The back end of the rod moved [tex]1.90\ \mathrm{mm}$[/tex] in this time interval.
Given:
Young's modulus, Y = [tex]20 \times 10^{10}\;N/m^{2}[/tex]
Steel density, [tex]\rho = 7.86 \times 10^{3}\;kg/m^{3}[/tex]
Length of the rod, L = 80 cm = 0.800m
The speed of the wave in the rod is
[tex]$v = \sqrt{\frac{Y}{\rho}} = \sqrt{\frac{20\times 10^{10}\ \mathrm{N/m^2}}{7.86\times 10^3\ \mathrm{kg/m^3}}} = 5044\ \mathrm{m/s}$[/tex]
Hence the time taken by the wave to travel the end of the rod is,
[tex]$t=\frac{L}{v} = \frac{0.800\ \mathrm{m}}{5044\ \mathrm{m/s}} = 1.58\times 10^{-4}\ \mathrm{s}$[/tex]
The velocity of the rod is [tex]$v_r = 12.0\ \mathrm{m/s}$[/tex]
The other end will keep moving after the front end hits the wall until the wave reaches the other end, given the period determined by the above problem.
As a result, before the wave reaches the end of the rod, it has traveled a distance of
[tex]$\Delta L = v_r t = (12.0\ \mathrm{m/s}) (1.58\times\ \mathrm{s}) = 1.90\times 10^{-3}\ \mathrm{m} = 1.90\ \mathrm{mm}$[/tex]
Hence, the [tex]1.90\ \mathrm{mm}$[/tex] at the back end of the rod moved in this time interval.
What do you mean by Youngs Modulus?Young's Modulus is a measurement of the mechanical characteristics of linear elastic solids like rods, wires, and other similar objects. It is also known as the Elastic Modulus or Tensile Modulus. Young's modulus is the most often used measurement of a material's elastic properties; other measurements include bulk modulus and shear modulus. This is so that it can inform us about a material's tensile elasticity (ability to deform along an axis).
The relationship between stress (force per unit area) and strain is described by Young's modulus (proportional deformation in an object). Thomas Young, a British scientist, is honored with the name of the Young's modulus. When a certain load is applied to a solid object, it deforms.
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which is the best description of a balanced stance
Which requires more work: lifting a 70 kg sack vertically 2 m or lifting a 35 kg sack vertically 4 meters?
Answer:
ADD ANSWER 5 PTS?
Explanation:
ME : Seriously
BRAINLY: 5 PTS!
Answer:
they require the same amount of work
Explanation:
the formula for work is
W=Fnet*Displacement
and Fnet =m*a
a=9.81 m/s^2
Which gives us
W=ma*d
The set up would be;
(35kg*9.81m/s^2)*4 m=W
(70kg*9.81m/s^2)*2m=W
W= 1373.4 J
Both are the same therefore the correcr answer is *both require the same amount of work*
why does a star go through a cycle?
Answer:
the sun
Explanation:
that is how the solar system works
please help me on this!
A rock has been sent on a journey down through the layers of the Earth until it reaches the inner core. Explain what happens to the atoms in the rock as it moves through each layer.
Answer:
erosion
Explanation:
grows into the eirth each year. the atmosphere and how the worldchanges every year
A dog runs after a ball that is 45 meters away. It takes him 9 seconds to reach the ball. How fast is the dog running?
Answer:
The answer in 5m/s
Explanation:
You use the formula s=d devided by t, so in other words, you devide 45 meters by 9seconds and the answer is 5m/s
2. A person lifts 200kg seven times over the course of 11.8s. If they displaced the weight 2.2m up each time, how much power did the person deliver?
Answer:
The person delivered a power of 2,558 Watt
Explanation:
Work and Power
Mechanical work is the amount of energy transferred by a force. It's a scalar quantity, with SI units of joules.
Being the force vector and the displacement vector, the work is calculated as:
[tex]W=\vec F\cdot \vec s[/tex]
If both the force and displacement are parallel, then we can use the equivalent scalar formula:
W=F.s
Power is the amount of energy transferred per unit of time. In the SI, the unit of power is the watt, equivalent to one joule per second.
The power can be calculated as:
[tex]\displaystyle P=\frac {W}{t}[/tex]
Where W is the work and t is the time.
If the person lifts a mass of m=200 Kg, then exerts a force equal to its weight:
F = m.g = 200*9.8 = 1,960
F = 1,960 N
The work done when lifting the weight 7 times by a distance of s=2.2 m is:
W = 7*1,960*2.2=30,184
W = 30,184 J
Finally, the power delivered in t=11.8 seconds is:
[tex]\displaystyle P=\frac {30,184}{11.8}[/tex]
P = 2,558 Watt
The person delivered a power of 2,558 Watt
We know from experience that the harder we throw a ball (apply more force), the faster it will be
moving (greater initial velocity resulting from acceleration). If you throw a 1 kg softball as hard
as you can, and it is traveling at 20 m/s when it leaves your hand, how fast do you think a 5 kg
shot put would travel with the same throw?
The velocity the 5 Kg shot put would have, given the data from the question is 4 m/s
What is momentum?Momentum is defined as the product of mass and velocity. It is expressed as
Momentum = mass × velocity
How to determine the momentum of the 1 Kg ballWe'll begin by calculating the momentum of the 1 Kg ball. This can be obatined as follow:
Mass = 1 KgVelocity = 20 m/sMomentum = ?Momentum = mass × velocity
Momentum = 1 × 20
Momentum = 20 Kg.m/s
How to determine the velocity of the 5 Kg shot putMass = 5 KgMomentum = 20 Kg.m/sVelocity of 5 Kg = ?Momentum = mass × velocity
20 = 5 × velocity
Divide both sides by 5
Velocity = 20 / 5
Velocity of 5 Kg = 4 m/s
Thus, the 5 Kg shot put will have a velocity of 4 m/s
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The information gathered in an investigation is called _________.
Answer:
Evidence
Explanation:
WILL MARK BRAINLIEST ONCE I KNOW THE RIGHT ANSWER *(AFTER THE FULL TEST)*
Rules:
DO NOT SCAM
DO NOT ANSWER IF YOU DO NOT KNOW
COMMENT RESPECTFULLY
What is the mass in grams of 3.1 mol of mercury, Hg Show Your work
Answer:
621.83grams
Explanation:
Using the formula;
Mole = mass ÷ molar mass
Where;
Mole = mol
Mass = grams
Molar mass = g/mol
According to the information given in this question, number of moles = 3.1mol, mass of Hg = ?, Molar mass (MM) of Hg = 200.59g/lol
Hence, using mole = mass/MM
3.1 = mass / 200.59
mass = 200.59 × 3.1
Mass = 621.829
Mass = 621.83grams
Gases, just like liquids are made of particles which can be further classified as atoms or molecules,
True
False
Answer:
True
Explanation:
Solids, Liquids, and Gases are all make up of atoms and molecules.
When water turns to ice:
1. The distances between the molecules increase, 2. Heat is released into the environment, 3. The temperature of the ice does not change during the transformation, 4. All statements are correct.
Answer:
1
Explanation:
Fossil fuels, hydroelectric power, and wind power ultimately get their energy from _______.
Fossil fuels, hydroelectric power, and wind power ultimately get their energy from sun.
Fossil fuels are hydrocarbons which are composed of carbon, hydrogen and oxygen. These are obtained from the decomposition of animals and organisms. The fossil energy almost came from the sun
Hydroelectric power is an indirect form of solar energy generated from water falling from high to low potential. It is a better alternative of electricity as it is environment friendly and do not release wastes, smoke and heat.
Wind power is renewable energy and generated from high speed wind. It is used to run wind turbines is a sustainable source of solar energy.
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picture is attached with question
59.00 m is the calculated distance.
Distance is the sum of an object's movements, regardless of direction. Distance can be defined as the amount of space an object has covered, regardless of its starting or ending position. The International System of Units defines a meter as the distance unit. It's interesting to note that many other derived units or quantities, such as volume, area, acceleration, and speed, may be constructed using this as the basic unit and a few formulae.
V = V₀ + at = 4.30 + 3.00*5.00 = 19.30 m/s
d = V₀t + (1/2) at²
= 4.30*5.00 + (1/5.00) ² = 59.00 m
or
d = (1/2) (V₀+V) t
= (1/2) (4.30+19.30) (5.00)
= 59.00 m
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Part A
If you are not wearing a seat belt in a car that rounds a curve, and you slide across your seat and slam against a car door, what kind of force is responsible for your slide
centripetal, centrifugal, or no force?
O It is centrifugal force as viewed by someone outside the car.
There is no force as viewed by someone outside the car. To them you move in a straight line
O Centripetal force
It is centripetal force, but only as viewed by someone inside the car.
Answer:
I think it is the last option
Explanation:
How do we determine the conditions that existed in the very early universe? A We can only guess at the conditions, since we have no way to calculate or observe what they were. B The conditions in the very early universe must have been much like those found in stars today, so we learn about them by studying stars. C From the current expansion rate we can work backward to estimate temperature and densities at various times in the early universe. D By looking all the way to the cosmological horizon, we can see the actual conditions that prevailed all the way back to the first instant of the Big Bang.
Answer:
D By looking all the way to the cosmological horizon, we can see the actual conditions that prevailed all the way back to the first instant of the Big Bang.
Explanation:
Astrophysicists are able to determine the conditions that existed in the early universe, by using instruments such as telescopes to observe and study cosmic horizons. More ideas about the early universe can be found from the thermal light present in cosmic backgrounds.
Scientists study these details that provide an insight into the conditions that existed so many years ago. They have been able to determine that the Big Bang involved so many collisions from these observations.
Two cats jump off a roof that is 23m off the ground. Cat A jumps directly up with a velocity of 7m/s, and cat B jumps directly down with a velocity of 7m/s. How far up does cat A go? How fast does cat A go just before it hits the ground? How fast does cat B go just before it hits the ground? How much longer is cat A in the air than cat B?
(1) The height reached by cat A is 2.5 m.
(2) The speed of cat A before it hits the ground is 36.4 m/s.
(3) The speed of cat B before it hits the ground is 22.39 m/s.
(4) The time spent in air by cat A than cat B is 1.43 seconds.
Time of motion of cat AThe time of motion of cat A is calculated as follows;
h = vt - ¹/₂gt
-23 = 7t - 4.9t²
4.9t² - 7t - 23 = 0
solve the quadratic equation using formula method;
a = 4.9, b = -7, c = - 23
t = 3.0 seconds
Time of motion of cat BThe time of motion of cat B is calculated as follows;
h = vt - ¹/₂gt
23 = 7t + 4.9t²
4.9t² + 7t - 23 = 0
solve the quadratic equation using formula method;
a = 4.9, b = 7, c = -23
t = 1.57 seconds
Height reached by cat Ah = u²/2g
h = (7²)/(2 x 9.8)
h = 2.5 m
Speed of cat A before it hits the groundv = u + gt
v = 7 + 3(9.8)
v = 36.4 m/s
Speed of cat B before it hits the groundv = u + gt
v = 7 + 1.57(9.8)
v = 22.39 m/s
Time spent in air by cat A than cat B
Time difference = 3 s - 1.57 s = 1.43 seconds
Thus, the height reached by cat A is 2.5 m.
The speed of cat A before it hits the ground is 36.4 m/s.
The speed of cat B before it hits the ground is 22.39 m/s.
The time spent in air by cat A than cat B is 1.43 seconds.
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Think back on what we have learned about gravity, mass, and weight. We are
going to take 5 minutes to write a 5-6 sentence reflection on what you learned
during this time. Make sure to use as many vocabulary words as you can.
Your answer
Answer: mass is both a property of a physical body and a measure of its resistance to acceleration when a net force is applied. An object's mass also determines the strength of its gravitational attraction to other bodies. weight is the weight of an object is the force acting on the object due to gravity. and gravity is a natural phenomenon by which all things with mass or energy—including planets, stars, galaxies, and even light—are brought toward one another.
Explanation: and that is mass weight and gravity
obtain derivatives of x/sinx
Answer:
[tex]\displaystyle \frac{x}{\sin x} = \sum^{\infty}_{n = 0} \frac{(2n + 1)!}{(-1)^nx^{2n}}[/tex]
General Formulas and Concepts:
Calculus
Differentiation
DerivativesDerivative NotationSequences
Series
Taylor Polynomials
MacLaurin Polynomial: [tex]\displaystyle P_n(x) = \frac{f(0)}{0!} + \frac{f'(0)}{1!}x + \frac{f''(0)}{2!}x^2 + \frac{f'''(0)}{3!}x^3 + \cdots + \frac{f^n(0)}{n!}x^n + \cdots[/tex]Power Series
Power Series of Elementary FunctionsMacLaurin SeriesTaylor SeriesExplanation:
*Note:
You could derive the Taylor Series for sin(x) using Taylor polynomials by differentiation by usually you have it memorized.
We want to obtain an infinite amount of derivatives of the given:
[tex]\displaystyle \frac{x}{\sin x}[/tex]
We know that a power series is defined as an infinite derivatives of a function. We know that the power series for sin(x) is:
[tex]\displaystyle \sin x = \sum^{\infty}_{n = 0} \frac{(-1)^nx^{2n + 1}}{(2n + 1)!}[/tex]
Divide x by the power series to obtain our derivatives:
[tex]\displaystyle \frac{x}{\sin x} = \sum^{\infty}_{n = 0} \frac{x}{\frac{(-1)^nx^{2n + 1}}{(2n + 1)!}}[/tex]
Simplify this down:
[tex]\displaystyle \frac{x}{\sin x} = \sum^{\infty}_{n = 0} \frac{(2n + 1)!}{(-1)^nx^{2n}}[/tex]
And we have our final answer.
Topic: AP Calculus BC (Calculus I + II)
Unit: Power Series
Using 6. 0×1024 kg for the mass of the earth, what is the acceleration of the earth toward her as she accelerates toward the earth with an acceleration of 9. 8 m/s2 ? assume that the net force on the earth is the force of gravity she exerts on it.
The value of the acceleration of the earth toward it when it accelerates toward the earth with 9.8m/s² is a = 7.35×10-²³m/s².
What are forces?Forces are the definition of Newton's second law, which is stated under the relation:
∑ Force = mass × acceleration.
In other words, force is the origin of motion since it generates acceleration in a system.
In this case we must complete the statement:
"A student with mass 45 kg jumps off a high diving board. Using 6. 0×1024 kg for the mass of the earth, what is the acceleration of the earth toward her as she accelerates toward the earth with an acceleration of 9. 8 m/s2 ? assume that the net force on the earth is the force of gravity she exerts on it."
We determine the Force of the student:
F = ma
F = 45kg * 9.8m/s².
F = 441N
Now we go to the acceleration of the earth:
a = F/m
a = 441N / 6×10²⁴ Kg
a = 7.35×10-²³m/s².
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A Smart Car, which has a mass of 1000 kg, is going 20 m/s. When it hits the barrier, it stops at a time of 0.5 seconds. What is the impulse on the car?
Answer:
Imp = 20000 [kg*m/s]
Explanation:
In order to solve this problem we must divide it into two parts. In the first part we must use the following equation of kinematics.
[tex]V_{f}=v_{i}-a*t[/tex]
where:
Vf = final velocity = 0 (the car stops)
Vi = initial velocity = 20 [m/s]
a = acceleration [m/s²]
t = time = 0.5 [s]
Acceleration is negative as the cart slows down as it stops.
[tex]0=20-a*0.5\\20=0.5*a\\a=40 [m/s^{2}][/tex]
The second part is the determination of momentum, which is defined as the product of force over a given time. But to determine the force we must use Newton's second law which tells us that the sum of the forces of a body is equal to the product of mass by acceleration.
∑F = m*a
[tex]F = 1000*40\\F = 40000[N][/tex]
Now the impulse or momentum
[tex]Imp = F*t\\Imp = 40000*0.5\\Imp=20000[kg*m/s][/tex]
A player hits a ball with a bat. The action is the force of the bat against the ball.
What is the reaction to this force?
Answer:
Force of the ball against the bat
Explanation:
Newton's third law of motion states that for every action, there is an equal and opposite reaction. When a player hits a ball with a bat, the force the player exerted on the ball through the bat gave the ball a push force in the forward direction. This is an action force. Now that an action has been initiated, there must be a reaction according to Newton's third law of motion. The magnitude of the force on the ball equals the magnitude of the force on the bat. The direction of the force on the ball is opposite to the direction of the force on the ball. The ball will give the bat an equal and opposite force trying to push the bat backward by resisting the impact of the bat. This is the reaction. The ball will only move if the applied force is able to overcome the resisting force by the bat.
Where;
is the action force of the bat against the ball.
is the equal and opposite reaction force of the ball towards the ball.
Calculate the centripetal force of a ball on a string in circular motion if the mass is 7 kg
traveling at 3 m/s and the radius of the string is 4 meters.
0 11 N
0 14 N
0 16 N
0 25 N
Answer:
F = 16 N
Explanation:
Given that,
Mass of the ball, m = 7 kg
Speed of the ball in circular motion, v = 3 m/s
The radius of the string, r = 4 m
We need to find the centripetal force of a ball on a string in circular motion. The formula for the centripetal force is given by :
[tex]F=\dfrac{mv^2}{r}[/tex]
Putting all the values in the above formula
[tex]F=\dfrac{7\times (3)^2}{4}\\\\=15.75\ N[/tex]
or
F = 16 N
Hence, the correct option is (c).
What two kinds of energy are part of thermal energy?
Answer:
Many forms of energy exist, but they all fall into two basic categories:
Potential energy.Kinetic energy.Explanation:
Thermal energy is due to the movement, and the kinetic energy associated with this movement, of molecules that make up an object or substance.
Hoped I helped U!! ❤️
Answer:
1.) mechanical energy and 2.) potential energy
Explanation:
Sound is made up of vibrations thermal energy consists of moving molecules in air or in an object, and mechanical energy is the combination of kinetic and potential energy of a moving object.
I hope this helps!!!!
Coach carver has created a new team game for his students to play it involves sprinting tagging and throwing a ball
Coach Carver has created a new team game for his students to play. It involves sprinting, tagging, and throwing a ball. Each team consists of 10 to 20 students. Which place is the safest to play the game
Answer:
Football Field
Explanation:
In sporting or gaming activities that involve sprinting, tagging, and throwing a ball. The safest place to play the game is "FOOTBALL FIELD"
This is because the football field is originally designed and created for footballing activities which are deemed spacious and free of danger. There is also evidence in the Olympic sporting activities.
Therefore, in this case, even though there is no option in the question, the correct answer is the Football field.
The insulating material placed between the conducting plates of a capacitor is a(n) ?
Answer:
the answer is dielectric
hope helps you
Explanation:
Answer:
dielectric
Explanation:
edge
URGENT‼
An amateur marksman aims directly at a bulls-eye (on the same level) 75.0 m away. If the bullet leaves the gun at a speed of 180 m/s, by how much will it miss the target?
Hello!
He will miss it by ≈ 0.852 m
Begin by finding the amount of time necessary to hit the target. Use the formula t = d / s:
t = 75 / 180 = 0.4167 sec
Use the equation d = vi + 1/2at² to solve for the amount the bullet will miss the target. (vi is 0 in this instance). We are solving for the vertical component, so use a = 9.81 m/s (gravity).
d = 0 + 1/2(9.81)(0.4167²)
d ≈ 0.852 m
GP Submarine A travels horizontally at 11.0 m/s through ocean water. It emits a sonar signal of frequency f = 5.27× 10³Hz in the forward direction. Submarine B is in front of submarine A and traveling at 3.00 m/s relative to the water in the same direction as submarine A. A crewman in submarine B uses his equipment to detect the sound waves ("pings") from submarine A. We wish to determine what is heard by the crewman in submarine B. (a) An observer on which submarine detects a frequency f' as described by Equation 17.19 ?
The frequency [tex]5.3 \times 10^3 \mathrm{~Hz}[/tex] that the submarine B detects a frequency f' as described by Equation 17.19.
Given:
Submarine A velocity, [tex]v_{s}=11\;m/s[/tex]
Submarine A Frequency, [tex]F = 5.27 \times 10^{3}\;Hz[/tex]
Submarine B velocity, [tex]v_{o}=3\;m/s[/tex]
As the sign of the submarine B frequency is positive. So, The submarine B is moving away from Submarine A. Therefore, The observer from submarine B detects the frequency [tex]f^{'}[/tex]
Using the Doppler Shift formula, we can determine the frequency of the sonar signal that the crewman in submarine B heard:
[tex]\begin{gathered}f_o=f_s\left(\frac{v-v_o}{v-v_s}\right), \\f_o=5.27 \times 10^3 \mathrm{~Hz} \cdot\left(\frac{1533 \frac{\mathrm{m}}{\mathrm{s}}-3 \frac{\mathrm{m}}{\mathrm{s}}}{1533 \frac{\mathrm{m}}{\mathrm{s}}-11 \frac{\mathrm{m}}{\mathrm{s}}}\right)=5.3 \times 10^3 \mathrm{~Hz} .\end{gathered}[/tex]
Hence, the frequency of [tex]5.3 \cdot 10^3 \mathrm{~Hz}[/tex] that the submarine detects a frequency f' as described by Equation 17.19.
What do you mean by Frequency?A frequency is the quantity of waves produced each second.
A measure of frequency is the number of times in a second that an alternating current (AC) changes from positive to negative. Direct currents do not experience this switching (DC). Hertz is used to measure frequency (Hz) The period is the length of time it takes for an AC current to start at zero, change from positive to negative, and then return to zero (i.e., the length of time it takes to complete one cycle), while the frequency is the reciprocal of the period. In contrast to low frequency, which has fewer waves per second but a longer period, high frequency refers to the number of waves per second and the length of the period.
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Of there was no matter to vibrate, How will this affect a sound?
1. This sound would be louder.
2. The sound would have higher pitch.
3. There would be no sound.
4. The sound would have a lower pitch
Answer:
3. There would be no sound.
Explanation:
Sound is produced by vibrations that travel through a medium, most commonly through air.
If there is no matter to vibrate (such as in the vacuum of space) then there's no way for a sound wave to be produced.
Thus the answer is option 3. There would be no sound.
A uniform electric field exists in a region of space containing no charges. What can you conclude about the net electric flux through a gaussian surface placed in this region of space?
The net electric flux in such gaussian surface is zero.
In a uniform electric field existing in a region of space and contains no charge, it is impossible for there to be an electric flux in such space. This is because flux generated in an electric field is a product of the charge and the permittivity of the free space.
In other words, every field line sent into a given closed surface continues through the interior and is typically directed outward somewhere on the surface if there is no provided net charge there. The net or total electric flux is zero because the negative flux barely equals the positive flux in magnitude.
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