pLS ANSWER FAST WILL MARK BRAINLIEST

PLS ANSWER FAST WILL MARK BRAINLIEST

Answers

Answer 1

In position A

The mirror has to be observed in the ray reflected from the mirror.

Since the the angle of reflection is equal to the angle of incidence, the reflected ray must be in equal path as the incident ray.

That phenomenon is only in diagram A


Related Questions

two sources of error and precaution in the centre of gravity experiment​

Answers

Answer:

The answer to this question is given below in this explanation sections.

Explanation:

The weight of an object is concentrated at the center of gravity.The term center of gravity is used interchangeably with center of mass.For a symmetrical object the center of mass is located  at the geometric  center of the object.If the object is not symmetric we can determined the center of mass using the mentioned below.

Materials:

cardboardweight(washer,bolt,or fishing weight)hole punchpencil

Procedure:

Cut the cardboard into a strange shape.Do not use a circle,square,rectangle,or any other common geometric shape.Punch a hole near the edge of the cut-out cardboard piece and hang it from a nail.Place the weight, a washer or bolt, on a thread and tie it off.Hang the thread and weight from the nail in front of the cardboard.use a pencil to draw a plumb line down the cardboard where the thread touches.This mark your center  line from that hanging point.

conclusion:

             What would happen to the center of gravity of the shape if you were to spin it freely?

center of gravity experiment:

Balance a ruler with a hammer.Take a rubber band or string and make a loose loop around the hammer and ruler. Make sure the end of the hammer is touching the ruler,and then positions the ruler at the edge of the table.Balance two forces with  a toothpick.A common magic  trick using the properties of center of gravity.The two forks are balanced on the edge of the glass by a toothpick. Stand with your back and feet against a wall.Have someone place quarter on the floor at your feet.Try to pick it cup.Most people cant make these adjustments.Stand against a wall sideways with your arm and leg touching the wall,with nothing to from the out away hold onto.Try to lift your other leg straight out away from the wall.you wont be able to do it.The girls away win chairs lifting challanges place dining chairs against a wall.Bend over the chair so that your head touches the wall and you upper body is parallel to the floor.lift the chair to your chest to your chest and then try to stand up.

1. how much time will it take for a bug to travel 5.0 meters
If it travels it a velocity of 1.4 m/s South?

Answers

T= D dived by V

5.0/1.4= 3.57

Question 24 (1 point)
A 85 kg boy is riding his bicycle in circles with a radius of 7.2 meters. It takes him 6
seconds to make ones revolution. What is his velocity?
730 m/s
0.53 m/s
1.25 m/s
4:
7.54 m/s

Answers

I believe it is B. Or C.


I hope this helped!


I would appreciate it if you gave me a Thanks and a brainliest (:

A boy of mass 85 kg is riding a bicycle in a circle with a radius of 7.2 meters, and it takes 6 seconds to make one revolution, then his velocity will be equal to 7.54 m/s.

What is tangential velocity?

The movement of an object along the circle's edge which path is always at the tangent to any specific point on the circle is described by tangential velocity.

As a result, tangential velocity is the amount of motion along a circle's edge that may be measured at any given time.

The speed at any location that really is tangent to the rotating wheel is quantified as the tangential velocity in a circular motion. The connection between rotational acceleration and tangential velocity is expressed by the formula. The part of movement along the circle's edge that can be detected at any time is called tangential velocity.

The given data in the question,

Radius, r = 7.2 meters.

Time, t = 6 seconds.

v = 2πr / t

v = 2π(7.2)/6

v = 7.54 m/s.

Therefore, the velocity of the boy is 7.54 m/s.

To know more about tangential velocity:

https://brainly.com/question/28738284

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There are some laws of physics that have to do with motion. For example Newton's first law of motion states that objects ______ or ______ will stay unless acted upon by __________.

Answers

Answer:

Newton's first law of motion states that objects state of rest or uniform motion will stay unless acted upon by an external force

Explanation:

Newton's first law of motion is also called the Law of Inertia. Because, it describes the property of inertia of the body. Newton's First Law states that every object continues its state of rest or uniform motion, until or unless it is acted upon by an external force. It means that if an object is in state of rest, it will remain at rest until or unless an external force is not applied to it. Same goes for the state of uniform motion. Hence, the answer will be:

Newton's first law of motion states that objects state of rest or uniform motion will stay unless acted upon by an external force

Answer: Newton's first law of motion states that objects at rest or in motion will stay unless acted upon by a net external force.

Explanation:

Motion is typically described in terms of velocity, acceleration, displacement and time. An object's velocity cannot change unless it is acted upon by a force, as described by Newton's first law also known as inertia. More generally, the term motion signifies any spatial and or temporal change in a physical system.

Many scientists have studied motion and it's properties because of its importance to life. The Italian, Galileo Galile, who lived from 1564 to 1642, did the first systematic study of motion. Also Sir Issac Newton did more detailed work on the study of motion. In his works in motion he came about three different laws.

- Newton's first law: This states that objects at rest or in motion will stay unless acted upon by a net external force.

-- Newton's second law: This states that the force on an object is equal to its mass times its acceleration.

- Newton's third law: This states that for every action there is an equal and opposite reaction.

A pizza delivery car, parked 200 m East of a restaurant, moves to a position 600 m West of the same restaurant in 18 s. Calculate the average velocity of the delivery car in moving to its new position

Answers

Answer:

22.2m/s

Explanation:

Average velocity is expressed as;

Average velocity = Displacement/Time

Get the displacement

If a pizza delivery car, parked 200 m East of a restaurant and moves to a position 600 m West

The displacement = 600 -200

Displacement = 400m

Time = 18s

Substitute and get the velocity;

Average velocity = 400/18

Average velocity = 22.2m/s

Hence the average velocity of the delivery car in moving to its new position is 22.2m/s

What is Physics? How is Physics used in your everyday life? Give at least two examples and explain your answer. You need at least 3

Answers

Answers:

The transportation industry is no stranger to the manipulation of everyday physics. Cars and trains utilize the wheel, which provides a smooth, steady motion.

The ears hear sounds which occur through the movement of air molecules, and the chemistry that drives all of biology depends on the physics of energy and molecules. Every day, for example, plants absorb sunlight, water, and carbon dioxide, creating glucose and releasing oxygen as a byproduct.

Brainlist pls!

The ratio between the velocity of microwaves to the velocity of gamma ray in air is_____ .

less than 1
greater than 1
equal to 1
no correct answer

Answers

Answer:

velocity of all electromagnetic waves are

[tex] \huge3 \times {10}^{8} m {s}^{ - 1} [/tex]

So, the ratio is equal to 1.

Lavon is going to the beach on a hot summer day. He wants to take a bottle of cold water
What material would be best to wrap the bottle to keep the water cool?

Answers

Answer:

aluminum foil and cotton

Explanation:

It was found that the aluminum foil and cotton were the best insulators for keeping the water cold while the Styrofoam sheets and the bubble wrap were the worst two insulators for keeping the water cold.

Why does a third class lever cannot magnify force?​

Answers

Explanation:

The third class lever cannot magnify our force because in third class lever the effort it between the load and the fulcrum. Also, in this type of lever no matter where the force is applied, it is always greater than the force of load. Hence, That type of lever cannot magnify our force.

The sum of all forces acting on an object is what is referred to as _________
Group of answer choices
Mass
Net Force
weight
Normal force

Answers

Net force is the total of all forces acting in the object.

ReadWorks
Date:
Name:
1. According to the text, what are plastics made of?
A. specially treated silicon
B. negatively charged particles
C. long chains of carbon molecules
D. a standard photovoltaic cell

Answers

Answer:

c. long chains of carbon molecules

Describe two adaptations and explain how they help you survive.

Answers

Answer:

My feet and my fists

Explanation:

My feet help me walk

and my fists help me one punch people

Feet’s you can run, and arms that can help you make food and do stuff

The radius of a Bromine (Br) atom is 100 pm. What is its' Circumference?

Answers

Answer:

The circumference of the bromine atom is 628 pm

Explanation:

The formula for the circumference of a circle is 2πr.

Where π is 3.14 and r is the radius of the circle.

Since atoms have a circular shape. The formula above can be used to determine the circumference of an atom (bromine atom in particular).

circumference of the bromine atom is 2πr (where r is 100 pm)

2 × 3.14 × 100 = 628 pm.

The circumference of the bromine atom is 628 pm

If there is an unbalanced force acting on an object, the object will?


(A)Accelerate
(B)Move at a constant velocity
(C)Remain at rest
(D)Change direction

Answers

Answer:

A

Explanation:

because newton's second law states that if a resultant force acts on an object then, it will accelerate in the direction of the resultant force

please help me out ! I will be marking brainliest! thanks! <3

Answers

Answer:

#1. decrease

#2. increases

#3. increases

#4.increases

Explanation:

One model of tennis ball launcher has advertised that it is capable of
imparting 15,000 J of kinetic energy to a 0.5 kg ball initially at rest. A
student carefully measures the compression of the spring to be 0.10 m-
What is the value of the spring constant for the tennis ball launcher
according to the data provided?

Answers

Answer:

The answer for the first question is: 3,000,000 N/m

The answer for the second question is: If the question was, "Which of the following is the best example of kinetic energy being transformed into potential energy?" then the answer is winding the spring on a toy car

Explanation:

For the first question: I have no explanation, I just got it right on my test so I thought i'd help you out.

For the second question: (i'll try to explain the best I can).

Kinetic energy = energy in motion

Potential energy = stored energy

so when winding the spring of a car you are using energy in motion (kinetic energy) to create stored energy (potential energy) that will be used to move the car. So it goes something like:

kinetic energy > potential energy > kinetic energy

A basketball player jumps straight up with a speed of 14 m/s. How high did the player jump?

Answers

Answer:

ttrftyrdy

Explanation:

tytrterte

A plant is said to be an exact copy of the parent plant when it has ALL the same characteristics that the parent plant has. Do you agree with this statement? Justify.

Answers

Explanation:

In Asexual reproduction , part of parent plant is detached and grows to become a complete plant. In this process plant produced is generally identical to the its parent plant. It has ALL the same characteristics that the parent plant has. However, this is not true in case of sexual reproduction of plants.

A tennis ball is hit with a speed of 30 m/s at an angle of 40 degrees above the horizontal. What is the range of the ball?

Answers

Answer:

90.44 m

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 30 m/s

Angle of projection (θ) = 40°

Acceleration due to gravity (g) = 9.8 m/s²

Range (R) =?

The range of the ball can be obtained as follow:

R = u² Sine 2θ / g

R = 30² Sine (2×40) / 9.8

R = 900 Sine 80 / 9.8

R = 900 × 0.9848 / 9.8

R = 886.32 / 9.8

R = 90.44 m

Therefore, the range of the tennis ball is 90.44 m

What are clouds called that generate rain?
A) cirrus clouds

B) nimbus clouds

C) stratus clouds

D) cumulus clouds

Answers

Answer:

B= nimbus clouds

Answer:

B= nimbus clouds

A 1405 kg car is accelerating at
1.77 m/s? Its engine creates a forward
force of 3150 N, and air resistance
creates a backward force. What is
the magnitude (+) of the force of
air resistance or the car?
(Unit = N)

Answers

Answer:

fair = 663.15 [N]

Explanation:

To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

∑F = m*a

where:

∑F = forces applied [N]

m = mass = 1405 [kg]

a = acceleration = 1.77 [m/s²]

In this way, we have two forces, the one that develops the engine to move the car and the resistance force of the air that opposes the movement of the car.

[tex]3150-f_{air}=m*a\\3150-f_{air}=1405*1.77\\f_{air}=3150-2486.85\\f_{air}=663.15[N][/tex]

Please help me with this question

Answers

Answer: m∠P ≈ 46,42°

because using the law of sines in ΔPQR

=> sin 75°/ 4 = sin P/3

so ur friend is wrong due to confusion between edges

+) we have: sin 75°/4 = sin P/3

=> sin P = sin 75°/4 . 3 = (3√6 + 3√2)/16

=> m∠P ≈ 46,42°

Explanation:

A basketball player jumps straight up with a speed of 14 m/s. How high did the player jump?

Answers

Answer:

The basketball player jumped 10 m high.

Explanation:

Vertical Launch Upwards

In a vertical launch upwards, an object is launched vertically up without taking into consideration any kind of friction with the air.

If vo is the initial speed and g is the acceleration of gravity, the maximum height reached by the object is given by:

[tex]\displaystyle h_m=\frac{v_o^2}{2g}[/tex]

The basketball player jumps up with a speed of vo=14 m/s. The maximum height is:

[tex]\displaystyle h_m=\frac{14^2}{2*9.8}[/tex]

[tex]\displaystyle h_m=\frac{196}{19.6}=10[/tex]

The basketball player jumped 10 m high.

An object is traveling at a constant velocity of 10 m/s when it experiences a constant acceleration of 3.5 m/s2 for a time of 10 s. What will its velocity be after that acceleration?

Answers

Answer:

The final velocity of the object is 45 m/s.

Explanation:

Given;

initial velocity of the object, u = 10 m/s

acceleration of the object, a = 3.5 m/s²

time of motion, t = 10 s

The final velocity of the object is given as;

v = u + at

where;

v is the final velocity of the object

v = 10 + (3.5 x 10)

v = 45 m/s

Therefore, the final velocity of the object is 45 m/s.

what's ur father put is ur name​

Answers

nothing he left lol pain

Plz help me and HAPPY NEW YEAR ♧
Energy stored in the bonds between atoms is called
A.kinetic energy.
B.mechanical energy.
C.chemical energy.
D.thermal energy.

Answers

Answer:

it's answer is Compound chemical energy

hope it helps you

A student is playing with a pendulum. He gives the ball a push and watches the ball as it swings. After a while, the ball stops swinging.Why does the ball stop swinging?

Answers

A because it’s not good

this will have to do with that which statement describes seismic waves?​

Answers

Answer:

an elastic wave in the earth produced by an earthquake or other means

Explanation:

Answer:

They carry energy

Explanation:

A physics student throws a ball thrown horizontally from the top of a building with a speed of 8 m/s. The student measures the height of the building to be 15m.

Answers

Answer:

Following are the solution to the given question:

Explanation:

Please find the complete question in the attached file.

[tex]a_x = 0\\\\a_y = -g = -9.81\ \ \frac{m}{s^2} \\\\v_{iy} = 0 \\\\y = v_{iy} \times t+ \frac{1}{2ay} \times t^2 \\\\ 15 = \frac{1}{2} \times 9.8 \times t^2 \\\\t = \sqrt{(2 \times \frac{15}{9.8})} \\\\[/tex]

  [tex]= 1.75 \ sec \\\\[/tex]

Distance:

[tex]x = v_{ix} \times t \\\\[/tex]

  [tex]= 8 \times 1.75\\\\= 14 m[/tex]

Using the concept of motion, the answers to the question posed on the motion of a dropped ball are :

Vertical component of acceleration = - 9.8 m/Horizontal component of acceleration = 0Initial vertical Velocity = 0Time taken = 1.75 seconds Landing distance from building = 14 meters

The vertical component of acceleration is denoted as [tex]a_{y} [/tex] :

The gravitational force acting on the ball in the downward direction has an acceleration of - 9.8 m/s². Hence,

[tex]V_{y} = 9.8 m/s^{2} [/tex]

Gravitational force only acts downwards along the vertical, hence, horizontal component of acceleration will be Zero.

[tex]V_{y} = 0 [/tex]

then the vertical component of x, will be 0

[tex]V_{x} [/tex] = 0

The initial vertical velocity ; [tex]V_{iy} is Zero [/tex] :

[tex]V_{iy} = 0 [/tex] :

The time taken :

S = 0.5gt² ; S = distance = 15 meters ; g = - 9.81

15 = 0.5(9.8)t²

15 = 4.9t²

t² = (15 ÷ 4.9)

t² = 3.061

t = √3.061

t = 1.75 seconds

Landing Distance from building :

Horizontal speed × time taken

[tex]V_{ix} \times 1.75 [/tex]

[tex]8 \times 1.75 = 14 meters [/tex]

Therefore, the ball landed 14 meters away from the building.

Learn more : https://brainly.com/question/13981527

hELP PLS ITS BEEEN A DAY AND A HALF im lit rally stuck pls i lost 10 points and didnt get the answer help me pls

Answers

Answer:

The height of the hurdler when he clears the hurdle is approximately 1.1045 meters (high)

Explanation:

The given parameters are;

The distance the hurdler is from the hurdle, d = 0.535 m

The velocity with which the hurdler jumps, u = 6.82 m/s

The angle at which the hurdler jumps, θ = 67.9°

The horizontal component of the velocity is uₓ = u × cos(θ)

∴ uₓ = 6.82 × cos(67.9°) ≈ 2.566 m/s

The time it takes, t, the hurdler to get to the hurdle horizontally 0.535 m away is given as follows;

Time, t = Distance/Velocity = d/uₓ = 0.535 m/(2.566 m/s) ≈ 0.2085 s

t ≈ 0.2085 s

The kinematic equation of vertical motion, under gravity can be presented as follows;

h = [tex]u_y[/tex]·t - 1/2·g·t²

Where;

h = The height reached by the hurdler in time t

[tex]u_y[/tex] = The vertical component of the velocity = u × sin(θ)

g = The acceleration due to gravity

∴ [tex]u_y[/tex] = 6.82 m/s × sin(67.9°) ≈ 6.3189 m/s

[tex]u_y[/tex] ≈ 6.3189 m/s

Substituting the known values gives;

h = 6.3189 × 0.2085 - 1/2×9.8×0.2085² ≈ 1.1045 m

The height of the hurdler when he clears the hurdle, h ≈ 1.1045 m.

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