Answers
Answer:
The starting position of this object is 3 m.
The object is traveling at a velocity of 3 m/s
Explanation:
the graph begins at 3, and increases by 3 at each second
plz mark me brainliest. :)
Related Questions
Hello, I am in a rush because this is due tomorrow and I would really really appreciate it if you guys can help me and answer one of the boxes, (it counts for marks) I hope you guys can help:)
Answers
Answer:
1. Yes, no, no
2. No, yes, no
3. Yes, Yes, No
Explanation:
Three states of matter exist – solid, liquid, and gas. Solids have a definite shape and volume. Liquids have a definite volume, but take the shape of the container. Gases have no definite shape or volume.
Answer:
Explanation:
Ok so for the first row I believe is Yes, No, No
Second row No, yes, No
last row i dont know
I hope this helped
(p.s I have't done this in a couple of months so it might be wrong and i am so sorry if it is.)
HELP!
Which of the following fossils is an example of permineralization?
Answers
Answer:
Examples of permineralization
Most dinosaur bones are permineralized. Petrified wood: Permineralization is the first step in petrification.
Answer: you didn’t put any picture of any answers to pick but example of permineralization fossils would be dinosaur remains and wood
This molecule can be synthesized from an alkyne anion and an alkyl bromide. However, there are two ways in which this molecule can be formed. One way uses a higher molecular weight alkyne anion (Part 1) and the other uses a lower molecular weight anion (Part 2). Draw the two versions in the boxes below. Omit spectator ions.
For Part 1: Draw the reactants (i.e., alkyne anion and alkyl bromide) needed for the pathway that uses a higher molecular weight alkyne anion:
For Part 2: Draw the reactants (i.e., alkyne anion and alkyl bromide) needed for the pathway that uses a lower molecular weight alkyne anion:
Answers
Answer:
See explanation below
Explanation:
First of all, we need to know the molecule that need to be synthesized. In the first picture attached, we have the molecule.
Now, according to that, the molecule can be formed in two ways. Both ways are rather different but we have one thing in common in both ways, and it's the fact that both ways requires the reaction with an alkyne. In one way, with the higher MW and the other with the lowest.
For the first way, when we need to use the higher MW, all we need to do is to put the triple bond in the highest molecule, in this case, a molecule that include the benzene ring, and the other reactant will be the alkyl bromide. You can see the picture of this product below, (Picture 2).
For the second way, the triple bond should be located in the lowest MW, in this case an ethyl group, instead of the benzene ring, and the molecule with the benzene ring would have the bromide. In both cases we will have the same product. See picture 2 for this.
Hope this helps
One mole (mol) of ethanol (C2H60) has a mass of 46.0684 g.
What is the mass of 2.1 mol of ethanol in kilograms?
Need to see how the calculation was done
Answers
Answer:
0.0967kg
Explanation:
1 mol = 46.0684 g
2.1 mol = 46.0684 × 2.1 = 96.74364 g
1000 g = 1 kg
96.74364 g = 96.74364/1000 = 0.0967kg
what is the major use of carbon monoxide
Answers
Answer:
Carbon monoxide is a very important industrial compound. In the form of producer gas or water gas.
hope ths help and if you want more information go to this website: science.jrank.org
What is the volume (in mL) of glacial acetic acid (17.4 M) that would have to be added to 500 mL of a solution of 0.20 M sodium acetate in order to achieve a pH of 5.0
Answers
Answer:
3.16mL of glacial acetic acid must be added
Explanation:
The mixture of acetic acid with sodium acetate produce a buffer. The buffer follows the H-H equation:
pH = pKa + log [A⁻] / [HA]
Where pH is the pH of the buffer: 5.0
pKa is pKa of the buffer = 4.74
[A⁻] could be taken as moles of acetate ion = 0.500L * (0.20mol/L) = 0.100mol
And [HA] are moles of acetic acid.
Replacing:
5.0 = 4.74 + log [0.100mol] / [HA]
0.26 = log [0.100mol] / [HA]
1.8197 = [0.100mol] / [HA]
[HA] = 0.100mol / 1.8197
[HA] = 0.05495 moles of acetic acid
As the glacial acetic acid is 17.4M, the volume we must add to prepare the buffer is:
0.05495 mol * (1L / 17.4mol) = 3.16x10⁻³L =
3.16mL of glacial acetic acid must be added
The scientific method
A.is a recipe for doing science
B.will always give the right answer
C.is a systematic approach to the study of phenomena
D.involves preconceived ideas
Answers
Answer:
A. Is a recipe for soing science
Explanation:
A scientific method is a procedure for conducting science experiments, its almost like a recipe for a science experiment.
The surface temperature of a star can be estimated based on the stars
Answers
Which would be another way to make the ice melt faster
Answers
Answer:
d because ur heating the ice and causing friction
2. How do you find the density of a substance given its mass and volume? Write the equation.
Density =
Answers
Answer:Density, mass of a unit volume of a material substance. The formula for density is d = M/V, where d is density, M is mass, and V is volume. Density is commonly expressed in units of grams per cubic centimetre.
Explanation:
Calculate the change in temperature of a 650. g sample of water that loses 5480. J of energy
Answers
Answer:
2
Explanation:
1) the formula of the energy is:
E=cm*Δt, where E - the value of the energy (5480 J.), c - the specific heat capacity (4200 J/(kg*C)), Δt - the difference between initial temperature and the final one (it is unknown);
2) if to perform the substitution of the values 'E', 'm' and 'c' into the formula above, then
5480=4200*0.65*Δt;
3) to calculate Δt:
Δt=5480/4200/0.65≈2 (°C).
note: the initial temperature is higher than the final.
. If Kc is the equilibrium constant for a forward reaction, 2 A⇌ B, what is Kc' for the reaction 4 A⇌ 2B?
Answers
Answer:
(Kc)^2
Explanation:
For this reaction 4 A⇌ 2B Kc is (Kc)∧².
What is equilibrium constant?The equilibrium constant is the value of the reaction quotient that is calculated from the expression for chemical equilibrium. A thermodynamic equilibrium constant, denoted by , is defined to be the value of the reaction quotient Qt when forward and reverse reactions occur at the same rate. At chemical equilibrium, the chemical composition of the mixture does not change with time and the Gibbs free energy change. Stability constants, formation constants, binding constants, association constants and dissociation constants are all types of equilibrium constants.
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Look at this data and calculate the mean, median, mode, and range.
5, 9, 10, 15, 14, 9, 14, 12, 20, 14, 20
mode
range
median
mean (to the nearest whole number)
Answers
Answer:
the median is 14 the range is 15 the mode is 14 and the mean is 12.7
Explanation:
for the median you put all numbers is order but least to greatest and figure out the middle number for range you take the smallest and the biggest number and subtract them for mode you use the most repeated number and for the mean you add all the numbers and divide by the total of numbers I hope this helped
Titanium dioxide (TiO2) is used extensively as a white pigment. It is produced from an ore that contains ilmenite (FeTiO3) and ferric oxide (Fe2O3). The ore is digested with an aqueous sulfuric acid solution to produce an aqueous solution of titanyl sulfate [(TiO)SO4 ] and ferrous sulfate (FeSO4 ). Water is added to hydrolyze the titanyl sulfate to H2TiO3, which precipitates, and H2SO4. The precipitate is then roasted, driving off water and leaving a residue of pure titanium dioxide. (Several steps to remove iron from the intermediate solutions as iron sulfate have been omitted from this description.) Suppose an ore containing 24.3% Ti by mass is digested with an 80% H2SO4 solution, supplied in 50% excess of the amount needed to convert all the ilmenite to titanyl sulfate and all the ferric oxide to ferric sulfate [Fe2 (SO4 )3 ]. Further suppose that 89% of the ilmenite actually decomposes. Calculate the masses (kg) of ore and 80% sulfuric acid solution that must be fed to produce 1000 kg of pure TiO2.
Answers
Answer:
2928kg of ore are required.
2585kg of the 80% H₂SO₄ solution are required.
Explanation:
To solve this question we need first to find the moles of titanium in 1000kg of TiO₂. Keeping in mind the 89% of descomposition we can find the mass of the ore and the mass of the 80% sulfuric acid required:
Moles TiO₂ -Molar mass: 79.866g/mol-:
1x10⁶g * (1mol / 79.866g) = 12521 moles Titanium
In mass -Molar mass Ti: 47.867g/mol-:
12521 moles Titanium * (47.867g / mol) = 599341.4g of Ti.
As the ore contains 24.3% of Ti:
599341.4g of Ti = 599.34kg Ti * (100 / 24.3) = 2606kg ore
As the descomposition is just of 89%:
2606kg ore * (100 / 89) =
2928kg of ore are requiredMass 80% sulfuric acid:
12521 moles Titanium = 12521 moles H₂SO₄ * (100/89) = 14068.5 moles of H₂SO₄ are required.
In an excess of 50% =
14068.5 moles of H₂SO₄ are required * 1.5 = 21102.8 moles of H₂SO₄.
The mass is:
21102.8 moles of H₂SO₄ * (98g / mol) = 2068075g = 2068kg of sulfuric acid
That is in the 80%:
2068kg of sulfuric acid * (100/ 80) =
2585kg of the 80% H₂SO₄ solution are required2771.53 kg of titanium ore and 2584.63 kg of 80% H₂SO₄ are required to produce 1000 kg of pure TiO2.
The moles of titanium in 1000 kg of TiO₂ is first determined:
Molar mass of TiO₂ = 79.88 g/molMolar mass of Ti = 47.88 g/molmoles of TiO₂ = mass of TiO₂/molar mass of TiO₂mass of TiO₂ = 1000 kg = 1 * 10⁶g
moles of TiO₂ = 1 * 10⁶g/79.88 g/mol
moles of TiO₂ = 12518.77 moles
1 mole of TiO₂ produces 1 mole of titanium
12518.77 moles TiO₂ produces 12518.77 moles of titanium
mass of titanium = number of moles * molar mass
mass of titanium = 12518.77 moles * 47.88 g/mol
mass of titanium = 599398.70 g
Since the percentage mass of titanium in the ore is 24.3%
mass of ore = 599399.18 g * 100/24.3
mass of ore = 2466661.31 g
mass of ore in kg = 2466.66 kg
Since only 89% of ore decomposed, mass of ore required = 2466.66 kg *100/89
mass of ore required = 2771.52
Mass 80% sulfuric acid required is calculated as follows:
Molar mass of H₂SO₄ = 98.00 g/mol1 mole of titanium requires 1 mole of H₂SO₄Therefore, 12521 moles Titanium = 12521 moles H₂SO₄
Since only 89% of the ore decomposes;
moles of H₂SO₄ required = 12518.77 moles * 100/89
moles of H₂SO₄ required = 14066.03 moles
The H₂SO₄ solution is supplied in excess of 50%moles of H₂SO₄ supplied = 14066.03 moles * 150/100
moles of H₂SO₄ supplied = 21099. 04 moles
mass of H₂SO₄ supplied = number of moles * molar massmass of H₂SO₄ supplied = 21099. 04 moles * 98 g/mol
mass of H₂SO₄ supplied = 2067702 g
Since the solution is only 80% H₂SO₄;mass of 80% H₂SO₄ required = 2067702 g * 100/80
mass of 80% H₂SO₄ required = 2584627.5 g
mass of 80% H₂SO₄ required in kg = 2584.63 kg
Therefore, 2771.53 kg of ore and 2584.63 kg of 80% H₂SO₄ are required to produce 1000 kg of pure TiO2.
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Name each of the following species for the following acid-base reactions. (The equilibrium lies to the right in each case, i.e., the product side is favored. If the species is an ion, include the word "ion" in the name. Use systematic names such as "methanol" instead of archaic names like "methyl alcohol" or "wood alcohol".)
(a) H3O+ (hydronium ion) + CH3O- (methoxide ion) <--> *reverse reaction arrow*
acid:?
base:?
conjugate acid:?
conjugate base:?
(b) CH3CH2O- (ethoxide ion) + HCl (hydrogen chloride) <--> *reverse reaction arrow*
acid:?
base:?
conjugate acid:?
conjugate base:?
(c) NH2- (amide ion) + CH3OH (methanol) <--> *reverse reaction arrow*
acid:?
base:?
conjugate acid:?
conjugate base:?
Answers
Answer: a) [tex]H_3O^++CH_3O^-\rightleftharpoons CH_3OH+H_2O[/tex]
acid : hydronium ion
base : methoxide ion
conjugate acid : methanol
conjugate base: water
b) [tex]CH_3CH_2O^-+HCl\rightleftharpoons CH_3CH_2OH+Cl^-[/tex]
acid : hydrogen chloride
base : ethoxide ion
conjugate acid : ethanol
conjugate base: chloride ion
c) [tex]NH_2^-+CH_3OH\rightleftharpoons NH_3+CH_3O^-[/tex]
acid : methanol
base : amide ion
conjugate acid : ammonia
conjugate base: methoxide ion
Explanation:
According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.
The species accepting a proton is considered as a base and after accepting a proton, it forms a conjugate acid.
The species losing a proton is considered as an acid and after loosing a proton, it forms a conjugate base
For the given chemical equation:
a) [tex]H_3O^++CH_3O^-\rightleftharpoons CH_3OH+H_2O[/tex]
acid : hydronium ion
base : methoxide ion
conjugate acid : methanol
conjugate base: water
b) [tex]CH_3CH_2O^-+HCl\rightleftharpoons CH_3CH_2OH+Cl^-[/tex]
acid : hydrogen chloride
base : ethoxide ion
conjugate acid : ethanol
conjugate base: chloride ion
c) [tex]NH_2^-+CH_3OH\rightleftharpoons NH_3+CH_3O^-[/tex]
acid : methanol
base : amide ion
conjugate acid : ammonia
conjugate base: methoxide ion
.
What is the value for the rate of constant, k(with units)?
Answers
Answer:
b
Explanation:
which atom has the largest number of neutrons
Answers
Sodium benzoate, the sodium salt of benzoic acid, is used as a food preservative. A sample containing solid sodium benzoate mixed with sodium chloride is dissolved in 50.0 mL of 0.500 M HCl, giving an acidic solution (ben- zoic acid mixed with HCl). This mixture is then titrated with 0.393 M NaOH. After the addition of 46.50 mL of the NaOH solution, the pH is found to be 8.2. At this point, the addition of one more drop (0.02 mL) of NaOH raises the pH to 9.3. Calculate the mass of sodium benzo- ate (NaC6H5COO) in the original sample. (Hint: At the equivalence point, the total number of moles of acid [here HCl] equals the total number of moles of base [here, both NaOH and NaC6H5COO].)
Answers
Answer:
0.966g of sodium benzoate are in the original sample
Explanation:
The sodium benzoate, B⁻, reacts with HCl as follows:
B⁻ + HCl → BH + Cl⁻
Where 1 mole of benzoate reacts per mole of HCl
The HCl is added in excess. We can find the HCl that reacts with sodium benzoate using the NaOH that reacts with HCl.
When 1 drop change the pH in 1,1 units, this point is the equivalence point. Thus, moles in excess of HCl = Moles of NaOH added are:
0.04650L * (0.393mol / L) = 0.0183 moles NaOH = Moles HCl in excess
Moles HCl added:
0.0500L * (0.500mol/L) = 0.0250 moles HCl added
Moles HCl that react = Moles Sodium benzoate:
0.0250 moles HCl - 0.0183 moles HCl = 0.0067 moles HCl = Moles Sodium benzoate
Mass Sodium benzoate -Molar mass: 144.11g/mol-:
0.0067 moles Sodium benzoate * (144.11g/mol) =
0.966g of sodium benzoate are in the original sampleDraw the Zaitsev product formed when 2,3‑dimethylpentan‑3‑ol undergoes an E1 dehydration. The starting material is a chiral carbon with an in plane bond pointing up to methyl and an in plane bond to O H pointing to the lower right. There is a wedged bond to isopropyl pointing to the lower left and a dashed bond to ethyl pointing to the left. This reacts with H 3 P O 4 in an E 1 reaction to give the Zaitsev product.
Answers
Answer:
See explanation
Explanation:
Dehydration of an alcohol by E1 mechanism occurs in two steps. The first step is the is the protonation of the -OH group in the alcohol followed by the elimination of water, a good leaving group.
In the case of 2,3‑dimethylpentan‑3‑ol, the carbocation formed undergoes rearrangement followed by loss of a hydrogen atom. This now yields the product as shown in the image attached.
Note that, the Zaitsev's product is the most substituted product and is most stable hence it is the most favored product.
Find the normality of 0.321 g sodium carbonate in a 250 mL solution.
Answers
Answer:
the normality of the given solution is 0.0755 N
Explanation:
The computation of the normality of the given solution is shown below:
Here we have to realize the two sodiums ions per carbonate ion i.e.
N = 0.321g Na_2CO_3 × (1mol ÷ 105.99g)×(2eq ÷ 1mol)
= 0.1886eq ÷ 0.2500L
= 0.0755 N
Hence, the normality of the given solution is 0.0755 N
How many moles of Fe(OH)3 are produced when 85.0 L of iron(3) sulfate at a concentration of 0.600 mol/L reacts with excess NaOH
Answers
Answer:
e = Mc hammer.
Explanation:
can someone help me with number 2
Answers
Answer: Goldfish. :p
Explanation:
A white light shined onto a green brick bricks science
Answers
Answer:what’s the question?
Explanation:
Define: Atomic Mass, Mass Number, Isotope
Answers
Answer:
Explanation:
the mass of an atom of a chemical element expressed in atomic mass units. It is approximately equivalent to the number of protons and neutrons in the atom (the mass number) or to the average number allowing for the relative abundances of different isotopes.
the total number of protons and neutrons in a nucleus.
to write the symbol for an isotope, place the atomic number as a subscript and the mass number (protons plus neutrons) as a superscript to the left of the atomic symbol
Part A
Which substance is the limiting reactant when 14 g of sulfur reacts with 24 g of oxygen and 28 g
of potassium hydroxide according to the following chemical equation?
2 S(s)+ 3 O2(g) + 4 KOH(q) — 2 K2SO4(aq) + 2 H20(1)
O O2(g)
S(s)
K2SO4
O KOH(aq)
O None of these substances is the limiting reactant.
Yery
Submit
Request Answer
Answers
Answer:
KOH is limiting reactant
Explanation:
To solve this question, we need to convert the mass of each reactant to moles. Then, using the balanced reaction, we can find the limiting reactant:
Moles S -Molar mass: 32g/mol-:
14g S * (1mol / 32g) = 0.44mol
Moles O₂ -Molar mass: 32g/mol-:
24g O₂ * (1mol / 32g) = 0.75mol
Moles KOH -Molar mass: 56g/mol-:
28g KOH * (1mol / 56g) = 0.5mol
For a complete reaction of the KOH are required:
0.5mol KOH * (2mol S / 4mol KOH) = 0.25mol S
0.5mol KOH * (3mol O₂ / 4mol KOH) = 0.38mol O₂
As there are 0.44 moles of S and 0.38moles of oxygen,
KOH is limiting reactantIf 4.50 moles of HNO3 are used, how many moles of copper (II) nitrate are produced?
Answers
Answer:
2.25 moles of Cu(NO₃)₂.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
Cu + 2HNO₃ —> Cu(NO₃)₂ + H₂
From the balanced equation above,
2 moles of HNO₃ reacted to produce 1 mole of Cu(NO₃)₂.
Finally, we shall determine the number of mole of Cu(NO₃)₂ produced by the reaction of 4.5 moles of HNO₃. This can be obtained as follow:
From the balanced equation above,
2 moles of HNO₃ reacted to produce 1 mole of Cu(NO₃)₂.
Therefore, 4.5 moles of HNO₃ will react to produce = 2.25 moles of Cu(NO₃)₂.
Thus, 2.25 moles of Cu(NO₃)₂ were obtained from the reaction.
What mass of sodium chloride is produced when 5.4 g of iron
chloride are used?
Answers
Answer:
5.0 g
Explanation:
Step 1: Write the balanced equation
FeCl₂ + 2 Na⁺ = 2 NaCl + Fe²⁺
Step 2: Calculate the moles corresponding to 5.4 g of FeCl₂
The molar mass of FeCl₂ is 126.75 g/mol.
5.4 g × 1 mol/126.75 g = 0.043 mol
Step 3: Calculate the moles of NaCl produced from 0.043 moles of FeCl₂
The molar ratio of FeCl₂ to NaCl is 1:2. The moles of NaCl produced are 2/1 × 0.043 mol = 0.086 mol.
Step 4: Calculate the mass corresponding to 0.086 moles of NaCl
The molar mass of NaCl is 58.44 g/mol.
0.086 mol × 58.44 g/mol = 5.0 g
hydroxide, express your answer in a chemical formula
Answers
Answer:
OH⁻
Explanation:
Hydroxide is represented as OH⁻, since it is specifically the oxygen atomic that is specifically connected to a central metal ion of Fe, never hydrogen, which means that it could be represented as OH⁻.
OH⁻ is the chemical formula for hydroxide, since it is specifically the oxygen atomic that is specifically connected to a central metal ion of Fe, never hydrogen, which means that it could be represented as OH⁻.
A chemical formula is a way to describe the chemical ratios of the atoms that make up a specific chemical compound or molecule in chemistry. Chemical element numbers, symbols, and on occasion other symbols, including parentheses, dashes, brackets, commas, and plus (+) and minus () signs, are used to represent the chemical elements. Which may also include subscripts or superscripts. Since a chemical formula inherently wordless, it cannot be considered a chemical name. A chemical formula does not equal a complete chemical structural formula, despite the fact that it may suggest certain basic chemical structures. Hydroxide is represented as OH⁻.
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Sofia goes on a hike on a trail that is 10 km long. She starts at 2:00pm and ends at
5:00pm. The end of the trail is 300m north of the beginning of the trail. What is
Sofia's average velocity?
(Velocity= displacement/time)
100 m/hr S
30 m/hrs
0.01 m/hrs
3.3 m/hr s
Answers
Answer:
100 m/hr S
Explanation:
Use formula Velocity = displacement/time
V=? d=300 t=3
V=300/3
V=100
Hope this helps!! :D
Sofia's average velocity is 100 m/hrs using the velocity formula which is displacement/time.
What is average velocity?Speed of an object refers to the change in position of that object concerning time. Velocity on the other hand is nothing, but the speed defined concerning the direction in which an object travels.
Average velocity according to the definition is the ratio of the displacement from point a to point b of an object to the time it takes to make that displacement from point a to point b. It may be noted that we use the term movement instead of distance to emphasise the direction.
Velocity is a vector quantity and average velocity can be found by dividing displacement by time. It is found out as, 300/3=100 m/hrs.
Thus, Sofia's average velocity is 100 m/hrs using the velocity formula which is displacement/time.
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Organisms that eat other organisms or dead organic matter are known as ___________________.
Group of answer choices
producers
autotrophs
heterotrophs
eukaryotes
Answers
Answer:
the answer is heterotrophs