The surface area of revolution of C about the x-axis is π/27 (81^(3/2) - 1) or approximately 478.48 units².
How to the surface area of revolution of a curve?To find the surface area of revolution of C about the x-axis, we can use the formula:
Surface area = ∫2πy ds
where y is the function that defines the curve C, and ds is an element of arc length along the curve.
We can express ds in terms of dx as follows:
ds = √(1 + (dy/dx)²) dx
where dy/dx is the derivative of y with respect to x.
For the curve C, we have:
y = 3x³
dy/dx = 9x²
Substituting these into the expression for ds, we get:
ds = √(1 + (9x²)²) dx
= √(1 + 81x⁴) dx
Substituting y and ds into the formula for surface area, we get:
Surface area = ∫₂πy √(1 + (dy/dx)²) dx
= ∫₀³ 2π(3x³) √(1 + 81x⁴) dx
This integral can be evaluated using substitution:
Let u = 1 + 81x⁴
Then du/dx = 324x³
And dx = du/324x³
Substituting these into the integral, we get:
Surface area = ∫₁₀³ 2π(3x³) √(1 + 81x⁴) dx
= 2π/108 ∫₁₀³ (3x³) √u du
= π/54 ∫₁₀³ u^(1/2) du
= π/54 (2/3) u^(3/2) | from 1 to 81
= π/81 (2/3)(81^(3/2) - 1)
= π/27 (81^(3/2) - 1)
Therefore, To find the surface area of revolution of C about the x-axis, we can use the formula:
Surface area = ∫2πy ds
where y is the function that defines the curve C, and ds is an element of arc length along the curve.
We can express ds in terms of dx as follows:
ds = √(1 + (dy/dx)²) dx
where dy/dx is the derivative of y with respect to x.
For the curve C, we have:
y = 3x³
dy/dx = 9x²
Substituting these into the expression for ds, we get:
ds = √(1 + (9x²)²) dx
= √(1 + 81x⁴) dx
Substituting y and ds into the formula for surface area, we get:
Surface area = ∫₂πy √(1 + (dy/dx)²) dx
= ∫₀³ 2π(3x³) √(1 + 81x⁴) dx
This integral can be evaluated using substitution:
Let u = 1 + 81x⁴
Then du/dx = 324x³
And dx = du/324x³
Substituting these into the integral, we get:
Surface area = ∫₁₀³ 2π(3x³) √(1 + 81x⁴) dx
= 2π/108 ∫₁₀³ (3x³) √u du
= π/54 ∫₁₀³ u^(1/2) du
= π/54 (2/3) u^(3/2) | from 1 to 81
= π/81 (2/3)(81^(3/2) - 1)
= π/27 (81^(3/2) - 1)
Therefore, the surface area of revolution of C about the x-axis is π/27 (81^(3/2) - 1) or approximately 478.48 units².
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4/625 x 625/9 cross cancellation
Answer:
Step-by-step explanation:
4/625 x 625/9 = 4 x 1 / 5 x 5 x 5 x 1 = 4/625. The cross cancellation did not change the result.
can yall awnser this asap pls I NEED TO PASS!!
Answer: 36 inches
Step-by-step explanation:
The lateral surface area of a cube with sides of length 3 inches is given by the sum of the areas of all four side faces. Each side face is a square with an area equal to the product of the length and width, which in this case is 3 inches by 3 inches. Therefore, the lateral surface area of the cube is:
LSA = 4 x (3 inches x 3 inches) = 36 square inches
So the lateral surface area of the cube is 36 square inches
A foam cylinder, with a diameter of 3 inches and height of 4 inches, is carved into the shape of a cone. what is the
maximum volume of a cone that can be carved? round your answer to the hundredths place.
The maximum volume of a cone that can be carved from the foam cylinder is approximately 9.42 cubic inches.
Given data:
diameter = 3 inches
radius = r = 3 ÷ 2 = 1.5 inches
height = 4 inches
We need to find the maximum volume of a cone that can be carved from the foam cylinder. The volume of a cone is given by the formula:
V = [tex]\frac{1}{3}\pi r^2h[/tex]
where:
V = volume
r = radius of the base
h = height
π = 3.14.
Substituting the r, h, and π values in the formula, we get:
V = [tex]\frac{1}{3}[/tex]π[tex]r^2[/tex]h
V = [tex]\frac{1}{3}[/tex] × π × (1.5)² ×(4)
V = [tex]\frac{1}{3}[/tex] × π × 2.25 ×(4)
V = 3 π
V = 9.42 cubic inches
Therefore, the maximum volume of a cone is 9.42 cubic inches.
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4x - 2y = -1
8x - 4y = -2
what method is most efficient to use and what is the answer
Determine the measure of arc cad thanks grade 9-10-11 it is either 240 or 260
The measure of arc CAD is either 240 or 260.
How to do measure of arc?Without additional information, it is not possible to determine the measure of arc CAD with certainty. The measure of an arc depends on the central angle that subtends it.
If the central angle is known, the measure of the arc can be calculated using the formula: measure of arc = (central angle / 360) x circumference of the circle. However, without knowing the central angle, we cannot determine the measure of arc CAD.
Therefore, we need to be provided with additional information such as the measure of another angle that is related to the central angle, or the length of a chord that subtends the arc in order to determine the central angle and the measure of arc CAD.
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Can please write answer in box Please Thank you
Find the total differential. w = x15yz11 + sin(yz) = dw =
The total differential of w is given by dw = (∂w/∂x)dx + (∂w/∂y)dy + (∂w/∂z)dz + (∂w/∂z)(∂z/∂y)dy + (∂w/∂z)(∂z/∂z)dz.
Differentiation is a process of finding the changes in any function with a small change in By differentiation, it can be checked that how much a function changes and it also shows the way of change Differentiation is being used cost, production and other management decisions. It gives the rate of change independent variable with respect to the independent variable. First, let's get the partial derivatives of w with respect to x, y, and z: ∂w/∂x = 15x^14yz^11, ∂w/∂y = x^15z^11cos(yz), ∂w/∂z = 11x^15y^z^10 + x^15y^11cos(yz). Next, we need to find (∂w/∂z)(∂z/∂y): ∂z/∂y = cos(y)
So, (∂w/∂z)(∂z/∂y) = x^15y^11z^10cos(y). Substituting these values into the formula for the total differential, we get: dw = (15x^14yz^11)dx + (x^15z^11cos(yz))dy + (11x^15y^z^10 + x^15y^11cos(yz))dz + (x^15y^11z^10cos(y))dy
Simplifying, we get: dw = 15x^14yz^11dx + x^15z^11cos(yz)dy + (11x^15y^z^10 + x^15y^11cos(yz) + x^15y^11z^10cos(y))dz.
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true or false, Inflation occurs in an economy when there's a reduction in the total amount of money.
Answer:
False.
Inflation occurs in an economy when there is an increase in the overall price level of goods and services over time. It is usually caused by factors such as an increase in the money supply, higher demand for goods and services, or a decrease in the supply of goods and services. Therefore, a reduction in the total amount of money in an economy would generally lead to deflation, which is the opposite of inflation.
In a box of nerds candy, the ratio of pink to purple candies is 19:20. if there are 429 pieces of candy in the box, how many are pink?
There are 199 pink candies in the box of Nerds calculated on the basis of given information.
To find out, you first need to add the ratio of pink and purple candies, which is 19+20=39. Then, divide the total number of candies by the sum of the ratio to find the value of one unit of the ratio, which is 429/39 = 11.
Then, multiply the value of one unit of the ratio by the value of the pink candies, which is 19, to find the number of pink candies, which is 11 x 19 = 209. Therefore, there are 209 purple candies in the box.
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how many times does five go into 6
Answer:
1 time, though your answer would be ongoing. If you the actual answer, it's 1.2
Step-by-step explanation:
Round to the nearest tenth.
Answer:
1.2
Step-by-step explanation:
Five can go into six 1.2 times because (1.2)(5)=6. Of course, if you want to know how many times five can go into 6 as a WHOLE, then the answer would obviously be 1.
Hope this helps a bit :)
ASAP THX!!! ANSWER GETS BRAINLIEST
Rachel went to the grocery store and spent $68. She now has only $23 to get gasoline with before she returns home. How much money did Rachel have before she went grocery shopping? Create an equation to represent the situation. Make sure to identify and label your variable. Solve for the variable and describe your answer. Show your work and prove your solution to be correct
The solution is correct, as both sides of the equation are equal.
To find out how much money Rachel had before she went grocery shopping, we can create an equation using a variable.
Let x represent the amount of money Rachel had before grocery shopping.
The equation for the situation would be: x - $68 = $23
Now, let's solve for x:
Step 1: Add $68 to both sides of the equation:
x = $23 + $68
Step 2: Calculate the sum:
x = $91
So, Rachel had $91 before she went grocery shopping.
To prove the solution is correct, we can plug the value of x back into the equation:
$91 - $68 = $23
$23 = $23
Hence, both are equal.
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If f(x) = x2 + 4x + 6, find the following values. = 1. f(a) = 2. f(a - 1) = 3. f(a + 1) =
To find the values of f(a), f(a-1), and f(a+1) when f(x) = x^2 + 4x + 6, So, the values are: f(a) = a^2 + 4a + 6, f(a-1) = a^2 + 6a + 3, f(a+1) = a^2 + 6a + 11.
we simply substitute the given values of a into the function.
1. f(a) = a^2 + 4a + 6
2. f(a-1) = (a-1)^2 + 4(a-1) + 6 = a^2 + 2a + 1 + 4a - 4 + 6 = a^2 + 6a + 3
3. f(a+1) = (a+1)^2 + 4(a+1) + 6 = a^2 + 2a + 1 + 4a + 4 + 6 = a^2 + 6a + 11
So, the values are:
1. f(a) = a^2 + 4a + 6
2. f(a-1) = a^2 + 6a + 3
3. f(a+1) = a^2 + 6a + 11
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Please help! asap! (any accounts that give links will be reported)
⊙O and ⊙P are given with centers (−2, 7) and (12, −1) and radii of lengths 5 and 12, respectively. Using similarity transformations on ⊙O, prove that ⊙O and ⊙P are similar. Explain
We have shown that ⊙O and ⊙P are similar using similarity transformations.
To prove that ⊙O and ⊙P are similar using similarity transformations, we need to show that they have the same shape . Let's consider a dilation transformation with a scale factor of 2, centered at point A, which is the midpoint of the line segment connecting the centers of ⊙O and ⊙P:
1.Draw a line segment connecting the centers of ⊙O and ⊙P, and label the midpoint of this line segment as point A.
2.Draw two radii from the centers of ⊙O and ⊙P to a point B on the circumference of ⊙O, and label the intersection point of AB and ⊙P as point C.
3.Draw a perpendicular line from point A to BC, and label the intersection point as point D.
4.Since AD is the perpendicular bisector of BC, we have BD = DC.
5.By the properties of dilation, the length of any line segment on ⊙O is doubled when it is transformed by a dilation with a scale factor of 2 centered at A.
6.Therefore, the length of BD is doubled to become BE, and the length of DC is doubled to become CF.
7.Since ⊙O is transformed to a circle with center A and radius 10, and ⊙P is transformed to a circle with center A and radius 24, we can see that they have the same shape but different sizes.
Therefore, we have shown that ⊙O and ⊙P are similar using similarity transformations.
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Thr ratio of measures of the angle is ABC IS 4:13:19. Find the measure of the angle. This is geometry
The measure of angle A is 20 degrees, the measure of angle B is 65 degrees, and the measure of angle C is 95 degrees.
To find the measure of the angles in triangle ABC, we first need to determine the total ratio of measures.
The total ratio is 4 + 13 + 19 = 36.
Next, we can use the ratios to find the measure of each angle.
Let x be the measure of the smallest angle in triangle ABC.
Then the measures of the angles are:
Angle A = 4x
Angle B = 13x
Angle C = 19x
We know that the sum of the angles in a triangle is 180 degrees, so we can set up the equation:
4x + 13x + 19x = 180
Simplifying, we get:
36x = 180
Dividing both sides by 36, we get:
x = 5
Therefore, the measures of the angles in triangle ABC are:
Angle A = 4x = 4(5) = 20 degrees
Angle B = 13x = 13(5) = 65 degrees
Angle C = 19x = 19(5) = 95 degrees
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The diagram below shows a quadratic curve. Determine the equation of the curve, giving your answer in the form ax²+bx+c y = = 03 where a, b and care integers. y i 32 (2.0) (8.0)
Answer:
Step-by-step explanation:
Without a diagram, I cannot determine the equation of the curve. However, I can provide you with the general steps to find the equation of a quadratic curve given three points on the curve.
Let the three points be (x1, y1), (x2, y2), and (x3, y3). Then the equation of the quadratic curve in the form ax²+bx+c can be found using the following system of equations:
y1 = a(x1)² + b(x1) + c
y2 = a(x2)² + b(x2) + c
y3 = a(x3)² + b(x3) + c
Solving this system of equations simultaneously will give us the values of a, b, and c, which we can use to write the equation of the quadratic curve.
However, since you have only provided three y-values (32, 2.0, and 8.0), without their corresponding x-values or the diagram, it is not possible to determine the equation of the curve.
verify that the equation is an identity. 2cosx2x/sin2x=cotx-tanx
The LHS is equal to the RHS, and the given equation is verified as an identity. We have to verify that the following equation is an identity:
2cos(x) 2x / sin2(x) = cot(x) - tan(x)
Starting from the left-hand side (LHS):
2cos(x) 2x / sin2(x) = 2cos(x) 2x / (1 - cos2(x)) (using the identity sin2(x) = 1 - cos2(x))
= 2cos(x) 2x / (1 - cos(x)) (1 + cos(x))
= 2cos(x) 2x / (1 - cos(x)) (1 + cos(x)) (multiplying the denominator by (1 + cos(x)))
= 2cos(x) 2x / (1 - cos2(x))
= 2cos(x) 2x / sin2(x) (using the identity 1 - cos2(x) = sin2(x))
= 2cos(x) / sin(x) (simplifying by canceling out the common factor of 2 and cos(x))
= 2cos(x) / sin(x) * (cos(x) / cos(x)) (multiplying by 1 in the form of cos(x)/cos(x))
= 2cos2(x) / (sin(x)cos(x))
= 2cos(x)/sin(x) * cos(x)
= cot(x) * cos(x)
Now, moving to the right-hand side (RHS):
cot(x) - tan(x) = cos(x)/sin(x) - sin(x)/cos(x)
= cos2(x)/sin(x)cos(x) - sin2(x)/sin(x)cos(x)
= (cos2(x) - sin2(x))/sin(x)cos(x)
= cos(x)/sin(x) * cos(x)/cos(x) - sin(x)/cos(x) * sin(x)/sin(x) (using the identity cos2(x) - sin2(x) = cos(x)cos(x) - sin(x)sin(x))
= cot(x) * cos(x)
Therefore, the LHS is equal to the RHS, and the given equation is verified as an identity.
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Graph the points (–2.5,–3), (2.5,–4), and (5,0.5) on the coordinate plane.
The points are graphed on a coordinate plane and attached
What is a coordinate planeA coordinate plane, also known as a Cartesian plane, is a two-dimensional plane with two perpendicular lines that intersect at a point called the origin.
The horizontal line is called the x-axis and the vertical line is called the y-axis. The axes divide the plane into four quadrants.
Each point on the plane can be uniquely identified by a pair of coordinates (x, y), where x is the horizontal distance from the origin along the x-axis and y is the vertical distance from the origin along the y-axis.
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A spotlight is mounted on the eaves of a house 20 feet above the ground. A flower bed runs between the house and the sidewalk, so the closest the ladder can be placed to the house is 15 feet. How long a ladder is needed so that an electrician can reach the place where the light is mounted
Answer:
Step-by-step explanation:
We can use the Pythagorean theorem to solve this problem. Let's call the length of the ladder "L". The ladder, the wall of the house, and the ground form a right triangle. The distance between the ladder and the house is the base of the triangle, which is 15 feet. The height of the triangle is the distance from the ground to the spotlight, which is 20 feet. The length of the ladder is the hypotenuse of the triangle.
Using the Pythagorean theorem, we have:
L^2 = 15^2 + 20^2
L^2 = 225 + 400
L^2 = 625
L = sqrt(625)
L = 25
Therefore, a ladder of at least 25 feet is needed for the electrician to reach the place where the light is mounted.
I need help on the quesrion attached
A simplification of the expression [tex]\frac{x^3y^3 \cdot x^3 }{4x^2}[/tex] is [tex]\frac{x^4y^3 }{4}[/tex].
What is an exponent?In Mathematics, an exponent is a mathematical operation that is commonly used in conjunction with an algebraic equation or expression, in order to raise a given quantity to the power of another.
Mathematically, an exponent can be represented or modeled by this mathematical expression;
bⁿ
Where:
the variables b and n are numbers (numerical values), letters, or an algebraic expression.n is known as a superscript or power.By applying the division and multiplication law of exponents for powers of the same base to the given algebraic expression, we have the following:
[tex]\frac{x^3y^3 \cdot x^3 }{4x^2}=\frac{x^{3+3-2}y^3 }{4}\\\\\frac{x^{3+3-2}y^3 }{4}=\frac{x^4y^3 }{4}[/tex]
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Complete Question;
Simplify each of the expressions given.
Find the critical point and determine if the function is increasing or decreasing on the given intervals. y = x2 - 4x?, x>0 (Use decimal notation. Give your answer to three decimal places.) critical point c= _____
The critical point is c = 2, the function is decreasing on the interval 0 < x < 2, and increasing on the interval x > 2.
To find the critical point of the function y = x^2 - 4x, we first need to find its derivative, which represents the slope of the tangent line at any point on the curve.
The derivative of y with respect to x is:
y' = 2x - 4
Now, we need to find the critical points, which occur where the derivative is zero or undefined. In this case, the derivative is a polynomial, so it is never undefined. To find where it equals zero, we set y' equal to zero:
0 = 2x - 4
Solving for x, we get:
x = 4/2 = 2
So, the critical point is c = 2.
Now, we need to determine if the function is increasing or decreasing on the interval x > 0. To do this, we can analyze the sign of the derivative. If y' > 0, the function is increasing; if y' < 0, the function is decreasing.
For x > 2 (to the right of the critical point), the derivative y' = 2x - 4 is positive (since 2x > 4 when x > 2). Therefore, the function is increasing on the interval x > 2.
For x < 2 (to the left of the critical point), the derivative y' = 2x - 4 is negative (since 2x < 4 when x < 2). Therefore, the function is decreasing on the interval 0 < x < 2.
In summary, the critical point is c = 2, the function is decreasing on the interval 0 < x < 2, and increasing on the interval x > 2.
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Find the error & explain why it is wrong:
megan solved the following problem. what did she do wrong?
what is (f - g)(2)?
f(x) = 3x2 – 2x + 4
g(x) = x2 – 5x + 2
The value of (f-g)(2) is 16, provided that Megan has made no mistakes in the calculation.
Find the error in the given problem solved by Megan?The problem asks us to compute the value of (f - g)(2) where f(x) = 3x^2 - 2x + 4 and g(x) = x^2 - 5x + 2.
The notation (f - g)(2) means that we need to subtract g(x) from f(x) and then evaluate the result at x = 2. We can do this as follows:
(f - g)(x) = f(x) - g(x) = (3x^2 - 2x + 4) - (x^2 - 5x + 2) = 2x^2 + 3x + 2
Substituting x = 2, we get:
(f - g)(2) = 2(2)^2 + 3(2) + 2 = 16
Therefore, the value of (f - g)(2) is 16.
It's worth noting that the problem statement mentions "what did she do wrong?" without providing any context or information about what Megan did or didn't do. So, it's not possible to identify any error in Megan's solution based on the given information. However, based on the correct computation above, we can be sure that (f - g)(2) is indeed equal to 16.
In other words, it can be described as,
The error in Megan's solution is not clear from the given statement. However, it seems that she may have made an error while computing (f-g)(2).
To compute (f-g)(2), we need to subtract g(2) from f(2) as follows:
f(2) = 3(2)^2 - 2(2) + 4 = 12
g(2) = (2)^2 - 5(2) + 2 = -4
Therefore, (f-g)(2) = f(2) - g(2) = 12 - (-4) = 16. is the final conclusion.
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Consider the function f(x,y) = 4x^4 - 4x^²y + y^2 + 9 and the point P(-1,1). a. Find the unit vectors that give the direction of steepest ascent and steepest descent at P. b. Find a vector that points in a direction of no change in the function at P.
The unit vector in the direction of steepest ascent at P is <-4/sqrt(17), -1/sqrt(17)>, and the unit vector in the direction of steepest descent at P is <4/sqrt(17), 1/sqrt(17)>. A vector that points in a direction of no change at P is ⟨-1,1⟩.
To find the direction of steepest ascent/descent at P(-1,1) for f(x,y) = 4x^4 - 4x^2y + y^2 + 9, we need to find the gradient vector evaluated at P and then normalize it to get a unit vector. The gradient vector is given by
grad f(x,y) = <∂f/∂x, ∂f/∂y> = <16x^3 - 8xy, -4x^2 + 2y>
So, at P(-1,1), the gradient vector is
grad f(-1,1) = <16(-1)^3 - 8(-1)(1), -4(-1)^2 + 2(1)> = <-8,-2>
To find the unit vector that gives the direction of steepest ascent, we normalize the gradient vector
||grad f(-1,1)|| = sqrt[(-8)^2 + (-2)^2] = sqrt(68)
So, the unit vector in the direction of steepest ascent at P is
u = (1/sqrt(68))<-8,-2> = <-4/sqrt(17), -1/sqrt(17)>
To find the unit vector that gives the direction of steepest descent, we take the negative of the gradient vector and normalize it
||-grad f(-1,1)|| = ||<8,2>|| = sqrt[8^2 + 2^2] = sqrt(68)
So, the unit vector in the direction of steepest descent at P is
v = (1/sqrt(68))<8,2> = <4/sqrt(17), 1/sqrt(17)>
To find a vector that points in a direction of no change in the function at P, we need to find a vector orthogonal to the gradient vector at P. One such vector is
n = <2,-8>
To see why this works, note that the dot product of the gradient vector and n is
<16x^3 - 8xy, -4x^2 + 2y> . <2,-8> = 32x^3 - 16xy - 4x^2y + 2y^2
Evaluating this at P(-1,1), we get
32(-1)^3 - 16(-1)(1) - 4(-1)^2(1) + 2(1)^2 = 0
So, the vector n is orthogonal to the gradient vector at P and points in a direction of no change in the function.
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The first number is 30% less than the second number and the third number is 40% more than the second number.What is the ratio of the first number to the third number?
Which linear equation represents a relation that is NOT a function? y = 3x +6 y = 9 −4y + 5x = 20 x = 7
Answer:
x = 7 is not a function--it is a vertical line.
How to work out the size of angle x with 35° degrees only
Answer:
Step-by-step explanation:
33
20 points for this IF RIGHT ANSWER
The surface area of the solids are listed below:
Case 1: A = 366 mm²
Case 2: A = 448 cm²
Case 3: A = 748 m²
Case 4: A = 221.5 in²
Case 5: A = 692 in²
Case 6: A = 276 ft²
How to determine the surface area of a solid
In this question we need to determine the surface area of six solids, that is, the sum of areas of all faces in each solid. The solids can include areas of rectangles and triangles, whose formulas are:
Rectangle
A = b · h
Triangle
A = 0.5 · b · h
Where:
A - Area of the face.b - Base of the face.h - Height of the face.Case 1
A = 2 · (13 mm) · (3 mm) + 2 · (13 mm) · (9 mm) + 2 · (9 mm) · (3 mm)
A = 78 mm² + 234 mm² + 54 mm²
A = 366 mm²
Case 2
A = 2 · (20 cm) · (6 cm) + 2 · (4 cm) · (6 cm) + 2 · (20 cm) · (4 cm)
A = 240 cm² + 48 cm² + 160 cm²
A = 448 cm²
Case 3
A = 2 · (5 m) · (14 m) + 2 · (16 m) · (14 m) + 2 · (5 m) · (16 m)
A = 748 m²
Case 4
A = 2 · (2 in) · (6.5 in) + 2 · (11.5 in) · (6.5 in) + 2 · (11.5 in) · (2 in)
A = 221.5 in²
Case 5
A = 2 · 0.5 · (12 in) · (7 in) + (11 in) · (19 in) + (9 in) · (19 in) + (12 in) · (19 in)
A = 692 in²
Case 6
A = 2 · 0.5 · (8 ft) · (3 ft) + 2 · (5 ft) · (14 ft) + (8 ft) · (14 ft)
A = 276 ft²
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Answer: Goofy Ahh
Step-by-step explanation:
That question is so Goofy Ahh
Weeee
A museum sells stone souvenirs shaped like a cone with a diameter of 4.2 centimeters and a height of 9.5 centimeters. What is the volume of each souvenir? Round to the nearest tenth
PLEASE HURRY
the volume of each souvenir is 43. 85 cm³
How to determine the volumeThe formula for calculating the volume of a cone is represented as;
V = 1/3 πr²h
Given that;
V is the volumer is the radius of the coneh is the height of the coneThen,
r = diameter/2 = 4.2 /2 = 2.1 centimeters
Substitute the values, we have
Volume = 1/3 × 3.14 × 2.1² × 9.5
find the square, we have;
Volume = 1/3 × 3.14 × 4. 41 × 9.5
Multiply the values
Volume = 131. 5503/3
divide the values
Volume = 43. 85 cm³
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Find the Differentials of
1) z = x^2 - xy^2 + 4y^5
2) f(x,y) = (3x-y)/(x+2y)
3) f(x,y) = xe^x3y
1) To find the differentials of z = x^2 - xy^2 + 4y^5, we can use the total differential formula:
dz = (∂z/∂x)dx + (∂z/∂y)dy
Taking the partial derivatives of z with respect to x and y:
∂z/∂x = 2x - y^2
∂z/∂y = -2xy + 20y^4
Substituting these into the total differential formula:
dz = (2x - y^2)dx + (-2xy + 20y^4)dy
2) To find the differentials of f(x,y) = (3x-y)/(x+2y), we can again use the total differential formula:
df = (∂f/∂x)dx + (∂f/∂y)dy
Taking the partial derivatives of f with respect to x and y:
∂f/∂x = (y-3)/(x+2y)^2
∂f/∂y = (3x-2y)/(x+2y)^2
Substituting these into the total differential formula:
df = [(y-3)/(x+2y)^2]dx + [(3x-2y)/(x+2y)^2]dy
3) To find the differentials of f(x,y) = xe^x3y, we can once again use the total differential formula:
df = (∂f/∂x)dx + (∂f/∂y)dy
Taking the partial derivatives of f with respect to x and y:
∂f/∂x = e^(x3y) + 3xye^(x3y)
∂f/∂y = 3x^2e^(x3y)
Substituting these into the total differential formula:
df = (e^(x3y) + 3xye^(x3y))dx + (3x^2e^(x3y))dy
Here are the results:
1) For z = x^2 - xy^2 + 4y^5, the partial derivatives are:
∂z/∂x = 2x - y^2
∂z/∂y = -2xy + 20y^4
2) For f(x,y) = (3x-y)/(x+2y), the partial derivatives are:
∂f/∂x = (3(x+2y) - 3(3x-y))/(x+2y)^2
∂f/∂y = (-1(x+2y) + (x+2y))/(x+2y)^2
3) For f(x,y) = xe^(x^3y), the partial derivatives are:
∂f/∂x = e^(x^3y) * (1 + 3x^2y)
∂f/∂y = xe^(x^3y) * x^3
These partial derivatives represent the differentials for each respective function.
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Can someone help me I'm stuck.
Alexandria rolled a number cube 60 times and recorded her results in the table.
What is the theoretical probability of rolling a one or two? Leave as a fraction in simplest from
The theoretical probability of rolling a one or two on a number cube is 2/5 or 0.4.
To find the theoretical probability of rolling a one or two on a number cube, we need to determine the number of outcomes that correspond to rolling a one or two, and divide that by the total number of possible outcomes.
From the table, we can see that Alexandria rolled a one or two a total of 24 times out of 60 rolls. This means that the probability of rolling a one or two is: P(1 or 2) = 24/60
Simplifying the fraction by dividing both the numerator and denominator by the greatest common factor, we get: P(1 or 2) = 4/10
This can be further reduced to: P(1 or 2) = 2/5
Therefore, the theoretical probability of rolling a one or two on a number cube is 2/5 or 0.4.
In summary, the theoretical probability is the expected probability of an event occurring, based on mathematical reasoning. Here, we used the number of favorable outcomes to calculate the probability of rolling a one or two, and expressed the answer as a fraction in simplest form.
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Beatrice used a slingshot to launch an egg into the air. She recorded the egg’s path using a motion detector. The following data represents the height (in feet) of the egg at certain time points (in seconds): { ( 0.0 , 16 ) , ( 1.7 , 20.46 ) , ( 2.5 , 23.16 ) , ( 3.7 , 23.51 ) , ( 5.1 , 20.07 ) , ( 6.6 , 12.4 ) , ( 7.3 , 5.62 ) , ( 8.0 , 0.15 ) }
Step 4: Determine the height from which the egg was launched.
8 feet
3 feet
16 feet
0 feet
Answer:
mmm, well, not much we can do per se, you'd need to use a calculator.
I'd like to point out you'd need a calculator that has regression features, namely something like a TI83 or TI83+ or higher.
That said, you can find online calculators with "quadratic regression" features, which is what this, all you do is enter the value pairs in it, to get the equation.
Step-by-step explanation:
What is the domain of the function y=^3/x-1?
The domain of the function y = (3/x) - 1 is all real numbers except x = 0
The domain of a function consists of all the valid input values for which the function is defined. In the case of the function y = (3/x) - 1, the only restriction on the domain arises from the presence of the variable x in the denominator.
To determine the domain, we need to find the values of x for which the expression 3/x is defined. Division by zero is undefined, so we must exclude any value of x that makes the denominator equal to zero.
In this case, we set the denominator, x, equal to zero and solve for x:
x = 0
Therefore, x cannot be equal to zero. All other real numbers are valid input values for this function. Therefore, the domain of the function y = (3/x) - 1 is all real numbers except x = 0. In interval notation, we can represent the domain as (-∞, 0) ∪ (0, ∞).
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