Question 4Multiple Choice Worth 5 points)
(Dilations MC)
Polygon ABCD with vertices at A(1,-1), B(3, -1), C(3, -2), and D(1, -2) is dilated to create polygon ABCD with vertices at A(4, -4), B(12,-4), C(12, -3), and D(4, -3). Determine the scale factor used to
create the image
0 1/4
0 1/2
0 2
0 4

The value of 408^5 is approximately 273,539,283,056,896. This is a large number that can be accurately calculated using a calculator or computer program.

To work out the value of 408^5, we need to perform the exponentiation calculation. In this case, 408 is the base, and 5 is the exponent.

Calculating large exponentiations like this can be time-consuming and prone to error if done manually. However, with the help of a calculator or computer, we can easily find the result.

Using a calculator or computer program, we can calculate 408^5 and obtain the value. The result is a very large number:

408^5 ≈ 273,539,283,056,896

Therefore, the value of 408^5 is approximately 273,539,283,056,896.

In decimal notation, the value is written as:

273,539,283,056,896

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The solution to the system is (a) a = 4/5, b = 5, c = -4 and d =-4

From the question, we have the following parameters that can be used in our computation:

The augmented matrix

Where, we have

[tex]\left[\begin{array}{cccc|c}1&0&0&0&4/5\\0&1&0&0&5\\0&0&1&0&-4\\0&0&0&1&-4\end{array}\right][/tex]

From the above, we have the diagonals to be 1

And other elements to be 0

This means that the equation has been solved

So, we have

a = 4/5, b = 5, c = -4 and d =-4

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Answer:

Based on the values in the table, it can be observed that changing the radius of the sphere has a direct effect on the surface area of the sphere. As the radius increases, the surface area also increases.

Step-by-step explanation:

In general, multiplying the radius of a sphere by a factor of x will result in the surface area of the sphere being multiplied by a factor of x^2. This is because the surface area of a sphere is given by the formula:

Surface Area = 4πr^2

When the radius is multiplied by a factor of x, the new radius becomes xr. Substituting this into the formula, we get:

New Surface Area = 4π(xr)^2

= 4πx^2r^2

= x^2(4πr^2)

Therefore, the surface area of the sphere is multiplied by a factor of x^2 when the radius is multiplied by a factor of x. This relationship shows that the surface area increases at a faster rate than the radius.

Answer:

The fish tank holds 40,000 ml of water.

Step-by-step explanation:

Volume = Length x Width x Height

Volume = 50 x 40 x 20

Volume = 40,000

Answer:  See the flowchart proof below.

Explanation:

The given info is indicated by the marked angles. We also use the reflexive property to say that BG = BG. After that we use the ASA (angle side angle) property to prove the triangles are congruent. The triangles are mirrored clones of one another. The mirror line is segment BG.

A flowchart proof that proves that the two triangles are congruent is shown in the image below.

In Mathematics and Geometry, two triangles are said to be similar when the ratio of their corresponding side lengths are equal and their corresponding angles are congruent.

In this context, we can prove that triangle BIG is congruent with triangle BAG by completing the two-column proof shown above with the following reasons:

Statements                                Reasons

∠IBG ≅ ∠ABG                              Given

∠IGB ≅ ∠AGB                              Given

BG ≅ BG                               Reflexive property

ΔBIG ≅ ΔBAG                       ASA Congruence

Based on the angle, side, angle (ASA) similarity theorem, we can logically deduce that triangle BIG and triangle BAG are both congruent.

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Answer:

A 1/2

Step-by-step explanation:

was on my test trust me on this one

The density of lead is 11,300 kg/[tex]m^3[/tex], which means that lead is a dense material with a significant mass per unit volume.

To find the density of lead, we can use the formula:

Density = Mass / Volume

Given that the mass of lead is 3,390 kg and the volume is 0.3 [tex]m^3[/tex], we can substitute these values into the formula:

Density = 3,390 kg / 0.3[tex]m^3[/tex]

To simplify the calculation, we divide the mass by the volume:

Density = 11,300 kg/[tex]m^3[/tex]

Therefore, the density of lead is 11,300 kg/[tex]m^3[/tex].

Density is a physical property of a substance that describes how much mass is packed into a given volume. In this case, the density of lead tells us that for every cubic meter of lead, there are 11,300 kilograms of mass.

It is important to note that the density of lead is a characteristic property and remains constant regardless of the size or shape of the sample. It is a useful parameter in various scientific and industrial applications.

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The question probable may be:

If 3,390 kg of lead occupy a volume of 0.3 m^3, find the density of lead.

Answer:

211%

Step-by-step explanation:

percent = part/whole × 100%

percent = 19/9 × 100%

percent = 211%

Answer:

The range of this graph is (-4, 6], or

-4 < y < 6.

The range of the graph is [-4, 6].

In Mathematics and Geometry, a range is the set of all real numbers that connects with the elements of a domain.

This ultimately implies that, a range simply refers to the set of all possible output numerical values (real numbers), which are shown on the y-coordinate (y-axis) of a graph.

Based on the information provided in this scenario, the domain and range of the graph of this equation can be determined are as follows:

Domain = [1, 10] or 1 ≤ x < 10

Range = [-4, 6], or -4 < y ≤ 6.

Therefore, the range can be rewritten as [-4, 6].

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2 5 7 ÷ 4 5 6 3

- 2 5 7

1993

- 1 7 9 9

Answer:

194

We can solve for d = 150 / (tan(34) - tan(12)) Once we have the value of d, we can substitute it back into the equation h = d * tan(12) to find the height h of the smaller building.

To find the height h of the smaller building, we can use trigonometric ratios and the concept of angles of depression.

Let's denote the height of the smaller building as h. We are given that the observer in the larger building measures angles of depression of 12 degrees and 34 degrees to the top and bottom of the smaller building, respectively.

From the given information, we can form a right triangle with the vertical distance between the observer and the smaller building as the opposite side and the horizontal distance between the observer and the smaller building as the adjacent side.

Using trigonometric ratios, we can set up the following equations:

For the angle of depression of 12 degrees:

tan(12) = h / d

For the angle of depression of 34 degrees:

tan(34) = (h + 150) / d

Here, d represents the horizontal distance between the observer and the smaller building.

We can solve these two equations simultaneously to find the values of h and d.

From the equation for the angle of depression of 12 degrees, we can rewrite it as:

h = d * tan(12)

Substituting this expression for h in the equation for the angle of depression of 34 degrees, we get:

tan(34) = (d * tan(12) + 150) / d

Now, we can solve this equation for d. Rearranging the equation, we have:

d * tan(34) = d * tan(12) + 150

Simplifying further:

d * (tan(34) - tan(12)) = 150

Finally, we can solve for d:

d = 150 / (tan(34) - tan(12))

Once we have the value of d, we can substitute it back into the equation h = d * tan(12) to find the height h of the smaller building.

Note: To obtain an actual numerical value for h, we need the precise values of the tangent of 12 degrees and 34 degrees.

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The largest possible weight for the package is 11.5 kg.

To find the largest possible weight for the package, we need to consider the range within which the weight lies when rounded to the nearest kilogram.

When the package is weighed at 11 kg to the nearest kilogram, it means the actual weight could be anywhere between 10.5 kg and 11.5 kg. This is because rounding to the nearest kilogram involves considering values halfway between two integers to round up or down.

To determine the largest possible weight, we take the upper limit of this range, which is 11.5 kg. Therefore, the largest possible weight for the package is 11.5 kg.

Keep in mind that when rounding to the nearest kilogram, values from 10.5 kg to 11.4 kg would round down to 11 kg, while values from 11.5 kg to 12.4 kg would round up to 12 kg.

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1a. Sum of interior angles of a heptagon:

[tex]\displaystyle \sf \text{Sum of interior angles} = (7 - 2) \times 180^\circ = 900^\circ[/tex]

1b. Sum of interior angles of a 13-gon:

[tex]\displaystyle \sf \text{Sum of interior angles} = (13 - 2) \times 180^\circ = 1980^\circ[/tex]

2. Number of sides for a polygon with a sum of interior angles of 1260°:

[tex]\displaystyle \sf (n - 2) \times 180^\circ = 1260^\circ[/tex]

[tex]\displaystyle \sf n - 2 = \frac{1260^\circ}{180^\circ}[/tex]

[tex]\displaystyle \sf n - 2 = 7[/tex]

[tex]\displaystyle \sf n = 7 + 2 = 9[/tex]

Therefore, the sum of the measures of the interior angles of a heptagon is 900°, the sum of the measures of the interior angles of a 13-gon is 1980°, and the polygon with a sum of interior angles of 1260° is a nonagon (9-gon).

[tex]\huge{\mathfrak{\colorbox{black}{\textcolor{lime}{I\:hope\:this\:helps\:!\:\:}}}}[/tex]

♥️ [tex]\large{\underline{\textcolor{red}{\mathcal{SUMIT\:\:ROY\:\:(:\:\:}}}}[/tex]

Answer:

1. a. 900°       b. 1980°

2. Nonagon

Step-by-step explanation:

In order to find the interior angles of a polygon, use the formula,

Sum of interior angles = (n-2)*180°

For

a. Heptagon

no of side =7

The sum of the interior angles of a heptagon:

(7-2)*180 = 900°

b. 13-gon

no. of side =13

The sum of the interior angles of a 13-gon:
(13-2)*180 = 1980°

2.

The sum of the interior angles of a convex polygon is 1260°,

where n is the number of sides.

In this case, we have

1260 = (n-2)*180

1260/180=n-2

n-2=7

n=7+2

n=9

Therefore, the polygon has 9 sides and is classified as a nonagon.

The correct statement is C. The mean of East Hills HS is greater than the mean of Southview HS. So, option C is the correct answer.

To compare the centers of the distributions, we need to consider the measures of central tendency such as the median and the mean.

Looking at the given information about the class sizes at East Hills HS and Southview HS:

East Hills HS class sizes: 24, 26, 28, 30, 32, 34, 36, 38, 40, 42, 44

Southview HS class sizes: 0, 24, 26, 28, 30, 32, 34, 36, 38, 40, 42, 44

Let's compare the measures of central tendency:

Median: The median is the middle value of a dataset when arranged in ascending or descending order. In this case, both datasets have an odd number of values, so the median is the middle value.

For East Hills HS: Median = 34

For Southview HS: Median = 34

Therefore, the medians of both distributions are the same.

Mean: The mean is calculated by summing all the values in the dataset and dividing by the total number of values.

For East Hills HS: Mean = (24 + 26 + 28 + 30 + 32 + 34 + 36 + 38 + 40 + 42 + 44) / 11 ≈ 35.727

For Southview HS: Mean = (0 + 24 + 26 + 28 + 30 + 32 + 34 + 36 + 38 + 40 + 42 + 44) / 12 ≈ 33.667

Therefore, the mean of East Hills HS is greater than the mean of Southview HS.

Based on the comparisons, the correct statement is:

C. The mean of East Hills HS is greater than the mean of Southview HS.

So, option C is the correct answer.

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The question is asking for comparison of the centers and range of two data sets - the class sizes at two different high schools. Because no specific numeric data given for the mean and median of both school sizes, it's not possible to definitively choose an answer. Theoretically, if Southview has a higher concentration at larger class sizes, its median and mean might be larger.

This question refers to comparing the statistical centers (mean and median) and range of two data sets, which are the class sizes at East Hills High School and Southview High School. The centers and range of a data distribution tell us about the typical values, variety, and spread in the data set.

Without actual numbers (i.e., mean and median) for both the East Hills HS and Southview HS distributions, we can't definitively answer this question. However, let's assume that the representations provided suggest that Southview HS has a higher concentration of students in larger class sizes. In that case, the mean and median for Southview HS could be greater than those for East Hills HS, which would suggest option A and D. With regards to the range, if the minimum and maximum values of class sizes are the same in both schools, then the range, which is the difference between the maximum and minimum, would be the same. Therefore, option B wouldn't be accurate. However, as previously mentioned, this can only be suggestive as actual numbers are required for a definite answer.

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The daily cost of keeping a 50-watt bulb lit for 9 hours each day would be approximately $0.045 (or 4.5 cents).

To calculate the daily cost of keeping a 50-watt bulb lit for 9 hours each day, we need to consider the electricity cost per kilowatt-hour (kWh) and convert the wattage to kilowatts.

First, we convert the wattage of the bulb to kilowatts by dividing it by 1000:

50 watts = 50/1000 = 0.05 kilowatts.

Next, we calculate the total energy consumed by multiplying the power (in kilowatts) by the time (in hours):

Total energy consumed = 0.05 kW * 9 hours = 0.45 kilowatt-hours (kWh).

Now, we multiply the total energy consumed by the cost per kilowatt-hour to find the daily cost:

Daily cost = 0.45 kWh * $0.10/kWh = $0.045.

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The value of the algebric  expression [tex]2^{-3} \cdot 3^{-2}$ is $\frac{1}{72}[/tex].

To compute the expression [tex]2^{-3} \cdot 3^{-2}[/tex], we can simplify each term separately and then multiply the results.

First, let's simplify [tex]2^{-3}[/tex]. The exponent -3 indicates that we need to take the reciprocal of the base raised to the positive exponent 3. Therefore, [tex]2^{-3} = \frac{1}{2^3} = \frac{1}{8}[/tex].

Next, let's simplify 3^{-2}. Similar to before, the exponent -2 means we need to take the reciprocal of the base raised to the positive exponent 2. So, [tex]3^{-2} = \frac{1}{3^2} = \frac{1}{9}[/tex].

Now that we have simplified both terms, we can multiply them together: [tex]\frac{1}{8} \cdot \frac{1}{9}[/tex]. When multiplying fractions, we multiply the numerators together and the denominators together. So, [tex]\frac{1}{8} \cdot \frac{1}{9} = \frac{1 \cdot 1}{8 \cdot 9} = \frac{1}{72}[/tex].

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An equation representing a line perpendicular to y = -6/5 [tex]\times[/tex] x - 7 would be y = 5/6 [tex]\times[/tex] x + c, where c is any constant.

To determine a line that is perpendicular to the given line y = -6/5 [tex]\times[/tex] x - 7, we need to consider the slope of the given line.

The given line has a slope of -6/5.

For two lines to be perpendicular, their slopes must be negative reciprocals of each other.

The negative reciprocal of -6/5 can be found by flipping the fraction and changing the sign, which gives us 5/6.

Therefore, the equation of a line perpendicular to y = -6/5 [tex]\times[/tex] x - 7 will have a slope of 5/6.

To find the equation of this perpendicular line, we can use the point-slope form of a line, using a known point on the line.

Let's assume the line passes through the point (x1, y1).

The equation of the perpendicular line can be written as: y - y1 = (5/6) [tex]\times[/tex] (x - x1).

Since we do not have a specific point given, we cannot determine the exact equation of the perpendicular line without additional information.

In summary, the equation of a line perpendicular to y = -6/5 [tex]\times[/tex] x - 7 will have a slope of 5/6, but the specific equation depends on the point it passes through.

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After 8 visits: General Admission: Each person would pay $200. Annual Public Session Pass: Each person would pay $299.

After 10 visits: General Admission: Each person would pay $250. Annual Public Session Pass: Each person would still pay $299.

To determine when it is better to have a session pass versus just paying general admission, we need to compare the costs for each option.

General Admission with skate rental: $25

Annual Public Session Pass with skate rental: $299

After 8 visits:

For General Admission, the cost per visit would be $25 per visit.

Total cost for 8 visits: $25 x 8 = $200

For the Annual Public Session Pass, the cost is a one-time payment of $299, regardless of the number of visits. Therefore, after 8 visits, the cost remains the same at $299.

Therefore, after 8 visits, it would be more cost-effective to have the Annual Public Session Pass as the cost per person would be $299.

After 10 visits:

For General Admission, the cost per visit remains at $25 per visit.

Total cost for 10 visits: $25 x 10 = $250

For the Annual Public Session Pass, the cost remains the same at $299, regardless of the number of visits.

Therefore, after 10 visits, it would still be more cost-effective to have the Annual Public Session Pass as the cost per person would still be $299.

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The following question may be like this:

When is it better to have a session pass versus just paying general admission? After 8 visits: How much would each person pay? Show your work for calculations. Session Pass______? General Admission______?After 10 visits: How much would each person pay? Show your work for calculations.Session pass _____? General Admission_____?

GENERAL ADMISSION WITH SKATE RENTAL  $25

ANNUAL PUBLIC SESSION PASS WITH SKATE RENTAL $299

LOCKER RENTAL-ONE TIME USE  $5

HELMET RENTAL  $5

SKATE HELPER-PER HOUR $15

The area of the garden is 135 square yards.

Let's imagine you have a rectangular garden measuring 15 yards in length and 9 yards in width.

You want to find the area of this garden, which represents the amount of space inside the garden.

To find the area of a rectangle, you multiply the length by the width.

In this case, the length is 15 yards and the width is 9 yards.

Area = Length × Width

Area = 15 yards × 9 yards

Area = 135 square yards

This means that the garden can hold 135 square yards of grass, flowers, or any other objects you place inside it.

It's worth noting that the unit of measurement for area is always squared, such as square yards in this example.

This is because area is a two-dimensional measurement, representing the space within a flat surface.

By using the formula to calculate the area of a rectangle, you can easily determine the amount of space enclosed by any rectangular area when given the length and width.

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Step-by-step explanation:

To solve this problem, we need to use the product rule of differentiation and some trigonometric identities. Let's start by finding the derivative of y with respect to x:

y = (sin 2x) √(3+2x)

Using the product rule, we get:

dy/dx = (sin 2x) d/dx(√(3+2x)) + (√(3+2x)) d/dx(sin 2x)

To find these derivatives, we need to use the chain rule and the derivative of sin 2x:

d/dx(√(3+2x)) = (1/2√(3+2x)) d/dx(3+2x) = (1/√(3+2x))

d/dx(sin 2x) = 2cos 2x

Substituting these values, we get:

dy/dx = (sin 2x) / √(3+2x) + 2cos 2x (√(3+2x))

Now, we need to simplify this expression to the desired form. To do that, we can use the trigonometric identity:

sin 2x = 2sin x cos x

Substituting this value, we get:

dy/dx = 2sin x cos x / √(3+2x) + 2cos 2x (√(3+2x))

Now, we can use the trigonometric identity:

cos 2x = 1 - 2sin^2 x

Substituting this value, we get:

dy/dx = 2sin x cos x / √(3+2x) + 2(1 - 2sin^2 x)(√(3+2x))

Simplifying further, we get:

dy/dx = (2cos x - 4cos x sin^2 x) / √(3+2x) + 2√(3+2x) - 4sin^2 x√(3+2x)

Now, we can see that this expression matches the desired form:

dy/dx = sin 2x + (4 + Bx)cos 2x / √(3+2x)

where A = -4 and B = -2. Therefore, we have shown that:

dy/dr = sin 2x + (4 - 2x)cos 2x / √(3+2x)

where A = -4 and B = -2.

First, we need to calculate the area of the room Jenny is tiling, which appears to be in the shape of a rectangle. The area is calculated by multiplying the length and width of the rectangle. If the measurements provided (2.6m and 11m) are for the length and width, then the area of the room would be:

Area = length x width

Area = 2.6m x 11m

Area = 28.6 m²

Next, we need to calculate how many packs of tiles Jenny needs to buy. Given that each pack covers an area of 3m², we divide the total area by the area each pack covers:

Number of packs needed = total area / area covered by one pack

Number of packs needed = 28.6m² / 3m² ≈ 9.53 packs

Since Jenny can't buy a fraction of a pack, she needs to purchase 10 packs of tiles.

The tiles are marked at £18.60, so before the discount, the total cost of the tiles would be:

Total cost = number of packs x price per pack

Total cost = 10 packs x £18.60 = £186

Jenny has a discount card which gives her a 25% discount off the marked price. The discount amount can be calculated as:

Discount = total cost x discount rate

Discount = £186 x 25% = £46.5

So, the cost of the tiles after the discount is:

Discounted price = total cost - discount

Discounted price = £186 - £46.5 = £139.5

Jenny has £100 to spend on the tiles. The extra amount Jenny needs is the difference between the cost of the tiles after the discount and the amount she has:

Extra amount needed = discounted price - amount Jenny has

Extra amount needed = £139.5 - £100 = £39.5

The question asks for the answer in pence, and there are 100 pence in a pound, so:

Extra amount needed in pence = extra amount needed in pounds x 100

Extra amount needed in pence = £39.5 x 100 = 3950 pence

Therefore, Jenny needs an extra 3950 pence to buy the tiles.

Answer:

16cm

Step-by-step explanation:

perimeter for C is 44cm

perimeter for A and B 60cm

60cm-44cm=16cm

Hope this helps

The actual length corresponding to the 3-inch length on the model is 10.5 feet.

Given that the scale of the model is 1 inch to 3.5 feet, we can use this information to find the actual length corresponding to a given length on the model.

Let's denote:

Model's length = 3 inches

Actual length = ?

According to the given scale, 1 inch on the model represents 3.5 feet in reality. We can set up a proportion to find the actual length:

(1 inch) / (3.5 feet) = (3 inches) / (x feet)

Cross-multiplying, we get:

1 inch * x feet = 3 inches * 3.5 feet

Simplifying the equation:

x feet = 10.5 feet

Therefore, the actual length corresponding to the 3-inch length on the model is 10.5 feet.

In summary, the actual length is 10.5 feet.

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Using the property of vertical angles, the value of x is 24 degrees

Vertical angles are a pair of non-adjacent angles formed by the intersection of two lines. They are opposite each other and share a common vertex, but they are not adjacent angles.

When two lines intersect, they form four angles at the point of intersection. The vertical angles are the angles that are directly across from each other and are formed by opposite pairs of intersecting lines. In other words, if you draw a line segment connecting the vertices of the vertical angles, it will divide the intersection into two pairs of congruent angles.

The property of vertical angles is that they have equal measures. This means that if one vertical angle measures a certain number of degrees, the other vertical angle will also measure the same number of degrees.

In this problem, to find the value of x, we have to use the property of vertical angles which states that vertical angles are equal to one another.

This implies that ∠ABC = DBE

3x - 14 = 2x + 10

Collect like terms

3x - 2x = 10 + 14

x = 24°

The answer is option D.

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Similarity statement and justification for two similar figures with given measurements. The given figures are AB = 40, AC = 50, and BC = 60. For the second figure, YX = 37.5, YZ = 30, and ZX = 45.

To write a similarity statement, we compare the ratios of corresponding sides of the two figures. So, we can compare AB/BC to YX/ZX and AC/BC to YZ/ZX.AB/BC = 40/60 = 2/3YX/ZX = 37.5/45 = 5/6AC/BC = 50/60 = 5/6YZ/ZX = 30/45 = 2/3Since the ratios of the corresponding sides of both figures are the same, we can say that the two figures are similar.

A similarity statement for these figures can be written as:ΔABC ~ ΔXYZThis statement indicates that the two triangles ABC and XYZ are similar. The symbol ~ is used to denote similarity.

The justification for this similarity statement is based on the fact that the ratios of the corresponding sides of the two figures are equal.

Therefore, by the definition of similarity, we can conclude that the two triangles are similar.

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The total liabilities and stockholders' equity for Deacon Company as of March 31st is $275,400.

To calculate the total liabilities and stockholders' equity, we need to add the amounts of accounts payable, common stock, and retained earnings. Accounts Payable: The balance sheet provides the information that the accounts payable is $71,100.

Common Stock: The balance sheet states that the common stock is $70,000.

Retained Earnings: The balance sheet shows that the retained earnings are $134,300.

Calculate the total liabilities and stockholders' equity: Add the amounts of accounts payable, common stock, and retained earnings.

Total liabilities and stockholders' equity = Accounts payable + Common stock + Retained earnings

= $71,100 + $70,000 + $134,300

= $275,400

Therefore, the total liabilities and stockholders' equity for Deacon Company as of March 31st is $275,400.

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Step-by-step explanation:

Therefore, the first five multiples of 17 are 17 , 34 , 51 , 68 and 85 .