*PLEASE HELP*
Light passing through a double slit
with separation d=3.33x10^-5 m
creates its first minimum (m = 1) at an
angle of 0.551 deg. What is the
wavelength of the light, IN
NANOMETERS?
(Hint: The answer will be between 400 and
700.) (Unit = nm)

Answer:

the max is 2,500 or less

Explanation:

because you cant owe anymore

Answer:

[tex]P = -\frac{17978}{1609344}(h)+101.325[/tex]

Explanation:

Given

[tex]h = height[/tex]

[tex]P = Pressure[/tex]

[tex](h_1,P_1) = (0,101.325)[/tex]

[tex](h_2,P_2) = (1609.344 ,83.437 )[/tex]

Required

Determine the linear equation for P in terms of h

First, we calculate the slope/rate (m);

The following formula is used:

[tex]m = \frac{P_2 - P_1}{h_2 - h_1}[/tex]

Substitute values for P's and h's

[tex]m = \frac{83.347 - 101.325}{1609.344- 0}[/tex]

[tex]m = \frac{-17.978}{1609.344}[/tex]

[tex]m = -\frac{17.978}{1609.344}[/tex]

Multiply by 1000/1000

[tex]m = -\frac{17.978 * 1000}{1609.344*1000}[/tex]

[tex]m = -\frac{17978}{1609344}[/tex]

The equation is then calculated using:

[tex]P - P_1 = m(h - h_1)[/tex]

Substitute values for m, h1 and P1

[tex]P - P_1 = m(h - h_1)[/tex]

[tex]P - 101.325 = -\frac{17978}{1609344}(h - 0)[/tex]

[tex]P - 101.325 = -\frac{17978}{1609344}(h)[/tex]

Make P the subject

[tex]P = -\frac{17978}{1609344}(h)+101.325[/tex]

The above is the required linear equation

Answer:

m = 45 kg

Explanation:

Given that,

Mass of Jadan, m = 45 kg on Earth

Jupiter has more gravity than the Earth.

Mass of an object is the amount of matter contained inside an object. We need to tell about the mass of Jaden on Jupiter. The mass of the object remains same everywhere.It does not change in any of the location.

Hence, Jaden's mass will be 45 kg on Jupiter.

Answer:

(a) the particle position = 135 m

(b) the velocity of the particle = 44 m/s

(c) the acceleration of the particle = 50 m/s²

Explanation:

Solution to Question 2.

Given;

velocity of a particle, v = 2 - 4t + 2t³

initial position at t = 0, s₀ = 3 m

(a) the particle position at t = 3 s

s = vt

s = (2 - 4t + 2t³)t

s = 2t - 4t² + 2t⁴

s = s₀ + s₃

s = s₀ + 2(3) - 4(3²) + 2(3⁴)

s = s₀ + 6 - 36 + 162

s = s₀ + 132 m

s = 3m + 132 m

s = 135 m

(b) the velocity of the particle at t = 3 s

v = 2 - 4t + 2t³ = 2 - 4(3) + 2(3)³

v = 44 m/s

(c) the acceleration of the particle at t = 3s

v = 2 - 4t + 2t³

[tex]a = \frac{dv}{dt} \\\\a = \frac{d}{dt} (2 -4t + 2t^3)\\\\a = -4 + 6t^2[/tex]

a = -4 + 6(3)²

a = 50 m/s²

Explanation:

w=F×d 1kg=9.807N

p=w/t 400kg=9.807×400=3922.8N

p=Fd/t

=3922.8×20×1

power=78456 watt

..sorry..if the answer is not right..

Answer:

B. The more potential energy it has.

Explanation:

I majored in Physics

Answer:

The best example would be a pendulum inside a sealed empty room.

Explanation:

Explanation:

Length of a string, l = 0.626 m

A tennis ball revolves in a horizontal circle above his head at a rate of 4.50 rev/s.

(a) The centripetal acceleration of the tennis ball is given by :

[tex]a=\omega^2r\\\\a=(4.5\times 2\pi)^2\times 0.626\\\\=500.44\ m/s^2[/tex]

(b) When r = 0.626 m and ω = 4.50 rev/s

Speed,

[tex]v=r\omega\\\\=0.626\times 4.50 \times 2\pi\\\\=17.69\ m/s[/tex]

When r = 1 m and ω = 4 rev/s

Speed,

[tex]v=r\omega\\\\=1\times 4 \times 2\pi\\\\=25.13\ m/s[/tex]

Speed is more in second case when child now increases the length of the string to 1.00m but has to decrease the rate of rotation to 4.00 rev/s.

(c) [tex]a=\omega^2r\\\\a=(4\times 2\pi)^2\times 1\\\\=631.65\ m/s^2[/tex]

Hence, this is the required solution.

Answer:

call me 7164013838 hurry bye

Answer:

a) [tex] v_{U-235} = 2.68 \cdot 10^{5} m/s [/tex]

[tex]v_{He-4} = -1.57 \cdot 10^{7} m/s[/tex]  

b) [tex] E_{He-4} = 8.23 \cdot 10^{-13} J [/tex]

[tex] E_{U-235} = 1.41 \cdot 10^{-14} J [/tex]

Explanation:

Searching the missed information we have:                                        

E: is the energy emitted in the plutonium decay = 8.40x10⁻¹³ J

m(⁴He): is the mass of the helium nucleus = 6.68x10⁻²⁷ kg  

m(²³⁵U): is the mass of the helium U-235 nucleus = 3.92x10⁻²⁵ kg            

a) We can find the velocities of the two nuclei by conservation of linear momentum and kinetic energy:

Linear momentum:

[tex] p_{i} = p_{f} [/tex]

[tex] m_{Pu-239}v_{Pu-239} = m_{He-4}v_{He-4} + m_{U-235}v_{U-235} [/tex]

Since the plutonium nucleus is originally at rest, [tex]v_{Pu-239} = 0[/tex]:

[tex] 0 = m_{He-4}v_{He-4} + m_{U-235}v_{U-235} [/tex]  

[tex] v_{He-4} = -\frac{m_{U-235}v_{U-235}}{m_{He-4}} [/tex]    (1)

Kinetic Energy:

[tex] E_{Pu-239} = \frac{1}{2}m_{He-4}v_{He-4}^{2} + \frac{1}{2}m_{U-235}v_{U-235}^{2} [/tex]

[tex] 2*8.40 \cdot 10^{-13} J = m_{He-4}v_{He-4}^{2} + m_{U-235}v_{U-235}^{2} [/tex]    

[tex] 1.68\cdot 10^{-12} J = m_{He-4}v_{He-4}^{2} + m_{U-235}v_{U-235}^{2} [/tex]   (2)    

By entering equation (1) into (2) we have:

[tex] 1.68\cdot 10^{-12} J = m_{He-4}(-\frac{m_{U-235}v_{U-235}}{m_{He-4}})^{2} + m_{U-235}v_{U-235}^{2} [/tex]  

[tex] 1.68\cdot 10^{-12} J = 6.68 \cdot 10^{-27} kg*(-\frac{3.92 \cdot 10^{-25} kg*v_{U-235}}{6.68 \cdot 10^{-27} kg})^{2} +3.92 \cdot 10^{-25} kg*v_{U-235}^{2} [/tex]  

Solving the above equation for [tex]v_{U-235}[/tex] we have:

[tex] v_{U-235} = 2.68 \cdot 10^{5} m/s [/tex]

And by entering that value into equation (1):

[tex]v_{He-4} = -\frac{3.92 \cdot 10^{-25} kg*2.68 \cdot 10^{5} m/s}{6.68 \cdot 10^{-27} kg} = -1.57 \cdot 10^{7} m/s[/tex]                        

The minus sign means that the helium-4 nucleus is moving in the opposite direction to the uranium-235 nucleus.

b) Now, the kinetic energy of each nucleus is:

For He-4:

[tex]E_{He-4} = \frac{1}{2}m_{He-4}v_{He-4}^{2} = \frac{1}{2} 6.68 \cdot 10^{-27} kg*(-1.57 \cdot 10^{7} m/s)^{2} = 8.23 \cdot 10^{-13} J[/tex]

For U-235:

[tex] E_{U-235} = \frac{1}{2}m_{U-235}v_{U-235}^{2} = \frac{1}{2} 3.92 \cdot 10^{-25} kg*(2.68 \cdot 10^{5} m/s)^{2} = 1.41 \cdot 10^{-14} J [/tex]

I hope it helps you!                                                                                    

Answer:

Average speed = 46.67 m/s

Explanation:

Given that the time taken in covering first 1000 m = 25 seconds.

The time taken in covering next 2.5 km = 50 seconds.

Total distance covered = 1000 m + 2500 m = 3500 m

Total time taken = 25+50=75 seconds

Average speed = Total distance covered / total time taken

= 3500/75 = 46.67 m/s

Answer:

(a)The final speed of the truck "v"  is 1.76 m/s

(b) The horizontal force exerted on the truck is 178.64 N

Explanation:

Given;

work done by the man, W = 4,465 J

mass of the truck, m = 2.9 x 10³ kg

initial speed of the truck, u = 0

distance the truck was pushed to, d = 25 m

final speed of the truck, = v

The work done in pushing the truck is calculated as;

W = F x d

where;

F is the horizontal force applied

d is the distance in which the truck was pushed to

W = ma x d

[tex]a = \frac{W}{md} \\\\a = \frac{4465}{2.9 \times 10^3 \ \times 25} \\\\a = 0.0616 \ m/s^2[/tex]

(a)The final speed of the truck "v"  is calculated as;

v²= u² + 2ad

v² = 0 + 2(0.0616 x 25)

v² = 3.08

v = √3.08

v = 1.76 m/s

(b) the horizontal force exerted on the truck

F = ma

F = (2.9 x 10³) (0.0616)

F = 178.64 N

Answer:  C) 48 N forward

===================================================

Explanation:

Subtract the two forces, since they are working opposite one another.

79-31 = 48

The net force is 48 newtons forward. The truck is moving forward since the engine's force (79 N) is larger than the force of friction (31 N).

The force of friction cannot exceed the engine's force because friction only slows down an object, and does not push the object backward. In other words, if the object was stationary, then the ground isn't pushing the object backwards assuming you're on a level flat ground.

Answer:

theta = 90°

Explanation:

hope it's helpful

Explanation:

A • B = (2i - 3j + k) • (i + j + k)

= (2)(1) + (- 3)(1) + (1)(1)

= 0 = AB cos θ

∴ cos θ = 0 (as A ≠ 0,B ≠ 0)

or θ = 90°

or the vectors A and B are mutually perpendicular.

-TheUnknownScientist

Answer:

b. melting

Explanation:

it is made of sediments and that is not necessary

Answer:

That isnt a question so no one will know the answer to what you are talking about. I suggest adding a sceenshot or picture of the question.

Answer:

it depends on wether the + and - are facing eachother

or away from eachother

Explanation:

Answer:

Yes, they are correct, you need to include all parts of the question, don't just copy and paste the words. But in the diagram that was supposed to be there, the magnets' north poles are facing each other. Therefore they would push away from each other if they were to get any closer.  So, the magnetic potential energy would decrease due to their movement away from each other. So your answer is (C. It will decrease.

Explanation:

Answer:

There are 4 liquids in this experiment and red is the least dense of all of them so it should float on top, which it is doing.

The red that you see at the bottom is neither liquid nor is it a part of the experiment.

It is simply the color of the bottom of the container that the experiment was conducted in.

The bottom thing doesn’t matter. That is not meant to be red, it‘s the bottom of the beaker. The star is at the very bottom of the beaker. it’s just the base of the beaker.

Answer:

Explanation:

Maybe start by trying to draw out some transverse waves, longitudinal waves, stationary waves etc. From there you could explain things about each type. For example, particles oscillate in the direction of energy transfer in longitudinal waves or you could include that all electromagnetic waves are examples of transverse waves. Hope this helps you get started :)

Waves are a form of energy transfer through matter or space. Waves can be characters using their amplitude, frequency, wavelength, energy etc.

A wave can be defined as the energy transfer or disturbances in air or matter. Sound and light are two types of waves.

There are broadly two types of waves namely longitudinal waves which vibration parallel  to the direction of the wave and transverse wave vibrating perpendicular to the direction of wave.

A wave is associated with an amplitude. It is the maximum distance that its molecules are displaced or it is the measure of intensity.

Frequency of a wave is the number crests or troughs passing per unit time. Wavelength is the distance between two consecutive crests or throughs.

Each wave is associated with certain amount of energy which is directly proportional to its frequency. High energy wave can easily penetrate through a body.

Hence, by the terms such as amplitude, frequency, wavelength and energy a wave can be characterized.

To find more about waves, refer the link below:

https://brainly.com/question/3639648

#SPJ2

Answer:

Option (C) is correct.

Explanation:

Assuming that the hiker starts walking from the origin O as shown in the figure.

First, he walks 200 m west to point A (say), then he walks 100 m north to the final point B (say) as shown in the figure.

The final point B is in the north-west direction, therefore, the resulting point is in the north-west direction.

Hence, option (C) is correct.

Answer:

D) 60 m

Explanation:

We can use the constant acceleration equation that contains displacement, initial velocity, acceleration, and time. We want to solve for the time that the ball was in the air first.

Let's use this equation in terms of the y-direction.

The vertical displacement will be 0 meters since the ball will be on the floor. The initial vertical velocity is 10 m/s, the vertical acceleration is g = 10 m/s², and we are going to solve for time t.

Let's set the upwards direction to be positive and the downwards direction to be negative. We must use -g to be consistent with our other values.

Plug the known values into the equation.

Simplify the equation.

Factor the equation.

Solve for t by setting both factors to 0.

We get t = 0, t = 2. We must use t = 2 seconds because it is the only value for t that makes sense in the problem.

Now that we have the time that the ball was in the air, we can use the same constant acceleration equation to determine the horizontal displacement of the tennis ball. We will use this equation in terms of the x-direction:

Plug the known values into the equation.

We can eliminate the right side of the equation since anything multiplied by 0 outputs 0.

The horizontal displacement of the ball is 60 meters. Therefore, the answer is D) 60 m.

Answer:

Explanation:

They have the same kinetic energy

Answer:

500J

Explanation:

The arrow will have an energy of 500J after it has been released from its state of rest.

This is compliance with the law of conservation of energy which states that "in every system, energy is neither created nor destroyed but transformed from one form to another".

Answer:

I guess that the bottom part that is colored red represents the base of the container and not the actual red liquid.

Always, the densest materials/substances will go to the bottom.

One could see different things if, for example, when one of the elements changes state it becomes more or less dense (an example is the water, which has a solid phase, the ice, less dense than the liquid phase, and you can see that solid water usually floats on liquid water)

But in the text there is nothing about possible changes in temperature or changes in phase, then that option can be discarded.

The only option that makes sense is that the red part at the bottom represents the base of the column.

Answer:

The magnitude of the work done by the snake against friction is 402 J.

Explanation:

The work is given by:

[tex] W = F*d [/tex]

Where:

F: is the force

d: is the distance

The distance traveled by the snake is given by the perimeter of the circle:

[tex] P = 2\pi r = 2\pi 3.20 m = 20.1 m [/tex]

Now, the force in the direction of the movement is:

[tex] |\Sigma F| = F_{\mu} = \mu N = \mu W = 0.25*80.0 N = 20 N [/tex]

Finally, the work is:

[tex] W = F*d = 20 N*20.1 m = 402 J [/tex]

Therefore, the magnitude of the work done by the snake against friction is 402 J.

I hope it helps you!                                              

Answer:

let the coefficient of friction be ß

Explanation:

[tex]from \: third \: law \: of \: solid \: friction \\ friction = \beta \times R \\ where \: R \: is \: the \: normal \: reaction \\ 46 = 0.30 \times R \\ R = \frac{46}{0.30} \\ R = 153.33 \: N \\ but \: R = mg \\ where \: mg \: is \: the \: weight \\ hence \\ weight, W = 153.33 \: N[/tex]