Select all that apply please!

Select All That Apply Please!

Answers

Answer 1

Answer:

x= –4/5 , x= 2

Step-by-step explanation:

5x²-6x-14=-6

5x² –6x –14 +6=0

5x²–6x –8=0

(5x+4)(x-2)=0

x=–4/5

x=2

Answer 2

Hi! I'm happy to help!

To solve this, we simply have to replace x with the given values.

First, we have -14, let's apply that:

(5·(-14²))-(6·(-14))-14=

Now, let's solve (using the order of operations):

(5·(-14²))-(6·(-14))-14=

(5·196)-(6·(-14))-14=

980-(6·(-14))-14=

980-(-84)-14=

980+84-14=

1064-14=

1050=

1050≠-6

Option 1 is incorrect.

Next, let's substitute 14 for x:

(5·14²)-(6·14)-14=

Now, let's solve:

(5·14²)-(6·14)-14=

(5·196)-(6·14)-14=

980-(6·14)-14=

980-84-14=

896-14=

880=

880≠-6

Option 2 is incorrect.

Now, let's substitute -7 for x:

(5·(-7²))-(6·(-7))-14=

Now, let's solve:

(5·(-7²))-(6·(-7))-14=

(5·49)-(6·(-7))-14=

245-(6·(-7))-14=

245-(-42)-14=

245+42-14=

287-14=

273=

273≠-6

Option 3 is incorrect.

Now, let's substitute 7 for x:

(5·7²)-(6·7)-14=

Now, let's solve:

(5·49)-(6·7)-14=

245-(6·7)-14=

245-42-14=

203-14=

189=

189≠-6

Option 4 is incorrect.

Now, let's substitute -2 for x, and solve:

(5·(-2²))-(6·(-2))-14=

(5·4)-(6·(-2))-14=

20-(6·(-2))-14=

20-(-12)-14=

20+12-14=

32-14=

18=

18≠-6

Option 5 is incorrect.

Now, let's substitute 2 for x and solve:

(5·2²)-(6·2)-14=

(5·4)-(6·2)-14=

20-(6·2)-14=

20-12-14=

8-14=

-6=

-6=-6

Option 6 is correct.

Now, let's substitute -1 for x and solve:

(5·(-1²))-(6·(-1))-14=

(5·1)-(6·(-1))-14=

5-(6·(-1))-14=

5-(-6)-14=

5+6-14=

11-14=

-3=

-3≠-6

Option 7 is incorrect.

Now, let's substitute 1 for x and solve:

(5·1²)-(6·1)-14=

5-(6·1)-14=

5-6-14=

-1-14=

-15=

-15≠-6

Option 8 is incorrect.

Now, let's substitute -4/5 for x and solve:

(5·(-4/5²))-(6·(-4/5))-14=

(5·0.64)-(6·(-4/5))-14=

3.2-(6·(-4/5))-14=

3.2-(-4.8)-14=

3.2+4.8-14=

8-14=

-6=

-6=-6

Option 9 is correct.

Now let's substitute 4/5 for x and solve:

(5·4/5²)-(6·4/5)-14=

(5·0.64)-(6·4/5)-14=

3.2-(6·4/5)-14=

3.2-4.8-14=

-1.6-14

-15.6

-15.6≠-6

Option 10 is incorrect.

To summarize, you should pick option 6, and option 9.

I hope this was helpful, keep learning! :D


Related Questions

PLS HELP! WILL GIVE BRAINLIEST

Answers

Answer:

csc x sec x

Step-by-step explanation:

csc = 1/sin

1/sin^2    /  cos/sin    =   1 / sin^2    *  sin/cos       =   1 / sin cos  = csc sec

The price of a sandwich decreases from $6 to $4. What is the percent decrease in the price of the sandwich?

Answers

Answer:

33.33%

Step-by-step explanation:

Decrease in price= Original price -- New price

= $6 - $4

= $2

Percentage decrease= $2÷$6 × 100

= 33.33%

6(a+2b+3c)=6, left parenthesis, a, plus, 2, b, plus, 3, c, right parenthesis, equals

Answers

Ok so it would be 13

In a survey of 60 students ,30 drink milk,25 drink curd and 10 students drink as well as curd then.Find the number of students who drink of them.draw a venn-diagram to illustrate the above information.​

Answers

Hope it helps!!!!!!!!!!

Hurry will mark brainiest . There are seven nickels and five dimes in your pocket. Three times, you randomly pick a coin out of your pocket, return it to your pocket, and then mix-up the change in your pocket. All three times, the coin is a nickel. Find the probability of this occurring.
A. 343/1728
B. 1/22
C. 1/8
D. 25/546

Answers

Answer: A. 343/1728

Step-by-step explanation:

All you have to do is multiply (or, in this case, cube) both the numerator and denominator to get the probability.

[tex]\frac{7^{3} }{12^{3} }[/tex] or [tex]\frac{7*7*7}{12*12*12}[/tex]

Enlargements I cannot do can someone help plz

Answers

Answers:

The coordinates of the vertices are

(6,2)(8,2)(8,6)(4,6)

These coordinates are from the red points shown in the diagram below.

=============================================================

Explanation:

Because the center of dilation is at the origin, we'll multiply each coordinate of each point by the scale factor.

Specifically, we'll double the coordinate values since the scale factor is 2.

A point like (3,1) becomes (6,2)A point like (4,1) becomes (8,2)

and so on

The diagram is shown below. The original preimage is in blue while the dilated enlarged image is in red. Your teacher only wants the location of the red corner points.

Simplify the complex fraction: 8/9 / -4

Answers

Step-by-step explanation:

[tex] \frac{ \frac{8}{9} }{ - 4} \\ \frac{8}{9} \times \frac{1}{ - 4} \\ \frac{8 \times 1}{9 \times - 4} \\ \frac{8}{ - 36} \\ \frac{2}{ - 9} \\ - 0.22[/tex]

Answer:

B. [tex] - \frac{2}{9} [/tex] (second option)

Step-by-step explanation:

[tex] \frac{ \frac{8}{9} }{ - 4} [/tex]

[tex] \frac{8}{9} \div 4 = \frac{8}{9} \times \frac{1}{4} [/tex]

[tex] \frac{8 \times 1}{9 \times 4} = \frac{8}{9 \times 4} [/tex]

[tex] - \frac{2}{9} [/tex] ✅

Find the area of this circle

Answers

Answer:

153.86 ft^2

Step-by-step explanation:

π=3.14

r=7ft

πr^2=3.14*7*7

=153.86 ft^2

Area of circle = π

Here , We have

π = 3.14

r = diameter/2r = 14/2 r = 7 ft.

Area of circle = 3.14 × (7)²

Area of circle = 3.14 × 49 ft²

Area of circle = 153.86 ft²

Determine all values of the constant k for which the given set of vectors is linearly independent in R4.{(1,1,0,−1), (1,k,1,1),(5,1,k,1), (−1,1,1,k)}

Answers

If these vectors are to be linearly independent, then there exists some not-all-zero choice for scalars [tex]c_1,c_2,c_3,c_4[/tex] such that

[tex]c_1(1,1,0,-1) + c_2(1,k,1,1) + c_3(5,1,k,1) + c_4(-1,1,1,k) = (0,0,0,0)[/tex]

We can recast this as a system of linear equations,

[tex]\begin{bmatrix}1&1&5&-1\\1&k&1&1\\0&1&k&1\\-1&1&1&k\end{bmatrix}\begin{bmatrix}c_1\\c_2\\c_3\\c_4\end{bmatrix} = \begin{bmatrix}0\\0\\0\\0\end{bmatrix}[/tex]

This system has a solution if the coefficient matrix on the left side is not singular. So we attempt to find k such that it *is* singular, i.e. the determinant is zero:

• A cofactor expansion along the first column gives

[tex]\begin{vmatrix}1&1&5&-1\\1&k&1&1\\0&1&k&1\\-1&1&1&k\end{vmatrix} = \begin{vmatrix}k&1&1\\1&k&1\\1&1&k\end{vmatrix} - \begin{vmatrix}1&5&-1\\1&k&1\\1&1&k\end{vmatrix} + \begin{vmatrix}1&5&-1\\k&1&1\\1&k&1\end{vmatrix}[/tex]

• Cofactor expansions along the first columns of the remaining 3x3 matrices give

[tex]\begin{vmatrix}k&1&1\\1&k&1\\1&1&k\end{vmatrix} = k \begin{vmatrix}k&1\\1&k\end{vmatrix} - \begin{vmatrix}1&1\\1&k\end{vmatrix} + \begin{vmatrix}1&1\\k&1\end{vmatrix} = k^3-3k+2[/tex]

[tex]\begin{vmatrix}1&5&-1\\1&k&1\\1&1&k\end{vmatrix} = \begin{vmatrix}k&1\\1&k\end{vmatrix} - \begin{vmatrix}5&-1\\1&k\end{vmatrix} + \begin{vmatrix}5&-1\\k&1\end{vmatrix} = k^2-4k+3[/tex]

[tex]\begin{vmatrix}1&5&-1\\k&1&1\\1&k&1\end{vmatrix} = \begin{vmatrix}1&1\\k&1\end{vmatrix} - \begin{vmatrix}5&-1\\k&1\end{vmatrix} + \begin{vmatrix}5&-1\\1&1\end{vmatrix} = -k^2 - 6k + 7[/tex]

It follows that

[tex]\begin{vmatrix}1&1&5&-1\\1&k&1&1\\0&1&k&1\\-1&1&1&k\end{vmatrix} = (k^3-3k+2) - (k^2-4k+3) + (-k^2 - 6k + 7) \\\\ \begin{vmatrix}\cdots\end{vmatrix} = k^3 - 2k^2 - 5k + 6 = (k-3)(k-1)(k+2)[/tex]

which makes the coefficient matrix singular if k = 3, k = 1, or k = -2.

Then the four vectors are linearly independent for

[tex]\left\{ k\in\mathbb R \mid k\not\in\{-2,1,3\}\right\}[/tex]

Write the interval notation represented by each description below:
1.
The set of all numbers less than negative ten.
2.
The set of all positive real numbers.
3.
The set of all numbers less than 4.242 and greater than 12.566.
4.
The set of all numbers that are greater than 15 and less than 50.
5.
The set of all numbers that are at most 5.
6.
The set of all numbers that are at least 18.

Thank you so much for your help!

Answers

Answer:

1. (-∞ , -10]

2. [0, ∞ )

3. [12.566, 4.242]

4. [15, 50]

5. (-∞ , 5]

6. [18, ∞)

Step-by-step explanation:

Answer:

1. The set of all numbers less than negative ten.

(- ∞, -10)

2. The set of all positive real numbers.

(0, +∞)

3. The set of all numbers less than 4.242 and greater than 12.566.

(-∞, 4.242 )∪ (12.566, +∞)

4. The set of all numbers that are greater than 15 and less than 50.

(15, 50)

5. The set of all numbers that are at most 5.

(-∞, 5]

6. The set of all numbers that are at least 18.

[18, +∞)

The overall direction of this data is __________. The strength of the association is __________. a.) positive; strong

Answers

Answer:

The overall direction of this data is positive. The strength of the association is strong

Step-by-step explanation:

it might be that the data could be negative and not positive

the strength is perfectly strong

base on the whole statement so

hope that helps>3

The overall direction of the data is positive also the strength of the association is strong.

What is an arithmetic operation?

The four basic mathematical operations are the addition, subtraction, multiplication, and division of two or even more integers. Among them is the examination of integers, particularly the order of actions, which is crucial for all other mathematical topics, including algebra, data organization, and geometry.

The overall trend of the data is positive, and the association is strongly correlated.

To know more about arithmetic operations:

https://brainly.com/question/13585407

#SPJ5

___ minus 14 = 9 times 3​

Answers

Answer: x=41

Step-by-step explanation:

Let x be the number missing

Given expression

x - 14 = 9 × 3

Simplify by multiplication

x - 14 = 27

Add 14 on both sides

x - 14 + 14 = 27 + 14

[tex]\boxed {x=41}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Step-by-step explanation:

[tex]x - 14 = 9 \times 3 \\ x - 14 = 27 \\ x = 27 + 14 \\ x = 41 \\ thank \: you[/tex]

expressions equal to 10^3

Answers

Answer:

1000

Step-by-step explanation:

10³

= 1000

Answer:

10 * 10 * 10

Step-by-step explanation:

Cubing a number just means you are multiplying that number 3 times to itself. Since we have 10^3, we multiply 10 to itself three times.

Best of Luck!

what is
[tex] \frac{28}{141} [/tex]
as a percentage​

Answers

The answer to the question is 17.02

Answer:

19,86%

Step-by-step explanation:

[tex] \frac{28}{141} = 0.198582[/tex]

➡️ [tex]0.1986[/tex]

➡️ [tex]0.1986 \times \frac{100}{100} [/tex]

➡️ [tex] \frac{0.1986 \times 100}{100} [/tex]

➡️ [tex] \frac{19.86}{100} [/tex]

➡️ [tex] = 19.86\%[/tex] ✅

Question 7 of 10
Which of the following can you determine, when you use deduction and start
from a given set of rules and conditions?
A. None of these
B. What must be true
C. What may be false
D. What may be true

Answers

Answer:

what may be true

Step-by-step explanation:

i just took the test and got the answer correct, i hope this helps.

What is 12 divided by 2/5?

Answers

Answer:30

Step-by-step explanation:

Show that the points (3,3) ,. (-2,3) are vertices of an isosceles triangle​

Answers

Answer:

because the points are vertical and an isosceles has vertical sides

-2/3-8=14 please help

Answers

Answer:

-33

Step-by-step explanation:

this math equation looks relatively simple so i assume the actual equation is -2/3x - 8 = 14

add 8

-2/3x =22

multiply by -3/2

answer is -33

Customer are charged a late fee of 20% of their bill. This person is a week late on a bill of $200.00 What should we charge for the late fee?

Answers

Multiply the amount owed by 20% by changing the percent to a decimal.

20% = 0.20

200 x 0.20 = 40

The late fee is $40

Write the number in expanded form 68,020

Answers

Answer:

hope it is helpful

Step-by-step explanation:

68,020-

6= 60,000

8= 8,000

0=0

2= 20

0=0

find the coordinates of the vertex ​

Answers

You can either transform this quadratic equation into a vertex form which would rather painful or use derivatives.

I'll use dervatives. We know that vertex of a quadratic function is either its maxima or its minima, since the leading coefficient [tex]-x^2[/tex] has a negative prefix that means we get a downward turned parabola with minima being the vertex.

First we take the derivative with respect to x,

[tex]\dfrac{d}{dx}-x^2-2x+3=-2x-2[/tex]

The derivative is esentially information what is the slope of a function at a particular x. When the slope is 0 we reached some sort of turning point, such as minima.

We therefore do,

[tex]-2x-2=0\implies x=-1[/tex]

So at [tex]x=-1[/tex] there appears to be a minima or x-coordinate of the vertex of the function.

Plug the coordinate into the function to get y,

[tex]y=f(-1)=-1+2+3=4[/tex]

So the vertex of the function is at [tex]\boxed{(-1,4)}[/tex].

Assuming you don't know derivatives, there is another way.

First compute the roots of the function,

[tex]-x^2-2x+3=0[/tex]

[tex]-(x-1)(x+3)=0[/tex]

[tex]x_1=1,x_2=-3[/tex]

In the middle between [tex]x_1,x_2[/tex] is an x coordinate of a vertex,

[tex]x=\dfrac{x_1+x_2}{2}=\dfrac{1-3}{2}=-1[/tex]

Just like we had before, we compute for y, [tex]h(-1)=4[/tex] and again the result is [tex]\boxed{(-1,4)}[/tex].

Hope this helps :)

Tickets to a band concert cost 10 dollars each

Answers

It 10 bucks each ticket

Answer:

10

Step-by-step explanation:

It 10 bucks each ticket

Solve the equation e2x dy/dx 1 given that y = 5 when x = 0 ​

Answers

Answer:

The equation is

[tex]{ \underline{ \sf{y = - 2 {e}^{ - 2x} + 7 }}}[/tex]

Step-by-step explanation:

[tex]{ \sf{ {e}^{2x} \frac{dy}{dx} = 1}} \\ \\ { \sf{dy = {e}^{ - 2x} dx}}[/tex]

integrate:

[tex]{ \sf{ \int dy = \int { - e}^{2x} dx}} \\ { \sf{y = - 2 {e}^{ - 2x} + c}}[/tex]

c is a constant.

when y is 5, x is 0:

[tex]{ \sf{y = { - 2e}^{ - 2x} + c}} \\ { \sf{5 = - 2 {e}^{( - 2 \times 0)} + c }} \\ { \sf{5 = - 2 {e}^{0} + c }} \\ { \sf{5 = ( - 2 \times 1) + c}} \\ { \sf{5 = - 2 + c}} \\ { \sf{c = 7}}[/tex]

therefore, equation:

[tex]y = - 2 {e}^{ - 2x} + 7[/tex]

If 18 drinks cost £54, how much will 7 drinks cost ?

Answers

Step-by-step explanation:

solution :

cost of 18 drinks (is)=52

-2/5 + 1/2 plz answer need help

Answers

Answer:

solution -2/5+1/2 =-2*2+1*5/5*2 =-4+5/10 =1/10

Compare 7/2 and 10/8

Answers

Step-by-step explanation:

7/2

=3.5

10/8

=1.25

Hence, 3.5>1.25

Therefore, 7/2>10/8

(-1,-6)(-1,-3)(-1,-2)(-4,-2)(-4,1)(-4,4) range

Answers

Answer:

range is the y part and domain is the x so the range is the y coordinates

-6,-3,-2,-2,1,4

Step-by-step explanation:

Determine which of the following mappings are functions. If the relation is not a function, indicate why it is not.

Answers

Answer:

First mapping is a function because there is no more than one output for each input.Second mapping is not a function because there is more than one output for input B.Third mapping is a function because there is no more than one output for each input.Fourth mapping is a function because there is more than one output for each input.

Step-by-step explanation:

A function can be defined as two variables (independent and dependent) which cannot have more than one output for each input.

Step-by-step explanation:

1. the first mapping is a function

2. the second mapping is not a function, because: B has 2 relations, C & E have no relations.

3. the third mapping is a function

4. the fourth mapping is not a function, because B has no relation.

In a class of 25 students, 13 students wear glasses and 12 students do not wear glasses.

The ratio of glasses to non-glasses wearing students is 13:12.

Is this ratio part-to-part or part-to-whole?

Answers

the ratio of students do not wear glass to total students

[tex]\frac{12}{25}[/tex]

the ratio of students wear glass to total number of students is

[tex]\frac{13}{25}[/tex]

Given

In a class of 25 students, 13 students wear glasses and 12 students do not wear glasses

The ratio of glasses to non-glasses wearing students is 13:12.

Explanation :

we need to find the ratio students wear glasses to whole students

There are total of 25 students.

13 students wear glass

So the ratio of students wear glass to total number of students is

[tex]\frac{13}{25}[/tex]

Similarly , we can find the ratio of students do not wear glass to total students

[tex]\frac{12}{25}[/tex]

Learn more :  brainly.com/question/17218035

expand or simplify
3c(5+c) -2(3c-7)​

Answers

3c(5+c) -2(3c-7)
15c+3c^2-6c+14
9c+3c^2+14

Answer:

It is 3c² + 9c + 14

Step-by-step explanation:

[tex]3c(5 + c) - 2(3c - 7)[/tex]

open the brackets:

[tex] = (15c + 3 {c}^{2} ) - (6c - 14) \\ = (15c + {3c}^{2} ) - 6c + 14[/tex]

express in quadratic equation:

[tex]3 {c}^{2} + 9c + 14[/tex]

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