Qn in attachment. ..​

The magnitude of the force of the car against the hill is approximately 13690 pounds.

a. To find the magnitude of the force required to keep the car from sliding down the hill, we need to calculate the force component perpendicular to the hill (the normal force) and the force component parallel to the hill (the force of friction). The force of friction must be equal and opposite to the component of the weight of the car parallel to the hill to keep the car from sliding.

First, we need to calculate the weight of the car in Newtons:

3100 pounds = 1406.13 kg

Weight = mg = 1406.13 kg * 9.81 m/s^2 = 13791.68 N

The force component perpendicular to the hill is equal to the weight of the car multiplied by the cosine of the angle of inclination:

F_perpendicular = Weight * cos(5.6°) = 13791.68 N * cos(5.6°) = 13689.55 N

The force component parallel to the hill is equal to the weight of the car multiplied by the sine of the angle of inclination:

F_parallel = Weight * sin(5.6°) = 13791.68 N * sin(5.6°) = 1275.02 N

The force of friction is equal to the force parallel to the hill, so:

F_friction = F_parallel = 1275.02 N

Therefore, the magnitude of the force required to keep the car from sliding down the hill is equal to the force component perpendicular to the hill plus the force of friction:

F_required = F_perpendicular + F_friction = 13689.55 N + 1275.02 N = 14964.57 N

Rounded to the nearest whole number, the magnitude of the force required to keep the car from sliding down the hill is approximately 14965 pounds.

b. To find the magnitude of the force of the car against the hill, we just need to calculate the force component perpendicular to the hill (the normal force):

F_normal = F_perpendicular = 13689.55 N

Rounded to the nearest whole number, the magnitude of the force of the car against the hill is approximately 13690 pounds.

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To determine the range and sample standard deviation of tornadoes that touched down during each month of one year, we need to use the data in the table.

However, the table is not provided in the question.

Please provide the table with the number of tornadoes that touched down during each month of one year so I can help you with your question.
To determine the range and sample standard deviation of the number of tornadoes that touched down each month, you'll first need to provide the data in a table format.

Once you provide the data, I can help you calculate the range and sample standard deviation.

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Correct question:

Each​ year, tornadoes that touch down are recorded. The following table gives the number of tornadoes that touched down during each month of one year. Determine the range and sample standard deviation.

3 2 41 115 197 95

70 85 68 64 110 91

Range?

Sample Standard Deviation?

The area of the squares are;

1.  9x²ft². Option D

2.  6x² - 7x - 3 in². Option C

The formula for calculating the area of a square is expressed as;

A = a²

Such that the parameters of the formula are;

From the information given, we have that;

Area = (3x)²

Find the square of the expression, we have that;

Area = 9x²ft²

2. Substitute the values, we have that;

Area = (2x -3)(3x + 1)

expand the bracket, we have;

Area = 6x² + 2x - 9x - 3

collect the like terms

Area = 6x² - 7x - 3

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To multiply the polynomials (1-2t)(5t+t^2), we can use the distributive property and multiply each term in the first polynomial by each term in the second polynomial:

(1-2t)(5t+t^2) = 1(5t+t^2) - 2t(5t+t^2)

Multiplying the first term by each term in the second polynomial, we get:

5t + t^2

Multiplying the second term by each term in the second polynomial, we get:

-10t^2 - 2t^3

Combining like terms, we get:

-2t^3 - 10t^2 + 5t

Therefore, the answer is D. -2t^3 - 9t^2 + 5t.

6. The probability that all 5 couples will have a baby of the preferred gender is 0.2373.

7. The probability that at least 4 of the 5 couples will have a baby of the preferred gender is 1 - 0.3672 = 0.6328.

Probability is a way to gauge how likely something is to happen. Many things are difficult to predict with absolute certainty.

Answer: The probability that one couple will have a baby of the preferred gender is 0.75. Assuming the gender of each baby is independent of the others, the probability that all 5 couples will have a baby of the preferred gender is 0.75⁵ = 0.2373.

Numeric value: 0.2373

In words: The probability that all 5 couples will have a baby of the preferred gender is 0.2373.

Answer: There are two ways to approach this problem. One way is to calculate the probability of each possible outcome (0 to 5 couples having a baby of the preferred gender) and then add up the probabilities for the outcomes where at least 4 couples have a baby of the preferred gender. Another way is to use the complement rule and subtract the probability that fewer than 4 couples have a baby of the preferred gender from 1.

Using the first method, we can calculate the probabilities as follows:

- 0 couples: 0.25⁵ = 0.0009766

- 1 couple: 5 x 0.75 x 0.25⁴ = 0.01465

- 2 couples: 10 x 0.75² x 0.25³ = 0.08789

- 3 couples: 10 x 0.75³ x 0.25² = 0.2637

- 4 couples: 5 x 0.75⁴ x 0.25 = 0.3955

- 5 couples: 0.75⁵ = 0.2373

The probabilities for the outcomes where at least 4 couples have a baby of the preferred gender are 0.3955 and 0.2373, so the total probability is 0.3955 + 0.2373 = 0.6328.

Using the second method, we can calculate the probability that fewer than 4 couples have a baby of the preferred gender as follows:

- 0 couples: 0.25⁵ = 0.0009766

- 1 couple: 5 x 0.75 x 0.25⁴ = 0.01465

- 2 couples: 10 x 0.75² x 0.25³ = 0.08789

- 3 couples: 10 x 0.75³ x 0.25² = 0.2637

The probability that fewer than 4 couples have a baby of the preferred gender is the sum of these probabilities: 0.0009766 + 0.01465 + 0.08789 + 0.2637 = 0.3672.

Therefore, the probability that at least 4 of the 5 couples will have a baby of the preferred gender is 1 - 0.3672 = 0.6328.

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The simplified expression [tex](3.05 * 10^-7) (8.67 * 10^4)[/tex] in standard form to 3 decimal places is approximately 0.026

To simplify the expression[tex](3.05 * 10^-7) (8.67 *  10^4)[/tex] and provide the answer in standard form to 3 decimal places.

Step 1: Multiply the coefficients (3.05 and 8.67).
3.05 * 8.67 = 26.4445

Step 2: Use the properties of exponents to multiply the powers of 10.
[tex]10^{-7} * 10^4 = 10^{(-7+4)} = 10^-3[/tex]

Step 3: Multiply the results from Step 1 and Step 2.
[tex]26.4445 * 10^-3 = 0.0264445[/tex]

Step 4: Round the result to 3 decimal places.
0.0264445 ≈ 0.026

So, the simplified expression (3.05 x 10^-7) (8.67 x 10^4) in standard form to 3 decimal places is approximately 0.026.

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The minimum height of the ladder needed to change the blown outdoor lightbulb is 5 meters.

To determine the minimum height of the ladder needed to change a blown outdoor lightbulb that is 5m up, we need to consider the following terms:

1. The bulb's height (5m)

2. Your reach when on the top rung of the ladder (1m)

3. The required space off the house for the ladder's base for stability (3m)

First, subtract your reach from the bulb's height: 5m - 1m = 4m. This means the ladder needs to reach at least 4 meters up the wall.

Next, we need to use the Pythagorean theorem to find the ladder's minimum height. The theorem states that in a right-angled triangle, the square of the length of the hypotenuse (the ladder) is equal to the sum of the squares of the lengths of the other two sides (the distance from the house and the height up the wall).

Let's denote the ladder's height as L, the distance from the house as A (3m), and the height up the wall as B (4m).

According to the Pythagorean theorem, we have:
L² = A² + B²

Substitute the values for A and B:
L² = (3m)² + (4m)²
L² = 9m² + 16m²
L² = 25m²

Now, find the square root to get the minimum height of the ladder:
L = √25m²
L = 5m

So, the minimum height of the ladder needed to change the blown outdoor lightbulb is 5 meters.

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The possible value of <J is 78 degrees

It is important to note that the different trigonometric identities are;

Also, the law of sines in a triangle is expressed as;

sin A/a = sin B/b = sin C/c

Given that the angles are in capitals and the sides are in small letters.

From the information given, we have that;

sinI/i = sin J/j

Substitute the values, we get;

sin 72 /70 = sin J/72

cross multiply the values, we have;

sin J = 68. 476/70

divide the values

sin J = 0. 9782

Find the inverse of sin

<J = 78 degrees

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a) The price of the old model is P22,289.

b) The dimensions of the rectangle are 16 by 32.

a) Let x be the price of the old model. According to the problem, the price of the new 32'' LED television is P15,500 less than twice the price of the old model.

This can be expressed as 2x - P15,500 = P29,078. Solving for x, we can add P15,500 to both sides to get 2x = P44,578, and then divide both sides by 2 to get x = P22,289.

b) Let w be the width of the rectangle. According to the problem, the length of the rectangle is twice the width, so the length is 2w. The perimeter of a rectangle is the sum of the lengths of all four sides, which in this case is 2w + 2(2w) = 6w.

We are given that the perimeter is 96, so we can set up an equation: 6w = 96. Solving for w, we can divide both sides by 6 to get w = 16. Since the length is twice the width, the length is 2(16) = 32.

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The volume of the large box is 120[tex]s^3[/tex].

If Frank can fit 15 cube-shaped containers in each layer and stack 8 layers into one box, then the total number of containers he can fit in one box is:

15 containers/layer x 8 layers = 120 containers

Since each container is cube-shaped, we can assume that it has the same length, width, and height. Let's represent the length of one side of the container as "s". Then, the volume of one container is:

Volume of one container = [tex]s^3[/tex]

The volume of 120 containers that can fit in one box is:

Volume of 120 containers = 120 x Volume of one container

Substituting the expression for the volume of one container, we get:

Volume of 120 containers = 120[tex]s^3[/tex]

Therefore, the volume of the large box that can hold 120 cube-shaped containers with side length "s" is 120[tex]s^3[/tex].

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Answer:

1024

Step-by-step explanation:

I hope everything I wrote is clear, I really need to sharpen my pencil oof

Answer:

Step-by-step explanation:

I assume the question is what trig function do you use to find x?  If that's correct then answers, from TOP to BOTTOM, are:

tan

cos

sin

Answer:

Triangle 1: tangent

Triangle 2: cosine

Triangle 3: sine

Step-by-step explanation:

First, some definitions before working the problem:

The three standard trigonometric functions, cosine, tangent, and sine, are defined as follows for right triangles:

[tex]sin(\theta)=\dfrac{opposite}{hypotenuse}[/tex]

[tex]tan(\theta)=\dfrac{opposite}{adjacent}[/tex]

[tex]cos(\theta)=\dfrac{adjacent}{hypotenuse}[/tex]

One memorization tactic is "Soh Cah Toa" where the first capital letter represents one of those three trigonometric functions, and the "o" "a" and "h" represent the "opposite" "adjacent" and "hypotenuse" respectively.

The triangle must be a right triangle, or there wouldn't be a "hypotenuse", because the hypotenuse is always across from the right angle.  

Triangle 1

For the first triangle, the known acute angle is in the bottom left.  The two sides of the triangle that are known or are a "goal to find" are not the hypotenuse, so they are the "opposite" & "adjacent".

Specifically, the side of length "13" is touching the known acute angle AND the right angle, so it is the adjacent side.  The unknown side of length "x" is is touching the right angle but is NOT touching the known acute angle, so it is the "opposite" (across from the angle).

Out of "Soh Cah Toa," the part that uses o & a is "Toa".  The "T" in "Toa" stands for Tangent.  So, the desired function to use for the first triangle is the Tangent function.

Triangle 2

For the second triangle, the known acute angle is in the top left.  This time, the "adjacent" side is unknown, labeled as x, so it is the "goal to find" side.  The "hypotenuse" is known.

Therefore, the two sides of the triangle that are known or are a "goal to find" are the "adjacent" & "hypotenuse".

Out of "Soh Cah Toa," the part that uses "a" & "h" is "Cah".  So, the desired function to use for the first triangle is the Cosine function.

Triangle 3

For the third triangle, the known acute angle is in the top right.

This time, the side (at the bottom) across from the angle (at the top right) is known -- the "opposite" leg.  Additionally, the "hypotenuse" is unknown and is our "goal to find" side.  

Therefore, the two sides of the triangle that are known or are a "goal to find" are the "opposite" & "hypotenuse".

Out of "Soh Cah Toa," the part that uses "o" & "h" is "Soh".  So, the desired function to use for the first triangle is the Sine function.

Statements C and D are statements of causation, while statements A, B, E, and F are not.

Causation refers to the relationship between cause and effect, where a change in one variable causes a change in another variable. Statements of causation imply a cause-and-effect relationship between two variables.

Based on the given statements, the statements of causation are C and D. Statement C implies that higher clarity causes an increase in the price of a diamond, and statement D implies that a higher weight causes an increase in the price of a diamond.

Statements A, B, E, and F are not statements of causation. Statement A only provides information about the cost of a particular diamond and does not explain the reason behind the cost. Statement B suggests a relationship between color and clarity, but it does not imply a cause-and-effect relationship.

Statement E also suggests a relationship between color and price, but it does not imply causation. Statement F only suggests an observation about the relationship between cut grade and price, but it does not imply causation.

In summary, statements C and D are statements of causation, while statements A, B, E, and F are not.

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By using trigonometry,

we have shown that tan(15°) = 2 - √3.

One of the most significant areas of mathematics, trigonometry has a wide range of applications. T

he study of the relationship between the sides and angles of the right-angle triangle is essentially the focus of the field of mathematics known as "trigonometry."

Hence, employing trigonometric formulas, functions, or trigonometric identities can be helpful in determining the missing or unknown angles or sides of a right triangle.

Angles in trigonometry can be expressed as either degrees or radians. 0°, 30°, 45°, 60°, and 90° are some of the trigonometric angles that are most frequently employed in computations.

We can use the half-angle formula for tangent to show that:

tan(15°) = tan(30°/2) = (1 - cos(30°)) / sin(30°)

We know that cos(30°) = √3/2 and sin(30°) = 1/2, so we can substitute those values in:

tan(15°) = (1 - √3/2) / 1/2

Simplifying the denominator and multiplying by the reciprocal:

tan(15°) = 2(1 - √3/2)

Simplifying the expression:

tan(15°) = 2 - √3

Therefore, we have shown that tan(15°) = 2 - √3.

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Based on the information on the number line, the numbers that represent the percentages are: 42 (100%), 21 (50%), 63 (150%).

To calculate the number that is equivalent to each percentage we must carry out the following procedure: Rule of three. In this case we must take into account that 42 represents 100% of the people.

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The Unique or Many for each description by placing a check or X in the appropriate box is given below.

We are given that;

Measurements=  30°, 60°, 90°

Side lengths 5 cm, 5 cm, 5 cm Side lengths 3 in and 4.

Now,

If three angle measures are given, and they add up to 180 degrees, then there are infinitely many similar triangles with those angle measures, but they differ in size. This is called the AAA (angle-angle-angle) similarity criterion.

If two angles and a non-included side are given, then there may be zero, one, or two possible triangles with those measurements, depending on the length of the side and the position of the angles. This is called the AAS (angle-angle-side) or SSA (side-side-angle) criterion.

Using criteria, we can fill in the table as follows:

Conditions | Unique | Many Side lengths 3 cm, 6 cm, 7 cm | ✓ | Angle measures 30°, 60°, 90° | | ✓ Angle measures 35º, 35°, 110° | | ✓ Side lengths 5 cm, 5 cm, 5 cm | ✓ | Side lengths 3 in and 4 in with an included 95° angle | ✓ |

Therefore, by the angle the answer will be given.

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Weight difference between the large box and the small box is [tex](1/2)*(w2 - w1)[/tex] pounds.

Let's assume that Gina has n boxes in total, and let x be the weight of each box in pounds. We can then express the weight of the boxes that weigh less than [tex]1/2[/tex] pound as [tex](1/2)*w1[/tex], where [tex]w1[/tex] is the number of boxes that weigh less than [tex]1/2[/tex] pound. Similarly, we can express the weight of the boxes that weigh more than 1/2 pound as [tex](1/2)*w2[/tex], where [tex]w2[/tex] is the number of boxes that weigh more than [tex]1/2[/tex] pound.

Since Gina puts all the boxes weighing less than [tex]1/2[/tex] pound into a small box, the weight of the small box will be the sum of the weights of all the boxes that weigh less than [tex]1/2[/tex] pound, which is [tex](1/2)*w1[/tex].

Similarly, since Gina puts all the boxes weighing more than [tex]1/2[/tex] pound into a large box, the weight of the large box will be the sum of the weights of all the boxes that weigh more than [tex]1/2[/tex] pound, which is [tex](1/2)*w2[/tex].

The weight difference between the large box and the small box will be:

[tex](1/2)*w2 - (1/2)*w1[/tex]

Simplifying this expression, we get:

[tex](1/2)*(w2 - w1)[/tex]

Therefore, the weight difference between the large box and the small box is [tex](1/2)*(w2 - w1)[/tex] pounds.

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There are no points of inflection.

To determine the intervals on which the function S(x) = (x - 10)(1 - x) is concave up or down and find the points of inflection, we need to find the second derivative and analyze its sign.

First, find the first derivative, S'(x):
S'(x) = (x - 10)(-1) + (1 - x)(1) = -x + 10 - 1 + x = 9

Next, find the second derivative, S''(x):
S''(x) = d(S'(x))/dx = d(9)/dx = 0

Since the second derivative S''(x) is constant and equal to 0, there is no concavity, and the function is neither concave up nor concave down. There are no points of inflection.

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The number of students in each bus is 15, and the number of students in each van is 28.

To find the number of students in each van and bus for the field trip to Yellowstone National Park, we can set up a system of equations using the given information. Let x represent the number of students in each van and y represent the number of students in each bus.

For high school A, we have:
2x + 8y = 254

For high school B, we have:
6x + 11y = 398

Now, we can solve this system of equations using the substitution or elimination method. We will use the elimination method:

Step 1: Multiply the first equation by 3 to make the coefficients of x the same in both equations:
6x + 24y = 762

Step 2: Subtract the second equation from the new first equation:
(6x + 24y) - (6x + 11y) = 762 - 398
13y = 364

Step 3: Divide both sides by 13 to find the value of y:
y = 364 / 13
y = 28

Now that we have the number of students in each bus, we can find the number of students in each van:

Step 4: Substitute y back into the first equation:
2x + 8(28) = 254
2x + 224 = 254

Step 5: Subtract 224 from both sides to find the value of x:
2x = 30

Step 6: Divide both sides by 2 to find x:
x = 15

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There are 39 red blocks out of 65 total blocks.

To solve this problem, we need to find the total number of blocks in each repeating pattern. The pattern is three red blocks followed by two blue blocks. So in each pattern, there are five blocks total.

To find the number of red blocks in 65 total blocks, we need to figure out how many times the pattern repeats. We can do this by dividing the total number of blocks (65) by the number of blocks in each pattern (5):

65 ÷ 5 = 13

So the pattern repeats 13 times.

In each pattern, there are three red blocks. So to find the total number of red blocks, we need to multiply the number of red blocks in each pattern (3) by the number of times the pattern repeats (13):

3 x 13 = 39

Therefore, there are 39 red blocks out of 65 total blocks.

The correct answer is option B.

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After one month, Betty will owe $407.02 on her credit card.

The amount Betty will owe after one month depends on how much of the stability she will pay off in the course of that point.

Assuming she does not make any payments in the course of the first month, here is how to calculate her balance:

The cash-withdrawal price is a one-time fee, so it does no longer affect the stability after one month.

Betty withdrew $400, so her starting balance is $406 ($400 for the lawnmower plus $6 cash-withdrawal price).

The interest rate is 3%, that's an annual price. To calculate the monthly charge, divide with the aid of 12: three% / 12 = 0.25%.

To calculate the interest charged for the first month, multiply the stability through the monthly interest rate: $406 * 0.25% = $1.02.

Add the interest to the balance: $406 + $1.02 = $407.02. that is Betty's balance after one month.

Consequently, after one month, Betty will owe $407.02 on her credit card.

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The distance which this light travel per second is equal to 3 × 10⁸ meters per seconds.

In Mathematics and Science, speed is the distance covered by a physical object per unit of time.

In Mathematics and Science, the speed of any a physical object can be calculated by using this formula;

Speed = distance/time

By making distance the subject of formula, we have:

Distance, d(t) = speed × time

Distance = (9.45 × 10¹⁵ meters per year) × (1 year/ 3.15 × 10⁷ seconds)

Distance = 3 × 10⁸ meters per seconds.

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Complete Question:

Light travels 9.45 × 10¹⁵ meters in a year. There are about 3.15 × 10⁷ seconds in a year. How far does light travel per second?

Answer:

no solution

Step-by-step explanation:

There are no values of x that make the equation true.

The solution to the problems using trigonometric ratios are:

12a) x = 16.09

12c) x = 7 and y = 7

13a) Time it takes to reach the ground is: 8 seconds

13b) Highest point reached is: 80 ft

12a) Using the law of sines, we can say that:

x/sin 90 = 9/sin 34

x = (9 * sin 90)/sin 34

x = 16.09

12c) Using the law of sines, we can say that:

x/sin 45 = 7√2/sin 90

x = (7√2 * 1/√2)/1

x = 7

Similarly, because it is an isosceles triangle, y = 7

13a) The equation of the height above the ground is :

h = 40t - 5t²

where:

h is height

t is time in seconds

Thus:

Time it takes to reach the ground is at h = 0.

40t - 5t² = 0

5t² = 40t

5t = 40

t = 8 seconds

b) Highest point reached:

h'(t) = 40 - 10t

h'(t) = 0

40 - 10t = 0

t = 4 seconds

Thus:

h_max = 40(4) - 5(4)²

h_max = 80 ft

c) Time at which ball was 35ft off ground is:

35 = 40t - 5t²

5t² - 40t + 35 = 0

Using quadratic equation calculator gives us:

t = 1 and 7 seconds

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For the function,

-number of complex zeros: four

-possible # of imaginary zeros: two pairs

-possible # of positive real zeros: zero

-possible # negative real zeros: 0 or 2

-possible rational zeros:  ±1, ±3, ±5, ±9, ±15, ±45

-factors to: (x + 3i)(x - 3i)(x + √5i)(x - √5i)

-zeros: x = ±3i, x = ±√5i.

The function is: F(x) = x⁴ +14x²+45.

Number of complex zeros: By the Fundamental Theorem of Algebra, the function has at most four complex zeros.

Possible number of imaginary zeros: If the complex zeros are not real, then there are at most two pairs of imaginary zeros.

Possible number of positive real zeros: The function has no positive real zeros since F(x) is always positive for x>0.

Possible number of negative real zeros: By Descartes' Rule of Signs, the function has either 0 or 2 negative real zeros.

Possible rational zeros: The rational zeros can be found using the Rational Root Theorem. They are of the form ±(a factor of 45) / (a factor of 1), which gives the following possible rational zeros: ±1, ±3, ±5, ±9, ±15, ±45.

To factor the polynomial:

F(x) = x⁴ +14x²+45

= (x² + 9)(x² + 5)

So the factors to linear factors are: (x + 3i)(x - 3i)(x + √5i)(x - √5i), where i is the imaginary unit.

Therefore, the zeros are: x = ±3i, x = ±√5i.

Note that all zeros are complex since there are no real roots.

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To solve the exact differential equation (5t^2 + 8y) dy + (10yt + 9t^2) = 0, we need to check if it is exact or not. We do so by taking partial derivatives with respect to y and t:

∂/∂y (5t^2 + 8y) = 8
∂/∂t (10yt + 9t^2) = 10y + 18t

Since these partial derivatives are not equal, the equation is not exact. To make it exact, we can multiply the entire equation by a integrating factor, which is given by:

μ = e^(∫(∂/∂t)(10yt + 9t^2) dt) = e^(∫(10y + 18t) dt) = e^(10yt + 9t^2)

Multiplying both sides of the equation by μ, we get:

(5t^2 + 8y)e^(10yt + 9t^2) dy + (10yt + 9t^2)e^(10yt + 9t^2) dt = 0

Now, we can check if this equation is exact:

∂/∂y (5t^2e^(10yt + 9t^2) + 8ye^(10yt + 9t^2)) = 10te^(10yt + 9t^2)
∂/∂t ((10ye^(10yt + 9t^2)) + (9t^2e^(10yt + 9t^2))) = 10ye^(10yt + 9t^2) + 18t^2e^(10yt + 9t^2)

These partial derivatives are equal, so the equation is exact. Therefore, we can find a potential function Φ such that:

∂Φ/∂y = 5t^2e^(10yt + 9t^2) + 8ye^(10yt + 9t^2)
∂Φ/∂t = (10ye^(10yt + 9t^2)) + (9t^2e^(10yt + 9t^2))

Integrating the first equation with respect to y, we get:

Φ = ∫(5t^2e^(10yt + 9t^2) + 8ye^(10yt + 9t^2)) dy = (5t^2/10)e^(10yt + 9t^2) + (4y/10)e^(10yt + 9t^2) + C(t)

where C(t) is an arbitrary constant of integration that depends only on t.

Now, we can differentiate this expression with respect to t and compare it to the second equation:

∂Φ/∂t = (10t/10)e^(10yt + 9t^2) + C'(t)
(10ye^(10yt + 9t^2)) + (9t^2e^(10yt + 9t^2)) = (10t/10)e^(10yt + 9t^2) + C'(t)

Comparing the two expressions, we get:

C'(t) = 10ye^(10yt + 9t^2)

Integrating both sides with respect to t, we get:

C(t) = ∫10ye^(10yt + 9t^2) dt = e^(10yt + 9t^2) + K

where K is another arbitrary constant of integration.

Therefore, the solution to the exact differential equation (5t^2 + 8y) dy + (10yt + 9t^2) = 0 is given by:

(5t^2/10)e^(10yt + 9t^2) + (4y/10)e^(10yt + 9t^2) + e^(10yt + 9t^2) + K = 0

or simplifying:

y = (-5t^2/4) - (1/2)e^(-10yt - 9t^2) - (K/4)e^(-10yt - 9t^2)

where K is an arbitrary constant of integration.

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The expression (2x-3)(2x-3) is equal to (2x-3)^2.

To expand the expression (2x-3)(2x-3), we can use the FOIL method (which stands for First, Outer, Inner, Last).

Multiplying the first terms of each binomial, we get 2x times 2x, which is 4x^2.

Multiplying the outer terms, we get -3 times 2x, which is -6x.

Multiplying the inner terms, we get -3 times 2x again, which is also -6x.

Multiplying the last terms of each binomial, we get -3 times -3, which is 9.

Combining like terms, we get 4x^2 - 12x + 9.

Therefore, (2x-3)(2x-3) is equal to (2x-3)^2, which is equivalent to 4x^2 - 12x + 9.

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The percentage by which the median earnings of college degree exceed that of high school degreed for 1973 for men is 17.9%

College: Women= 4400

H.School: Women = 3300

Solving we have

The base number is the high  school women.

The difference is 4400 - 3300 = 1100

So the % = (1100/3300) * 100% = 33.3%

1973

The base number is again high school 5600

Difference: 6600 - 5600 = 1000

% = (1000/5600) * 100% = 17.9

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Full Question:

Although part of your question is missing, you might be referring to this full question:

See the aattached image.

The amount of interest earned by Mr. Jones's retirement account over 5 years is $79,025.

Mr. Jones has invested $410,000 in a retirement account that earns 3.85% simple interest per year. Simple interest is calculated by multiplying the principal amount by the annual interest rate and the time period in years.

In this case, the time period is 5 years. Using the formula for simple interest, we can calculate the amount of interest earned on this investment as:

I = P * r * t = $410,000 * 0.0385 * 5 = $79,025

Therefore, the amount of interest earned by Mr. Jones's retirement account over 5 years is $79,025. This means that the total value of his retirement account after 5 years would be $489,025 ($410,000 + $79,025).

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