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Answer:

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Answer:

Concentration: The amount of a given substance within a set solution.

Explanation:

For example, the units for concentration include mol/[tex]dm^{3}[/tex] which means that if a substance has 3 mol/[tex]dm^{3}[/tex], it means 3 moles of that substance is in a 1 dm cubed of that solution. You could give examples of the concentration of acids like Hydrochloric Acid (HCl) and alkalis like Hydroxide (OH).

A 25.0 mL solution of Sr(OH)₂ is neutralized with 31.6 mL of 0.150 M HBr, then the concentration of the original Sr(OH)₂ solution is 0.189M.

Concentration of the solution will be calculated by using the below chemical reaction as:

M₁V₁ = M₂V₂, where

M₁ & V₁ is the molarity and volume of HBr solution and M₂ & V₂ is the molarity and volume of original Sr(OH)₂ solution.

On putting values on above equation by taking from question, we get

M₂ = (0.15)(31.6) / (25) = 0.189 M

Hence required molarity of Sr(OH)₂ solution is 0.189M.

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Answer:

i think its C

Explanation:

The graph indicates that the reaction reaches equilibrium around 1.5 seconds. The graph shows how the concentrations of reactants and products change over time until they eventually become constant. So, the correct option is D.

Equilibrium is a state in a chemical process when forward and backward reactions occur at the same rate, meaning that the concentrations of reactants and products do not change with time. In other words, the forward reaction rate equals the reverse reaction rate.

In the example above, the graph indicates that the reaction reaches equilibrium in about 1.5 seconds. The graph shows how the concentrations of reactants and products change over time until they eventually become constant. This indicates that the reaction has reached equilibrium when obtained in approximately 1.5 seconds.

So, the correct option is D.

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Answer:

i think d maybe correct me if im wrong

Explanation:

La³⁺ ions are colorless compounds because they have a 4f⁰ electronic configuration. Therefore, option (B) is correct.

The lanthanide series comprises 15 metallic chemical elements with atomic numbers 57 to 71, from lanthanum through the lutetium. These elements have chemically similar elements scandium and yttrium, which are often collectively called rare-earth elements.

The chemical symbol Ln can be used to refer to any lanthanide.  They are f-block elements, corresponding to the filling of the 4f-shell. All lanthanoids form trivalent cations, Ln³⁺ are determined by the ionic radius, which decreases from lanthanum to lutetium.

The valence orbitals in lanthanides have f → f transitions that are much weaker and narrower than d → d transitions. In general, the colors of lanthanide complexes are far fainter than transition metal complexes.

The electronic configuration of the lantanum is [Rn]5d¹6s². In the +3 oxidation state, it has all shells fully filled therefore, no electron transitions are possible. Therefore, La³⁺  form colorless compounds.

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Answer:

Unequal number of protons and electrons

Explanation:

When an atom loses or gains electrons, this affects its charge, thus creating it an ion (a charged atom)!

From the calculation, the percentage of water in the sodium hydroxide sample is 7%.

The term neutralization has to do with the reaction between an acid and a base to yiled salt and water.

Now we have  to apply the titration formula;

CAVA/CBVB = NA/NB

CA = concentration of acid

CB = concentration of base

VA = volume of acid

VB = volume of base

NA = number of moles of acid

NB = number of moles of base

The reaction equation is; HCl + NaOH ----->NaCl + H2O

CAVANB = CBVBNA

CB = CAVANB /VBNA

CB = 34.9 * 0.2 M * 1/10 * 1

CB = 0.698 M

Number of moles = Conncentration * volume

= 0.698 M * 100/1000 L = 0.0698 moles

Mass = Number of moles * molar mass

Mass =  0.0698 moles * 40 g/mol = 2.79 g

percent of NaOH = 2.79 g/ 3g * 100/1 = 93%

Percent of water = 100- 93 = 7%

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Answer:

The rate of effusion of helium is always about twice that of oxygen.

Explanation:

Recall Graham's law of effusion:

[tex]\displaystyle \frac{r_1}{r_2} = \sqrt{\frac{\mathcal{M}_2}{\mathcal{M}_1}}[/tex]

Where r are the rates of effusion and M are the respective molecular weights.

Let r₁ be the effusion rate of helium and r₂ be the effusion rate of oxygen. Hence, M₁ = 8.00 g/mol and M₂ = 32.00 g/mol.

Substitute:

[tex]\displaystyle \begin{aligned}\frac{r_1}{r_2} & = \sqrt{\frac{(32.00\text{ g/mol})}{(8.00\text{ g/mol})}} \\ \\ & = \sqrt{4.00} \\ \\ & = 2.00 \end{aligned}[/tex]

Solving for r₁ yields:
[tex]\displaystyle \begin{aligned} \frac{r_1}{r_2} & = 2.00\\ \\ r_1 & = 2.00r_2\end{aligned}[/tex]

Hence, the rate of effusion of helium is always about twice that of oxygen. This is expected, as helium is smaller than oxygen.

Answer: 83.656 kpa

Explanation:

Use Dalton's law of partial pressures which states that the total pressure of a combination of gases is equal to the sum of the partial pressures of the constituent gases.

So we have,

P(total) = P(oxygen) + P(water vapour)

96.00 kpa = 12.344 + P(oxygen)

P(oxygen) = 83.656 kpa

From the stoichiometry of the reaction, the percentage yiled of the copper is 89.6%

The reaction equation here is given as; Fe(s) + CuSO4 (aq) ----->FeSO4(aq) + Cu(s)

Number of moles of Fe = 0.9845 g/56 g/mol = 0.018 moles. Since the reaction is 1:1, this is also the number of moles of Cu formed.

Theoretical yiled of Cu =  0.018 moles * 63.5 g/mol = 1.143 g

Percentage yiled =  1.024 g/1.143 g * 100/1 = 89.6%

If 1 mole of Fe contains 6.02 * 10^23 molecules

0.018 moles of Fe contains 0.018 moles *  6.02 * 10^23 molecules/1 mole = 1.1 * 10^22 molecules.

Number of moles of AgNO3 =  1.35 g/170 g/mol = 0.0079 moles

Molarity of the solution = 0.0079 moles/250 * 10^-3 L = 0.0032 M

Hence; 0.0032 M * V1 = 100 mL  *  0.01 M

V1 = 312.5 mL

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Answer:

Explanation:

We can use the equation to find out

E = mc△T

E is the total energy (calories) needed, m for mass, c for specific heat capacity and △T for the temperature change.

Substitute the numbers given

E = 500 x 1 x 10

E =5000

Therefore the answer is 5000CalWe can use the equation to find out

E = mc△T

E is the total energy (calories) needed, m for mass, c for specific heat capacity and △T for the temperature change.

Substitute the numbers given

E = 500 x 1 x 10

E =5000

Therefore the answer is 5000Cal

For a normal boiling point of a liquid is 282 °C, the temperature is mathematically given as

T2=181.55°C\

Generally, the equation for the gas  is mathematically given as

ln(p1/p2)=dHvap/R(1/T2-1/T1)

Therefore

ln(1/0.26)=23500/8.214(1/T2-1/555)

T2=181.55^C

In conclusion

T2=181.55°C

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The given temperature of water is 50 degrees Celsius, hence, we can conclude that the phase of the given water is liquid phase.

Water can exist in three different phases, namely;

Therefore, if the given temperature of water is 50 degrees Celsius, hence, we can conclude that the phase of the given water is liquid phase.

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Answer:

C

Explanation:

We can use heat stoichiometry. Thus, convert from grams of Ba to moles of Ba; and use the ΔH value to calculate the amount of heat released. Hence:

[tex]\displaystyle 5.75\text{ g Ba}\cdot \frac{1\text{ mol Ba}}{137.33\text{ g Ba}} \cdot \frac{1\text{ mol}_{rxn}}{2\text{ mol Ba}} \cdot \frac{-1107\text{ kJ}}{1\text{ mol}_{rxn}} =-46.4 \text{ kJ}[/tex]

Therefore, about 46.4 kJ of heat was released.

In conclusion, our answer is C.

The number of moles of water are needed in order to produce 21.8 g of

calcium hydroxide is 0.588 moles.

Moles of any substance will be calculated as:

n = W/M, where

W = given mass

M = molar mass

Given chemical reaction is:
CaC₂ + 2H₂O → C₂H₂ + Ca(OH)₂

Moles of 21.8g of Ca(OH)₂ = 21.8g / 74.1g/mol = 0.294mol

From the stoichiometry of the reaction, it is clear that

1 mole of Ca(OH)₂ = needed 2 moles of water

0.294 mole of Ca(OH)₂ = needed 2×0.294=0.588 moles of water

Hence required moles of water is 0.588 moles.

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formula= PV = nRT

moles of Zn = 4.33 g Zn x 1 mol Zn/65.4 g

= 0.0662 moles Zn

moles H2 = 0.0662 moles Zn x 1 mol H2/mol Zn

= 0.0662 mole H2 gas

V = nRT/P

T = 38 + 273

= 311K

763 torr/760

= 1.00 atm

V = (0.0662 mol)(0.0821 Latm/Kmol)(311K)/1.00 atm

V = 1.69 L

u did a five because u are awsome.

Answer:

I would rate myself a 5 because I completed all the work with no issues. 

Explanation:

Answer:

What Structures??

Explanation:

Can you please explain the question more

Answer:

Your answer is correct based on what I remember from AP Chemistry  

Explanation:

The required volume of concentrated stock solution of hydrochloric acid is 102.71 mL.

Volume of any solution will be calculated by using the density as:

Volume = Mass/Density

Given that percent mass of HCl is 37%, so mass of the HCl = 37g

So that mass of solution = 100g

And density of solution = 1.2 g/mL

Volume of solution = 100/1.2 = 83.33 mL = 0.08333 L

Moles of HCl will be calculated as:

n = W/M, where

W = given mass = 37g

M = molar mass = 36.4g/mol

n = 37/36.4 = 1.014mol

Then the molarity of the stock solution will be calculated as:

M = n/V

M = 1.014 / 0.0833 = 12.17M

Now the required volume of stock solution will be calculated by using the following equation as:

M₁V₁ = M₂V₂, where

M₁ & V₁ is the molarity and volume of stock solution and M₂ & V₂ is the molarity and volume of dilute solution. On putting values in the above solution we get

12.17 × V₁ = 0.5 × 2500

12.17 × V₁ = 1250

V₁ = 102.71 mL

Hence required volume of stock solution is 102.71 mL.

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Your answer is FE, or iron!

Answer:

Magnesium hydroxide is a base. Hydrochloric acid, as the name suggests, is an acid.

So an acid and a base together will produce salt and water. In this case, the salt is magnesium chloride.

This process is known as neutralisation

Answer:

A rotation

Explanation:

Answer:

The answer is When CO2 increases, pH decreases and acidity increases.

Explanation:

Excess carbon dioxide (CO2) in the atmosphere gets absorbed at the ocean surface of the ocean. This excess CO2 results in more hydrogen ions, which increases the acidity of the ocean.

Answer:

D. Temp

Explanation:

Temperature is a mesure of the KE of the molecules/atoms of the substance

Taking into account the reaction stoichiometry, 1 mole of silver chromate Ag₂CrO₄ are produced in this reaction.

In first place, the balanced reaction is:

2 AgC₂H₃O₂ + K₂CrO₄  → Ag₂CrO₄ + 2 KC₂H₃O₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

By reaction stoichiometry 2 moles of AgC₂H₃O₂ form 1 mole of Ag₂CrO₄.

In other words, according to this balanced chemical equation, 1 mole of silver chromate Ag₂CrO₄ are produced in this reaction.

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Answer:

A prokaryotic cell is shown in the image

Explanation:

Prokaryotic cells are the most basic types. Since they are basic, they don't have a nucleus. All eukaryotic cells have it but prokaryotic cells don't have it. A nucleus contains organelles such as a mitochondria which the diagram doesn't show as well. Thus a prokaryotic cell is shown in the image.

According to the mole concept, the number of moles in 50 g of NO₂ is 1.086 as molar mass of NO₂ is 46 g and as per STP conditions volume is 24.32 L.

Mole is defined as the unit of amount of substance . It is the quantity measure of amount of substance of how many elementary particles are present in a given substance.

It is defined as exactly 6.022×10²³ elementary entities. The elementary entity can be a molecule, atom ion depending on the type of substance. Amount of elementary entities in a mole is called as Avogadro's number.

It is widely used in chemistry as a suitable way for expressing amounts of reactants and products.For the practical purposes, mass of one mole of compound in grams is approximately equal to mass of one molecule of compound measured in Daltons. Molar mass has units of gram per mole . In case of molecules, where molar mass  in grams present in one mole  of atoms is its atomic mass.

Initially the number of moles is calculated as, 50/46=1.086 moles . As 1 mole occupies 22.4 L at STP conditions,1.086 moles occupy 1.086×22.4=24.32 L.

Hence, the volume in liters of 50 g of NO₂ at STP is 24.32 L.

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