Answer:
a) F= 0,19 [N] according to problem statement
b) F = 0,19*10⁹ [N] using the right value of K
Explanation:
The force between two electric charges is according to Coulomb´s law is:
F = K * q₁*q₂ / d² where q₁ and q₂ are the charges on body one and body 2 respectively, d is the distance between the two bodies and K is a constant K = 8,988100*10⁹ N.m²/C². The problem establishes to use K = 8,988100 N.m²/C².
NOTE: To value of is : K = 8,988100*10⁹ N.m²/C². I am going to solve the problem using K = 8,988100 N.m²/C² if that information was an error, all we need to get the right answer is multiply the result by 10⁹
Then:
F = 8,988100 * 1,2* 0,36 / (4,5)² [ N*m²/C² ] * [ C*C*/m²]
F = 3,882859/ 20,25 [N]
F= 0,19 [N]
The force is of repulsion since the two charges are positive and in the direction of the straight line which passes through the centers of the bodies
A bird flew to catch a prey and went from 12 m/s to 22 m/s in 2 seconds. What was the magnitude of the bird's acceleration?
Answer: Peregrine falcons are famed for their high-speed, high-altitude stoops. Hunting prey at perhaps the highest speed of any animal places a stooping falcon under extraordinary physical, physiological, and cognitive demands, yet it remains unknown how this behavioural strategy promotes catch success. Because the behavioral aspects of stooping are intimately related to its biomechanical constraints, we address this question through an embodied cognition approach. We model the falcon’s cognition using guidance laws inspired by theory and experiment, and embody this in a physics-based simulation of predator and prey flight. Stooping maximizes catch success against agile prey by minimizing roll inertia and maximizing the aerodynamic forces available for maneuvering but requires a tightly tuned guidance law, and exquisitely precise vision and control.
Explanation:
What is Newton first law?
Newton's First Law of Motion states "An object continues to be in its state of rest or of uniform motion along a straight line unless acted upon by an unbalanced force".
HELP PLS
Given the following blackbody curve graph, what color will Star A be?
Blackbody radiation graph for Star A, which has a surface temperature of 5,700 degrees Celsius. At the point where the curve peaks, the wavelength is approximately 550 nanometers, in the middle of the visible light spectrum.
Blue
Red
White
Yellow
Answer:
red I think
Explanation:
it's on red so I googled some of it and the closest was red
Answer:
Red
Explanation:
A bowling ball of mas 6.0 kg is released from rest
Answer:
could u give a more longer understanding
how to type a capital letter in my computer
Answer:
Hold down the shift key if your on windows, mac or chromebooks.
Explanation:
Computer Technician
Answer:
Press the "caps lock" button and then press which letter u want to be in cap
Plastic is a good conductor of heat. True/ False
Answer:
false because they have no fee electrons
False, it is a poor conductor of heat. They are great insulators though.
The graph below was created from the motion of a cart on a ramp. Use the graph to answer the question that follows.
main seconde
What is the acceleration of the object at t4s?
5. A horizontal force of 10 N is applied to a 1-kg object resting on a frictionless table. How much will the object accelerate?
A. 3.25 m/s2
B. 6.0 m/s2
C. 9.0 m/s2
D. 10 m/s2
Answer:
C
Explanation:
because it is TM
explain how hydrogen is changed to helium during fusion.
Answer:
The Sun and Nuclear Fusion. In the core of the Sun hydrogen is being converted into helium. This is called nuclear fusion. It takes four hydrogen atoms to fuse into each helium atom
Explanation:
hop it helps
If an airplane needs a minimum of 148 m/s to take off, and it accelerates at 3 m/s^2, how long should the runway be so that it can take off at this minimum speed?
Assuming it takes off from rest, the runway should have length x such that
(148 m/s)² - 0² = 2 (3 m/s²) x
which follows from the formula,
v² - u² = 2 a ∆x
(where u is initial speed and v is final speed; the other two's significance should be obvious)
Solve for x :
x = (148 m/s)² / (2 (3 m/s²))
x ≈ 3650.67 m
Your dirty clothes, left on the floor overnight, are there when you wake up in the morning. What type of law is at work ?
Answer:
1st law of motion
Explanation:
it's newton's first law of motion.
Answer:
A C E
Explanation:
How fast must a 2.7-g ping-pong ball move in order to have the same kinetic energy as a 145 g baseball moving at 37.0 m/s
Answer:
271.14m/sExplanation:
The kinetic energy of the 145g is
mass= 0.145kg
velocity= 37m/s
KE=1/2mv^2
KE=1/2(0.145*37^2)
KE=1/2(0.145*1369)
KE=1/2(198.505)
KE=198.505/2
KE=99.25J
Now since the kinetic energy of the 2.7g must be 99.25J
mass =2.7g= 0.0027kg
99.25=1/2(0.0027)v^2
99.25=0.00135v^2
99.25/0.00135=v^2
73518.5185185=v^2
v=√73518.5185185
v=271.14m/s
6.
The minimum value of coefficient of friction (u)
such that block of mass '5 kg' remains at rest is
5 kg
μ
ng
3 kg
(1) 0.3
(3) 0.6
(2) 0.5
(4) 0.4
Answer:
2
Explanation:
It is simple coman sense
What is the velocity of Car B after collision?
Answer:
30m/s
Explanation:
m1v1=m2v2
12 * 10=4* v2
120/4 =v2
V2=30m/s
A rod of length Lo moves iwth a speed v along the horizontal direction. The rod makes an angle of (θ)0 with respect to the x' axis.
Required:
a. Show that the length of the rod as measured by a stationary observer is L=L0[1-v^2/c^2 cos^2(θ)0].
b. Show that the angle the rod makes iwth the x-axis is given by the expression tan(theta)=tan(θ)0/(1-v^2/c^2)^.5
Answer:
From the question we are told that
The length of the rod is [tex]L_o[/tex]
The speed is v
The angle made by the rod is [tex]\theta[/tex]
Generally the x-component of the rod's length is
[tex]L_x = L_o cos (\theta )[/tex]
Generally the length of the rod along the x-axis as seen by the observer, is mathematically defined by the theory of relativity as
[tex]L_xo = L_x \sqrt{1 - \frac{v^2}{c^2} }[/tex]
=> [tex]L_xo = [L_o cos (\theta )] \sqrt{1 - \frac{v^2}{c^2} }[/tex]
Generally the y-component of the rods length is mathematically represented as
[tex]L_y = L_o sin (\theta)[/tex]
Generally the length of the rod along the y-axis as seen by the observer, is also equivalent to the actual length of the rod along the y-axis i.e [tex]L_y [/tex]
Generally the resultant length of the rod as seen by the observer is mathematically represented as
[tex]L_r = \sqrt{ L_{xo} ^2 + L_y^2}[/tex]
=> [tex]L_r = \sqrt{[ (L_o cos(\theta) [\sqrt{1 - \frac{v^2}{c^2} }\ \ ]^2+ L_o sin(\theta )^2)}[/tex]
=> [tex]L_r= \sqrt{ (L_o cos(\theta)^2 * [ \sqrt{1 - \frac{v^2}{c^2} } ]^2 + (L_o sin(\theta))^2}[/tex]
=> [tex]L_r = \sqrt{(L_o cos(\theta) ^2 [1 - \frac{v^2}{c^2} ] +(L_o sin(\theta))^2}[/tex]
=> [tex]L_r = \sqrt{L_o^2 * cos^2(\theta) [1 - \frac{v^2 }{c^2} ]+ L_o^2 * sin(\theta)^2}[/tex]
=> [tex]L_r = \sqrt{ [cos^2\theta +sin^2\theta ]- \frac{v^2 }{c^2}cos^2 \theta }[/tex]
=> [tex]L_o \sqrt{1 - \frac{v^2}{c^2 } cos^2(\theta ) }[/tex]
Hence the length of the rod as measured by a stationary observer is
[tex] L_r = L_o \sqrt{1 - \frac{v^2}{c^2 } cos^2(\theta ) }[/tex]
Generally the angle made is mathematically represented
[tex]tan(\theta) = \frac{L_y}{L_x}[/tex]
=> [tex]tan {\theta } = \frac{L_o sin(\theta )}{ (L_o cos(\theta ))\sqrt{ 1 -\frac{v^2}{c^2} } }[/tex]
=> [tex]tan(\theta ) = \frac{tan\theta}{\sqrt{1 - \frac{v^2}{c^2} } }[/tex]
Explanation:
The special relativity relations allow to find the results for the questions about the measurements made by an observed at rest on the rod are:
a) The length of the rod is: [tex]L = L_o \sqrt{1 - \frac{v^2}{c^2} \ cos^2\theta_o }[/tex]
b) The angle with respect to the x axis is: [tex]tan \theta = \frac{tan \theta_o}{\sqrt{1- \frac{v^2}{c^2} } }[/tex]
Special relativity studies the motion of bodies with speeds close to the speed of light, with two fundamental assumptions.
The laws of physics are the same in all inertial systems. The speed of light in vacuum has the same value for all inertial systems.
If we assume that the two systems move in the x-axis, the relationship between the components of the length are:
[tex]L_x = L_{ox} \ \sqrt{1- \frac{v^2}{c^2} }[/tex]
[tex]L_y = L_o_y \\L_z = L_{oz}[/tex]
Where the subscript "o" is used for the fixed observed on the rod, that is, it is at rest with respect to the body, v and c are the speed of the system and light, respectively.
a) They indicate that the length of the rod is L₀ and it forms an angle θ with the horizontal.
Let's use trigonometry to find the components of the length of the rod in the system at rest, with respect to it.
sin θ = [tex]\frac{L_{oy}}{L_o}[/tex]
cos θ = [tex]\frac{L_{ox}}{L_o}[/tex]
[tex]L_{oy}[/tex] = L₀ sin θ
L₀ₓ = L₀ cos θ
Let us use the transformation relations of the length of the special relativity rod.
x-axis
[tex]L_x = (L_o cos \theta_o) \ \sqrt{1- \frac{v^2}{c^2} }[/tex]
y-axis
[tex]L_y = L_{o} sin \theta_o[/tex]
The length of the rod with respect to the observer using the Pythagorean theorem is:
L² = [tex]L_x^2 + L_y^2[/tex]
[tex]L^2 = (L_o cos \theta_o\sqrt{1- \frac{v^2}{c^2} })^2 + (L_o sin \theta_o)^2[/tex]
[tex]L_2 = L_o^2 ( cos^2 \theta_o - cos^2 \theta_o \frac{v^2}{c^2} + sin^2\theta_o)[/tex]
[tex]L^2 = L_o^2 ( 1 - \frac{v^2}{c^2} \ cos^2 \theta_o)[/tex]
[tex]L= Lo \sqrt{1- \frac{v^2}{c^2} cos^2 \theta_o}[/tex]
b) the angle with the x-axis measured by the stationary observer is:
[tex]tna \theta = \frac{L_y}{L_x}[/tex]
[tex]tan \ theta = \frac{L_o sin \theta_o}{L_o cos \theta_o \sqrt{1- \frac{v^2}{c^2} } }[/tex]
[tex]tan \theta = \frac{tan \theta_o}{\sqrt{1-\frac{v^2}{c^2} } }[/tex]
In conclusion, using the special relativity relations we can find the results for the questions about the measurements made by an observed at rest on the rod are:
a) The length of the rod is: [tex]L = L_o \sqrt{1- \frac{v^2}{c^2} \ cos^2\theta_o }[/tex]
b) The angle to the x axis is: [tex]tan \theta = \frac{tan \theta_o}{\sqrt{1- \frac{v^2}{c^2} } }[/tex]
Learn more about special relativity here: brainly.com/question/9820962
Which of the following involves reflected light waves
what is the weight of a 10 kg object on earth
Answer:
100N.
Its 100n. :)
In a nuclear power plant, the nuclear reaction is kept from going critical by keeping the rate of reaction safe.
How do the control rods figure into this?
A. The control rods absorb the excess heat produced in the reaction.
B. The control rods absorb excess neutrons, keeping them from causing too many uranium atoms to split too quickly.
C. The control rods absorb excess uranium atoms so that the reaction doesn't happen too quickly.
D. The control rods provide additional neutrons to keep the reaction going.
Answer:
B. The control rods absorb excess neutrons, keeping them from causing too many uranium atoms to split too quickly
Answer:
The control rods absorb excess neutrons, keeping them from causing too many uranium atoms to split too quickly.
Explanation:
I took the test before.
You can see my other article just search in search engine with: Learningandassignments diy4pro
Click on my site and find these related article post:
Nuclear Energy- Quiz
Hope it helps.
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a table is pushed it 15 metre across a room with the force of 50N.what is the work done?
Answer:
W=f*d
= 50 * 15
=750 J
Therefore, the work done is 750 joule( J)
Calculate the acceleration due to gravity on the planet where a 80 kg astronaut weighs only 304 N.
Answer:
3.8 m/s/s^2
Explanation:
The acceleration due to gravity on the planet where a 80 kg astronaut weighs only 304 N is 3.8 m/s².
What is acceleration due to gravity?The gravitational force is the force by which an object attracts other objects into its centre of mass. The force it exerts depends on the mass of the body and distance between them. Earth attracts every objects on its surface to the ground by gravitational force
The acceleration arises in the body due to the force of gravitation is called acceleration due to gravity (g). It varies from planets to planet. The weight we experience in earth is due to the gravity.
Weight = m g
where m is the mass.
given the mass of an astronaut = 80 kg
weight = 304 N
then g = weight/ mass
= 304 N / 80 Kg = 3.8 m/s²
Therefore, the acceleration due to gravity of the planet is 3.8 m/s².
To find more on acceleration due to gravity, refer here:
https://brainly.com/question/3198512
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Which action would increase the strength of the electric force between the
balloon and the water?
A. Holding a magnet near the stream of water
B. Holding the balloon closer to the stream of water
C. Holding a magnet near the balloon
D. Moving the balloon farther away from the stream of water
Answer:
B
Explanation:
Holding the balloon closer to the stream of water
Holding the balloon closer to the stream of water is an action which would increase the strength of the electric force between the balloon and the water. Thus, the correct option is B.
What is electric force?The repulsive or attractive interaction between any two charged bodies is called as the electric force. This is similar to any force, the impact and effects on the given body are described through the Newton's laws of motion. The electric force is one of the various forces which act on objects.
Electric force is the attractive force which is present between the electrons (negatively charged bodies) and the nucleus. Here, a positive charge or a negative charge creates a field in the empty space which is around it, and we call that empty space as an electric field.
Holding the balloon closer to the stream of water is an action which would increase the strength of the electric force between the balloon and the water.
Therefore, the correct option is B.
Learn more about Force here:
https://brainly.com/question/13191643
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What energy movement lasting about 5 to 15 minutes and does not require energy?
Answer:
cause it too powerful lol ;)
Consider a system consisting of two Einstein solids, A and B, each containing N= 10 oscillators, and sharing a total of q= 20 units of energy. Assume that the two solids areweakly coupled and the total energy is fixed.
Required:
a. How many different macrostates are available to solid A or B?
b. How many different microstates are available to the combined system of A & B?
c. Starting with the exact form for the multiplicity of an Einstein solid, calculate the probability of finding all the energy in solid A, assuming that the system is in thermal equilibrium.
d. Calculate the probability of finding exactly half the energy in solid A.
Answer:Gg
Explanation:
Can someone help me with these please I would appreciate it
Answer:
7) 5 m/s
8) 1.5 m/s
9) -9 m/s^2
10) 2.2 m/s
11) 5 s
Explanation:
These problems make use of the relations:
a = ∆v/∆t
d = 1/2at^2 . . . . acceleration to/from rest
v^2 = 2ad . . . . . acceleration to/from rest
In each case, choose the formula appropriate to the question, fill in the given values, and solve for what's missing.
__
7) v^2 = 2ad
v = √(2(9.8 m/s^2)(1.5 m)) = √(29.4 m^2/s^2) ≈ 5 m/s
__
8) d = 1/2at^2
a = 2d/t^2 = 2(75 m)/(10 s)^2 = 1.5 m/s^2
__
9) a = ∆v/∆t
a = (-45 m/s)/(5 s) = -9 m/s^2
__
10) a = ∆v/∆t
∆v = a·∆t = (0.09 m/s^2)(10 s) = 0.9 m/s
Vivian's final speed is the initial speed plus the change in speed:
1.3 m/s + 0.9 m/s = 2.2 m/s
__
11) a = ∆v/∆t
∆t = ∆v/a = (0.50 cm/s -0.75 cm/s)/(-0.05 cm/s^2) = -.25/-.05 s = 5 s
examples of electromagnetic interactions in everyday life
Answer:
Maybe when you bump into the refrigerator and the magnet falls?
Explanation:
This is an example of you interacting with electromagnetics because you must have bumped into something and made a magnet fall.
I hope it helps?
If it does help can I have a brainliest?
HELP ASAP!!!!!!
Which change will decrease the electric force between two positively charged objects?
1.moving them closer together
2.moving them farther apart
3.adding neutrons
4.removing electrons
Answer:
I think it’s adding neutrons
Explanation:
Question 1 Water: Start with the Water tab. Note that light areas represent places where the water is high (crests). Dark areas represent low points (troughs). The water drops should already be dripping from the faucet. You can inerease their frequency and amplitude by using the Frequency and Amplitude slider. Using the controls on the far right, you can add measuring tools, add wall, add another faucet, or insert a single-slit or tw0-slit barrier. Part A What kind of wave patterns do you observe in the sink in the top view? I Part B Click on the Show Graph button in the top right corner of the window. The graph shows the moving water level, which is the actual amplitude of the waves. What general mathematical graph function does this look like? What pattern do you observe in the amplitude of these waves? Provide a hypothesis to explain this pattern in the amplitude. I Part C What happens when you increase the frequency of the water drops? What happens to the wavelength of the waves on the surface of water? PLZ ANSWER ALL FOR BRAINLIEST
Answer:
Looks like a cosine function graph. The wave pattern is transversal waves . The faster the amplitude the higher the wave. The force of the drop hitting the water pushes the water down and out causing waves If the water hits from a higher amplitude the waves raise bigger . When you increase the frequency of the water drops the waves move faster but no bigger. When you increase the frequency of the water drops the wave ripples faster .
Explanation:
An answer to part of your question
A transverse wave is the kind of wave pattern I observe in the sink in the top view.
Transverse waves
A transverse wave is a wave whose oscillations are perpendicular to the direction of the wave's advance. This is in contrast to a longitudinal wave which travels in the direction of its oscillations
At a particular sea level location at a particular time the atmospheric pressure is 14.8 lbs/in^2 and the temperature is 80 degrees F. Estimate the temperature, pressure, and air density at an altitude of 8,000 ft.
Answer:
30.52 °F
1572 lbs/ft²
0.0019 slug/ft³
Explanation:
Given that
Pressure at sea level, P₁ = 14.8 PSI
Temperature, T₁ = 80 °F
At 8,000 ft (m) altitude
for altitude h, less than 36000 ft, the model used to modify temperature and pressure is written below
T = 59 - 0.00356h, where h is the altitude
T = 59 - 0.00356(8,000)
T = 59 - 28.48
T = 30.52 °F
Next, we find the pressure which is calculated using the formula
P = 2116 [(T + 459.7)/518.6]^5.256
P = 2116 [(30.52 + 459.7) / 518.6]^5.256
P = 2116 [490.22/518.6]^5.256
P = 2116 (0.945)^5.256
P = 2116 * 0.743
P = 1572 lbs/ft²
The density is gotten using the formula
ρ = P / [1718 (T + 459.7)]
ρ = 1572 / [1718 (30.52 + 459.7)]
ρ = 1572 / (1718 * 490.22)
ρ = 1572 / 842198
ρ = 0.0019 slug/ft³
HELP ASAP!!!!!!
Two objects are held close together. When they are released, they move toward one another. Which conclusion is
supported by this evidence?
O The objects are both positively charged.
O The objects are both negatively charged.
O The objects have no charge.
O The objects have opposite charges.
Answer:
they have opposite charges
You threw a ball straight up into the air at 7.34m/s. How high does the ball go?
Answer:
7.34x
Explanation:
Depends on how long it was in the air. 7.34x, x is how many seconds.