Question 7 of 10
When naming a molecule, how do you indicate that the carbons on either side
of the double bond are pointing in opposite directions?
OA. Use the prefix cis-.
OB. Use the prefix methyl-.
OC. Use the number 2 as a prefix.
OD. Use the prefix trans-.

The longest wavelength of a photon that has enough energy to cause the photodissociation of the weakest bond in a peroxyacyl nitrate molecule is approximately 590 nm.

Given the weakest bond in Peroxyacyl nitrate is N-O bond.

The standard bond-dissociation energy of N-O = 201 kJ mol−1

Let the wavelength = l

We know that E = h c / λ, where E is the energy in joules, h is Planck's constant, c is the speed of light, and λ is the wavelength of photons

[tex]E = (6.626 * 10^{-34}) * (3 * 10^8) / \lambda[/tex]

λ =  [tex](6.626 * 10^{-34}) * (3 * 10^8)/201 kJ mol^{-1}[/tex]

λ = 590nm

In order for photodissociation to occur, the photon must have enough energy to break the N−O bond in the nitrate functional group of the molecule. All of the energy of the photon is efficiently used for the photodissociation.

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The growth of coral on objects found at the bottom of the ocean is a physical change, not a chemical change.

This is because the coral is simply attaching itself to the surface of the object through a physical process, rather than changing the chemical composition of the object itself. The coral is able to attach itself to the surface due to physical forces such as adhesion, cohesion, and surface tension.

However, it is worth noting that over time, the growth of coral on an object can lead to chemical changes in the object as the coral secretes calcium carbonate, which can gradually alter the object's composition.

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Answer:

50.0moles

Explanation:

The balanced equation of the reaction is:

2NaOH + H2SO4____ Na2SO4 +2H2O

2moles of NaOH reacted with 1mole of H2SO4

x moles of NaOH will react with 25moles of H2SO4

2moles______1mole

xmoles______25

x=25×2

x=50moles of NaOH

Answer:

The molecular formula of X = C4 h8 O

Answer:

H20 oxygen 17 8 0 gyjhf I'd

Explanation:

The amount of heat required to melt a solid substance is given by the formula:

Q = m * ΔHf

where Q is the amount of heat required, m is the mass of the substance, and ΔHf is the heat of fusion of the substance. The heat of fusion of ethanol is 111.3 J/g.

So, for melting 148 g of solid ethanol, the amount of heat required is:

Q1 = 148 g * 111.3 J/g = 16499.6 J

The amount of heat required to raise the temperature of the liquid ethanol from -26.8°C to its melting point of -114.1°C is given by the formula:

Q2 = m * C * ΔT

where Q2 is the amount of heat required, m is the mass of the substance, C is its specific heat capacity, and ΔT is the change in temperature.

The specific heat capacity of ethanol is 2.44 J/g°C. The change in temperature is:

ΔT = (-114.1°C) - (-26.8°C) = -87.3°C

Since we want to bring the ethanol to its melting point, we assume that it is still in the liquid state. Therefore, we use the specific heat capacity of liquid ethanol for this calculation.

So, for raising the temperature of 148 g of liquid ethanol from -26.8°C to -114.1°C, the amount of heat required is:

Q2 = 148 g * 2.44 J/g°C * (-87.3°C) = -30834.8 J

Note that the negative sign indicates that heat is lost from the ethanol as it cools.

The total amount of heat required to melt 148 g of solid ethanol and bring it to a temperature of -26.8°C is the sum of Q1 and Q2:

Qtotal = Q1 + Q2 = 16499.6 J + (-30834.8 J) = -14335.2 J

The answer is -14335 J (rounded to three significant digits), which means that 14335 J of heat energy must be removed from the system (or the surroundings must supply 14335 J of heat energy) to carry out the process as described.

The mass of the nitrogen gas that is found to be produced from the reaction equation is 22.4 g.

A balanced chemical equation is a representation of a chemical reaction using the formulas of the reactants and products, and the coefficients that represent the number of each species involved in the reaction.

The correct equation of the reaction is;

2 NH3 + 3 CuO → 3 Cu + N2 + 3 H2O

Number of moles of CuO consumed = 197g/80 g/mol

= 2.4 moles

Given that;

3 moles of CUO is consumed to give 1 moles of N2

2.4 moles of CUO will give 2.4 * 1/3

= 0.8 moles

Mass of N2 = 0.8 * 28 g/mol

= 22.4 g

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The molarity of the Epsom salt solution is 0.271 M.

To find the molarity (M) of the Epsom salt (MgSO4) solution, we need to first calculate the number of moles of MgSO4 present in the given mass of Epsom salt. We can use the formula:

moles = mass / molar mass

where the molar mass of MgSO4 is 120.37 g/mol.

mass of MgSO4 = 75 g

molar mass of MgSO4 = 120.37 g/mol

moles of MgSO4 = 75 g / 120.37 g/mol = 0.6237 mol

Next, we need to calculate the volume of the solution in liters, since molarity is defined as the number of moles of solute per liter of solution:

volume of solution = 2.3 L

Now we can calculate the molarity of the Epsom salt solution:

Molarity = moles of MgSO4 / volume of solution

= 0.6237 mol / 2.3 L

= 0.271 M

Therefore, the molarity of the Epsom salt solution is 0.271 M.

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Sulfur dioxide decomposition's balanced chemical equation is 2 SO2(g) 2 S(s) + 3 O2 (g). 200.00 g of solid sulphur would result from 25.0 g of sulphur dioxide.

In order to compute the mass of oxygen that will react or the mass of 02 that will react with aluminium, multiply the molar mass of oxygen molecules, 0.69 mol two, by 32 g per mole. Hence, the answer is that 25 g of aluminium and 22.22 g of cobalt will react.

First, we must determine how many moles of sulphur dioxide are contained in 25.0 g:

Number of moles of SO2 = mass / molar mass

Number of moles of SO2 = 25.0 g / 64.06 g/mol (molar mass of SO2)

Number of moles of SO2 = 0.3904 mol

The number of moles of sulphur produced can then be calculated using the mole ratio between sulphur dioxide and sulphur:

Number of moles of S = 2 x number of moles of SO2

Number of moles of S = 2 x 0.3904 mol

Number of moles of S = 0.7808 mol

Lastly, we may convert the amount of moles to grammes using the molar mass of sulphur:

Mass of S = number of moles x molar mass

Mass of S = 0.7808 mol x 256.53 g/mol (molar mass of S8)

Mass of S = 200.00 g (rounded to two decimal places)

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As HF is hydrogen bonded, it has a highest boiling point of 19 oC or less, when it becomes liquid. The boiling points of the remaining hydrogen halides, which are gaseous, are determined by the van der Waal forces.

Hydrogen fluoride (H 2 F) has a lower boiling point than water (H 2 O) ( ). H2O has a boiling point of 100 °C while only having a boiling point of 5 °C. Despite the fact that water and hydrogen fluoride have stronger hydrogen bonds than each other, water only forms two hydrogen bonds per molecule whereas hydrogen fluoride only forms one.

Furthermore, water creates hydrogen bonds between nearby molecules. The extremely electronegative oxygen on the other molecule interacts with hydrogen. This is a strong type of interaction that takes more energy than dipole-dipole interactions. As a result, water boils at a greater temperature than HCL.

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The molarity of a 0.5 liter solution that contains 3.84 moles of NaCl would be 7.68 M.

Molarity is simply the ratio of the number of moles of solutes per liter volume of a solution.

In other words, molarity is a measure of the concentration of a solute in a solution. It is commonly denoted by the symbol "M" and expressed in units of mol/L.

Molarity = mole/volume

Where the volume is in liters.

In this case:

Molarity of the NaCl solution = 3.84/0.5

                                                = 7.68 M

Thus, the molarity of a 0.5 Liter solution that contains 3.84 moles of NaCI is 7.68 M.

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Assuming the volume of the tire remains constant, we can use the ideal gas law to determine the pressure of the tire at the higher temperature:

P1/T1 = P2/T2

where P1 is the initial pressure, T1 is the initial temperature, P2 is the final pressure (what we're trying to find), and T2 is the final temperature.

Converting the temperatures to Kelvin (as the ideal gas law requires temperatures in Kelvin), we have:

P1/T1 = P2/T2

P1 = 2.25 atm

T1 = 20 + 273.15 = 293.15 K

T2 = 45 + 273.15 = 318.15 K

Solving for P2, we get:

P2 = P1(T2/T1)

P2 = 2.25 atm (318.15 K / 293.15 K)

P2 = 2.44 atm (rounded to two significant figures)

Therefore, the pressure in your tires at 45°C would be approximately 2.44 atm.

The molarity of the bleach solution is 0.0635 M.

First we need to know the number of moles of solute (in this case, NaOCI) and the volume of the solution in liters.

First, we need to convert the mass of NaOCI to moles using its molar mass:

molar mass of NaOCI = 23.0 g/mol (for Na) + 16.0 g/mol (for O) + 35.5 g/mol (for Cl) + 1.0 g/mol (for I) = 74.5 g/mol

moles of NaOCI = mass / molar mass = 9.50 g / 74.5 g/mol = 0.127 moles

Next, we need to convert the volume of the solution to liters:

volume = 2,000 ml = 2,000 / 1,000 L = 2.0 L

Now we can calculate the molarity of the solution:

Molarity (M) = moles of solute / volume of solution in liters

M = 0.127 moles / 2.0 L = 0.0635 M

Therefore, the molarity of the bleach solution is 0.0635 M.

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Answer:

Explanation:

We can use to convert the given number of atoms of nickel to moles.

1 mole of any element contains 6.022 x 10^23 atoms of the element

So, the number of moles of nickel can be calculated as:

moles of Ni = (number of atoms

moles of Ni = 3.88 x 10^23 / 6.022 x 10^23

moles of Ni = 0.644

Therefore, the answer is option B: 0.644 moles Ni.

The percent yield for the reaction of a sample of 0.49 g of carbon dioxide was obtained by heating 1.22 g of calcium carbonate is 92.4%

Given the mass of carbon dioxide ([tex]CO2[/tex]) = 0.49g

The mass of calcium carbonate ([tex]CaCO3[/tex]) = 1.22g

The reaction is as follows:

[tex]CaCO3(s) -- > CaO(s)+CO2(s)[/tex]

As we see 1 mole of CaCO3 is required to produce 1 mole of [tex]CO2[/tex]

The molar mass of calcium carbonate, = 100.09 g/mol.

The molar mass of given carbon dioxide = 44g

mass of [tex]CaCO3[/tex] used = number of moles x molar mass = 1 * 100 = 100g

Mass of [tex]CO2[/tex] produced = 1 * 44 = 44g

Here for 100g of [tex]CaCO3[/tex] 44g of [tex]CO2[/tex] is produced.

Then for 1.22g of [tex]CaCO3[/tex] = 44 * 1.22/100 = 0.53g of [tex]CO2[/tex] is produced.

But the actual yield of carbon dioxide is 0.49 g

The percent yield is calculated by dividing the actual yield by the theoretical yield and multiplying by 100.

percent yield = 0.49/0.53 * 100 = 92.4%

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Answer:

The compound composed of Cr³+ ions and SO32- ions is called chromium(III) sulfite.

The formula for this compound can be determined by balancing the charges of the Cr³+ ion and the SO32- ion so that the overall charge of the compound is neutral.

The charge of the Cr³+ ion is +3, while the charge of the SO32- ion is -2. To balance these charges, we need two SO32- ions for every Cr³+ ion:

Cr³+ + 2 SO32- → Cr2(SO3)3

Therefore, the formula for the compound is Cr2(SO3)3.

The condensed structural formula of the compound is;

(CH3)3CCH2CH(CH2CH3)CH2CH2CH(CH3)(CH2CH3)

The functional groups in norethynodrel are;  ketone, alcohol and alkyne

The condensed structure of an organic compound is a simplified representation of the molecular structure of the compound that uses brackets and symbols to indicate the arrangement of atoms in the molecule.

In a condensed structure, the individual atoms are not explicitly shown, and the bonds between them are indicated by lines.

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HBr has a dipole moment of 7.95debye and an interatomic spacing of 1.94 x 10-om.

HBr (a polar covalent molecule) has a dipole moment () of 0.851D (debye) and a percentage ionic character of 12.6%.

The size of the charge multiplied by the distance between the centres of the positive and negative charges yields a dipole moment. The Greek character " is used to represent it. It is measured in Debye units ('D'). 1 D = 3.33564 10-30 C.m, where C signifies Coulomb and m a metre.

It's 1018 statcoulomb-centimeters. Traditionally, the debye moment was defined as the dipole moment produced by two charges of opposing sign but equal magnitude of 1010 statcoulomb.

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The metal has a density of 19.3g/mL.

A material's density is determined by how much mass there is in a given volume of that material. We must divide the metal's mass by its volume to determine its density. Density of gold is 19.3 g/mL.Since the volume of the metal is equal to the volume of water it displaced, we can calculate the density of the metal by dividing the mass of the metal (352.3 grams) by the volume of water it displaced (18.0 mL).

Density = [tex]\frac{Mass}{Volume}[/tex]

Density = [tex]\frac{352.3 g}{18.0 mL}[/tex]

Density = 19.3 g/mL

Therefore, the density of the metal is 19.3 g/mL.

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complete question:

She measured the mass of the metal to be 352.3 grams. Then she dropped the metal into a measuring cup and found that it displaced 18.0 mL of water

calculate the density  of metal

densities of some common substances for comparison

Density of water = 1.00 g/mL

Density of air = 1.225 g/mL

Density of iron = 7.86 g/mL

Density of aluminum = 2.7 g/mL

Density of gold = 19.3 g/mL

Answer:

1M

Explanation:

To find molarity, we use the formula [tex]\frac{n}{v}[/tex], where n is the moles of solute, and v is the volume in liters.

This formula is fairly straightforward. When we input our values we get a formula of [tex]\frac{0.50 moles}{0.5 liters}[/tex]. Simplifying yields 1M. (Hint: Don't forget that occasionally we do have to convert between units. In this case, the 500mL was converted to liters using the known conversion factor that 1000mL= 1 liter.)

1. 15.78 grams of Cl2 are produced from 45 grams of AuCl3.

2. 15.31 grams of AgCl are produced from 4.75 grams of AlCl3.

3. 3.55 grams of NaOH are needed to produce 25.2 grams of Na2SO4.

4.  34.40 grams of CO2 are produced from 25 grams of O2.

1. To determine how many grams of Cl2 are produced from 45 grams of AuCl3, we need to use the balanced chemical equation for the reaction:

2 AuCl3 + 3 Cl2 → 2 AuCl5

From this equation, we can see that 3 moles of Cl2 are produced for every 2 moles of AuCl3. To calculate the number of moles of AuCl3 in 45 grams, we divide the mass by the molar mass:

45 g AuCl3 x (1 mol AuCl3 / 303.33 g AuCl3) = 0.1482 mol AuCl3

Using the mole ratio from the balanced chemical equation, we can calculate the number of moles of Cl2 produced:

0.1482 mol AuCl3 x (3 mol Cl2 / 2 mol AuCl3) = 0.2223 mol Cl2

Finally, we can convert the number of moles of Cl2 to grams by multiplying by the molar mass:

0.2223 mol Cl2 x 70.906 g/mol = 15.78 g Cl2

Therefore, 15.78 grams of Cl2 are produced from 45 grams of AuCl3.

2. The balanced chemical equation for the reaction between aluminum chloride (AlCl3) and silver nitrate (AgNO3) is:

3 AgNO3 + AlCl3 → 3 AgCl + Al(NO3)3

From this equation, we can see that 3 moles of AgCl are produced for every 1 mole of AlCl3. To calculate the number of moles of AlCl3 in 4.75 grams, we divide the mass by the molar mass:

4.75 g AlCl3 x (1 mol AlCl3 / 133.34 g AlCl3) = 0.0356 mol AlCl3

Using the mole ratio from the balanced chemical equation, we can calculate the number of moles of AgCl produced:

0.0356 mol AlCl3 x (3 mol AgCl / 1 mol AlCl3) = 0.1068 mol AgCl

Finally, we can convert the number of moles of AgCl to grams by multiplying by the molar mass:

0.1068 mol AgCl x 143.32 g/mol = 15.31 g AgCl

Therefore, 15.31 grams of AgCl are produced from 4.75 grams of AlCl3.

3. The balanced chemical equation for the reaction between NaOH and Na2SO4 is:

2 NaOH + Na2SO4 → 2 Na2SO4 + 2 H2O

From the balanced equation, we see that 2 moles of NaOH react with 1 mole of Na2SO4 to produce 2 moles of Na2SO4 and 2 moles of H2O. To calculate the mass of NaOH needed to produce 25.2 grams of Na2SO4, we need to use the molar mass of Na2SO4:

Molar mass of Na2SO4 = 142.04 g/mol

First, we need to calculate the number of moles of Na2SO4 produced from 25.2 grams:

25.2 g Na2SO4 x (1 mol Na2SO4 / 142.04 g Na2SO4) = 0.1774 mol Na2SO4

Since 2 moles of NaOH react with 1 mole of Na2SO4, we need half that amount, or 0.0887 mol NaOH, to react completely with the given amount of Na2SO4. Finally, we can calculate the mass of NaOH needed using its molar mass:

0.0887 mol NaOH x 40.00 g/mol = 3.55 g NaOH

Therefore, 3.55 grams of NaOH are needed to produce 25.2 grams of Na2SO4.

4. To determine the mass of CO2 produced from 25 grams of O2, we need to use the balanced chemical equation for the combustion of carbon:

C + O2 → CO2

From this equation, we can see that 1 mole of O2 reacts with 1 mole of carbon to produce 1 mole of CO2. To calculate the number of moles of O2 in 25 grams, we divide the mass by the molar mass:

25 g O2 x (1 mol O2 / 32.00 g O2) = 0.78125 mol O2

Since the mole ratio of O2 to CO2 is 1:1, we know that 0.78125 moles of CO2 are produced. Finally, we can convert the number of moles of CO2 to grams by multiplying by the molar mass:

0.78125 mol CO2 x 44.01 g/mol = 34.40 g CO2

Therefore, 34.40 grams of CO2 are produced from 25 grams of O2.

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Answer: To convert 350 miles per hour to meters per second, we need to use the following conversion factors:

1 mile = 1609.344 meters

1 hour = 3600 seconds

Therefore, we can write:

350 miles per hour = 350 miles / 1 hour × 1609.344 meters / 1 mile × 1 hour / 3600 seconds

Simplifying the expression, we get:

350 miles per hour = 155.65104 meters per second (rounded to six decimal places)

Therefore, 350 miles per hour is equivalent to 155.65104 meters per second (approximately).

Explanation:

Ethane (C2H6) burns to make dioxide and steam: 2C2H6(g) + 7O2(g) (g) Ethane (C2H6) fires to give methane gas and steam: 4CO2(g) + 6H2O + 2C2H6(g) + 7O2(g) (l)

We must determine the molecules of CO2 and CO2 that were created. According to the equation above, when 2 molecules of Online C 2 H 6 are exposed to oxygen, 4 moles of Carbon dioxide C O 2 are created.

Oxygen gas and ethane (C2H6) react to create both water and carbon dioxide. Find the quantity of carbon dioxide created when the reaction yield is 60% when 5 mol of propane is burnt with 16 molecule of oxygen initially. 2C2H6+7O2→4CO2+6H2O.

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Answer: As the fertilizers enter the water systems, they cause an explosion of growth by algae and aquatic plants. When the organisms die they are decomposed by microbes that quickly deplete the oxygen in water, killing animals such as fish and shellfish.

Explanation: Excess fertilizers lead to "eutrophication".

Boyle's Law-

[tex]\:\:\:\:\:\:\:\:\:\:\:\star\:\sf \underline{ P_1 \: V_1=P_2 \: V_2}\\[/tex]

(Pressure is inversely proportional to the volume)

Where-

As per question, we are given that -

Now that we have all the required values and we are asked to find out volume which will be occupied if the pressure is adjusted to 80 KPa and the temperature remains unchanged. For that we can put the values and solve for the final volume of helium-

[tex]\:\:\:\:\:\:\:\:\:\:\:\star\:\sf \underline{ P_1 \: V_1=P_2 \: V_2}[/tex]

[tex] \:\:\:\:\:\:\longrightarrow \sf 100 \times 160 = 80 \times V_2\\[/tex]

[tex] \:\:\:\:\:\:\longrightarrow \sf V_2 = \dfrac{100 \times 160}{80}\\[/tex]

[tex] \:\:\:\:\:\:\longrightarrow \sf V_2 =100\times \cancel{\dfrac{ 160}{80}}\\[/tex]

[tex] \:\:\:\:\:\:\longrightarrow \sf V_2 = 100 \times 2\\[/tex]

[tex] \:\:\:\:\:\:\longrightarrow \sf \underline{V_2 = 200 \:cm^3 }\\[/tex]

From a single location on the circular chromosome, DNA is copied in both directions.

The correct option is E.

Binary fission is the process of asexual reproduction in which one organism is divided into two separate ones. An organism's genetic material, or deoxyribonucleic acid (DNA), doubles when it splits into two halves (cytokinesis) through binary fission, with each new species inheriting one copy of the latter.

Bacterial binary fission is the method by which bacteria split their cells. Find out how binary fission functions, including how to make a new cell wall and a copy of a bacterial chromosome. Mitosis and binary fission, two types of asexual reproduction, both entail the division of a parent cell into two identical daughter cells.

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According to the given statement the alpha particle's wavelength is 6.48×10⁻¹⁵ meters.

The positively charged alpha particles (α) are created when the nucleus of an atom's two protons as well as two neutrons join forces. Alpha particles are created by the radioactivity of the most dangerous radioactive elements, including uranium, radium, and polonium.

The de Broglie wavelength equation may be used to determine the alpha particle's wavelength:

λ = h / p

where p is the particle's momentum, h is its Planck constant (6.626 * 10⁻³⁴ J s), and is its wavelength.

The mass (m) and velocity (v) of an alpha particle may be used to compute its momentum:

p = m * v

Inputting the values provided yields:

p = (6.70×10⁻²⁷ kg) * (1.52×10⁷ m/s) = 1.02×10⁻¹⁹ kg m/s

Now we can determine the wavelength using this value:

λ = h / p = 6.626 x 10⁻³⁴ J s / 1.02×10⁻¹⁹ kg m/s

λ = 6.48 x 10⁻¹⁵ m

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The complete question is -

Calculate the wavelength of -

An alpha particle (6.70×10⁻²⁷ kg) moving at a speed of 1.52×10⁷ m/s (34000000 miles per hour). What is the m ?