Please determine the solution to this quadratic function x^2+5x+2
Answer:
A
Step-by-step explanation:
Please best awnswer gets brainliest
Answer: he was a stranger or a hunter
Step-by-step explanation: I think this because it says that they covered him with their muskets and muskets are obviously kind of gun, so it had to be a stranger or hunter. hope this helped if not sorry
There are 18 boys in a class. There are a fewer boys than girls. How many students are there?
Solve for r 7 = 0.2(r + 3) - -5
Answer:
57 for the way you wrote it. -10 if you write it backwards.
Step-by-step explanation:
2(3x-5)+3x+3=20 solve for x
Answer:
= 9x−7
Step-by-step explanation:
=(2)(3x)+(2)(−5)+3x+3
=6x+−10+3x+3
Combine Like Terms:
=6x+−10+3x+3
=(6x+3x)+(−10+3)
=9x+−7
please help pleaseeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee
Answer:
-4 5/12
Step-by-step explanation:
-23/3 + (-11/2) + 35/4
Find a common denominator (12).
-92/12 + (-66/12) + 105/12
Reform the equation to have this as a single fraction.
(-92 + (-66) + 105)/12
Subtract 66 from -92 to get -158.
(-158 + 105)/12
Add 105 to -158 to get -53.
-53/12
Convert into a mixed number by dividing by 12.
-4 5/12 (Choice A) is your answer.
PLS HELP DUE TODAY
Equation and explain
Answer:
8 divided by 1/4 = 2
12 divided by 1/4 = 3
more cows were put in the barn
Step-by-step explanation:
8 horses 1/4= 2
12 horses 1/4= 3
NEED HELP AAAH!!!!!!!!
Answer:
x = 13
Step-by-step explanation:
We have the expression -26 - 2x = 13 - 5x and are asked to solve for x.
To solve we need to isolate x.
-26 -2x = 13 - 5x
Add 26 to both sides :
-2x = 39 - 5x
Add 5x to both sides :
3x = 39
Divide 3 from both sides :
x = 13
Solve the equation. Show your work, or explain your reasoning.
-3x - 5 = 16
The tickets for the school play are $7.00 for adults and $5.00 for students. There were 100 tickets sold. If the total profit was $550.00, how many of each were sold?
Answer:
25 adult tickets and 75 student tickets were sold.
Step-by-step explanation:
Given that the tickets for the school play are $ 7.00 for adults and $ 5.00 for students, and that there were 100 tickets sold generating a total profit of $ 550.00, to determine how many of each were sold the following calculation must be performed:
100 x 5 = 500
550 - 500 = 50
7 - 5 = 2
50/2 = 25
100 - 25 = 75
(25 x 7) + (75 x 5) = X
175 + 375 = 550
Therefore, 25 adult tickets and 75 student tickets were sold.
A study is done to determine if students in the California state university system take longer to graduate than students enrolled in private universities. One hundred students from both the California state university system and private universities are surveyed. From years of research, it is known that the population standard deviations are 1.5811 years and 1 year, respectively. The following data are collected.
The California state university system students took on average 4.5 years with a standard deviation of 0.8.
The private university students took on average 4.1 years with a standard deviation of 0.2.
Required:
Conduct a hypothesis test at the 5% level.
Answer:
Step-by-step explanation:
From the given information:
sample size n = 100
Since the population is assumed to be normal. then:
[tex]\overline X _{state} - \overline X_{private} \sim N(\overline X _{state}-\overline X _{private, SD^2_{state} + SD^2_private} -2\times Cov(\overline X _{state} - \overline X_{private}})}[/tex]
[tex]\overline X _{state} - \overline X_{private} \sim N(4.5-4.1, 0.8^2 + 0.2^2 -2\times 0})}[/tex]
[tex]\overline X _{state} - \overline X_{private} \sim N(0.4, 0.68})}[/tex]
The test statistics:
[tex]z = \dfrac{\overline X_{state} - \overline X_{private} }{ \sqrt{\dfrac{\sigma^2_{state}}{n } + \dfrac{\sigma^2_{private}}{n } } }[/tex]
[tex]z = \dfrac{0.4 }{ \sqrt{\dfrac{1.5811^2}{100 } + \dfrac{1^2}{100 } } }[/tex]
z = 2.138
Using the z tables;
P-value = (Z> 2.138)
P-value = 1 - (Z<2.138)
P-value = 1 - 0.9837
P-value = 0.0163
Decision rule: to reject the null hypothesis if the p-value is less than the significance level
Conclusion: We reject the null hypothesis and conclude that there is enough evidence to conclude that the average time it requires for the students to graduate from a private university is lesser than that of the time it takes such student to graduate from the California state university system.
The three lengths 3, 10, 7 create a triangle.
Answer:
false
Step-by-step explanation:
I assume this is a true/false question.
The answer would be 'false'.
For 3 segments to make a triangle, each single side must be LESS than the sum of the other two.
Here, that is not the case. The '10' side is not less than 3+7.
A circle is centered at J(3, 3) and has a radius of 12.
Where does the point F(-6,-5) lie?
Choose 1 answer:
A.- Inside the circle
B.-On the circle
C.- Outside the circle
Answer:
[tex](-6,\, -5)[/tex] is outside the circle of radius of [tex]12[/tex] centered at [tex](3,\, 3)[/tex].
Step-by-step explanation:
Let [tex]J[/tex] and [tex]r[/tex] denote the center and the radius of this circle, respectively. Let [tex]F[/tex] be a point in the plane.
Let [tex]d(J,\, F)[/tex] denote the Euclidean distance between point [tex]J[/tex] and point [tex]F[/tex].
In other words, if [tex]J[/tex] is at [tex](x_j,\, y_j)[/tex] while [tex]F[/tex] is at [tex](x_f,\, y_f)[/tex], then [tex]\displaystyle d(J,\, F) = \sqrt{(x_j - x_f)^{2} + (y_j - y_f)^{2}}[/tex].
Point [tex]F[/tex] would be inside this circle if [tex]d(J,\, F) < r[/tex]. (In other words, the distance between [tex]F\![/tex] and the center of this circle is smaller than the radius of this circle.)
Point [tex]F[/tex] would be on this circle if [tex]d(J,\, F) = r[/tex]. (In other words, the distance between [tex]F\![/tex] and the center of this circle is exactly equal to the radius of this circle.)
Point [tex]F[/tex] would be outside this circle if [tex]d(J,\, F) > r[/tex]. (In other words, the distance between [tex]F\![/tex] and the center of this circle exceeds the radius of this circle.)
Calculate the actual distance between [tex]J[/tex] and [tex]F[/tex]:
[tex]\begin{aligned}d(J,\, F) &= \sqrt{(x_j - x_f)^{2} + (y_j - y_f)^{2}}\\ &= \sqrt{(3 - (-6))^{2} + (3 - (-5))^{2}} \\ &= \sqrt{145} \end{aligned}[/tex].
On the other hand, notice that the radius of this circle, [tex]r = 12 = \sqrt{144}[/tex], is smaller than [tex]d(J,\, F)[/tex]. Therefore, point [tex]F[/tex] would be outside this circle.
Answer:
outside the circle
Step-by-step explanation:
khan
A sign says that the price marked on all music equipment is 30℅ off the original price. you buy an electric guitar for the sale price of $315. How much money did you save
Can somebody help me plleeeaseee
Answer: A
Step-by-step explanation:
26/400 = x/56,000
6.5% of the products are defective so you can just use that information to find the total defective.
.065 x 56,000 = 3,640
Answer:
3,640
Step-by-step explanation:
First find the percent of products that were defective out of 400.
26 ÷ 400 = 0.065 or 6.5%
Then find 6.5% of 56,000.
56,000 × .065 = 3640
RUBU
Uuuuu 25 pizzas tor her birthday party. Each pizza has 8 slices. How many slices of pizza a
there altogether?
2. 225 bottles of mineral water can be packed in a cardboard box. How many bottles can be
accommodated in 8 such boxes?
Answer:
200 slices
28.125 bottles and if you need to round it is 28
Step-by-step explanation:
10 x 5 / 2 x 4533432
DON'T USE CALCULATOR AND SHOW YOUR WORK OR NO BRIANLEST
Answer:
113335800
Step-by-step explanation:
solve it step by step
10 x 5/2 is 25
25 x 4533432= 113335800
Answer:
113335800
Step-by-step explanation:
10x5=50
2x4533432=9066864
9066864+50=113335800
find a curve that passes through the point (1,-2 ) and has an arc length on the interval 2 6 given by 1 144 x^-6
Answer:
[tex]f(x) = \frac{6}{x^2} -8[/tex] or [tex]f(x) = -\frac{6}{x^2} + 4[/tex]
Step-by-step explanation:
Given
[tex](x,y) = (1,-2)[/tex] --- Point
[tex]\int\limits^6_2 {(1 + 144x^{-6})} \, dx[/tex]
The arc length of a function on interval [a,b]: [tex]\int\limits^b_a {(1 + f'(x^2))} \, dx[/tex]
By comparison:
[tex]f'(x)^2 = 144x^{-6}[/tex]
[tex]f'(x)^2 = \frac{144}{x^6}[/tex]
Take square root of both sides
[tex]f'(x) =\± \sqrt{\frac{144}{x^6}}[/tex]
[tex]f'(x) = \±\frac{12}{x^3}[/tex]
Split:
[tex]f'(x) = \frac{12}{x^3}[/tex] or [tex]f'(x) = -\frac{12}{x^3}[/tex]
To solve fo f(x), we make use of:
[tex]f(x) = \int {f'(x) } \, dx[/tex]
For: [tex]f'(x) = \frac{12}{x^3}[/tex]
[tex]f(x) = \int {\frac{12}{x^3} } \, dx[/tex]
Integrate:
[tex]f(x) = \frac{12}{2x^2} + c[/tex]
[tex]f(x) = \frac{6}{x^2} + c[/tex]
We understand that it passes through [tex](x,y) = (1,-2)[/tex].
So, we have:
[tex]-2 = \frac{6}{1^2} + c[/tex]
[tex]-2 = \frac{6}{1} + c[/tex]
[tex]-2 = 6 + c[/tex]
Make c the subject
[tex]c = -2-6[/tex]
[tex]c = -8[/tex]
[tex]f(x) = \frac{6}{x^2} + c[/tex] becomes
[tex]f(x) = \frac{6}{x^2} -8[/tex]
For: [tex]f'(x) = -\frac{12}{x^3}[/tex]
[tex]f(x) = \int {-\frac{12}{x^3} } \, dx[/tex]
Integrate:
[tex]f(x) = -\frac{12}{2x^2} + c[/tex]
[tex]f(x) = -\frac{6}{x^2} + c[/tex]
We understand that it passes through [tex](x,y) = (1,-2)[/tex].
So, we have:
[tex]-2 = -\frac{6}{1^2} + c[/tex]
[tex]-2 = -\frac{6}{1} + c[/tex]
[tex]-2 = -6 + c[/tex]
Make c the subject
[tex]c = -2+6[/tex]
[tex]c = 4[/tex]
[tex]f(x) = -\frac{6}{x^2} + c[/tex] becomes
[tex]f(x) = -\frac{6}{x^2} + 4[/tex]
You can use the formula for finding the arc length on specified interval on x axis.
The curves whose arc length on the given interval is described are
[tex]f(x) = 6x^{-2} -8[/tex]
and
[tex]f(x) = -6x^{-2} + 4[/tex]
What is the length of the arc of a function f(x) from x = a to x = b?If the function is differentiable in the given interval, then we have:
[tex]s = \int_a^b\sqrt{(1 + (f'(x))^2)}\:dx[/tex]
where s denotes the length of the arc of the given function from x = a to x = b
Using the above formula, as we're already given the arc length, thus,
[tex]\int_a^b\sqrt{(1 + (f'(x))^2)}\:dx = \int_2^6\sqrt{(1 +144x^{-6})}\:dx[/tex]
This gives us
[tex]f'(x) = \pm \sqrt{144x^{-6}} = \pm 12x^{-3}[/tex]
Integrating both sides with respect to x, we get:
[tex]f(x) = \pm \int 12x^{-3}\\\\f(x) = \pm 6x^{-2} + c[/tex]
where c is constant of integration.
Since the curve passes through (1,-2), thus, putting f(x) = -2, x = 1, we get:
[tex]f(x) = \pm 6x^{-2} + c\\-2 = \pm 6 + c\\c = -2 \mp 6 = -8, or ,4[/tex]
c = -8 when we have [tex]f(x) = 6x^{-2} + c[/tex]
c = + 4 when we have [tex]f(x) = -6x^{-2} + c[/tex]
The curves whose arc length on the given interval is described are
[tex]f(x) = 6x^{-2} -8[/tex]
and
[tex]f(x) = -6x^{-2} + 4[/tex]
Learn more about length of the arc of a curve here:
https://brainly.com/question/14319881
A piggy bank contains 3 pennies, 4 nickels, 4 dimes and 9 quarters. Two coins
are selected at random. There is replacement. What is the probability of 1 penny
and 1 nickel?
Answer:
1325/10000
Explain Step By Step Answer
On a scale drawing, the scale is 12 inch = 1 foot. What are the dimensions on the scale drawing for a room that is 22 feet by 17 feet?
Answer:
......
Step-by-step explanation:
Answer
11 inches by 8.5 inches
Step-by-step explanation:
We can use proportions to solve this problem, drawing on top, real life on bottom
1/2 inch x inches
-------------- = ----------
1 ft 22ft
Using cross products
1/2 * 22 = x*1
11 =x
11 inches
1/2 inch x inches
-------------- = ----------
1 ft 17ft
Using cross products
1/2 * 17 = x*1
8.5 =x
What is the force of an object with a mass of 30 kg and an acceleration of 10 m/s2?
The answer is 300N
C 67 zoom in 11 4 In math class, the following question was a warm-up for students. Write an equivalent expression for the following: 2 (3x + 4y +52) +4(x - y) to the warm-up question? 6.EE.4 · Alex wrote 24x + 4y + 147 Jonah wrote 9x + 4y + 72 Steven wrote 10x + 4y + 10Z Which, if any, of the three students wrote an expression that is equivalert to the warm-up question? Show you work to prove which expressio if any, are equivalent.
Answer:
Alex I think
Step-by-step explanation:
Please join help quickly
Answer:
A hope its right!!
Step-by-step explanation:
Have a good day!
NEED THIS IN 10 MINUTES PLEASE
Answer:
5) $82
6) 300
Step-by-step explanation:
If y=x is your linear regression equation, and if x = temperature and y = $ of ice cream sales, then...
5) x = 82, and given that y=x, then y = $82
6) y = $300, and given that y=x, then x = 300
This doesn't really require algebraic calculation, so I wonder if the linear regression equation obtained from the scatter plot is correct.
I’m struggling helplpppppppppppppp
Answer:
The scale factor would be 3
Step-by-step explanation:
do 12/4 and get 3
The perimeter of the rectangle is 72cm. The width of he rectangle is 8cm greater than the length. Find the width and the length.
perimeter = 72 cm
width = x
length = x+8
perimeter of rect. = 2(l+b)
2(x+x+8) = 72
2(2x+8) = 72
4x + 16 = 72
4x = 56
x = 56|4
x= 14
hence width is 14 so ,length will
14+ 8 = 22
hope it helps and your day will full of happiness
There are 8,427 trees in the
state park. The governor is
planning to plant 3 times as
many trees over the next few
years. How many trees will
there be when she is done?
200 W
€
Answer:
35
Step-by-step explanation:
Hope this helps
==========================================================
Explanation:
There are currently 8,427 trees. Triple this value to get 3*8427 = 25,281
Add this result onto the previous number of trees to get 25,281+8,427 = 33,708
-----------
An alternative approach:
if we started off with x number of trees, and then added on three times as much, then we add on 3x more trees. This gets us x+3x = 4x trees total.
In this case, x = 8427, so that leads to 4*x = 4*8427 = 33,708
I need the answer because I thought it was 39 but was not sure if 39 was the answer
Answer:
I believe you are correct
Step-by-step explanation:
hope I am right
Find the equation of the regression line that relates the variable you chose in question 3 (use this variable as the x-value) to the total weight of discarded garbage (use this variable as the y-value). Write your equation in y = mx + b form, and round your values of m and b to two decimal places.
Answer:
See Explanation
Step-by-step explanation:
The question has missing details as no link is provided to the "question 3".
However, I'll give a worked solution on how to calculate the equation of a regression line.
Using the following data:
[tex]\begin{array}{cc}x & {y} & {43} & {99} & {21} & {65} \ \\ {25} & {79} & {42} & {75} \ \end{array}[/tex]
Calculate the equation of the regression line.
The equation is calculated using:
[tex]y = mx + b[/tex]
Where:
[tex]m = \frac{n(\sum xy ) - (\sum x)(\sum y)}{n(\sum x^2) - (\sum x)^2}[/tex]
and
[tex]b = \frac{(\sum y)(\sum x^2) - (\sum x)(\sum xy)}{n(\sum x^2) - (\sum x)^2}[/tex]
So, first we fill in the table with columns x^2, y^2 and xy
[tex]\begin{array}{ccccc}x & {y} & {xy} & {x^2} & {y^2 }& {43} & {99} & {4257} & {1849} & {9801} & {21} & {65} &{1365} &{441} & {4225}\ \\ {25} & {79} & {1975} & {625} & {6241}& {42} & {75} &{3150} & {1764} & {5625}\ \end{array}[/tex]
From the above table.
[tex]\sum x = 43+21+25+42[/tex]
[tex]\sum x = 131[/tex]
[tex]\sum y = 99+65+79+75[/tex]
[tex]\sum y = 318[/tex]
[tex]\sum xy = 4257+1365+1975+3150[/tex]
[tex]\sum xy = 10747[/tex]
[tex]\sum x^2 = 1849 + 441 + 625 + 1764[/tex]
[tex]\sum x^2 = 4679[/tex]
[tex]\sum y^2 = 9801 + 4225 + 6241 + 5625[/tex]
[tex]\sum y^2 = 25892[/tex]
[tex]n =4[/tex]
Solving for m
[tex]m = \frac{n(\sum xy ) - (\sum x)(\sum y)}{n(\sum x^2) - (\sum x)^2}[/tex]
[tex]m = \frac{4 * 10747 - 131*318}{4*4679 -(131)^2}[/tex]
[tex]m = \frac{1330}{1555}[/tex]
[tex]m = 0.86[/tex] --- approximated
Solving for b
[tex]b = \frac{(\sum y)(\sum x^2) - (\sum x)(\sum xy)}{n(\sum x^2) - (\sum x)^2}[/tex]
[tex]b = \frac{318*4679 - 131*10747}{4*4679-131^2}[/tex]
[tex]b = \frac{80065}{1555}[/tex]
[tex]b = 51.49[/tex]
The equation becomes:
[tex]y = mx + b[/tex]
[tex]y = 0.86x + 51.49[/tex]
Apply the above steps and you will arrive at a solution.
Does anyone know 3² + (12r2) - 16 / 4?
Answer:
=12r2+5
Step-by-step explanation:
3² + (12r2) - 16 / 4
9+12r2+−4
Combine like terms
(12r2)+(9+−4)
12r2+5