Answer:
Subtract 1 from both sides.
Answer:
subtract 1 from both sides. because taking out the 1 from 1 and 1 from 17 will equal 16. which leaves t/4=16
13, 9, 17, 12, 18, 12, 17, 7, 16, 19
so what is the Mean Median_____ Range
PLEASEEEEEEEEEEEEEEEEEEE
Answer:
< 3 = 3x + 105°
Step-by-step explanation:
There is remot angle theory which is the exterior angle is congrent to the other non adjecent angle in triangle.
so <1 + <EDF = <3
(3x + 15 ) ° + 90° = <3
3x°+ 105° = <3
< 3 = 3x + 105° .... so the measur of angle 3 interms of x is 3x + 105°
What is the image of the point (-3,8) after a rotation of 180 counterclockwise about the origin
The image of point (-3, 8) after a rotation of 180 counterclockwise about the origin is (3, -8)
What is transformation?Transformation is the movement of a point in the coordinate plane from one location to another. Transformation can either be reflection, rotation, translation and dilation.
Rotation is the flipping of a figure about a point in the coordinate plane; this point of rotation is usually origin.
(x, y) → (-x, -y) represents a rotation 180° counterclockwise.
The image of point (-3, 8) after a rotation of 180 counterclockwise about the origin is (3, -8)
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Find dx/dy, if x=sin^3t,y=cos^3t.
dx/dy = -sin(t)/cos(t) when x = sin^3(t) and y = cos^3(t).
To find dx/dy, we first need to find dx/dt and dy/dt, and then we can use the chain rule.
Given x = sin^3(t) and y = cos^3(t),
dx/dt = d(sin^3(t))/dt = 3sin^2(t) * cos(t) (using the chain rule)
dy/dt = d(cos^3(t))/dt = -3cos^2(t) * sin(t) (using the chain rule)
Now, we can find dx/dy by dividing dx/dt by dy/dt:
dx/dy = (dx/dt) / (dy/dt) = (3sin^2(t) * cos(t)) / (-3cos^2(t) * sin(t))
Simplify the expression:
dx/dy = -sin(t)/cos(t)
So, dx/dy = -sin(t)/cos(t) when x = sin^3(t) and y = cos^3(t).
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A 4.0kg box slides with an initial speed of 3.0 m/s, end fraction towards a spring on a frictionless horizontal surface. when the box hits the spring, the spring compressed by 0.30m. what is the spring constant.
The spring constant is 180 N/m.
To solve for the spring constant, we can use the equation: k = (m * g) / x
where k is the spring constant, m is the mass of the box, g is the acceleration due to gravity (9.8 m/s^2), and x is the compression distance of the spring.
First, let's get the final velocity of the box when it hits the spring. We can use the equation:
v^2 = u^2 + 2as
where v is the final velocity (0 m/s), u is the initial speed (3.0 m/s), a is the acceleration (which is constant and equal to -k/m since the force from the spring is in the opposite direction of the box's motion), and s is the compression distance of the spring (0.30 m).
Rearranging the equation, we get:
k/m = (u^2 - v^2) / (2s)
k/4.0 = (3.0^2 - 0^2) / (2 * 0.30)
k/4.0 = 45
k = 180 N/m
Therefore, the spring constant is 180 N/m.
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The number of males of a species of whale in Antarctic feeding grounds is w(x) when x million squid are present. Squid availability in the feeding grounds changes according to the surface temperature of the water so that the number of available squid is x(t) when the water is t°F. In December, when water temperature is near 32°F, there are an estimated 710 million deep-water squid in the feeding grounds, with the number of squid increasing by approximately 3 million squid per degree. At the same time, there are 6,000 adult male whales in the Antarctic feeding grounds, with the number of male whales increasing by 4 whales per million squid. Evaluate each of the following expressions when the surface temperature of the ocean is 32°F, and write a sentence interpreting each value. (a) Evaluate x(t). x(32) = million squid Write a sentence interpreting the value. When water temperature is near 32°F, the squid population is million squid. (b) Evaluate w(x). w(710) = whales Write a sentence interpreting the value. When there are 710 million squid there are adult male whales in the Antarctic feeding grounds. (C) Evaluate x million squid per degree Write a sentence interpreting the value. When water temperature is near 32°F, the squid population is increasing by million squid per degree. (d) Evaluate dw dw whales per million squid dx x = 710 Write a sentence interpreting the value.
The number of adult male whales in Antarctic feeding grounds, w(x), depends on the number of million squid available, x(t). At a surface temperature of 32°F, x(32) = 710 million squid, and w(710) = 6000 whales. The population of squid is increasing by 3 million per degree, and the population of whales is increasing by 4 whales per million squid.
The following expressions when the surface temperature of the ocean is 32°F is
(a) To evaluate x(t) when t=32°F, we use the given information that "there are an estimated 710 million deep-water squid in the feeding grounds, with the number of squid increasing by approximately 3 million squid per degree." Thus, at 32°F, we have:
x(32) = 710 + 3(32-32) = 710 million squid
Interpretation: When the water temperature is near 32°F, there are approximately 710 million deep-water squid in the feeding grounds.
(b) To evaluate w(x) when x=710 million squid, we use the given information that "there are 6,000 adult male whales in the Antarctic feeding grounds, with the number of male whales increasing by 4 whales per million squid." Thus, at 710 million squid, we have:
w(710) = 6,000 + 4(710-710) = 6,000 adult male whales
Interpretation: When there are approximately 710 million deep-water squid in the feeding grounds, there are approximately 6,000 adult male whales in the Antarctic feeding grounds.
(c) To evaluate dx/dt when t=32°F, we use the given information that "the number of available squid is x(t) when the water is t°F, with the number of squid increasing by approximately 3 million squid per degree." Thus, at 32°F, we have:
dx/dt = 3 million squid per degree
Interpretation: When the water temperature is near 32°F, the population of deep-water squid in the feeding grounds is increasing by approximately 3 million squid per degree.
(d) To evaluate dw/dx when x=710 million squid, we use the given information that "the number of male whales increases by 4 whales per million squid." Thus, at 710 million squid, we have:
dw/dx = 4 whales per million squid
Interpretation: For every additional 1 million deep-water squid that are present in the feeding grounds, the number of adult male whales in the Antarctic feeding grounds increases by approximately 4 whales.
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Every day, Carmen walks to the bus stop and the amount of time she will have to wait for the bus is between 0 and 12 minutes, with all times being equally likely (i. E. , a uniform distribution). This means that the mean wait time is 6 minutes, with a variance of 12 minutes. What is the probability that her total wait time over the course of 60 days is less than 5. 5 hours
The probability that Carmen's total wait time over the course of 60 days is less than 5.5 hours is approximately 0.0746.
The total wait time over 60 days will have a mean of 360 minutes (6 minutes per day x 60 days) and a variance of 720 minutes (12 minutes per day x 60 days). Since the wait times are uniformly distributed, the total wait time over 60 days will follow a normal distribution.
To find the probability that the total wait time over 60 days is less than 5.5 hours, we need to standardize the value using the z-score formula:
z = (x - μ) / σ
where x is the total wait time in minutes, μ is the mean total wait time in minutes, and σ is the standard deviation of the total wait time in minutes.
Substituting the values, we get:
z = (330 - 360) / sqrt(720) = -1.4434
Using a standard normal distribution table or calculator, we find that the probability of a z-score less than -1.4434 is 0.0746.
Therefore, the probability that Carmen's total wait time over the course of 60 days is less than 5.5 hours is approximately 0.0746.
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[tex]4^3\sqrt{-88}[/tex]
Help I don't know where the negative goes.
if you meant simplification
[tex]4^3\sqrt{-88}\implies 64\sqrt{-88}\implies 64\sqrt{(-1)(2^2)(2)(11)}\implies 64(2)\sqrt{(-1)(2)(11)} \\\\\\ 128\sqrt{(2)(11)}\cdot \sqrt{-1}\implies 128\sqrt{22}~i[/tex]
The money in Maya's college savings account earns 2 1/5% interest. Which value is less than 2 1/5%?
A. 0. 0215
B. 11/5
C. 0. 022
D. 11/500
A value that is less than 2 1/5% from the given data is 0. 0215. Option A is the correct answer.
A fraction represents a part of a number or any number of equal parts. There is a fraction, containing numerator and denominator.
To find a value that is less than 2 1/5% we need to find the decimal number of a given fraction. to convert the given fraction into decimal form we need to divide the given fraction by 100.
= 2 1/5% / 100
= (2 + (1/5)) / 100
= 0.022
A value that is less than 0.022 from the given data is 0. 0215.
Therefore, a value less than 2 1/5% is 0. 0215.
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What is the equation of a circle with center (2,3) that passes through the point (5, 3)?
The equation of the circle with center (2, 3) that passes through the point (5, 3) is [tex](x - 2)^2 + (y - 3)^2 = 9.[/tex]
To find the equation of a circle with center (2, 3) that passes through the point (5, 3), we'll need to use the standard equation of a circle and the given information.
The standard equation of a circle is[tex](x - h)^2 + (y - k)^2 = r^2[/tex], where (h, k) is the center and r is the radius.
Step 1: Substitute the center coordinates (h, k) = (2, 3) into the equation:
[tex](x - 2)^2 + (y - 3)^2 = r^2[/tex]
Step 2: Use the point (5, 3) to find the radius. Plug the coordinates of the point into the equation and solve for [tex]r^2[/tex]:
[tex](5 - 2)^2 + (3 - 3)^2 = r^2\\3^2 + 0^2 = r^2\\9 = r^2[/tex]
Step 3: Plug[tex]r^2[/tex] back into the equation:
[tex](x - 2)^2 + (y - 3)^2 = 9[/tex]
So, the equation of the circle with center (2, 3) that passes through the point (5, 3) is [tex](x - 2)^2 + (y - 3)^2 = 9.[/tex]
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Check each set of side lengths to see if it would be a
right triangle.
Remember plug the numbers into the Pythagorean
Theorem to see if they work!
Select ALL that are right traingles!
A 5,8, and 9
B 20, 21, and 29
C 9, 12, and 15
D 5, 6, and 11
Where the above figures are given, The right triangles are: B and C.
What is the explanation for the above response?Using the phythagoren theorem, we can determind the options that represent a right ttriangle.
A 5,8, and 9:
5^2 + 8^2 = 25 + 64 = 89
9^2 = 81
Not a right triangle.
B 20, 21, and 29:
20^2 + 21^2 = 400 + 441 = 841
29^2 = 841
It is a right triangle.
C 9, 12, and 15:
9^2 + 12^2 = 81 + 144 = 225
15^2 = 225
It is a right triangle.
D 5, 6, and 11:
5^2 + 6^2 = 25 + 36 = 61
11^2 = 121
Not a right triangle.
The right triangles are: B and C.
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Find the value of x that will make aiib.
4x 2x
x=
The value of x that will make a parallel to b is 30. We solved the equation 4x + 2x = 180 and obtained x = 30.
According to the definition of interior consecutive angles, when a transversal intersects two parallel lines, the sum of the measures of the two interior consecutive angles formed on the same side of the transversal is always 180°.
In this case, we are given that lines A and B are parallel, and line q intersects these lines at two distinct points, forming two interior consecutive angles with measures 4x and 2x, respectively.
Since the two angles are consecutive and on the same side of the transversal, their sum is equal to 180°. Therefore, we can set up the following equation
4x + 2x = 180
Simplifying the equation, we get
6x = 180
Dividing both sides by 6, we get
x = 30
Therefore, the value of x that will make a parallel to b is 30.
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--The given question is incomplete, the complete question is given
" Find the value of x that will make a parallel to b.
Lines A and B are parallel lines and a transverse line is intersecting these lines at two distinct points, making the angle 4x and 2x
x= "--
Alexander stacked unit cubes to build the rectangular prism below. Use the rectangular prism to answer
Alexander stacked 16 unit cubes required to build the rectangular prism.
What is a prism?A three-dimensional solid object called a prism has two identical ends. It consists of equal cross-sections, flat faces, and identical bases. Without bases, the prism's faces are parallelograms or rectangles.
Here we need to find the number of cubes required to build the rectangular prism.
Here first we need to find how many cubes stack in the base layer
Number of unit cubes in the base layer = Number of cubes along the length * Number of cubes along the width
The number of unit cubes in the base layer = 2 * 4 = 8 cubes.
Total number of unit cubes in prism =Number of unit cubes in the base layer *Number of layers = 8 * 2 = 16 unit cubes
So, there are 16 unit cubes are required to build the rectangular prism.
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Complete question :
Alexander stacked unit cubes to build the rectangular prism below. Use the rectangular prism to answer the question.
How many cubes are required to build the rectangular prism?
what is the measure of the unknown segment? pls help i keep getting bots :(
To determine the measure of the unknown segment, it's essential to first gather information about the given problem, such as the context, any provided measurements, and any relationships between the segments or angles involved. Once you have this information, you can utilize relevant geometric principles and theorems to establish connections and solve for the unknown value.
For example, if the unknown segment is a side in a triangle, you may apply the Pythagorean theorem, triangle inequality theorem, or trigonometric functions such as sine, cosine, or tangent to calculate its length. If the unknown segment is part of a circle, you might use the properties of arcs, chords, or the circumference to determine its measure. In cases where the unknown segment is part of a polygon, you can consider properties like diagonals, perimeter, or area to derive its length.
After identifying the appropriate method and relationships, you can set up equations and solve for the unknown variable. To verify the solution, you can plug it back into the original problem to ensure it satisfies all given conditions. In conclusion, finding the measure of an unknown segment involves understanding the problem's context, applying relevant geometric concepts, and using mathematical techniques to solve for the desired value.
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Help asap
what is the measure of angle oac if major arc ab measures 220 degrees?
a. 55
b. 70
c. 110
d. 140
pls explain/show work
The measure of angle OAC if major arc AB measures 220 degrees is 110 degrees. Therefore, the correct option is C.
To find the measure of angle OAC, we need to use the central angle theorem which states that the measure of an inscribed angle is equal to half the measure of the intercepted arc.
Here, we are given that the major arc AB measures 220 degrees. So, the measure of angle AOB (the central angle) is 220 degrees.
Since angle OAC is an inscribed angle that intercepts arc AB, its measure is half the measure of arc AB.
Therefore, measure of angle OAC = (1/2) * 220 = 110 degrees.
So, the correct answer is option (c) 110.
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Answer the following questions for the function
f(x) = x^3/x^2 - 4 defined on the interval (–18, 19) Enter the z-coordinates of the vertical asymptotes of f(x) as a comma-separated list. That is, if there is just one value, give it; if there are more than one, enter them separated commas; and if there are nono, enter NONE
There is a vertical asymptote at x = 0.
A vertical asymptote is a vertical line that the graph of a function approaches but never touches or crosses. In the case of a rational function such as f(x) = x^3/(x^2-4), vertical asymptotes occur where the denominator of the function is equal to zero.
In this case, the denominator is x^2 - 4, which is equal to zero when x = ±2. However, we need to check whether these values are in the domain of the function. Since the interval of interest is (–18, 19), we see that only x = 2 is in the domain of the function.Therefore, the only vertical asymptote of the function f(x) = x^3/(x^2-4) on the interval (–18, 19) is at x = 0, which is the value of x where the denominator is closest to zero.
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Your family decides they have $400 per month to spend towards remodeling their house. the bank offers them a ten year(120 months) home equity loan for $30,000 with an interest rate of 6.5%. use p = p v ( i 1 − ( 1 + i ) − n ) to determine if your family can afford the monthly payment.
The monthly payment for the loan is $328.05. So we can determine that the family can afford the monthly payment.
Money spend = $400
Time = 120 months
Loan amount = $30,000
Interest rate = 6.5%.
The formula is given P = [tex]PV*(i / (1 - (1+i)^{-n}))[/tex]
The interest should be calculated at the monthly rate. So, we can divide the interest rate by 12.
i = 0.065/12 = 0.00541667
Substituting the values into the formula,
P = [tex]30000 * 0.00541667 / (1 - (1+0.00541667)^{-120})[/tex]
P = $328.05
Therefore, we can conclude that the monthly payment for the loan is $328.05.
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A pond of fish starts with 200 fish. The pond can sustain 460 fish, 40% of the fish die each year while the number of births is 60% of the current population. – 3.04174E+07 fish are harvested from the pond each year. Write a differential equation that models the problem
The differential equation that models the problem is: dN/dt = 0.2*N(t) - 3.04174E+07.
Let's denote the current number of fish in the pond by N(t), where t is time in years.
The rate of change of N(t) is given by the difference between the number of births and deaths, minus the number of fish harvested from the pond:
dN/dt = (0.6N(t)) - (0.4N(t)) - (3.04174E+07)
The first term represents the number of births, which is 60% of the current population N(t). The second term represents the number of deaths, which is 40% of the current population N(t). The third term represents the number of fish harvested from the pond each year.
Therefore, the differential equation that models the problem is:
dN/dt = 0.2*N(t) - 3.04174E+07
Note that we have simplified the expression (0.6-0.4)N(t) to 0.2*N(t) for simplicity.
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One day, Bill at the candy shop sold 210 bottles of cherry soda and grape
soda for a total of $230. 30. If the cherry soda costs $1. 15 and the grape
soda costs $0. 99, how many of each kind were sold?
Bill sold 140 bottles of cherry soda and 70 bottles of grape soda.
Let's assume that x is the number of bottles of cherry soda sold and y is the number of bottles of grape soda sold. We can set up a system of equations to represent the given information:
x + y = 210 (equation 1: the total number of bottles sold is 210)
1.15x + 0.99y = 230.30 (equation 2: the total cost of the sodas is $230.30)
We can use the first equation to solve for y in terms of x:
y = 210 - x
Substituting this expression for y into the second equation, we get:
1.15x + 0.99(210 - x) = 230.30
Simplifying and solving for x, we get:
1.15x + 207.9 - 0.99x = 230.30
0.16x = 22.4
x = 140
So Bill sold 140 bottles of cherry soda. Substituting this value into equation 1, we get:
140 + y = 210
y = 70
Therefore, Bill sold 140 bottles of cherry soda and 70 bottles of grape soda.
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Find f
f’’(θ) = sin (θ) +cos (θ), f(0) = 2, f’(0) = 4
F(θ) =
Substituting these values into the expression for f(θ), we get:
f(θ) = -sin(θ) - cos(θ) + 5θ + 4
To find f, we need to integrate f''(θ) twice.
First, we integrate sin(θ) + cos(θ) with respect to θ to get f'(θ):
f'(θ) = -cos(θ) + sin(θ) + C1
where C1 is the constant of integration.
Next, we integrate f'(θ) with respect to θ to get f(θ):
f(θ) = -sin(θ) - cos(θ) + C1θ + C2
where C2 is the constant of integration.
Using the initial conditions given, we can solve for C1 and C2:
[tex]f(0) = -1 - 1 + C2 = 2[/tex]
C2 = 4
f'(0) = -1 + 0 + C1 = 4
C1 = 5
Substituting these values into the expression for f(θ), we get:
f(θ) = -sin(θ) - cos(θ) + 5θ + 4
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Sam has 42 pencils and 56 pens.he will give all of them to a group of his classmates. each classmate will receive the same number of each item. what is the greatest number of classmates sam can give pencils and pens to? how many of each item will each classmate receive?
Sam can give pencils and pens to 14 classmates, with each classmate receiving 3 pencils and 4 pens (since 42 divided by 14 is 3, and 56 divided by 14 is 4).
Sam has 42 pencils and 56 pens, and he wants to distribute them equally among his classmates. To find the greatest number of classmates, we need to find the greatest common divisor (GCD) of 42 and 56.
The GCD of 42 and 56 is 14. Therefore, the greatest number of classmates Sam can give pencils and pens to is 14.
Each classmate will receive:
- 42 pencils / 14 classmates = 3 pencils per classmate
- 56 pens / 14 classmates = 4 pens per classmate
So, each of the 14 classmates will receive 3 pencils and 4 pens.
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The diagram below shows the radius of the circular opening of a Ice cream cone.
Which of the following Is closest to the circumference of the opening in inches.
Given: AB=CD, AD|| BC, BF=HD, CGE=AHF and AE=FC.
Prove: BAE=DCF
The ∠BAE ≅ ∠DCF by SAS congruence of triangles. The solution has been obtained by using the congruence of triangles.
What is congruence of triangles?
If all three corresponding sides and all three corresponding angles of two triangles have the same size, the triangles are said to be congruent. These triangles can be moved, flipped, twisted, and turned to achieve the same result. They are parallel to one another when moved.
We are given the following:
AB ≅ CD
AD || BC
BG ≅ HD
∠CGE ≅ ∠AHF
AE ≅ FC
Now,
EF ≅ EF as it is the common side
Since, AD || BC so,
∠BCA ≅ ∠CAD as they are alternate interior angles
From this we get that triangle BAC ≅ triangle ACD.
So, the ∠BAE ≅ ∠DCF.
Hence, the ∠BAE ≅ ∠DCF by SAS congruence of triangles.
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Math geometry question please help
Answer:
LP is a raym∠LMO = 90°m∠LPO = 90°m∠MLP = 26°arc MP = 154°arc MNP = 206°Step-by-step explanation:
You want various angle and arc measures in the given figure.
RelationshipsThe relevant angle relationships are ...
a radius to a point of tangency makes a right angle with the tangentan arc has the same measure as its central anglethe sum of the arcs of a circle is 360°the sum of angles in a quadrilateral is 360°an angle is formed from two rays whose endpoints are the vertex of the angleThese answer the given questions as follows:
LP is a ray.
The angle at M is 90°.
The angle at P is 90°.
The angle at L is 360° -90° -90° -154° = 26°
Arc MP has the same measure as angle MOP, 154°
Arc MNP completes the circle, so is 360° -154° = 206°
A triangular prism is 40 yards long and has a triangular face with a base of 32 yards and a height of 30 yards. The other two sides of the triangle are each 34 yards. What is the surface area of the triangular prism?
The surface area of the triangular prism is 4800 square yard.
How to find the surface area of the triangular prism?The surface area of a triangular prism is sum of the areas of the faces that make the prism.
The surface area of a triangular prism is given by:
SA = (a + b + c)L + bc
Where a and b are the bases of the rectangular faces, c is the height of the triangle and h is the total length of the prism
In this case:
L = 40, a = 34, b = 32 and c = 30
SA = (34 + 32 + 30)40 + (32 * 30)
SA = 3840 + 960
SA = 4800 square yard
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From a distance of 300 m, Susan looks up at the top of a lighthouse. The angle of elevation is 5',
Determine the height of the lighthouse to the nearest meter,
If Susan stands 300 m away from the lighthouse and looks up at it with an angle of elevation of 5 degrees, the height of the lighthouse is approximately 26 meters. This calculation is important for navigation and other purposes.
To determine the height of the lighthouse, we can use trigonometry. We know that the angle of elevation, which is the angle between Susan's line of sight and the ground, is 5'. We also know the distance between Susan and the lighthouse, which is 300 m.
We can use the tangent function to find the height of the lighthouse:
tan(5') = height/300
To solve for height, we can cross-multiply and simplify:
height = 300 x tan(5')
Using a calculator, we get that the height of the lighthouse is approximately 26.2 m.
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The hourly wages earned by 20 employees are shown in the first box-and-whisker plot below. The person earning $15 per hour quits and is replaced with a person earning $8 per hour. The graph of the resulting salaries is shown in plot 2. A box-and-whisker plot is shown. The number line goes from 7 to 15. The whiskers range from 8 to 15, and the box ranges from 8. 8 to 10. 2. A line divides the box at 9. 5. Plot 1 A box-and-whisker plot is shown. The number line goes from 7 to 15. The whiskers range from 8 to 11, and the box ranges from 8. 7 to 10. A line divides the box at 9. 6. Plot 2 How does the mean and median change from plot 1 to plot 2? The mean and median remain the same. The mean decreases, and the median remains the same. The mean remains the same, and the median decreases. The mean and median decrease.
The mean decreases, and the median remains the same from plot 1 to plot 2.
In the first box-and-whisker plot, the hourly wages earned by 20 employees are displayed, with a range from $8.70 per hour to $11.50 per hour. The median, which is the value that separates the higher half of the data from the lower half, is $10 per hour. The mean, which is the average of all the wages, is calculated by adding up all the wages and dividing the total by 20.
When one employee earning $15 per hour quits and is replaced by a new employee earning $8 per hour, the second box-and-whisker plot is created. The range of wages extends from $8 per hour to $15 per hour, with a median of $9.50 per hour. Since the new employee is earning a lower wage, the mean hourly wage decreases.
Therefore, the correct answer to the question is that the mean decreases, and the median remains the same. It is important to note that while the median does not change in this case, it is not always the case in other situations where data is added or removed from a set. It is also important to note that box-and-whisker plots are helpful in visualizing the spread of data and identifying any outliers.
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Copy and complete the equation of line B below. y = — 84 NWPца - 0 7- 6+ 5- 4- 3- 2- 1/ -11 -2- -8-7-6-5-4-3-2-10 1 2 3 4 5 6 7 8 ܢܐ ܚ ܩ ܘ ܘ ܢ -3 -4- -5 -6 x +_ -7 -8- Line B 19
The equation of the line passing through the given points is y = 3x-1.
Given that is a line passing through two points (0, 2) and (-1, -1) we need to find the equation of the line using them,
We know that the equation of a line passing through points (x₁, y₁) and (x₂, y₂) is =
y-y₁ = y₂-y₁ / x₂-x₁ (x-x₁)
Here (x₁, y₁) and (x₂, y₂) are (0, 2) and (-1, -1),
Therefore, the required equation is =
y+1 = -1-2/-1 (x-0)
y+1 = 3x
y = 3x-1
Hence, the equation of the line passing through the given points is y = 3x-1.
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√x+3
a.3x^1/2
b.(x+3)^1/2
c.x^1/2+3
d.(3x)^1/2
Answer:
b
Step-by-step explanation:
The expression √x+3 means the square root of x+3. We can rewrite this as (x+3)^(1/2), using the exponent rule that says taking the square root is the same as raising to the power of 1/2.
So the options become:
a. 3x^(1/2)
b. (x+3)^(1/2)
c. x^(1/2) + 3
d. (3x)^(1/2)
None of the other options match the given expression. So the correct answer is (b) (x+3)^(1/2).
Identify the point (x1, y1) from the equation: y 8 = 3(x – 2)
The point (2, 8) is the point (x1, y1) identified from the equation y - 8 = 3(x - 2
Identify (x1, y1) the equation: y 8 = 3(x – 2)The equation y - 8 = 3(x - 2) is in point-slope form, which is y - y1 = m(x - x1), where (x1, y1) is the point on the line and m is the slope of the line. In this case, the slope of the line is 3, which means that for every increase of 1 in the x-coordinate, the y-coordinate increases by 3.Comparing the given equation with the point-slope form, we can see that x1 = 2 and y1 = 8. Therefore, the point (2, 8) is the point identified from the equation.Learn more about equation
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