(a) The mode, median, first quartile, and third quartile of the data set is 24, 24, 12, and 43, respectively. There are no outliers.
(b) The data value corresponding to the 60th percentile is 33.8.
(c) The percentile rank of the age 40 is 70th percentile.
(a) The mode of the data set is 24, as it appears twice in the data set.
The median of the data set is 24, as it is the middle value when the data set is arranged in ascending order.
The first quartile (Q1) is 12, as it is the median of the lower half of the data set.
The third quartile (Q3) is 43, as it is the median of the upper half of the data set.
To check for outliers, we can use the interquartile range (IQR), which is Q3 - Q1 = 43 - 12 = 31.
The lower outlier boundary is Q1 - 1.5(IQR) = 12 - 1.5(31) = -34.5.
The upper outlier boundary is Q3 + 1.5(IQR) = 43 + 1.5(31) = 89.5.
Since all the values in the data set are within the outlier boundaries, there are no outliers.
(b) To find the data value corresponding to the 60th percentile, we can use the formula:
Percentile rank = (p/100)(n + 1)
where p is the percentile, and n is the number of data values.
In this case, p = 60 and n = 25, so the percentile rank is (60/100)(25 + 1) = 15.6.
Since the percentile rank is not a whole number, we can use interpolation to find the data value corresponding to the 60th percentile.
The data value corresponding to the 60th percentile is 32 + (0.6)(35 - 32) = 33.8.
(c) To find the percentile rank of the age 40, we can use the formula:
Percentile rank = (L + 0.5f)/n
where L is the number of data values less than 40, f is the frequency of 40, and n is the number of data values.
In this case, L = 17, f = 1, and n = 25, so the percentile rank of the age 40 is (17 + 0.5(1))/25 = 0.7 or 70th percentile.
(d) To draw a boxplot for the data set, we can use the values of the first quartile (Q1), median, and third quartile (Q3) that we found in part (a).
The boxplot would look like this:
[12]---[24]---[43]
Q1 Median Q3
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Simplify the following expression by combining like terms 3y+8+4y+2
Consider the two functions x1 = y^2 and x2 = b on the y-interval [-a, a], if a = 6.2. What value does b have to be in order for the area between x, and x2 and [-a, a], to equal 50.5? Round your answer to five decimal places.
The value of b that makes the area between the two functions equal to 50.5 on the interval [-6.2, 6.2] is 29.64355.
To find the value of b that makes the area between the two functions equal to 50.5 on the interval [-6.2, 6.2], we need to set up an integral and solve for b.
First, we need to find the difference between the two functions:
x2 - x1 = b - y^2
Next, we need to integrate this difference over the given interval:
∫[-6.2, 6.2] (b - y^2) dy
Using the power rule for integration, we get:
[b*y - (y^3)/3] from -6.2 to 6.2
Plugging in the values for the interval and simplifying, we get:
(6.2b - 158.488) - (-6.2b - 158.488)
Simplifying further, we get:
12.4b - 316.976
Now, we can set this equal to the given area and solve for b:
12.4b - 316.976 = 50.5
12.4b = 367.476
b = 367.476/12.4
b = 29.64354839
Rounding to five decimal places, we get:
b = 29.64355
So, the value of b that makes the area between the two functions equal to 50.5 on the interval [-6.2, 6.2] is 29.64355.
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Suppose x > y > 0 and a > b > 0. Is it true that x/b > y/a? if so
For the inequality x > y > 0 and a > b > 0 the expression ( x /y)> (x +b)/ (y+ a) > b/a is true if x/b > y/a.
For x > y > 0 and a > b > 0
The inequality x/b > y/a
Simplify by cross-multiplication we get,
⇒xa > yb
Adding xy to both sides,
⇒xy + xa > xy + yb
Factoring the left-hand side,
⇒ x(y + a) > y(x + b)
Dividing both sides by (y + a)(x + b), as x > y > 0 and a > b > 0,
⇒ x/(x + b) > y/(y + a)
Multiplying both sides by x/y we get the expression,
⇒x/y > (x + b)/(y + a) __(1)
It proves the half part of the expression, x/y > (x + b)/(y + a)
Now second part x/y > (x + b)/(y + a) > b/a.
Using inequality x/b > y/a to get:
a/b > y/x
Multiplying both sides by (x + b)/(y + a),
⇒(a/b) × (x + b)/(y + a) >(y/x) × (x + b)/(y + a)
Expand both sides and simplifying,
⇒ ( ax + ab ) / (by + ab ) > ( xy + by ) / ( xy + ax )
⇒( ax + ab )( xy + ax ) > ( xy + by ) (by + ab )
⇒ ax²y + a²x² + abxy + a²bx > by²x + abxy + b²y² + ab²y
⇒ (ax -by )( x + b )( y + z) > 0
⇒ax - by > 0 or ( x + b )> 0 or ( y + z) > 0
⇒ ax > by
⇒ x /y > b /a
As a > b > 0
⇒ (x +b)/ (y+ a) > b/a __(2)
From (1) and (2) we have,
( x /y)> (x +b)/ (y+ a) > b/a
Therefore , the expression ( x /y)> (x +b)/ (y+ a) > b/a is true for the given condition.
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The above question is incomplete, the complete question is:
Suppose x > y > 0 and a > b > 0. Is it true that x/b > y/a then expression
( x /y)> (x +b)/ (y+ a) > b/a.
Consider the expression.
17 (5) (9 + 14y)
Select all statements about the expression that are true.
There are exactly 4 terms.
One term of the expression is 23
The expression has exactly 3 factors.
The constant in the factor 9 + 14y is 9.
The factors in the expression are 17.5.9, and 14y.
Answer: None of the statements are true.
The expression has only two terms: 17 and (5)(9 + 14y).
No term in the expression equals 23.
The expression has three factors: 17, 5, and (9 + 14y).
The constant in the factor 9 + 14y is 9.
The factors in the expression are 17, 5, 9, and (9 + 14y).
Step-by-step explanation:
Solve the right triangle. Round side measures to the nearest tenth and angle measures to the nearest degree.
Step-by-step explanation:
Refer to pic..........
The formula t=−10 li (T-R/ 95.6 −R) can be used to calculate the elapsed time once a person has died, where T is the bodys temperature in " F, R is the canstant room temperature in" F. and t is the elapsed time since death in hours. A coroner examined a body found in a foom with room temperature ta f and aneatured the temperature of the body as 835∗F. Use the formula to estimate how long belore the coroner's ecainsination the person had died. ________hours______ minutes
The person had died approximately 5 hours and 10 minutes before the coroner's examination.
Using the formula, t=−10 log10(T-R/95.6-R), we can calculate the elapsed time since death.
Given that T = 83.5°F, R = 75°F and t is the elapsed time since death in hours, we can calculate the elapsed time.
t = -10 log10(83.5-75/95.6-75)
t = -10 log10(8.5/20.6)
t = -10 * 0.517 = -5.17 hours
Therefore, the person had died approximately 5 hours and 10 minutes before the coroner's examination.
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A person has rupees 210 he wants to donate it he gives rupees 1 for first day rupees 2 for second day rupees 3 for third day and so on for donation he can donate this for maximum how munch days
Answer: This is a classic problem in mathematics known as the arithmetic series or the Gauss sum.
To find out how many days the person can donate with a total of Rs. 210, we need to sum the sequence of donations until we reach the total amount of Rs. 210. The sequence of donations is:
1 + 2 + 3 + 4 + 5 + ... + n
The sum of the sequence can be expressed as:
n(n+1)/2
So we need to solve the equation:
n(n+1)/2 = 210
n(n+1) = 420
n^2 + n - 420 = 0
We can solve this quadratic equation using the quadratic formula:
n = (-b ± sqrt(b^2 - 4ac)) / 2a
where a = 1, b = 1, and c = -420.
n = (-1 ± sqrt(1^2 - 4(1)(-420))) / 2(1)
n = (-1 ± sqrt(1 + 1680)) / 2
n = (-1 ± sqrt(1681)) / 2
n = (-1 ± 41) / 2
Since we are looking for a positive integer value of n, we can discard the negative solution:
n = (41 - 1) / 2
n = 40 / 2
n = 20
Therefore, the person can donate for a maximum of 20 days with a total donation of Rs. 210, starting with Rs. 1 on the first day and increasing by Rs. 1 each day.
Step-by-step explanation:
Suppose a machine produces metal parts that contain some defective parts with probability 0.05. How many parts should be produced in order that the probability of atleast one part being defective is 21 or more?
(Given that, log1095=1.977 and log102=0.3)
O 11
O 12
O 15
O 14
The probability of at least one part being defective is 21 or more when 14 parts are produced. So, the correct answer is D: 14.
Let X be the number of defective parts among n parts produced. Since each part can either be defective or non-defective, X follows a binomial distribution with parameters n and p, where p = 0.05.
We want to find the smallest value of n such that P(X ≥ 1) ≥ 0.21. We can use the complement rule to rewrite this as P(X < 1) ≤ 0.79.
P(X < 1) = P(X = 0) = (1 - p)^n
= (0.95)^n
We need to find n such that (0.95)^n ≤ 0.79. Taking logarithms of both sides, we get:
n log(0.95) ≤ log(0.79)
n ≥ log(0.79) / log(0.95)
n ≥ 13.65
Since we need n to be an integer, we round up to the nearest integer and get n = 14.
Therefore, the answer is option D: 14.
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Find the distance from the point $\left(1,\ 2\right)$ to the line $y=\frac{1}{2}x-3$
. Round your answer to the nearest tenth.
The distance from the point [tex]$(1,2)$[/tex] to the line [tex]$y=\frac{1}{2}x-3$[/tex] is approximately 3.7 units.
What is expression ?In mathematics, an expression is a combination of numbers, variables, and operators, which when evaluated, produces a value. An expression can contain constants, variables, functions, and mathematical operations such as addition, subtraction, multiplication, and division.
According to given information :To find the distance from a point to a line, we need to find the length of the perpendicular segment from the point to the line.
The line [tex]$y=\frac{1}{2}x-3$[/tex] can be rewritten in slope-intercept form as [tex]$y = \frac{1}{2}x - 3$[/tex], so its slope is [tex]\frac{1}{2}$.[/tex]
A line perpendicular to this line will have a slope that is the negative reciprocal of [tex]\frac{1}{2}$[/tex], which is [tex]-2$.[/tex]
We can then use the point-slope form of a line to find the equation of the perpendicular line that passes through the point [tex]$(1,2)$[/tex]:
[tex]$y - 2 = -2(x - 1)$[/tex]
Simplifying, we get:
[tex]$y = -2x + 4$[/tex]
Now we need to find the point where the two lines intersect, which will be the point on the line [tex]$y = \frac{1}{2}x-3$[/tex] that is closest to [tex]$(1,2)$[/tex]. We can do this by setting the equations of the two lines equal to each other and solving for [tex]$x$[/tex]:
[tex]$\frac{1}{2}x - 3 = -2x + 4$[/tex]
Solving for [tex]$x$[/tex], we get:
[tex]$x = \frac{14}{5}$[/tex]
To find the corresponding [tex]$y$[/tex] value, we can substitute this value of [tex]$x$[/tex] into either of the two line equations. Using [tex]$y = \frac{1}{2}x-3$[/tex], we get:
[tex]$y = \frac{1}{2} \cdot \frac{14}{5} - 3 = -\frac{7}{5}$[/tex]
Therefore, the point on the line [tex]$y = \frac{1}{2}x-3$[/tex] that is closest to [tex]$(1,2)$[/tex] is [tex]$\left(\frac{14}{5}, -\frac{7}{5}\right)$[/tex].
Finally, we can use the distance formula to find the distance between [tex]$(1,2)$[/tex] and [tex]$\left(\frac{14}{5}, -\frac{7}{5}\right)$[/tex]:
[tex]$\sqrt{\left(\frac{14}{5} - 1\right)^2 + \left(-\frac{7}{5} - 2\right)^2} \approx 3.7$[/tex]
Rounding to the nearest tenth, the distance from the point [tex]$(1,2)$[/tex] to the line [tex]$y=\frac{1}{2}x-3$[/tex] is approximately 3.7 units.
Therefore, the distance from the point [tex]$(1,2)$[/tex] to the line [tex]$y=\frac{1}{2}x-3$[/tex] is approximately 3.7 units.
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for each quantity, decide wether circumference or area would be needed to calculate it. explain or show you reasoning
The concepts that we use are
1. circumcenter of the circle.
b. Area of the circle
c. Area of the circle
d. Circumference of the circle.
Circumference and area of the circle:The circumference of a circle is the distance around its outer boundary, while the area of a circle is the total space enclosed within its boundary.
The formula we use in a given problem depends on the context of the problem the following situations can be understood as follows
Here we have 5 situations
a. The distance around a circular track.
Here to find the distance around the circular track we need to calculate the perimeter of the circular track i.e circumcenter of the circle.
b. The total number of equally-sized tiles on a circular floor.
The total size of tiles on the circular floor represents the area of the circle. Hence we need to use the area of the circle
c. The amount of oil it takes to cover the bottom of a frying pan.
The amount of oil that spread on the bottom of the pan will equal the area of the circular surface of the pan
Hence, we need to use the Area of the circle
d. The distance your car will go with one turn of the wheels.
The distance will cover by the wheel will equal to boundary line around the wheel hence, we need to use the circumference of the circle.
Therefore,
The concepts that we use are
1. circumcenter of the circle.
b. Area of the circle
c. Area of the circle
d. Circumference of the circle.
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Complete Question:
For each quantity, decide whether circumference or area would be needed to calculate it. Explain or show your reasoning.
a. The distance around a circular track.
b. The total number of equally-sized tiles on a circular floor.
c. The amount of oil it takes to cover the bottom of a frying pan.
d. The distance your car will go with one turn of the wheels.
Please type the answer by company so that i can see it clearly, thank you!
The occupational safety of workers in Country ABC piqued the curiosity of a safety officer. Country ABC was split into 18 districts by the officer. For personal interviews, five workers were chosen at random from each district. The following are some of the questions that were asked during the interview.
Question (I) – How many days did you work on November 2021 (total 30 days)?
Question (II) – Which district are you living in?
Question (III) – Do you agree that the safety standard in your working environment is high? (Totally disagree/ disagree/ neutral/ agree/ totally agree)
Question (IV) – How much is your daily salary (in HK$100)?
Questions
For each of the following variables, determine whether the variable is qualitative or quantitative. If the variable is quantitative, determine whether the variable is discrete or continuous. In addition, indicate the level of measurement.
(i) The number of days that the worker worked on November 2021
(ii) District that the worker is living in
(iii) Level of agreement on the high safety standard in the working environment of the worker
(iv) Daily salary of the worker (in HK$100)
Quantitative, discrete, ratio
(i) Quantitative, discrete, interval
(ii) Qualitative, nominal
(iii) Qualitative, ordinal
(iv) Quantitative, discrete, ratio
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3. Letfbe a differentiable function of one variable, andw=f(ex+2xy). (a) Verify that the functionwsatisfies the equation(ex+2y)wy−2xwx=0. (b) Iff(u)=cosu, calculatewxy. 4. Consider the functionf(P,t)=f(x(t),y(t),z(t),t)=t(ysinx+ez)and the pointP=(π,1,0). Find the material derivative offatP
3 a. The function w satisfies the equation (ex+2y)wy−2xwx=0.
3 b. The value of wxy is -2x(ex+2y)cos(ex+2xy) - 2ysin(ex+2xy)
4 . The material derivative of fatP is 0.
3. (a) To verify that the function w satisfies the equation (ex+2y)wy−2xwx=0, we can take the partial derivatives of w with respect to x and y, and then substitute them into the equation.
First, let's find the partial derivatives of w:
∂w/∂x = f'(ex+2xy)(ex+2y)
∂w/∂y = f'(ex+2xy)(2x)
Now, we can substitute these partial derivatives into the equation:
(ex+2y)(f'(ex+2xy)(2x)) - 2x(f'(ex+2xy)(ex+2y)) = 0
Simplifying this equation, we get:
2exf'(ex+2xy) + 4xyf'(ex+2xy) - 2exf'(ex+2xy) - 4xyf'(ex+2xy) = 0
This simplifies to 0 = 0, which is true. Therefore, the function w satisfies the equation (ex+2y)wy−2xwx=0.
(b) If f(u) = cosu, then we can find wxy by taking the partial derivative of w with respect to x and y, and then substituting f(u) = cosu:
∂w/∂x = f'(ex+2xy)(ex+2y) = -sin(ex+2xy)(ex+2y)
∂w/∂y = f'(ex+2xy)(2x) = -sin(ex+2xy)(2x)
Now, we can find wxy by taking the partial derivative of ∂w/∂x with respect to y:
wxy = ∂(∂w/∂x)/∂y = ∂(-sin(ex+2xy)(ex+2y))/∂y = -2x(ex+2y)cos(ex+2xy) - 2ysin(ex+2xy)
4. To find the material derivative of fatP, we can use the formula:
Df/Dt = ∂f/∂t + ∂f/∂x(dx/dt) + ∂f/∂y(dy/dt) + ∂f/∂z(dz/dt)
First, let's find the partial derivatives of f:
∂f/∂t = ysinx + ez
∂f/∂x = ty*cosx
∂f/∂y = tsinx
∂f/∂z = tez
Now, we can find the material derivative of fatP by substituting the point P = (π,1,0) and the derivatives of x, y, and z with respect to t:
Df/Dt = (1*sinπ + e^0) + (π*1*cosπ)(dx/dt) + (π*sinπ)(dy/dt) + (π*e^0)(dz/dt) = 0 + 0 + 0 + 0 = 0
Therefore, the material derivative of fatP is 0.
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-22/3
4/3
6/17
2/13
which two are the smallest???
Answer: i think -22/3 and 6/17
Step-by-step explanation:
Solve this equation. 12 - 3x = 4+ (-2x)
Answer: -2x = 16
Step-by-step explanation:
The answer is -2x = 16.
We start by isolating the -2x on one side of the equation. To do this, we must subtract 3x from both sides of the equation. This gives us -2x = 4 - 3x. We then add 3x to both sides of the equation to give us -2x + 3x = 4. Since 3x + (-3x) = 0, we are left with -2x = 16.
Answer:
x=8
Step-by-step explanation:
12 -3x=4+ (-2x)
12-3x=4-2x add 12 to both sides
-3x=-2x-8 add 2x to both sides
-x=-8 divide both sides by 1
x=8
let me know if this helped :)
a rectangular field has side lenght that measure 9\10 mile and 1\2 mile. what is the area of the field?
The area of rectangular field is [tex]\frac{9}{20} \ \text{miles}^2[/tex].
What is area of rectangle?The area a rectangle occupies is the space it takes up inside the limitations of its four sides. The dimensions of a rectangle determine its area. In essence, the area of a rectangle is equal to the sum of its length and breadth.
Here the given rectangle , length= [tex]\frac{9}{10}[/tex]miles and Breadth = [tex]\frac{1}{2}[/tex]miles
Now using area of rectangle formula,
=> A = length× breadth square unit.
=> A = [tex]\frac{9}{10}\times\frac{1}{2}[/tex]
=> A = [tex]\frac{9}{20} \ \text{miles}^2[/tex]
Hence the area of rectangular field is [tex]\frac{9}{20} \ \text{miles}^2[/tex].
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A gardener is planting two types of trees: Type A is 6 feet tall and grows at a rate of 18 inches per year. Type B is 3 feet tall and grows at a rate of 21 inches per year. Algebraically determine exactly how many years it will take for these trees to be the same height.
Answer:
1 year.
Step-by-step explanation:
First set up the equation for each tree
Tree A = 6 + 18x
Tree B = 3 + 21x
Since we want to find how long it would take the tree to be same height just set the equation equal to each other.
6+18x = 3+21x
Now you can just solve it by isolating x.
First, subtract 18x from both sides so that we can have just one x and coefficient.
6 = 3 + 3x
Then, subtract 3 from both sides to isolate the x.
3 = 3x
Next, divide both sides by 3.
1 = x
X means the years and so that means it would take just 1 year for the trees to be same height.
Use the special factoring methods to factor the following binomial. If it cannot be factored, indicate "Not Factorable". 121y^(8)z^(2)-256x^(6)
The binomial 121y8z2 - 256x6 can be factored using the difference of two squares rule.
To factor the binomial 121y8z2 - 256x6, use the special factoring methods. Notice that the binomial has a difference of two squares, where the first term is a perfect square and the second term is the square of a binomial. This means that you can factor this binomial using the difference of two squares rule:
[tex]121y8z^2 - 256x^6 = (11y4z^2 - 16x^3) * (11y4z^2 + 16x^3)[/tex]
Therefore, the binomial 121y8z2 - 256x6 can be factored using the difference of two squares rule.
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The value of x is decreased by 74% . Which expression represents this situation?
74x
0.74x
0.926x
0.26x
Answer:
0.26x
Step-by-step explanation:
If x is decreased by 74% then new value of x
= x - 74% of x
74% as decimal = 74/100 = 0.74
New value of x
= x - 0.74x
=x(1 - 0.74)
=0.26x
I need help on 8 and 9!!
Answer:
8) the ordered pair (-1,-1) is a solution
9)the ordered pair (-8,-2) is a solution
Step-by-step explanation:
8) 3x-5y≥2
3(-1)-5(-1)=2
2=2
9)-x-6y>12
-(-8)-6(2)=-4
-4>12
Expand open parentheses x plus 8 close parentheses and open parentheses x minus 8 close parentheses.
The expanded form of the given expression is x^2 - 64.
Describe distributive property:The distributive property states that for any two numbers a and b, a(b+c) = ab + ac. This means that you can multiply a number by the sum of two numbers and get the same result as when you multiply that number by each of the two numbers separately and then add the two products together.
To expand the given expression, we need to use the distributive property. The distributive property states that a(b + c) = ab + ac. Applying this property to the given expression, we get:
(x + 8)(x - 8) = x(x - 8) + 8(x - 8)
Next, we need to distribute the x and 8 to the terms inside the parentheses:
x(x - 8) + 8(x - 8) = x^2 - 8x + 8x - 64
Finally, we can simplify the expression by combining like terms:
x^2 - 8x + 8x - 64 = x^2 - 64
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ach in the lowest-yielding, least-risky acc uld she invest in each account to achieve x+y+z=50,000 0.03x+0.055y+0.09z=2540
The investor should invest $32,500 in the lowest-yielding, least-risky account, $20,000 in the medium-yielding, medium-risk account, and $17,500 in the highest-yielding, highest-risk account.
To solve this problem, we can use a system of linear equations.
We have three equations and three unknowns: x, y, and z.
The equations are: x + y + z = 50,0000.03x + 0.055y + 0.09z = 2540
We can use substitution or elimination to solve for one of the variables and then plug that value back into the other equations to find the remaining variables.
For example, we can solve for x in the first equation:
x = 50,000 - y - z
Then we can substitute this value of x into the second equation:
0.03(50,000 - y - z) + 0.055y + 0.09z = 2540
Simplifying this equation gives us:
1500 - 0.03y - 0.03z + 0.055y + 0.09z = 25400.025y + 0.06z = 1040
Now we can solve for one of the remaining variables, such as y:
y = (1040 - 0.06z) / 0.025
And we can substitute this value of y back into the first equation to find z:
50,000 - (1040 - 0.06z) / 0.025 - z = 50,000
Solving for z gives us:
z = 17,500
Finally, we can plug this value of z back into the equations for x and y to find the remaining variables:
x = 50,000 - y - 17,500 = 32,500 - y
y = (1040 - 0.06(17,500)) / 0.025 = 20,000
So the solution is x = 32,500, y = 20,000, and z = 17,500.
This means that the investor should invest $32,500 in the lowest-yielding, least-risky account, $20,000 in the medium-yielding, medium-risk account, and $17,500 in the highest-yielding, highest-risk account.
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what order do these go in?
For [tex]4x + 2x^2(3x-5)[/tex] : degree = 3, number of terms = 3, so the answer is 3 and 3.
For [tex](-3x^4 + 5x^3 - 12) + (7x^3 - x^5 + 6)[/tex]: degree = 5, number of terms = 4, so the answer is 5 and 4.
For [tex](3x^2 - 3)(3x^2 + 3)[/tex] : degree = 4, number of terms = 1, so the answer is 4 and 1.
What is expression ?
In mathematics, an expression is a combination of numbers, symbols, and operators (such as +, ×, ÷, etc.) that represents a mathematical relationship or quantity.
Expressions can be simple, such as 2 + 3, or more complex, such as [tex](4x^2 - 2x + 5)/(x - 1).[/tex] They can also include variables, which are symbols that represent unknown or changing values.
For the expression [tex]4x + 2x^2(3x-5):[/tex]
Simplified form:[tex]6x^3 - 10x^2 + 4x[/tex]
Degree: 3
Number of terms: 3
For the expression [tex](-3x^4 + 5x^3 - 12) + (7x^3 - x^5 + 6):[/tex]
Simplified form: [tex]-x^5 - 3x^4 + 12x^3 - 6[/tex]
Degree: 5
Number of terms: 4
For the expression[tex](3x^2 - 3)(3x^2 + 3):[/tex]
Simplified form: [tex]9x^4 - 9[/tex]
Degree: 4
Number of terms: 1
Therefore, the correct options are:
For [tex]4x + 2x^2(3x-5)[/tex] : degree = 3, number of terms = 3, so the answer is 3 and 3.
For [tex](-3x^4 + 5x^3 - 12) + (7x^3 - x^5 + 6)[/tex] : degree = 5, number of terms = 4, so the answer is 5 and 4.
For [tex](3x^2 - 3)(3x^2 + 3):[/tex] degree = 4, number of terms = 1, so the answer is 4 and 1.
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The covariance between the returns of A and B is -0. 112. The standard deviation of the rates of return is 0. 26 for stock A and 0. 81 for stock B. The correlation of the rates of return between A and B is closest to: A. )-1. 88 B. )-. 53 C. ). 53 D. )1. 88
The correlation of the rates return between stock A and B for the given covariance and standard deviation is given by option B. -0.53.
Covariance between stock A and B = -0.112
Standard deviation of the rates return for stock A = 0.26
Standard deviation of the rates return for stock B = 0.81
Formula for correlation in terms of covariance and standard deviations is
Correlation = covariance / (standard deviation of A x standard deviation of B)
Here correlation of the rates of return between A and B.
Substitute the given values we get,
⇒ Correlation = (-0.112) / (0.26 x 0.81)
⇒ Correlation ≈ -0.430769 / 0.81
⇒ Correlation ≈ -0.5318
⇒ Correlation ≈ -0.53
Therefore, the correlation of the rates of return between A and B is is equal to option B. -0.53.
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Compute A² – 2A + I. A= | 1 0 -1| . | 0 -4 0| . |2 0 2| NOTE: Write the elements of the matriz exactly. A2 - 2A +I=
The elements of the matrix are: A² – 2A + I = | 0 0 -1 | | 0 25 0 | | 2 0 -1 |. To compute A² – 2A + I, we need to first find A², then multiply A by 2, and finally add the identity matrix I to the result.
The identity matrix I is a matrix with 1s on the main diagonal and 0s elsewhere.
A² = A * A = | 1 0 -1| * | 1 0 -1| = | 1*1+0*0+(-1)*2 1*0+0*(-4)+(-1)*0 1*(-1)+0*0+(-1)*2 |
| 0 -4 0| | 0 -4 0| | 0*1+(-4)*0+0*2 0*0+(-4)*(-4)+0*0 0*(-1)+(-4)*0+0*2 |
| 2 0 2| | 2 0 2| | 2*1+0*0+2*2 2*0+0*(-4)+2*0 2*(-1)+0*0+2*2 |
= | 1 0 -3 |
| 0 16 0 |
| 6 0 2 |
2A = 2 * | 1 0 -1| = | 2 0 -2|
| 0 -4 0| | 0 -8 0|
| 2 0 2| | 4 0 4|
I = | 1 0 0 |
| 0 1 0 |
| 0 0 1 |
A² – 2A + I = | 1 0 -3 | - | 2 0 -2 | + | 1 0 0 | = | 1-2+1 0-0+0 -3-(-2)+0 |
| 0 16 0 | | 0 -8 0 | | 0 1 0 | | 0-0+0 16-(-8)+1 0-0+0 |
| 6 0 2 | | 4 0 4 | | 0 0 1 | | 6-4+0 0-0+0 2-4+1 |
= | 0 0 -1 |
| 0 25 0 |
| 2 0 -1 |
Therefore, A² – 2A + I = | 0 0 -1 |
| 0 25 0 |
| 2 0 -1 |
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In quadrilateral QRST, QS = RT. Is QRST a rectangle?
Answer:
I believe that no, it is not a rectangle because we don't know if the other 2 sides equal each other. In a rectangle 2 sets of sides are equal so no. it is not a rectangle.
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Step-by-step explanation:
100 points and mark brainly please hurry
Answer:
12 of them
Step-by-step explanation:
5x5 cube so
25*48%
Answer:
its 12 squares
Step-by-step explanation:
First you take all the squqres as 100 percent then you divide both sides by 100 to find how much squares is 1 percent, then multiply the 1 percent answers by the percentage you need which is 48 to get the squares
Part A. In two or more complete sentences explain the differences between liabilities and assets.
Part B. In two or more complete sentences give examples of both liabilities and assets.
The differences and examples of liabilities and assets have been detailed below.
What are liabilities and assets?The things that your business has and can potentially provide future financial gain are called assets. What you owe other people is the liability. In essence, assets increase your financial situation while obligations decrease it.
A. A company's assets are things it has that will be useful to it in the future, whereas its liabilities are things it must pay.
Unlike liabilities, which are not depreciable, assets are subject to depreciation over time.
B. Cash, receivables, goodwill, investments, buildings, etc. are a few examples of assets.
Liabilities include things like Accounts payable, Interest payable, and Deferred Revenue, among others.
Hence, the differences and examples of liabilities and assets have been provided.
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Let X and Y be independent, geometrically distributed random
variables, each with parameter p, p ∈(0, 1). Set N = X + Y.
(a) Find the joint PMF of X, Y, and N.
(b) Find the joint PMF of X and N.
(a) The joint PMF of X, Y, and N can be found by multiplying the two independent PMFs of X and Y. The joint PMF is: P(X=x, Y=y, N=n) = P(X=x) * P(Y=y) = (1-p)^x * p * (1-p)^y * p = (1-p)^(x+y) * p^2.
(b) The joint PMF of X and N can be found by marginalizing over Y. The joint PMF is: P(X=x, N=n) = P(X=x, Y=n-x) = (1-p)^(x+(n-x)) * p^2 = (1-p)^n * p^2.
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ABCD is a parallelogram. Find the measures of the numbered angles.
m∠1=
m∠2=
m∠3=
m∠4=
The value of the given segments are EC = 6, AC = 12, EB = 4, and BD = 8.
What are diagonals of parallelogram?A quadrilateral with opposing sides that are parallel and equal is known as a parallelogram. Due to the opposite sides' alignment and equality, they have equal angles on them. The lines that link the parallelogram's opposing corners are known as its diagonals.
Given that,
EA = 6
For a parallelogram the diagonals of the quadrilateral bisect each other.
Thus,
EC = 6
AC = EA + EC = 6 + 6 = 12
Similarly, ED = 4
EB = 4
and the value of BD = ED + EB = 8
Hence, the value of the given segments are EC = 6, AC = 12, EB = 4, and BD = 8.
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3(3x+5)-8=7 give statement and give reasons and give check
Answer:
x = 0
Step-by-step explanation:
3(3x+5) - 8 =7
9x + 15 - 8 = 7
9x + 7 = 7
9x = 0
x = 0
Let's check
3(3(0) + 5) - 8 = 7
3(0 + 5) - 8 = 7
3(5) - 8 = 7
15 - 8 = 7
7 = 7
So, x = 0 is the correct answer.