Polygon JKLM is drawn with vertices J(−2, −5), K(−4, 0), L(−1, 2), M (0, −1). Determine the image coordinates of K′ if the preimage is translated 6 units up.
A. K′(−10, 0)
B. K′(−4, −6)
C. K′(−4, 6)
D. K′(2, 0)

Answer:

E. 10

Step-by-step explanation:

To solve the equation x + 50 = 60, we need to isolate x on one side of the equation. Subtracting 50 from both sides, we get:

x + 50 - 50 = 60 - 50

x = 10

Therefore, the solution to the equation is x = 10. Checking the answer choices, we see that E. 10 is the only number that belongs to the solution set. Therefore, the answer is:

E. 10

Answer:

The numerical values of the circumference and area are equal

Step-by-step explanation:

Circumference: 12.57

Area: 12.57

12.57=12.57

Hope this helps! :)

Answer:

10 outcome is the answer

A deposit of $2000 earning 4.2% simple interest for 3 years will have a balance of $2252. The estimated balance rounded to the nearest whole number is $2252.

To calculate the balance in the account after 3 years, we can use the formula

balance = principal x (1 + interest rate x time)

Plugging in the values, we get

balance = 2000 x (1 + 0.042 x 3)

balance = 2000 x (1 + 0.126)

balance = 2000 x 1.126

balance = 2252

Therefore, the balance in the account after 3 years is $2252.

As for the estimate, since the interest is simple, we can approximate it by multiplying the interest rate by the number of years and adding it to the principal. So, the estimate would be

estimate = principal x (1 + interest rate x time)

estimate = 2000 x (1 + 0.042 x 3)

estimate = 2000 x (1 + 0.126)

estimate = 2000 x 1.126

estimate = 2252

Rounding to the nearest whole number, the estimate is also $2252.

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the volume of the smallest region E enclosed by the cone and sphere is (64/3)π(1 - no⁴/5), where no is the constant in the equation of the cone Z = - no Ix² + y².

To compute the volume of the smallest region E enclosed by the cone and sphere, we will use spherical coordinates. In spherical coordinates, a point in 3D space is represented by three values: radius (r), polar angle (θ), and azimuthal angle (φ).

First, we need to find the intersection of the cone and sphere. Substituting Z = - no Ix² + y² into the equation of the sphere, we get x² + y² + (- no Ix² + y²)² = 32. Simplifying this equation gives us x² + y² + no²x⁴ - 2no²x²y² + y⁴ = 32. We can rewrite this equation in terms of r, θ, and φ as follows:

r²sin²θ + no²r⁴cos⁴θsin²θ - 2no²r⁴cos²θsin²θ + no²r⁴cos²θsin⁴θ = 32

Simplifying this equation gives us:

r = √(32/(sin²θ + no²cos²θsin²θ))

Next, we need to find the limits of integration for r, θ, and φ. Since the region E is enclosed by the sphere x² + y² + z² = 32, we know that the maximum value of r is 4√2. The minimum value of r is zero. The limits of integration for θ are 0 to π/2, since the cone is pointing downwards in the negative z direction. The limits of integration for φ are 0 to 2π, since the region E is symmetric about the z-axis.

The volume of the region E can be computed using the following integral:

Vol(E) = ∫∫∫ r²sinθ dr dθ dφ

Integrating over the limits of integration for r, θ, and φ, we get:

Vol(E) = ∫₀^(2π) ∫₀^(π/2) ∫₀^(4√2) r²sinθ dr dθ dφ

Evaluating this integral gives us:

Vol(E) = (64/3)π(1 - no⁴/5)

Therefore, the volume of the smallest region E enclosed by the cone and sphere is (64/3)π(1 - no⁴/5), where no is the constant in the equation of the cone Z = - no Ix² + y².
Hi! To compute the volume of the region E enclosed by the cone Z = -√(x² + y²) and the sphere x² + y² + z² = 32 using spherical coordinates, we can set up the triple integral as follows:

Vol(E) = ∫∫∫ ρ² sin(φ) dρ dθ dφ

In spherical coordinates, the cone Z = -√(x² + y²) becomes φ = 3π/4, and the sphere x² + y² + z² = 32 becomes ρ = 4.

The limits of integration are:
- ρ: 0 to 4
- θ: 0 to 2π
- φ: π/2 to 3π/4

So, the triple integral can be written as:

Vol(E) = ∫(ρ=0 to 4) ∫(θ=0 to 2π) ∫(φ=π/2 to 3π/4) ρ² sin(φ) dρ dθ dφ

By calculating this triple integral, we can find the volume of the region E.

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Answer:  x=20  y=43

Step-by-step explanation:

That little symbol in <1 means that the angle is a right angle, which is = to 90°  so

<1 = 90°

133-y = 90        solve for y by subtracting 133 from both sides

-y = -43             divide by -1 on both sides

y=43

Because all 3 angles make a line, which is 180, and you know <1 = 90   then <2+<3=90 as well.

<2+<3=90

22 + x + 48 =90     simplify

70 + x =90              subtract 70 from both sides

x=20

The rate of appreciation of the classic car is 18% per year.

An exponent is a mathematical operation that indicates how many times a number or expression is multiplied by itself. It is represented by a superscript number that is written to the right and above the base number or expression. The exponent tells us how many times the base is multiplied by itself.

The value V of the classic car appreciates exponentially, and it is represented by the formula:

V = 32,000[tex]1.18^{2}[/tex]

The term [tex]1.18^{t}[/tex] represents the factor by which the value of the car increases each year. If we calculate this factor for one year (t=1), we get:

(1.18)¹= 1.18

This means that the value of the car increases by 18% in the first year. Similarly, if we calculate the factor for two years (t=2), we get:

(1.18)² = 1.39

This means that the value of the car increases by 39% in the first two years (18% in the first year and an additional 21% in the second year).

Therefore, the rate of appreciation of the classic car is 18% per year.

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The weight of the contents in the container is approximately 873 pounds.

A shipping container is in the shape of a right rectangular prism with a length of 7 feet, a width of 14 feet, and a height of 13.5 feet.

To find the volume of the container, we multiply the dimensions: 7 ft × 14 ft × 13.5 ft = 1,323 cubic feet. The container is completely filled with contents that weigh, on average, 0.66 pound per cubic foot.

To find the weight of the contents in the container, we multiply the volume by the average weight: 1,323 ft³ × 0.66 lb/ft³ ≈ 873.18 pounds.

Rounded to the nearest pound, the weight of the contents in the container is approximately 873 pounds.

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Answer:

-12+3(-11)-40-10

Step-by-step explanation:

Answer:

Step-by-step explanation:

-12+12-45-40+1

0-85+1

-84

The sets of side lengths that could form a right triangle are 36-48-60 (option b) and 14-48-50 (option d).

To determine which of these sets of side lengths could form a right triangle, we will use the Pythagorean theorem (a² + b² = c²), where a and b are the shorter sides and c is the hypotenuse. Let's evaluate each option:

a) 4-7-10
Applying the Pythagorean theorem: 4² + 7² = 16 + 49 = 65, which is not equal to 10² (100). So, this set does not form a right triangle.

b) 36-48-60
Applying the Pythagorean theorem: 36² + 48² = 1296 + 2304 = 3600, which is equal to 60² (3600). So, this set does form a right triangle.

c) 6-10-14
Applying the Pythagorean theorem: 6² + 10² = 36 + 100 = 136, which is not equal to 14² (196). So, this set does not form a right triangle.

d) 14-48-50
Applying the Pythagorean theorem: 14² + 48² = 196 + 2304 = 2500, which is equal to 50² (2500). So, this set does form a right triangle.

In conclusion, the sets of side lengths that could form a right triangle are 36-48-60 (option b) and 14-48-50 (option d).

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The equation that could represent each of the graphed polynomial function include the following:

First graph: y = x(x + 2)(x - 3)

Second graph: y = x⁴ - 5x² + 4

In Mathematics and Geometry, a polynomial graph simply refers to a type of graph that touches the x-axis at zeros, roots, solutions, x-intercepts, and factors with even multiplicities.

Generally speaking, the zero of a polynomial function simply refers to a point where it crosses or cuts the x-axis of a graph.

By critically observing the graph of the polynomial function shown in the image attached above, we can logically deduce that the first graph has a zero of multiplicity 1 at x = 2 and zero of multiplicity 1 at x = -3.

Similarly, we can logically deduce that the second graph has a zero of multiplicity 2 at x = 2 and zero of multiplicity 2 at x = -2.

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The cost of the stock, including the broker's fee, is $50,454.30.

The cost of the stock can be found by multiplying the number of shares purchased by the price per share. In this case, the investor purchased 500 shares of Exxon-mobil stock at $98.93 per share, so the cost of the stock can be calculated as follows:

Cost of stock = Number of shares × Price per share

Cost of stock = 500 × $98.93

Cost of stock = $49,465

However, the broker charges 2% of the cost of the stock, which is an additional fee that needs to be added to the total cost. To find the broker's fee, we can simply multiply the cost of the stock by 2%:

Broker's fee = 2% × Cost of stock

Broker's fee = 2% × $49,465

Broker's fee = $989.30

Therefore, the total cost of the stock, including the broker's fee, is:

Total cost of stock = Cost of stock + Broker's fee

Total cost of stock = $49,465 + $989.30

Total cost of stock = $50,454.30

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Marcus is incorrect. The percentage increase in the time he spent doing homework this week compared to last week is 10%.

To determine if Marcus is correct, we need to calculate the percentage increase in the time he spent doing homework this week compared to last week.

First, we calculate the difference in hours:

11 hours - 10 hours = 1 hour

Then, we calculate the percentage increase:

(1 hour / 10 hours) x 100% = 10%

Therefore, Marcus is incorrect. The percentage increase in the time he spent doing homework this week compared to last week is 10%, not 110%.

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The surface area of octagonal pyramid with height of 12 and a side length of 4.24 is 281.477 unit²

Height of octagonal pyramid = 12

Side length of octagonal pyramid = 4.14

The surface area of octagonal pyramid is  

SA = 2s²( 1 + √2) + 4sh

Here, s is side length of the octagonal pyramid = 4.14

h is height of the octagonal pyramid = 12

putting the values in the equation we get

SA = 2 × 4.14 ( 1 + √2 ) + 4 × 4.14 × 12

SA = 82.757 + 198.72

SA = 281.477

The surface area of octagonal pyramid is 281.477

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With the given pay increase Daniel will earn a total of $185,141.90 in 4 years .

To find out how much Daniel will earn in 4 years with a starting salary of $42,000 and a 6.5% pay increase every year, follow these steps:

1. Calculate the annual salary for each year by applying the percentage increase.
2. Sum up the salaries for all 4 years.

Step 1: Calculate the annual salary for each year
Year 1: $42,000
Year 2: $42,000 * (1 + 6.5%) = $42,000 * 1.065 = $44,730
Year 3: $44,730 * (1 + 6.5%) = $44,730 * 1.065 = $47,656.95
Year 4: $47,656.95 * (1 + 6.5%) = $47,656.95 * 1.065 = $50,754.95

Step 2: Sum up the salaries for all 4 years
Total earnings = $42,000 + $44,730 + $47,656.95 + $50,754.95 = $185,141.90

Daniel will earn a total of $185,141.90 in 4 years with the given pay increase.

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The simplified form of the expression 3(w+11) / 6w  is w + 11 / 2w .

Simplifying expressions mean rewriting the same algebraic expression with no like terms and in a compact manner.

In other words, we have to expand any brackets, next multiply or divide any terms and use the laws of indices if necessary, then collect like terms by adding or subtracting and finally rewrite the expression.

Therefore, let's simplify the expression:

3(w+11) / 6w

Hence, let's divide both the numerator and denominator by 3

Therefore,

3(w+11) / 6w =  w + 11 / 2w

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Minimum

-11

Main concepts:

Concept 1: Identify the type of equation

Concept 2: Identify the concavity (opens up/down)

Concept 3: Finding a vertex of a parabola

Concept 1: Identify the type of equation

First, observe that the equation is a polynomial.  This is a type of equation where there may be multiple terms containing an x, where each term with an x is raised to a whole number power, and may be multiplied by a real number.  Additionally, there may be a constant term added (or subtracted).

For our equation, [tex]y=3x^2-12x+1[/tex], the first two terms contain an x, each raised to a whole number power, and are multiplied by a number.  Additionally, there is a constant added to the end of the equation.  Therefore, this is a polynomial.

The largest power of x in a polynomial is called the "degree" of the polynomial.  Since the largest power of x is 2, this is called a second degree polynomial.  Another common name for a second degree polynomial is a quadratic equation.

This quadratic equation is already in what is known as "Standard form" [tex]y=ax^2+bx+c[/tex]

Concept 2: Identify the concavity (opens up/down)

For quadratic equations, the graph of the equation will be a sort of "U" shape" called a parabola.  The parabola either opens up or down depending on the "leading coefficient" in the quadratic equation.

The "leading coefficient" of any polynomial is the constant number that is multiplied to x in the term with the highest power.  In this case, the leading coefficient is 3.

A parabola opens up or down in correspondence with the sign of the leading coefficient.  If the leading coefficient is positive, the parabola opens upward.  If the leading coefficient is negative, the parabola opens downward.

Since the leading coefficient is 3, the parabola for our example opens upward.  The branches of the "U" will go upward forever, without a maximum.  However, the bottom of the "U" will have a minimum value.  We are assigned to find this minimum value (how low it goes).

Concept 3: Finding a vertex of a parabola

To find the vertex of a parabola, with an equation in standard form, there are a few methods, but the most straightforward is to use the vertex formula:

[tex]h=\dfrac{-b}{2a}[/tex]

Where "h" is the x-coordinate of the vertex, and "a" and "b" are the coefficients from the quadratic equation: [tex]y=ax^2+bx+c[/tex]

[tex]h=\dfrac{-(-12)}{2(3)}[/tex]

[tex]h=\dfrac{12}{6}[/tex]

[tex]h=2[/tex]

So, the parabola will have a vertex with an x-coordinate of "2", meaning that the lowest point will be at a position that is 2 units to the right of the origin... however, we still don't know how high that minimum is.  Fortunately, the equation [tex]y=3x^2-12x+1[/tex] itself gives the relationship between any x-value and the y-value that is associated with it.

[tex]y=3x^2-12x+1[/tex]

[tex]y=3(2)^2-12(2)+1[/tex]

[tex]y=3*4+(-12)*2+1[/tex]

[tex]y=12+-24+1[/tex]

[tex]y=-11[/tex]

So, the vertex of the parabola is (2,-11).

The height of the vertex is -11, so the value of the minimum is -11.

Side note: "What is the value of the minimum" is a different question that "where is the minimum at".  The minimum is at 2.  The actual value of the minimum is -11.

Answer:

Step-by-step explanation:

where are the streets

The number of 6-card hands  in which at least one card from each suit is equal to 8,184,220.

Total number of 6-card hands that can be formed from a deck of 60 cards is,

Using combination formula,

C(60, 6) = 50,063,860

Now, subtract the number of 6-card hands that do not contain at least one card from each suit.

There are 5 ways to choose the suit that will be missing from the hand.

Once this suit is chosen, there are 48 cards remaining in the other suits.

Choose 6 cards from this set, so the number of 6-card hands that do not contain any cards from the chosen suit is,

C(48, 6) = 12,271,512

Overcounted the number of hands that are missing more than one suit.

There are C(5, 2) ways to choose 2 suits that will be missing from the hand.

Once these suits are chosen, there are 36 cards remaining in the other 3 suits.

Choose 6 cards from this set, so the number of 6-card hands that do not contain any cards from the chosen suits is,

C(36, 6) = 1,947,792

We cannot have a 6-card hand that is missing more than 2 suits.

3 suits with no cards in the hand, which is not allowed.

Number of 6-card hands that have at least one card from each suit is,

C(60, 6) - 5×C(48, 6) + C(5, 2)×C(36, 6)

=50,063,860 - 5×  12,271,512 + 10 × 1,947,792

= 50,063,860 -61,357,560 + 19,477,920

= 8,184,220

Therefore, there are 8,184,220 of 6-card hands that have at least one card from each suit.

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Note that the light is about 9.17 x 10³ times faster than sound. See the explanation below.

To arrive a the above, we only need to simplify Jakes observation as follows

[tex]\frac{1.1 * 10^{9} km/h }{1.2 * 10^{3}km/h }[/tex]

dividing the coefficients

1.1/1.2 = 0.91666666666

0.91666666666 x 10 ⁹⁻³

= 9.1666667 x 10 ⁵

further simplified, we have
9.17 x 10³

Thus, we can summarize that light is about 9.17 x 10³ faster than the speed of sound going by Jake observation.

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Full Question:

Jake noted that speed of light is approximately 1.1 × 10⁹ km/h;

the speed of sound is approximately 1.2 x 10³ km/h; and

11 + 12 = 0.916.

Using Jake's figures how many times faster is light than speed?

Write your answer in standard form.

Based on the graph, it appears that F(x) is a downward-facing parabola that has been shifted horizontally and vertically.

The vertex of the parabola is located at the point (3,-3), so the equation must include (x - 3) and (y + 3). Additionally, since the graph is narrower than the graph of G(x) = x^2, there must be a coefficient that is greater than 1 in front of the squared term.

Looking at the answer choices, we can eliminate options B and D because they have positive coefficients in front of the squared term, which would result in an upward-facing parabola. Option C has a negative coefficient in front of the squared term, which would result in a wider parabola than the graph shown.

Therefore, the correct answer is A, F(x) = 3(x-3)^2 - 3.

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Answer:

k = 1

Step-by-step explanation:

We can use the table for g(x) = f(kx) to find the value of k.

Notice that when x = -2, we have g(-2) = f(k(-2)) = f(-2k) = 64. Similarly, when x = 2, we have g(2) = f(k(2)) = f(2k) = 64.

Using the fact that f(x) is a quadratic function, we can see that its axis of symmetry passes through the vertex at (0, 0), which means that the x-coordinate of the vertex is 0. This tells us that the coefficient of the x term in f(x) is 0, so the function can be written as f(x) = ax^2 + bx + c, where a is not equal to 0.

Using the points (−2,4), (−1,1), (0,0), (1,1), and (2,4), we can write a system of equations to solve for a, b, and c:

a(-2)^2 + b(-2) + c = 4

a(-1)^2 + b(-1) + c = 1

a(0)^2 + b(0) + c = 0

a(1)^2 + b(1) + c = 1

a(2)^2 + b(2) + c = 4

Simplifying and rearranging, we get:

4a - 2b + c = 4

a - b + c = 1

c = 0

a + b + c = 1

4a + 2b + c = 4

Substituting c = 0 into the system, we get:

4a - 2b = 4

a - b = 1

a + b = 1

4a + 2b = 4

Solving this system of equations, we get a = 1, b = -1, and c = 0.

Substituting these values into g(x) = f(kx), we get:

g(x) = f(kx) = x^2 - x

Substituting the values from the table into this equation, we get:

g(-2) = 4 = (-2)^2 - (-2) = 4k

g(2) = 4 = (2)^2 - (2) = 4k

Solving for k, we get k = 1 or k = -1/4.

However, we need to check which value of k satisfies all the points in between -2 and 2, so we can check g(-1) = 1 = (-1)^2 - (-1) = k, and g(1) = 1 = (1)^2 - (1) = k.

Thus, the value of k that satisfies all the points is k = 1, and therefore the answer is:

k = 1

We can use the information given to find the value of k.

Since the vertex of the quadratic function f(x) is at (0,0), we know that the equation for f(x) is in the form of f(x) = ax^2 for some constant a.

Using the point (-2, 4) on the graph of f(x), we can set up the equation 4 = 4a, which gives us a = 1.

So, the equation for f(x) is f(x) = x^2.

Now, we can use the table for g(x) = f(kx) to find the value of k.

When x = -2, we have g(-2) = f(k(-2)) = f(-2k) = 4k^2.

Similarly, when x = 2, we have g(2) = f(k(2)) = f(2k) = 4k^2.

We also know that g(0) = f(k(0)) = f(0) = 0, and g(-1) = f(k(-1)) = f(-k) = k^2 and g(1) = f(k(1)) = f(k) = k^2.

Using the values from the table, we can set up the following system of equations:

4k^2 = 64

k^2 = 16

0 = 0

k^2 = 16

The only solution that works for all of these equations is k = 4 or k = -4.

Therefore, the value of k is either k = 4 or k = -4.

Answer:

8.19 units.

Step-by-step explanation:

I didn't use desmos, i completed the question with all steps and working and didn't require desmos. Hope this Helps. Question was solved using trignometric ratios.

The answer is not 9 > 6, as that is a comparison between two numbers, but rather g ≤ 6, as it sets a limit on the number of goldfish that can be in the tank.

The correct inequality that represents the situation is g ≤ 6. The problem states that the maximum number of goldfish that can live in a small tank is 6, meaning that the number of goldfish must be less than or equal to 6.

The symbol ≤ represents "less than or equal to", while the symbol > represents "greater than".

Therefore, the answer is not 9 > 6, as that is a comparison between two numbers, but rather g ≤ 6, as it sets a limit on the number of goldfish that can be in the tank.

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Answer:

BC= 47.424

I believe that’s correct, but if you really need an answer just get a triangle calculator

An expression for the sequence of operations described "Subtract three from the product of seven and eight." is (7 × 8) - 3.

In order to evaluate and solve this expression, we would have to apply the PEMDAS rule, where mathematical operations within the parenthesis (grouping symbols) are first of all evaluated, followed by exponent, and then multiplication or division from the left side of the equation to the right. Lastly, the mathematical operations of addition or subtraction would be performed from left to right.

Based on the information provided, we have the following mathematical expression:

Expression: (7 × 8) - 3

56 - 3

53

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Answer:

Step-by-step explanation: The vertex is the point at the bottom if the parabola opens up and at the top if it opens at the bottom.

Answer:

Step-by-step explanation:

It's given that, Radius of the circle is 9 cm.

We know that Circumference of the circle is calculated as 2πr

where,

Substituting the required values,

Circumference = 2 × 3.14 × 9

= 6.28 × 9

= 56.52 cm

Hence the required circumference of the circle is 56.52 cm