Answer:
a. 3
Explanation:
Answer:
A. 3
Explanation:
AP3X
ConsolidatedEdison'sIndianPointNo.2reactorisdesignedtooperateatapowerof 2,758 MW. Assuming that all fissions occur in 235U, calculate in grams per day the rate at which 235U is (a) fissioned, (b) consumed.
Answer:
a) the rate at which 235U is fissioned is 2895.9 grams per day
b) the rate at which 235U is consumed is 3385.3071 gram/day
Explanation:
Given the data in the question;
a)
designed operation thermal power = 2758 MW.
we know that, the burn up rate fission rate of 235U is 1.05 grams per MW-day.
so, the rate at which 235U is fissioned will be;
⇒ 2758 × 1.05 = 2895.9 grams per day
Therefore, the rate at which 235U is fissioned is 2895.9 grams per day
b)
Consumption rate is given as;
Cr = 1.05 × ( 1 + ∝ )P gram/day
where ∝ is 0.169 for U-235
so,
Cr = 1.05 × ( 1 + 0.169 )2758 gram/day
Cr = 1.05 × 1.169 × 2758 gram/day
Cr = 3385.3071 gram/day
Therefore, the rate at which 235U is consumed is 3385.3071 gram/day
An SUV is accelerated from rest to a speed v in a time interval t. Neglecting air resistance effects and assuming the engine is operating at its maximum power rating when accelerating, determine the time interval for the SUV to accelerate from rest to a speed 2v.
a. 2t
b. 4t
c. 2.5t
d. 3t
Answer:
A. [tex]2\cdot t[/tex]
Explanation:
The SUV accelerates uniformly. In this case, speed ([tex]v[/tex]) is directly proportional to time ([tex]t[/tex]). That is:
[tex]v \propto t[/tex] (1)
[tex]v = k\cdot t[/tex]
Where [tex]k[/tex] is the proportionality constant.
Then, we eliminate this constant by creating the following relationship:
[tex]\frac{v_{1}}{t_{1}} = \frac{v_{2}}{t_{2}}[/tex] (2)
If we know that [tex]v_{1} = v[/tex], [tex]t_{1} = t[/tex] and [tex]v_{2} = 2\cdot v[/tex], then the time interval for the SUV to accelerate from rest to a speed [tex]2\cdot v[/tex] is:
[tex]\frac{v}{t} = \frac{2\cdot v}{t_{2} }[/tex]
[tex]t_{2} = 2\cdot t[/tex]
Hence, correct answer is A.
Cara is building a model of the solar system, which includes the Sun. She plans to include a written description to provide details about each piece in her model. In order for her model to be realistic, which of the following should she include in her representation of the Sun?
Answer:
she should write about how big is it and what the sun looks and how far away is it from earth.
A Car is moving at a speed of 20 m/s. How Much Distance it will cover in 1 min? Express the answer in km.
Answer:
d=20m/sx60s=1200m=1200/1000Km=1.2km
Explanation:
how much heat energy is needed to raise the temperature of 2.0 kg of concrete from 10c to 30c
A man is standing at a distance of 2m from a large plane mirror.
he walks 1m farther away from the mirror.how far is his image now from him
Answer: 3m
Explanation: If he is already 2m away from the mirror then if he walks away 1m then it would equal out to 3. You could also add 1 to 2 so you could get the same results.
A person is holding a bucket by applying a force of 10N. He moves a horizontal distance of 5m and then climbs up a vertical distance of 10m. Find the total work done by him?
Answer:
dgfggddhdbxbxjxddhsnsxnc
Where the air conditioner disconnecting means is not within sight from the equipment, the provision for locking or adding a lock to the disconnecting means shall be on the switch or circuit breaker and remain in place _____ the lock installed.
Answer:
With or without.
Explanation:
According to the National Electrical Code (NEC), here the air conditioner disconnecting means is not within sight from the equipment, the provision for locking or adding a lock to the disconnecting means shall be on the switch or circuit breaker and remain in place with or without the lock installed. Thus, this is in accordance with section 110.25 of the National Electrical Code (NEC).
HELP ASAP PLEASE
Which 2 factors must be present for chemical vapor deposition to be successful:
A.) The size of the diamond is larger than the most.
B.) The conditions during cooling are controlled.
C.) The heat in a vacuum forms a gas of single atoms.
D.) The heat in a vacuum is decreased to freezing.
E.) The pressure of a reaction vessel is negative.
The distance to the other planets in the Solar System from the Earth depends on where they are in their orbit. The closest that Mars gets to the Earth is 0.5 AU. At this time it is observed to have an angular diameter of 18 arcseconds. The furthest it gets from Earth is 2.5 AU. What would its angular diameter be for this observation
Answer:
3.6 arcsec
Explanation:
angular diameter = diameter / distance
diameter is constant
so angular diameter ∝ 1 / distance
angular diameter = k / distance
For first case ,
18 = k / .5
for second case let angular diameter be D .
D = k / 2.5
dividing ,
D / 18 = .5 / 2.5 = 1 / 5
D = 18 / 5 = 3.6 arcsec
3.6 arcsec is the answer .
A ball 12 m in 4 seconds and then 2.5 seconds later it rolls 8 m in 2 seconds what is its acceleration
Answer:
If it accelerates at 20 m/s2 for a period of 22 seconds, what is its final velocity? ... How fast is the ball falling after 5 seconds? v = v0 + gt v = 0 + 10(5) v = 50 m/s. 4. ... + ½ 2.5(15)2 x = 281 m. 5. What is the total displacement of the car in question 2? ... 8. A base jumper falls until he reaches a speed of 200 m/s
Explanation:
A projectile is fired directly upwards at 49.4 m/s. A second projectile is dropped from rest at some higher elevation at the instant the first projectile is fired and passes the first projectile 3.00 s later. From the frame of reference of the first projectile, what is the velocity of the second projectile as it passes by
Answer:
Explanation:
velocity of first projectile after 3 s
v = u - gt
v = 49.4 - 9.8 x 3
= 20 m /s
Velocity of second projectile after 3 s after being dropped from rest
v = u + gt
= 0 + 9.8 x 3
= 29.4 m /s
They will be moving in opposite direction at the time of meeting , so their relative velocity
= 20 + 29.4 = 49.4 m /s
From the frame of reference of the first projectile, the velocity of the second projectile will be 49.4 m /s .
ecosystem ecosystem science science
Answer:
c
Explanation:
Answer: C
Explanation:
A skydiver has a mass of 140 kg. At what speed will she have a momentum
of 10,000 kg•m/s?
Answer:
I think its 71.4 if u get it wrong u can slap me
In trial 1 of an experiment, a cart moves with a speed of vo on a frictionless, horizontal track and collides with another cart that is initially at rest. In trial 2, the setup is identical except the carts stick together during the collision. How does the speed of the two-cart system's center of mass change, if at all, during the collision in each trial
Answer:
1) elastic shock, the velocity of the center of mass does not change
2) inelastic shock, he velocity of the mass center change
Explanation:
The position of the center of mass of your system is defined by
[tex]x_{cm}[/tex] = [tex]\frac{1}{M} \sum x_i m_i[/tex]
in this case we have two bodies
x_{cm} = [tex]\frac{1}{M}[/tex] (x₁m₁ + x₂ m₂)
the velocity of the center of mass is
x_{cm} = dx_{cm} / dt = [tex]\frac{1}{M} ( m_1 \frac{dx_1}{dt} \ + m_2 \frac{dx_2}{dt} )[/tex]
x_{cm} = [tex]\frac{1}{M} ( m_1 v_1 + m_2 v_2 )[/tex]
where M is the total mass of the system.
Therefore to answer this question we have to find the velocity of the body after the collision.
Let's use momentum conservation, where the system is formed by the two bodies, so that the forces have been internal during the collision.
Let's solve each case separately.
2) inelastic shock
initial instant. Before the crash
p₀ = m₁ v₀ + 0
final instant. After the collision with the cars together
p_f = (m₁ + m₂) v
p₀ = p_f
m₁ v₀ = (m₁ + m₂) v
v = [tex]\frac{m_1}{m_1+m_2}[/tex] v₀
let's find the velocity of the center of mass
M = m₁ + m₂
initial.
[tex]v_{cm o}[/tex] = [tex]\frac{1}{m_1 +m_2}[/tex] (m₁ vo)
final
[tex]v_{cm f}[/tex] = [tex]\frac{1}{M} ( \frac{m_1}{m_1 + m_2} v_o )[/tex] ( v) = v
v_{cm f} = [tex]\frac{m_1}{M^2} v_o[/tex]
Let's find the ratio of the velocities of the center of mass
vcmf / vcmo = [tex]\frac{1}{M} = \frac{1}{m_1 +m_2}[/tex]
therefore the velocity of the mass center change
1) elastic shock
initial instant.
p₀ = m₁ v₀
final moment
p_f = m₁ v_{1f} + m₂ v_{2f}
p₀ = p_f
m₁ v₀ = m₁ v_{1f} + m₂ v_{2f}
m₁ (v₀ - v_{2f}) = m₂ v_{2f}
in this case the kinetic energy is conserved
K₀ = K_f
½ m₁ v₀² = ½ m₁ v_{1f}² + ½ m₂ v_{2f}²
m₁ (v₀² - v_{1f}²) = m₂ v_{2f}²
m₁ (v₀ + v_{1f}) (v₀ - v_{1f}) = m₂ v_{2f}
we write our system of equations
m₁ (v₀ - v_{1f}) = m₂ v_{2f} (1)
m₁ (v₀ - v_{1f}) (v₀ + v_{1f}) = m₂ v_{2f}²
we solve the system
v₀ + v_{1f} = v_{2f}
we substitute and look for the final speeds
v_{1f} = [tex]\frac{m_1 -m_2}{m1 +m2 } v_o[/tex]
v_{2f} = [tex]\frac{2 m_1}{m-1+m_2} vo[/tex]
now let's find the velocity of the center of mass
initial
[tex]v_{cm o}[/tex] = [tex]\frac{1}{M}[/tex] m₁ v₀
final
[tex]v_{cm f}[/tex] = [tex]\frac{1}{M}[/tex] (m₁ v_{1f} + m₂ v_{2f} )
v_{cm f} = [tex]\frac{1}{M}[/tex] [ [tex]m_1 \frac{m_2}{M}[/tex] + [tex]m_2 \frac{2 m_1}{M}[/tex] ] v₀
v_{cm f} = [tex]\frac{1}{M^2}[/tex] ( m₁² - m₁m₂ +2 m₁m₂) v₂
v_{cm f} = [tex]\frac{1}{M^2}[/tex] (m₁² + m₁ m₂) v₀
let's look for the relationship
v_{cm f} / v_{cm o} = [tex]\frac{1}{M}[/tex] M
v_{cm f} / v_{cm o} = 1
therefore the velocity of the center of mass does not change
we see in either case the velocity of the center of mass does not change.
1. A SUV along with 5 passengers has a mass of 3500 kg. It has a driving force of 2500 N directed along west on a perfectly horizontal road. The surface of the road exerts a resistance force of 500 N due east. At the same time a high wind is blowing a force of 500 N due east in the opposite direction of the car's drive force. Does the car has any acceleration
Answer:
The net acceleration of the SUV is 0.429 meters per square second due west.
Explanation:
Statement is incomplete. Description is presented below:
A SUV along with 5 passengers has a mass of 3500 kg. It has a driving force of 2500 N directed along west on a perfectly horizontal road. The surface of the road exerts a resistance force of 500 N due east. At the same time a high wind is blowing a force of 500 N due east in the opposite direction of the car's drive force. Does the car has any acceleration? If yes, then what are the magnitude and direction of the car's acceleration?
According to Newton's Laws of Motion, the SUV will accelerate if and only if net acceleration is different of zero. Let suppose as positive the direction of driving force ([tex]F[/tex]), measured in newtons:
[tex]\Sigma F = F - R -f = F_{net}[/tex] (1)
Where:
[tex]R[/tex] - Resistance force, measured in newtons.
[tex]f[/tex] - Wind force, measured in newtons.
[tex]F_{net}[/tex] - SUV net force, measured in newtons.
If we know that [tex]F = 2500\,N[/tex], [tex]R = 500\,N[/tex] and [tex]f = 500\,N[/tex], then net force experimented by the SUV is:
[tex]F_{net} = 2500\,N-500\,N-500\,N[/tex]
[tex]F_{net} = 1500\,N[/tex]
The car has acceleration.
By definition of force for systems with constant mass, we calculate the acceleration of the vehicle below:
[tex]a_{net} = \frac{F_{net}}{m}[/tex] (2)
Where [tex]m[/tex] is the mass of the SUV, measured in kilograms.
If we know that [tex]F_{net} = 1500\,N[/tex] and [tex]m = 3500\,kg[/tex], then the net acceleration of the car is:
[tex]a_{net} = \frac{1500\,N}{3500\,kg}[/tex]
[tex]a_{net} = 0.429\,\frac{m}{s^{2}}[/tex]
The net acceleration of the SUV is 0.429 meters per square second due west.
6. A 25 g sample of iron (initially at 800.00°C) is dropped into 200 g of water (initially at
30.00°C). The final temperature of the system is 40.22°C. Find the specific heat of iron.
90
Answer:
[tex]c=0.45\ J/g^{\circ} C[/tex]
Explanation:
Given that,
A 25 g sample of iron (initially at 800.00°C) is dropped into 200 g of water (initially at 30.00°C). The final temperature of the system is 40.22°C.
We need to find the specific heat of iron.
It can be calculated as:
Cooler water gains = hot metal loses
mc∆T = - mc∆T
Put all the values,
[tex]200g(4.184\ J/g^{\circ} C)(T_f-T_i) = -25g(c)(T_f-T_i) \\\\200g(4.184 )( 40.22-30.00) = -25\times (c)\times (40.22-800.00)\\\\8552.096 = 18994.5c\\\\c=\dfrac{8552.096 }{18994.5}\\\\c=0.45\ J/g^{\circ} C[/tex]
So, the specific heat of iron is [tex]0.45\ J/g^{\circ} C[/tex]
an always be used to calculate the electric field. relates the electric field at points on a closed surface to the net charge enclosed by that surface. relates the surface charge density to the electric field. relates the electric field throughout space to the charges distributed through that space. only applies to point charges.
Complete Question:
Gauss's law:
Group of answer choices
A. can always be used to calculate the electric field.
B. relates the electric field throughout space to the charges distributed through that space.
C. only applies to point charges.
D. relates the electric field at points on a closed surface to the net charge enclosed by that surface.
E. relates the surface charge density to the electric field.
Answer:
D. relates the electric field at points on a closed surface to the net charge enclosed by that surface.
Explanation:
Gauss's law states that the total (net) flux of an electric field at points on a closed surface is directly proportional to the electric charge enclosed by that surface.
This ultimately implies that, Gauss's law relates the electric field at points on a closed surface to the net charge enclosed by that surface.
This electromagnetism law was formulated in 1835 by famous scientists known as Carl Friedrich Gauss.
Mathematically, Gauss's law is given by this formula;
ϕ = (Q/ϵ0)
Where;
ϕ is the electric flux.
Q represents the total charge in an enclosed surface.
ε0 is the electric constant.
A baseball with a mass of 151 g is thrown horizontally with a speed of 39.5 m/s (88 mi/h) at a bat. The ball is in contact with the bat for 1.10 ms and then travels straight back at a speed of 45.1 m/s (101 mi/h). Determine the average force exerted on the ball by the bat.
Answer:
the average force exerted on the ball by the bat is 11,613.27 N
Explanation:
Given;
mass of the baseball, m = 151 g = 0.151 kg
initial velocity of the baseball, u = 39.5 m/s
final velocity of the baseball, v = 45.1 m/s
time of action, t = 1.10 ms = 1.10 x 10⁻³ s
The average force exerted on the ball by the bat is calculate as;
[tex]F = ma = \frac{m(v-u)}{t} \\\\F = \frac{0.151(45.1-(-39.5))}{1.10\times 10^{-3}} \\\\F = \frac{0.151(45.1\ +\ 39.5)}{1.10\times 10^{-3}} \\\\F = 11,613.27 \ N[/tex]
Therefore, the average force exerted on the ball by the bat is 11,613.27 N
Force excerted is defined as the product of mass and rate of change of velocity .The average force exerted on the ball by the bat will be 11,613.27 N.
What is force?Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body. Force is defined as the product of mass and acceleration. Its unit is Newton.
m is the mass of the baseball = 151 g = 0.151 kg
u is the initial velocity of the baseball =39.5 m/s
v is the final velocity of the baseball = 45.1 m/s
t is time of contact = 1.10 ms = 1.10 x 10⁻³ s
The average force mathematically given as
[tex]\rm F=\frac{m(v-u)}{t} \\\\\rm F=\frac{0.151(45.1-39.85)}{1.10\times10^-3} \\\\\rm F=11,613.27 N[/tex]
Hence the average force exerted on the ball by the bat will be 11,613.27 N.
To learn more about the force refer to the link;
https://brainly.com/question/26115859
Electric power is to be generated by installing a hydraulic turbine-generator at a site 120 m below the free surface of a large water reservoir that can supply water at a rate of 2300 kg/s steadily. Determine the power generation potential.
Answer:
the power generation potential is 2.705 x 10⁶ J/s.
Explanation:
Given;
height below the free surface of a large water reservoir, h = 120 m
mass flow rate of the water, m' = 2300 kg/s
The power generation potential is calculated as;
[tex]Power = \frac{Energy}{time} = \frac{F\times h}{t} = \frac{(mg) \times h}{t} = \frac{m}{t}\times gh = m' \times gh\\\\Power = m' \times gh\\\\Power = 2300 \ kg/s \ \times \ 9.8 \ m/s^2 \ \times \ 120 \ m\\\\Power = 2.705 \times 10^6 \ J/s[/tex]
Therefore, the power generation potential is 2.705 x 10⁶ J/s.
what is the difference between heat and temperature
A carmaker has designed a car that can reach a maximum acceleration of 12 meters/second2. The car’s mass is 1,515 kilograms. Assuming the same engine is used, what should the car’s mass be if the carmaker wants to reach an acceleration of 15 meters/second2? Use F = ma.
A.
1,212 kg
B.
1,335 kg
C.
1,466 kg
D.
1,515 kg
E.
1,894 kg
Answer:
A: 1,212 kg
Explanation:
You are given three pieces of wire that have different shapes (dimensions). You connect each piece of wire separately to a battery. The first piece has a length L and cross-sectional area A. The second is twice as long as the first, but has the same thickness. The third is the same length as the first, but has twice the cross-sectional area. Rank the wires in order of which carries the most current (has the lowest resistance) when connected to batteries with the same voltage difference.
Rank the wires from most current (least resistance) to least current (most resistance).
a. Wire of Lenght L and area A
b. Wire of Lenght 2L and area A
c. Wire of Lenght L and area 2A
Answer:
The answer is below
Explanation:
The resistance of a wire is directly proportional to the length of the wire and inversely proportional to its area. The resistance (R) is given by:
[tex]R=\frac{\rho L}{A}\\\\where\ L=length \ of\ wire,A=cross\ sectional\ area, \rho=resistivity\ of\ wire.[/tex]
Let us assume that all the wires have the same resistivity.
a) Wire of Length L and area A
[tex]R_1=\frac{\rho L}{A}[/tex]
b) Wire of Length 2L and area A
[tex]R_2=\frac{\rho *2L}{A}=2R_1[/tex]
C) Wire of Length L and area 2A
[tex]R_3=\frac{\rho L}{2A}=\frac{1}{2}R_1[/tex]
Therefore the wire of least resistance is R3 and R2 has the highest resistivity.
R₃ < R₁ < R₂
Therefore, the ranking of the wires from most current (least resistance) to least current (most resistance) is:
R₃ < R₁ < R₂
An 80-kg firefighter slides down a fire pole. After 1.3 seconds of sliding, the firefighter is sliding at a velocity of 6.5 m/s, straight down the pole. Once this velocity is reached, the firefighter grips the pole so that the force of friction exerted by the firefighter's hands on the pole is equal to the force of gravity. At this point what is the downward acceleration of the firefighter
Answer:
a= 0
Explanation:
In the vertical direction, if the friction force (directed upward) is equal to the force of gravity (downward) this means that no net force is acting on the firefighter.According to Newton's 2nd Law, if no net force is present, the acceleration in this direction is just zero, as follows:[tex]F_{net} = m*a = 0 (1)[/tex]
⇒ a = 0
Temperature changes can affect substances in different ways. Which of these actions will form a new substance with different properties?
melting ice into water
freezing juice into ice pops
baking cake batter to make a cake
heating chocolate chips to form a syrup
Answer:
a
Explanation:
3. a. (i) You are traveling on a plane trip from Washington, D.C. to Cleveland, Ohio andthe plane uses 1,260 MJ/passenger trip. If you made the trip by car it would take 18 gallons/passenger trip.There are 142 MJ in a gallon of kerosene, a type of jet fuel. How many gallons of kerosene does it take to make the trip by plane
Answer:
#_galon = 8,873 gallons
Explanation:
For this exercise let's use a direct rule of proportions (rule of three). If 1 gallon is 142 MJ, how many gallons is 1260 MJ
#_galon = 1260 MJ (1 gallon / 142 MJ)
#_galon = 8,873 gallons
therefore air travel uses less fuel than car travel
why would the bulb not light?
Answer:
beacuse it isnt on
Explanation:
Explanation:
The wires isn't in a circulation, the negative side must be connected to the wire
A house that was heated by electric resistance heaters consumed 1200 kWh of electric energy in a winter month. If this house were heated instead by a heat pump that has an average COP of 2.4, determine how much money the homeowner would have saved that month. Assume a price of $0.12/kWh for electricity.
Answer:
$84
Explanation:
The coefficient of performance (COP) show the relationship between the power (kW) output of the heat pump and the power (kW) input to the compressor.
The heater consumed by the heater is 1200 kWh.
For a heat pump with a COP of 2.4, the electric input needed to produce an output of 1200 kWh is:
Electric input to heat pump = 1200 / 2.4 = 500 kWh
That means that supplying a heat pump with 500 kWh produces an output of 1200 kWh
The amount of power saved = power consumed by heater - power consumed by heat pump = 1200 - 500 = 700 kWh
Money saved = $0.12/kWh * 700 kWh = $84
The amount of money the homeowner would have saved during the month is $84.
Given the following data:
Energy output = 1200 kWhCoefficient of performance (COP) = 2.4Cost of electricity = $0.12To determine the amount of money the homeowner would have saved during the month:
In Science, the coefficient of performance (COP) is a mathematical expression that is typically used to show the relationship between the power output (kilowatts) of a heater and the power input (kilowatts) to the compressor.
Mathematically, the coefficient of performance (COP) is given by the formula:
[tex]COP = \frac{E_o}{E_i}[/tex]
Where:
[tex]E_i[/tex] is the energy input.[tex]E_o[/tex] is the energy output.First of all, we would determine the energy input of the heaters.
[tex]E_i = \frac{E_o}{COP} \\\\E_i=\frac{1200}{2.4}[/tex]
Energy input = 500 kWh
For power saved:
[tex]Power = 1200 -500[/tex]
Power = 700 kWh
For the amount of money saved while using these heaters:
[tex]Money = 0.12 \times 700[/tex]
Amount of money = $84
Read more: https://brainly.com/question/22599382
A workman carries some lumber up a staircase. The workman moves 9.6m vertically and 22m horizontally. If the lumber weighs 45N. How much work was done by the workman?
Answer:
a.432
B. 562
C.402
D. 316
A
Explanation:
Work is defined as the product of applied force and the distance through which the body is displaced on which the force is applied. Work was done by the workman will be 432 Nm.
What is work?
Work is defined as the product of applied force and the distance through which the body is displaced on which the force is applied.
Work may be zero, positive and negative.it depend on the diection of body displaced . if the body is displaced in thw same direction of force it will be positive .
while if the displacement is in the opposite direction of force applied the work will be negative work . if their is no displacement of the body the work done will b e zero.
As given in question wall is stationary diplacement will be zero so in that work will also z
The given data in the problem is;
x is the displacement in the horizontal direection=22m
y is the displacement in the verical direection=9.6m
W is the weight of lumber = 45 N
[tex]\rm W=F\times y[/tex]
[tex]\rm W=F\times y \\\\\rm W=45\times 9.6\\\\ \rm W=432\;Nm[/tex]
Hence Work was done by the workman will be 432 Nm.
To learn more about the work refer to the link ;
https://brainly.com/question/3902440
The earth has a vertical electric field at the surface, pointing down, that averages 100 N/C. This field is maintained by various atmospheric processes, including lightning. If research came out on Planet x in a distant solar system that had a electric field with strength 222 N/C and 0.6 the radius of the earth, what would be the excess charge on planet x
Answer:
q = 3.6 10⁵ C
Explanation:
To solve this exercise, let's use one of the consequences of Gauss's law, that all the charge on a body can be considered at its center, therefore we calculate the electric field on the surface of a sphere with the radius of the Earth
r = 6 , 37 106 m
E = k q / r²
q = E r² / k
q = [tex]\frac{100 \ (6.37 \ 10^6)^2}{9 \ 10^9}[/tex]
q = 4.5 10⁵ C
Now let's calculate the charge on the planet with E = 222 N / c and radius
r = 0.6 r_ Earth
r = 0.6 6.37 10⁶ = 3.822 10⁶ m
E = k q / r²
q = E r² / k
q = [tex]\frac{222 (3.822 \ 10^6)^2}{ 9 \ 10^9}[/tex]
q = 3.6 10⁵ C