PLz help--- What's happening here?
This object is not moving
This object is not changing speeds.
This object is changing speeds; it's getting faster.
This object is changing speeds; it's getting slower.

Answer: When a gas is in a smaller volume, the molecules are more confined and bump into the walls of the flask more, thereby exerting a greater pressure.

Explanation:

Electrons are transferred from oxygen atoms to iron atoms is a redox reaction. Option B is correct.

A redox reaction is a type of chemical reaction in which two species exchange electrons.

Any chemical process in which the oxidation number of a molecule, atom, or ion changes by gaining or losing an electron is known as an oxidation-reduction reaction.

A redox reaction can result in the creation of hydrogen fluoride. The creation of hydrogen fluoride is another example of a redox reaction.

We can evaluate the oxidation and reduction of reactants by breaking down the process. Each hydrogen turns positive after being oxidized and losing two electrons.

Electrons are transferred from oxygen atoms to iron atoms is a redox reaction.

Hence, the option B is correct.

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Answer: D) Electrons are transferred from iron atoms to oxygen atoms

If anyone else needs it

Explanation: the iron is increasing in oxidation number (losing electrons) and oxygen is decreasing in oxidation number (gaining electrons). This tells us that we have oxidation (or rusting) taking place.

The magnitude of the magnetic field in the coil is 21.65 T.

The given parameters;

The induced emf in the coil is determined by applying Faradays law;

[tex]emf =N \frac{d\phi }{dt} \\\\emf = N ( \frac{\phi _2 - \phi_1}{t} )\\\\emf= N(\frac{BAsin\ 60 - BAsin\ 90}{t} )\\\\emf = NBA(\frac{sin60 - sn90}{t} )\\\\-0.058 = 500(6\times 10^{-4})\times B\times (\frac{0.866 - 1}{15} )\\\\-0.058 = -0.00268B\\\\B = \frac{0.058}{0.00268} \\\\B = 21.65 \ T[/tex]

Thus, the magnitude of the magnetic field in the coil is 21.65 T.

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Answer:

It should be mentioned that an efficient way to work this vector addition problem is with the cosine law for general triangles (and since  

a

,

b

 and  

r

 from an isosecles triangle, the angles are easy to figure). However, in the interest of reinforcing the usual systematic approach to vector addition, we note that the angle  

b

 makes with the +x axis  is 30

0

+105

0

=135

0

(a) The x component of  

r

x

​

​

=(10.0m)cos30

0

+(10.0m)cos135

0

=1.59m

(b)  the y component of  

r

 is r

y

​

=(10.0m)sin135

0

 = 12.1 m.

(c) the magnitude of  

r

 is r =  ∣

r

∣=

(1.59m)

2

+(12.1m)

2

​

=12.2m

(d) The angle between  

r

 and the +x direction is tan

−1

[(12.1m)/(1.59m)]=82.5

0

Explanation:

Hi there!

For an object moving in a circle:

Centripetal force = ∑F = mv²/r

Thus:

56 = mv²/r

Rearrange to solve for velocity:

√(56r/m) = v

√(56 × 21)/650 = 1.345 m/s

Answer:

Explanation:

have a good day

Answer:

Molar mass of NH3=14+3=17g

[tex]mole = \frac{given \: mass}{molar \: mass} \\ mole = \frac{28}{17} \\ mole = 1.65[/tex]

BRAINLIST

Answer:

12,000,000 boxes

Explanation:

the volume of the room can be found by using the equation for volume of a rectangular box:V=LxWxH

where:

L=2m

W=3m

H=4m

(it doesn't really matter which is which since it is multiplication)

when we multiply our values (2m*3m*4m) we get 24cubic meters

now we need to convert cubic meters to cubic centimeters

each cubic meter is 1,000,000 cubic centimeter we multiply 24 by 1,000,000 and we get: 24,000,000 cubic centimeters (cc)

dividing 24,000,000 by 2 (since each box is 2cc) we get 12,000,000

so, we know we can fit 12,000,000, 2 cubic centimeter boxes in this room

Explanation:

a.displacement is vector quantity there fore

we combine the two direction

[tex] {c}^{2} = \sqrt{ {a}^{2} + {b}^{2} } [/tex]

[tex] {c}^{2 } = \sqrt{ {12}^{2} + {16}^{2} } [/tex]

[tex] {c}^{2} = \sqrt{400 } [/tex]

[tex]c = 20[/tex]

displacement is 20km to wards north

b:average speed

[tex]v = s \div t[/tex]

20/3=6.67

c: please type correctly

Explanation:

A) kinetic energy

B) potential energy

C) Mechanical energy

a) The motorcyclist rises utilising chemical energy's "mechanical energy" (kinetic and potential energy). b) The cyclist's highest "gravitational potential energy" is transformed into motion downhill. c) When the rider moves downhill, potential energy becomes "kinetic energy." "Kinetic energy" is most vital.

a) "Mechanical energy" is used by the cyclist to ride up the slope. Kinetic and potential energy from an object's motion and position make up mechanical energy. As they pedal, cyclists transform chemical energy from their bodies into mechanical energy. This mechanical energy overcomes gravity as the cyclist climbs. As the cyclist climbs, potential energy accumulates, which is translated into kinetic energy as they descend.

b) At the summit of the slope, the biker has "gravitational potential energy." An object's gravitational potential energy depends on its position in a gravitational field. The biker has gained potential energy by climbing against gravity. At the crest of the hill, the cyclist's kinetic energy is lowest while potential energy is highest. The cyclist's potential energy is ready to be turned into kinetic energy as they descend.

c) Without pedalling, the rider gains "kinetic energy." The cyclist's speed increases as they descend, converting potential energy into kinetic energy. The cyclist's potential energy is turned into kinetic energy by gravity. As the rider descends, their potential energy diminishes but their kinetic energy increases, speeding up their bike. The biker converts potential energy into kinetic energy as he descends, and most of it is converted back at the bottom.

In conclusion, the cyclist climbs the incline using "mechanical energy" from chemical energy. They descend using "gravitational potential energy" at the top. Potential energy becomes "kinetic energy" when the rider descends without pedalling, speeding up the bike. Potential-to-kinetic energy conversion helps the cyclist climb the slope.

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Answer:

[tex]315meters[/tex]

Explanation:

Solution is attached.

Cuando el niño hace girar 0.7 vueltas por segundo una pelota de hule que se encuentra sujeta mediante un cordón de 0.75 m de longitud, tenemos que:

a) El periodo de la pelota es 1.43 segundos.

b) La velocidad lineal de la pelota es 3.3 m/s.

a) El periodo de la pelota está dado por:

[tex] T = \frac{2\pi}{\omega} [/tex]

En donde:

ω: es la velocidad angular

Dado que la pelota da 0.7 vueltas (revoluciones) cada segundo, la velocidad angular es:

[tex] \omega = \frac{0.7 \:rev}{s}*\frac{2\pi rad}{1 \:rev} = 4.40 rad/s [/tex]

Entonces, el periodo es:

[tex]T = \frac{2\pi}{\omega} = \frac{2\pi}{4.40 rad/s} = 1.43 s[/tex]

b) La velocidad lineal de la pelota se puede calcular usando la siguiente ecuación:

[tex] v = \omega r [/tex]

En donde:

r: es el radio de la circunferencia = longitud del cordón = 0.75 m

[tex]v = \omega r =4.40 rad/s*0.75 m = 3.3 m/s[/tex]

Por lo tanto, la velocidad lineal de la pelota es 3.3 m/s.

Puedes encontar mas aquí:

Espero que te sea de utilidad!

Answer:

(B) B is travelling fastest

Explanation:

slope of xt graph = speed.

Slope of B is greater than a and c.

BRAINLIST PLS

Answer: D, All of the above!

Explanation:

I just helped my daughter with this test and it was correct!! Good luck !!

Answer:

proportional...?

Explanation:

not sure if thats correct...

hope this helped tho

try your best!

mark me brianliest :D

Answer:

Answer → Distance is 5 × 10⁴ km

Explanation:

Gravitational formular

[tex]{ \tt{F = \frac{GMm}{ {r}^{2} } }} \\ [/tex]

For the first case;

[tex]{ \tt{F _{1} = \frac{GMm}{2.5 \times {10}^{4} } }} \\ [/tex]

For the second case;

[tex]{ \tt{F _{2} = \frac{GMm}{r _{2}} }} \\ [/tex]

but F2 = ½F1

Therefore, F1 = 2F2

Hence:

[tex]{ \tt{ \frac{GMm}{2.5 \times {10}^{4} } =2 \times \frac{GMm}{r _{2} } }} \\ \\ { \tt{ \frac{1}{2.5 \times {10}^{4} } = \frac{2}{r _{2} } }} \\ \\ { \tt{r _{2} = 2 \times 2.5 \times {10}^{4} }} \\ \\ { \underline{ \tt{ \: \: r _{2} = 5 \times {10}^{4} \: km \: \: }}}[/tex]

Answer: Distance is 5 × 10⁴ km

Explanation:

Answer:

[tex]\displaystyle v = 12.4134 \ m/s[/tex]

General Formulas and Concepts:

Energy

Kinetic Energy Formula: [tex]\displaystyle KE = \frac{1}{2}mv^2[/tex]

Explanation:

Step 1: Define

Identify variables.

KE = 7250 J

m= 94.1 kg

Step 2: Solve for v

Topic: AP Physics 1 - Algebra Based

Unit: Energy

When a single star with a mass equal to the sun dies, it will become a: white dwarf.

A star is a giant celestial (astronomical) object which comprises a luminous sphere of plasma bounded together by its own gravitational force.

A single star can be defined as a type of star that moves through space alone.

Generally, a star is mainly composed of two (2) hot gases and these are:

I. Hydrogen (H).

II. Helium (He).

Based on Astronomy, when a star runs out of hydrogen, depending on its mass, it would either turn into any of the following:

Similarly, when a single star with a mass equal to the sun dies, it will turn into a white dwarf.

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Water waves shake energy over the surface of the sea, while sound waves thump energy through the body of the air. Sound waves are compression waves. They're also called longitudinal waves because the air vibrates along the same direction as the wave travels.

Answer:

B

Explanation:

Moment = force * perpendicular distance

Since the beam is balanced(equilibrium), the 2 moments will be equal.

30 * P = 70 * Q

The 2 combinations which achieve this equality is P = 21 and Q = 9

Answer:

draw the picture / (.) (.) \ Patrick star

Answer:

combine them all

6 m

Explanation:

Answer:

1

Explanation:

because when we use v=u+at we derived v-u÷t

Hi there!

We can first find the angular displacement of the first 20 seconds by finding the angular acceleration.

Begin by converting 120 rev/min to rev/sec:

120 rev/min × 1 min/60 sec = 2 rev/sec

ω = αt

2 = 20α

α = 0.1 rev/sec²

θ = ωit + 1/2αt²

The fan starts from rest, so:

θ = 1/2αt²

θ = 1/2(0.1)(20²) = 20 revolutions

Now, for the next 40 seconds, we can find the fan's deceleration:

ωf = ωi + αt

0 = 2 + αt

-2 = 40α

α = -0.05 rad/sec²

Use the above equation:

θ = ωit + 1/2αt²

θ = 2(40) + 1/2(-0.05)(40²) = 80 - 40 = 40 rev

θ = 4800 - 2400 = 2400 revolutions

Add the two:

θtotal = 20 + 40 = 60 revolutions

Answer: be cut in half

Explanation: