Question 5(Multiple Choice Worth 4 points) (05.05)Based on the graph, what is the initial value of the linear relationship?

Answer:

C. 1/16

Step-by-step explanation:

[tex]16 * 4^{-4}[/tex]

16 can be written as a power of 4.

[tex]4^2 * 4^{-4}[/tex]

The bases are same, add exponents.

[tex]4^{2+-4}[/tex]

[tex]4^{-2}[/tex]

Simplify negative exponent.

[tex]\frac{1}{4^2 }[/tex]

[tex]\frac{1}{16}[/tex]

Answer:

Option C.

Step-by-step explanation:

In the given figure we have two parallel lines AB and CD.

A transversal line FB intersect the parallel lines at point B and C.

We know that the if a transversal line intersect two parallel lines, then corresponding angles are congruent.

[tex]\angle ABC=\anle ECF[/tex]

[tex]x=y[/tex]

To prove this by translation, we need a translation along the directed line segment CB maps ine CD onto line AB and angle y onto angle x.

Therefore, the correct option is C.

Answer:

(a) The value of x is 5.

(b) The value of y is 15.

Step-by-step explanation:

Let the random variable X represent the number of electric toasters produced that require repairs within 1 year.

And the let the random variable Y represent the number of electric toasters produced that does not require repairs within 1 year.

The probability of the random variables are:

P (X) = 0.20

P (Y) = 1 - P (X) = 1 - 0.20 = 0.80

The event that a randomly selected electric toaster requires repair is independent of the other electric toasters.

A random sample of n = 20 toasters are selected.

The random variable X and Y thus, follows binomial distribution.

The probability mass function of X and Y are:

[tex]P(X=x)={20\choose x}(0.20)^{x}(1-0.20)^{20-x}[/tex]

[tex]P(Y=y)={20\choose y}(0.20)^{20-y}(1-0.20)^{y}[/tex]

(a)

Compute the value of x such that P (X ≥ x) < 0.50:

[tex]P (X \geq x) < 0.50\\\\1-P(X\leq x-1)<0.50\\\\0.50<P(X\leq x-1)\\\\0.50<\sum\limits^{x-1}_{0}[{20\choose x}(0.20)^{x}(1-0.20)^{20-x}][/tex]

Use the Binomial table for n = 20 and p = 0.20.

[tex]0.411=\sum\limits^{3}_{x=0}[b(x,20,0.20)]<0.50<\sum\limits^{4}_{x=0}[b(x,20,0.20)]=0.630[/tex]

The least value of x that satisfies the inequality P (X ≥ x) < 0.50 is:

x - 1 = 4

x = 5

Thus, the value of x is 5.

(b)

Compute the value of y such that P (Y ≥ y) > 0.80:

[tex]P (Y \geq y) >0.80\\\\P(Y\leq 20-y)>0.80\\\\P(Y\leq 20-y)>0.80\\\\\sum\limits^{20-y}_{y=0}[{20\choose y}(0.20)^{20-y}(1-0.20)^{y}]>0.80[/tex]

Use the Binomial table for n = 20 and p = 0.20.

[tex]0.630=\sum\limits^{4}_{y=0}[b(y,20,0.20)]<0.50<\sum\limits^{5}_{y=0}[b(y,20,0.20)]=0.804[/tex]

The least value of y that satisfies the inequality P (Y ≥ y) > 0.80 is:

20 - y = 5

y = 15

Thus, the value of y is 15.

Answer: [tex]\dfrac{1}{5}[/tex]

Step-by-step explanation:

From, the circle graph in the attachment below,

The percentage of portion taken by 6 (dark blue) = 20%  

So, the probability of pulling out a tile with a 6 on it = percentage of portion taken by 6 (dark blue) = 20%     [Probability can also be written as a percentage]

[tex]=\dfrac{20}{100}\\\\=\dfrac{1}{5}[/tex]  [we divide a percentage by 100 to convert it into fraction]

Hence, the probability of pulling out a tile with a 6 on it = [tex]\dfrac{1}{5}[/tex]

Answer: C)  tan(pi/56)

=============================================

Explanation:

I recommend using a trig identity reference sheet. The specific identity we will be using is [tex]\frac{\tan(A)-\tan(B)}{1+\tan(A)\tan(B)} = \tan(A-B)[/tex]

What we are given is in the form [tex]\frac{\tan(A)-\tan(B)}{1+\tan(A)\tan(B)}[/tex] with A = pi/7 and B = pi/8

A-B = (pi/7)-(pi/8)

A-B = pi(1/7-1/8)

A-B = pi(8/56 - 7/56)

A-B = pi*(1/56)

A-B = pi/56

Therefore,

[tex]\frac{\tan\left(\pi/7\right)-\tan(\pi/8)}{1+\tan(\pi/7)\tan(\pi/8)} = \tan\left(\pi/56\right)[/tex]

Answer:

f(x) = (x + 6)² - 29

Step-by-step explanation:

Given

f(x) = x² + 12x + 7

To complete the square

add/subtract ( half the coefficient of the x- term )² to x² + 12x

x² + 2(6)x + 36 - 36 + 7

= (x + 6)² - 29, thus

f(x) = (x + 6)² - 29

answers are 6, and -29

Answer:

the answer is y= 2/3x - 5

Answer:

i think (d) one i think it will help you

Answer:

18

Step-by-step explanation:

Given the above table of the data set, the number of values less than or equal to 6 would be the sum of the frequencies of all values that is equal to or less than 6.

From the table above, we would add up the frequencies of the values of 6 and below, which is:

2 + 3 + 6 + 4 + 3 = 18

Answer = 18

The number of values less than or equal to 6 is 18

Here the number of values should be less than or equivalent to 6 represent the sum of the frequencies i.e. equal or less than 6

So, here the number of values should be

= 2 + 3 + 6 + 4 + 3

= 18

Hence, we can conclude that  The number of values less than or equal to 6 is 18

Learn more about frequency here: https://brainly.com/question/20875379

Answer:

Revenue : 47.77

Units Sold : 28.91

Step-by-step explanation:

The revenue is the amount that is received after selling the goods manufactured. VanArsdel's sold good of manufactured in Alberta. Goods manufactured by VanArsdel's is considered as 100 percent out of which it sold 28.91 % of units in Alberta. The revenue percentage is 47.77%.

Answer:

The least common multiple of $6!$ and $(4!)^2.$

is 6×4! or 144

I think the answer is option B.

Because while researchers research they believed that it will lengthen the time and it don't reduced the time.

Hope it's correct..

Answer:

(A) What is the z- score of the sample mean?

The z- score of the sample mean is 0.0959

(B) Is this sample significantly different from the population?

No; at 0.05 alpha level (95% confidence) and (n-1 =79) degrees of freedom, the sample mean is NOT significantly different from the population mean.

Step -by- step explanation:

(A) To find the z- score of the sample mean,

X = 75 which is the raw score

¶ = 74 which is the population mean

S. D. = 10.43 which is the population standard deviation of/from the mean

Z = [X-¶] ÷ S. D.

Z = [75-74] ÷ 10.43 = 0.0959

Hence, the sample raw score of 75 is only 0.0959 standard deviations from the population mean. [This is close to the population mean value].

(B) To test for whether this sample is significantly different from the population, use the One Sample T- test. This parametric test compares the sample mean to the given population mean.

The estimated standard error of the mean is s/√n

S. E. = 16/√80 = 16/8.94 = 1.789

The Absolute (Calculated) t value is now: [75-74] ÷ 1.789 = 1 ÷ 1.789 = 0.559

Setting up the hypotheses,

Null hypothesis: Sample is not significantly different from population

Alternative hypothesis: Sample is significantly different from population

Having gotten T- cal, T- tab is found thus:

The Critical (Table) t value is found using

- a specific alpha or confidence level

- (n - 1) degrees of freedom; where n is the total number of observations or items in the population

- the standard t- distribution table

Alpha level = 0.05

1 - (0.05 ÷ 2) = 0.975

Checking the column of 0.975 on the t table and tracing it down to the row with 79 degrees of freedom;

The critical t value is 1.990

Since T- cal < T- tab (0.559 < 1.990), refute the alternative hypothesis and accept the null hypothesis.

Hence, with 95% confidence, it is derived that the sample is not significantly different from the population.

Answer:

a=11/5 OR 5.5

Step-by-step explanation:

Answer:

Yes

Step-by-step explanation:

They are congruent by the AAS postulate.

∠A corresponds to and is congruent to ∠D

Side BC corresponds to and is congruent to side EC

∠C is congruent to ∠C by the Vertical Angles Theorem.

So, ΔABC ≅ ΔDEC

Answer:

I am pretty sure that the answer is D. The value should be 1.

Step-by-step explanation:

Answer:

Answer is D

Step-by-step explanation:

On Edge 2020

[tex]y^2 = 9(9+3)\\\\y^2 = 9(12)\\\\y^2 =3^2\cdot3\cdot2^2\\\\y = 6\sqrt{2}[/tex]

Answer:

X+y = 20... equation 1

3.2x + 2y = 54.4...equation 2

X= 12

12 of $3.2 grade is needed

Step-by-step explanation:

Let x = grade containing$ 3.2 per pound

Let y = grade containing $2.00 per pound

X+y = 20... equation 1

X3.2 +2y = 20(2.72)

3.2x + 2y = 54.4...equation 2

Multiplying equation 1 by 2

2x +2y = 40

3.2x + 2y = 54.4

1.2x = 14.4

X= 12

If x= 12

2x +2y = 40

2(12) + 2y = 40

2y = 40-24

2y = 16

Y= 8

Answer:

g(x) = -2x - 5

2x becomes -2x as a reflection across the y-axis

add on -5 to shift the function 5 units down

Answer:

(0, 3), (4, -1)

(1, 2)

Step-by-step explanation:

If the answers that have been provided to you are only in pairs then it'd just be the first answer I wrote. The points (1, 2) also are on the graph of y=x+3 but if the answers aren't individual than I'd just stick with the (0, 3), (4, -1). Does that make sense? I used a graphing calculator online called Desmos, it's very good. I highly recommend it for problems like these.

I hope this helps:) Select as brainliest because I actually put work into this and tried.

Answer:

The probability is [tex]P(x_1 \le X \le x_2 ) = 0.4332[/tex]

Step-by-step explanation:

From the question we are told that

   The population mean is  [tex]\mu = 400[/tex]

   The  standard deviation is  [tex]\sigma = 10[/tex]

   The considered values are  [tex]x_1 = 400 \to x_2 = 415[/tex]

Given that the weight follows a normal distribution

     i.e       [tex]\approx X (\mu , \sigma )[/tex]

Now the probability of a weight between 415 pounds and the mean of 400 pounds is mathematically as

     [tex]P(x_1 \le X \le x_2 ) = P(\frac{x_1 - \mu }{\sigma } \le \frac{X - \mu }{\sigma } \le \frac{x_2 - \mu }{\sigma } )[/tex]

So  [tex]\frac{X - \mu }{\sigma }[/tex] is equal to Z (the standardized value of  X  )

Hence we have  

     [tex]P(x_1 \le X \le x_2 ) = P(\frac{x_1 - \mu }{\sigma } \le Z \le \frac{x_2 - \mu }{\sigma } )[/tex]

substituting values

      [tex]P(x_1 \le X \le x_2 ) = P(\frac{400 - 400 }{10 } \le Z \le \frac{415 - 400}{415 } )[/tex]

      [tex]P(x_1 \le X \le x_2 ) = P(0\le Z \le 1.5 )[/tex]

      [tex]P(x_1 \le X \le x_2 ) = P( Z < 1.5) - P( Z < 0)[/tex]

From the standardized normal distribution table  [tex]P( Z< 1.5) = 0.9332[/tex] and

   [tex]P( Z < 0) = 0.5[/tex]

So

     [tex]P(x_1 \le X \le x_2 ) = 0.9332 - 0.5[/tex]

     [tex]P(x_1 \le X \le x_2 ) = 0.4332[/tex]

NOTE :  This above  values obtained from the standardized normal distribution table can also be obtained using the P(Z) calculator at  (calculator dot net).

Answer:

a) percentage of the employees that will experience lost-time accidents in both years = 1.2%

b) percentage of the employees that will suffer at least one lost-time accident over the two-year period = 10.8%

Step-by-step explanation:

given

percentage of lost time accident last year

P(L) = 8% = 0.08 of the employees

percentage of lost time accident current year

P(C) = 4% = 0.04 of the employees

P(C/L) = 15% = 0.15

using the probability

P(L ∩ C) = P(C/L) × P(L)

= 0.08 × 0.15 = 0.012 = 1.2%

percentage of the employees will experience lost-time accidents in both years = 1.2%

b) Using the probability of the event

P(L ∪ C) = P(L) + P(C) - P(L ∩ C)

= 0.08 + 0.04 -0.012 = 0.108 = 10.8%

percentage of the employees will suffer at least one lost-time accident over the two-year period = 10.8%

Answer:

Centerville is 13 kilometers away from Manchester

Step-by-step explanation:

26.1 - 13.1 = 13

Answer:

f(9,6) = 2

Step-by-step explanation:

We know df = (df/dx)dx + (df/dy)dy

From the question, df/dx = fx(8,5) = 2 and df/dy = fy(8,5) = 2

Since we need to find f(9,6) and f(8,5) = -2

dx = 9 - 8 = 1 and dy = 6 - 5 = 1

f(9,6) = f(8,5) + df

df = (df/dx)dx + (df/dy)dy

df = fx(8,5)dx + fy(8,5)dy

Substituting the values of fx(8,5) = 2, fy(8,5) = 2, dx = 1 and dy = 1

df = 2 × 1 + 2 × 1

df = 2 + 2

df = 4

f(9,6) = f(8,5) + df

substituting the value of df  and f(8,5) into the equation, we have

f(9,6) = -2 + 4

f(9,4) = 2

The value of f(9,6) = 2

Answer:

15

Step-by-step explanation:

Answer:

30

Step-by-step explanation:

30 hcchxfifififififfud7dd7d

Answer:

6x + y = -18

Step-by-step explanation:

The given equation is,

y - 6 = -6(x + 4)

We have to rewrite this equation in the form of Ax + By = C

Where A, B and C are the integers.

By solving the given equation,

y - 6 = -6x - 24 [Distributive property]

y - 6 + 6 = -6x - 24 + 6 [By adding 6 on both the sides of the equation]

y = -6x - 18

y + 6x = -6x + 6x - 18

6x + y = -18

Here A = 6, B = 1 and C = -18.

Therefore, 6x + y = -18 will be the equation.

Answer:

Given:

AC = 14      and       BC = 9

AB = ?

Solution:

From the fig:

AC = AB + BC

Putting the values

14 = AB + 9

AB = 14 - 9

AB = 5

(you can also take AB = x or any other variable)

Step-by-step explanation:

Answer:

8192

Step-by-step explanation:

2 ¹²= 4096

4096 x 2 = 8192

Answer:

Let the distance be AB.

So, by using distance formula, we get

AB=√(x^2-x^1)^2+(y^2-y^1)^2

AB=√[-1-(-3)]^2+[-2-(-2)]^2

AB=√(-1+3)²+(-2+2)²

AB=√2²+0²

AB=√4

AB=2 units

hope it helps u...

plz mark as brainliest...

Answer: The distance between the points (-3, -2) and (-1, -2). is 2

Answer: A(3, -5)

B(6, -2)

C(9, -2)

Step-by-step explanation:

If we have a point (x, y), and we do a reflection over the axis y = a, then the only thing that will change in our point is the value of x.

Now, the distance between x and a must remain constant before and after the reflection.

so if x - a = d

then the new position of the point will be:

(a - d, y) = (2a - x, y).

I will use that relationship for the 3 points

A)

We start with the point (1, -5)

The reflection over y = -1 leaves.

The distance between 1 and -1 is = 1 - (-1) = 2.

Then the new point is (-1 - 2, -5) = (-3, -5)

Now we do a reflection over y = 1, so D = -3 - 1 = -2

Then the new point is:

A = (1 -(-2), -5) = (3, -5)

B) (2, -2)

Reflection over y = -1.

distance, d = 2 - (-1) = 3

the point is (-1 - 3, -2) = (-4, -2)

Now, a reflection over y = 1.

The distance is D = -4 - 1 = -5

The new point is (1 - (-5), 2) = (6, -2)

C) (5, -2)

reflection over y = -1

Distance: D = 5 - ( - 1) = 6

New point: (-1 - 6, -2) = (-7, -2)

Reflection over y = 1.

Distance D = -7 - 1 = -8

New point ( 1 - (-8), -2) = (9, -2)