Sam jumped from a plane. His acceleration was -9.8 m/s². He hit the ground in 30
seconds. What was his velocity just before he hit the ground?

GP Submarine A travels horizontally at 11.0 m/s through ocean water. It emits a sonar signal of frequency f = 5.27× 10³Hzin the forward direction. Submarine B is in front of submarine A and traveling at 3.00 m/s relative to the water in the same direction as submarine A. A crewman in submarine B uses his equipment to detect the sound waves ("pings") from submarine A. We wish to determine what is heard by the crewman in submarine B. (b) In Equation 17.19, the sign of v(S) should be positive.

Recurrence is the quantity of events of a rehashing occasion for each unit of time. It is additionally once in a while alluded to as fleeting recurrence to underscore the difference to spatial recurrence, and customary recurrence to stress the differentiation to precise recurrence. Recurrence is communicated in units of hertz (Hz) which is comparable to one (occasion) each second. The comparing time frame is the time term of one cycle in a rehashing occasion, so the period is the corresponding of the recurrence. Recurrence is estimated in units called hertz (Hz). At the point when one wave passes in a single second its recurrence is 1 wave each second or 1 Hertz. Recurrence and period are really alternate extremes. While period is estimated in seconds per cycle, recurrence is estimated in cycles each second. Think about wave with a time of 2 seconds.

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Gauss law states that the electric flux is defined as the electric field multiplied by the area of the surface in a plane perpendicular to the field.

Mathematically,

Φ=Q ϵo

Where;

Q is enclosed charge

ϵo is the permittivity of the free space

If the charge is moved to another location inside the same cube, the flux in the electric field remains the same. This is because as long as the charge remains within the plane of the electric field, the flux is calculated in all directions and thus the flux remains unchanged. It only changes when the charge is moved outside the cube.

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The sound power incident on the eardrum at the threshold of pain is,

[tex]5 \times 10^{-5} W[/tex]

In physics, the power transferred per unit area is known as the intensity or flux of radiant energy, where the area is measured on a plane perpendicular to the direction of the energy's propagation. Watts per square meter (W/m2) and kilograms per square meter (kg/s3) are the units used in the SI system. With waves like acoustic waves (sound) or electromagnetic waves like light or radio waves, intensity is most usually employed to describe the average power transfer across one period of the wave. Other situations where energy is exchanged can also be described in terms of intensity. One could, for instance, figure out how much kinetic energy each drop of water from a sprinkler is carrying.

Power =  intensity x area

Given:

Area, A = [tex]5 \times 10^{-5} \;m^{2}[/tex]

Intensity, I = [tex]1\;W/m^{2}[/tex]

We know that,

Sound Power, P = [tex]I \times A[/tex]

P = [tex]1 \times 5 \times 10^{-5}[/tex]

P = [tex]5 \times 10^{-5}\;W[/tex]

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The distance between charge 1 and 3 is equal to 20 cm and the force between charge 1 and 3 is equal to force between charge 1 and 3 that is 0.9 Newton and the force between charge 2 and 3 is equal to 1.41 Newton.

Electric charges are basic property of matter carried by some elementary particles that governs how the particles are affected by an electric or magnetic field. Electric charge, which can be positive or negative, occurs in discrete natural units and is neither created nor destroyed.

Coulomb's law states that like charges repel and opposite charges attract, with a force proportional to the product of the charges and inversely proportional to the square of the distance between them.

Given:

Magnitude on charge 1 = 4 μC

Magnitude on charge 2 = 4 μC

Magnitude on charge 3 = 1 μC

Distance between charge 1 and 2 = 32 cm

Distance of charge 3 from center of charge 1 and 2 = 12 cm

Distance between charge 1 and 3 can be find using Pythagoras theorem.

Distance between charge 1 and 3 = √(256 + 144)

Distance between charge 1 and 3 = 20cm

Similarly Distance between charge 2 and 3 = 20cm

Force between charge 1 and 3 can be found using coulomb law.

Force between charge 1 and 3 = (9 × 4 × 1)/40

Force between charge 1 and 3 = 36/40

Force between charge 1 and 3 = 0.9 Newton

Similarly using symmetry, force between charge 2 and 3 = 0.9 Newton

Force between charge 1 and 2 =(9 × 4 × 4)/102

Force between charge 1 and 2 = 1.41 newton

Therefore the distance between charge 1 and 3 is equal to 20 cm and the force between charge 1 and 3 is equal to force between charge 1 and 3 that is 0.9 Newton and the force between charge 2 and 3 is equal to 1.41 Newton.

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The average high from June 11 through June 30 will be 76°F.

a)

The average high temperature for the previous 10 days must first be determined:

(84 + 88 + 91 + 92 + 96 + 94 + 89 + 78 + 87 + 81)/ 10

= 880/10

= 88°

According to the query, 82° is the "average" high temperature on a June day in Albemarle.

therefore,

88° - 82° = 6° is greater than normal

(b)The total of all temperatures for 30 days is 30*80 if the average temperature for 30 days is 80°.

= 2400

As calculated above, the sum of temperatures for the first 10 days is 880. Consequently, the total temperature for the following 20 days is

2400 - 880 = 1520

The mean for last 20 days is

1520/20

= 76°

The average high from June 11 through June 30 will be 76°F

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The value of electric flux will be ​zero.

For a uniform electric field passing through a plane surface,

​electric flux(ϕ) = EAcosθ

where,

θ is the angle between the electric field and the normal to the surface

E is the electric field

A is surface area

(a)

The electric field is perpendicular to the surface,

so,

θ=0

​electric flux(ϕ) = EAcosθ

​electric flux(ϕ)   =(6.20×10⁵N/C)(3.20m²)cos0

​electric flux(ϕ) =1.98×10⁶Vm

(b)

The electric field is parallel to the surface

θ=90°

so,

cosθ=0 and the flux is zero For a uniform electric field passing through a plane surface,

therefore, ​electric flux(ϕ) =0

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The magnitude of the velocity gradient of water is 892.86 s^-1 or 892.86/s

Given:

The shear stress in the fluid is 1 N/m^2

Solution:

The formula for velocity gradient is given below

(dµ / dy)  =  τ / µ

Here τ  is sheer stress, µ is the dynamic viscosity and dµ / dy represents the velocity.

In the above equation, put the values  N/m^2 for τ and 1.12 x 10^-3 Ns/m^2  for μ.

(dµ / dy)  =  1 / 1.12 x 10^-3 Ns/m^2

(dµ / dy)  = 892.86 s^-1

Thus, the magnitude of the velocity gradient of water is 892.86 s^-1 or 892.86/s

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Spectroscopy is the study of the absorption and emission of light and other radiation by matter.

Spectroscopy is the interaction of lights and atoms and the study of the emission and absorption of light.

Spectroscopy can be defined as the study of light absorption as well as its emission. It is also uses to study of structure of atoms.

It offers techniques that has to do with how a sample responds to the radiation of light.

Its applications are:

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The gravitational field strength is 51.6925 N/kg.

We need to know about the gravitational field to solve this problem. The gravitational field is the area where affected by gravitational force. The magnitude of the gravitational field can be calculated by this equation

g = G . m / r²

where g is the gravitational field, G is gravitational constant (6.67 x 10¯¹¹ Nm²/kg²), m is the mass of the planet and r is the radius of the planet

From the question above, we know that

m = 3.10 x 10²⁴ kg

r = 2.00 x 10⁶ m

By substituting the given parameter, we get

g = G . m / r²

g = 6.67 x 10¯¹¹ . 3.10 x 10²⁴/ (2.00 x 10⁶)²

g = 51.6925 N/kg

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Answer:

u have to divide the 2numbers and multiply by 2

Explanation:

The correct answe is South Africa - Economic Growth and Development:

After the formal end of the previous apartheid system two decades ago, South Africa can now boast having one of the richest economies in Africa and a well-functioning democracy. It is the largest economy in Africa, but it also has deeply ingrained structural issues that limit its ability to expand and flourish.

One of the largest economies on the African continent is that of South Africa. However, despite a period of rapid development from 2003 to 2007, its real GDP average yearly growth rate between 2001 and 2010 has been very weak and unquestionably significantly below the African average. A number of African nations have had substantially faster growth rates, which has improved a number of development-related indices.

By the standards of the recent growth records of several Euro Zone nations, South Africa's development is hardly sluggish! One crucial aspect of the economy is that South Africa has achieved relatively modest progress in meeting a number of important development targets and some of the Millennium Development Goals, but her economy does not appear to have achieved the "take-off" required to kick start significant development progress, especially against the backdrop of her deep social problems.

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Answer: I am assuming it is decreases

Explanation: a straight line is 180 degrees. 2 angles both add up to 180 degrees on a straight line. When one increases, the other has to decrease to keep it 180 degrees on a straight line

The calculated mass is 10 kg.

Mass (kg) times acceleration (m/s2) equals force (N). A constant mass item will therefore accelerate in direct proportion to the force exerted. When two objects of differing masses are subjected to the same force, the heavier object accelerates more slowly than the lighter object. Mass times acceleration, or F=m x a, equals force. This means that in order to move an object at the same speed as an object with smaller mass, a stronger force is required.

So, Mass times acceleration equals force

100=Mass×10

To calculate mass on its own, divide 100 by 10 on both sides.

Mass = 10 kg

Because this formula was developed using kg rather than another unit of mass like the slug, the mass is expressed in kg.

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The kinetic energy as measured in the Earth reference frame is 6.704*10^22 Joules.

To find the answer, we have to know about the Lorentz transformation.

It is given that, an alien spaceship traveling at 0.600 c toward the Earth, in the same direction the landing craft travels with a speed of 0.800 c relative to the mother ship. We have to find the kinetic energy as measured in the Earth reference frame, if the landing craft has a mass of 4.00 × 10⁵ kg.

                  [tex]V_x'=0.8c\\V=0.6c\\m=4*10^5kg[/tex]

                  [tex]KE=m_0c^2=\frac{mc^2}{1-(\frac{v_x^2}{c^2} )}[/tex]

                      [tex]V_x'=\frac{V_x-V}{1-\frac{VV_x}{c^2} } \\thus,\\V_x=V_x'(1-\frac{VV_x}{c^2} )+V[/tex]

          [tex]V_x=0.8c(1-\frac{0.8c*0.6c}{c^2} )+0.6c=(0.8c*0.52)+0.6c=1.016c[/tex]

              [tex]KE=\frac{4*10^5*(3*10^8)^2}{\sqrt{1-\frac{(1.016c)^2}{c^2} } } =\frac{1.2*10^{22}}{0.179}=6.704*10^{22}J[/tex]

Thus, we can conclude that, the kinetic energy as measured in the Earth reference frame is 6.704*10^22 Joules.

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Answer:

down below

Explanation:

I assume you're asking about it's orbit around the sun. I believe the Earth's orbit around the sun would be shorter. If the Earth sped up, one can assume that means the days are shorter and the rate at which the Earth orbits the sun would also speed up.

This sounds like an open ended question, so I don't think there can be a wrong answer.

Hope this helps! :)

The magnetic field 40.0 cm away from the middle of the straight cord, in the plane of the two wires is [tex]7.5\times 10^{-9}T[/tex]

Let [tex]B_1[/tex] be inside the plane and [tex]B_2[/tex] be outside the plane . It is required to calculate magnetic field at point A .

Direction of magnetic field at A is calculated using Right hand rule.

[tex]B_{net}=B_2-B_1\\\\B_{net}=\frac{u_0I}{2\pi (0.4-\frac{3\times10^{-3}}{2}) } -\frac{u_0I}{(0.4+\frac{3\times10^{-3}}{2})} \\\B_{net}=7.5\times 10^{-9}T[/tex]

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Answer: The answer is 0.6 volts

Explanation:

As the formula of  Resistance says that

Resistance= Voltage÷ Current  

Where its going to be

Voltage= Resistance÷ Current

Resistance= 120 ohms

Current= 0.005A

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A and B. The pairs that can be the components of a velocity of 30 m s¹ (east) are 20 m s' (east), 10 m s' (east) and 35 m s¹ (east), 5 m s¹ (west).

The resultant velocity of an object is the sum of its individual vector velocities.

For a resultant velocity of 30 m/s east, the component velocities that can equal the resultant velocity is calculated as follows;

35 m/s east and 5 m/s west

let the east direction be positive

let the west direction be negative

R = 35 m/s - 5 m/s

R = 30 m/s east

20 m/s east and 10 m/s east

R = 20 m/s + 10 m/s

R = 30 m/s

Thus, the pairs that can be the components of a velocity of 30 m s¹ (east) are (a) 20 m s' (east), 10 m s' (east) and (b) 35 m s¹ (east), 5 m s¹ (west).

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A pallet jack also known as a pallet truck, is a device used to lift and move heavy or stacked pallets.

A pallet jack, additionally called a pallet truck, pallet pump, pump truck, hand truck, scooter, canine, or jigger is a device used to lift and pass pallets. Pallet jacks are the most fundamental shape of a forklift and are meant to transport pallets within a warehouse.

A pallet jack is the most fundamental form of forklift and is intended to transport pallets in a warehouse or trailer. Pallet jacks are some of the maximum important gear located in warehouses and are used for transporting small masses for quick distances

The pallet jack has a deal with a lever. Slide the prongs into function beneath a pallet and crank the handle up and all the way down to carry the prongs off of the floor. Push or pull the pallet on your favored location and keep the lever right down to decrease the prongs returned to the ground.

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To launch a 100 kg human so that he leaves a cannon moving at a speed of 4 m/s, you need a spring with an appropriate spring constant. This spring will be compressed 2. 0 m from its natural length to launch the person.400N/m spring constant is needed.

The spring constant, k, is a proportional constant. It gauges how firm the spring is. When a spring is compressed or extended to a length that differs by an amount x from its equilibrium length, it produces a force F = -kx that pushes it back towards its equilibrium position.

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The ball that is projected 125 meters straight upward has a total time in the air of: 10.1 s

The formulas for the vertical launch upward and the procedures we will use are:

Where:

Information about the problem:

Applying the maximum height formula and clearing the initial velocity we get:

y max = v₀²/(2*g)

v₀ = √(y max * (2*g))

v₀ = √( 125 m * (2 * 9.8 m/s²))

v₀ = √( 125 m * 19.6 m/s²)

v₀ = √2450 m²/s²

v₀ = 49.497 m/s

Applying the maximum time formula we get:

t max= v₀ / g

t max= 49.497 m/s / 9.8 m/s²

t max = 5.050 s

Applying  the time of flight formula, we get:

t(of) =2 * t max

t(of) =2 * 5.050 s

t(of) = 10.1 s

In physics vertical launch upwards is the motion described by an object that has been launched vertically upwards in which the height and the effect of the earth's gravitational force on the launched object are taken into account.

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The time taken now is 10 s

We know that in this case, the object was projected vertically upward and we know that in this direction the acceleration due to gravity is negative. Then the ball falls straight down to  the ground. We have to use the equation of kinematics under gravity to approach the problem.

We now have that;

h = ut + 1/2gt^2

Considering the downward motion were g is positive u = 0 m/s

h =  1/2gt^2

t = 2h/g

t = √2h/g

t = √ 2 * 125/10

t = 5 s

Given that the time taken to go up is the same as the time taken to come down;

Total time spent in air = 2 (5 s) = 10 s

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The robot is moving with an acceleration of 1.0 m/s.

Magnitude is simply "distance or quantity" in the context of physics. In terms of motion, it shows the absolute or relative size, direction, or movement of an object. It is used to describe something's size or scope. In physics, the term "magnitude" often refers to a size or amount.

Scalar values serve as units of measurement, and scalar multiplication serves as the definition of magnitude. A quantity's magnitude in a particular unit multiplied by that unit equals the original quantity. This is true for all tensor types, including vectors and real-number tensors.

The given parameters;

mass of the toy doll, m = 0.2 kg

mass of the robot, M = 0.3 kg

force applied by the robot, F = 0.3 N

The magnitude of the acceleration of the robot is calculated from Newton's second law of motion;

F = ma

where;

a is the acceleration of the robot

Thus, the magnitude of the acceleration of the robot is 1 m/s²

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The control group for the Michelson-Morley experiment was Interferometer.

The Michelson Morley Experiment was one of the unsuccessful tests that proved the luminiferous ether idea did not exist.

Michelson and Morley attempted to explain how the Earth orbited the sun and how the passage of substances such as ether over the Earth's surface might cause measurable "ether wind."

They attempted to show the idea that the speed of light depends on the size of the ether wind as well as the direction of the beam in relation to it when the light is emitted from an Earthly source. It was supposed that ether was immobile.

The experiment's goal was to measure the speed of light in different directions in order to determine the speed of the ether relative to Earth, so proving its existence.

The theorized material Luminiferous Ether serves as a medium for the transmission of electromagnetic waves such as light rays and X-rays. Ether was thought to be a transmission medium for light propagation.

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Coefficient of static friction between the car’s tires and the road is 0.3

What is static friction ?

A force that holds an object at rest is called static friction. The definition of static friction is: The resistance people feel when they attempt to move a stationary object across a surface without actually causing any relative motion between their body and the surface they are moving the object across.

Give an illustration of static friction.

When something is sitting on a surface, static friction affects it. For instance, every time you place your foot on the trail when trekking in the woods, there is static friction between your shoes and the surface.

Assume that road is level

Friction force provides centripetal force to the car

The weight of the car is = 1250 kg

speed of the car is = 25 m/s

curve radius =r= 175m

we know the formula of centripetal force is given by

[tex]f_{s} =\frac{mv^{2} }{r}[/tex]         where m = mass of the object

                                   v=  velocity

                                    r=  curve radius

and we know  the static force is given by f= μN

                                                                     here, N= mg

so now,

μmg=[tex]\frac{mv^{2} }{r}\\[/tex]

now put the all give values then we get,

[tex]$$\mu_r=\frac{v^2}{r g}=\frac{(25 \mathrm{~m} / \mathrm{sec})^2}{(175 \mathrm{~m})\left(9.8 \mathrm{~m} / \mathrm{sec}^2\right)}$$[/tex]

μ=[tex]\frac{625}{1715}[/tex]

μ= 0.3 , This is the coefficient of friction between the car tire and the rode

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By using Bragg's diffraction, the spacing d is 0.112 nm.

We need to know about Bragg's diffraction to solve this problem. Bragg's diffraction is described how monochromatic light travels through a crystal medium. The monochromatic light should follow

2d.sin(θ) = λ

where d is the spacing between the planes of the crystal, θ is the incident light angle and λ is the wavelength.

From the question above, we know that

θ = 70⁰

λ = 0.210 nm = 0.21 x 10¯⁹ m

By substituting the given parameters, we get

2d.sin(θ) = λ

2d.sin(70⁰) = 0.21 x 10¯⁹

2d . 0.94 = 0.21 x 10¯⁹

d = 1.12 x 10¯¹⁰ m

d = 0.112 nm

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Answer:

Badminton game played with one player per side is true and Badminton game played with two players per side is also true.

Explanation:

The calculated charge density on each plate is 8*10⁻⁸ C/m²

The charge density is a measurement of the amount of electric charge present per unit of surface area, body volume, or field. How much charge is held in a specific field is determined by the charge density. It is possible to calculate charge density in terms of length, area, or volume.

L = 50cm = 0.5m for side length. Q = 4*10⁻⁸C, charge on the plate

= Q/A for surface charge density

Each component's surface charge density is then equal to half of the plate's overall charge density. Thus,

σ(face) = 1/2σ

(face = Q/2A)

(face = Q/2L2) Now that we have Q and L, we can plug in.

σ(face) = 4*10⁻⁸/ 2*0.5²

σ(face) = 4*10⁻⁸ / 0.5

(face) = 8 * 10 ⁻⁸ C/m²

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In the electron-transport chain, as electrons move along a series of carriers, they release energy that is used to pump protons across a membrane.

In plants and animals, the electron transport chain points to the consistent streaming of electrons across cells where electron donors donate electrons and electron acceptors accept electrons through an oxidation-reduction reaction.

As a result of the oxidation-reduction reaction, an electrochemical gradient is created and ATPs are generated for energy purposes.

Moreover, the chain comprises 4 key protein complex molecules that are transferred across the plasma membrane cell.

This cellular process takes place in mitochondria and is responsible for chemical reactions such as photosynthesis and cellular respiration. The four principle steps of this process are Krebs' cycle, glycolysis, oxidative phosphorylation, and pyruvate oxidation.

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The fuel required to gain minimum energy is (3.02 x 10²³ / ΔH) kg.

We need to know about relativistic energy to solve this problem. The rest energy of the object can be determined by

Eo = m₀ . c²

where Eo is rest energy, m₀ is rest mass and c is the speed of light (3 x 10⁸ m/s).

The total energy of object can be described as

E = Eo / √(1 - v²/c²)

where E is total energy, v is the object speed.

From the question above, we know that :

m₀ = 2.4 x 10⁶ kg

c = 3 x 10⁸ m/s

v = 0.7c

Find the rest energy

Eo = m₀ . c²

Eo = 2.4 x 10⁶ . (3 x 10⁸)²

Eo = 2.16 x 10²³ joule

Determine the total energy

E = Eo / √(1 - v²/c²)

E = 2.16 x 10²³ / √(1 - (0.7c)²/c²)

E = 2.16 x 10²³ / 0.71

E = 3.02 x 10²³ joule

Assume that the Heat of Combustion for Space fuel = ΔH J/kg

m = E / ΔH

m = 3.02 x 10²³ /  ΔH kg

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