A telescope with a 40-inch primary lens has four times the light-gathering power compared to a telescope with a 20-inch lens. Space telescope data is important for studying celestial objects across the electromagnetic spectrum and provides comprehensive information. Telescopic data helps determine distances between objects through techniques like redshift measurement and the cosmic distance ladder.
Explanation:The relative light-gathering power of a telescope is determined by the area of its primary lens or mirror. In this case, the telescope with the 40-inch primary lens has four times the light-gathering power compared to the telescope with the 20-inch lens. This is because the area of the 40-inch lens is four times larger than the area of the 20-inch lens.
Space telescope data is important across the electromagnetic spectrum because it allows astronomers to study celestial objects in different wavelengths, revealing information that is not accessible through visible light observations alone. By using data from telescopes that operate in various parts of the electromagnetic spectrum, astronomers can gather more comprehensive information about the universe.
One way telescope data helps determine distances between celestial objects is through the measurement of redshift. Redshift occurs when light from distant objects is stretched to longer wavelengths due to the expansion of the universe. By analyzing the amount of redshift in the light from a celestial object, astronomers can estimate its distance. This method is a part of the cosmic distance ladder—a set of techniques used to determine distances to different objects in the universe.
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Sound travels through air at a speed of 342m/s
342
m
/
s
at room temperature. What is the frequency of a sound wave with a wavelength of 1.8m
1.8
m
Answer:
Explanation:
The formula relating the speed of sound, frequency, and wavelength is:
speed = frequency x wavelength
Rearranging this formula to solve for frequency:
frequency = speed / wavelength
Substituting the given values:
frequency = 342 m/s / 1.8 m
frequency = 190 Hz
Therefore, the frequency of the sound wave is 190 Hz.
A block of mass m1=3.0kg rests on a frictionless horizontal surface. A second block of m2=2.0kg hangs from an ideal cord of negligible mass that runs over an ideal pulley and then is connected to the first block . the blocks are released from rest . determine the displacement of the velocityA block of mass m1=3.0kg rests on a frictionless horizontal surface. A second block of m2=2.0kg hangs from an ideal cord of negligible mass that runs over an ideal pulley and then is connected to the first block . the blocks are released from rest . Determine how far has block 1 moved during the 1.2-s interval?
A) 13.4 m
B) 2.1 m
C) 28.2m
D) 7.6m
The answer is:
D. 7.6m
5. A pool ball leaves a table with an initial horizontal velocity of 2.4 m/s and lands
0.84 m away from the table. Predict the time required for the pool ball to fall to the
ground and height of the table.
Answer:
Explanation:
Since the initial velocity is purely horizontal, we know that it won't affect the time taken for the ball to fall. So, we can use the equations of motion for a freely falling object to determine the time taken to fall and the height of the table.
Let's use the following equations:
h = vit + 1/2gt^2 ---(1)
vf = vi + gt ---(2)
where h is the height of the table, vi is the initial vertical velocity (which is zero), vf is the final velocity (which is the velocity with which the ball hits the ground), t is the time taken to fall, g is the acceleration due to gravity.
First, let's find the time taken for the ball to fall:
From equation (2), we have:
vf = vi + gt
vf = gt
t = vf/g
Now, we need to find vf. We know that the ball lands 0.84 m away from the table, which means that it has traveled a horizontal distance of 0.84 m. We can use this information along with the initial horizontal velocity to find the time taken for the ball to travel this distance:
d = vit
t = d/vi
t = 0.84 m / 2.4 m/s
t = 0.35 s
So, the time taken for the ball to fall is:
t = vf/g = 0.35 s
Now, we can use equation (1) to find the height of the table:
h = vit + 1/2gt^2
h = 0 + 1/2 * 9.81 m/s^2 * (0.35 s)^2
h = 0.6 m
Therefore, the height of the table is 0.6 m.
HELP
Complete the ray diagram below:
The image characteristics are ____. (2 points)
A concave mirror is shown with curvature positioned at 8 on a ruler that goes from 0 to 14 centimeters. The object is located at 5, and the focal point is located at 6.5.
upright, virtual, and smaller
upright, real, and same size
inverted, virtual, and smaller
inverted, real, and same size
Real, inverted, and same size are the features of the image. when A concave mirror with a curvature of 8 is displayed on a ruler with a range of 0 to 14 cm.
The mirror formula may be used to calculate the image distance for an item located 4 cm from a 1.5 cm focal length mirror.
1/f = 1/u+1/v
f is the focal length
u is the object distance
v is the image distance
Keep in mind that the concave mirror's image distance and focal length are both positive.
Given:
u = 4cm
f = 1.5cm
1/v = 1/1.5-1/4
1/v = 0.67-0.25
1/v = 0.42
v = 1/0.42
v = 2.38cm
The picture is Genuine and INVERTED since the image distance value is positive.
We shall find its magnification and see if it is magnified or lessened. It is amplified if the magnification is larger than 1, and it is decreased if it is less.
Magnification = v/u
Magnification = 2.38/4
Magnification = 0.595 or. 0.6
The picture is reduced in size since the magnification is less than one (SMALLER).
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A current of O.S.A flows in a circuit with resistance 60 calculate the potential difference of the circuit
Therefore, the potential difference of the circuit is 30 volts.
What in electricity is a potential difference?The external effort required to move a charge from one position to another in an electric field is known as an electric potential difference, or voltage. A test charge that has an electric potential differential of +1 will experience a shift in potential energy.
To calculate the potential difference (V) of the circuit, we can use Ohm's Law, which states that V = IR, where I is the current flowing through the circuit and R is the resistance of the circuit.
In this case, the current (I) is given as 0.5 A and the resistance (R) is given as 60 Ω. Therefore, we can substitute these values into Ohm's Law to find the potential difference:
V = IR
V = 0.5 A × 60 Ω
V = 30 volts
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Who discovered energy quanta and earned a Nobel Prize in Physics?
Answer: Max Planck
He won the Nobel Prize for Physics in 1918.
A Car accelerate Cuniformly from) 13 ms -1 to 31ms-1 while entering the motor way Covering the distance 220m
Answer:
3.84 m/s^2.
Explanation:
To solve this problem, we can use the following kinematic equation:
v^2 = u^2 + 2as
where:
v is the final velocity (31 m/s)
u is the initial velocity (13 m/s)
a is the acceleration (which is assumed to be constant)
s is the distance traveled (220 m)
We want to solve for the acceleration, so we can rearrange the equation as follows:
a = (v^2 - u^2) / 2s
Substituting the given values:
a = (31^2 - 13^2) / (2 x 220)
a = 3.84 m/s^2
Therefore, the acceleration of the car is 3.84 m/s^2.
please rate
Faculty of Medicine
Tutorial No 3
1. When an 81.0-kg adult uses a spiral staircase to climb to the second floor of his house, his
gravitational potential energy increases by 2.00 × 103
J. By how much does the potential
energy of an 18.0-kg child increase when the child climbs a normal staircase to the second
floor?
What was the angle of application of the force of 35 if on a distance of 15 the work of 350 was done?
HELP!!! Which simple machines represent variations of an inclined plane? Select all that apply.
screw
lever
wedge
pulley
wheel and axle
I need help with this question
The Large Hadron Collider is a product of and is used for
A. scientific investigations, technological development.What is Large Hadron ColliderThe Large Hadron Collider (LHC) was designed and built for scientific investigations in the field of particle physics. Its primary purpose is to collide particles at very high energies and observe the resulting interactions to gain insights into the fundamental nature of matter and the universe.
However, the construction and operation of the LHC have also contributed to technological development in fields such as superconductivity, cryogenics, and data processing.
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The bigger the spring constant, the more__________the spring is.
The bigger the spring constant, the more stiff or rigid the spring is.
What does it signify when a spring's spring constant is higher?The exact amount of force needed to bend a spring depends on the spring constant. Although pounds/inch is a common measurement in North America, the standard international (SI) unit for spring constants is Newtons/meter. A stiffer spring has a greater spring constant, and vice versa.
What does it signify when the spring constant is higher?The exact amount of force needed to bend a spring depends on the spring constant. Although pounds/inch is a common measurement in North America, the standard international (SI) unit for spring constants is Newtons/meter. A stiffer spring has a greater spring constant, and vice versa.
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How much heat is necessary to change 10 g of ice at -20°C into water at 10°C?
Answer:
Explanation:
The process can be broken down into two steps:
Heat required to raise the temperature of ice from -20°C to 0°C.
Heat required to melt ice at 0°C and raise the temperature of water from 0°C to 10°C.
Step 1:
The heat required to raise the temperature of ice can be calculated using the specific heat capacity of ice, which is 2.09 J/g°C.
Heat required = mass × specific heat capacity × change in temperature
Heat required = 10 g × 2.09 J/g°C × (0°C - (-20°C))
Heat required = 418 J
Step 2:
The heat required to melt ice and raise the temperature of water can be calculated using the heat of fusion of ice and the specific heat capacity of water.
Heat required to melt ice = mass × heat of fusion of ice
Heat required to melt ice = 10 g × 334 J/g
Heat required to melt ice = 3340 J
Heat required to raise the temperature of water can be calculated using the specific heat capacity of water, which is 4.18 J/g°C.
Heat required = mass × specific heat capacity × change in temperature
Heat required = 10 g × 4.18 J/g°C × (10°C - 0°C)
Heat required = 418 J
Total heat required = Heat required in Step 1 + Heat required to melt ice + Heat required in Step 2
Total heat required = 418 J + 3340 J + 418 J
Total heat required = 4176 J
Therefore, 4176 J of heat is required to change 10 g of ice at -20°C into water at 10°C.
Which correctly describes a different evolutionary stage of a star like the sun
A) it’s forms from a cold, dusty molecular cloud
B) During a yellow giant stage, it burns carbon in its core and helium in the shell surrounding the core.
C) After leaving the main sequence, its core is stable due to electron degeneracy
D) It becomes a white dwarf after exploding as a supernova
E)During a red giant stage, its core contracts and cools
The statement that correctly defines an evolutionary stage of a star like the sun is that after leaving the main sequence, its core is stable due to electron degeneracy. That is option C.
What are the stage of life cycle of a star?The stages of the life cycle of a star include the following:
Giant Gas CloudProtostarT-Tauri PhaseMain SequenceRed GiantThe Fusion of Heavier ElementsSupernovae and Planetary NebulaeThe evolutionary stage is also called the main sequence stage of the life cycle of the star.
In this stage, the core temperature reaches the point for the fusion to occur whereby the protons of hydrogen are converted into atoms of helium. This leads to the stability of the core of the newly formed start due to electron degeneracy.
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At 5220J, a temperature increase occurs from 10 degrees Celsius to 60 degrees Celsius. What is the mass of the water?
The mass of water that undergoes a change in temperature from 10 degrees celsius to 60 degrees celsius is 24.9 g.
What is mass?Mass is the quantity of matter a body contained.
To calculate the mass of the water, we use the formula below
Formula:
m = Q/cΔt................... Equation 1Where:
m = Mass of waterQ = Amount of heatc = Specific heat capacity of waterΔt = Change in temperatureFrom the question,
Given:
Q = 5220 Jc = 4200 J/kg.KΔt = 60-10 = 50 degree celsiusSubstitute these values into equation 1
Q = 5220/(4200×50)Q = 0.0249 kgQ = 24.9 gHence, the mass of water is 24.9 g.
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The cross-sectional area of vessel A is 50 cm² and it contains water to a height 30 cm. The vessel B has an area of cross-section of 25 cm². The two vessels are connected with a thin tube as shown in the figure, When the tap is slowly opened, and the water attained an equilibrium in both vessels. The reduction in the potential energy of the water is (Density of water is 1000 kgm-³)
1) 7.5 J
2) 22.5 J
3) 0.75 J
4) 8.5 J
5) 75 J
Please show the working along with a brief explanation.
The reduction in the potential energy of the water is approximately 7.5 J.
option 1
What is the reduction in potential energy?We can use the principle of conservation of energy to determine the reduction in potential energy of the water.
Initially, the water in vessel A has a certain amount of potential energy due to its height above the bottom of the vessel. When the water flows through the tube and reaches vessel B, its height above the bottom of vessel B is lower than that of vessel A, which means that its potential energy has decreased.
The potential energy of the water in vessel A is given by:
PE_A = mgh_A
The mass of the water in vessel A is given by:
m = density x volume
volume = A x h_A
Substituting for m and simplifying, we get:
PE_A = density x A x h_A x g
Similarly, the potential energy of the water in vessel B is:
PE_B = density x A_B x h_B x g
At equilibrium, the height of the water in the two vessels will be the same, so we can set h_A = h_B = h.
Also, since the water is in equilibrium, the pressure at the bottom of both vessels must be the same. This means that the pressure difference between the top and bottom of the water column in vessel A (due to the weight of the water) must be balanced by the pressure difference between the top and bottom of the water column in vessel B.
The pressure difference in vessel A is:
P_A = density x g x h_A
and the pressure difference in vessel B is:
P_B = density x g x h_B
Since the pressure difference must be balanced, we have:
P_A - P_B = density x g x h_A - density x g x h_B = 0
which simplifies to:
h_A = h_B x A_B / A
Substituting for h_A and h_B in the expressions for PE_A and PE_B, we get:
PE_A = density x A x h x g
PE_B = density x A_B x h x g x A / A_B
The reduction in potential energy of the water is:
ΔPE = PE_A - PE_B = density x g x h x (A - A_B x A / A_B)
which simplifies to:
ΔPE = density x g x h x (A - A_B)
Substituting the given values, we get:
ΔPE = 1000 kg/m³ x 9.8 m/s² x 0.3 m x (50 cm² - 25 cm²)
Converting the area units to m², we get:
ΔPE = 1000 kg/m³ x 9.8 m/s² x 0.3 m x (0.005 m² - 0.0025 m²)
Simplifying, we get:
ΔPE = 7.4 J
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Find the density of seawater at a depth where
I the pressure atm
at the
the
surface is 1050 kg/m³. Seawater has a bulk
modulus of 2.3 x 10° N/m². Bulk modulus is
defined to be
B =
Po AP
Ap
Answer:
To find the density of seawater at a certain depth, we need to use the following equation:
P = P0 + ρgh
where:
P0 = pressure at the surface (given as 1 atm = 101325 Pa)
ρ = density of seawater at the depth we're interested in
g = acceleration due to gravity (9.81 m/s^2)
h = depth below the surface
We also need to use the bulk modulus equation to find the change in pressure with depth:
B = (ρ/ρ0)(P-P0)/P
where:
ρ0 = density of seawater at the surface (given as 1050 kg/m^3)
P = pressure at the depth we're interested in
Combining these two equations, we get:
B = (ρ/ρ0)((P0 + ρgh) - P0)/P
B = ρgh/P
ρ = (BP)/(gh)
Substituting the given values, we get:
ρ = (2.3 x 10^9 N/m^2)(101325 Pa)/(9.81 m/s^2)(1050 kg/m^3)(1 atm)
ρ ≈ 1031.4 kg/m^3
Therefore, the density of seawater at a depth where the pressure is 1 atm and the density at the surface is 1050 kg/m^3 is approximately 1031.4 kg/m^3.
A porter can climb 10 staircase of 30cm each in 10 sec by carrying a 50kg bag. Calculate the power of the porter
Therefore, the power of the porter is 441,450 J/s, or approximately 441.5 watts.
What is work done?The work done by the porter in lifting the 50 kg bag up the stairs can be calculated as the product of the force applied and the distance moved.
The force applied is the weight of the bag, which is given by:
F = m * g
where m is the mass of the bag and g is the acceleration due to gravity, which is approximately 9.81 m/s². Substituting the given values, we get:
F = 50 kg * 9.81 m/s²
F = 490.5 N
The distance moved by the porter in lifting the bag up one staircase is 30 cm, and the porter climbs 10 staircases in 10 seconds, which gives a speed of:
v = (10 * 30 cm) / 10 s
v = 30 cm/s
The power of the porter is the rate at which work is done, which can be calculated as:
P = W / t
where W is the work done and t is the time taken. Substituting the values, we get:
P = F * d * v / t
P = 490.5 N * 10 * 30 cm * 30 cm/s / 10 s
P = 441,450 J/s
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Work Energy Theorem QUESTION: A 1200kg automobile is moving at 25m/s along level ground. What is the initial KE of the automobile? What is the final KE of the automobile? What is the change in KE of the automobile?What is the work done?
(a) The initial kinetic energy (KE) of the automobile is 375,000 J
(b) The final KE will also be 375,000 J.
(c) The work done on the automobile is zero
What is the initial kinetic energy?The initial kinetic energy (KE) of the automobile can be found using the formula:
KE = 1/2mv²
where;
m is the mass of the automobile and v is its velocity.KE = 1/2 x 1200 kg x (25 m/s)²
KE = 375,000 J
The final KE of the automobile will be the same as the initial KE if the velocity remains constant. However, if there is a change in velocity, the final KE can be found using the same formula as above.
The change in KE can be found by subtracting the initial KE from the final KE, or by using the work-energy theorem:
ΔKE = W
where;
ΔKE is the change in kinetic energy and W is the work done.Assuming there is no external work done on the automobile, the change in KE will be zero.
Therefore, the final KE will also be 375,000 J.
The work done on the automobile can be found using the work-energy theorem:
W = ΔKE = 0 J (since there is no change in KE)
Therefore, the work done on the automobile is zero.
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Work Energy Theorem Question:: A 0.0025 kg bullet traveling straight horizontally at 350 m/s hits a tree and slows uniformly to a stop while penetrating a distance of 0.12 m into the tree’s trunk. What is the initial KE of the bullet? What is the final KE of the bullet? What the the change in KE of the bullet? What is the force exerted?
Two spheres of masses 200kg and 100kg respectively have the centres seperated by a distance of 0.5m. Calculade the magnitude of force of attraction between them. G = 6·7x 10" N m² kg - ²
The epicenter of an Earthquake was located 1800 kilometers away. If the S-wave arrived at the seismic station at 10:06:40 am, at what time did the P-wave arrive?
Answer:
The P-wave travels faster than the S-wave and arrives at the seismic station before the S-wave. The time difference between the arrivals of the P-wave and S-wave can be used to determine the distance between the seismic station and the earthquake epicenter.
Explanation:
could any of you please help i really need it
Answer: B is insulating and A is conducting
Explanation:
I really hope that's right. If not, I am so sorry.
a Toyota Celica, travelling initially at 26.9 m/s [S], comes to a stop in 2.61 s. The mass of the car with the driver is 1.18 × 103 kg. Calculate the car’s acceleration.
The initial velocity of the car is 26.9 m/s [S], and the final velocity is 0 m/s [S]. The time taken for the car to come to a stop is 2.61 s. Using the formula:
acceleration = (final velocity - initial velocity) / time
we can find the car's acceleration:
acceleration = (0 m/s - 26.9 m/s) / 2.61 s
acceleration = -10.305 m/s^2
The negative sign indicates that the car is decelerating, or slowing down.
To calculate the force acting on the car during the deceleration, we can use Newton's second law:
force = mass x acceleration
force = (1.18 × 10^3 kg) x (-10.305 m/s^2)
force = -12,166.1 N
The force acting on the car during deceleration is -12,166.1 N, or approximately 12.2 kN.
What is Albert Einstein theory?
Albert Einstein was a German-born theoretical physicist who developed the theory of general relativity, effecting a revolution in physics.
Where is the contradiction between quantum physics and Einstein’s gravity?Rμν−12gμνR=8πGT^μν.
This is Einstein’s field equation. Essentially, this equation is general relativity. The left-hand side represents the geometry of spacetime. The right-hand side, the energy, momentum, and stresses of matter.
What this equation describes, in the words of Wheeler, is this: Spacetime tells matter how to move; matter tells spacetime how to curve.
But look closely. That T
on the right-hand side. It has a hat.
It has a hat because it is a quantum-mechanical operator. Because we know that matter consists of quantum fields. So it is described by operator-valued quantities (Dirac called them q-numbers). They are unlike ordinary numbers. For instance, when you multiply them, the order in which they appear matters. That is, when you have two operators p^
and q^
, p^q^≠q^p^
most of the time. So they are definitely not like numbers.
When Einstein wrote down his field equation over 100 years ago, the T
did not have a hat. But that’s because they didn’t know about operator-valued quantities at the time. Now we do. So I have to put the hat there.
But there are no hats on the left-hand side. And because of that, my equation might as well say something like, some apples = some oranges. It makes no sense. The stuff on the left-hand side (which consists of numbers) can never equal the stuff on the right-hand side (which definitely does not consist of numbers.)
I can make it work, though. I can replace that operator with its so-called expectation value:
Rμν−12gμνR=8πG⟨Tμν⟩.
This is called semiclassical gravity. And it works well, very well indeed. A little too well, as a matter of fact. Gravity is so weak, quantum effects are so irrelevant, this equation accurately describes Nature everywhere we can look. But we still don’t like it, because using that expectation value trick is a cheat, a cop-out.
Now you might wonder, why don’t I put hats on top of the things on the left-hand side? I would… if I knew how to quantize spacetime. That is, how to turn the numbers that describe gravity into quantum-mechanical operators.
But I do not. And nobody does. The standard methods all fail, leading to equations that make no sense at all.
So we are kind of stuck… we don’t know how to quantize gravity, and our observations don’t help us, don’t offer any hints as to how to get beyond semiclassical gravity. Theorists keep trying to come up with new ideas (or recycle old ones) but basically, we’ve been pretty much just spinning our wheels for decades.
You leave Fort worth ,Texas,at 2:41 p.m. and arrive in Dallas at 3:23 p.m. , covering a distance of 58km. what is your average speed in metres per second ?
Answer:
Explanation:
The time taken to travel from Fort Worth to Dallas is:
t = 3:23 pm - 2:41 pm = 42 minutes = 0.7 hours
The distance covered is:
d = 58 km
The average speed is:
v = d/t = 58 km / 0.7 hours = 82.86 km/h
To convert km/h to m/s, we can use the conversion factor:
1 km/h = 0.2778 m/s
Therefore, the average speed in m/s is:
v = 82.86 km/h × 0.2778 m/s/km = 23.06 m/s (rounded to two decimal places)
So the average speed is 23.06 m/s.
if an 80 kg person is 5 m away from a 100 kg person, what is the force of gravity between them?
The force of gravity between the 80 kg person and the 100 kg person, who are 5 meters apart, is approximately 1.07269 × 10^-6 Newtons.
To find the force of gravity between them?The force of gravity between two objects is given by the formula:
F = G(m1*m2)/r^2
Where
F is the force of gravity G is the gravitational constant (6.67430 × 10^-11 N·(m/kg)^2) m1 and m2 are the masses of the two objectsr is the distance between themPlugging in the given values, we get:
F = 6.67430 × 10^-11 N·(m/kg)^2 * (80 kg) * (100 kg) / (5 m)^2
Simplifying this expression, we get:
F = 1.07269 × 10^-6 N
Therefore, the force of gravity between the 80 kg person and the 100 kg person, who are 5 meters apart, is approximately 1.07269 × 10^-6 Newtons.
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In deep space, there is very little friction. Once they launch a probe into deep space, where there are no external forces acting on it, scientists shut the probe’s engines off because the scientists want the probe to
stop immediately.
speed up.
slow down.
move at constant velocity.
A student uses 800 W microwave for three seconds how much energy does a student use
Answer:
The student use 2400 Joules
Explanation:
From the formula E = pt
p = 800W
t = 3 seconds
=> E = 800*3 = 2400J
A missile weighing 400N on the earth surface is shot into the atmosphere to an altitude of 6.4 x 106 m. Taking the earth as a sphere of radius 6.4 x 10-6 m and assuming the inverse-square law of universal gravitation, what would be the weight of the missile at that altitude?
Answer:
Explanation:
We can use the inverse-square law of universal gravitation to determine the weight of the missile at an altitude of 6.4 x 10^6 m. The law states that the force of gravity between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.
Let M be the mass of the Earth and m be the mass of the missile. At the Earth's surface, the weight of the missile is:
F1 = mg
where g is the acceleration due to gravity on the Earth's surface, which we assume to be 9.81 m/s^2.
At an altitude of 6.4 x 10^6 m, the distance between the center of the Earth and the missile is:
r = R + h
where R is the radius of the Earth (6.4 x 10^6 m) and h is the altitude of the missile (6.4 x 10^6 m).
The weight of the missile at this altitude can be calculated using the inverse-square law of universal gravitation:
F2 = G * M * m / r^2
where G is the gravitational constant (6.6743 x 10^-11 N * m^2 / kg^2).
Substituting the given values, we get:
F2 = (6.6743 x 10^-11 N * m^2 / kg^2) * (5.97 x 10^24 kg) * (400 N) / (6.4 x 10^6 m + 6.4 x 10^6 m)^2
F2 = 39.61 N
Therefore, the weight of the missile at an altitude of 6.4 x 10^6 m is approximately 39.61 N.