PLSS I NEED THIS! Number 4

The equation that represents the linear function is y = 11 + 7x.

What is the solution to the linear equation?

The solution of a linear equation is defined as the points, in which the lines represent the intersection of two linear equations. In other words, the solution set of the system of linear equations is the set of all possible values to the variables that satisfies the given linear equation.

We have given the rules:

x: a number

y: 11 more than 7 times x.

Linear equations are the equations of degree 1. It is the equation for the straight line.

The standard form of the linear equation is ax+by+c =0,

where a ≠ 0 and b ≠ 0.

From the given conditions we can form the linear equation:

That is,

y = 11 + 7x,

Hence, the equation that represents the linear function is y = 11 + 7x.

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Step-by-step explanation:

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Answer:

[tex] \frac{92}{15} [/tex]

Step-by-step explanation:

change to improper

[tex] \frac{24}{5} + \frac{4}{3} [/tex]

this gives us

[tex] \frac{92}{15} [/tex]

final answer

plz mark as brainliest

Answer:

[tex]\frac{92}{15} or 6\frac{2}{15}[/tex]

Step-by-step explanation

hope this helps have a good day :)

Answer:

[tex]m = 10\sqrt 3[/tex]

[tex]n = 10[/tex]

Step-by-step explanation:

Required

Find m and n

Considering the given angle, we have:

[tex]\sin(60) = \frac{Opposite}{Hypotenuse}[/tex]

This gives:

[tex]\sin(60) = \frac{m}{20}[/tex]

Make m ths subject

[tex]m = 20 * \sin(60)[/tex]

[tex]\sin(60) =\frac{\sqrt 3}{2}[/tex]

So, we have:

[tex]m = 20 *\frac{\sqrt 3}{2}[/tex]

[tex]m = 10\sqrt 3[/tex]

Considering the given angle again, we have:

[tex]\cos(60) = \frac{Adjacent}{Hypotenuse}[/tex]

This gives:

[tex]\cos(60) = \frac{n}{20}[/tex]

Make n the subject

[tex]n = 20 * \cos(60)[/tex]

[tex]\sin(60) =\frac{1}{2}[/tex]

So, we have:

[tex]n = 20 *\frac{1}{2}[/tex]

[tex]n = 10[/tex]

Answer:

200 CENTIMETRES

Step-by-step explanation:

Answer:

ND>MA n type in both 300k and 700k as ND and NA are not affected by rempredure, only NI is affected and it increases the electron and helps with the sane value so always electrons will be greater than holes at T= 300k Ni = 10 10 cm 3

Therefore , the solution of the given problem of perimeter comes out to be the perimeter is represented by the expression of Perimeter = 30 -6x.

In geometry, a shape's perimeter, or overall length, is referred to as its perimeter. The lengths of all a shape's sides and edges are added up to determine its perimeter.

Here,

Given :  length = 5 - 1(x) or

=> length = 5-x

Width is twice the length

thus,

=>Width = 2(5-x)

=>Width = 10-2x

So ,To find the perimeter

We use,

=> Perimeter = 2(length + width)

=> Perimeter = 2( 5-x + 10-2x )

=>  Perimeter = 2( 15 -3x)

=>   Perimeter = 30 -6x

Therefore , the solution of the given problem of perimeter comes out to be the perimeter is represented by the expression of Perimeter = 30 -6x.

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Respuesta:

23,5 milímetros

Explicación paso a paso:

Dado :

Diámetro del círculo = 47 mm

Radio del círculo = diámetro / 2

Por lo tanto, Radio = 47 mm / 2

Radio = 23,5 mm

Answer:

0.15

Step-by-step explanation:

I just put the fraction in decimal form since there is no photo.

Answer:

The null hypothesis is [tex]H_0: \mu = 99[/tex]

The alternate hypothesis is [tex]H_a: \mu > 99[/tex]

The test statistic is [tex]z = 0.31[/tex]

The pvalue of the test is 0.3783 > 0.05, which meas that the results are not significant at the 5% level.

Step-by-step explanation:

It is believed that the average amount of money spent per U.S. household per week on food is about $99. We want to test the hypothesis that the mean weekly food budget for all households in this community is higher than the national average.

At the null hypothesis, we test if the mean is the national average of 99, that is:

[tex]H_0: \mu = 99[/tex]

At the alternate hypothesis, we test if the mean is greater than the national average of 99, so:

[tex]H_a: \mu > 99[/tex]

The test statistic is:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.

99 is tested at the null hypothesis:

This means that [tex]\mu = 99[/tex]

A random sample of 16 households in a certain affluent community yields a mean weekly food budget of $100. Standard deviation of $13.

This means that [tex]n = 16, X = 100, \sigma = 13[/tex]

Value of the test statistic:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

[tex]z = \frac{100 - 99}{\frac{13}{\sqrt{16}}}[/tex]

[tex]z = 0.31[/tex]

The test statistic is [tex]z = 0.31[/tex].

Determine if the results significant at the 5% level.

The pvalue of the test is the probability of finding a sample mean above 100, which is 1 subtracted by the pvalue of z = 0.31.

Looking at the ztable, z = 0.31 has a pvalue of 0.6217

1 - 0.6217 = 0.3783

The pvalue of the test is 0.3783 > 0.05, which meas that the results are not significant at the 5% level.

Neither of the triangles are similar to the one given.

Two triangles are said to be similar if, they have congruent corresponding angles and sides are in equal ratios.

Given are three triangles, we need to find which of them are similar to the given one,

According to the definition of the similar triangles,

1) 10 / 5.5 = 10 / 5.5 ≠ 4 / 2

So, they are similar triangles.

2) 30 / 10 = 30 / 10 ≠ 14 / 4

Hence, Neither of the triangles are similar to the one given.

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Answer:

From the statements in the question, I and III is CORRECT

Step-by-step explanation:

First we take down the given data from the question for substitution;

Process mean = 16.9 ounces

Lower specification limit = 16.75 ounces

Upper specification limit = 17.05 ounces

Standard deviation = 0.04

Now, we get our Cpk;

Cpk = MINIMUM( (Upper specification limit - mean ) / 3 × Standard deviation), (mean - Lower specification limit) / 3 × Standard deviation) )

so we substitute

Cpk = MINIMUM(  ((17.05 ounces - 16.9 ounces) / 3 × 0.04 ounces ), (( 16.9 ounces - 16.75 ounces) / 3 × 0.04 ) )

Cpk = MINIMUM( 0.15 / 0.12 ), ( 0.15 / 0.12 )

Cpk = MINIMUM( 1.25, 1.25 )

Cpk = 1.25

Next the Cp;

Cp = ( Upper specification limit - Lower specification limit ) / ( 6 ×  standard deviation )

we substitute

Cp = ( 17.05 ounces - 16.75 ounces ) / ( 6 × 0.04 ounces )

Cp = 0.3 / 0.24

Cp = 1.25

Hence;

Cpk calculation is not less than Cp calculation.

Since Cp is greater than 1, the process is cable.

Since the actual process mean is also 16.90 ounces, then  the process is centered.

Therefore, From the statements in the question, I and III is CORRECT

The correct statement is "the Cp calculation indicates that the process is capable" and "the process is centered, so the Cp calculation should be used" and this can be determined by using the formula of Cpk and Cp.

GIven :

The formula of Cpk is given below:

[tex]\rm Cpk = minimum\left( \dfrac{Upper \;specification \;limit - mean}{ 3 \times Standard \;deviation)}, \dfrac{ mean - Lower\; specification\; limit} { 3 \times Standard \;deviation}\right )[/tex]

Now, substitute the known terms in the above formula.

[tex]\rm Cpk = minimum \left(\dfrac{17.05-16.9}{3\times 0.04},\dfrac{16.9-16.75}{3\times 0.04}\right)[/tex]

[tex]\rm Cpk = minimum \left(\dfrac{0.15}{0.12},\dfrac{0.15}{0.12}\right)[/tex]

Cpk = 1.25

Now, the formula of Cp is given below:

[tex]\rm Cp = \dfrac{Upper\; specification\; limit - Lower\; specification \;limit} { 6 \times standard \;deviation }[/tex]

Now, substitute the known terms in the above formula.

[tex]\rm Cp = \dfrac{17.05-16.75}{6\times 0.04}[/tex]

Cp = 1.25

So, the correct statement is "the Cp calculation indicates that the process is capable" and "the process is centered, so the Cp calculation should be used".

Therefore, the correct option is D) I and III.

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Answer:

The degrees of freedom for this problem are 21

Step-by-step explanation:

Degrees of freedom:

When testing an hypothesis involving two samples, the number of degrees of freedom is given by:

[tex]df = n_1 + n_2 - 2[/tex]

In which [tex]n_1[/tex] is the size of the first sample and [tex]n_2[/tex] is the sample of the second sample.

In this question:

Samples of 9 and 14, so [tex]n_1 = 9, n_2 = 14[/tex]

The degrees of freedom for this problem are

[tex]df = n_1 + n_2 - 2[/tex]

[tex]df = 9 + 14 - 2 = 21[/tex]

The degrees of freedom for this problem are 21

The required degree of freedom is 21.

Given that,

He randomly selects a sample of 9 lunch tickets from the city population resulting in a mean of $14.30 and a standard deviation of $3.40.

He randomly selects a sample of 14 lunch tickets from the suburban population resulting in a mean of $11.80 and a standard deviation $2.90.

He is using an alpha value of .10 to conduct this test.

We have to find,

The degrees of freedom for this problem are.

According to the question,

Degrees of freedom refers to the maximum number of logically independent values, which are values that have the freedom to vary, in the data sample.

Degrees of freedom are commonly discussed in relation to various forms of hypothesis testing in statistics, such as a chi-square.

When testing an hypothesis involving two samples, the number of degrees of freedom is given by,

[tex]Degree \ of \ freedom = n_1+n_2-2[/tex]

Where, [tex]n_1[/tex] is the size of the first sample and [tex]n_2[/tex] is the sample of the second sample.

[tex]n_1 = 9 \ and\ n_2 = 14[/tex]

Therefore,

[tex]Degree \ of \ freedom = 9+14-2\\\\Degree \ of \ freedom = 21[/tex]

Hence, The required degree of freedom is 21.

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Answer:

matching pairs of participants based on a variable and then randomly assigning one member of each pair to each group.

Step-by-step explanation:

A control experiment can be defined as an experiment in which a condition assumed to be a probable cause of the effect is being compared to the same situation by the scientist without involving or using the suspected condition.

A control group generally makes an experiment to work because they are not exposed to the variables and a neutral treatment.

On the other hand, an experimental group can be defined as a collection of participants that are subjected to the independent variable.

A matched pairs design involves matching pairs of participants based on a variable and then randomly assigning one member of each pair to each group. Thus, it's a process which typically involves pairing each individual in an experimental group with respect to another in the control group.

Generally, a matched pairs design is often times used when only a small group of participants are available for an experimental study or research.

Answer:

I can't please the question is sooo hard but can you give steps

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Explanation:

If we replace every copy of x with t, then we go from this

F(x) = 3x+5

to this

F(t) = 3t + 5

All we've done really is change the letter. We still are dealing with a variable. We're told that F(t) is equal to 26, which would allow us to replace the "F(t)" with "26" in the second equation above.

So we now have the equation 26 = 3t+5 which is the same as 3t+5 = 26

Let's solve for t

3t+5 = 26

3t = 26-5 .... subtract 5 from both sides

3t = 21

t = 21/3 .... divide both sides by 3

t = 7  is the answer

Now note that...

F(t) = 3t + 5

F(7) = 3*7 + 5 .... replace t with 7

F(7) = 21 + 5

F(7) = 26

This means we got F(t) = 26 when t = 7

It's the same as saying x = 7 leads to F(x) = 26.

This helps confirm we have the correct answer.

Answer:

t = 7

Step-by-step explanation:

I hope this helps

Answer:

6488765

Step-by-step explanation:

I did the math hope this helps!!

Answer:

[tex]\displaystyle 1\frac{1}{4}\pi[/tex]

Step-by-step explanation:

[tex]\displaystyle \boxed{y = 4cos\:(1\frac{3}{5}x - 1\frac{3}{10}\pi)} \\ \\ y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{\frac{13}{16}\pi} \hookrightarrow \frac{1\frac{3}{10}\pi}{1\frac{3}{5}} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{-\frac{3}{4}\pi} \hookrightarrow \frac{2}{1\frac{3}{5}}\pi \\ Amplitude \hookrightarrow 4[/tex]

OR

[tex]\displaystyle \boxed{y = 4sin\:(1\frac{3}{5}x + 1\frac{1}{5}\pi)} \\ \\ y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-\frac{3}{4}} \hookrightarrow \frac{-1\frac{1}{5}\pi}{1\frac{3}{5}} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{1\frac{1}{4}\pi} \hookrightarrow \frac{2}{1\frac{3}{5}}\pi \\ Amplitude \hookrightarrow 4[/tex]

Keep in mind that although this IS a sine function, if you plan on writing your equation as a function of cosine, then by all means, go right ahead. As you can see, the photograph farthest to the right displays the trigonometric graph of [tex]\displaystyle y = 4cos\:1\frac{3}{5}x,[/tex]in which you need to replase "sine" with "cosine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the sine graph [photograph farthest to the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the cosine graph [photograph farthest to the right] is shifted [tex]\displaystyle \frac{13}{16}\pi\:units[/tex]to the left, which means that in order to match the sine graph [photograph farthest to the left], we need to shift the graph FORWARD [tex]\displaystyle \frac{13}{16}\pi\:units,[/tex]which means the C-term will be positive, and by perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{\frac{13}{16}\pi} = \frac{1\frac{3}{10}\pi}{1\frac{3}{5}}.[/tex]So, the cosine graph of the sine graph, accourding to the horisontal shift, is [tex]\displaystyle y = 4cos\:(1\frac{3}{5}x - 1\frac{3}{10}\pi).[/tex]Intermediate, the centre photograph displays the trigonometric graph of [tex]\displaystyle y = 4sin\:1\frac{3}{5}x.[/tex]Again, just like before, we must figure out the appropriate C-term that will make this sine graph horisontally shift and map onto the sine graph in the leftward photograph. So, between the two photographs, we can tell that the centre sine graph is shifted [tex]\displaystyle \frac{3}{4}\pi\:units[/tex]to the right, which means that in order to match the leftward sine graph, we need to shift the graph BACKWARD [tex]\displaystyle \frac{3}{4}\pi\:units,[/tex]which means the C-term will be negative, and by perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{-\frac{3}{4}\pi} = \frac{-1\frac{1}{5}\pi}{1\frac{3}{5}}.[/tex]So, the sine graph is [tex]\displaystyle y = 4sin\:(1\frac{3}{5}x + 1\frac{1}{5}\pi).[/tex]Now, the amplitude is obvious to figure out because it is the A-term. Moreover, the midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = 0,[/tex]in which each crest is extended four units beyond the midline, hence, your amplitude. Now, with all that being said, no matter how far the graph shifts vertically, the midline will ALWAYS follow.

I am delighted to assist you at any time.

Answer:

Step-by-step explanation:

If m∠ABJ = 28 and ∠ABC ≅ ∠DBJ, then we can set up the following equation:

m∠ABC = m∠DBJ

Since angles ∠ABC and ∠DBJ are congruent, they have the same measure, so the equation above is true.

Since we are trying to find m∠JBC, we can use the fact that the measure of an angle is equal to the sum of the measures of the other two angles in the triangle to set up another equation:

m∠JBC = m∠ABC + m∠ABJ

Substituting the value for m∠ABC from the first equation into the second equation, we get:

m∠JBC = m∠DBJ + m∠ABJ

Substituting the given value of m∠ABJ into this equation, we get:

m∠JBC = m∠DBJ + 28

Since m∠ABJ = m∠DBJ, we can substitute m∠ABJ in for m∠DBJ:

m∠JBC = m∠ABJ + 28

Substituting the given value of m∠ABJ into this equation, we get:

m∠JBC = 28 + 28

Solving this equation, we find that m∠JBC = 56.

Therefore, the measure of angle ∠JBC is 56 degrees.

Answer:

A. Adjacent  

B. Complementary

C. Complementary

Step-by-step explanation:

Answer:

90 degree

Step-by-step explanation:

since the original angle BAC is 90 degree, no matter the triangle is rotated or translated, the angle remain unchanged

The value of angle of elevation (x) is 67°

The angle of elevation is an angle that is formed between the horizontal line and the line of sight. If the line of sight is upward from the horizontal line, then the angle formed is an angle of elevation.

Angle of elevation can be found by using trigonometry ratio

The height of the house is the opposite and the height of the ladder is the hypotenuse.

Therefore from trigonometry ratio;

sin x = 11/12

sin x = 0.92

x = sin^-1 (0.92)

x= 66.93°

x = 67° ( nearest degree)

Therefore the value of angle of elevation is 67°

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Answer:

minimum: 6500

maximum: 18500

Hope this helps

GLL

Step-by-step explanation:

Answer:

Correct answer is below

Step-by-step explanation:

Answer:

m<A=40°

m<B=55°

m<C=85°

Step-by-step explanation:

Add up all the angles to equal 180 because all triangles add up to 180.

(2x+5)+(x+15)+x=180

Simplify.

4x+20=180

Solve for x.

x=40.

Plug x into the equations. Hope this helps.

Answer:

D is correct Answer. x-4. THANK YOU.