Problem solving: Janine is 7 years younger than Lucy and 4 years older than
Samantha. The average of their ages is 16. How old is:
a. Janine?
b. Samantha?
c. Lucy?

Answer:

7 3/8 + (-4 1/2) ÷ (-5 2/3) = 8 23/136

Step-by-step explanation:

1) First I turned all the mix numbers into improper fractions:

7 3/8 ----> ( 7(8)+3/8) = 59/8, 4 1/2 ----> (4(2)+1/2) = 9/2, 5 2/3 ---->  (5(3)+2/3) = 17/3

So now it should look like this: 59/8 + (-9/2)÷(-17/3)

2) Now our goal is to divide both of the improper fractions (-9/2)÷(-17/3),

- We first apply our fraction rule:  -a/-b = a/b (when we have two negatives they cancel out each other and make a positive)

Our Case, From this:-9/2 ÷ -17/3 = To This: 9/2 ÷ 17/3

3) Now we can divide the fractions using this rule: a/b ÷ c/d = a times d / b times

Our Case, From This: 9/2 ÷ 17/3 To This: 9(3)/2(17) Which Gives Us: 27/34

(9 x 3 = 27, 2 x 17= 34)

So now it looks like this: 59/8 +27/34

4) Our look goal is to have the same denominator (which is the bottom part of the fraction)  which are 8 and 34

To find it we find the LCM or Least Common Multiple of 8 and 34

(The LCM of a, b is the smallest positive number that is divisible by both a and b) which in this case a and b are 8 and 34  

LCM is 136

5) We adjust our two fractions based on the LCM,

(Multiply each numerator ( top part of the fraction)  by the same amount of needed to multiply its corresponding denominator to turn it to the LCM 136.

From This: 59/8  and 27/34 To This: 1003/136 and 108/36 ( 59(17)/8 (17) = 1003/136, 27(4)/34(4) = 108/306

6) Finally we can add the numerator (1003 and 108) together: 1003+108= 1111 and now we are left with 1111/136

Then we turn our improper fraction back into a mix number: 1111/138= 8 23/136

Answer:

[tex]\frac{1111}{136} = 8 \frac{23}{136}[/tex]

Step-by-step explanation:

We want to simplify:

[tex]7 \frac{3}{8} + \frac{ -4 \frac{1}{2} }{ -5 \frac{2}{3} }[/tex]

First, convert all the fractions to improper fractions:

[tex]\frac{59}{8} + \frac{ - \frac{9}{2} }{ - \frac{17}{3} } \\\\= \frac{59}{8} + \frac{27}{34}[/tex]

Find the LCM of the denominators:

[tex]\frac{(17 * 59) + (4 * 27)}{136} \\\\ = \frac{1003 + 108}{136}\\ \\= \frac{1111}{136} \\\\= 8 \frac{23}{136}[/tex]

Answer: Shania types 30 words in 1 minute. --> (1, 30)  

Shania types 120 words in 4 minutes. --> (4,120)

Shania types 150 words in 5 minutes. ---> (5, 150)

Step-by-step explanation:

In the given graph, At x-axis we have Time (minutes) which is an independent variable. On the other hand, at y-axis we have Words type which is dependent varaible.

Point on graph is written in the form (x,y)

So, points corresponding to

Shania types 30 words in 1 minute. --> (1, 30)  [here x= 1 and y=30]

Shania types 120 words in 4 minutes. --> (4,120) [here x=4 and y=120]

Shania types 150 words in 5 minutes. ---> (5, 150)[here x= 5 and y=150]

Explanation:

The vertical angles at C are congruent with each other, so we have the necessary conditions to invoke the SAS congruence postulate:

  ∆BCA ≅ ∆ECD

BA ≅ ED by CPCTC (corresponding parts of congruent triangles are congruent)

Answer:

The speed V = 194.03 mph

Direction = 3.6° northeast

Step-by-step explanation:

The distance of the trip = 291 miles

The direction of flight = 9.1 degrees northeast

Speed of the prevailing wind = 25 mph

Direction of wing = southeast = 45 degrees South of East

The speed heading to Ivy Cliffs = V₁

V×(sin(9.1) + cos(9.1)) + 25×(-sin(45) + cos(45))  × t₁ = 291 miles

V×(sin(9.1) + cos(9.1)) + 25×(sin(45) + -cos(45))  × t₂ = 291 miles

t₁ + t₂ = 3 hours

(V×(sin(9.1)-25×(sin(45))j + (V×cos(9.1) + 25×cos(45))i

The magnitude V² = V²+29.32·V +625= 291²/t₁²......(1)

Also on the return trip we have;

V²-29.32·V +625= 291²/(3-t₁)²..........................................(2)

Subtracting equation (2) from (1) gives;

58.64·V = 291²/t₁² - 291²/(3-t₁)² = 291²×(6·t-9)/(t²·(t-3)²)

V = 291²×(6·t-9)/(t²·(t-3)²)/58.64

Substituting the value of V in (2) with a graphing calculator gives;

t₁= 1.612 or 1.387

Given that magnitude of the speed going > return = V² for  t₁ < t₂

t₁ = 1.387, t₂ = 1.612

From  V²+29.32·V +625= 291²/t₁², we have

V²+29.32·V +625= 291²/1.387²

Which gives

V²+29.32·V -43336.5 = 0

(V + 233.35)(V-194.03) = 0

V = -233.35 mph or V = 194.03 mph

Given that V is a natural number, we have, V = 194.03 mph.

The direction is given by the relation;

V×(sin(9.1) + cos(9.1)) + 25×(-sin(45) + cos(45))  × t₁ = 291 miles

V×(sin(9.1) + cos(9.1)) + 25×(-sin(45) + cos(45))  × t₁ = 291 miles

194.03×sin(9.1 degrees)-25×sin(45 degrees)j + 194.03×cos(9.1 degrees) + 25×cos(45 degrees)i = 291/1.387

13j + 209.27i = 208.81 mph

The angle tan θ = 13/209 = 0.00622

θ = tan⁻¹(13/209.27) = 3.6°.

Answer: [tex]x = \frac{3}{4}[/tex]

Step-by-step explanation:

[tex]4x-2=1\\Add(2)\\4x=3\\Divide(4)\\x=3/4[/tex]

Hope it helps <3

Answer:

[tex]\boxed{x=\frac{3}{4}}[/tex]

Step-by-step explanation:

[tex]4x-2=1[/tex]

Add 2 on both sides.

[tex]4x-2+2=1+2[/tex]

[tex]4x=3[/tex]

Divide both sides by 4.

[tex]\displaystyle \frac{4x}{4} =\frac{3}{4}[/tex]

[tex]\displaystyle x=\frac{3}{4}[/tex]

Answer:

8

Step-by-step explanation:

Hi there! :)

Answer:

y = 8.

Step-by-step explanation:

Starting with:

3/4y - 2 = 6 - 1/4y

Isolate the y variable to solve this equation. Begin by adding '1/4y' to both sides:

3/4y + 1/4y - 2 = 6

y - 2 = 6

Add 2 to both sides:

y = 8.

Answer:

A square root of a number is a value that, when multiplied by itself, gives the number.

Examples:

4 multiplied by itself is 16. Therefore, the square root of 16 is 4.

(4 x 4 = 16)

The same goes for every number.

(3 x 3 = 9) square root of 9 is 3

(5 x 5 = 25) square root of 25 is 5

finding the number which was multiplied to itself giving the given product of question

Answer:

1.

[tex](x , y) = (4 ,\: 0)[/tex]

2.

[tex](4,0) = (x,y)[/tex]

3.

[tex](x,y) = ( - 3,0)[/tex]

I hope it helps :)

Answer:

96[tex]\sqrt{3}[/tex] cm²

Step-by-step explanation:

A hexagon can be cut into 6 equilateral triangles.

Using the half shown in the diagram to calculate the apothem a , and the exact value

sin60° = [tex]\frac{\sqrt{3} }{2}[/tex] , then

sin60° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{a}{8}[/tex] = [tex]\frac{\sqrt{3} }{2}[/tex] ( cross- multiply )

2a = 8[tex]\sqrt{3}[/tex] ( divide both sides by 2 )

a = 4[tex]\sqrt{3}[/tex] cm

The area (A) can be calculated using

A = [tex]\frac{1}{2}[/tex] pa ( p is the perimeter of the hexagon )

The sides of the hexagon measure 8 cm ( equilateral Δ has congruent sides )

p = 6 × 8 = 48 cm, so

A = [tex]\frac{1}{2}[/tex] × 48 × 4[tex]\sqrt{3}[/tex] = 96[tex]\sqrt{3}[/tex] cm²

Answer:

135° and 45° respectively

Step-by-step explanation:

x + y = 180° (angles on a straight line)

x = 3y (corresponding angles)

3y + y = 180°

4y = 180°

y = 180/4

y = 45°

x = 180 - y

x = 180 - 45

x = 135°

Answer:

5

Step-by-step explanation:

Answer:

x=0,8

Step-by-step explanation:

We want to find the values of x when y = -6

There are two different values of x that give y = -6

The first is x=0

When f(0) = -6

The second is x=8

f(8) = -6

Answer:

0 or 8

Step-by-step explanation:

The output is -6

output = y

input = x

When y = -6, x = 0 or x = 8 (as shown in the graph).

Answer:

14 feet away from the surface. -14

Step-by-step explanation:

The diver was 42 feet below the surface.

He went up 28 feet.

We have to find out how far he is from the surface.

All you would do is subtract 42 - 28.

This would be 14 feet.

This means the diver is 14 feet away from the surface.

The diver is 14 feet away from the surface.

The unitary technique involves first determining the value of a single unit, followed by the value of the necessary number of units.

For Example, Let's say Ram spends 36 Rs. for a dozen (12) bananas.

12 bananas will set you back 36 Rs. 1 banana costs 36 x 12 = 3 Rupees.

As a result, one banana costs three rupees. Let's say we need to calculate the price of 15 bananas.

This may be done as follows: 15 bananas cost 3 rupees each; 15 units cost 45 rupees.

Given:

The diver was 42 feet below the surface.

He went up 28 feet.

So, after moving 28 feet up the remaining distance would be

= 42 - 28.

= 14 feet

Hence, the diver is 14 feet away from the surface.

Learn more about Unitary Method here:

https://brainly.com/question/22056199

#SPJ2

Answer:

55

Step-by-step explanation:

m^2p - p(m - p), if m=3 and p=5.

So we plug those value into the correct space...

(3)^2 (5) - (5) (3 - 5)

9x5 - 5 x (-2)

45 - (-10)

45 + 10

55

Answer:

4262

Step-by-step explanation:

[tex]543+23+6+3690=\\500+40+3+20+3+6+3000+600+90=\\3000+600+500+90+40+20+6+3+3=\\3600+500+90+40+20+6+3+3=\\4100+90+40+20+6+3+3=\\4190+40+20+6+3+3=\\4230+20+6+3+3=\\4250+6+3+3=\\4256+3+3=\\4259+3=\\4262[/tex]

*see attachment below showing the dot plot and box plot created by Tia

Answer:

Dot plot

Step-by-step explanation:

In a dot plot, the temperature of a day is represented by 1 dot. There are 30 dots on the box plot shown in the attachment that was made by Tia.

This dot plot display makes it easier to find how many days had a temperature that is higher than 15°.

Thus, from the dot plot, we have:

2 dots representing 2 days having a temperature of 16°C each

2 days also have daily temperature of 17°C

2 days have temperature of 18°C as well, and

1 day has temperature of 19° C.

Therefore, the number of days that had a temperature above 15°C is 7 days.

Answer:

Dot Plot, Box Plot

Step-by-step explanation:

I got the other guy's answer wrong but mine is right =)

Answer:

42

Step-by-step explanation:

Answer:

x = 42

Step-by-step explanation:

Given x/6 = 7

solution:

multiply both sides by 6

x/6*6 = 7*6

x = 42

Answer:

( 0 < y < 23 / 6 ) mins

Step-by-step explanation:

Solution:-

We will define a variable ( x ) as the time it took for Jo Anne to give her speech at home.

The time taken to give her speech must always be less than 4 minutes. We can express this mathematically using an inequality as follows:

                              ( 0 < x < 4 ) minutes

Jo Anne gave her speech which was 10 seconds less than the one she practised at home. We will convert the time in seconds to minutes as follows:

                             [tex]10 s * \frac{min}{60 s} = \frac{1}{6} min[/tex]

The time taken by Jo Anne to complete her speech in English class can be represented as:

                             y = x - 1/6

Using the range of time that Jo Anne could take in delivering her speech in the class would be:

                                    0 < x < 4

                            0 - 1/6 < y < 4 - 1/6

                            -1/6 < y < 23 / 6

Since time can not be less than zero. We correct the lower limit to " 0 " as follows:

                              ( 0 < y < 23 / 6 ) mins

The possible times for her speech of her at school vary between 0 and 3:50 minutes.

Since Jo Anne needs to do a speech in her English class that can't be more than 4 minutes long, and she timed herself when she practiced last night and was within the time limit, and in class, her speech was 10 seconds less than the one that she did at home, to determine what are the possible times for her speech at school the following calculation must be performed:

Learn more in https://brainly.com/question/22690925

Answer:

[tex](\frac{2}{3},\infty)[/tex]

Step-by-step explanation:

Set builder notation is a mathematical notation used to write the elements of a set stating the conditions that the elements of the set must satisfy. A solution set is also a way of defining solutions to equations and inequalities. A solution set contains a set of all variables for which the equation is true.

The notation {x l x > two-thirds} is a set of all real numbers greater than 2/3, it can also be represented as:

[tex](\frac{2}{3},\infty)[/tex]

Answer:

c) (two-thirds, ∞)

Step-by-step explanation:

edg2020

Answer:

1. The amount of ice needed = 18 m²

2. The amount of fabric needed to manufacture the umbrella is 0.76 m²

3. The height of the cone, is 3.75 cm

4. The dimensions of the deck are;

Width = 28/3 m, breadth = 28/3 m

The area be 87.11 m²

5.   The dimensions of the optimal design for setting the storage area at the corner, we have;

Width = 10m

Breadth = 10 m

The dimensions of the optimal design for setting the storage area at the back of their building are;

Width = 7·√2 m

Breadth = 7·√2 m

Step-by-step explanation:

1. The amount of ice needed is given by the volume, V, of the pyramid given by V = 1/3 × Base area × Height

The base area = Base width × Base breadth = 3 × 5 = 15 m²

The pyramid height = 3.6 m

The volume of the pyramid = 1/3*15*3.6 = 18 m²

The amount of ice needed = 18 m²

2. The surface area of the umbrella = The surface area of a cone (without the base)

The surface area of a cone (without the base) = π×r×l

Where:

r = The radius of the cone = 0.4 m

l = The slant height = √(h² + r²)

h = The height of the cone = 0.45 m

l = √(0.45² + 0.4²) = 0.6021 m

The surface area = π×0.4×0.6021 = 0.76 m²

The surface area of a cone (without the base) = 0.76 m²

The surface area of the umbrella = 0.76 m²

The amount of fabric needed to manufacture the umbrella = The surface area of the umbrella = 0.76 m²

3. The volume, V, of the cone = 1/3×Base area, A, ×Height, h

The volume of the cone V = 150 cm³

The base area of the cone A = 120 cm²

Therefore we have;

V = 1/3×A×h

The height of the cone, h = 3×V/A = 3*150/120 = 3.75 cm

4. Given that the deck will have railings on three sides, we have;

Maximum dimension = The dimension of a square as it is the product of two  equal maximum obtainable numbers

Therefore, since the deck will have only three sides, we have that the length of each side are equal and the fourth side can accommodate any dimension of the other sides giving the maximum dimension of each side as 28/3

The dimensions of the deck are width = 28/3 m, breadth = 28/3 m

The area will then be 28/3×28/3 = 784/9 = [tex]87\frac{1}{9}[/tex] =87.11 m²

5. The optimal design for setting the storage area at the corner of their property with four sides is having the dimensions to be that of of a square with equal sides of 10 m each as follows;

Width = 10m

Breadth = 10 m

The optimal design to have the storage area at the back of their building having a fence on only three sides, is given as follows;

Storage area specified = 98 m²

For optimal use of fencing, we have optimal side size of fencing = s = Side length of a square

s² = 98 m²

Therefore, s = √98 = 7·√2 m

Which gives the width = 7·√2 m and the breadth = 7·√2 m.

Answer:

hi you can solve this sum by 4×side formula

Step-by-step explanation:

plz solve and check you equation

Answer:

40

Step-by-step explanation:

[tex] 12x = 34^2 - 26^2 \\

12x = (34+26)(34-26)\\

12x = 60\times 8\\\\

x = \frac{60\times 8}{12}\\\\

x = 5\times 8\\

x = 40[/tex]

Answer:

a) N

b) L

c) area I

d) area II

e) area VI

Step-by-step explanation:

a) the points that are 2cm from R are Q, N, M, S. Then, points that are 4cm from P are K, N, R. So, the only one point that works for both is N.

b) the points that are >2cm from R are P, K, L, T. We do not count those are exactly 2cm from R. Then, points that are 4cm from T are R, M, L. Ans is L.

c) <4cm from P, are area I and II. Then area that are >2cm from R are I, VI, and V. So, the only area that works for both is I.

d) <2cm from R, are areas II, III, and IV. Then, <4cm from P, are areas I and II. So, the only one works for both is area II.

e) >4cm from T, are areas I, II, III, VI. Then, >4cm from P, are III, IV, V, VI. Finally, >2cm from R, are areas I, VI, V. The only one that works for all three conditions is area VI.

Step-by-step explanation:

Answer:

The length of segment AC is 10 units ⇒ 1st answer

Step-by-step explanation:

Look to the attached figure

In circle A

∵ AB is a radius

∵ BC is a tangent to circle A at B

- The radius and the tangent are perpendicular to each other

    at the point of contact

∴ AB ⊥ BC at point B

∴ m∠ABC = 90°

In ΔABC

∵ m∠B = 90°

∵ AB = 8 units

∵ BC = 6 units

- By using Pythagoras Theorem (Square the hypotenuse is

    equal to the sum of the squares of the other two sides of

     the triangle)

∵ (AC)² = (AB)² + (BC)²

∴ (AC)² = (8)² +(6)²

∴ (AC)² = 64 + 36

∴ (AC)² = 100

- Take √ for both sides

∴ AC = 10 units

The length of segment AC is 10 units

follow me plzzz

Answer:A

On edge.

Step-by-step explanation:

Answer:

0.9855 or 98.55%.

Step-by-step explanation:

The probability of each individual match being flawed is p = 0.008. The probability that a matchbox will have one or fewer matches with a flaw is the same as the probability of a matchbox having exactly one or exactly zero matches with a flaw:

[tex]P(X\leq 1)=P(X=0)+P(X=1)\\P(X\leq 1)=(1-p)^{23}+23*(1-p)^{23-1}*p\\P(X\leq 1)=(1-0.008)^{23}+23*(1-0.008)^{23-1}*0.008\\P(X\leq 1)=0.8313+0.1542\\P(X\leq 1)=0.9855[/tex]

The probability  that a matchbox will have one or fewer matches with a flaw is 0.9855 or 98.55%.

Answer: Sorry dont know

Step-by-step explanation:

Answer:

-6y^4 + 4y^2 - 12.

Step-by-step explanation:

(6y^4 + 3y^2 - 7) - (12y^4 - y^2 + 5)

= 6y^4 + 3y^2 - 7 - 12y^4 + y^2 - 5

= 6y^4 - 12y^4 + 3y^2 + y^2 - 7 - 5

= -6y^4 + 4y^2 - 12.

Hope this helps!

Answer:  $57,700.00

Step-by-step explanation:

Total Gross Annual income = $70,000

a) Pension at 5% = $70,000(0.05) = $3,500

b) Employee Insurance at 2.4% = $70,000(0.024) = $1,680

c) Income Tax at 0% for $0-$11,000 = $11,000(0) = $0

   Income Tax at 8% for $11,000-$25,000 = $14,000(0.08) = $1,120

   Income Tax at 12% for $25,000-$50,000 = $25,000(0.12) = $3,000

   Income Tax at 15% for $50,000-$100,000 = $20,000(0.15) =$3,000

Total Income Tax = $7,120

Annual Net Income = Gross - Pension - Employee Insurance - Income Tax:

$70,000 - $3,500 - $1,680 - $7,120 = $57,700

Answer:

The answer is below

Step-by-step explanation:

An equilateral triangle is a triangle in which all the three sides are equal and all the angles are also equal. Each angle in an equilateral triangle is equal to 60°.

1) We cannot determine if the Two triangles are congruent because for congruence at least one side must be equal. Since we know that all the angles in both triangle ABC and DEF have the same measure of angle, we cannot finalize that they are congruent until the have at least one equal measure of length

ΔABC is not ≅ ΔDEF

2) All angles in an equilateral triangle are equal and is 60°. Therefore m∠E = 60°

3) Two triangles are said to be similar if they have the same shape and their sides have the same proportion. Since both triangle ABC and DEF have the same measure of angle, therefore they are similar. i.e

ΔABC ~ ΔDEF

An equilateral triangle is a triangle with all three sides of equal length and all angles are equal.

△ABC and △DEF are not congruent to each other.

 ∠E = 60 degree.

△ABC ≈ △DEF

Since, An equilateral triangle has three sides with equal length and three angles with equal measure.

1 . In triangle △ABC and △DEF , for congruency at least one side should be equal to apply ASA congruency rule.

ASA  congruence state that , if two angles of one triangle, and the side contained between these two angles, are respectively equal to two angles of another triangle and the side contained between them, then the two triangles will be congruent.

2. Both triangles △ABC and △DEF are equilateral.

      ∠B = ∠E =  60 degree

3. Two triangles are said to be similar if their corresponding angles are congruent and the corresponding sides are in proportion .

Similar triangles are the same shape, but not necessarily the same size.

So,  triangles △ABC and △DEF are  similar.

         △ABC ≈ △DEF

Learn more:

https://brainly.com/question/16815166

Answer:

Colin has 8 sheets left for his third class.

Step-by-step explanation:

Given that:

Total Number of pieces of papers = [tex]x[/tex]

Number of pieces of papers used for 1st class = 5 fewer than half of the pieces in the pad

Writing the equation:

[tex]\text{Number of pieces of papers used for 1st class =} \dfrac{x}{2} -5 ...... (1)[/tex]

Also, Given that number of pieces of papers used for the 2nd class are 2 more than that of papers used in the 1st class.

[tex]\text{Number of pieces of papers used for 2nd class =} \dfrac{x}{2} -5+2 = \dfrac{x}2 -3 ...... (2)[/tex]

Now, number of pieces of papers left for the third class = Total number of pieces of papers in the pad - Number of pieces of papers used in the first class - Number of pieces of papers used in the first class

[tex]\text{number of pieces of papers left for the third class = }x-(\dfrac{x}{2}-5)-(\dfrac{x}{2}-3)\\\Rightarrow x-\dfrac{x}2-\dfrac{x}2+5+3\\\Rightarrow x-x+5+3\\\Rightarrow 8[/tex]

So, the answer is:

Colin has 8 sheets left for his third class.