QUICK!!

Which equation represents the relationship shown in the graph??

Answer:

15x^5

Step-by-step explanation:

That's the answer I got im pretty sure it correct

Answer: 5 1/2

Step-by-step explanation:

I took the test ig, but im not 100% sure

Answer:

[tex]x = 26[/tex]

Step-by-step explanation:

Given

The above triangles

Required

Find x

The two triangles are similar. So we make use of the following equivalent ratios, to solve for x

[tex]XZ : ZY = JL : LK[/tex]

Replace each side with their measurements

[tex]13 : 10 = x : 20[/tex]

Express as fraction

[tex]\frac{13}{10} = \frac{x}{20}[/tex]

Solve for x

[tex]x = \frac{13}{10} * 20[/tex]

[tex]x = 1.3 * 20[/tex]

[tex]x = 26[/tex]

Answer:

-496

Step-by-step explanation:

it's right :)

Answer:

The answer is -7.

Step-by-Step explanation:

Answer:

9) 73

10) he set off at 1:55 pm

easy-Peasy

Answer:

48 cm²

Step-by-step explanation:

Area of trapezoid = [tex]\frac{a + b}{2}[/tex] × h

Area = (8 + 16)/2 x 4

Area = 24/2 x 4

Area = 12 x 4

Area = 48 cm²

Answer:

$96.35

Step-by-step explanation:

31.45 x 2 = 62.90

62.90 + 18.50 + 14.95 = $96.35

Answer:

663

Step-by-step explanation:

ratio of Malay = 5

ratio of Indian= 4

ratio of Chinese= 8

Total number of Indian + Chinese= 468

Total ratio= 5+4+8= 17

Let the total number of students= X

Ratio of India= 4/17 × X=

Ratio of Chinese= 8/17 × X=

Addition of ratio of both India and Chinese=

4X/17 + 8X/17= 468

(4X +8X)/17 = 468

12X/17= 468

X= 663

Hence, total number of students is 663

Answer:

.33

Step-by-step explanation:

Answer:

48 outfits

Step-by-step explanation:

Using Fundamental Principal of counting

number of outfits that Juan can wear

=number of ties * number of pants * numberof pants

=4*3*4

=48 outfits

The number of different outfits can he wear if he chooses one Tie, one shirt, one pair of pants for each outfit is 48 outfits.

The arrangement of different things or numbers in a number of ways is called a combination.

A permutation is an orderly arrangement of things or numbers. Combinations are a way to choose items or numbers from a collection or group of items without worrying about the items' chronological order.

Given that Juan has four ties, three shirts, and four pairs of pants.

Using the Fundamental Principle of counting,

Number of outfits that Juan can wear

N =number of ties x number of pants x number of pants

N =4 x 3 x 4

N =48 outfits

Therefore, the number of different outfits can he wear if he chooses one Tie, one shirt, one pair of pants for each outfit is 48 outfits.

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Answer:

x = 3

y = 4

Step-by-step explanation:

y = 3x -5

4x - 2(3x-5) = 4

4x - 6x + 10 = 4

-2x = -6

x = 3

y = 4

Answer:

4/5

Step-by-step explanation:

slope is 4/5

y = mx + b

m = slope

Answer: x = 110 degrees

Step-by-step explanation:

35 and its vertical angle inside the triangle both = 35 deg

43 and 32 add to 75 deg

The total degree measure inside a triangle is 180

180-75-35 = 70 deg

70 degrees is the supplementary angle of x

180-70 = x

x = 110 degrees

Answer:

50 students

Step-by-step explanation:

20 is 40% of 50

because 50 x .40 = 20

Hope this helps!

Answer:

30

Step-by-step explanation:

40%/2=20%

20/2=10

100%-40%=60%

60%/3=20%

10x3=30

Answer:

5

Step-by-step explanation:

the mode is the number that appears most frequently on a data set.

Answer:

5

Step-by-step explanation:

Answer:

maybe its b

Step-by-step explanation:

Answer:

6 5/36

Step-by-step explanation:

MARK ME BRAINLIEST?

Answer:

I think its b

Step-by-step explanation:

Yes, your answers are correct.

The volume of a cone is given by V = 1/3πr²h.  Since the diameter of the first cone is 4, the radius is 2; therefore the volume is

V = 1/3π(2²)(8) = 32π/3

We divide the volume of the sink, 2000π/3, by the volume of the cone:

2000π/3 ÷ 32π/3 = 2000π/3 × 3/32π = 6000π/96π = 62.5 ≈ 63.

The diameter of the second conical cup is 8, so the radius is 4.  The volume then is:

V = 1/3π(4²)(8) = 128π/3

Dividing the volume of the sink, 2000π/3, by 128π/3:

2000π/3 ÷ 128π/3 = 2000π/3 × 3/128π = 6000π/384π = 15.625 ≈ 16

The requried,
(a) Carissa scoop out 63 cups.
(b) Carissa scoop out 16 cups

Volume is defined as the mass of the object per unit density while for geometry it is calculated as profile area multiplied by the length at which that profile is extruded.

Here,
The problem requires us to find out how many cups of water Carissa needs to scoop out of the sink to empty it, given the volume of the sink and the dimensions of the two cups. We can solve this problem by using the formula for the volume of a cone:

V = (1/3) * π * r² * h

First, simplify the volume formula for a cone to make it easier to manipulate:

V = 1/3πr²h

Next, plug in the given values for the first cone:

V = 1/3π(2²)(8) = 32π/3

Then, divide the volume of the sink by the volume of the first cone:

2000π/3 ÷ 32π/3 = (2000π/3) * (3/32π) = 2000/32 = 62.5 ≈ 63.

Now, calculate the volume of the second cone using the same formula:

V = 1/3π(4²)(8) = 128π/3

Finally, divide the volume of the sink by the volume of the second cone:

2000π/3 ÷ 128π/3 = (2000π/3) * (3/128π) = 2000/128 = 15.625 ≈ 16.

Divide the volume of the sink by the volume of the first cone to get the number of first cones that can fit into the sink:

2000π/3 ÷ 32π/3 = (2000π/3) * (3/32π) = 2000/32 = 62.5 ≈ 63.

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Answer:

x + 9

Step-by-step explanation:

The sum of x and 9,

x + 9

Answer:

D

Step-by-step explanation: the answer is D

Answer:

x1=-6, x2=-2

Step-by-step explanation:

Answer:

this is the answer hope it helps

Answer:

1. I'll Be Fine - Juice Wrld

2. ON GOD - Juice Wrld

3. Rich and Blind - Juice Wrld

Answer: it’s a

Step-by-step explanation:

Answer:

1. Surface Area = 122                Volume = 84

2. Surface Area = 1632             Volume = 2880

3. Surface area = 168                Volume = 144

4. Volume = 1350[tex]\pi[/tex]

Step-by-step explanation:

1. This is a rectangular prism. To find the surface area it is the same thing. Find the area of all sides and add them together.  Because this is a rectangular prism most of the sides are equal so we will only need to find the area of three sides. To find the area of the right side, just do 4*3=12. That would be the same for the opposite side. Then to find the front side, do 7*4= 28. That would also be the same for the opposite side. Then to find the top side, do 7*3= 21. That is the same for the bottom side. Add them all together and you will get your answer. 28+28+21+21+12+12 = 122.

To find the volume of a rectangular prism the formula is V = l*w*h.

Plug in: V = 7*3*4 and then you will get 84.

2. This is a triangular prism. First find the area of the the triangular surface by multiplying the base x height and dividing by 2. (16*12)/2 = 96.  That is the same for the opposite side. Then find the area of the bottom rectangular surface. 12*30 = 360. Then find the area of the back rectangular surface. 16*30 = 480. Then find the area of the final base rectangle. 30*20 = 600. Add them together and you will get 1632. Basically, find the area of all sides and then add them together.

To find volume the formula is, V = (1/2)a*c*h

Fill that in: V = (1/2)16*12*30 and then you will get 2880.

3. This is a trapezoidal prism. To find the surface area you would find the area of all sides then add them together. To find the are of a trapezoid, the formula is: A = [tex]\frac{a+b}{2}[/tex]h

Fill that in: A = [tex]\frac{4+12}{2}[/tex](6) and then you will get 48.

That is the same for the opposite side. Then you need to find the area of the rectangular side of the trapezoidal prism. 3*4= 12. This is also the same as the opposite side. The bottom side is 12*3= 36. The top side is 3*4= 12.

Add all of them together and you get 168.

1/2(4+12)*6

To find volume, V =  [tex]\frac{1}{2}[/tex]h(b₁+b₂)h.

Fill in: V =  [tex]\frac{1}{2}[/tex]6(12+4)3 and then you will get 144.

4. This is a cylinder. The formula to find the volume is A=[tex]\pi[/tex]r²h. Because you are leaving the answer in terms of pi, do not multiply pi into the equation.

So you would do r²h. 15² = 225. 225*6= 1350. So your answer would be 1350[tex]\pi[/tex].