Question 5
A swimming pool has a length of 30 ft, a width of 12 ft, and a uniform depth of 8 ft. How many gallons of water does it hold?
(Hint: Find the volume in cubic ft and then use dimensional analysis to convert to gallons. 7.5 gal - 1 cubic ft.)
Round your answer to the nearest whole gallon, but do not include a unit of measure with your response.

Answer:

False.

Step-by-step explanation:

Whole numbers can be described as the integers greater than and including zero. 56 has no fractional or decimal part, and is positive, so it is a whole number and an integer!

Answer: 1680ml

Step-by-step explanation:

1000 mL are in 1 L, so with that logic

1=1000

.68=680

1000+680=1680

Step-by-step explanation:

A=Xb c

2+4=6

5+5=10

9+20=75

Answer:

ab=20 bc=16+4=20 ac=40

The correct option is M(2) = 39; If Hazel mows a yard for 2 hours, she will earn $39 . Option C

A function can be defined as an expression that shows the relationship between an independent variable and a dependent variable.

Given the function;

M(t) = 7t + 25

Where;

For M(2), we substitute the value of t as 2 in the function

M(2) = 7(2) + 25

M(2) = 14 + 25

M(2) = $39

This explains that the she mows the yard for t = 2 hours, she would earn $39

Thus, the correct option is M(2) = 39; If Hazel mows a yard for 2 hours, she will earn $39. Option C

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Answer:

40 degrees

Step-by-step explanation:

Substitute f = 104:

[tex]C = \frac{5(f - 32)}9 \\\\\to C = \frac{5(104 - 32)}9 \\\\\to C = \frac{5 \times 72}9 \\\\\to C = 5 \times 8 = 40 \text{ degrees}[/tex]

Answer:

Both factors are negative,so that the product will be positive

Step-by-step explanation:

Hope it helps you

[tex] \frac{3}{ \sqrt{5} - 2 } [/tex]

Rationalize the denominator by multiplying the numerator and denominator by the denominator. (Important: if the denominator has a minus sign, change to plus and vice versa)

[tex]⟹\frac{3 \times \sqrt{5 + 2} }{ (\sqrt{5} - 2 ) \times ( \sqrt{5} + 2) } [/tex]

[tex] ⟹ \frac{3 \sqrt{5} + 6 }{ \sqrt{25} + 2 \sqrt{5} - 2 \sqrt{5} - 4 } ⟹\frac{3 \sqrt{5} + 6 }{5 - 4} [/tex]

[tex] ⟹\frac{3 \sqrt{5} + 6}{1} ⟹3 \sqrt{5} + 6[/tex]

[tex] \frac{6 - \sqrt{12} }{ \sqrt{3} + \sqrt{10} } [/tex]

Rationalize the denominator.

[tex] ⟹\frac{(6 - \sqrt{12} ) \times ( \sqrt{3} - \sqrt{10} )}{ (\sqrt{3} + \sqrt{10} ) \times ( \sqrt{3} - \sqrt{10} } [/tex]

[tex]⟹\frac{6 \sqrt{3} - 6 \sqrt{10} - \sqrt{36} + \sqrt{120} }{ \sqrt{9} - \sqrt{30} + \sqrt{30} - \sqrt{100} } [/tex]

[tex]⟹ \frac{6 \sqrt{3} - 6 \sqrt{10} - \sqrt{36} + \sqrt{120} }{3 - 10} ⟹ \frac{6 \sqrt{3} - 6 \sqrt{10} - \sqrt{36} + \sqrt{120} }{ - 7} [/tex]

[tex] ⟹\frac{6 \sqrt{3} - 6 \sqrt{10} - 6 + \sqrt{12 \times 10} }{ - 7}⟹\frac{6 \sqrt{3} - 6 \sqrt{10} - 6 + 4 \sqrt{3 \times 10} }{ - 7} [/tex]

[tex] ⟹ - \frac{6 \sqrt{3} - 6 \sqrt{10} - 6 + 2 \sqrt{30} }{7} [/tex]

Therefore:

1. [tex]3 \sqrt{5} + 6[/tex]

2. [tex] - \frac{6 \sqrt{3} - 6 \sqrt{10} - 6 + 2 \sqrt{30} }{7} [/tex]

Answer:  [tex](5.6)^3[/tex]

This is the same as saying (5.6)^3

===============================================

Explanation:

The base is 5.6 and it is multiplied a total of 3 times. We use an exponent of 3 to condense things down. So [tex]5.6 * 5.6 * 5.6 = (5.6)^3[/tex]

Another example: [tex]2^4 = 2*2*2*2 = \text{four copies of '2' multiplied}[/tex]

Considering the definition of an inequality, the inequality that can be used to determine p, the maximum number of people who can go to the amusement park, is:

17.25 + 37.25×p ≤ 605

An inequality is the existing inequality between two algebraic expressions, connected through the signs:

Solving an inequality consists of finding all the values ​​of the unknown for which the inequality relation holds.

In this case, you know that:

Being "p" the number of people who can go to the amusement park, the inequality that expresses the previous relationship is

17.25 + 37.25×p ≤ 605

Finally, the inequality that can be used to determine p, the maximum number of people who can go to the amusement park, is:

17.25 + 37.25×p ≤ 605

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A point that is part of the intersection of planes ACD and MHG is: Point B.

A plane has at least three points that lie on it. When two planes intersect, they do so at some certain points. This means that two intersecting planes share some points in common alone the line of their intersection.

In the diagram given, plane ACD and plane MHG intersect along line BA. This means that both planes share points A and B in common.

Therefore, we can state that a point that is part of the intersection of planes ACD and MHG is: Point B.

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Answer:

the answer is B

Step-by-step explanation:

x = y - 9

y - 4 = 10

x = ?

y = 10 + 4

° y = 14

x = y - 9

= 14 - 9

✔️ x = +5

ANSWERS

y-4=10

y=10+4

y=14

sub y equ 1

x=14-9

x=+5

Answer:

it d

Step-by-step explanation:

1) When k = 1.5 and x = 50, the value of y is; y = 75

2) When k = 14 and y = 334, the value of x is; x = 23.84

3) When k = 12 and x = 245, the value of y is; y = 2940

4) When k = 16 and y = 38, the value of x is; x = 2.375

We are given the equation for the constant of proportionality, as y/x = k

1) When k = 1.5 and x = 50, we want to find the value of y = ?

y/50 = 1.5

y = 50 * 1.5

y = 75

2) k = 14 and y = 334, x = ?. We want to find the value of x. Thus;

334/x = 14

x = 334/14

x = 23.84

3) k = 12 and x = 245, y = ?

y/245 = 12

y = 245 * 12

y = 2940

4) k = 16 and y = 38; x = ?

38/x = 16

x = 38/16

x = 2.375

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Complete question is;

Solve for the unknown value using the equation for the constant of proportionality, y/x = k .Known Values​ Unknown Value​

k = 1.5 and x = 50

y = ?

k = 14 and y = 334, x = ?

k=12 and x=245, y = ?

k = 16 and y = 38; x = ?

For the given geometric sequence, we have that:

A geometric sequence is a sequence in which the result of the division of consecutive terms is always the same, called common ratio q.

The nth term of a geometric sequence is given by:

[tex]a_n = a_1q^{n-1}[/tex]

In which [tex]a_1[/tex] is the first term.

For the series given by:

8, 12, 18, 27, ...

We have that:

When a geometric series is infinite and has a common ratio greater than 1, it diverges.

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The image of the point after a 180∘ counterclockwise rotation about the origin is (-1, 4)

The given parameters are

Point = (1, -4)

Transformation: 180∘ counterclockwise about the origin

The rule of 180∘ counterclockwise about the origin is

(x, y) = (-x, -y)

When this rule is applied to the given point, we have the image to be

Image = (-x, -y)

This gives

Image = (-1, 4)

Hence, the image of the point after a 180∘ counterclockwise rotation about the origin is (-1, 4)

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Answer:

Step-by-step explanation:

annie runs in park = every 3 days

ron runs in park = every 5 days

lets find LCM of 3 and 5 = 3*5 = 15

if they ran on 1st of January then they will meet again on on 15th January , will again meet on 30th of January and will again meet on 14 February . if is was a leap year they would again meet at 29th February .

From the given examples 5z - 3x = -3x + 5z  and 5(xy) = 5(xy) are following the commutative property.

According to the given question.

We have some equations

2x + 3x = 5x

5xy = 5(xy)

5z - 3x = -3x + 5z

3(a + b) = 3a + 3b

Here, we have to find which equation is following the commutative property.

As we know that, the commutative property is a math rule that says that the order in which we multiply numbers does not change the product.

For, example 4 + 5 gives 9, and 5 + 4 also gives 9.

From the given example the equation

5z - 3x = -3x + 5z is following the commutaive property of addition.

And, 5(xy) = 5(xy) is following the commutative property of multiplication.

Hence, from the given examples 5z - 3x = -3x + 5z  and 5(xy) = 5(xy) are following the commutative property.

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Answer: Does it specify how long his short bumper stickers are?

Step-by-step explanation:

[tex]{ \qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Here we go ~

Value of g (x) is -2, when :

[tex]\qquad \sf  \dashrightarrow \: - 2.5 < x \leqslant - 1.5[/tex]

And since -2 lies in this range of x,

[tex]\qquad \sf  \dashrightarrow \:g( - 2) = - 2[/tex]

Value of x is -1, when :

[tex]\qquad \sf  \dashrightarrow \: - 1.5 < x \leqslant - 0.5[/tex]

And -0.5 falls in this range, hence

[tex]\qquad \sf  \dashrightarrow \:g( - 0.5 ) = - 1[/tex]

Next, The value of x is 0 when :

[tex]\qquad \sf  \dashrightarrow \: - 0.5 < x < 0.5 [/tex]

But, it isnt equal to 0.5, since there is open interval at both extremes.

Next, Value of x is 1, when :

[tex]\qquad \sf  \dashrightarrow \:0.5 \leqslant x < 1.5[/tex]

And since it also has the value 0.5 included in it,

[tex]\qquad \sf  \dashrightarrow \:g(0.5) = 1[/tex]

p = (n - 30)/ 6 as a function of n.

Here we need to find the value of p in terms of n.

From the question, we have two equation

The first equation is:

   m = 1/6n .......(1)

The second equation is:

    p = m - 5.......(2)

From equations 1 and 2 we have to find the value of p in term of n.

So by putting the value of m in the second equation we have:

p = 1/6n - 5

  = (n - 30)/6

Therefore we get the value of p as (n -30)/6 in terms of n.

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The slope of the line -1/6.

The value of m = -1.

The slope of a line is a measure of its steepness. slope is calculated as "rise over run" (change in y divided by change in x).

given:

f(x) = √10-x

let f(x)=y

y = √10-x

Now,

dy/dx = -1/2(√10-x)

at x=1

dy/dx =  -1/2(√10-1)

dy/dx = -1/2(3)

dy/dx = -1/6

equation of line is

y= mx + b

y= (-1/6)x + b

6y = -x + b

So, m= -1

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4,12
represents that jorge takes 4 steps to walk 12 feet
or represents number of steps that it takes to walk 12 feet either is right

Answer:

D. ∠1 and ∠3

Hope this helps!

Answer:

1 and 3 or also known as D

Step-by-step explanation:

i took the test and got it right

Answer:

Step-by-step explanation:

Compute the midpoint of the line segment with endpoints:

p_1 = (-4, 4) and p_2 = (5, -1)

The midpoint between (x_1, y_1) and (x_2, y_2) is their componentwise average:

((x_1 + x_2)/2, (y_1 + y_2)/2)

Substitute (x_1, y_1) = (-4, 4) and (x_2, y_2) = (5, -1):

= ((-4 + 5)/2, (4 - 1)/2)

-4 + 5 = 1:

= (1/2, (4 - 1)/2)

4 - 1 = 3:

Answer:  = (1/2, 3/2)

Answer: 1/10 of a pound

Step-by-step explanation:

The total weight was 7/10 of a pound. Cutting the fudge into 7 pieces implies dividing the fudge by 7.

7 is the same as 7/1.

When dividing fractions, we can multiply by the reciprocal. Essentially, we just flip the second number.

[tex]\frac{7}{10}/7 =\frac{7}{10} / \frac{7}{1} =\frac{7}{10} *\frac{1}{7}[/tex]

We can multiply this out to 7/70 and then simplify to 1/10,

or we could first cross simplify by dividing the 7s out of the numerator and denominator before multiplying. Either way, your answer ends up being 1/10 of a pound.

Hope this helps!

Answer:

Choice a) 3700 €

Step-by-step explanation:

Total salary among 12 workers = Avg Salary x 12 = 3500 x 12 = 42,000 €

Total salary of 2 part-timers = part-time avg x 2 = 2500 x 2 = 5000

Total salary without part-timers salary= 42,000 - 5000 = 37,000 €

If we exclude the 2 part-timers, there are 10 full-timers who earn 37,000 €

So new Average Salary = 37000/10 = 3,700 €

answer: Choice a) 3700 €

If the coordinate is reflected over the y-axis, the resulting coordinates will be (1, 2).

Images that are reflected are mirror images of each other. For instance, given the coordinate points (x, y), if it is reflected across the y-axis, then the result of the expression is (-x, y).

Given the coordinate point (-1, 2), if the coordinate is reflected over the y-axis, the resulting coordinates will be (1, 2).

Note that the x-coordinate point is negated if the coordinate is reflected over the y-axis.

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We need to know the relation between height, time to solve this problem. The time taken by the object to be 6 feet above the valley floor is 25 seconds.

The distance an object falls is proportional to the time it took to fall because of gravitational force. Here we have been given an equation that shows us the relation between height of the object and the time taken to reach that height. We know that the initial height of the object is 406 feet, if we substitute the initial height in the equation we get time to be zero which shows us that this is the initial height. We need to find out the time taken by the object to be 6 feet above the valley floor.

h= -16t+406

6=-16t+406

-400=-16t

t=400/16=25 seconds

Therefore the time taken by the object to be at a height 6 feet above the valley floor is 25 seconds.

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