sam is an astronomer on planet hua, which orbits the distant star barnard. it has recently been accepted that hua is spherical in shape, although its exact size is unknown. while studying in the library, in the city of joy, sam learns that during equinox, barnard is directly overhead in the city of bar, located 1100.0 km north of his location. on the equinox, sam goes outside and measures the altitude of barnard at 78 degrees. what is the radius of hua in km?

(a) The height reached by cat A is 2.5 m.

(b) The speed of cat A before it hits the ground is 36.4 m/s.

(c) The speed of cat B before it hits the ground is 22.39 m/s.

(d) The time spent in air by cat A than cat B is 1.43 seconds.

The time of motion of cat A is calculated as follows;

h = vt - ¹/₂gt

-23 = 7t - 4.9t²

4.9t² - 7t - 23 = 0

solve the quadratic equation using formula method;

a = 4.9, b = -7, c = - 23

t = 3.0 seconds

The time of motion of cat B is calculated as follows;

h = vt - ¹/₂gt

23 = 7t + 4.9t²

4.9t² + 7t - 23 = 0

solve the quadratic equation using formula method;

a = 4.9, b = 7, c = -23

t = 1.57 seconds

h = u²/2g

h = (7²)/(2 x 9.8)

h = 2.5 m

v = u + gt

v = 7  + 3(9.8)

v = 36.4 m/s

v = u + gt

v = 7  + 1.57(9.8)

v = 22.39 m/s

Time difference = 3 s - 1.57 s = 1.43 seconds

Thus, the height reached by cat A is 2.5 m.

The speed of cat A before it hits the ground is 36.4 m/s.

The speed of cat B before it hits the ground is 22.39 m/s.

The time spent in air by cat A than cat B is 1.43 seconds.

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Answer:

D. Time t = 1 [s]

Explanation:

To solve this problem we must use the following equation of kinematics.

[tex]v_{f}=v_{o}-g*t[/tex]

where:

Vf = final velocity = 0 (when the ball reaches the maximum height its elevation won't be increased since the velocity is zero)

vi = initial velocity = 10 [m/s]

g = gravity acceleration = 10 [m/s²]

t = time [s]

Now replacing:

[tex]0 = 10-10*t\\10 = 10*t\\t = 1 [s][/tex]

Answer:

I'll give you all the answers, I know them all, I just did this. I need $1 via cas ap tho since it's hard

The best radioisotope that can be used for radioisotope imaging and for radionuclide therapy is It emits beta particles and gamma rays.

It is a treatment in which ionizing radiation (X-ray, for example) is used to destroy a tumor or prevent its cells from increasing. These radiations are not seen and during the application the patient does not feel anything. Radiation therapy can be used in combination with chemotherapy or other treatments.

in this case, the best radioisotope that can be used for imaging is radionuclide because It emits beta particles and gamma rays.

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Answer:

It emits beta particles and gamma rays.

Explanation:

By the charge density, the curved surface area of the cylinder charge is 0.141 nC.

We need to know about charge density to solve this problem. The charge density can be determined as

λ = Q / A

where λ is charge density, Q is charge and A is surface area.

The parameter given is the charge density and the solid cylinder shape which are :

λ = 15 nC/m²

r = 2.5 cm = 0.025 m

L = 6.0 cm = 0.06 m

Find the curved surface area of cylinder

A = 2πrL

A = 2π. 0.025. 0.06

A = 9.43 x 10¯³ m²

Find the charges

Q = λ x A

Q = 15 x 9.43 x 10¯³

Q = 0.141 nC

Hence, the curved surface area of the cylinder charge is 0.141 nC.

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The study of the physical properties of light, such as its wavelength and amplitude, and the human perception of color is called psychophysics. It comprises two major areas: discrimination and absolute.

The study of wavelength and amplitude, interaction between physical stimuli and their consequential effects such as perceptions and sensations is called psychophysics.

This concept is applied in psychophysics tasks where extensive research and studies are performed on sensory and other visual information.

To put it in simple words, psychophysics is vital for measuring the perception of a subject through stimulus detection experiments.

Stimuli detection is done either through the method of limits, adjustment technique, or constant stimuli method.

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The end of the detergent molecule which attaches to fat (grease) repels water molecules. It is known as hydrophobic, meaning "water fearing." By attempting to move away from the water molecules, the hydrophobic ends of the detergent molecules push up to the surface. This weakens the hydrogen bonds holding the water molecules together at the surface. The result is a break in the surface tension of the water.

Answer:

In a soap-and-water solution the hydrophobic (greasy) ends of the soap molecule do not want to be in the liquid at all. Those that find their way to the surface squeeze their way between the surface water molecules, pushing their hydrophobic ends out of the water. This separates the water molecules from each other.

Explanation:

huhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh

To find limits of the amplitude of motion of real vibrating system that is driven at one of its resonant frequencies, Here the damping of vibrations  turns the energy of vibration into internal energy.

Answer:

Electrical energy

Explanation:

electrical energy Essentials. A battery is a device that stores chemical energy and converts it to electrical energy. The chemical reactions in a battery involve the flow of electrons from one material (electrode) to another, through an external circuit. The flow of electrons provides an electric current that can be used to do work.

The correct answer is 19.7 m/s.

Range is the height of the projectile when it reaches a vertical velocity of zero; after that, gravity will take over and quicken the object's descent. The projectile range, which is determined by the object's initial velocity, is the horizontal displacement of the object projected.

Only when one force is applied at the start of the trajectory does projectile motion occur; thereafter, gravity is the only resistance. A projectile launched under specified beginning circumstances will have a range in physics. Assuming a flat Earth with a consistent gravity field and no air resistance may make it more predictable.

Range R = 38.7 m

Acceleration due to gravity g =9.8 m/s

Launch angle θ = 51

Range of the projectile is given by

R = [tex]u^2[/tex] Sin2θ / g

[tex]u^2[/tex] = gR/ Sin 2θ

u = √gR/ Sin 2θ

u = √ 9.8 × 38.7 / Sin ( 2 × 51)

u = 19.7 m/s.

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The model that correctly represents the product or products of the chemical reaction is the first one. Thus, the correct option for this question is A.

A chemical reaction may be defined as a type of reaction in which one or more substances that are known as the reactants are considerably converted to one or more different substances that are known as the products.

In a chemical reaction, the molecules or atoms of the substance may always remain the same in the reactant or product. That is the mass of the chemical substance may always remain the same. While model 2 and 4 increases the mass of compound A in the given reaction. So, they are eliminated.

Option 3 is incorrect because when you get a product of any chemical reaction, it may never be separated automatically as described in option C.

Therefore, the model that correctly represents the product or products of the chemical reaction is the first one. Thus, the correct option for this question is A.

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Answer:

Imp = 20000 [kg*m/s]

Explanation:

In order to solve this problem we must divide it into two parts. In the first part we must use the following equation of kinematics.

[tex]V_{f}=v_{i}-a*t[/tex]

where:

Vf = final velocity = 0 (the car stops)

Vi = initial velocity = 20 [m/s]

a = acceleration [m/s²]

t = time = 0.5 [s]

Acceleration is negative as the cart slows down as it stops.

[tex]0=20-a*0.5\\20=0.5*a\\a=40 [m/s^{2}][/tex]

The second part is the determination of momentum, which is defined as the product of force over a given time. But to determine the force we must use Newton's second law which tells us that the sum of the forces of a body is equal to the product of mass by acceleration.

∑F = m*a

[tex]F = 1000*40\\F = 40000[N][/tex]

Now the impulse or momentum

[tex]Imp = F*t\\Imp = 40000*0.5\\Imp=20000[kg*m/s][/tex]

Answer:

5000 J

Explanation:

W=F*D

W=500N*10m

w=5000 J

When a man applies a force of 500 N to push a truck 10 m down the street. Then the work of 5000 J has been done.

Work done is the amount energy gained (loosed) in bringing the body from initial position to final position. It is denoted by W and its SI unit is joule(J). i.e. Work(W) is force(F) times displacement(s). W=F× s When a body is displaced with 1 newton of force by 1 m, then we can say that work has been done on the body by 1 joule.

Writing for it's dimension, W=F× s

Force has dimension [L¹ M¹ T²]

Displacement has dimension [L¹]

multiplying both the dimensions Force and Displacement we get, dimension of Work [L² M¹ T²].

Given,

F = 500 N

s = 10 m

Work = Fs = 500×10 = 5000 J

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Answer:

323.4N

Explanation:

Given parameters:

Mass of the box = 33kg

Unknown:

Normal force on the body  = ?

Solution:

The normal force of a body is the vertical force the body exerts on another body.

It is expressed as;

        Normal force  = mass x acceleration due to gravity

Acceleration due to gravity  = 9.8m/s²

Normal force  = 33 x 9.8  = 323.4N

For this we have the hidrostatic equation:

[tex]\boxed{P = \rho gh}[/tex]

Being:

P = Pressure

ρ = Density of liquid (water) = 1000 kg/m

g = Gravity = 9,81 m/s²

h = Height = 4 m

Replacing acording formula:

[tex]\boxed{P = 1000 \ kg/m ^{3} * 9,81 \ m/s^{2} * 4 \ m}[/tex]

Resolving:

[tex]\boxed{P = 39240 \ Pa}[/tex]

Result:

The pression at the bottom is 39240 Pa.

Answer:

2ms^2

Explanation:

A = 2000 divided by 1000

A= 2

Answer:

I would say D. Believable. Sorry if its wrong.

Explanation:

Answer:

ADD ANSWER 5 PTS?

Explanation:

ME : Seriously

BRAINLY: 5 PTS!

Answer:

they require the same amount of work

Explanation:

the formula for work is

W=Fnet*Displacement

and Fnet =m*a

a=9.81 m/s^2

Which gives us

W=ma*d

The set up would be;

(35kg*9.81m/s^2)*4 m=W

(70kg*9.81m/s^2)*2m=W

W= 1373.4 J

Both are the same therefore the correcr answer is *both require the same amount of work*

Answer:

11m/s

Explanation:

Given parameters:

Mass of the lead shot = 8kg

Energy of the shot  = 484J

Unknown:

Velocity of the shot  = ?

Solution:

To solve this problem, we apply the kinetic energy formula;

        K.E  = [tex]\frac{1}{2}[/tex] m v²  

m is the mass

v is the unknown

 Now, insert the parameters and solve;

        484  = [tex]\frac{1}{2}[/tex] x 8 x v²

        484  = 4v²

           v² = 121

            v  = 11m/s

Answer:

add lotion

Explanation:

Answer: True

Explanation:

Answer:

The displacement of the object is -8 m

Explanation:

Displacement

The displacement of a moving object can be calculated as the area under (or above) the graph of velocity vs time.

If the area is below the y-axis, then the displacement is negative. Otherwise is positive.

It's important to differentiate displacement from distance. Displacement takes into consideration the direction of the movement. Distance does not and it's always positive.

From the graph provided, we can see the velocity from t=12 s from t=16 s is negative, and the displacement will also be negative.

The displacement is calculated as the area of the triangle with base b=16-12= 4 seconds and height = -4 m/s, thus:

[tex]\displaystyle D = \frac{4*(-4)}{2}=-\frac{16}{2}=-8\ m[/tex]

The displacement of the object is -8 m