² + 6 = 0

We have to find the solution of the quadratic equation.

Subtracting both sides by 6,

4a² + 6 - 6 = 0 - 6

4a² = -6

a² = -6/4

a² = -3/2

Taking square root on both sides,

a = √(-3/2), which implies that the given quadratic equation does not have a real solution.

Hence there are no real solution for the given equation.

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A certain number is multiplied by 7 and
11 is added to the product. The total is
67. What is the number?

Answers

Answer:

the answer is 8

Step-by-step explanation:

subtract 11
67 - 11 = 56

Divide 7 to find the answer

56/7 = 8

Determine the LCM of the given polynomials: Leave your answer in factored form. \[ x^{2}+8 x+16 \text { and } x^{2}+11 x+28 \]

Answers

The LCM of the polynomials x² + 8x + 16 and x² + 11 x + 28 is (x + 4)(x + 4)(x + 7).

To determine the LCM of the given polynomials, we need to find the smallest polynomial that is a multiple of both  x² + 8x + 16 and x² + 11 x + 28.

First, let's factor the given polynomials:
x² + 8x + 16 = (x + 4)(x + 4)

x² + 11 x + 28 = (x + 4)(x + 7)

Now, we can see that the LCM of these two polynomials is the product of the highest power of each factor:

LCM = (x + 4)(x + 4)(x + 7)

So, the LCM of the given polynomials in factored form is (x + 4)(x + 4)(x + 7).

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O FRACTIONS Addition or subtraction of fractions with the sam Add. Write your answer as a fraction in simplest form. (1)/(8)+(5)/(8)

Answers

Fraction in simplest form is (3)/(4).

To add or subtract fractions with the same denominator, you simply add or subtract the numerators and keep the same denominator. Then, simplify the fraction if possible.

In this case, the fractions have the same denominator of 8, so we can simply add the numerators:

(1)/(8) + (5)/(8) = (1 + 5)/(8) = (6)/(8)

Now, we need to simplify the fraction by finding the greatest common factor (GCF) of the numerator and denominator. The GCF of 6 and 8 is 2, so we can divide both the numerator and denominator by 2 to get:

(6)/(8) = (6/2)/(8/2) = (3)/(4)

So the final answer is (3)/(4).

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Find the value of the variable y when

the sum of fractions [tex]\frac{y+1}{y-5}[/tex] and [tex]\frac{10}{y+5}[/tex] is equal to their product.

Answers

The value of y that satisfies the equation is y = -11.

Describe Equation?

An equation is a mathematical statement that expresses the equality of two expressions. It typically consists of two sides, separated by an equals sign (=), with each side containing one or more terms that may include variables, constants, and mathematical operators.

We can start by setting up the equation:

(y+1)/(y-5) + 10/(y+5) = (y+1)/(y-5) × 10/(y+5)

To solve for y, we need to simplify and manipulate the equation:

Multiply both sides by (y-5) × (y+5) to eliminate the denominators:

(y+1)(y+5) + 10(y-5) = 10 × (y+1)

Expand and simplify:

y² + 6y - 15 + 10y - 50 = 10y + 10

Combine like terms:

y² + 16y - 55 = 0

Factor the quadratic:

(y + 11)(y - 5) = 0

Solve for y:

y = -11 or y = 5

However, we need to check if either solution makes the denominators of the original equation equal to zero, since division by zero is undefined:

For y = -11, the denominators are -16 and -6, respectively, which are both nonzero. Therefore, y = -11 is a valid solution.

For y = 5, the denominator of the first fraction is 0, which is not allowed. Therefore, y = 5 is an extraneous solution and should be discarded.

Therefore, the value of y that satisfies the equation is y = -11.

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If the expression x -2 y-4 3 sqrt 64xy³ is written in the form axby, then what is the
product of a, b and c?

Answers

The expression x -2 y-4 3 sqrt 64xy³ can be written in the form axby as follows:

ax -2by-4c 3 sqrt 64xy³

What is coefficient?

Coefficient in mathematics is a numerical value that is used to represent the magnitude of a given quantity in an equation. It is normally the numerical factor associated with the variables in an equation that represent a certain amount of change in the equation. For example, the coefficient of x in the equation y = 5x + 7 is 5, which indicates that x is multiplied by 5 in the equation.

In this expression, a, b, and c refer to the coefficients of the x, y, and the cube of y respectively. Thus, a is equal to 1, b is equal to -2, and c is equal to -4. Therefore, the product of a, b and c is equal to 8.

To break down the expression further, the coefficient of x is a, which is equal to 1. The coefficient of y is -2b, which is equal to -2. The coefficient of the cube of y is -4c, which is equal to -4. Finally, the coefficient of the square root of 64xy³ is 3, which is equal to 3.

Thus, when written in the form axby, the expression x -2 y-4 3 sqrt 64xy³ is equal to 1 -2 -4 3 sqrt 64xy³. The product of a, b, and c in this expression is equal to 8.

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(1 point) Express the following sum in closed form. n Σ (3k – 3) = ____
k=1 Note: Your answer should be in terms of n.

Answers

This is our final answer in terms of n.

The given sum is n Σ (3k – 3) = ____ , where k=1. To express this sum in closed form, we can use the formula for the sum of an arithmetic series. The formula is:

S = n/2 (a1 + an)

where S is the sum, n is the number of terms, a1 is the first term, and an is the last term.

In this case, the first term is 3(1) - 3 = 0 and the last term is 3(n) - 3 = 3n - 3. Plugging these values into the formula, we get:

S = n/2 (0 + 3n - 3)

Simplifying the equation gives us:

S = n/2 (3n - 3)

S = (3n^2 - 3n)/2

S = (3n^2)/2 - (3n)/2

S = (3/2)n^2 - (3/2)n

Therefore, the sum in closed form is:

n Σ (3k – 3) = (3/2)n^2 - (3/2)n

This is our final answer in terms of n.

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Kuro has a stack of 15 coins on a table with a volume of 8 cubic centimeters. He has stacked them perfectly straight creating a cylindrical shape. He accidentally bumps the table, causing the coins to shift to a leaning position; but are still stacked. What would be the best estimate of the volume of the stack once it has been bumped/shifted?

Answers

The best estimate of the volume of the stack once it has been bumped/shifted is 4πt³ cubic centimeters.

Describe Volume of cylinder?

A cylinder is a three-dimensional geometric shape that consists of two parallel circular bases connected by a curved surface. The volume of a cylinder is the amount of space occupied by the shape and is given by the formula:

Volume = πr²h

where π (pi) is a mathematical constant approximately equal to 3.14, r is the radius of the circular base, and h is the height of the cylinder.

Assuming that the coins have the same dimensions and are perfectly circular, the original stack of 15 coins formed a cylinder with a height of 15 times the thickness of a single coin, and a radius equal to the radius of a single coin.

The volume of this cylinder can be calculated using the formula V = πr²h, where r is the radius and h is the height.

Since the volume of the original stack is 8 cubic centimeters, we can set up the equation:

8 = πr²(15t)

where t is the thickness of a single coin.

Solving for r, we get:

r = √(8/15πt)

When the stack is bumped and shifts to a leaning position, the new shape will still be a cylinder, but the height will be shorter than before. Let's say that the new height is h2. We can calculate the new volume using the same formula:

V2 = πr²h2

To estimate the new height, we can use the fact that the coins are now leaning against each other, so the new height will be less than 15t. Let's say that the new height is approximately 12t.

Substituting in the values, we get:

V2 = π(√(8/15πt))²(12t)

Simplifying, we get:

V2 = 4πt³

Therefore, the best estimate of the volume of the stack once it has been bumped/shifted is 4π³ cubic centimeters.

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the circumference of a circle is 23r cm. what is exact the area of the circle?

Answers

As a result, the circle's precise size is (529/4)π³  square centimetres.

Explain what a circle is?

A circle is a closed, two-dimensional shape where every point in the surface is equally spaced from a central point. The line of mirror symmetry is formed by all lines that traverse the circle. Additionally, every point has circular symmetry around the centre.

The circumference of a circle is given by the formula:

C = 2πr

where r is the radius of the circle. We can rearrange this formula to solve for the radius:

r = C / 2π

When we substitute the circumference's specified number, we obtain:

r = (23r) / (2π)

Simplifying:

r = (23/2)π

Now that we know the radius, we can use the formula for the area of a circle:

A = πr²

Substituting the value we found for the radius, we get:

A = π[(23/2)π]²

Simplifying:

A = π(529/4)π²

A = (529/4)π³

Therefore, the exact area of the circle is (529/4)π³ square cm.

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A soccer ball kicked off the ground has a height modeled by the function h= -t2 + 6t,
where t is the number of seconds since the ball was kicked and h is the height in meters.
What is the maximum height reached by the ball?
3 meters
6 meters
9 meters
27 meters

Answers

The maximum height reached by the baII is 9 meters.

What is a functiοn?

In mathematics, a functiοn is a relatiοn between twο sets, typically called the dοmain and range, that assigns tο each element οf the dοmain a unique element οf the range. In οther wοrds, a functiοn is a rule οr a set οf rules that assοciates each input value with exactly οne οutput value.

Tο find the maximum height reached by the ball, we need to find the vertex of the parabolic functiοn [tex]h = -t^2 + 6t[/tex]. The vertex of a parabola in the form[tex]y = ax^2 + bx + c[/tex] is located at the point [tex](-b/2a, c - b^2/4a)[/tex].

In this case, the functiοn is[tex]h = -t^2 + 6t[/tex]t, which has a=-1, b=6, and c=0. Therefοre, the vertex οf the parabοla is located at:

t = -b/2a = -6/(-2) = 3

Tο find the maximum height, we substitute t = 3 into the functiοn:

[tex]h = -t^2 + 6t = -3^2 + 6(3) = 9 meters[/tex]

Therefοre, the maximum height reached by the baIl is 9 meters.

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i need help with this questchin (image attach)

Answers

Answer:

scalene triangle

Step-by-step explanation:

in a scalene triangle, all the sides are not equal

IH is not equal to HJ and also is not equal to JI

13. The scale on a map is 1 : 20 000.
The area of a lake on the map is 1.6 square centimeters.
Calculate the actual area of the lake. Give your answer in square meters.

Answers

The actual area of the lake 64000 square meters.

What is ratio?

When two numbers are compared, the ratio between them shows how often the first number contains the second. As an illustration, the ratio of oranges to lemons in a dish of fruit is 8:6 if there are 8 oranges and 6 lemons present.

In this given question, we are first of all going to use the given ratio of the on map measurements to the actual measurements, that is 1:20000 to calculate the actual measurements as follows:

[tex]1.6cm^2=1\times 1.6cm^2[/tex]------->1

Using the ratio 1:20000 in 1.1, we get,

[tex]1.6\times1 cm^2= 1.6\times (20000)^2 cm^2 = 1.6\times 400000000 cm^2 = 640000000cm^2[/tex]-----> 2

As the actual measurement of the area of the lake.

So, 1m = 100 cm

=> [tex](1m)^2=(100cm)^2[/tex]

=> [tex]1m^2 = 10000cm^2[/tex]-------> 3

So, using equation 3 in the value obtained 2, we get,

=> [tex]640000000cm^2 = \frac{640000000}{10000} = 64000m^2[/tex]

Hence the actual area of the lake is 64000 square meters.

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3. John wants an average bowling score of 215. If he scored 159, 182, 225, 240, 198,
200 and 230 on his first seven games, what must he score on his 8th game to achieve
this average?

Answers

John must score 286 on his 8th game to achieve an average score of 215.

What is an Average?

Average, also known as the mean, is a mathematical concept that represents the central value of a set of numbers. It is found by dividing the sum of the numbers by the total count of the numbers.

To find out what John must score on his 8th game to achieve an average score of 215, we need to use the formula for calculating the average or mean:

Average = (Sum of Scores) / (Number of Scores)

We can use this formula to solve for the unknown score:

215 = (159 + 182 + 225 + 240 + 198 + 200 + 230 + x) / 8

Multiplying both sides by 8, we get:

1720 = 159 + 182 + 225 + 240 + 198 + 200 + 230 + x

Simplifying, we get:

1720 = 1434 + x

Subtracting 1434 from both sides, we get:

x = 286

Therefore, John must score 286 on his 8th game to achieve an average score of 215.

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BRAINLIEST. Can someone please answer all the question in the picture below. BRAINLIEST.

Answers

Answer:

P'(1,2) S'(2,5)

Step-by-step explanation:

P(3,-2) S(4,-5) glode translation (x-2,y)

-2 -2

P(1,-2) S(2,-5) reflect over x-axis

P'(1,2) S'(2,5) ----> answer

hope this helpzzz

Find the scale factor.
35
35
11 61035 dit
42
42
پر
42 M

Answers

The scale factor is 11.

What is scale factor?

Scale factor is a numerical value used to proportionally enlarge or reduce a size of an object or image. It is also used to compare two similar shapes or objects. When the scale factor is greater than 1, it indicates an increase in size and when the scale factor is less than 1, it indicates a decrease in size. Scale factors are usually expressed as a ratio, such as 1:2, which means that the object has been doubled in size.

To calculate it, divide the first number by the second number and multiply by the third number: (35/42) x 11 = 10.714. Therefore, the scale factor is 11.

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Please HELP! I'll DO ANYTHING!!!!

Answers

If you could provide me more details, including the dimensions of the two triangle ' angles and sides, I might be able to evaluate whether or not they are comparable.

What precisely is a triangle?

A triangle is a polygon because it includes four or so additional parts. It features a simple rectangular shape. A rectangle having edges A, B, and C is referred to as a triangle. When the sides are actually not collinear, Euclidean geometry yields a single plane and cube. If a triangle contains three parts and three angles, it is a polygon. The intersections of a triangle's three sides are referred to as its corners. The sum of a triangle's sides is 180 degrees.

Two polygons must have congruent corresponding angles and proportionate corresponding sides in order to be considered comparable.

If you could provide me more details, including the dimensions of the two polygons' angles and sides, I might be able to evaluate whether or not they are comparable.

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In Exercises 51-56, find all solutions to the equation in the interval \( [0,2 \pi) \). You do not need a calculator. 51. \( 2 \cos x \sin x-\cos x=0 \) 52. \( \sqrt{2} \tan x \cos x-\tan x=0 \) 53. \

Answers

Solutions to Exercises 51-56:

The equation can be rewritten as: \( \cos x (2 \sin x-1)=0 \). The solutions are: \( \cos x=0 \) or \( \sin x=\frac{1}{2} \). The solutions in the interval \( [0,2 \pi) \) are: \( x=\frac{\pi}{2}, \frac{3 \pi}{2}, \frac{\pi}{6}, \frac{5 \pi}{6} \).

The equation can be rewritten as: \( \tan x (\sqrt{2} \cos x-1)=0 \). The solutions are: \( \tan x=0 \) or \( \cos x=\frac{1}{\sqrt{2}} \). The solutions in the interval \( [0,2 \pi) \) are: \( x=0, \pi, \frac{\pi}{4}, \frac{3 \pi}{4}, \frac{5 \pi}{4}, \frac{7 \pi}{4} \).

The equation can be rewritten as: \( \sin x (1-\cos x)=0 \). The solutions are: \( \sin x=0 \) or \( \cos x=1 \). The solutions in the interval \( [0,2 \pi) \) are: \( x=0, \pi, 2 \pi \).

Overall, the solutions to these exercises can be found by factoring the equations and finding the solutions to each factor in the given interval.

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The solutions in the interval \( [0,2 \pi) \) are x = 0, π, and 2π.

In Exercises 51-56, find all solutions to the equation in the interval \( [0,2 \pi) \). You do not need a calculator.

51. \( 2 \cos x \sin x-\cos x=0 \): The solutions in the interval \( [0,2 \pi) \) are x = 0, π, and 2π.

52. \( \sqrt{2} \tan x \cos x-\tan x=0 \): The solutions in the interval \( [0,2 \pi) \) are x = π/4, 3π/4, 5π/4, and 7π/4.

53. \( 2 \cos^2 x-\sin^2 x=1 \): The solutions in the interval \( [0,2 \pi) \) are x = 0, π, and 2π.

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Students are making lemonade from a powdered lemon drink mix.
Wyatt mixes 2 cups of water and 1 cup of powdered lemon mix. Emma
mixes 12 cups of water and 7 cups of powdered lemon mix. Use Wyatt
and Emma's percent of water to determine whose mix will be more
watery.

Answers

Wyatt's mix will be more watery compared to Emma's mix.

What does it mean for a mixture to be "more watery"?

The percentage of water in a mix is an essential factor that determines its taste, texture, and consistency. A higher percentage of water in a lemonade mix will make it more watery and less concentrated. In contrast, a lower percentage of water will make the mix less watery and more concentrated. The right balance of water and lemon mix is crucial to make a perfect lemonade.

Calculation for percent of water in the lemon drink mix:

To find the percent of water in the lemonade mixes, we need to divide the amount of water by the total volume of the mix and then multiply by 100.

For Wyatt's mix:

Percent of water = (2 cups water / (2 cups water + 1 cup lemon mix)) x 100

Percent of water = 66.67%

For Emma's mix:

Percent of water = (12 cups water / (12 cups water + 7 cups lemon mix)) x 100

Percent of water = 63.16%

From the calculations, we can see that Wyatt's mix has a higher percentage of water than Emma's mix. Therefore, Emma's mix will be less watery compared to Wyatt's mix.

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The estimated population, in thousands of people , of city A can be modeled by the function f(t)=15(1. 03) , where is the number of decades (10-year period) since 1980 the estimated population , in thousands of people , of city B can be modeled by the function g(t)=0. 4t+16, where t is the number of decades since 1980

Answers

Part A) Estimated Populations of Cities A and B are given.

Part B)  City A's estimated population is increasing at a faster rate than City B's estimated population for each decade.

Part C) the estimated population of City A first exceeds the estimated population of City B at the start of the 4th decade (t = 3)

Part D) The models may not realistically predict population growth over very long time scales, as they do not take into account other factors  

Part A:

Estimated Populations of Cities A and B

Decades Since 1980  City A (in thousands)          City B (in thousands)

0                                       15                                           16

1                                  19.5                                   16.4

2                                  25.2                                   17.8

3                                  32.7                                   19.2

4                                  42.4                                    20.6

Part B:

Population Increases from the previous Decade for Cities A and B

Decades Since 1980 City A (in hundreds)           City B (in hundreds)

0                                         -                                                   -

1                                       450                                              40

2                                       570                                               140

3                                       750                                               140

4                                       970                                               140

Interpretation:

From the table, we can see that City A's estimated population is increasing at a faster rate than City B's estimated population for each decade. This indicates that City A is growing more rapidly than City B, and may continue to do so in the future.

Part C:

To find the start of the decade when the estimated population of City A first exceeds the estimated population of City B, we need to solve the equation:

15[tex](1.03)^t[/tex] > 0.4t + 16

where t is the number of decades since 1980.

One way to solve this is to use a graphing calculator to graph both functions and find their intersection point. Alternatively, we can use trial and error to test different values of t until we find the smallest one that satisfies the inequality.

Using a graphing calculator, we find that the estimated population of City A first exceeds the estimated population of City B at the start of the 4th decade (t = 3), when the estimated population of City A is approximately 32.7 thousand people, and the estimated population of City B is approximately 19.2 thousand people.

Part D:

The models may not realistically predict population growth over very long time scales, as they do not take into account factors such as changes in birth and death rates, migration patterns, and economic or environmental changes that may affect population growth. Additionally, the models assume that population growth will continue to follow a linear or exponential pattern, which may not be accurate in the long term. Therefore, while the models can provide useful estimates for short- to medium-term population trends, they should be used with caution when making long-term projections.

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The correct question should be:

The estimated population, in thousands of people, of city A can be modeled by the function SO) = 15(1.03), where is the number of decades (10-year period) since 1980 The estimated population, in thousands of people, of the city can be modeled by the function (1)-0.41 +16, where is the number of decades since 1980

Part A)     Complete this table, showing both estimated population values, rounded to the nearest tenth for each city based on the number of decades since 1980 Estimated Populations of Cities A and B City Decades Since 1980 City B (thousands of people) (thousands of people) 0 . 2 3 4

Part B)      Using the table in Part A, complete this table showing population increases, in hundreds of people, cach decade Population Increases from previous Decade for Cities A and B Decades Since 1980, Increase of City A Increase of City B (hundreds of people), (hundreds of people), fin)-(-1) g) -R-1) 2 3 4 Interpret the differences in the increases of the estimated populations of the two cities based on the functions that model cach city's population. Provide evidence to support your answer

Part C)    At the start of which decade will the estimated population of city A first exceed the estimated population of city B? What will be the estimated populations of each city at the start of that decade? Provide evidence to support your answers.

Part D)   Based on the behavior of the functions, do the models realistically predict population growth over very long time scales? Provide evidence to support your answer.

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