PLEASEE HELPPP!!! GIVING 15 PT

Answer:

v=18.97 m/s

Explanation:

the equation for the above question is v²=u²+2as

Answer:

Good conductor of heat

Explanation:

Because metals are shiny, ductile, malleable, sonorous, good conductors of heat and electricity and have high melting and boiling points

Answer: mine is different so im sorry im here for points

Explanation:

Answer:

50N

Explanation:

the net force is the addition of all forces in an object.

The frictional force is the opposite of the applied force, so:

Nf(net force)= 250(applied force)-200(frictional force)

so Nf=50N

Answer: You should not cheat during tests

Explanation: This is your professor.

Mr. Jorge Millan O.

Answer:

phle follow karo yrr tab hee bat u ga

Answer:

no

Explanation:

ok

Answer:

bc I'm ugly

Explanation:

i just answer a random thing bc I know is not from school

Answer:

you shouldn't, if u were to choose me then you would be making a huge mistake since choosing me would go against why you shouldn't choose me.

Answer:

Assuming b = 9.3i + 9.5j (b = 931 + 9.5 is wrong):

a) a×b = 34.27k

b) a·b = 128.43

c) (a + b)·b = 305.17

d) The component of a along the direction of b = 9.66

Explanation:

Assuming b = 9.3i + 9.5j (b = 931 + 9.5 is wrong) we can proceed as follows:  

a) The vectorial product, a×b  is:

[tex] a \times b = (8.6*9.5 - 5.1*9.3)k = 34.27k [/tex]

b) The escalar product a·b is:

[tex] a\cdot b = (8.6*9.3) + (5.1*9.5) = 128.43 [/tex]

c) Asumming (a + b)·b instead a+b·b we have:

[tex](a + b)\cdot b = [(8.6 + 9.3)i + (5.1 + 9.5)j]\cdot (9.3i + 9.5j) = (17.9i + 14.6j)\cdot (9.3i + 9.5j) = 305.17[/tex]

d) The component of a along the direction of b is:

[tex] a*cos(\theta) = \frac{a\cdot b}{|b|} = \frac{128.43}{\sqrt{9.3^{2} + 9.5^{2}}} = 9.66 [/tex]

I hope it helps you!                        

Answer:

because pushing it the mass is sitting steal when pushing the mass and no choice but to move

Answer:

Explanation:

Gravity and normal

Answer:

Gravity and Normal

Answer:

The probability is [tex]\dfrac{1}{2}[/tex]

Explanation:

Given that,

The energy at time t will yield the result [tex]h^2pi^2/2ml^2[/tex]

Suppose, At time t = 0 the normalized wave function for a particle of mass m in the one-dimensional infinite well is given by,

[tex]V(x)={0 0<x<L,\ \infty\ elsewhere[/tex]

The normalized wave function is,

[tex]\psi(x)=\dfrac{1+i}{2}\sqrt{\dfrac{2}{L}}\sin\dfrac{\pi x}{L}+\dfrac{1}{\sqrt{2}}\sqrt{\dfrac{2}{L}}\sin\dfrac{2\pi x}{L}\ 0<x<L, 0\ elsewhere[/tex]

What is the probability that a measurement of the energy at time t will yield the result h^2 pi^2/2mL^2?

We need to find the probability

Using given data

[tex]probability=(\dfrac{1+i}{2})(\dfrac{1-i}{2})[/tex]

[tex]probability=\dfrac{1-i^2}{4}[/tex]

[tex]probability=\dfrac{1+1}{4}[/tex]

[tex]probability=\dfrac{1}{2}[/tex]

Hence, The probability is [tex]\dfrac{1}{2}[/tex]

Answer: A/ average velocity=d/t

Explanation:

The average velocity is the displacement divided by change in time Thus it can be written as Ad/At. Hence, option b is correct.

Velocity of an object is the rate of change of  speed of that object. Mathematically it is the ratio of total displacement to the time taken to travel.

Velocity = Displacement/time.

Let a body travelling a distance within a time t have an initial velocity and then changes to a new final velocity then, the measure of net velocity is called its average velocity.

Suppose v1 be the initial velocity and v2 be the final velocity to move a distance d at a time t, then the average velocity is written as follows:

v2 - v1 = d/t.

Therefore, average velocity is written in terms of average distance travelled and change in time thus, option b is correct.

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Answer:

C

Explanation:

Chemical energy is in the food you eat and It fuels your body

Answer: B

Explanation:

When you chew it, you're changing the physical state it's in.

Answer:

it can be up to 15 ppl

ur team can be on a court

width

28 I believe

less then 10 seonds

Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

[tex]a = \frac{f}{m} \\ [/tex]

where

f is the force

m is the mass

From the question

f = 8268 N

m = 1125 kg

We have

[tex]a = \frac{8268}{1125} \\ =7.3493 3333...[/tex]

We have the final answer as

Hope this helps you

Answer:

(a). The width of the river is 90.5 m.

The current speed of the river is 3.96 m.

(b). The shortest time is 15.0 sec and we would end 59.4 m east of our starting point.

Explanation:

Given that,

Constant speed = 6.00 m/s

Time = 20.1 sec

Speed = 9.00 m/s

Time = 11.2 sec

We need to write a equation for to travel due north across the river,

Using equation for north

[tex]v^2-c^2=\dfrac{w^2}{t^2}[/tex]

Put the value in the equation

[tex]6.00^2-c^2=\dfrac{w^2}{(20.1)^2}[/tex]

[tex] 36-c^2=\dfrac{w^2}{404.01}[/tex]....(I)

We need to write a equation for to travel due south across the river,

Using equation for south

[tex]v^2-c^2=\dfrac{w^2}{t^2}[/tex]

Put the value in the equation

[tex]9.00^2-c^2=\dfrac{w^2}{(11.2)^2}[/tex]

[tex] 81-c^2=\dfrac{w^2}{125.44}[/tex]....(II)

(a). We need to calculate the wide of the river

Using equation (I) and (II)

[tex]45=\dfrac{w^2}{125.44}-\dfrac{w^2}{404.01}[/tex]

[tex]45=w^2(0.00549)[/tex]

[tex]w^2=\dfrac{45}{0.00549}[/tex]

[tex]w=\sqrt{\dfrac{45}{0.00549}}[/tex]

[tex]w=90.5[/tex]

We need to calculate the current speed

Using equation (I)

[tex]36-c^2=\dfrac{(90.5)^2}{(20.1)^2}[/tex]

[tex]36-c^2=20.27[/tex]

[tex]c^2=20.27-36[/tex]

[tex]c=\sqrt{15.73}[/tex]

[tex]c=3.96\ m/s[/tex]

(b). We need to calculate the shortest time

Using formula of time

[tex]t=\dfrac{d}{v}[/tex]

[tex]t=\dfrac{90.5}{6}[/tex]

[tex]t=15.0\ sec[/tex]

We need to calculate the distance

Using formula of distance

[tex]d=vt[/tex]

[tex]d=3.96\times15.0[/tex]

[tex]d=59.4\ m[/tex]

Hence, (a). The width of the river is 90.5 m.

The current speed of the river is 3.96 m.

(b). The shortest time is 15.0 sec and we would end 59.4 m east of our starting point.

Answer:

a)     E = k Q / r² ,      k = 1 / 4πε₀,  b)  E=0, C) E=0,   d) Q=0

Explanation:

To find the electric field in this exercise let's use Gauss's law

         Ф = ∫ E. dA = [tex]q_{int}[/tex] /ε₀

Let's use a sphere as a Gaussian surface, in this case the field lines and the radii of the spheres are parallel so the scalar product is reduced to the algebraic product, let's carry out the integral

          E A = q_{int} /ε₀

The area of ​​a sphere is

         A = 4π r²

we substitute

          E (4π r²) =q_{int} /ε₀

a) The field is requested outside the spherical shell

        d> R₂

in this case the charge inside the Gaussian surface is

          q_{int} = Q

           E = Q / (4π r²) ε₀

           E = k Q / r²

           k = 1 / 4πε₀

b) In the second case, the field inside the spherical casing is requested.

As the surface is metallic, the charge is located on the surface of it, the electrons repel each other. So the charge inside is zero

           q_{int} = 0

            E = 0

c) The field in the interior region of the shell, all the charge is external, therefore the internal charge is zero

           q_{int} = 0

           E = 0

d) as the shell is conductive, the electrons can move freely, which is why it moves as far away as possible between them, this means that everything is located as close as possible to the outer surface of the conductor. Consequently, THERE ARE NO ELECTRONS ON THE INTERNAL SURFACE

              Q_internal =0

Answer:

a)

b is at higher potential

b)

E = 800 V/m

c)

W = -48.0 μ J

Explanation:

Given:

electric field has magnitude E and is directed in the negative x direction

potential difference between point a (at x = 0.60 m) and point b (at x = 0.90 m) = 240 V

a)

Direction of the electric field is in the negative x direction so it is away from the positive charge and the more distance away from direction, the lesser the potential gets. So b is at the higher potential.

b)

When the magnitude of electric field is constant then the potential difference between two points in the field is given by:

Vab = Ed

where

Vab is the potential difference between two points a and b in the field

E is electric field magnitude

d is the distance between two points

Compute distance between two points a and b

d = 0.90 - 0.60

d = 0.30

d = 0.3 m

Since potential difference between two points in the field is given which is 240 V

Compute E:

The above formula becomes:

Vab = Ed

E = Vab/d

  = 240/0.3

E = 800 V/m

c)

The negative charge moved from the higher potential to low so work done on the point charge by electric field is negative.

W = Fd

Electric field = E = F/q

where

E is electric field magnitude

F is electric force on q

q is point charge magnitude

The charge q is either positive or negative and when charge is positive the directions of E and F are same otherwise opposite in case of negative charge.

So to calculate the work done on the point charge by the electric field:

E = F/q

F = Eq

so

W = Fd = Eqd

Now putting the values:

E = 800 V/m

q = - 0.200 μC

d = 0.3 m

W = Eqd

W = 800 * - 0.200 * 0.3

W = 800 * - 0.2 * 10⁻⁶ * 0.3

W = - 48 * 10⁻⁶

W = - 4.8 * 10⁻⁵ J

W = -48.0 μJ

a. The point which is at a higher potential is point a.

b. The magnitude (E) of the uniform electric field is equal to 800 V/m.

c. The work done on the point charge by the electric field is equal to -48 microjoules.

Given the following data:

a. Since the uniform electric field with a magnitude (E) is directed in the negative x direction, the point at a higher potential is point a because the electric field is not close to the positive charge and it is further away from point b by 0.90 meter. Also, the potential difference of an electric field is inversely proportional to the square of the distance from a point charge.

b. To calculate the magnitude (E) of the uniform electric field:

At a constant potential difference, the magnitude (E) of this electric field is given by the formula:

[tex]V_{ab} = Ed[/tex]

Where:

First of all, we would determine the distance (d).

[tex]d = d_b - d_a\\\\d = 0.90 -0.60[/tex]

Distance, d = 0.30 meter.

Substituting the given parameters into the formula, we have;

[tex]240 = 0.3E\\\\E=\frac{240}{0.3}[/tex]

E = 800 V/m

c. To calculate the work done on the point charge by the electric field:

Mathematically, the work done on a point charge in an electric field is given by the formula:

[tex]W = Fd = Eqd\\\\W = 800 \times (-0.200 \times 10^{-6}) \times 0.3\\\\W = -240 \times 0.200 \times 10^{-6}\\\\W = -48\times 10^{-6}\;Joules[/tex]

Note: 1 microjoules = [tex]1\times 10^{-6}[/tex] Joules

Work done = -48 microjoules.

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Answer:

S=d/t.

distance is= speed multiplied by the time

D= 115 multiplied by 20

the answer is 2300km

Driver is approximately 0.63888 kilometers away from where he received the text message after 20 seconds.

To determine the distance the driver travels 20 seconds after receiving the text message, we need to calculate the distance covered during that time interval.

First, we convert the driver's speed from km/h to m/s for consistent units. The conversion factor is 1 km/h = 0.27778 m/s.

Driver's speed = 115 km/h × 0.27778 m/s = 31.944 m/s

Next, we use the formula for distance traveled:

Distance = Speed × Time

Distance = 31.944 m/s × 20 s = 638.88 meters

Therefore, the driver will be 638.88 meters away from the point where he received the text message after 20 seconds.

To convert this distance to kilometers, we divide by 1000:

Distance = 638.88 m ÷ 1000 = 0.63888 km

So, the driver is approximately 0.63888 kilometers away from where he received the text message after 20 seconds.

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Answer:

hfwf2f2f2ff2fefwgwfe

Answer:

0.258 +- 0.0162

Explanation:

First change the uncertainty to percentage uncertainty :

%uncertainty =uncertainty /estimated value *100

0.1/51.6 * 100=0.19%

Do the same for the rest you will get:

0.1%, 1%, 5%

Then add the %uncertainties

0.19% + 0.1% + 1% +5%=6.29%

Find density:

51.6/10 * 100 * 0.20 = 0.258

Change the %percentage uncertainty to absolute uncertainty :

Absolute uncertainty = %uncertainty * the answer

6.29/100 * 0.258 = 0.0162

Answer = 0.258 +- 0.0162

After rounding:

0.26 +- 0.02

Answer:

1. Scalar

2.Vector

3. Scalar

4. Vector

5.Scalar

6.Scalar

7.Vector

8.Vector

9.Scalar

10.Scalar

11.Scalar

12. Vector

13.Scalar

Explanation:

Scalar refers to magnitude, and Vectors include magnitude with directions.

Answer:

Reversing the polarity of the magnet

Explanation:

The action that will cause the induced current to decrease or remain constant is "reversing the polarity of the magnet"

To reverse the polarity, a battery and coil of copper can be used. Reversing the polarity of the magnet will also cause the induced current to reverse in direction. The polarity of the magnet actually determines the direction of the electromagnetic force.

Answer:

Follows are the solution to this question:

Explanation:

By checking the value in which we have calculated by performing its differentiation of [tex]\frac{a}{3}t^3+bt[/tex], the correct form of its integer value is calculating  with regard to t, that also provides as expected [tex]at^2+b = F(t)[/tex].

Answer:

strontium has 50 neutrons

Answer:

the answer is 50 hope it helps =)

Explanation:

Answer:

A

 [tex]k = 0.11 \ m [/tex]  beyond the goal  post

B

Given that the goal  was score against the Bruins it then means that the Flyer won the game with 2 points

Explanation:

From the question we are told that

  The amount of time left in the game is  [tex]t =  20 \ s[/tex]

   The  amount of time the goal was defended  is  [tex]t_1  =  9 \  s[/tex]

   The  time remaining when the shot was made is  [tex]t_2 =  1.25 \  s[/tex]

     The  distance of the pluck from the goal is  [tex]d =  37 \  m[/tex]

     The  initial  velocity of the pluck is [tex]u =  30 \  m/s[/tex]

    The acceleration of the pluck is  [tex]a =  -0.50 \  m/s^2[/tex]

Generally the distance travel at the remaining time is mathematically represented as

      [tex]D =  u *  t _2  +  \frac{1}{2}* a*  t_2[/tex]

      [tex]D =  30 * 1.25  - \frac{1}{2}* 0.50* 1.25^2[/tex]

       [tex]D =  37.11 \ m [/tex]

So the position of the pluck when the game clock reaches zero is

        [tex]k = D - d[/tex]

=>    [tex]k = 37.11 - 37[/tex]

=>        [tex]k = 0.11 \ m [/tex]  beyond the goal  post

Given that the goal  was score against the Bruins it then means that the Flyer won the game with 2 points

Answer:

The ratio of the new potential energy to the potential energy before the insertion of the dielectric is 0.58

Explanation:

Given that,

Length of plates = 8 cm

Width = 5.52 cm

Distance = 1.99 cm

Dielectric constant = 2.6

Length = 4.4 cm

Potential = 0.8 V

We need to calculate the initial capacitance

Using formula of capacitance

[tex]C=\dfrac{\epsilon_{0}A}{d}[/tex]

Put the value into the formula

[tex]C=\dfrac{8.85\times10^{-12}\times8\times5.52\times10^{-4}}{1.99\times10^{-2}}[/tex]

[tex]C=1.96\times10^{-12}[/tex]

We need to calculate the final capacitance

Using formula of capacitance

[tex]C'=\dfrac{\epsilon_{0}A_{1}}{d}+\dfrac{k\epsilon_{0}A_{2}}{d}[/tex]

Put the value into the formula

[tex]C'=(\dfrac{8.85\times10^{-12}}{1.99\times10^{-2}})((4.4\times5.52)+(3.6\times5.52)2.6)\times10^{-4}[/tex]

[tex]C'=3.37\times10^{-12}[/tex]

We need to calculate the  ratio of the new potential energy to the potential energy before the insertion of the dielectric

Using formula of energy

[tex]\dfrac{E}{E'}=\dfrac{\dfrac{1}{2}CV^2}{\dfrac{1}{2}C'V^2}[/tex]

Put the value into the formula

[tex]\dfrac{E}{E'}=\dfrac{1.96\times10^{-12}}{3.37\times10^{-12}}[/tex]

[tex]\dfrac{E}{E'}=0.58[/tex]

Hence, The ratio of the new potential energy to the potential energy before the insertion of the dielectric is 0.58