pls show simple working out

Pls Show Simple Working Out

Answers

Answer 1

Step-by-step explanation:

the angles which occupy the same relative position at each intersection where a straight line crosses two others, are called corresponding angles. If the two lines are parallel, the corresponding angles are equal.

two angles, not adjoining one another, that are formed on opposite sides of a line that intersects two other lines, are called alternate angles. If the original two lines are parallel, the alternate angles are equal.

since we are only dealing with parallel lines here, the angles are always equal.

a)

a = 60°, alternate

b)

a = 75°, corresponding

c)

a = 108°, corresponding


Related Questions

If the coordinates of point a are (-2,,3) what is the image of a after reflection over the y axis followed by dilation with a scale factor of 3 centered at the orgin

Answers

The image of point a after reflection over the y axis followed by dilation with a scale factor of 3 centered at the origin is,

⇒ (6, 9)

What is Coordinates?

A pair of numbers which describe the exact position of a point on a cartesian plane by using the horizontal and vertical lines is called the coordinates.

Given that;

The coordinates of point a are,

⇒ a =  (-2,3)

Now, We can multiply by 3 in the point;

⇒ (- 2, 3) = (- 2 × 3, 3×3)

              = (- 6, 9)

Now, After reflection over the y axis,

Image of the point are,

⇒ (6, 9)

Thus, The image of point a after reflection over the y axis followed by dilation with a scale factor of 3 centered at the origin is,

⇒ (6, 9)

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For each of the following, find the formula for an
exponential function that passes through the two points
given.
a. (-1,2) and (4,64)
f(x)=?
b. (-3,9) and (2,1)
g(x)=?

Answers

The exponential function that passes through the two points given is (a) f(x) = 4(2ˣ) and (b) g(x) = (9^(2/5)) ((1/9)^(1/5))ˣ.

To find the formula for an exponential function that passes through two points, we can use the following steps:


1. Use the general form of an exponential function: f(x) = abˣ
2. Plug in the x and y values from the first point into the equation and solve for b.
3. Plug in the x and y values from the second point and the value of b into the equation and solve for a.
4. Substitute the values of a and b back into the general equation to get the formula for the function.

For point a:

1. f(x) = abˣ
2. 2 = ab⁻¹
3. 64 = ab⁴
4. Divide the equations to eliminate a: (64/2) = (ab⁴)/(ab⁻¹) = b⁵
5. Solve for b: b = 2
6. Substitute b back into one of the equations and solve for a: 2 = a(2)⁻¹ = a/2, a = 4
7. Substitute a and b back into the general equation: f(x) = 4(2)ˣ

For point b:

1. g(x) = abˣ
2. 9 = ab⁻³
3. 1 = ab²
4. Divide the equations to eliminate a: (1/9) = (ab²)/(ab⁻³) = b⁵
5. Solve for b: b = (1/9)^(1/5)
6. Substitute b back into one of the equations and solve for a: 9 = a((1/9)^(1/5))⁻³ = a(9^(3/5)), a = 9^(2/5)
7. Substitute a and b back into the general equation: g(x) = (9^(2/5))((1/9)^(1/5))ˣ

So the formulas for the exponential functions are:
f(x) = 4(2)ˣ
g(x) = (9^(2/5)) ((1/9)^(1/5))ˣ

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chess vs cribbage 2x4y=60

Answers

30 peοple are playing chess and 30 peοple are playing cribbage.

What is the system οf linear equatiοns?

A system οf linear equatiοns is a set οf twο οr mοre linear equatiοns with multiple variables that are sοlved simultaneοusly. The gοal οf sοlving a system οf linear equatiοns is tο find the values οf the variables that satisfy all the equatiοns in the system.

A linear equatiοn is an equatiοn in which the variables appear οnly tο the first pοwer, and the cοefficients οf the variables are cοnstants. Fοr example, the equatiοn y = 3x + 2 is a linear equatiοn, where y and x are the variables, and 3 and 2 are the cοefficients.

A system οf linear equatiοns can have οne unique sοlutiοn, nο sοlutiοn, οr infinitely many sοlutiοns. The number οf sοlutiοns depends οn the number οf equatiοns and variables in the system, and the relatiοnships between them. There are variοus methοds tο sοlve a system οf linear equatiοns, such as substitutiοn, eliminatiοn, and matrix methοds.

Let's assume that there are x peοple playing chess and y peοple playing cribbage. Since everyοne is playing either chess οr cribbage, we knοw that:

x + y = 60

We alsο knοw that chess is a twο-player game, while cribbage is a fοur-player game. Therefοre, the tοtal number οf players in the games must be a multiple οf 2 and 4. This means that:

2x + 4y = 60

We can simplify this equatiοn by dividing bοth sides by 2

x + 2y = 30

Nοw we have twο equatiοns:

x + y = 60

x + 2y = 30

We can sοlve fοr x by subtracting the secοnd equatiοn frοm the first equatiοn:

x + y - (x + 2y) = 60 - 30

-y = -30

y = 30

Substituting this value οf y intο the first equatiοn, we get:

x + 30 = 60

x = 30

Therefοre, 30 peοple are playing chess and 30 peοple are playing cribbage.

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Complete question:

60 people attend a game night. Everyone chooses to play chess, a two-player game, or cribbage, a four-player game. All 60 people are playing either chess or cribbage. There are 3 more games of cribbage being played than games of chess being played. How many of each game are being played?

8 chess, 15 cribbage

30 chess, 30 cribbage

8 chess, 11 cribbage

30 chess, 15 cribbage

Exercise - 4.4 f mathematical induction, prove that, for n>=1 1^(3)+2^(3)+3^(3)+cdots +n^(3)=((n(n+1))/(2))^(2)

Answers

The equation is true for n = k+1, so the statement is true for all n>=1 by mathematical induction.

Proof by mathematical induction:

Base case: n = 1
1^(3) = ((1(1+1))/(2))^(2)
1 = ((2)/(2))^(2)
1 = 1^(2)
1 = 1
The base case is true.

Inductive step:
Assume that the statement is true for n = k, that is:
1^(3)+2^(3)+3^(3)+...+k^(3) = ((k(k+1))/(2))^(2)

Now we need to prove that the statement is also true for n = k+1:
1^(3)+2^(3)+3^(3)+...+k^(3)+(k+1)^(3) = (((k+1)((k+1)+1))/(2))^(2)

Substituting the assumption into the left-hand side of the equation:
((k(k+1))/(2))^(2) + (k+1)^(3) = (((k+1)((k+1)+1))/(2))^(2)

Expanding the right-hand side of the equation:
((k(k+1))/(2))^(2) + (k+1)^(3) = (((k+1)(k+2))/(2))^(2)

Simplifying the equation:
(k^(2)(k+1)^(2))/(2^(2)) + (k+1)^(3) = ((k+1)^(2)(k+2)^(2))/(2^(2))

Multiplying both sides of the equation by 2^(2):
(k^(2)(k+1)^(2)) + 2^(2)(k+1)^(3) = (k+1)^(2)(k+2)^(2)

Expanding the equation:
k^(2)(k+1)^(2) + 2^(2)(k+1)^(3) = (k+1)^(2)(k^(2)+4k+4)

Simplifying the equation:
k^(2)(k+1)^(2) + 2^(2)(k+1)^(3) = k^(2)(k+1)^(2) + 4k(k+1)^(2) + 4(k+1)^(2)

Subtracting k^(2)(k+1)^(2) from both sides of the equation:
2^(2)(k+1)^(3) = 4k(k+1)^(2) + 4(k+1)^(2)

Factoring out (k+1)^(2) from the right-hand side of the equation:
2^(2)(k+1)^(3) = (k+1)^(2)(4k+4)

Simplifying the equation:
2^(2)(k+1)^(3) = 4(k+1)^(2)(k+1)

Dividing both sides of the equation by (k+1)^(2):
2^(2)(k+1) = 4(k+1)

Simplifying the equation:
2^(2)(k+1) = 2^(2)(k+1)

The equation is true for n = k+1, so the statement is true for all n>=1 by mathematical induction.

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How do you do c) really need help!!

Answers

just add the 2 numbers together

how many solutions does the system of equations 4x+2y=6 and y=-2x+6 have?

Answers

The system of equations 4x + 2y = 6 and y = -2x + 6  have infinite many solutions

What is an equation?

An equation is an expression that shows the relationship between two or more numbers and variables. Equations can either be linear, quadratic, cubic and so on depending on the degree.

Given the system of equation:

4x + 2y = 6

Divide through by 2:

2x + y = 3

y = -2x + 6     (1)

The second equation is:

y = -2x + 6      (2)

Since both equations are the same hence the system of equations have infinite many solutions

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Determine the intervals where the following function is increasing or decreasing. g(x) = 3-1/zx, x<-2 . 4+3/2x, x>-2 Increasing on: (-2,infinity) Decreasing on: (-4,-2)

Answers

To determine the intervals where a function is increasing or decreasing, we need to take the derivative of the function and find the critical points. The critical points are where the derivative is equal to zero or undefined.

First, let's take the derivative of the function:
g'(x) = -1/(zx)^2, x<-2 . 3/2, x>-2

Now, let's find the critical points:
-1/(zx)^2 = 0 -> There are no values of x that will make this equation true, so there are no critical points for x<-2.
3/2 = 0 -> There are no values of x that will make this equation true, so there are no critical points for x>-2.

Since there are no critical points, the function is either always increasing or always decreasing. To determine which one it is, we can pick a value of x in each interval and plug it into the derivative:

For x<-2, let's pick x=-3:
g'(-3) = -1/(-3z)^2 = 1/(9z^2) > 0

Since the derivative is positive, the function is increasing on the interval (-infinity, -2).
For x>-2, let's pick x=0:
g'(0) = 3/2 > 0

Since the derivative is positive, the function is also increasing on the interval (-2, infinity).

Therefore, the function is increasing on the entire domain of the function, which is (-infinity, infinity).

Answer: Increasing on: (-infinity, infinity) Decreasing on: None

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Given z^(2)+2z-15=(z-3)(z+5), write another polynomial in general form that has a factored form of (z-3)(z+5) with different values for z.

Answers

Another polynomial with the same factored form of (z-3)(z+5) but different values for z is 2z^(2)+4z-30.

To find another polynomial with the same factored form, we can simply multiply the given factored form by a constant. This will change the values of z, but the factored form will remain the same.

For example, let's multiply the factored form by 2:

2(z-3)(z+5) = 2z^(2)+4z-30

In general form, this polynomial is 2z^(2)+4z-30.

We can see that the factored form is still (z-3)(z+5), but the values of z have changed. In the original polynomial, z^(2)+2z-15, the values of z were 3 and -5. In the new polynomial, 2z^(2)+4z-30, the values of z are 3/2 and -5/2.

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the quotient and remainder using long division for: (2x^(3)-6x^(2)+7x-11)/(2x^(2)+5)

Answers

The quotient and remainder using long division for [tex](2x^(3)-6x^(2)+7x-11)/(2x^(2)+5)[/tex] are x-11/2 and 55/2x-11, respectively.

The quotient and remainder using long division for the given expression can be found by following these steps:

Step 1: Set up the long division as follows:
[tex]```2x^(2)+5 | 2x^(3)-6x^(2)+7x-11         |----------------------         |```[/tex]

Step 2: Divide the first term of the dividend (2x^(3)) by the first term of the divisor (2x^(2)) to get the first term of the quotient (x):
[tex]```2x^(2)+5 | 2x^(3)-6x^(2)+7x-11         |----------------------         | x```[/tex]

Step 3: Multiply the first term of the quotient (x) by the divisor (2x^(2)+5) and subtract the result from the dividend:
[tex]```2x^(2)+5 | 2x^(3)-6x^(2)+7x-11         |-(2x^(3)+5x)         |----------------------         |        -11x^(2)+7x-11```[/tex]

Step 4: Repeat steps 2 and 3 until the degree of the remainder is less than the degree of the divisor:
[tex]```2x^(2)+5 | 2x^(3)-6x^(2)+7x-11         |-(2x^(3)+5x)         |----------------------         | x     -11x^(2)+7x-11         |      -(-11x^(2)-55/2x)         |----------------------         |         55/2x-11```[/tex]

Step 5: The final result is the quotient and remainder:
[tex]```Quotient = x-11/2Remainder = 55/2x-11```[/tex]

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"What are the corner points?
What is the solution to the linear programming problem?"
Minimize: C = 3x – 3y Subject to: 3x – y >= 2 x + y <= 5 x >= 0, y >= 0

Answers

The minimum value of the objective function is -15, which occurs at the corner point (0, 5).

The corner points of a linear programming problem are the points where the constraints intersect. These points can be found by solving the system of inequalities for each pair of constraints.

For this problem, we can find the corner points by solving the system of inequalities for each pair of constraints:

3x – y >= 2 and x + y <= 5:
- Add y to both sides of the first inequality: 3x >= 2 + y
- Subtract 2 from both sides of the first inequality: 3x - 2 >= y
- Substitute 3x - 2 for y in the second inequality: x + (3x - 2) <= 5
- Simplify: 4x <= 7
- Divide by 4: x <= 7/4
- Substitute 7/4 for x in the first inequality: 3(7/4) - 2 >= y
- Simplify: 5/4 >= y

The first corner point is (7/4, 5/4).

3x – y >= 2 and x >= 0:
- Set x = 0 and solve for y: 3(0) - y >= 2, y <= -2
- Set y = 0 and solve for x: 3x - 0 >= 2, x >= 2/3

The second corner point is (2/3, 0).

x + y <= 5 and x >= 0:
- Set x = 0 and solve for y: 0 + y <= 5, y <= 5
- Set y = 0 and solve for x: x + 0 <= 5, x <= 5

The third corner point is (0, 5).

x + y <= 5 and y >= 0:
- Set x = 0 and solve for y: 0 + y <= 5, y <= 5
- Set y = 0 and solve for x: x + 0 <= 5, x <= 5

The fourth corner point is (5, 0).

Now we can plug each corner point into the objective function to find the minimum value:

C = 3x – 3y

C = 3(7/4) - 3(5/4) = 3
C = 3(2/3) - 3(0) = 2
C = 3(0) - 3(5) = -15
C = 3(5) - 3(0) = 15

Therefore, the solution to the linear programming problem is (0, 5).

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so that \( i A_{1} \) is emalier than \( \left.A_{2} A_{2}\right) \) 7. [-81.19 Points] 5PRECALC7 6.5.023. so that \( A_{1} \) is smaller than \( A A_{2} \)-) \[ \begin{array}{l} b=27, c=33, \quad A=2

Answers

The answer to the question is that \( A_{1} \) is smaller than \( A_{2} \)

To begin, it is important to note that the terms "emalier" and "5PRECALC7" are not relevant to the question and can be ignored. Additionally, there are several typos and extraneous information that can also be ignored. The main focus of the question is to determine the relationship between \( A_{1} \) and \( A_{2} \).

From the information provided, it is clear that \( A_{1} \) is smaller than \( A_{2} \). This is because the value of \( A_{1} \) is given as 2, while the values of \( b \) and \( c \) are 27 and 33, respectively. Since \( A_{2} \) is the sum of \( b \) and \( c \), it is clear that \( A_{2} \) is larger than \( A_{1} \).

Therefore, the answer to the question is that \( A_{1} \) is smaller than \( A_{2} \).

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the class survayed 100 other students and found that 23% chose in-line skating as their favorite. Estimate how many students in both surveys combined chose in-line skating as their favorite.

Answers

An estimated 46 students in both surveys combined chose in-line skating as their favorite.

To estimate how many students in both surveys combined chose in-line skating as their favorite, we can use the given percentage and the total number of students surveyed.
First, we need to calculate the number of students who chose in-line skating in the first survey. We can do this by multiplying the percentage by the total number of students surveyed:
23% × 100 = 23
So, 23 students in the first survey chose in-line skating as their favorite.
Next, we need to add this number to the number of students who chose in-line skating in the second survey. Since we don't have information about the second survey, we can assume that the same percentage of students chose in-line skating:
23% × 100 = 23
Finally, we can add the two numbers together to get the total number of students who chose in-line skating in both surveys:
23 + 23 = 46

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Simplify: 18+7/10 -16+26/6 A. -25/6 B. -5/6 C. 5/6 D. 25/6

Answers

Step-by-step explanation:

[tex]18 + \frac{7}{10} - 16 + \frac{26}{6}\\ 30(18) + 30 \times \frac{7}{10} - 30(16) + 30 \times \frac{26}{6} \\ 540 + 21 - 480 + 130 \\ = 211[/tex]

The Lcm of 10 and 6

is 30

sorry but I got my answer to be 211

Rachel, Kayla, and Francesca raised $35.67 for their basketball team. Rachel and Kayla each raised the same amount, and Francesca raised $10.50 more than each of them.

If x = the amount raised by Kayla, choose the expressions that represent the amount each other player raised.

Answers

Answer:

Kayla and Rachel raised $8.39, Francesca raised $18.89.

Step-by-step explanation:

Knowing that $35.67 is the total amount raised, that Rachel and Kayla raised the same amount (x) each, and that Francesca raised $10.50 more than them (x + 10.50), then the equation would look like:

35.67 = x + x + (x + 10.50)

or

35.67 = 3x + 10.50

From here, you can solve algebraically.

Isolate the variable by subtracting 10.50 from both sides

25.17 = 3x

Then, find X by dividing both sides by 3:

x = 8.39

Knowing that Kayla and Rachel raised $8.39 each, to find Francesca's contribution you can either:

A) Subtract Kayla and Rachel's contributions from the total amount:

     35.67 - 8.39 - 8.39 = 18.89

or

B) Add $10.50 to the amount that Kayla and Rachel raised:

     8.39 + 10.50 = 18.89

I need help with this! If you answer please explain!

Answers

Answer:

Below

Step-by-step explanation:

Diameter = 20 inches     radius = 10 inches

Area = pi r^2 = 3.14 * 10^2 = 314 in^2

Jonah is a baker who specializes in wedding cakes. He would like to calculate the
cost of decorating a 3-tiered circular cake with fresh flowers around the base of each level. The bottom cake has a 14-inch diameter, the middle layer has a 10-inch diameter, and the top layer has a 6-inch diameter. All three layers are stacked on top of each other without spacers. He wants to place red roses without their stems around the bottom of each layer. The roses are 1½ inches wide and are sold for $0.99 each. How much will it cost Jonah to decorate the cake with the roses?

Answers

It wiII cοst Jοnah $63.36 tο decοrate the 3-tiered circuIar wedding cake with fresh red rοses arοund the base οf each IeveI.

Tο caIcuIate the cοst οf decοrating the cake with rοses, we need tο first determine the circumference οf each tier, which wiII teII us hοw many rοses are needed fοr each tier.

The circumference οf a circIe can be caIcuIated using the fοrmuIa C = πd, where C is the circumference, π is the mathematicaI cοnstant pi (apprοximateIy 3.14), and d is the diameter.

Fοr the bοttοm tier with a diameter οf 14 inches, the circumference is C = πd = 3.14 x 14 = 43.96 inches.

Fοr the middIe tier with a diameter οf 10 inches, the circumference is C = πd = 3.14 x 10 = 31.4 inches.

Fοr the tοp tier with a diameter οf 6 inches, the circumference is C = πd = 3.14 x 6 = 18.84 inches.

Nοw, we need tο determine hοw many rοses are needed fοr each tier. Tο dο this, we need tο caIcuIate hοw many rοses wiII fit arοund the circumference οf each tier. We can dο this by dividing the circumference οf each tier by the width οf the rοses, which is 1.5 inches.

Fοr the bοttοm tier: 43.96 inches / 1.5 inches per rοse = 29.3, rοunded up tο 30 rοses.

Fοr the middIe tier: 31.4 inches / 1.5 inches per rοse = 20.9, rοunded up tο 21 rοses.

Fοr the tοp tier: 18.84 inches / 1.5 inches per rοse = 12.6, rοunded up tο 13 rοses.

Nοw that we knοw hοw many rοses are needed fοr each tier, we can caIcuIate the tοtaI cοst οf the rοses. Each rοse cοsts $0.99, sο the cοst οf the rοses fοr each tier is:

Bοttοm tier: 30 rοses x $0.99 per rοse = $29.70

MiddIe tier: 21 rοses x $0.99 per rοse = $20.79

Tοp tier: 13 rοses x $0.99 per rοse = $12.87

The tοtaI cοst οf decοrating the cake with rοses is the sum οf the cοsts fοr each tier:

$29.70 + $20.79 + $12.87 = $63.36

Therefοre, it wiII cοst Jοnah $63.36 tο decοrate the 3-tiered circuIar wedding cake with fresh red rοses arοund the base οf each IeveI.

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Simplify 3x to the power of 2 x 4x to the power of 5

Answers

Answer:

I found this

Step-by-step explanation:

To simplify 3x² * 4x⁵, we can multiply the coefficients (numbers in front of the variables) and add the exponents of x:

3x² * 4x⁵ = (3 * 4) x^(2+5) = 12x^7

Therefore, the simplified expression is 12x^7.

suppose 8x + 16 ice cream cones were sold on saturday and 7x - 9 were sold on sunday. what is the total number of ice cream cones sold?

Answers

Answer:

this is right.....

Step-by-step explanation:

15x + 6

Bashir walked 10 miles in 4 hours. Fill out a table of equivalent ratios and plot the points on the coordinate axes provided.

Answers

The missing values are 2 and 35 respectively. The points plotted have been attached below. The solution has been obtained by using equivalent ratio.

What is an equivalent ratio?

When we compare two ratios, they are said to be equivalent. To determine whether two or more ratios are equivalent, they can be compared to one another.

We are given that Bashir walked 10 miles in 4 hours and the table is of equivalent ratios.

The ratio comes out to be 2.5.

So, he will walk 5 miles in 2 hours.

Similarly, in 14 hours he will walk 35 miles.

The points have been plotted on the coordinate axes and has been attached below.

Hence, the missing values are 2 and 35 respectively.

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A)
Discuss the main quality standards and provide some examples to
show where these standards are effective.
B) Why is translation quality so critical? Select an industry
and show how translation qual

Answers

A) In the technology industry, usability and security are essential for creating user-friendly and secure software and hardware. Without these quality standards, products and services may not function properly or may even pose risks to consumers.

B) In the legal industry, translation quality is also crucial for ensuring that contracts and other legal documents are accurately translated and understood by all parties involved. Without high-quality translation, there is a risk of miscommunication and misunderstandings, which can have serious consequences.

The main quality standards include reliability, validity, usability, and security. These standards are effective in various industries and settings. For example, in the medical field, reliability and validity are crucial in ensuring that medical devices and treatments are safe and effective for patients. In the technology industry, usability and security are essential for creating user-friendly and secure software and hardware. Without these quality standards, products and services may not function properly or may even pose risks to consumers.

Translation quality is critical because it ensures that information is accurately conveyed across different languages and cultures. This is especially important in industries such as healthcare, where accurate translation of medical information can be a matter of life or death. In the legal industry, translation quality is also crucial for ensuring that contracts and other legal documents are accurately translated and understood by all parties involved. Without high-quality translation, there is a risk of miscommunication and misunderstandings, which can have serious consequences.

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Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is:
O 9
O 11
O 13
O 15

Answers

The answer of third integer is 15.

To solve this problem, we can use algebra. Let's call the first of the three consecutive odd integers "x." The next two consecutive odd integers would then be "x + 2" and "x + 4."

The problem tells us that three times the first integer is 3 more than twice the third, so we can write an equation:

3x = 2(x + 4) + 3

Simplifying the equation, we get:

3x = 2x + 8 + 3

x = 11

So the first integer is 11, and the third integer is 11 + 4 = 15.

Therefore, the correct answer is O 15.

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Hi so my question is what are all of the expressions equivalent to 11x + 10 ? I am very confused..

Answers

There are infinitely many expressions equivalent to 11x + 10, including 22x + 20, 11(x+1)-1, -11(-x)-10, and 11(x+2)-12.

What is expression ?

In mathematics, an expression is a combination of numbers, symbols, and/or variables that are put together in a meaningful way, usually to represent a quantity or a mathematical relationship.

There are infinitely many expressions that are equivalent to 11x + 10, because you can add or subtract any expression to both sides of the equation to get a new equivalent expression. Here are some examples:

22x + 20: This is equivalent to 11x + 10 because if you distribute 11 to x and 10, you get 11x + 10.

11(x + 1) - 1: This is also equivalent to 11x + 10 because if you distribute 11 to x and 1, you get 11x + 11 - 1, which simplifies to 11x + 10.

-11(-x) - 10: This is equivalent to 11x + 10 because if you distribute -11 to -x, you get 11x + 10.

11(x + 2) - 12: This is also equivalent to 11x + 10 because if you distribute 11 to x and 2, you get 11x + 22 - 12, which simplifies to 11x + 10.

In general, any expression of the form 11x + k, where k is a constant, is equivalent to 11x + 10.

Therefore, there are infinitely many expressions equivalent to 11x + 10, including 22x + 20, 11(x+1)-1, -11(-x)-10, and 11(x+2)-12.

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What is the simplified form of StartRoot 400 x Superscript 100 Baseline EndRoot ?

Answers

The simplified root of the given root i.e. √(400x¹⁰⁰) is 20x⁵⁰. The solution has been obtained by using the law of indices.

What is the law of indices?

The guidelines for simplifying expressions containing powers of the same base number are known as index laws.

We are given an expression as √(400x¹⁰⁰).

Using law of indices,

⇒ √(400x¹⁰⁰) = √400 * √(x¹⁰⁰)             ( as √ab = √a * √b)

⇒ √(400x¹⁰⁰) = 20 √(x¹⁰⁰)

⇒ √(400x¹⁰⁰) = 20 √(x⁵⁰ * x⁵⁰)             ( as a⁴ = a² + a²)

√(400x¹⁰⁰) = 20x⁵⁰

Hence, the simplified root of the given root i.e. √(400x¹⁰⁰) is 20x⁵⁰.

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What is the volume (in cubic units) of a sphere with a radius of 15 units?

Answers

Answer:

The volume of a sphere is given by the formula V = (4/3)πr^3, where r is the radius.

Substituting r = 15, we get:

V = (4/3)π(15)^3

V = (4/3)π(3375)

V = 4π(1125)

V = 4500π

Therefore, the volume of the sphere with a radius of 15 units is 4500π cubic units. This can also be approximated as 14,137.17 cubic units by using a value of 3.14 for π and rounding to the nearest hundredth.

Step-by-step explanation:

Which is the correct factorization for the Difference of Squares or a^(2)-b^(2) ?

Answers

The correct factorization for the Difference of Squares or a²-b² is (a+b)(a-b). This is because when you multiply (a+b)(a-b), you get a²- ab + ab - b², which simplifies to a²-b².

Here is a step-by-step explanation of how to factor the Difference between Squares:

Step 1: Identify the two terms that are being squared. In this case, a and b are the terms being squared.
Step 2: Write the two terms with a plus sign in between them in one set of parentheses and with a minus sign in between them in another set of parentheses. This will give you (a+b)(a-b).
Step 3: Multiply the two sets of parentheses together to check your answer. You should get a²-b².
So, the correct factorization for the Difference of Squares or a²-b² is (a+b)(a-b).

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Find the value of X Round your answer to the nearest tenth.

(A right-angled triangle with two adjacent sides to the right angle labeled 4.6 feet and 3.5 feet. The length of hypotenuse is labeled 5.8 feet. An altitude drawn from the right angle vertex on hypotenuse is labeled x.)

Answers

Answer: X = 14

Step-by-step explanation: (:

Which numbers below are ratonal? (Select all that apply)

A. -7

B. 36.545454....

C. 9.149278643

D. 7/11

E. 10√

F. 25√+ 3

G. 2√+9√

Answers

Answer:

a,b,c,d

Step-by-step explanation:

all are rational except efg

what is 1 and 1/7 x 3/5

Answers

1 and 1/7 multiplied by 3/5 is equal to 24/35 or 0.6857 (rounded to four decimal places).

What do you mean by decimal?

In mathematics, a decimal is a number that represents a fraction or a part of a whole using a base-ten positional numeral system.

To multiply 1 and 1/7 by 3/5, we can first convert the mixed number to an improper fraction.

1 and 1/7 can be written as:

(7/7 * 1) + 1/7 = 7/7 + 1/7 = 8/7

So, we have:

1 and 1/7 = 8/7

Now, we can multiply 8/7 by 3/5 as follows:

(8/7) * (3/5) = (8 * 3) / (7 * 5) = 24/35

Therefore, 1 and 1/7 multiplied by 3/5 is equal to 24/35 or 0.6857 (rounded to four decimal places).

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Find all integer values of k such that [18]25 is equal to
[7]k
25?
(Explain and/or show work.))

Answers

The integer values of k such that [18]25 is equal to [7]k are 4, 11, 18, 25

To find all integer values of k such that [18]25 is equal to [7]k, we need to use the following steps:

Start with the given equation: [18]25 = [7]k

Use the definition of modular arithmetic to write the equation in a different form: 25 ≡ k (mod 7)

Simplify the equation: 4 ≡ k (mod 7)

Find all integer values of k that satisfy the equation. The smallest positive integer value of k that satisfies the equation is 4. We can add multiples of 7 to find other integer values of k: 4 + 7 = 11, 4 + 14 = 18, 4 + 21 = 25, etc.

The integer values of k that satisfy the equation are 4, 11, 18, 25, etc.


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6. Consider the expansion of x^2 (3x^2 + k/x)^8. The constant term is 16128. Find k. [7 marks]

Answers

The value of k is ∛√199.

Consider the expansion of x^2(3x^2 + k/x)^8. The constant term is 16128. We need to find the value of k.

The expansion of (3x^2 + k/x)^8 will have terms of the form (3x^2)^a(k/x)^b, where a + b = 8. The constant term will be the term where the powers of x cancel out, so we need to find a and b such that 2a - b = 0.

Solving for a and b, we get a = 4 and b = 8. So the constant term will be (3x^2)^4(k/x)^8 = 81x^8(k^8/x^8) = 81k^8.

Setting this equal to 16128 and solving for k, we get:

81k^8 = 16128
k^8 = 16128/81
k^8 = 199
k = ∛√199

Therefore, the value of k is ∛√199.

k = ∛√199.

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