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Tidal energy is the form of energy used to generate electrical energy.

The form of the energy is used to generate electrical energy in a tidal power station is kinetic energy.

Kinetic energy is the energy that an object has as a result of its movement. If we intend to accelerate an object, we should indeed apply force to it. Using force requires us to put in effort.

After work is completed, energy is transmitted to the object, and the object moves at a new constant speed.

Tidal energy is generated by the movement of our tides and oceans, where the intensity of the water from tide rise and fall is a type of kinetic energy.

Tidal power is related to gravitational hydropower, which uses water movement to propel a turbine and generate electricity.

Thus, kinetic energy is used to generate electrical energy in a tidal power station.

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Answer:

John dalton discovered

Answer:

ω = 1.7 rad/s

Explanation:

Conservation of angular momentum

Assuming the rod is initially hanging vertically at rest.

Initial angular momentum is carried by the bullet only

L = Iω = (mR²)(v/R) = mvR = 0.020(200)(0.7) = 2.8 kg•m²/s

the same angular momentum exists after impact, only the moment of inertia has increased by that of the rod. I = ⅓mR²

2.8 = (⅓(10)(0.7²) + 0.020(0.7²))ω

2.8 = (1.64313333...)ω

ω = 1.70406134...

Answer:

Now the electroscope will allow you to identify whether an object is positively or negatively charged. If you bring a negative object near the electroscope, the electrons in the scope will be repelled toward the leaves, balancing the charge.

Explanation:

The electrostatic force obeys the principle of linear super-position which basically states

that force between two particles does not get affected by the charge of the other and hence if the

rod is brought close to a suspended metal needle and is getting attracted then needle definitely

should possess opposite charge relative to the rod or basically negative charge as opposite charges

attract.

(b) In case the needle which is brought near the sus[ended needle and gets repelled that shows that

both of them possess same charge and hence positive charge on both objects and will start

repelling each other.

Answer:

A. The reactions taking place in a cold pack

Explanation:

This is because in a cold pack, there is no heat gained therefore a reaction stands by losing it's own heat to the surrounding.

[tex].[/tex]

Answer:

b

Explanation:

Answer:

Explanation:

651.9 mm                =  0.6519 m

71 V                         = 71 V

910 mg                    = 0.000910 kg

30.0 ps                    = 0.000 000 000 030 0 s

22.5 fm                    = 0.000 000 000 000 022 5 m

2.00 gigavolts         = 2 000 000 000 V

With a density of 0.875 g/cm³, a sample of 0.60 g of this oil would have a volume V such that

0.875 g/cm³ = (0.60 g)/V   ==>   V ≈ 0.686 cm³

If the oil is spread out uniformly over the water's surface, then it forms a cylinder whose diameter is equal to that of the dish, 21.6 cm. Then the thickness d of the oil cylinder is such that

V = π ((21.6 cm)/2)² d   ==>   d ≈ 0.0202 cm

Answer:

Explanation:

attracted

a) La Distancia entre el telescopio y el satélite es aproximadamente [tex]8.602\times 10^{5}[/tex] metros.

b) La señal sale del telescopio y se desplaza [tex]7\times 10^{5}[/tex] metros en Dirección + x y [tex]5\times 10^{5}[/tex] metros en Dirección +y.

a) Si asumimos la Posición del telescopio como el Origen de un Marco de Referencia, entonces la Distancia entre el telescopio y el satélite ([tex]d[/tex]), en metros, mediante la siguiente expresión:

[tex]d = \sqrt{(S(x,y) - O(x,y))\,\bullet\,(S(x,y) - O(x,y))}[/tex] (1)

Donde:

Si sabemos que [tex]O(x,y) = (0, 0)[/tex] y [tex]S(x,y) = (7\times 10^{5}, 5\times 10^{5})[/tex], entonces la Distancia entre el telescopio y el satélite es:

[tex]d = \sqrt{(7\times 10^{5})^{2}+(5\times 10^{5})^{2}}[/tex]

[tex]d \approx 8.602\times 10^{5}\,m[/tex]

Nota - (1) es una forma vectorial del Teorema de Pitágoras.

La Distancia entre el telescopio y el satélite es aproximadamente [tex]8.602\times 10^{5}[/tex] metros.

b) La señal sale del telescopio y se desplaza [tex]7\times 10^{5}[/tex] metros en Dirección + x y [tex]5\times 10^{5}[/tex] metros en Dirección +y.

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Answer:

a) v = 4.9 m/s at 62° above the horizontal

b) h = 0.94 m above the board or 4.94 m above the water

c) v = 10 m/s at 77° below the horizontal

Explanation:

Assume UP and FOREWARD are positive and the diving board is the origin.

Ignore air resistance.

s = s₀ + v₀t + ½at²

In the vertical

-4 = 0 + vy₀(1.3) + ½(-9.8)(1.3²)

vy₀ = 4.281 m/s

in the horizontal

3.0 = 0 + vx₀(1.3) + ½(0)(1.3²)

vx₀ = 2.307... m/s

v = √(4.281² + 2.307²) = 4.863...

tanθ = 4.281 / 2.307

θ = 61.680...

v² = u² + 2as

s = (v² - u²) / 2a

h = (0² - 4.281²) / 2(-9.8) = 0.9350...

v² = 4.863² + 2(9.8)(4)

v = 10.1019...

cosθ = 2.307/10.1019

θ = 76.798

(a) The initial velocity of Samuel is 4.02 m/s

(b) The maximum height reached by Samuel is 0.55 m

(c)  The final velocity when he enters the water is 5.20 m/s

The given parameter:

(a) The initial velocity of Samuel is calculated as;

[tex]h = v_o_y t + \frac{1}{2} gt^2\\\\[/tex]

Assume downward motion to be in negative direction

The vertical component of the velocity is calculated as;

[tex]4 = 1.3\times v_0_y + 0.5\times 9.8\times 1.3^2\\\\4 = 1.3v_{0y} + 8.281\\\\1.3v_{0y} = 4- 8.281\\\\1.3v_{0y} = -4.281\\\\v_{0y} = \frac{-4.281}{1.3} \\\\v_{0y} = -3.293 \ m/s\\\\v_{0y} = 3.293 \ m/s \ \ \ (downwards)[/tex]

The horizontal component of the velocity is calculated as;

Assume forward motion to be in positive direction

[tex]x = v_{0x}t \\\\3 = 1.3v_{0x}\\\\v_{0x} = \frac{3}{1.3} \\\\v_{0x} = 2.308 \ m/s[/tex]

The resultant of initial velocity is calculated as;

[tex]v_0 = \sqrt{v_{0y}^2 + v_{0x}^2} \\\\v_0 = \sqrt{3.293^2 + 2.308^2} \\\\v_0 = \sqrt{16.17} \\\\v_0 = 4.02 \ m/s[/tex]

(b) The maximum height reached by Samuel is calculated as;

[tex]v_f_y^2 = v_0_y^2 + 2gh\\\\at \ maximum \ height \ v_{fy} = 0\\\\0 = v_0_y^2 + 2gh\\\\-2gh = v_0_y^2\\\\h = \frac{v_0_y^2}{-2g} \\\\h = \frac{(3.293)^2}{-2\times 9.8} \\\\h = -0.55 \ m\\\\h = 0.55 \ m \ (downwards)[/tex]

(c) The final velocity when he enters the water;

The height traveled before he hits the water, h = 0.55 m

[tex]v_f^2 = v_{0}^2 + 2gh\\\\v_f^2 = (4.02)^2 + (2\times 9.8\times 0.55)\\\\v_f^2 = 26.94\\\\v_f = \sqrt{26.94} \\\\v_f = 5.20 \ m/s[/tex]

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[tex]\boxed{\sf R=\rho\dfrac{\ell}{A}}[/tex]

Or

[tex]\\ \rm\hookrightarrow \rho=R\dfrac{A}{l}[/tex]

Answer:

98.105610 Kilometers

Explanation:

Rounded to 8 digits

Answer:

98.11 km

Explanation:

60.96 mi (5280ft/mi)(12 in/ft)(2.54 cm/in)(1 m/ 100cm)(1 km/1000 m) = 98.10561024 km

however, reporting this precision to the nearest hundred millionth of a kilometer is silly as we only know the mile dimension to the nearest hundredth of a mile.

A hundredth of a mile is 5280/100 = 52.8 ft or just over 16 m

It would only be a little bit of a presumption to give our precision to the nearest 10 meters as I have done.

This also fits neatly into the significant digits rule. Both the original dimension and the converted dimension have four significant digits.

Explanation:

As the astronaut jumps and reaches the highest point, he is momentarily at rest, i.e.

[tex]v=0[/tex]

We also know

[tex]u=3, s=15[/tex]

By the formula,

[tex]v^2-u^2=2as[/tex]

where a is the acceleration of objectc due to gravity,

[tex]0^2-3^2=2a(15)[/tex]

[tex]-9=30a[/tex]

[tex]a=-0.3 ms^{-2}[/tex]

where negative sign indicates a downwards acceleration.

Answer:

b

Explanation:

the law says that energy can not be created or destroy but can be transform from one energy to another.

Answer:

19.284

or

9.33

Explanation:

Answer:

1.66

Explanation:

Found answer on chegg. Works for acellus

Answer:

1.33 mA

Explanation:

V=IR

I=10/(7.5×10³)

=1.33×10-³A

=1.33mA

Explanation:

Solution,

Volume (v)=287 cm^3

Mass(m)=816 g

Density(d)=m/v

=816/287

=2.84

So, the density of the block of marbles is 2.84 g/cm^3.

I hope it helped U

stay safe stay happy

Answer:

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Answer:

50km/hr is the velocity of a car that traveled a total of 75 km North in 1.5 hours.

Scientific laws are summaries or statements that describe a wide range of observations and results of experiments.

Scientific theories, on the other hand, are explanations for observations and results.

So, laws describe what happens and theories explain why things happen.

hope this help! ^^

Answer: the location from where the black ball was thrown from because after the collision the  velocity will make it still go further not stop

Explanation:

Answer:

175m

Explanation:

So it’s travelling at 35metres/1second so if we want to find 5 seconds we can do this…

[tex]\frac{35}{1} \frac{x}{5}.... so[/tex] 35x5 ÷ 1 = 175m/5 seconds

Answer:

175 is the right answer 35×5=175

Explanation:

175

There's a problem with the given information, but I'll get to that later.

Use Newton's second law. When F₂ points east, we have

F₁ + F₂ = (30 kg) (5.0 m/s²) = 150 N

and when F₂ points west, it acts in the opposite direction and

F₁ - F₂ = (30 kg) (10 m/s²) = 300 N

Solve for F₁ and F₂ : we have

(F₁ + F₂) + (F₁ - F₂) = 150 N + 300 N

2F₁ = 450 N

F₁ = 225 N

and

(F₁ + F₂) - (F₁ - F₂) = 150 N - 300 N

2F₂ = -150 N

F₂ = -75 N

But F₁ and F₂ are magnitudes, so they must be positive! Also, it doesn't make sense that when the forces both point east, the mass accelerates less than it does when the forces work against each other. Probably one of the given accelerations are supposed to point west instead of east.

If the scatter plot shows the number of minutes Guya practiced the flute each day in a given week, then Guya practiced 20 minutes on Tuesday, therefore the correct answer is option C.

A set of dots plotted on a horizontal and vertical axis is known as a scatter plot. Because they may demonstrate the degree of connection, if any, between the values of observed quantities or events, scatter plots are crucial in statistics.

As given in the problem If the scatter plot shows the number of minutes Guya practiced the flute each day in a given week,

The x coordinates is showing the days of practice and the y coordinate is showing the number of minutes he practiced the flute on a given day,

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Answer:

m=30kg

Explanation:

m=[tex]\frac{F}{a}[/tex]        ............(1)

F=150N

a=?

a=[tex]\frac{vf-vi}{t}[/tex]

a=[tex]\frac{30-10}{4}[/tex]

a=[tex]\frac{20}{4}[/tex]

a=5ms^-2

Putting the value of "F" and "a" in eq (1),

m=[tex]\frac{150}{5}[/tex]

Answer:

gravitational lensing

Explanation:

Answer:

Gravitational lensing

Explanation: