Answer:
Richard will pay $30.
Step-by-step explanation:
Because "x" is equivalent to the amount of video games he rents, you would replace "x" with 5. Do the math, and you would get 10+20=30! Hope this helps!
A train goes past you in 10 seconds and goes past a 100 meter long bridge in 30 seconds. What is the length (in meters) and the speed (inm/s) of the train?
Answer:
Bridge = 300 m
Speed = 10 m/s
Step-by-step explanation:
If a goes past you in 10 seconds, it means the train has speed of
100 m/ 10 seconds as it is 100 m long
The speed in m/s is:
100 m/ 10 s = 10 m/sThen it take 3 times of 10 seconds to cross the bridge, so
The length of the bridge is:
3*100 m= 300 mAnswer:
Length : 50m
Speed : 5 m / s
Which of the following functions is graphed below?
O A. y=x-4-2
O B. y=x+4-2
O C. y = x+4+2
D. y = x - 4+2
Answer:
Option (B)
Step-by-step explanation:
Given question is not complete; find the complete question in the attachment.
In the graph attached,
Parent function is an absolute value function,
f(x) = |x|
When this graph is shifted 4 units left, rule for the translation will be,
f(x) → f(x + 4)
Therefore, the new function of above translation will be,
g(x) = f(x + 4) = |x + 4|
Now the graph is shifted 2 units down so the translated function will be,
h(x) = g(x) - 2
h(x) = |x + 4| - 2
If we rewrite the function in the form of an equation, graph will be represented by
⇒ y = |x + 4| - 2
Therefore, Option (B) will be the answer.
Does this graph show a function? Explain how you know.
O A. No; there are yvalues that have more than one x-value.
ОО
B. Yes; there are no y-values that have more than one x-value.
C. No; the graph fails the vertical line test.
ОО
D. Yes; the graph passes the vertical line test.
It is possible to draw a single straight line to pass through more than one point on the red curve. Therefore, the graph fails the vertical line test. We have cases where one input leads to more than one output.
If 2/3 of a certain number is subtracted from twice the number, the result is 20. Find the number.
Let x be the number.
Set up an equation:
2x - 2/3x = 20
Simplify:
1 1/3x = 20
Divide both sides by 1 1/3
X = 15
The number is 15
the numbers of students in the 10 schools in a district are given below. ( Note that these are already ordered from Least to Greatest) 198, 216, 220, 236, 246, 252, 253, 260, 290, 319. Suppose that the number 319 from this list changes to 369. Answer the following what happens to the median? what happens to the mean?
Answer:median:249
Step-by-step explanation:
median:198] 216} 220] 236] 246 252 [253[ 260 {290[ 369
246 +252=498
498/2=249
as for the mean i will give you that later
Use the distributive property to write an equivalent expression to 2(n + 5)
Answer:
2n + 10.
Step-by-step explanation:
2(n + 5)
= 2 * n + 2 * 5
= 2n + 10.
Hope this helps!
Answer: 2n + 10
Explanation: In this problem, the 2 "distributes" through the parenthses which means that it multiplies by each of the terms inside.
So we have 2(n) + 2(5) which simplifies to 2n + 10.
6x²-7x=20 solve the following quadratic equation
Answer:
x = -4/3 and x = 5/2.
Step-by-step explanation:
6x² - 7x = 20
6x² - 7x - 20 = 0
To solve this, we can use the quadratic formula to solve this.
[please ignore the A-hat; that is a bug]
[tex]\frac{-b±\sqrt{b^2 - 4ac} }{2a}[/tex]
In this case, a = 6, b = -7, and c = -20.
[tex]\frac{-(-7)±\sqrt{(-7)^2 - 4 * 6 * (-20)} }{2(6)}[/tex]
= [tex]\frac{7±\sqrt{49 + 80 * 6} }{12}[/tex]
= [tex]\frac{7±\sqrt{49 + 480} }{12}[/tex]
= [tex]\frac{7±\sqrt{529} }{12}[/tex]
= [tex]\frac{7±23 }{12}[/tex]
[tex]\frac{7 - 23 }{12}[/tex] = [tex]\frac{-16 }{12}[/tex] = -8 / 6 = -4 / 3
[tex]\frac{7 + 23 }{12}[/tex] = [tex]\frac{30}{12}[/tex] = 15 / 6 = 5 / 2
So, x = -4/3 and x = 5/2.
Hope this helps!
Answer:
[tex]x1 = - \frac{4}{3} [/tex][tex]x2 = \frac{5}{2} [/tex]Step-by-step explanation:
[tex]6 {x}^{2} - 7x = 20[/tex]
Move constant to the left and change its sign
[tex] {6x}^{2} - 7x - 20 = 0[/tex]
Write -7x as a difference
[tex]6 {x}^{2} + 8x - 15x - 20 = 0[/tex]
Factor out 2x from the expression
[tex]2x(3x + 4) - 15x - 20 = 0[/tex]
Factor out -5 from the expression
[tex]2x(3x + 4) - 5(3x + 4) = 0[/tex]
Factor out 3x + 4 from the expression
[tex](3x + 4)(2x - 5) = 0[/tex]
When the product of factors equals 0 , at least one factor is 0
[tex]3x + 4 = 0[/tex]
[tex]2x - 5 = 0[/tex]
Solve the equation for X1
[tex]3x + 4 = 0[/tex]
Move constant to right side and change its sign
[tex] 3x = 0 - 4[/tex]
Calculate the difference
[tex]3x = - 4[/tex]
Divide both sides of the equation by 3
[tex] \frac{3x}{3} = \frac{ - 4}{3} [/tex]
Calculate
[tex]x = - \frac{4}{3} [/tex]
Again,
Solve for x2
[tex]2x - 5 = 0[/tex]
Move constant to right side and change its sign
[tex]2x = 0 + 5[/tex]
Calculate the sum
[tex]2x = 5[/tex]
Divide both sides of the equation by 2
[tex] \frac{2x}{2} = \frac{5}{2} [/tex]
Calculate
[tex]x = \frac{5}{2} [/tex]
[tex]x1 = - \frac{4}{3} [/tex]
[tex]x2 = \frac{5}{2} [/tex]
Hope this helps...
Best regards!!
Solve for the unknown quantity, x. Type only the value of x in the answer area.
4
4/x = 50/500
Answer:
x = 40
Step-by-step explanation:
4/x = 50/500
Simplify the right side
4/x = 1/10
Using cross products
4*10 = 1*x
40 = x
Step-by-step explanation:
4/x = 50/500
4/x = 0.1
x = 4/0.1
x = 40
Which would give a significantly smaller value than 1.19 x 10^-2 and which would give a significantly larger value?
1.19 x 10^-2 + 1.07 x 10^-2 smaller or larger?
1.19 x 10^-2 - 1.07 x 10^-2 smaller or larger?
1.19 x 10^-2 x 1.07 x 10^-2 smaller or larger?
1.19 x 10^-2 / 1.07 x 10^-2 (this problem is division) smaller or larger?
Answer:
a) [tex]1.19 \times 10^{-2} + 1.07\times 10^{-2}[/tex] is larger than [tex]1.19\times 10^{-2}[/tex]; b) [tex]1.19 \times 10^{-2} - 1.07\times 10^{-2}[/tex] is smaller than [tex]1.19\times 10^{-2}[/tex]; c) [tex](1.19\times 10^{-2})\cdot (1.07\times 10^{-2})[/tex] is smaller than [tex]1.19\times 10^{-2}[/tex]; d) [tex](1.19\times 10^{-2})/ (1.07\times 10^{-2})[/tex] is greater than [tex]1.19\times 10^{-2}[/tex].
Step-by-step explanation:
a) Is [tex]1.19 \times 10^{-2} + 1.07\times 10^{-2}[/tex] smaller or larger?
1) [tex]1.19 \times 10^{-2} + 1.07\times 10^{-2}[/tex] Given.
2) [tex](1.19+1.07)\times 10^{-2}[/tex] Distributive property.
3) [tex]2.26 \times 10^{-2}[/tex] Addition/Result.
[tex]1.19 \times 10^{-2} + 1.07\times 10^{-2}[/tex] is larger than [tex]1.19\times 10^{-2}[/tex].
b) Is [tex]1.19 \times 10^{-2} - 1.07\times 10^{-2}[/tex] smaller or larger?
1) [tex]1.19 \times 10^{-2} - 1.07\times 10^{-2}[/tex] Given.
2) [tex](1.19-1.07)\times 10^{-2}[/tex] Distributive property.
3) [tex][1.19+(-1.07)]\times 10^{-2}[/tex] Subtraction.
4) [tex]0.12\times 10^{-2}[/tex] Addition/Result.
[tex]1.19 \times 10^{-2} - 1.07\times 10^{-2}[/tex] is smaller than [tex]1.19\times 10^{-2}[/tex].
c) Is [tex](1.19\times 10^{-2})\cdot (1.07\times 10^{-2})[/tex] smaller or larger?
1) [tex](1.19\times 10^{-2})\cdot (1.07\times 10^{-2})[/tex] Given.
2) [tex](1.19\times 1.07)\cdot (10^{-2}\times 10^{-2})[/tex] Associative property/Commutative property.
3) [tex]1.27\times 10^{-4}[/tex] Multiplication/ ([tex]a^{b}\cdot a^{c} = a^{b+c}[/tex])/ [tex](-x)\cdot (-y) = x\cdot y[/tex] /Result.
[tex](1.19\times 10^{-2})\cdot (1.07\times 10^{-2})[/tex] is smaller than [tex]1.19\times 10^{-2}[/tex].
d) Is [tex](1.19\times 10^{-2})/ (1.07\times 10^{-2})[/tex] smaller or larger?
1) [tex](1.19\times 10^{-2})/ (1.07\times 10^{-2})[/tex] Given.
2) [tex](1.19\times 10^{-2})\cdot (1.07\times 10^{-2})^{-1}[/tex] Division.
3) [tex](1.19\times 10^{-2})\cdot (1.07\times 10^{2})[/tex] ([tex](a^{b})^{c} = a^{b\cdot c}[/tex]; [tex](-x)\cdot (-y) = x\cdot y[/tex])
4) [tex](1.19\times 1.07)\cdot (10^{-2}\cdot 10^{2})[/tex] Associative property/Commutative property.
5) [tex]1.27[/tex] Multiplication/([tex](a^{b})^{c} = a^{b\cdot c}[/tex]; [tex]a^{0} = 1[/tex])/Modulative property/Result.
[tex](1.19\times 10^{-2})/ (1.07\times 10^{-2})[/tex] is greater than [tex]1.19\times 10^{-2}[/tex].
Find three consecutive even integers such that the square of the third is 60 more that the square of the second
Answer:
-4,4,16
Step-by-step explanation:
They are all even integers.
-4^2=16
4^2=16
16^2=256
the square of the third,16 is 256 which is more than the square of the second,4=16
The three consecutive even integers such that the square of the third is 60 more than the square of the second are -18, -16 and -14.
What are integers?Any positive or negative number without fractions or decimal places is known as an integer, often known as a "round number" or "whole number."
Given:
Let the three even consecutive integers are 2n-2, 2n and 2n + 2.
According to the question,
So,
(2n + 2)² = (2n)² - 60
4n² + 4 + 8n = 4n² -60
8n = -64
n = -8
That means, the integers are -18, -16 and -14.
Therefore, the required even integers are -18, -16 and -14.
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A central angle is best described as which of the following?
A.
It has a measure greater than 180 degrees.
B.
It is an angle that has its vertex on the circle.
C.
It is an angle that has its vertex at the center of a circle.
D.
It is part of the circumference of a circle.
Answer:
C. It is an angle that has its vertex at the center of a circle.
Step-by-step explanation:
That's the definition.
A. is wrong. An angle with a measure greater than 180° is an obtuse angle,
B. is wrong. An angle that has its vertex on the circle is an inscribed angle.
D. is wrong. Part of the circumference of a circle is an arc.
When evaluating a multiple regression model, for example when we regress dependent variable Y on two independent variables X1 and X2, a commonly used goodness of fit measure is:
Answer:
Adjusted-R2
Step-by-step explanation:
When evaluating a multiple regression model, a commonly used goodness of fit is the adjusted-R2. It allows for a comparison of regression models with multiple predictors or independent variables. The addition of independent variables usually causes the model to be more reliable. The adjusted-R2 considers the effect of additional independent variables. It usually adjusts for the number of terms in the model.
given g(x)=3/x^2+2x find g^-1(x)
Answer:
A
Step-by-step explanation:
[tex]g(x) = \frac{3}{{x}^{2} + 2x} \\ {x}^{2} + 2x - \frac{3}{g(x)} = 0 \\ x = \frac{1}{2} \Big( - 2 + \sqrt{12 + \frac{12}{g(x)} }\Big) \\ x = - 1 + \sqrt{1 \pm \frac{3}{g(x)} } [/tex]
Now replace $x$ by $g^{-1}(x)$ and $g(x)$ by $x$ and you have your answer.
Help ASAP!!!!
Solve for X. Round to the nearest hundredth if necessary.
Answer:
11.47Step-by-step explanation:
Given : A right triangle
To do : Solve for x
Solution,
[tex]cos \: 55 = \frac{x}{20} [/tex] ( by definition of cos function, adjacent / hypotenuse )
[tex]0.5736 = \frac{x}{20} [/tex]
multiply both sides of the equation by 20
[tex](0.5736) \times 20 = x[/tex]
Calculate the product
[tex]11.471 = x[/tex]
Swipe both sides of the equation
[tex]x = 11.471[/tex]
Round answer to nearest hundredth
[tex]x = 11.47[/tex]
Hope this helps...
Best regards!!
What is 3/8 + 1/8 + 2/3 + 1/2 equal?
Answer:
5/3
Step-by-step explanation:
3/8 + 1/8 + 2/3 + 1/2
=> [ 3/8 + 1/8 ] + [ 2/3 + 1/2 ]
=> 1/2( or 4/8 ) + 7/6
=> 10/6 or 5/3
Answer:
[tex] \frac{3}{8} + \frac{1}{8} + \frac{2}{3} + \frac{1}{2} [/tex]
Add the fractions with the same common denominator
That's
[tex] \frac{3}{8} + \frac{1}{8} = \frac{4}{8} = \frac{1}{2} [/tex]
So we have
[tex] \frac{1}{2} + \frac{2}{3} + \frac{1}{2} [/tex]
Add the fractions with the same common denominator
That's
[tex] \frac{1}{2} + \frac{1}{2} = \frac{2}{2} = 1[/tex]
We have
[tex] 1 + \frac{2}{3} [/tex]
That's
[tex] \frac{1}{1} + \frac{2}{3} [/tex]
Find the common denominator
The common denominator is 3
[tex] \frac{1}{1} + \frac{2}{3} = \frac{3 + 2}{3} [/tex]
[tex] = \frac{5}{3} \: \: \: \: \: \: or \: \: \: \: \: \: \: 1 \frac{2}{3} [/tex]
Hope this helps you
Last week Holly took a math test. She got 98 out of 123 question correct. What percentage did Holly get correct? Round to the nearest hundredth.
Answer:
79.67%
Step-by-step explanation:
To find the percentage correct, take the number correct over the total
98/123
.796747967
Change to a percent by multiplying by 100 %
79.6747967%
Round to the nearest hundredth
79.67%
Answer:
79.67%
Step-by-step explanation:
percent = part/whole * 100%
percent = 98/123 * 100%
percent = 79.67%
CAN ANYONE HELP ME PLEASE? Jen Butler has been pricing Speed-Pass train fares for a group trip to New York. Three adults and four children must pay $106. Two adults and three children must pay $75. Find the price of the adult's ticket and the price of a child's ticket.
Answer:
The adult ticket costs $18 and the children ticket costs $13.
Step-by-step explanation:
Let the price of the adult ticket be a.
Let the price of the children ticket be c.
Three adults and four children must pay $106. This implies that:
3a + 4c = 106 _______(1)
Two adults and three children must pay $75. This implies that:
2a + 3c = 75 ________(2)
We have two simultaneous equations:
3a + 4c = 106 _____(1)
2a + 3c = 75 ______(2)
Multiply (1) by 2 and (2) by 3 and subtract (1) from (2):
6a + 9c = 225
- (6a + 8c = 212)
c = $13
Put this value of c in (2):
2a + 3*13 = 75
2a + 39 = 75
=> 2a = 75 - 39
2a = 36
a = 36/2 = $18
Therefore, the adult ticket costs $18 and the children ticket costs $13.
Identify any outlier(s) in the data. {52, 61, 42, 46, 50, 51, 49, 44, 40, 66, 53, 67, 45, 64, 60, 69}
An outlier in statistics is a data point that deviates considerably from other observations. The given data set has no outlier.
What is an outlier?An outlier in statistics is a data point that deviates considerably from other observations. An outlier can be caused by measurement variability or by experimental mistake; the latter is sometimes eliminated from the data set.
To find the outlier for the given data set follow the given steps.
Step one: The first step is to find the quartiles for the data set.
For this data set, the quartiles are:
Q1 = 45.5
Q3 = 62.5
Step Two: Find the Interquartile Range
The interquartile range is the difference between the first and third quartiles.
IQR = Q3 - Q1
IQR = 45.5 - 62.5
IQR = 17
Step Three:
The next step is to set up a fence beyond the first and third quartiles using the interquartile range.
Lower Fence = Q1 - (1.5 × IQR)
Lower Fence = 45.5 - (1.5 × 17)
Lower Fence = 20
Upper Fence = Q3 + (1.5 × IQR)
Upper Fence = 62.5 + (1.5 × 17)
Upper Fence = 88
Step Four: Find the Outliers
Any numbers in the data that are above or below the fences are outliers.
Since there are no numbers outside the two fences. Hence, it can be concluded that the given data set does not have, any outlier.
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plz help.... 2|x-3|-5=7
Answer:
x = -3 and x = 9.
Step-by-step explanation:
2|x - 3| - 5 = 7
2|x - 3| = 12
|x - 3| = 6
x - 3 = 6
x = 9
-(x - 3) = 6
-x + 3 = 6
-x = 3
x = -3
Hope this helps!
Answer:
x=9 x=-3
Step-by-step explanation:
2|x-3|-5=7
Add 5 to each side
2|x-3|-5+5=7+5
2|x-3|=12
Divide by 2
2/2|x-3|=12/2
|x-3|=6
There are two solutions to an absolute value equation, one positive and one negative
x-3 =6 x-3 = -6
Add 3 to each side
x-3+3 = 6+3 x-3+3 = -6+3
x=9 x = -3
Find factors of x³-7x-6 A. (x-4)(x-2)(x+1) B. (x-6)(x-1)(x+1) C. (x-3)(x+2)(x+1) D. (x+3)(x+2)(x-1)
Answer:
C. (x-3)(x+2)(x+1)
Step-by-step explanation:
We can use the rational roots test to help factor out the original equation.
The leading term is 1 and the constant is 6
p/q= 6/1
Now we find factors (all these are plus and minus)
1,2,3,6
1
We find the common ones (+1 and -1) and use -1 because it ends up being the root of the function
Factor, (x+1)
Now we have (x+1)(x^2-x-6)
Factor this with whatever method you perfer, I use AC method
Find two that are a product of -6 and add to -1 (-3 and 2)
We get (x+1)(x-3)(x+2)
C
Answer:
[tex]\boxed{C}[/tex]
Step-by-step explanation:
Let's solve all of the option and see which equals x³-7x-6
Option A)
[tex](x-4)(x-2)(x+1)[/tex]
=> [tex](x^2-6x+8)(x+1)[/tex]
=> [tex]x^3+x^2-6x^2-6x+8x+1\\x^3-5x^2+2x+1[/tex]
So, A is not correct
Option B)
[tex](x-6)(x-1)(x+1)\\(x+6)(x^2-1)\\x^3-x+6x^2-6\\x^2+6x^2-x-6[/tex]
This is also not correct
Option C) ← Correct
[tex](x-3)(x+2)(x+1)\\(x^2-x-6)(x+1)\\x^3+x^2-x^2-x-6x-6\\x^3-7x-6[/tex]
This equals to x³-7x-6, So, this is the correct option. No need to do Option D since we have the right option now!
A catering service offers 11 appetizers, 8 main courses, and 4 desserts. A customer is to select 9 appetizers, 3 main courses, and 2 desserts for a banquet. In how many ways can this be done?
Answer:
Total number of required ways = 18480
Step-by-step explanation:
Given that
Total appetizers = 11
Total main courses = 8
Total desserts = 4
To be selected 9 appetizers
3 main courses and
2 desserts.
To find:
Number of ways of selecting them.
Solution:
Number of ways to select 'r' number of items out of 'n' number of items is given as:
[tex]_nC_r = \dfrac{n!}{(n-r)!r!}[/tex]
One important property:
[tex]_nC_r = _nC_{n-r}[/tex]
Here we have 3 items, we will find each items' number of ways of selecting and then will multiply all of them.
Number of ways to select 9 appetizers out of 11 appetizers:
[tex]_{11}C_9\ or\ _{11}C_2 = \dfrac{11 \times 10}{2} = 55[/tex]
Number of ways to select 3 out of 8 main courses:
[tex]_{8}C_3= \dfrac{8 \times 7 \times 6}{6} = 56[/tex]
Number of ways to select 2 desserts out of 4:
[tex]_{4}C_2= \dfrac{4 \times 3}{2} = 6[/tex]
Total number of ways = [tex]55 \times 56 \times 6[/tex] = 18480
PLEASE HELP The probability distribution for a
random variable x is given in the table.
1
Step-by-step explanation:
p(x≤20)=p(x=-10) +p(x=-5)+p(X=0) +p(x=5) +p(x=10)+ p(X=15)+p(X=20)
This, p(X≤20)=0.20+0.15+0.05+0.1+0.25+0.1+0.15
=1
A building feet tall casts a foot long shadow. If a person looks down from the top of the building, what is themeasure of the angle between the end of the shadow and the vertical side of the building (to the nearest degree)
do not know because my brain cant focus on this sorry :/
if my grade is 69% what will my grade be if i got a 3.3 of 4 on a essay and it's worth 25% of my grade?
Answer:
72.4%
Step-by-step explanation:
The essay is 25% of your grade, and the rest is 75% of your grade.
25 (3.3/4) + 75 (0.69) ≈ 72.4
The Cambridge Power and Light Company selected a random sample of 20 residential customers. Following are the amounts, to the nearest dollar, the customers were charged for electrical service last month:
53 49 54 50 21 46 75 45 63 76 61 63 36 34 54 63 37 62 66 62
(a) Compute the arithmetic mean.(Round your answer to 2 decimal places. Omit the "$" sign in your response.)
The mean is $
(b) Indicate whether it is a statistic or a parameter.
Answer:
a) the mean is $53.50
b) it is a statistic
Step-by-step explanation:
mean = ∑fx/∑f
∑f = 20
mean = (sum of the terms) ÷ (number of terms)
mean = (53+49+54+50+21+46+75+45+63+76+61+63+36+34+54+63+37+62+66+62) ÷ 20 = 1070/20
=$53.50
b) it is statistics because it is a random sample of 20 residential customers not the actual population
Simplify the expression:
3+ – 5(4+ – 3v)
Answer:
The answer is
15v - 17Step-by-step explanation:
3+ – 5(4+ – 3v) can be written as
3 - 5( 4 - 3v)
Expand and simplify
That's
3 - 20 + 15v
15v - 17
Hope this helps you
Prove that tan (pi/4 + A) tan (3pi/4 +A) = -1
Answer:
Step-by-step explanation:
tan(pi\4+A)tan(3pi\4+A) =-1
using the tangent sum of angle formula
Amber created a scatter plot and drew a line of best fit, as shown. What is the equation of the line of best fit that Amber drew?
Answer:
The correct answer for the best line of fit is C: y = 1/3x+12
Step-by-step explanation:
So our goal here is to find the best equation that matches the line of fit.
So right away we can already eliminate two of the options because in the scatter point it shows that the starting y-intercept is 12 and two of the options have a y-intercept of 15. So we are able to tell that Option B and Option D isn't the equation for the lien of fit.
Now we are left with Option A and Option C, which both have a y-intercept of 12. To find the right equation that best matches the line of fit we look at the slope. Option A has a slope of 3x while Option C has a slope of 1/3x, to tell what slope the line of has we applied both option's slope and see which one matches it.
When we match Option A's slope which is 3x it doesn't match because a slope of 3x is going first going up the y-axis 3 times then moving through the x-axis 1 time. Which would had made the line of fit more steep.
Next we match Option C's slope which is 1/3x this slope matches the line of fit because in the scatter plot it clearly shows it going up 1 time on the y=axis and 3 times through the x-axis. Which made the line of fit not that steep.
So the correct answer to this question is C: y = 1/3x+12.
Here a picture of the line of fit if it has a slope of 3x.
Answer:
correct answer C: y = 1/3x+12
Step-by-step explanation:
i just did the problem
The slope of a line is 1/3 . What is the slope of a line perpendicular to this line? A. -3 B. 3 C. 1/3 D. -1/3
Answer:
The answer is option A
Step-by-step explanation:
Since the lines are perpendicular the slope perpendicular line is the negative inverse of the original line and when they are multiplied should give - 1
Let m be the slope of the perpendicular line
That's
1/3 × m = - 1
multiply through by 3
m = - 3
The slope of the perpendicular line is - 3
Hope this helps you
Answer:
-3
Step-by-step explanation:
Determine the zeros of r=2sin5theta
Answer:
[tex]\theta=\frac{n\pi}{5}[/tex]
Step-by-step explanation:
You have the following function:
[tex]r=2sin5\theta[/tex] (1)
In order to find the zeros of the function you equal to zero the equation (1), and then you solve for θ:
[tex]2sin5\theta=0\\\\sin5\theta=0\\\\5\theta=sin^{-1}(0)=n\pi;\ \ \ \ n=0,1,2,3,..\\\\\theta=\frac{n\pi}{5}[/tex]
Then, there are infinite zeros for the function of the equation (1), because n has infinite positive integers values.
Answer:
θ = 0, pi/5, 2pi/5, 3pi/5, 4pi/5 ,pi
Step-by-step explanation: